The function f(x) = x2 6x 3 is transformed such that g(x) = f(x − 2). find the vertex of g(x).

The solutions to the given quadratic equation are as follows:

x = 1.10, x = 10.9.

A quadratic function is given according to the following rule:

[tex]y = ax^2 + bx + c[/tex]

The solutions are:

In which:

[tex]\Delta = b^2 - 4ac[/tex]

For this problem, the equation in item D is:

-x² + 12x - 12 = 0

x² - 12x + 12 = 0

Hence the coefficients are:

a = 1, b = -12, c = 12.

Then the solutions to the equation are found as follows:

The solutions are:

x = 1.10, x = 10.9.

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Answer:

following the (x,y) coordinate system,

(0,4) ; (1,1) ; (2,-2)

Step-by-step explanation:

youre given the value of the x variable in the table, so all you need to do is substitute x and follow pedmas!! hope this helps<3

The simplified form of the expression is given as 83x/56 -(97/105)

Alphabets are usually represented as unknown variables in a equation or expression.

Given the following expression shown below

6/7 x -2/3 + 3/5 + 5/8 x -6/7

Collect the like terms to have;

6/7 x+ 5/8 x  -2/3 + 3/5 -6/7

Simplify

48x+35x/56 - (70-63 + 90)/105

The final expression will be given as;

83x/56 -(97/105)

Hence the simplified form of the expression is given as 83x/56 -(97/105)

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Answer:

The answer is 3

Step-by-step explanation:

25% of 2.40 equals 0.6

so 3 will be the total price and he will get 0.6 profit.

William bought canned goods at 2.40 per can. he wants to increase the price per can so that he makes a 25% profit,  the selling price per can be, 3.00

The percentage is a mathematical term, which means a number or a ratio which is represented in fractions of 100. We use the '%' symbol to represent the percentage.

Formula for percentage;

Percentage = (present quantity/whole quantity)×100

Given that,

William bought canned goods at 2.40

He wants to increase the price per can so that he makes a 25% profit

The selling price per can be =?​

Percentage = Amount he wants to increase/previous amount×100

25 = x/2.40×100

x = 0.60

new selling price = 2.40+0.60

                             = 3.00

Therefore, The new selling price is 3.00 per can

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Hi there,

please see below for solution steps :

‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗

⨠ use the distributive property

[tex]\sf{7x-3(x-6)=30}[/tex]

[tex]\sf{7x-3x+18=30}[/tex]

⨠ combine like terms

[tex]\sf{4x+18=30}[/tex]

⨠ subtract both sides by 18

[tex]\sf{4x=30-18}[/tex]

[tex]\sf{4x=12}[/tex]

⨠ divide both sides by 4

[tex]\boxed{\sf x=3}[/tex]

‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗

The terms b⁸, a⁶ · b², a⁴ · b⁴, a⁷ · b and a⁸ are part of the expansion of (3 · a + 4 · b)⁸.

In this case, we have to expand a power binomial by means of the Pascal's triangle, which offers a useful and quick resource to expand expressions of this kind, now we proceed to present the result of this approach:

(3 · a + 4 · b)⁸ = 6 561 · a⁸ + 69 984 · a⁷ · b + 326 592 · a⁶ · b² + 870 912 · a⁵ · b³ + 1 451 520 · a⁴ · b⁴ + 1 548 288 · a³ · b⁵ + 1 032 192 · a² · b⁶ + 393 216 · a · b⁷ + 65 536 · b⁸

Such combinations of products between variables a and b are also supported by the theorem of the binomial. Finally, the terms b⁸, a⁶ · b², a⁴ · b⁴, a⁷ · b and a⁸ are part of the expansion of (3 · a + 4 · b)⁸.

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Answer:

Let m be the number of muffins.

a) 4m <= 30

b) m <= 7.5, so the maximum number of muffins to buy is 7.

c) $4 × 7 = $28, so $2 will be left over.

Answer:

22480.000

Step-by-step explanation:

Cost of 1km²=6000

So,

Cost of 4.08km²=6000x4.08

=22480.000

I don't know what nearest $100 means tho maybe nearest hundredth but I'm not sure.

The total cost nearest 100 is = $22500.

Modern mathematics heavily relies on the concept of area. The area is the quantity that shows the amount of space occupied by a two-dimensional figure or shape or planar lamina in the plane. Simply put, the area is the amount of cloth or other material with the specified thickness needed to build a model of the form or the quantity of paint required to cover the shape's surface in a single layer, or "coat," of paint.

Cost of 1km2 = 6000

So,

Cost of 4.08km2 = 6000 * 4.08

                              =  22480.000

Rounding off to 100;

Cost = 22500.00

Hence,

Total cost of the land nearest 100 is = $22500.

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The sampling method used is classified as Systematic.

Samples may be classified as:

In this problem, every 4th element is taken, which is a systematic sample with k = 4.

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Esta estrategia se puede aplicar sumando  15,75 + 0,25, –1,8 + –0,20, 3,5 + 12,5 y 2,62 + 7,38 antes de sumar el tercer número dado en cada caso.

La estrategia propuesta consiste en sumar dos números decimales que den como resultado un número entero antes de sumar el tercer número decima. Por ejemplo si teneos  1,4 + 0,6  + 1,2, se debe sumar primero 1,4 + 0,6 lo que es igual a 2 antes de sumar el 1,2.

Este estrategia es beneficiosa porque facilita sumar números decimales.

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Answer: D

Step-by-step explanation: a^2+b^2=c^2

so use y value for b2 and 6 square root 3 as a and check with it.

Answer:

The length of the diagonal of a rectangle is 10m

Step-by-step explanation:

There is a visual below,

The diagonal of a rectangle has formed 2 right triangles.

This diagonal is called hypotenuse side length of a triangle

To find the hypotenuse, we can use the Pythagorean Theorem

a² + b² = c²

we are given the length of a and b, where a = 6 and b = 8

(6)² + (8)² = c²

36 + 64 = c²

100 = c²

√100 = c

10 = c

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The expression, written as the sine of an angle is sin (7π/10)

From the question, we are to write the given expression as the sine or cosine of an angle.

The given expression is

sin(π/5)cos(π/2) + sin(π/2)cos(π/5)

Let A = π/5

and

B = π/2

Thus, we get

sinA cosB + sinB cosA

From the given information, we have that

sin(A ± B) = sinA cos B ± cosA sinB

∴ sin(A + B) = sinA cos B + cosA sinB

Now,

sinA cosB + sinB cosA = sinA cosB + cosA sin B

∴ sinA cosB + sinB cosA = sin (A + B)

Put A = π/5

and

B = π/2

sinπ/5 cosπ/2 + sinπ/2 cosπ/5 = sin (π/5 + π/2)

sinπ/5 cosπ/2 + sinπ/2 cosπ/5 = sin (7π/10)

Hence, the expression, written as the sine of an angle is sin (7π/10)

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Answer:

y = 3x + 4

Step-by-step explanation:

Substituting into point-slope form and converting to slope-intercept form,

[tex]y+5=3(x+3) \\ \\ y+5=3x+9 \\ \\ \boxed{y=3x+4}[/tex]

So by direct evaluation we can see that the limit when x tends to 2 is equal to 1.

Here we want to get the limit:

[tex]\lim_{x \to \ 2} \frac{x^2 + 3x + 1}{x^3 + x + 1}[/tex]

First, we can try to evaluate directly in x = 2 and see if it does not generate any problem, we will get:

[tex]\lim_{x \to \ 2} \frac{x^2 + 3x + 1}{x^3 + x + 1} = \frac{2^2 + 3*2 + 1}{2^3 + 2 + 1} = 1[/tex]

So by direct evaluation we can see that the limit when x tends to 2 is equal to 1.

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Recall the Pythagorean identity,

[tex]\sin^2(x) + \cos^2(x) = 1[/tex]

Use it to rewrite the equation in terms of cos only.

[tex]12 (1 - \cos^2(x)) + \cos(x) - 6 = 0[/tex]

[tex]-12 \cos^2(x) + \cos(x) + 6 = 0[/tex]

Factorize the left side.

[tex]-(3\cos(x) + 2) (4\cos(x) - 3) = 0[/tex]

Solve the two cases for [tex]\cos(x)[/tex].

[tex]3 \cos(x) + 2 = 0 \text{ or } 4\cos(x) - 3 = 0[/tex]

[tex]\cos(x) = -\dfrac23 \text{ or } \cos(x) = \dfrac34[/tex]

From the first equation, we get one family of solutions:

[tex]\cos(x) = -\dfrac23[/tex]

[tex]x = \cos^{-1}\left(-\dfrac23\right) + 2n\pi \text{ or } x = -\cos^{-1}\left(-\dfrac23\right) + 2n\pi[/tex]

From the second equation, we get another family:

[tex]\cos(x) = \dfrac34[/tex]

[tex]x = \cos^{-1}\left(\dfrac34\right) + 2n\pi \text{ or } x = -\cos^{-1}\left(\dfrac34\right) + 2n\pi[/tex]

where [tex]n[/tex] is an integer.

We get solutions in the given domain for

[tex]n = 0 \implies \boxed{x = \cos^{-1}\left(-\dfrac23\right)} \text{ or } \boxed{x = \cos^{-1}\left(\dfrac34\right)}[/tex]

[tex]n=1 \implies \boxed{x = 2\pi - \cos^{-1}\left(-\dfrac23\right)} \text{ or } \boxed{x = 2\pi - \cos^{-1}\left(\dfrac34\right)}[/tex]

Answer: x^{3}(2x+9)

Step-by-step explanation:

Eliminate redundant parentheses:

(3x^{4}+3x^{3}+5x^{2})-1(x^{4}-6x^{3}+5x^{2})

3x^{4}+3x^{3}+5x^{2}-1(x^{4}-6x^{3}+5x^{2})

Distribute:

^{4}+3x^{3}+5x^{2}{-1(x^{4}-6x^{3}+5x^{2})}

3x^{4}+3x^{3}+5x^{2}

Combine like terms UNTIL YOU FIND ONE FACTOR

An example of the real world example of a rational function would be when a person would decide to share a cookie with their friend. Each of them would get half of the cookie each.

This is the term that is used to refer to the fraction that is represented by the use of a rational fraction. That is there is denominator and a numerator.

The denominator must have a variable and this variable has to be of degree 1. Hence the real world example of a rational function would be when a person would decide to share a cookie with their friend. Each of them would get half of the cookie each.

First you have to know if it is an inequality or not. Then you have to assign x and y variables to numbers. From here you form an equation. This equation is plotted on a graph.

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by breaking it down u can write it as

15p^-4/_20p^-12 * q^-6/q^-3

15/-20=-3/4

using law of indices we have

-3/4p^-4+12 * q^-6+3

-3/4p^8q^-3

the answer is the first own

The expected error between the sample mean and the population mean is 3.

In this problem, we have been given :

population mean (μ) = 80,

standard deviation (σ) = 24,  

sample size (n) = 64

We know that,

The Central Limit Theorem states that, for a normally distributed random variable X, with mean μ and standard deviation σ, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean μ and standard deviation, which is also called standard error [tex]s=\frac{\sigma}{\sqrt{n} }[/tex]

We need to find the error between the sample mean and the population mean.

standard error

= σ /√n

= 24 /√64

= 24 / 8

= 3

Therefore, the expected error between the sample mean and the population mean = 3

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The total amount spent by Elsa and her friends must not exceed RM 475; 475 ≤ x

Elsa + 3(her friends) ≤ Total

145 + 3(110) ≤ x

145 + 330 < x

475 ≤ x

Therefore, the total amount spent by Elsa and her friends must not exceed RM 475; 475 ≤ x

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Answer:

=========================

Triangle with:

As per definition of midsegment, it is connecting the midpoints of two sides and its length is half the length of the opposite side of the triangle.

So we have:

Solve it for n:

Correct choice is D.

Answer:

Step-by-step explanation:

the graph is down below

The next step she should take is to use her ruler to join the given point to the point where the arcs intersect.

From this, we can deduce that her next step is to use her ruler to join the given point to the point where the arcs intersect

Thus, the next step she should take is to use her ruler to join the given point to the point where the arcs intersect.

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Answer:

(x-y)(x-y)(x-y)= x²-yx+x²-yx-yx+y²-yx+y²

2x²-4yx+2y²

(y-x)(y-x)= y²-yx-yx+x²

y²-2yx+x²

-(y²-2yx+x²) = -y²+2yx-x²

2x²-4yx+2y²-y²+2yx-x²= x²-2yx+y²

or

(x−y−1)(x−y)² ≡ x³−x²+3xy²+2xy−y³−y²−3yx³

Applying the knowledge of fractions, the number of cups of water that will fill a bottle of 3 liters is calculated as: 13.5 cups.

Fractions are numbers that indicate a part of whole numbers. For example, 2/9 of a liter means 2/9 of a part of 1 liter.

In math, a proportion is simply and equation that sets to ratios equal to each other.

To solve the problem given, create a proportion then use cross product to find the wanted value, which is the number of cups of water that can be filled into a 3-liter bottle.

Let x represent the cups of water we are looking for.

1 cup = 2/9 liter

x = 3 liters

We would have:

(1)(3) = (2/9)(x)

3 = 2x/9

(3)(9) = 2x

27/2 = x

x = 13.5

The number of cups of water to fill a 3-liter bottle is: 13.5.

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The measure of the angle rst is [tex]105^{o}[/tex].

According to the theorem, a quadrilateral can be inscribed by a circle if and only if its opposing angles are supplementary. A quadrilateral that may be encircled by a circle is known as a cyclic quadrilateral.

The sum opposite angles of a quadrilateral is 180 degrees.

We can see that the angles rst and angle tqr are opposite angles of quadrilateral qrst, hence supplementary angles.

Therefore,

<RST + <TQR = 180

5x+15 + 4x+ 3 = 180

9x + 18 = 180

9x = 180 - 18

9x = 162

x = 162/9

x = 18

Since <RST = 5x+15

<RST = 5(18) + 15

<RST = 90 + 15

<RST = 105degrees

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The option that can be used to support the idea that the set of polynomials is closed under multiplication is; Option C: (10x^(0.5) - 8)(5x^(0.5) + 4)

When multiplying polynomials, the variables' exponents are added, according to the rules of exponents. It is pertinent to note that the exponents in polynomials are whole numbers. The whole numbers are closed under addition, which guarantees that the new exponents will be whole numbers. Thus, we can also say that the polynomials are closed under multiplication.

Now, looking at the options, we can say that option C is the only polynomial that is closed under multiplication because its' variables and exponents will not change;

(10x^(0.5) - 8)(5x^(0.5) + 4)

The output will retain the same thing.

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Answer:

  (2, 2) ⇒ (-2, 2)

  (-5, 6) ⇒ (-6, -5)

  (2, 6) ⇒ (-6, 2)

  (-5, 2) ⇒ (-2, -5)

Step-by-step explanation:

The new coordinates can be found using the transformation function for figures rotated 90° about the origin.

Rotation 90° (counterclockwise) about the origin can be described by ...

  (x, y) ⇒ (-y, x)

The end points of the diagonal that comes closest to the origin will be transformed to ...

  (2, 2) ⇒ (-2, 2)

  (-5, 6) ⇒ (-6, -5)

The other diagonal end points will be on the same horizontal and vertical lines as these.

  (2, 6) ⇒ (-6, 2)

  (-5, 2) ⇒ (-2, -5)