Resolver xfa... El taller trata de division de polinomios o algo asi

Answer:

x=1.08 (3SF)

Step-by-step explanation:

hope it helps!!!!

Solving a system of equations, we conclude that the value of x is 28.

Here we have the quadratic number pattern:

6, 15, x, 45, ...

First, we have that:

15 - 6 = 9

So 9 is the first difference.

Then we will have:

x = 15 + 9 + a

(where a is the second difference, constant of the sequence).

And:

45 = x + 9 + a + a

Then we have a system of equations:

x = 15 + 9 + a

45 = x + 9 + a + a

We can isolate a on the first equation:

a = x - 24

We can replace that in the other equation:

45 = x + 9 + 2a

45 = x + 9 + 2*(x - 24)

Now we can solve that for x:

45 - 9 = x + 2*(x - 24)

36 = 3x - 48

36 + 48 = 3x

84 = 3x

84/3 = x = 28

The value of x is 28.

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Answer:

x = 12

Step-by-step explanation:

1 + 7x = 5x + 25 ( subtract 5x from both sides )

1 + 2x = 25 ( subtract 1 from both sides )

2x = 24 ( divide both sides by 2 )

x = 12

Answer:

12

Step-by-step explanation:

Start by subtracting both sides by 5x:

[tex]1+7x-5x=25\\1+2x=25[/tex]

Subtract 1 from both sides

[tex]2x=24[/tex]

Divide both sides by 2

[tex]x=12[/tex]

[tex]1+7(12)=5(12)+25\\1+84=60+25\\85=85[/tex]

Therefore x = 12

Answer:

x = 8

Step-by-step explanation:

→ Add 16 to both sides

x = 8

The correct solution for the given expression [tex]-16+x = -8 \\[/tex]  is [tex]x[/tex] is equal to [tex]8[/tex].

Given expression:

[tex]-16+x =- 8 \\[/tex]

To solve for [tex]x[/tex], Rearrange the equation or isolate [tex]x[/tex] terms on one side of the expression.

Add [tex]8[/tex] on both side of the equation:

[tex]-16+x+8=-8+8[/tex]

Simplify:

[tex]x-8 = 0[/tex]

Isolate [tex]x[/tex] on one side:

[tex]x= 8[/tex]

The correct value of [tex]x[/tex] is [tex]8[/tex].

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Answer:

Below in bold,

Step-by-step explanation:

a. There's is only one card that fits this description so

Probability = 1/52.

b. There are 2 black Kings so

Probability = 2/52 = 1/26.

c. There are 2 of these - 7 of diamonds and 7 of hearts

so

Probability = 2/52 = 1/26.

d.  There 13 diamonds and 13 hearts so

Probability = 26/52 = 1/2.

e.  There  26 black cards

Probability = 26/52 = 1/2.

It is discovered using its notion that the domain and range of the function are given by (C) D: [–4, ∞) and R: [0, ∞).

To find the domain and range:

Therefore, it is discovered using its notion that the domain and range of the function are given by (C) D: [–4, ∞) and R: [0, ∞).

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The complete question is given below:

What are the domain and range of g of x equals the square root of the quantity x plus 4?

(A) D: [4, ∞) and R: [0, ∞)

(B) D: (–4, ∞) and R: (–∞, 0)

(C) D: [–4, ∞) and R: [0, ∞)

(D) D: (4, ∞) and R: (–∞, 0)

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies \begin{array}{llll} y+4=4(x-3)\implies y-(\stackrel{y_1}{-4})=\stackrel{m}{4}(x-\stackrel{x_1}{3})\\\\ ~\hfill (\stackrel{x_1}{3}~~,~~\stackrel{y_1}{-4}) \end{array}[/tex]

Answer:

Step-by-step explanation:

Answer: 16.8°C

Answer:

y=1

Step-by-step explanation:

Since you already found x,

We will only be needing one equation to find y..

I will take equation two: 3(2)+2y=8

Step Two: 6+2y=8 (then you minus 6 on each side)

Step Three: 2y=2 (divide)

y=1

If Mary measures the angle of elevation from a point A, to be 10°. She then walks 100m directly towards the tower, and finds the angle of elevation from the new point B to be 20°, the height of the tower comes out to be 37 meters.

Given Information and Formula Used:

The angle of elevation of the tower from point A (a in figure) = 10°

The angle of elevation of the tower from point B (b in figure) = 20°

The distance AB (ab n figure) = 100m

In right triangle adc, tan 10° = cd / ad ....... (1)

In right triangle bdc, tan 20° = cd / bd ......... (2)

Here, cd is the height of the tower.

Let the distance bd be x, then the ad = x + 100

Substituting this value of of ad in equation (1), we get,

tan 10° = cd / (x+100)

x+100 = cd / tan 10°

x+100 = cd / 0.18

x+100 = 5.6 cd ....... (3)

From equation (2),

tan 20° = cd / x

x = cd / tan 20°

x = cd / 0.34

x = 2.9 cd

Putting this value of x in equation (3), we obtain the height cd (or CD) as,

2.9 cd + 100 = 5.6 cd

(5.6 - 2.9)cd = 100

2.7cd = 100

cd = 100/2.7

cd ≈ 37m (To the nearest tenth of a meter)

Therefore, the height of the tower is calculated to be 37 meters.

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His body temperature in the evening is 102.6 °F

The given parameters are:

Temperature in the morning = 99.2°F.

Temperature increase = 3.4°F.

His body temperature in the evening is calculated as:

New = Temperature in the morning + Temperature increase

So, we have

New = 99.2°F +  3.4°F

Evaluate the sum

New = 102.6 °F

Hence, his body temperature in the evening is 102.6 °F

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The probability of getting a reading between 1.50 and 2.25 is; 0.00546

We are given the following information in the question:

Mean; μ = 0 °C

Standard Deviation; σ = 1 °C

We are given that the distribution of thermometer readings is a bell shaped distribution that is a normal distribution.

Formula for z-score is;

z = (x' - μ)/σ

P(Between 1.50 degrees and 2.25 degrees) is expressed as;

P(1.5 ≤ x ≤ 2.25)

= P((1.5 - 0)/1 ≤ z ≤ (2.25 - 0)/1))

= P(z ≤ 2.25) -  P(z < 1.5)

= 0.0546 = 5.46%

The graph that correctly describes this is the first graph

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The missing length indicated on the right triangle is 120 units

To start with:

The missing length in the right triangle can be represented with the variable x

Next, we have the following equivalent ratio from the given triangle

64 : x = x : 289 - 64

Express the ratio as a fraction

64/x = x/(289 - 64)

Evaluate the difference on the right-hand side

64/x = x/225

Cross multiply in the above equation

x * x = 64 * 225

This gives

x^2 = 64 * 225

Take the square root of x^2 (do not approximate)

x = 64 * 225

Take the square root of 64 and 225 (do not approximate)

x = 64 * 225

Evaluate the product of 8 and 5

x = 120

Based on the given parameters, the missing length indicated on the right triangle is 120 units

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First symmetrically cut the pentagon to get 5 pieces. (So that you will get the idea that this polygon is divided into 5 triangles)

Then find the area of one of the triangles:

Area of Triangle = [tex]\frac{1}{2} bh[/tex]

A = [tex]\frac{1}{2}[/tex] × 4 × 10

A = 20 m²

To find the area of the whole pentagon shape:

A = 20 × 5 = 100 m²

Hope it helps!

Answer:

13. Two real solutions.

14. No real solutions.

Step-by-step explanation:

Given quadratic equations:

13. [tex]x^2+7x+10=0[/tex]

14. [tex]4x^2-3x+4=0[/tex]

[tex]{\large \textsf{Quadratic Formula: }} x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\ \Bigg{\|}\ \textsf{when }ax^2+bx+c=0[/tex]

What is the discriminant?

The discriminant (Δ) is b² - 4ac, which is under the square root in the quadratic formula. It is used to determine the number of real solutions (roots) of a quadratic:

13. x² + 7x + 10 = 0

[tex]\implies a=\textsf{1},b=\textsf{7},c=\textsf{10}[/tex]

Find the discriminant value.

[tex]\implies \Delta = b^2 - 4ac[/tex]

[tex]\implies \Delta=(7)^2 - 4(1)(10)[/tex]

[tex]\implies \Delta=49 - 40[/tex]

[tex]\implies \Delta=9[/tex]

As [tex]9[/tex] > 0, this quadratic has two real solutions.

14. 4x² - 3x + 4 = 0

[tex]\implies a=\textsf{4},b=\textsf{-3},c=\textsf{4}[/tex]

Find the discriminant value.

[tex]\implies \Delta = b^2 - 4ac[/tex]

[tex]\implies \Delta = (-3)^2 - 4(4)(4)[/tex]

[tex]\implies \Delta = 9 - 64[/tex]

[tex]\implies \Delta = -55[/tex]

As [tex]-55[/tex] < 0, this quadratic has no real solutions.

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100–pound earthling's weight on Saturn using the proportion is (B)

15/4 = 100/x.

To find the 100–pound earthling's weight on Saturn using the proportion:

Therefore, 100–a pound earthling's weight on Saturn using the proportion is (B) 15/4 = 100/x.

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The correct question is given below:
A bowling ball weighs 15 pounds on earth and weighs 4 pounds on the planet Saturn. you could determine a 100–pound earthling's weight on Saturn using the proportion:

a. start fraction 15 over 4 end fraction = start fraction x over 100 end fraction

b. startfraction 15 over 4 endfraction = 100 over x endfraction

c. startfraction 4 over 15 endfraction = startfraction 100 over x endfraction

d. either a or c

The data set in discuss which contains three points and two of the residuals are 7 and -3 would have its third residual as; -4.

According.tinthe task content, the data set in discuss has three points and consequently should have three residuals.

Additionally, two of the three residuals have been given and on this note, it follows that the third residual must have a value such that the algebraic sum of all residuals is 0.

Hence, we have; -3 + 7 +x = 0;

x = 3-7 = 4.

Ultimately, the third residual is; -4.

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Answer:

-4

Step-by-step explanation:

We are going to substitute 0 in for x and solve for y.  

-2(0)+ 8y = -32  Anything times zero is zero

0 + 8 y = -32  Anything plus zero is itself.

8y = -32 Divide both sides by 8

y = -4

The factors of the trinomial are:

Options C and E

This is further explained below.

Generally, A trinomial is a kind of polynomial that is used in basic mathematics. It is composed of three components, also known as monomials.

In conclusion, The following expressions are the components of the trinomial: x - 7, x + 2

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Correct match for the quadratic equation are:

A. {-4, 4}

B.  {-5, 5}

C.  {-8, 8}

D.  {-11, 11}

E.  {3,-3}

An algebraic equation of the second degree in x is a quadratic equation. The quadratic equation is written as ax² + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term.

2x² - 32 = 0

Adding thirty-two to both sides of the equation:

2x² = 32

Dividing between two on both sides of the equation:

x² = 322

x² = 16

Applying square root to eliminate the exponent:

x =  ±√16

x =  ±4

4x² - 100 = 0

Adding hundred to both sides of the equation:

4x² = 100

Dividing between four on both sides of the equation:

x² = 100/4

x² = 25

Applying square root to eliminate the exponent:

x = ±√25

x = ±5

x² - 55 = 9

Adding fifty-five to both sides of the equation:

x² = 9 + 55

x² = 64

Applying square root to eliminate the exponent:

x = ±√64

x =  ±8

x² - 140 = -19

Adding one- fourty to both sides of the equation:

x² = -19 + 140

x² = 121

Applying square root to eliminate the exponent:

x = ±√121

x = ±11

2x² - 18 = 0

Adding eighteen to both sides of the equation:

2x² = 18

Dividing between two on both sides of the equation:

x² = 182

x² = 9

Applying square root to eliminate the exponent:

x = ±√9

x = ±3

Correct match for the quadratic equation are: A. {-4, 4},B.  {-5, 5},

C. {-8, 8},D.  {-11, 11},E.  {3,-3}

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I understand that the question you are looking for is:

Match each quadratic equation with its solution set.

A. 2x2 - 32 = 0  {-8, 8}

B. 4x2 - 100 = 0  {-4, 4}

C. x2 - 55 = 9          {-5, 5}

D. x2 - 140 = -19         {-11, 11}

E. 2x2 - 18 = 0  {3,-3}

Add 8 to both sides.

Add 7 and 8 to get 15.

Divide both sides by 3.

Divide 15 by 3 to get 5.

Subtract 9 from both sides.

Subtract 9 from −15 to get −24.

Divide both sides by 8.

Divide −24 entre 8 para obtener −3.

Swap the sides so that all the terms of the variables are on the left side.

Add 13 to both sides.

Add 8 and 13 to get 21.

Divide both sides by 3.

Divide 21 by 3 to get 7.

Subtract 22 from both sides.

Subtract 22 from 4 to get −18.

Divide both sides by 6.

Divide −18 entre 6 para obtener −3.

Swap the sides so that all the terms of the variables are on the left side.

Subtract 51 from both sides.

Subtract 51 from 84 to get 33.

Divide both sides by 11.

Divide 33 by 11 to get 3.

Solution 1 :-

>> 3k - 8 = 7

>> 3k = 7 + 8

>> 3k = 15

>> k = 15 / 3

>> k = 5

Solution 2 :-

>> 8b + 9 = -15

>> 8b = -15 - 9

>> 8b = -24

>> b = -24 / 8

>> b = -3

Solution 3 :-

>> 8 = 3x - 13

>> 3x = 13 + 8

>> 3x = 21

>> x = 21 / 3

>> x = 7

Solution 4 :-

>> 6p + 22 = 4

>> 6p = 4 - 22

>> 6p = -18

>> p = -18 / 6

>> p = -3

Solution 5 :-

>> 84 = 51 + 11c

>> 11c = 84 - 51

>> 11c = 33

>> c = 33 / 11

>> c = 3

The estimated standard error for the sample is 6

Given,

Sample size, n = 36

Sample variance, [tex]s^{2}[/tex] = 1296

Standard deviation, s = √1296

                                   = 36

Standard error, SE = [tex]\frac{s}{\sqrt{n} }[/tex]

                              = [tex]\frac{36}{\sqrt{36} }[/tex]

                              = [tex]\frac{36}{6}[/tex]

                              = 6

Concept

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Answer:

No real solutions.

Step-by-step explanation:

To solve this, we need to use Quadratic Formula.

Quadratic Formula:

[tex]x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ [/tex]

in the form of:

[tex]a {x}^{2} + bx + c[/tex]

Given information from the question, we can deduce:

a = -1

b = -2

c = 5

Let's substitute these values into the formula.

[tex]x = \frac{ - ( - 2) + - \sqrt{ {( - 2)}^{2} - 4( - 1)( -5)} }{2( - 1)} \\ = no \: real \: solutions[/tex]

if you punch these into the calculator.

Answer:

Step-by-step explanation:

Movie A: 267 students

Movie B: 217 students

Movie C: 233 students

Movie D: 183 students

Considering the angle of the arc, it is found that the value of x is of x = 12º.

It is twice the inside angle.

In this problem, the angle of the arc is of 102º, hence the inside angle is of 51º, which means that we can solve for x as follows:

4x + 3 = 51

4x = 48

x = 12º.

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Answer:

  (a)  (f +g)(x) = √(x-2) +√(x)

Step-by-step explanation:

The sum of two functions is the sum of their definitions.

  (f +g)(x) = f(x) +g(x)

  (f +g)(x) = √(x -2) +√(x)

Note: the radicals can only be combined if they can be reduced to a form that has the same expression under the radical. Here, that is not the case, so there is no way to simplify the sum.

80d = 400 is the equation that relates the number of days d that an athlete spends training when the athlete trains for 400 min given that athlete trains for 80 min each day for as many days as possible. This can be obtained by converting the given statements into algebraic equation.

Here in the question it is given that,

that is each day the athlete spends 80 min.

So we can write that,

400 min is the time spent by the athlete

400 min  = number of days × time spent by the athlete in one day

400 min  = d × 80

⇒ 80d = 400  

Hence 80d = 400 is the equation that relates the number of days d that an athlete spends training when the athlete trains for 400 min given that athlete trains for 80 min each day for as many days as possible.

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Answer:

2, 0, 2, 3, 5

1, 2, 4, 0, 5

Step-by-step explanation:

(ax + b)(cx² + dx + e)

acx³ + adx² + aex + bcx² + bdx + be

2(2)x³ + 2(3)x² + 2(5)x + 0 + 0 + 0

4x³ + 6x² + 10x

a = 2

b = 0

c = 2

d = 3

e = 5

1(4)x³ + 1(0)x² + 1(10)x + 2(4)x² + 0 + 10

4x³ + 8x² + 10x + 10

a = 1

b = 2

c = 4

d = 0

e = 5

Answer:

10, 8

Step-by-step explanation:

l + w = 18

l*w = 80

8 and 10 works