Answer:
The cell membrane is protective layer surrounding a cell.
Answer:
options D is correct
....hope it helps you
What is the oxidation state of oxygen (O) in the reactant O2(g)?
Answer:0
Explanation:
Since oxygen gas i.e., diatomic oxygen exists in the atmosphere in the free state, hence the oxidation state of each atom will be 0
#44) Draw the complete chemical equation for the hydrohalogenation reaction of 1-
pentene by HBr. You must show the structures in your reaction; you may NOT use
molecular formulas!
Hydrohalogenation Reaction:
The substitution of hydrogen and halide levels across a double bond takes place. The halide group is connected to the carbon with more substituents. The product will affect by the presence of peroxide
What is the hydrohalogenation reply with example?
Ethene is a symmetrical alkene having two carbon atoms. It reacts with HBr in the presence of CCl4, producing bromoethane or ethyl bromide (CH3CH2Br). Propene is an unsaturated alkene consisting of a three-carbon chain with two carbon particles on either side of the double bond.
What is the hydrohalogenation reaction with example?Ethene is a symmetrical alkene including two carbon atoms. It reacts with HBr in the presence of CCl4, producing bromoethane or ethyl bromide (CH3CH2Br). Propene is an unsaturated alkene consisting of a three-carbon chain with two carbon atoms on either flank of the double bond.
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Use a periodic table to help you answer these questions if needed.
How many valance electrons does aluminum have? 3
How many valance electrons does sulfur have? 6
What type of bond will these two elements form? ionic
The top three are correct but not sure on bottom questions of number of atoms Can you answer the question below.
How many aluminum atoms will you need? How many sulfur atoms will you need?
Answer:
2 Al and 3 S
Explanation:
Al2S3 so 2 Al and 3 S
The following reaction: HF(aq) <--> H+(aq) + F-(aq) has an equilbirum constant (K) value of 7.2 x 10-4. This means that the reaction proceeds essentially to completion.
Group of answer choices
True
False
Given an equilibrium constant value of 7.2 x 10-4 it is false to say that the reaction proceeds essentially to completion.
What is the equilibrium constant?In a reaction, we can judge using the value of the equilibrium constant weather or not the reaction moves on to completion. If the reaction moves up to completion, it the follows that the value of the equilibrium constant ought to be large.
On the other hand, when we have a case that the equilibrium constant is small and is not so large, then the reaction does not proceed essentially to completion.
Given an equilibrium constant value of 7.2 x 10-4 it is false to say that the reaction proceeds essentially to completion.
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The compound iron oxide can exist with either iron(II) ions or iron(III) ions. Conduct Internet research to learn about the differences between iron(II) oxide and iron(III) oxide. Give the chemical formula for each compound. Describe their appearance and uses. Based on your findings, are these two forms of the same compound, or are they two completely different compounds?
(What goes in the 6 empty spaces?)
Based on our finding these two compounds are not same they are completely different from each other as Formula of both compounds are different, their appearance is also different from each other.
What is Iron (II) Oxide ?The formula of the Iron II oxide is FeO. Common name of Iron (II) Oxide is Ferrous Oxide. Iron (II) Oxide is a black colored powder. The mineral form of Iron (II) oxide is known as Wustite. Iron (II) Oxide is used as a pigment. It is also used to make dyes.
What is Iron (III) Oxide ?The formula of the Iron (III) Oxide is Fe₂O₃. Common name of Iron (III) Oxide is Ferric oxide. Iron (III) Oxide appears as Red-Brown solid. It is also known as Hematite. Iron (III) oxide is used as pigments. It is used in dental composites , cosmetics. It is also used to apply the final polish on metallic jewellery.
Thus from the above conclusion we can say that Based on our finding these two compounds are not same they are completely different from each other as Formula of both compounds are different, their appearance is also different from each other.
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How to recover ballpoint ink washed off from a paper?
The first step in clearing a clogged ballpoint pen is to exert additional pressure when scrawling and drawing vertical lines on paper. If this approach doesn't work, dip the pen's tiny tip in rubbing alcohol. [Only the tidbit] Any dried-up or hardened ink on the tip will dissolve with this.
Suppose you need to prepare 136.9 mL of a 0.315 M aqueous solution of NaCl.
What mass, in grams, of NaCl do you need to use to make the solution?
Answer:
2.52 g NaCl
Explanation:
(Step 1)
To find the mass, you first need to find the moles NaCl. This value can be found using the molarity ratio:
Molarity = moles / volume (L)
After you convert mL to L, you can plug the given values into the equation and simplify to find moles.
136.9 mL / 1,000 = 0.1369 L
Molarity = moles / volume
0.315 M = moles / 0.1369 L
0.0431 = moles
(Step 2)
Now, you can use the molar mass to convert moles to grams.
Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol
Molar Mass (NaCl): 58.443 g/mol
0.0431 moles NaCl 58.443 g
------------------------------ x ------------------- = 2.52 g NaCl
1 mole
Solve this organic transformation....use - Br2,CCl4,KOH,CH3OH,Hg+2,diluted H2SO4, PCC,HBr,Mg,Dry ether,Na,H2,Pd,quinoline
Organic transformation sequential equation using catalysts will be as follows:
2CH3-CH2-O => (alc. KOH) => CH2=CH2 + KCl + H2O => (Br2/CCl4) => CH2Br-CH2Br + Zn
CH2Br-CH2Br + Zn => (HBr /Pd) => CH2=CH2+ZnBr2
As can be visualized from above organic transformation equation, conversion of dry ether in presence of alkaline potassium hydroxide results in formation of unstable ethene. This dry unsaturated compound of ethene is stabilized by reaction that happens in presence of bromine or calcium tetrachloride as the catalyst which results in formation of ethylene bromide which in presence of highly efficient palladium as catalyst results in formation of stable ethene as byproduct. Thereby with formation of stable compound of ethylene, it releases zinc bromide as byproduct resulting completion of reaction equation. This stable product ethene is a double bonded carbon structure that is chemically extremely flammable and has planar structure.
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Hydrogen gas has a density of 0.090/gL, and at normal pressure and 0.214°C one mole of it takes up 22.4L. How would you calculate the moles in 370.g of hydrogen gas?
Set the math up. But don't do any of it. Just leave your answer as a math expression.
Also, be sure your answer includes all the correct unit symbols.
how to set up this equation?
moles= ???
Answer:
See below
Explanation:
370 g / .090 g/l = _____?___ liters
take that answer then :
? liters / 22.4 liters / mole = # moles done!
There are approximately 183.50 moles of hydrogen gas in 370.g of hydrogen gas.
The number of moles in 370.g of hydrogen gas using the given information.
In the given example,
Density of hydrogen gas = 0.090 g/L
Molar volume at normal pressure and 0.214°C = 22.4 L/mol
So, we calculate the volume of hydrogen gas (in L) using the given mass and density:
Volume (in L) = mass (in g) / density (in g/L)
Volume (in L) = 370.g / 0.090 g/L
Volume (in L) ≈ 4111.11 L
By using the molar volume, calculate the number of moles:
moles = Volume (in L) / Molar volume (in L/mol)
moles = 4111.11 L / 22.4 L/mol
moles ≈ 183.50 moles (rounded to two decimal places)
Hence, there are approximately 183.50 moles of hydrogen gas in 370.g of hydrogen gas.
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find the solubility of agcl in a 0.1M solution of cucl2.
ksp = 1.8x10^-10
The solubility of AgCl is 18 × [tex]10^-^1^0[/tex] in a 0.1M solution of CuCl₂.
The amount of a substance that can dissolve completely in a solvent at a specific temperature is known as its solubility. A saturated solution is one such example.
The maximum number of moles per liter of solution can be dissolved before the solution becomes saturated.
The equilibrium in the saturated solution will be as :
[tex]AgCl[/tex] ⇄ [tex]Ag ^+ + Cl ^-[/tex]
[tex]a[/tex] [tex]a[/tex] [tex]a[/tex]
[tex]CuCl_2[/tex] ⇄ [tex]Cu^2^+ + Cl^-[/tex]
[tex]0.1[/tex] [tex]0.1[/tex] [tex]0.1[/tex]
Ksp = [tex]1.8[/tex] × [tex]10^ -^1^0[/tex]
The solubility product constant: Ksp is the equilibrium constant for the dissolving of an ionic compound in water. Ksp is a function of temperature.
[tex]ksp AgCl = [ Ag ^+ ] [ Cl^-]\\[/tex]
[tex]= a[/tex]×[tex][ a + 0.1][/tex]
[tex]= a^2 + 0.1a[/tex]
[tex]a^2[/tex] is very small, so it is neglected.
ksp AgCl = 0.1a
[tex]1.8[/tex] × [tex]10^ -^1^0[/tex] = 0.1a
a = 18 × [tex]10^-^1^0[/tex]
Therefore, the solubility of AgCl is 18 × [tex]10^-^1^0[/tex].
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what is the purpose of adding concentrated phosphoric acid to the reaction mixture in the synthesis of aspirin
Concentrated phosphoric acid is added to the reaction mixture in the synthesis of aspirin to maintain the acidic environment and to keep the reagents protonated.
What is the phosphoric acid?Phosphoric acid is an inorganic acid with the molecular H₃PO₄.
Its a triprotic acid which means that one molecule of the acid produces 3 molecules of hydrogen ions.
Phosphoric acid is important for many laboratory as well as industrial uses. It can be serve as buffer in living organisms.
It also used in the synthesis of aspirin.
The synthesis of aspirin requires an acidic environment. Therefore, concentrated phosphoric acid is added to the reaction mixture in the synthesis of aspirin to maintain the acidic environment and to keep the reagents protonated.
In conclusion, Phosphoric acid ensures an acidic environment in the synthesis of aspirin.
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How many mL of a 0.193 M aqueous solution of ammonium bromide, , must be taken to obtain 8.42 grams of the salt?
Answer:
445 mL NH₄Br
Explanation:
(Step 1)
Convert grams ammonium bromide (NH₄Br) to moles using its molar mass.
Molar Mass (NH₄Br): 14.007 g/mol + 4(1.008 g/mol) + 79.904 g/mol
Molar Mass (NH₄Br): 97.943 g/mol
8.42 grams NH₄Br 1 mole
----------------------------- x ------------------------ = 0.0860 moles NH₄Br
97.943 grams
(Step 2)
Calculate the volume of NH₄Br using the molarity equation. Then, convert liters (L) to milliliters (mL).
Molarity (M) = moles / volume (L)
0.193 M = 0.0860 moles / volume
(0.193 M) x volume = 0.0860 moles
volume = 0.445 L
1,000 mL = 1 L
0.445 L NH₄Br 1,000 mL
------------------------ x ------------------ = 445 mL NH₄Br
1 L
At STP, 1 mole of gas has a molar volume of 22.4 L. What is the density (g/L) of oxygen at STP?
(Hint: find mass using PV=nRT) and find Density using d=m/v
A chemistry student needs 45.0mL of pentane for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of pentane is ·0.626gcm−3. Calculate the mass of pentane the student should weigh out. Round your answer to 3 significant digits.
The mass of pentane the student should weigh out is
The density of pentane is 0.626 gcm-3
To calculate the mass of pentane following expression is used,
(Density is defined as the mass divide by volume)
Density = mass / volume
mass of pentane = Density of pentane * Volume of pentane
mass of pentane = 0.626 gcm-3 * 45.0 mL
= 28.17 g
Here the unit of mass of pentane is g,
However the unit of density is gcm-3 and unit of volume is mL i.e. cm3
Hence, Mass = gcm-3 * cm3
Mass = g
The mass of pentane the student should weigh out is 28.17g
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Need the answer pretttty pleaseeeeee
Answer:
The answer would be D.
Explanation:
Whenever one has many of the same correlating numbers within in a pattern, the rest tend to follow. With the information I was given and not the actual plotting, that would be my answer.
Which of the following could be
considered an example of physical
contamination?
a. Pesticide contamination in food
b. Copper leeching into food during the
cooking process
c. A bandage falling into a prepared dish
d. Sanitizer getting onto a food product during
preparation
A bandage falling into a prepared dish could be considered an example of physical contamination.
Physical contamination occurs when a physical object enters food at some level of the manufacturing or preparation procedure. Physical objects in meals may be a choking hazard and regularly introduce biological contaminants as well.
It may arise at any stage of food delivery and preparation. Physical contamination can reason critical damage to the consumer, which includes broken teeth or choking. Varieties of contaminants that can be found in food include jewelry, hair, plastic, bones, stones, pest bodies, and material.
Chemical contamination takes place while food is infected through chemical compounds. Some of the reasons for chemical contamination are cleansing merchandise or pesticides and herbicides from unwashed fruit and vegetables. Examples of chemical contaminants are commercial chemical substances and agricultural chemicals.
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Urgent!!!
A 74.0-gram piece of metal at 94.0 °C is placed in 120.0 g of water in a calorimeter at 26.5 °C. The final temperature in the calorimeter is 32.0 °C. Determine the specific heat of the metal. Show your work by listing various steps, and explain how the law of conservation of energy applies to this situation.
The specific heat of the metal, given the data from the question is 0.60 J/gºC
Data obtained from the questionThe following data were obtained from the question:
Mass of metal (M) = 74 gTemperature of metal (T) = 94 °CMass of water (Mᵥᵥ) = 120 g Temperature of water (Tᵥᵥ) = 26.5 °C Equilibrium temperature (Tₑ) = 32 °C Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC Specific heat capacity of metal (C) =? How to determine the specific heat capacity of the metalThe specific heat capacity of the sample of gold can be obtained as follow:
According to the law of conservation of energy, we have:
Heat loss = Heat gain
MC(T –Tₑ) = MᵥᵥC(Tₑ – Tᵥᵥ)
74 × C(94 – 32) = 120 × 4.184 (32 – 26.5)
C × 4588 = 2761.44
Divide both side by 4588
C = 2761.44 / 4588
C = 0.60 J/gºC
Thus, the specific heat capacity of the metal is 0.60 J/gºC
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Heating up a reaction does which of the following:
Group of answer choices
A. Increases the number of collisions as well as the strength of the collision
B. Increases the strength of the collisions only.
C. Increases the number of collisions only.
D. No effect is found on the reaction by increasing the temperature.
Heating up a reaction does increase the number of collision only.
Hence, Option C is correct answer.
What is Collision Theory ?According to the collision theory, the reaction take place when the collision occur and molecules having sufficient energy or threshold energy for collision.
The collision of molecules depend on the kinetic energy of molecules. Greater the kinetic energy greater the number of molecules collide. Lesser the kinetic energy lesser will be collision.
How temperature affect the collision theory ?With an increase in temperature, there is an increase in energy that can be converted into activation energy in a collision, and that will increase the reaction rate. A decrease in temperature would have the opposite effect. With an increase in temperature, there is an increase in the number of collision.
Thus from the above conclusion we can say that Heating up a reaction does increase the number of collision only.
Hence, Option C is correct answer.
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In the chemical reaction:
Cu + 2AgNO3 → 2Ag + Cu(NO3)2
What is the limiting reactant if you start with 1.8 moles of copper and 2.0 moles of silver nitrate?
Group of answer choices
A. copper (II) nitrate
B. copper
C. silver
D. silver nitrate
Taking into account the reaction stoichiometry and definition of limiting reactant, AgNO₃ will be the limiting reagent.
Reaction stoichiometryIn first place, the balanced reaction is:
Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Cu: 1 moleAgNO₃: 2 molesAg: 2 molesCu(NO₃)₂: 1 moleLimiting reagentThe limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
Limiting reagent in this caseTo determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Cu reacts with 2 moles of AgNO₃, 1.8 moles of Cu reacts with how many moles of AgNO₃?
[tex]amount of moles of AgNO_{3} =\frac{1.8 moles of Cux2 moles of AgNO_{3} }{1 mole of Cu}[/tex]
amount of moles of AgNO₃= 3.6 moles
But 3.6 moles of AgNO₃ are not available, 2 moles are available. Since you have less moles than you need to react with 1.8 moles of Cu, AgNO₃ will be the limiting reagent.
SummaryIn summary, AgNO₃ will be the limiting reagent.
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Given the reaction:
Fe3+(yellow) + SCN-(colorless) <--> [FeSCN]2+(dark red)
If Fe3+ is added to the solution:
Group of answer choices
A. No changes in color occur
B. The solution turns darker red
C. The solution becomes colorless
D. The solution becomes more yellow
Fe3+(yellow) + SCN-(colorless) <--> [FeSCN]2+(dark red)
If Fe3+ is added to the solution the solution turns darker red
While precipitating out Fe3+ (as Fe(OH)3) or SCN- (as AgSCN) will push the equilibrium to the left, consuming the complex and reducing color intensity, the addition of Fe3+ or SCN- will push the equilibrium to the right, creating more complex and intensifying the color.
The pace of reaction rises as Fe3+ levels rise. The concentration of SCN reduces as the rate rises.
The FeSCN2+ complex, which is created when iron(III) and thiocyanate ions react, displays an extremely strong blood red color (or orange in diluted solution), making it simple to detect and quantify using spectrophotometry.
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what is the acid dissociation constant of an monoprotic acid if a concentration of 0.3M solution has a pH of 3?
The acid dissociation constant of a weak monoprotic acid if the concentration of the acid is 0.3M and it has a pH of 3 is 3 × 10⁻⁶.
What is the acid dissociation constant?The acid dissociation constant (Ka) is the equilibrium constant for an acid dissociation reaction.
Let's consider the acid dissociation of a generic weak acid.
HA(aq) = H⁺(aq) + A⁻(aq)
Step 1. Calculate [H⁺].The pH of the solution is 3.
pH = -log [H⁺]
[H⁺] = antilog -pH = antilog -3 = 1 × 10⁻³ M
Step 2. Calculate the acid dissociation constant (Ka).The concentration of the acid (Ca) is 0.3 M. For a weak monoprotic acid, we can calculate the acid dissociation constant using the following expression.
[H⁺] = √(Ca × Ka)
Ka = [H⁺]² / Ca
Ka = (1 × 10⁻³)² / 0.3 = 3 × 10⁻⁶
The acid dissociation constant of a weak monoprotic acid if the concentration of the acid is 0.3M and it has a pH of 3 is 3 × 10⁻⁶.
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what is s for silicon tetrachloride Sicl4?
S denotes the ''number of shared electron pairs by an atom'', Hence, Silicon transmits its 4 electrons with 4 Cl-atoms. Thus the Value of S is 4 in SiCl₄ .It is also known as covalency
What is silicon tetrachloride used for?
Silicon Tetrachloride is a transparent, colorless, fuming liquid with an irritating odor. It is used to create Silicon-containing chemicals and in chemical analysis. determine potentially hazardous frontages.
How is silicon tetrachloride produced?Silicon tetrachloride is designed by the chlorination of various silicon compounds such as ferrosilicon, silicon carbide, or mixtures of silicon dioxide and carbon. The ferrosilicon route is most familiar. In the laboratory, SiCl 4 can be prepared by dining silicon with chlorine on 600 °C (1,112 °F): Si + 2 Cl 2 → SiCl.
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Quick explanation please i'm having trouble
Two different atoms have nine protons each and the same mass. However, one is neutral while the other has a negative charge. Describe what each atomic structure could be, listing the possible number and location of all subatomic particles.
Convert the following measurement
The correct answer would be 0.034 g/L.
Unit conversionWhat we are trying to do here is to convert from milligram to gram and from deciliter to liter.
First, let's do the milligram to gram conversion.
1 mg = 0.001 g
Therefore,
3.4 mg = 3.4 x 0.001 = 0.0034 g
In order to convert from deciliter to liter.
1 deciliter = 0.1 L
Thus, 3.4 mg/dL = 0.0034g/0.1 L = 0.034 g/L
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A sample of a gas (15.0 mol) at 2.0 atm is expanded at constant temperature from 5 L to 19.5 L. calculate the final pressure.
Answer:
.512 ATM
Explanation:
P1V1 = P2V2
2 * 5 = P2 * 19.5
P2 = .512 ATM
ClO(4)− Express your answer as a chemical formula.
ClO(4)− is regarded as perchlorate ion and are produced commercially in most situations as salts via industries and in the laboratory.
What is Perchlorate ion?This ion is referred to as a monovalent inorganic anion and is obtained by deprotonation of perchloric acid. It is composed of chlorine and oxygen atoms in the ratio 1 to 4 respectively.
This has 32 valence electrons available in the Lewis structure and is used in the commercial production of solid rocket fuel.This ion has a molar mass of 99.451 g mol−1 and is used in different processes such as an oxidizer and to control static electricity during the process of food preservation in industries.
Therefore ClO₄− is also regarded as perchlorate ion and is the most appropriate choice.
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Most of the heat that’s melting the ice comes from the foil. That’s because metals are good conductors of heat. Heat from the surroundings flows into the foil and then from the foil into the ice. Draw arrows to show the amount and direction of heat transfer between the foil and the ice.
the rate of cooling decreases
Lab Data
Mass of magnesium (g)
Moles of magnesium (mol)
Temperature of water (°C)
Temperature of water (K)
Vapor pressure of water (mmHg)
Barometric pressure (mmHg)
Observations
Volume of hydrogen gas collected (mL)
Volume of hydrogen gas collected (L)
Pressure of hydrogen gas (mmHg)
Pressure of hydrogen gas (atm)
Moles of hydrogen gas produced (mol)
Ideal das constant (L-atm-mol-K)
0.218
-X
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LAB DATA SH
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Answer:
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What is the mass of a 5.00cm3 piece of copper having a density of 8.96g/cm3
Answer:
44.8 grams
Explanation:
The density exists as a ratio comparing the mass of a piece of copper per 1 cm³. Since you have been given a new volume, you can set up a proportion to find the new mass.
[tex]\frac{8.96 grams}{1.00 cm^3} =\frac{?grams}{5.00cm^3}[/tex] <----- Proportion
[tex]44.8 = (1.00cm^3)(?grams)[/tex] <----- Cross-multiply
[tex]44.8= ?grams[/tex] <----- Divide both sides by 1.00
28. What mass
0.120M HCI?
of Na₂CO3 (Molar Mass = 106.0 g/mol) is required to react completely with 21.6 mL of.
Mass of [tex]$\mathrm{Na}{2} \mathrm{CO} 3$[/tex] required [tex]$=0.55 \mathrm{~g}$[/tex]
What is meant by molar mass?The mass of one mole of a sample is its molar mass. Add the atomic masses (atomic weights) of all the atoms in the molecule to obtain the molar mass. Using the mass listed in the Periodic Table or atomic weights table, determine the atomic mass for each element.The total mass of all the atoms that make up a mole of a specific molecule, measured in grams, is known as the molar mass or molecular weight. The measurement is made in grams per mole.Molar mass is a crucial factor to consider while planning an experiment. The molar mass enables you to calculate the quantity you should weigh on your scale if you are testing theories involving precise amounts of a substance. Take a look at an experiment that needs 2 moles of pure carbon as an illustration.The mass 0.120M HCI:
Moles of [tex]$\mathrm{HCl}$[/tex]reacted [tex]$=0.120 \times 21.6 / 1000=0.00260$[/tex]
according to balanced reaction, [tex]$\mathrm{HCl}$ and $\mathrm{Na} 2 \mathrm{CO} 3$[/tex] reacts in [tex]$2: 1$[/tex] the ratio
moles of [tex]$\mathrm{Na} 2 \mathrm{CO} 3$[/tex]required [tex]$=0.00260 \times 2=0.00520$[/tex]
convert moles to mass
mass [tex]$=$[/tex]moles [tex]$\times$[/tex]molar mass
mass [tex]$=0.00520 \times 106.0$[/tex]
mass [tex]$=0.55 \mathrm{~g}$[/tex]
mass of [tex]$\mathrm{Na} 2 \mathrm{CO} 3$[/tex]required [tex]$=0.55 \mathrm{~g}$[/tex]
Mass 0.120M HC is [tex]$=0.55 \mathrm{~g}$[/tex]
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