Both flowering and nonflowering plants possess specialized structures that help them in reproduction. Conifers are nonflowering plants that possess special
to carry out reproduction. When conifers reproduce using these special structures, it is a form of
.

Answer:

The answer would be D.

Explanation:

Whenever one has many of the same correlating numbers within in a pattern, the rest tend to follow. With the information I was given and not the actual plotting, that would be my answer.

Heating up a reaction does increase the number of collision only.

Hence, Option C is correct answer.

According to the collision theory, the reaction take place when the collision occur and molecules having sufficient energy or threshold energy for collision.

The collision of molecules depend on the kinetic energy of molecules. Greater the kinetic energy greater the number of molecules collide. Lesser the kinetic energy lesser will be collision.

With an increase in temperature, there is an increase in energy that can be converted into activation energy in a collision, and that will increase the reaction rate. A decrease in temperature would have the opposite effect. With an increase in temperature, there is an increase in the number of collision.

Thus from the above conclusion we can say that Heating up a reaction does increase the number of collision only.

Hence, Option C is correct answer.

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Fe3+(yellow) + SCN-(colorless) <--> [FeSCN]2+(dark red)

If Fe3+ is added to the solution the solution turns darker red

While precipitating out Fe3+ (as Fe(OH)3) or SCN- (as AgSCN) will push the equilibrium to the left, consuming the complex and reducing color intensity, the addition of Fe3+ or SCN- will push the equilibrium to the right, creating more complex and intensifying the color.

The pace of reaction rises as Fe3+ levels rise. The concentration of SCN reduces as the rate rises.

The FeSCN2+ complex, which is created when iron(III) and thiocyanate ions react, displays an extremely strong blood red color (or orange in diluted solution), making it simple to detect and quantify using spectrophotometry.

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ClO(4)− is regarded as perchlorate ion and are produced commercially in most situations as salts via industries and in the laboratory.

This ion is referred to as a monovalent inorganic anion and is obtained by deprotonation of perchloric acid. It is composed of chlorine and oxygen atoms in the ratio 1 to 4 respectively.

This has  32 valence electrons available in the Lewis structure and is used in the commercial production of solid rocket fuel.This ion has a molar mass of 99.451 g mol−1 and is used in different processes such as an oxidizer and to control static electricity during the process of food preservation in industries.

Therefore ClO₄− is also regarded as perchlorate ion and is the most appropriate choice.

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Answer:

44.8 grams

Explanation:

The density exists as a ratio comparing the mass of a piece of copper per 1 cm³. Since you have been given a new volume, you can set up a proportion to find the new mass.

[tex]\frac{8.96 grams}{1.00 cm^3} =\frac{?grams}{5.00cm^3}[/tex]                                         <----- Proportion

[tex]44.8 = (1.00cm^3)(?grams)[/tex]                              <----- Cross-multiply

[tex]44.8= ?grams[/tex]                                                 <----- Divide both sides by 1.00

pH = pKa + log [conj.base]/[acid]

Let the concentration of the conjugate base = x

=> The concentration of the acid is also x (As the acid concentration is equivalent to that of the conjugate base)

for CH₃COOH=0.50 M and CH₃COO=0,25 M

pH = pKa + log [salt]/[acid]

pKa = -log Ka = -log 1.8x10-5 = 4.74

pH = 4.74 + log (0.50 M/1.0 M) = 4.74 + log 0.5 = 4.74 + (-0.3)

pH = 4.74 - 0.3

pH = 4.44

For0.20 M Na2CO3

pH=−log[H+]

    =−log (1.54×10−12)

   =11.8

for HNO₂

Kb = 2.17X10^-11 = x^2 / 0.148

x = [OH-] = 1.79X10^-6

pOH = 5.747

pH = 14.000 - pOH = 8.253

​

for HPO₄³⁻

= [HPO₄³⁻] [PO₄³⁻] [H +]/×10⁻³

=[PO₄³⁻]5.464×10⁻¹⁸

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Taking into account the reaction stoichiometry and definition of limiting reactant, AgNO₃ will be the limiting reagent.

In first place, the balanced reaction is:

Cu + 2 AgNO₃  → 2 Ag + Cu(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Cu reacts with 2 moles of AgNO₃, 1.8 moles of Cu reacts with how many moles of AgNO₃?

[tex]amount of moles of AgNO_{3} =\frac{1.8 moles of Cux2 moles of AgNO_{3} }{1 mole of Cu}[/tex]

amount of moles of AgNO₃= 3.6 moles

But 3.6 moles of AgNO₃ are not available, 2 moles are available. Since you have less moles than you need to react with 1.8 moles of Cu, AgNO₃ will be the limiting reagent.

In summary, AgNO₃ will be the limiting reagent.

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Answer:0

Explanation:

Since oxygen gas i.e., diatomic oxygen exists in the atmosphere in the free state, hence the oxidation state of each atom will be 0

Given an equilibrium constant value of 7.2 x 10-4 it is false to say that the reaction proceeds essentially to completion.

In a reaction, we can judge using the value of the equilibrium constant weather or not the reaction moves on to completion. If the reaction moves up to completion, it the follows that the value of the equilibrium constant ought to be large.

On the other hand, when we have a case that the equilibrium constant is small and is not so large, then the reaction does not proceed essentially to completion.

Given an equilibrium constant value of 7.2 x 10-4 it is false to say that the reaction proceeds essentially to completion.

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Answer:

2.52 g NaCl

Explanation:

(Step 1)

To find the mass, you first need to find the moles NaCl. This value can be found using the molarity ratio:

Molarity = moles / volume (L)

After you convert mL to L, you can plug the given values into the equation and simplify to find moles.

136.9 mL / 1,000 = 0.1369 L

Molarity = moles / volume

0.315 M = moles / 0.1369 L

0.0431 = moles

(Step 2)

Now, you can use the molar mass to convert moles to grams.

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

0.0431 moles NaCl           58.443 g
------------------------------  x  -------------------  =  2.52 g NaCl
                                            1 mole

The equilibrium shift if the HCl concentration is increased to the product.

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)

If the concentration of a substance is changed, then the equilibrium will shift in such a way that it minimise the effect of change which occur. If we increase the concentration of a reactant, then the equilibrium will shift to minimize the changes in the direction of the reaction which uses the reactants, so that the reactant concentration decreases.

Thus, we concluded that with increase in the concentration of reactant equilibrium shift forward.

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Answer:

okkkk zjjdjdjdjduxuxu

The correct answer would be 0.034 g/L.

What we are trying to do here is to convert from milligram to gram and from deciliter to liter.

First, let's do the milligram to gram conversion.

1 mg = 0.001 g

Therefore,

3.4 mg = 3.4 x 0.001 = 0.0034 g

In order to convert from deciliter to liter.

1 deciliter = 0.1 L

Thus, 3.4 mg/dL = 0.0034g/0.1 L = 0.034 g/L

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Based on our finding these two compounds are not same they are completely different from each other as Formula of both compounds are different, their appearance is also different from each other.

The formula of the Iron II oxide is FeO. Common name of Iron (II) Oxide is Ferrous Oxide. Iron (II) Oxide is a black colored powder. The mineral form of Iron (II) oxide is known as Wustite. Iron (II) Oxide is used as a pigment. It is also used to make dyes.

The formula of the Iron (III) Oxide is Fe₂O₃. Common name of Iron (III) Oxide is Ferric oxide. Iron (III) Oxide appears as Red-Brown solid. It is also known as Hematite. Iron (III) oxide is used as pigments. It is used in dental composites , cosmetics. It is also used to apply the final polish on metallic jewellery.

Thus from the above conclusion we can say that Based on our finding these two compounds are not same they are completely different from each other as Formula of both compounds are different, their appearance is also different from each other.

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The mass of pentane the student should weigh out is

The density of pentane is 0.626 gcm-3

To calculate the mass of pentane following expression is used,

(Density is defined as the mass divide by volume)

Density = mass / volume

mass of pentane = Density of pentane * Volume of pentane

mass of pentane = 0.626 gcm-3 * 45.0 mL

                             = 28.17 g

Here the unit of mass of pentane is g,

However the unit of density is gcm-3 and unit of volume is mL i.e. cm3

Hence,   Mass = gcm-3 * cm3

              Mass = g

The mass of pentane the student should weigh out is 28.17g

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The oxidation number of reactant Fe is 0 while the  oxidation number of iron in the product is +3

The term redox reaction implies a reaction in which there is an increase in the oxidation number of a specie and the decrease in the oxidation number of another specie.

Now we have the answers as follows;

1) The oxidation number of reactant Fe is 0

2) The oxidation number of reactant oxygen is 0

3) The oxidation number of iron in the product is +3

4) The oxidation number of oxygen in the product is -2

5). Iron is oxidized in the reaction

6) Oxygen is reduced in the reaction

7) The oxidizing agent in this case is the oxygen atom

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Answer:

See below

Explanation:

370 g  /  .090 g/l = _____?___   liters

take that answer    then :

  ? liters   /   22.4 liters / mole   = # moles     done!

There are approximately 183.50 moles of hydrogen gas in 370.g of hydrogen gas.

The number of moles in 370.g of hydrogen gas using the given information.

In the given example,

Density of hydrogen gas = 0.090 g/L

Molar volume at normal pressure and 0.214°C = 22.4 L/mol

So, we  calculate the volume of hydrogen gas (in L) using the given mass and density:

Volume (in L) = mass (in g) / density (in g/L)

Volume (in L) = 370.g / 0.090 g/L

Volume (in L) ≈ 4111.11 L

By using the molar volume, calculate the number of moles:

moles = Volume (in L) / Molar volume (in L/mol)

moles = 4111.11 L / 22.4 L/mol

moles ≈ 183.50 moles (rounded to two decimal places)

Hence, there are approximately 183.50 moles of hydrogen gas in 370.g of hydrogen gas.

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Answer:

Explanation:

Discussion

When Pressure increases  equilibrium shifts to the side with the smallest number of moles. But which side is that?

N2(g) + 3H2(g) ⇌ 2NH3(g)

The left side has 1 mol of nitrogen (N2) and 3 moles of Hydrogen = 4 mols

on the left side.

The right side has 2 mols of NH3 = 2 mols on the right.

Conclusion: You tell the number of mols by the Balance numbers to the left of each chemical in an equation.

Since the left side N2 + 3H2 = 4 mols, the equilibrium does NOT shift left.

2NH3 is only two mols.

The equilibrium shifts Right

Answer

D

Concentrated phosphoric acid is added to the reaction mixture in the synthesis of aspirin to maintain the acidic environment and to keep the reagents protonated.

Phosphoric acid is an inorganic acid with the molecular H₃PO₄.

Its a triprotic acid which means that one molecule of the acid produces 3 molecules of hydrogen ions.

Phosphoric acid is important for many laboratory as well as industrial uses. It can be serve as buffer in living organisms.

It also used in the synthesis of aspirin.

The synthesis of aspirin requires an acidic environment. Therefore, concentrated phosphoric acid is added to the reaction mixture in the synthesis of aspirin to maintain the acidic environment and to keep the reagents protonated.

In conclusion, Phosphoric acid ensures an acidic environment in the synthesis of aspirin.

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Mass of [tex]$\mathrm{Na}{2} \mathrm{CO} 3$[/tex] required [tex]$=0.55 \mathrm{~g}$[/tex]

The mass 0.120M HCI:

Moles of [tex]$\mathrm{HCl}$[/tex]reacted [tex]$=0.120 \times 21.6 / 1000=0.00260$[/tex]

according to balanced reaction, [tex]$\mathrm{HCl}$ and $\mathrm{Na} 2 \mathrm{CO} 3$[/tex] reacts in [tex]$2: 1$[/tex] the ratio

moles of [tex]$\mathrm{Na} 2 \mathrm{CO} 3$[/tex]required [tex]$=0.00260 \times 2=0.00520$[/tex]

convert moles to mass

mass [tex]$=$[/tex]moles [tex]$\times$[/tex]molar mass

mass [tex]$=0.00520 \times 106.0$[/tex]

mass [tex]$=0.55 \mathrm{~g}$[/tex]

mass of [tex]$\mathrm{Na} 2 \mathrm{CO} 3$[/tex]required [tex]$=0.55 \mathrm{~g}$[/tex]

Mass 0.120M HC is [tex]$=0.55 \mathrm{~g}$[/tex]

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The specific heat of the metal, given the data from the question is 0.60 J/gºC

The following data were obtained from the question:

The specific heat capacity of the sample of gold can be obtained as follow:

According to the law of conservation of energy, we have:

Heat loss = Heat gain

MC(T –Tₑ) = MᵥᵥC(Tₑ – Tᵥᵥ)

74 × C(94 – 32) = 120 × 4.184 (32 – 26.5)

C × 4588 = 2761.44

Divide both side by 4588

C = 2761.44 / 4588

C = 0.60 J/gºC

Thus, the specific heat capacity of the metal is 0.60 J/gºC

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Organic transformation sequential equation using catalysts will be as follows:

2CH3-CH2-O => (alc. KOH) => CH2=CH2 + KCl + H2O => (Br2/CCl4) => CH2Br-CH2Br + Zn

CH2Br-CH2Br + Zn => (HBr /Pd) => CH2=CH2+ZnBr2

As can be visualized from above organic transformation equation, conversion of dry ether in presence of alkaline potassium hydroxide results in formation of unstable ethene. This dry unsaturated compound of ethene is stabilized by reaction that happens in presence of bromine or calcium tetrachloride as the catalyst which results in formation of ethylene bromide which in presence of highly efficient palladium as catalyst results in formation of stable ethene as byproduct. Thereby with formation of stable compound of ethylene, it releases zinc bromide as byproduct resulting completion of reaction equation. This stable product ethene is a double bonded carbon structure that is chemically extremely flammable and has planar structure.

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S denotes the ''number of shared electron pairs by an atom'', Hence, Silicon transmits its 4 electrons with 4 Cl-atoms. Thus the Value of S is 4 in SiCl₄ .It is also known as covalency

Silicon Tetrachloride is a transparent, colorless, fuming liquid with an irritating odor. It is used to create Silicon-containing chemicals and in chemical analysis. determine potentially hazardous frontages.

Silicon tetrachloride is designed by the chlorination of various silicon compounds such as ferrosilicon, silicon carbide, or mixtures of silicon dioxide and carbon. The ferrosilicon route is most familiar. In the laboratory, SiCl 4 can be prepared by dining silicon with chlorine on 600 °C (1,112 °F): Si + 2 Cl 2 → SiCl.

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Answer:

Molar mass = 30.026 g/mol

Explanation:

Let Molar mass be mm

mm of CH2O = 12.01 + 2(1.008) + 16.00

= 12.01 + 2.016 + 16.00 = 30.026 g/mol

Hydrohalogenation Reaction:

The substitution of hydrogen and halide levels across a double bond takes place. The halide group is connected to the carbon with more substituents. The product will affect by the presence of peroxide

Ethene is a symmetrical alkene having two carbon atoms. It reacts with HBr in the presence of CCl4, producing bromoethane or ethyl bromide (CH3CH2Br). Propene is an unsaturated alkene consisting of a three-carbon chain with two carbon particles on either side of the double bond.

Ethene is a symmetrical alkene including two carbon atoms. It reacts with HBr in the presence of CCl4, producing bromoethane or ethyl bromide (CH3CH2Br). Propene is an unsaturated alkene consisting of a three-carbon chain with two carbon atoms on either flank of the double bond.

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Answer:

445 mL NH₄Br

Explanation:

(Step 1)

Convert grams ammonium bromide (NH₄Br) to moles using its molar mass.

Molar Mass (NH₄Br): 14.007 g/mol + 4(1.008 g/mol) + 79.904 g/mol

Molar Mass (NH₄Br): 97.943 g/mol

8.42 grams NH₄Br                1 mole
-----------------------------  x  ------------------------  =  0.0860 moles NH₄Br
                                         97.943 grams

(Step 2)

Calculate the volume of NH₄Br using the molarity equation. Then, convert liters (L) to milliliters (mL).

Molarity (M) = moles / volume (L)

0.193 M = 0.0860 moles / volume

(0.193 M) x volume = 0.0860 moles

volume = 0.445 L

1,000 mL = 1 L

0.445 L NH₄Br           1,000 mL
------------------------  x  ------------------  =  445 mL NH₄Br
                                        1 L

Answer:

.512 ATM

Explanation:

P1V1 = P2V2

2 * 5   =  P2 * 19.5

P2 = .512 ATM

The first step in clearing a clogged ballpoint pen is to exert additional pressure when scrawling and drawing vertical lines on paper. If this approach doesn't work, dip the pen's tiny tip in rubbing alcohol. [Only the tidbit] Any dried-up or hardened ink on the tip will dissolve with this.