help! awarding 20 points ​

Answer:

d

Explanation:

d

Based on our finding these two compounds are not same they are completely different from each other as Formula of both compounds are different, their appearance is also different from each other.

The formula of the Iron II oxide is FeO. Common name of Iron (II) Oxide is Ferrous Oxide. Iron (II) Oxide is a black colored powder. The mineral form of Iron (II) oxide is known as Wustite. Iron (II) Oxide is used as a pigment. It is also used to make dyes.

The formula of the Iron (III) Oxide is Fe₂O₃. Common name of Iron (III) Oxide is Ferric oxide. Iron (III) Oxide appears as Red-Brown solid. It is also known as Hematite. Iron (III) oxide is used as pigments. It is used in dental composites , cosmetics. It is also used to apply the final polish on metallic jewellery.

Thus from the above conclusion we can say that Based on our finding these two compounds are not same they are completely different from each other as Formula of both compounds are different, their appearance is also different from each other.

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Organic transformation sequential equation using catalysts will be as follows:

2CH3-CH2-O => (alc. KOH) => CH2=CH2 + KCl + H2O => (Br2/CCl4) => CH2Br-CH2Br + Zn

CH2Br-CH2Br + Zn => (HBr /Pd) => CH2=CH2+ZnBr2

As can be visualized from above organic transformation equation, conversion of dry ether in presence of alkaline potassium hydroxide results in formation of unstable ethene. This dry unsaturated compound of ethene is stabilized by reaction that happens in presence of bromine or calcium tetrachloride as the catalyst which results in formation of ethylene bromide which in presence of highly efficient palladium as catalyst results in formation of stable ethene as byproduct. Thereby with formation of stable compound of ethylene, it releases zinc bromide as byproduct resulting completion of reaction equation. This stable product ethene is a double bonded carbon structure that is chemically extremely flammable and has planar structure.

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Concentrated phosphoric acid is added to the reaction mixture in the synthesis of aspirin to maintain the acidic environment and to keep the reagents protonated.

Phosphoric acid is an inorganic acid with the molecular H₃PO₄.

Its a triprotic acid which means that one molecule of the acid produces 3 molecules of hydrogen ions.

Phosphoric acid is important for many laboratory as well as industrial uses. It can be serve as buffer in living organisms.

It also used in the synthesis of aspirin.

The synthesis of aspirin requires an acidic environment. Therefore, concentrated phosphoric acid is added to the reaction mixture in the synthesis of aspirin to maintain the acidic environment and to keep the reagents protonated.

In conclusion, Phosphoric acid ensures an acidic environment in the synthesis of aspirin.

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The first step in clearing a clogged ballpoint pen is to exert additional pressure when scrawling and drawing vertical lines on paper. If this approach doesn't work, dip the pen's tiny tip in rubbing alcohol. [Only the tidbit] Any dried-up or hardened ink on the tip will dissolve with this.

Heating up a reaction does increase the number of collision only.

Hence, Option C is correct answer.

According to the collision theory, the reaction take place when the collision occur and molecules having sufficient energy or threshold energy for collision.

The collision of molecules depend on the kinetic energy of molecules. Greater the kinetic energy greater the number of molecules collide. Lesser the kinetic energy lesser will be collision.

With an increase in temperature, there is an increase in energy that can be converted into activation energy in a collision, and that will increase the reaction rate. A decrease in temperature would have the opposite effect. With an increase in temperature, there is an increase in the number of collision.

Thus from the above conclusion we can say that Heating up a reaction does increase the number of collision only.

Hence, Option C is correct answer.

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Explanation:

Reasons why you should not dispose of chemicals down drains

Pipes, especially older pipes, can leak at connections or where they have been damaged. Often large pipes, like storm water pipes or really large sewage mains, are made out of concrete so at places where two pipes meet, there can be minor leaks. It’s not a big deal when it’s just a little bit of storm water leaking, but if chemicals are also in this water, you’ve just given them a direct path to contaminating drinking water! Also, some of Indianapolis’s infrastructure is very old, and pipes used to be made out of things like bricks and hollowed out trees which will also leak.

Disposing of chemicals down drains can damage your plumbing which can be expensive to repair and also allow those chemicals a direct path into the groundwater.

Improperly disposing of chemicals at your site can lead to environmental contamination of your site which can be time consuming and expensive to clean up.

Answer:

80.5%

Explanation:

The percent yield is made up of the theoretical yield and actual yield. The theoretical yield is the amount of product produced from the balanced chemical equation and molar masses. The actual yield is the amount of product produced in an experiment.

To find the percent yield, you need to (1) convert grams C₃H₈ to moles C₃H₈ (via molar mass), then (2) convert moles C₃H₈ to moles CO₂ (via mole-to-mole ratio from equation coefficients), then (3) convert moles CO₂ to grams CO₂ (via molar mass), and then (4) calculate the percent yield. It is important to arrange the conversions/ratios in a way that allows for the cancellation of units.

(Steps 1 - 3)

Molar Mass (C₃H₈): 3(12.01 g/mol) + 8(1.01 g/mol)

Molar Mass (C₃H₈): 44.11 g/mol

Molar Mass (CO₂): 12.01 g/mol + 2(16.0 g/mol)

Molar Mass (CO₂): 44.01 g/mol

1 C₃H₈ + 5 O₂ -----> 3 CO₂ + 4 H₂O

296 g C₃H₈           1 mole            3 moles CO₂           44.01 g
-------------------  x  ----------------  x  ----------------------  x  ----------------  =  886 g CO₂
                               44.11 g            1 mole C₃H₈            1 mole

(Step 4)

                                  Actual Yield
Percent Yield  =  ------------------------------  x  100%
                              Theoretical Yield

                                713 g CO₂
Percent Yield  =  ----------------------  x  100%
                                886 g CO₂

Percent Yield  =  80.5%

Answer:

2 Al and 3 S

Explanation:

Al2S3 so 2 Al and 3 S

No, the mass does not change.

Freezing is a change in physical state, not a chemical reaction. No matter is added or taken away.

As water transitions to ice, no molecules are lost; it is boiling so it is not turning into a gas. There is a very, very small amount of mass lost in the form of energy as the water loses it's heat, but this amount of mass is so insignificant it practically can't be measured. In other words, it's negligible.

Hydrohalogenation Reaction:

The substitution of hydrogen and halide levels across a double bond takes place. The halide group is connected to the carbon with more substituents. The product will affect by the presence of peroxide

Ethene is a symmetrical alkene having two carbon atoms. It reacts with HBr in the presence of CCl4, producing bromoethane or ethyl bromide (CH3CH2Br). Propene is an unsaturated alkene consisting of a three-carbon chain with two carbon particles on either side of the double bond.

Ethene is a symmetrical alkene including two carbon atoms. It reacts with HBr in the presence of CCl4, producing bromoethane or ethyl bromide (CH3CH2Br). Propene is an unsaturated alkene consisting of a three-carbon chain with two carbon atoms on either flank of the double bond.

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The solubility of AgCl is 18 × [tex]10^-^1^0[/tex] in a 0.1M solution of CuCl₂.

The amount of a substance that can dissolve completely in a solvent at a specific temperature is known as its solubility. A saturated solution is one such example.

The maximum number of moles per liter of solution can be dissolved before the solution becomes saturated.

The equilibrium in the saturated solution will be as :

[tex]AgCl[/tex] ⇄ [tex]Ag ^+ + Cl ^-[/tex]

 [tex]a[/tex]           [tex]a[/tex]         [tex]a[/tex]

[tex]CuCl_2[/tex] ⇄ [tex]Cu^2^+ + Cl^-[/tex]

  [tex]0.1[/tex]        [tex]0.1[/tex]          [tex]0.1[/tex]

Ksp = [tex]1.8[/tex] × [tex]10^ -^1^0[/tex]

The solubility product constant: Ksp is the equilibrium constant for the dissolving of an ionic compound in water. Ksp is a function of temperature.

[tex]ksp AgCl = [ Ag ^+ ] [ Cl^-]\\[/tex]

             [tex]= a[/tex]×[tex][ a + 0.1][/tex]

             [tex]= a^2 + 0.1a[/tex]

[tex]a^2[/tex] is very small, so it is neglected.

ksp AgCl = 0.1a

[tex]1.8[/tex] × [tex]10^ -^1^0[/tex] = 0.1a

a = 18 × [tex]10^-^1^0[/tex]

Therefore, the solubility of AgCl is 18 × [tex]10^-^1^0[/tex].

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Answer:

the half life of reaction is 2 hours which is consist half life of consist in the first order reaction has the order reaction is one

Answer:

Δx(m.Δv)=h/4π

here ,

Δv = uncertainty in velocity

10−11×10−27×Δv=6.626×10−34/4×22/7

=5.25×103ms−1

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

According to Heisenberg's uncertainty principle :

[tex]\qquad \sf  \dashrightarrow \: \Delta x \Delta p \geqslant \cfrac{h}{4 \pi} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \Delta x \cdot m \Delta v \geqslant \cfrac{h}{4 \pi}[/tex]

[tex]\qquad \sf  \dashrightarrow \: \Delta v \geqslant \cfrac{h}{4 \pi \cdot m \Delta x}[/tex]

[tex]\qquad \sf  \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 \times 10 {}^{ - 34} }{4 \pi \cdot 10 {}^{ - 27} \times 10 {}^{ - 3} \times 10 {}^{ - 11} }[/tex]

[tex] \textsf{ [ we took } [/tex][tex]{ {10}^{-3} } [/tex][tex] \textsf{because mass of electron is} [/tex][tex] \textsf{ given in grams that need to be converted into kg ]} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 }{4 \pi } \times \cfrac{10 {}^{ - 34} } {10 {}^{ (- 27 - 3 - 11)} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 }{4 \times 3.14 } \times \cfrac{10 {}^{ - 34} } {10 {}^{ - 41} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 }{4 \times 3.14 } \times {10 {}^{ 7}}[/tex]

[tex]\qquad \sf  \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 }{12.56 } \times {10 {}^{ 7}}[/tex]

[tex]\qquad \sf  \dashrightarrow \: \Delta v \geqslant0.525\times {10 {}^{ 7}}[/tex]

[tex]\qquad \sf  \dashrightarrow \: \Delta v \geqslant5.25\times {10 {}^{ 6}} \:\:m/s[/tex]

The specific heat of the metal, given the data from the question is 0.60 J/gºC

The following data were obtained from the question:

The specific heat capacity of the sample of gold can be obtained as follow:

According to the law of conservation of energy, we have:

Heat loss = Heat gain

MC(T –Tₑ) = MᵥᵥC(Tₑ – Tᵥᵥ)

74 × C(94 – 32) = 120 × 4.184 (32 – 26.5)

C × 4588 = 2761.44

Divide both side by 4588

C = 2761.44 / 4588

C = 0.60 J/gºC

Thus, the specific heat capacity of the metal is 0.60 J/gºC

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Answer:

0.645 L

Explanation:

To find the volume, you need to (1) convert grams to moles (using the molar mass) and then (2) calculate the volume (using the molarity ratio). The final answer should have 3 sig figs to match the sig figs of the given values.

(Step 1)

Molar Mass (KOH): 39.098 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (KOH): 56.104 g/mol

19.9 grams KOH              1 mole
--------------------------  x  -----------------------  =  0.355 moles KOH
                                     56.014 grams

(Step 2)

Molarity = moles / volume                            <----- Molarity ratio

0.550 M = 0.355 moles / volume                 <----- Insert values

(0.550 M) x volume = 0.355 moles              <----- Multiply both sides by volume

volume = 0.645 L                                          <----- Divide both sides by 0.550

The volume of 15.7 M H2SO4 is required to prepare 12.0 L of 0.156 M sulfuric acid is 0.12 L

From the question given above, the following data were obtained:

The volume of the stock solution needed can be obtained by using the dilution formula as shown below:

M₁V₁ = M₂V₂

15.7 × V₁ = 0.156 × 12

15.7 × V₁ = 1.872

Divide both side by 15.7

V₁ = 1.872 / 15.7

V₁ = 0.12 L

Thus, the volume of the stock solution needed to prepare the solution is 0.12 L

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C2H4 is oxidized and O2 is reduced in both reactions.

Oxidation is defined in several ways. Some of the definitions are:

Reduction, on the other hand, is defined as:

In the two reactions, oxygen is being added to C2H4. Thus, C2H4 is being oxidized.

The oxidizing agent is O2. In oxidation reactions, the oxidizing agents usually get reduced. Thus, O2 is reduced in both reactions.

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The correct answer would be 0.034 g/L.

What we are trying to do here is to convert from milligram to gram and from deciliter to liter.

First, let's do the milligram to gram conversion.

1 mg = 0.001 g

Therefore,

3.4 mg = 3.4 x 0.001 = 0.0034 g

In order to convert from deciliter to liter.

1 deciliter = 0.1 L

Thus, 3.4 mg/dL = 0.0034g/0.1 L = 0.034 g/L

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Answer:

2.34 gms left

Explanation:

3 weeks = 21 days   =    7 half lives

300 * (1/2)^7 = 2.34 gms

The directions that are likely to result in a warmer earth are the directions 3, 5 and 6.

The term global warming has to do with the gradual rise in the temperature of the earth as a result of the re-radiation of infrared rays back to the earth. We know that greenhouse gases are able to trap the infrared rays from the sun and reradiate same to the surface of the earth and this ultimately leads to a warmer earth.

As such, if we look at the image closely, we can see that there is a reradiation of the rays to the earth in the directions 3, 5 and 6. It then follows that the directions that are likely to result in a warmer earth are the directions 3, 5 and 6.

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The mass of pentane the student should weigh out is

The density of pentane is 0.626 gcm-3

To calculate the mass of pentane following expression is used,

(Density is defined as the mass divide by volume)

Density = mass / volume

mass of pentane = Density of pentane * Volume of pentane

mass of pentane = 0.626 gcm-3 * 45.0 mL

                             = 28.17 g

Here the unit of mass of pentane is g,

However the unit of density is gcm-3 and unit of volume is mL i.e. cm3

Hence,   Mass = gcm-3 * cm3

              Mass = g

The mass of pentane the student should weigh out is 28.17g

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Fe3+(yellow) + SCN-(colorless) <--> [FeSCN]2+(dark red)

If Fe3+ is added to the solution the solution turns darker red

While precipitating out Fe3+ (as Fe(OH)3) or SCN- (as AgSCN) will push the equilibrium to the left, consuming the complex and reducing color intensity, the addition of Fe3+ or SCN- will push the equilibrium to the right, creating more complex and intensifying the color.

The pace of reaction rises as Fe3+ levels rise. The concentration of SCN reduces as the rate rises.

The FeSCN2+ complex, which is created when iron(III) and thiocyanate ions react, displays an extremely strong blood red color (or orange in diluted solution), making it simple to detect and quantify using spectrophotometry.

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A bandage falling into a prepared dish could be considered an example of physical contamination.

Physical contamination occurs when a physical object enters food at some level of the manufacturing or preparation procedure. Physical objects in meals may be a choking hazard and regularly introduce biological contaminants as well.

It may arise at any stage of food delivery and preparation. Physical contamination can reason critical damage to the consumer, which includes broken teeth or choking. Varieties of contaminants that can be found in food include jewelry, hair, plastic, bones, stones, pest bodies, and material.

Chemical contamination takes place while food is infected through chemical compounds. Some of the reasons for chemical contamination are cleansing merchandise or pesticides and herbicides from unwashed fruit and vegetables. Examples of chemical contaminants are commercial chemical substances and agricultural chemicals.

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Salt-water that dehydrates someone who drinks is NOT an example of a colligative property (Option D).

Colligative Properties make reference to physical properties associated with solute concentration instead of its intrinsical characteristics.

Some examples of colligative properties include boiling state, vapour pressure, and osmotic pressure due to the presence of ionic particles.

In conclusion, salt-water that dehydrates someone who drinks is NOT an example of a colligative property (Option D).

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Answer:

Explanation:

Greetings !

The electronic configuration 1s²,2s²,2p⁶,3s²,3p³ represents phosphorus with atomic number 15.

The electron configuration 1s², 2s², 2p⁶, 3s², 3p³ corresponds to the element phosphorus. The first two shells are full, with 2 electrons in each shell. The third shell has 2 electrons in the 3s subshell and 3 electrons in the 3p subshell. Hence option D is correct.

Phosphorus is a chemical element with the symbol P and atomic number 15. It belongs to Group 15 (or Group V) of the periodic table, which is also known as the nitrogen group. Here are some key features and characteristics of phosphorus:

Phosphorus is a non-metal, and at room temperature, it exists in several allotropes. The most common forms are white phosphorus, red phosphorus, and black phosphorus.

White phosphorus is a highly reactive and toxic waxy solid, while red phosphorus is less reactive and is often used in safety matches. Black phosphorus is a semiconductor material with interesting electronic properties.

Therefore option D) phosphorous is correct.

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The acid dissociation constant of a weak monoprotic acid if the concentration of the acid is 0.3M and it has a pH of 3 is 3 × 10⁻⁶.

The acid dissociation constant (Ka) is the equilibrium constant for an acid dissociation reaction.

Let's consider the acid dissociation of a generic weak acid.

HA(aq) = H⁺(aq) + A⁻(aq)

The pH of the solution is 3.

pH = -log [H⁺]

[H⁺] = antilog -pH = antilog -3 = 1 × 10⁻³ M

The concentration of the acid (Ca) is 0.3 M. For a weak monoprotic acid, we can calculate the acid dissociation constant using the following expression.

[H⁺] = √(Ca × Ka)

Ka = [H⁺]² / Ca

Ka = (1 × 10⁻³)² / 0.3 = 3 × 10⁻⁶

The acid dissociation constant of a weak monoprotic acid if the concentration of the acid is 0.3M and it has a pH of 3 is 3 × 10⁻⁶.

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the rate of cooling decreases

The equation of line q is determined as y =  ¹/₈x - ⁹/₄.

The slope of a line is the change in y axis to change in x axis.

y = – 8x + 6

from general line equation, y = mx + c

where;

m = - 8

m₂ = -1/m

m₂ = -1/-8

m₂ = 1/8

(y - y₁) / (x - x₁) = m₂

(y + 2)/(x - 2) = 1/8

y + 2 = ¹/₈(x - 2)

y + 2 = ¹/₈x -  ¹/₄

y = ¹/₈x - ⁹/₄

Thus, the equation of line q is determined as y =  ¹/₈x - ⁹/₄.

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