When the equation __no2 __h2o __o2 → __hno3 is balanced, the coefficient of hno3 is:_________

Suppose protons were emitted rather than electrons then it affects the experiment as the mean velocity of proton will be less then mean velocity electron .

The mass of proton is greater than the mass of electrons but charge of electron is equal to the charge of proton . So , due to difference in the mass of electron and proton there will be some effects.  We can conserve the electric energy which is equal to the qe .

The kinetic energy = 1/2[tex]mv^{2}[/tex]

Now changing the electric potential energy into kinetic energy

v = √2qe/m

The mean velocity of proton will be less then mean velocity electron .

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Solute s has a distribution constant of 5. 0 between water (phase 1) and hexane (phase 2), then the concentration of solute s in hexane if [s]water is 0. 011 m is 0.055m.

It is defined as the ratio of the concentration of solute in two immiscible ( or slightly miscible liquid) in two solids, when they are in equilibrium across the interface between them.

It is defined as the ratio of number of moles of compound to the volume of compound.

Solute S has a partition coefficient of 5 between water and hexane

Partition coefficient Kd = 5.0

Now we calculate the concentration of S in hexane

[hexane]/[water] = Kd

[Hexane]= 5.0 × (water)

[Hexane] = 5 × (0. 011)

[Hexane] = 0.055 m

Thus, we found that the concentration of solute of hexane if water is 0.011m is 0.055m.

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Answer:

D

Explanation:

Mercury is Hg.  Most of these reaction do not involve Hg.  Only D correctly shows a balanced equation with mercury (Hg).

(A) Pro(s)-> Pr(s) + O(g)                                  

(B) Mc₂O(s)-> 2 Mc(s) + O(g)

(C) 2 MnO(s)-> 2 Mn(s) + 20(g)

(D) 2 HgO(s)-> 2 Hg(1) + O₂(8)

Answer:

Answer:

a) The relative abundance of Li-6 =0.0749 = 7.49%

The relative abundance of Li-7 =1 - 0.0749 = 0.9251 =92.51%

b) The fraction of sample of lithium atoms with exact mass of  6.941 amu is 0.

The relative abundance of ⁶Li is around 0.076, and the relative abundance of ⁷Li is approximately 0.924.

To determine the relative abundances of isotopes, we need to compare the atomic masses of the isotopes and their average atomic mass.

Lithium has two stable isotopes: lithium-6 (⁶Li) and lithium-7 (⁷Li). The atomic masses of these isotopes are approximately 6.015 amu and 7.016 amu, respectively.

The average atomic mass of lithium, given as 6.94 amu, is a weighted average of the masses of the two isotopes, taking into account their relative abundances.

Let's assume the relative abundance of ⁶Li is x (in decimal form) and the relative abundance of ⁷Li is (1 - x). The average atomic mass equation can be set up as:

(6.015 amu * x) + (7.016 amu * (1 - x)) = 6.94 amu

Simplifying the equation:

6.015x + 7.016 - 7.016x = 6.94

Combining like terms:

-0.001x = -0.076

Dividing both sides by -0.001:

x ≈ 0.076

Therefore, the relative abundance of lithium-6 (⁶Li) is approximately 0.076, and the relative abundance of lithium-7 (⁷Li) is approximately (1 - 0.076) = 0.924.

In summary, the relative abundance of ⁶Li is around 0.076, and the relative abundance of ⁷Li is approximately 0.924.

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The average acceleration from the following data points is 20.625 m/s^2.

We know that average acceleration = change in speed / change in time
here,

change in speed = v2-v1

                          = 975-150

                          = 825 m/s

change in time   = t2 - t1

                         = 55 - 15

                         = 40 s

now, putting all the values, average acceleration = 825 / 40

                                                                             = 20.625 m/ s^2 .

what is acceleration?

The rate at which an entity's velocity with regard to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.

The SI unit of acceleration is metre per second square (m/s^2).

An average acceleration the speed at which velocity changes, the evolution of velocity through time, or the instantaneous acceleration ( acceleration at a given moment ) .

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Answer:

D

Explanation:

You are looking for   kg / L

  3.188 kg / 3.23 L = .987  kg/L

Now , we know that one mole of SO² Contains 2 Moles ( two ) of atoms of oxygen . Hence , 16 Grams of SO² Contains 0.5 Mole(s) of Oxygen

0.5

hope this helps you. :)

Answer:

a. true

Explanation:

It is true that, the materials in the flux covering on an electrode determine the electrical characteristics of the electrode.

1-H NMR spectroscopy tool will be used for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane.

The preferred method for determining or validating the structure of organic molecules or those containing protons is H NMR. When compared to other nuclei, a solution-state proton spectrum may be obtained relatively quickly, and it contains a wealth of knowledge regarding a compound's structure.

It can be calculated by simply counting the number of unique hydrogens on one side of the symmetry plane will give you the count of signals individual molecules emit in a 1H NMR spectrum.

Therefore, 1-H NMR spectroscopy tool will be used for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane.

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The molecules can be a reactant in a Friedel-crafts reaction will be aniline .

The Lewis acid as well as the chlorine atom of such acid chloride form a complex during the Friedel-Crafts acylation reaction. Cleaving the complex's C-Cl link produces an acylium ion. The acylium ion undergoes resonance stabilized but also has a positive electrical charge upon that carbon atom.

The Friedel-Crafts alkylation reaction, an electrophilic aromatic substitution process, may add an alkyl to a benzene molecule. One illustration is the insertion of a methyl group into a benzene ring.

Therefore, the molecules can be a reactant in a Friedel-crafts reaction will be aniline .

Hence, the correct answer will be option (a)

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Answer:

Atomic Number = 9

Mass Number = 19

Explanation:

The atomic number is the total amount of protons in an atom's nucleus. Therefore, if a fluorine atom has 9 protons, the atomic number is 9.

The mass number is the total amount of protons and neutrons in an atom's nucleus. Therefore, if a fluorine atom has 9 protons and 10 neutrons, the mass number is 19 (9 + 10 = 19).

A 20. 0 l cylinder of oxygen gas is at a temperature of 27. 0°c and a pressure of 5. 00 atm. The density of the oxygen gas in the cylinder is 1.24 atm

The physical force applied to an object is referred to as pressure. Per unit area, a perpendicular force is delivered to the surface of the objects. F/A is the fundamental formula for pressure (Force per unit area). Pascals are a unit of pressure (Pa). Absolute, atmospheric, differential, and gauge pressures are different types of pressure.

By pressing a knife on some fruit, one can get a straightforward illustration of pressure. The surface won't be cut if you press the flat section of the knife against the fruit. The force is dispersed over a wide area (low pressure).

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A. The volume of water (in litres) produced at SATP is 42.73 L

B. The volume of oxygen consumed in the experiment is 55.55 L

C. If the conditions were converted from SATP to STP, the volume of water (in litres) produced is 38.64 L

Mole = mass / molar mass

Mole of C₂H₁₀ = 20 / 58

Mole of C₂H₁₀ = 0.3448 mole

Balanced equation

2C₄H₁₀ + 13O₂ -> 8CO₂ + 10H₂O

From the balanced equation above,

2 moles of C₄H₁₀ reacted to produce 10 moles of water.

Therefore,

0.3448 mole of C₄H₁₀ will react to produce = (0.3448 × 10) / 2 = 1.724 mole of water

Thus, the volume of water (in litres) produced at SATP can be obtained by using the ideal gas equation as follow:

PV = nRT

Divide both sides by P

V = nRT / P

V = (1.724 × 0.0821 × 298) / 0.987

Volume of water produced at SATP = 42.73 L

Balanced equation

2C₄H₁₀ + 13O₂ -> 8CO₂ + 10H₂O

From the balanced equation above,

2 moles of C₄H₁₀ reacted with 13 moles of O₂

Therefore,

0.3448 mole of C₄H₁₀ will react with = (0.3448 × 13) / 2 = 2.2412 moles of O₂

Thus, the volume of O₂ (in litres) consumed at SATP can be obtained by using the ideal gas equation as follow:

PV = nRT

Divide both sides by P

V = nRT / P

V = (2.2412 × 0.0821 × 298) / 0.987

Volume of O₂ consumed = 55.55 L

PV = nRT

Divide both sides by P

V = nRT / P

V = (1.724 × 0.0821 × 273) / 1

Volume of water produced at STP = 38.64 L

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Answer:

20.4 grams Zn

Explanation:

To find the mass, you first need to find the moles. This can be found using the Ideal Gas Law equation:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)

-----> T = temperature (K)

Before you can plug the values into the equation, you need to convert Celsius to Kelvin.

P = 0.980 atm                   R = 0.08206 atm*L/mol*K

V = 7.80 L                          T = 25.0 °C + 273.15 = 298.15 K

n = ? moles

PV = nRT

(0.980 atm)(7.80 L) = n(0.08206 atm*L/mol*K)(298.15 K)

7.644 = n(24.466)

0.312 moles = n

Now that you have the number of moles, you can convert it to grams using the atomic mass of zinc. The final answer should have 3 sig figs to match the sig figs in the given values.

Atomic Mass (Zn): 65.380 g/mol

0.312 moles Zn           65.380 grams
-------------------------  x  -------------------------  =  20.4 grams Zn
                                         1 mole

The molecular mass of a 10g compound that has 30.066 × 10²³ atoms is 2.00g/mol.

The molecular mass of a substance can be calculated by dividing the mass of the substance by the number of moles.

molecular mass = mass ÷ no of moles

However, the number of moles of the substance must first be calculated by dividing the number of atoms by Avogadro's number.

no of moles = 30.066 × 10²³ ÷ 6.02 × 10²³

no of moles = 4.99moles

molecular mass = 10g ÷ 4.99 moles = 2.00 g/mol

Therefore, the molecular mass of a 10g compound that has 30.066 × 10²³ atoms is 2.00g/mol.

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The energy required to melt 20 kg of ice at 0°C is 6.68 kJ.

The enthalpy change for melting of an ice is called the enthalpy of fusion. Its value is 6.02 kJ/mol. This means for every mole of ice we must apply  6.02 kJ of heat for melting. The calculation of heat is done by following equation.

q = n×ΔH

in this problem we need to calculate heat needed to melt 20grams of ice at  0°C .

Calculation of moles of water,

Number of moles of water (n) = given mass/ molar mass = 20g/18.02g/mol

Number of moles of water (n) = 1.109 mole

heat or energy required = q = n×ΔH =  1.109 mole× 6.02 kJ/mol = 6.68 kJ

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Mg (Magnesium) is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, CaBr₂ (l) and molten magnesium iodide, MgI₂ (l).

The anode in the cell has been the negative electrode and attracts the positive ions in the solution. The cathode has been the positive electrode, and attract negative ions.

In electrolysis of Calcium bromide, Calcium will form at the cathode and Bromine will form at the anode.

The reaction is as follows:

2Br⁻ (aq) → Br₂ (g) + 2e⁻

In electrolysis of magnesium Iodide, Magnesium will form at the anode Iodine will form at the cathode.

The reaction is as follows:

2I⁻ (aq) → I₂ (g) + 2e⁻

Thus from the above conclusion we can say that Mg (Magnesium) is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, CaBr₂ (l) and molten magnesium iodide, MgI₂ (l).

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Conjugated dienes routinely undergo 1,2 and 1,4 addition reactions with a variety of electrophilic reagents; this suggests that electrophilic reagents are likely intermediates during these reactions.

Two double bonds and one single bond divide a conjugated diene into two halves. Nonconjugated (Isolated) Dienes have more than one single bond separating two double bonds. Two double bonds are joined to the same atom to form cumulated dienes.

Reagents that function by acquiring electrons or sharing electrons that once belonged to a foreign molecule are referred to as electrophilic reagents, or electrophiles, in some cases. Electrophiles are molecules with a positive charge and a lack of electrons that can react by exchanging electron pairs with nucleophiles, which have many electrons. Epoxides, hydroxy amines, nitroso and azoxy derivatives, nitrenium ions, and elemental sulfur are significant electrophiles.

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Answer: C- rearranged

Explanation:

Answer:

C

Explanation:

Answer:

An amide.

Explanation:

Amides are functional groups, in which a carbonyl atom is linked by a single bond to a nitrogen atom and either a hydrogen or a carbon atom. These defining traits single this functional group out as an amide.

The minimum amount of heat wasted in the production of methanol is 239kJ/mol of heat.

Now we know that the enthalpy is the heat that is released or absorbed in a reaction. The reaction involves the combination of reactants that leads to the formation of the product(s).

Now we know that the production of methanol leads to the evolution of about 239kJ/mol of heat. This heat is wasted as it goes to no good use but is just lost to the environment.

As such, the minimum amount of heat wasted in the production of methanol is 239kJ/mol of heat.

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The use of phenol (carbolic acid) as a surgical wound disinfectant was first practiced by Joseph Lister.

Joseph Lister was a surgeon, scientist, pathologist, etc. He was famous for the discovery of the prevention of infection in wounds. He first used phenol as a disinfectant agent for wounds.

Phenol is an inorganic compound, it is white crystalline and solid. It was used by Joseph Lister as an agent for a disinfectant agent. He discovered the safer medical procedure.

Thus, Joseph Lister was the first to utilize phenol (carbolic acid) to sterilize surgical wounds.

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The equation of the reaction is; B2O3 + CoO -----> Co(BO2)2.

The term chemical reaction has to do with the interaction  between reactants in order to yield products.  We know that when a chemical reaction occurs, the reactants are rearranged to form the products.

Now the first step in this reaction is that the Borax  is heated to form boric anhydride (B2O3). Thus compound now reacts with cobalt II oxide as follows; B2O3 + CoO -----> Co(BO2)2.

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Hydrogen bonding is generally an intermolecular force, and  covalent bonding is only an intramolecular attractive force.

When a hydrogen atom gets bound to a powerfully electronegative atom and is in close proximity to some other electronegative atom with such a single electron pairs, a hydrogen bond occurs as an intermolecular force (IMF).

The three types of intermolecular interactions include dipole-dipole, London dispersion, and hydrogen bonding forces. Metal bonds, ionic bonds, as well as covalent bonds are mostly the three types of intramolecular forces.

Therefore, Hydrogen bonding is generally an intermolecular force, and  covalent bonding is only an intramolecular attractive force.

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The compound  2-bromopentane contains a chiral carbon atom.

So , option D is correct one.

The carbon which is bonded with four different substituent or four valency of carbon is satisfy by the four different substituent is called chiral carbon and the molecule contain such chiral carbon is called chiral molecule. The molecule contain chiral carbon rotates plane polarized light.

Example: The compound  2-bromopentane contains chiral carbon at second carbon and four different substituent at second carbon is methyl , bromine , propyl and hydrogen.

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The half-life of gold-198 is 2.77 days

Given:

mass of gold sample = 200-gram

mass of decay sample = 160 grams

time taken to decay = 6.25 days

To Find:

the half-life of gold-198

Solution: The amount of time it takes to disintegrate by half an initial amount. For a given reaction, a reactant's half-life t1/2 is the time it takes for its concentration to reach a value which is the arithmetic mean of its initial and final (equilibrium) value.

Since Au-198 is 200 g originally and it decays to 160 g, so 40g left

the fraction decay is 40/200 = 0.2

the time base is 6.25 days

ln0.2/6.25 = -0.25

k=ln2/half life therefore half-life = ln2/k = ln2/0.25

half life = 2.77 days

So, half life of gold is 2.77 days

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The kf of Ag(NH₃)₂ for the given equation is 2.786 x 10⁷.

kf value can be calculated by dividing the molal concentration with the freezing point of depression.

The reaction are given:

Ag+(aq) + e- ⇋ Ag(s) E0= 0.81 V

Ag(NH₃)₂ +(aq) + e- ⇋ Ag(s) + 2NH₃(aq) E0= 0.37 V

To get Kf of Ag(NH₃)₂  we will rearrange the above written equations

a. Ag +(aq) + e- ⇋ Ag(s) E0= 0.81 V

b. Ag(s) + 2NH₃(aq) ⇋ Ag(NH₃)₂ +(aq) + e- E0= - 0.37 V

Adding equation (a) and equation (b) we will get

Ag +(aq) + 2NH₃(aq) ⇋ Ag(NH₃)₂  + (aq) Eo = 0.81 -0.37 = 0.44 V

By the Ernst equation,

E = E° - 0.0591 logkf

Now Kf is calculated at equilibrium and at equilibrium E = 0,

The number of transfer of electron is 1 ( 1 e-) , n=1

E° = 0.44 V

Substituting all the values in Ernst equation

0 - 0.44 - 0.0591/ 1 logkf

logkf = 0.44/ 0.0591

kf = 10 (0.44/ 0.0591)

Kf = 2.786 x 10⁷

Hence, Kf of Ag(NH₃)₂ for the given equation is 2.786 x 10⁷.

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The process which involves the addition of a hydrogen molecule to compounds containing multiple bonds will be known as hydrogenation reaction.

Unsaturated hydrocarbons are transformed into saturated hydrocarbons by the addition process when they interact with hydrogen gas and nickel. The term "hydrogenation reaction" is also employed to describe this process.

In the production of fats and oils, hydrogenation seems to be crucial for two reasons. It increases the oil's oxidative stability and turns liquid oils become semisolid or plastic fats for use in shortenings as well as margarine, among other things.

Therefore, the process which involves the addition of a hydrogen molecule to compounds containing multiple bonds will be known as hydrogenation reaction.

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6.32mL of phosphate solution is needed to completely neutralize the lead in this reaction.

A neutralization reaction is defined as the reaction between an strong acid and strong base to produce a salt and water.

The process of the reacting given volume of acids or bases for the determination of the concentration or volume of the acid or base which is required for neutralization is known as titration in volumetric analysis.

The formula used to determine the volume of the acid is given below:

(Ca × Va) /(Cb × Vb) = Na/Nb

where,

where Ca is the concentration of lead nitrate

Cb is the concentration of sodium phosphate

Va is the volume of lead nitrate

Vb is the volume of sodium phosphate

Na is the moles of lead nitrate

Nb is the moles of sodium phosphate

Concentration of lead nitrate = m/V

= 6.931/(0.1 × 331.2)

= 0.0281 M

Ca = 0.222M

Cb = 0.0281M

Na = Nb = 1

Va = ( 0.0281 × 50) /0.222

= 6.32 mL.

Thus, 6.32mL of phosphate solution is needed to completely neutralize the lead in this reaction.

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There are  1.2 hr would this current have to be applied to plate out 7. 20 g of iron .

Calculation ,

Given ; Current ( I ) = 5. 68 A

In [tex]Fe(NO_{3} )_{2}[/tex] , the valancy of Fe is +2 .

2 moles of [tex]e^{-}[/tex] are required for the decomposition of 1 mole of Fe .

7. 20 g  of Fe in moles  = 7. 20 g /55.845 g/mol =0.12 mole

x moles of  [tex]e^{-}[/tex] are required for the decomposition of 0.128 mole of Fe .

moles of   [tex]e^{-}[/tex] are required = 0.256 moles

Charge on 1 mole  of   [tex]e^{-}[/tex] = 96500 C

Charge on 0.256  mole  of   [tex]e^{-}[/tex] = 24704 C

Current ( I )= Q/t  

t =Q / I = 24704 C/5. 68 A = 4349 sec = 1.2 hr

Therefore , there are  1.2 hr would this current have to be applied to plate out 7. 20 g of iron .

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