How is a marketing -oriented firm different from a production-oriented firm or a sales-oriented firm?

Answer:

wait ewiai twia it i ti i got this soon

(1+3) x (2 x 3)

Answer:

you better give me brainliest

Step-by-step explanation:

i think they are lying about being in jail

The surface area of the new toy is given as follows:

1,439 in².

The surface area of a figure is given by the sum of the surface area of all it's compositions. This figure is given by a cylinder and a rectangular prism.

The surface area of a cylinder with radius r and height h is given by the following formula:

[tex]S = 2\pi r(r + h)[/tex]

In this problem, the dimensions are:

r = 3 in, h = 16 in.

Hence:

[tex]S = 2\pi \times 3(3 + 19) = 132\pi[/tex]

The surface area of a rectangular prism of length l, width w and height h is given as follows:

[tex]S = 2(lw + lh + wh)[/tex]

In this problem, the dimensions are:

l = 24 in, h = 10 in, w = 8 in.

Hence the surface area is:

S = 2 x (24 x 10 + 24 x 8 + 10 x 8) = 1024 in²

It is the sum of the surface areas, hence:

[tex]132\pi + 1024 = 1439 \text{in}^2[/tex]

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Answer: Here you go :)

Step-by-step explanation:

Hope it helps!

Answer:

100 miles and 5.5 inches

The area of the tarp is 54.125 square feet

From the figure in the question, we have the following angle measure:

DCE= 120

This means that:

<C = DCE - 90

Substitute the known values in the above equation

<C = 120 - 90

Evaluate the difference

<C = 30

The measure of D is then calculated as

<D = 90 - <C

This gives

<C = 90 - 30

Evaluate the difference

<C = 60

Represent the height with h.

This is then calculated as:

sin(D) = h/5

This gives

sin(60) = h/5

Multiply both sides by h

h = 5 * sin(60)

Evaluate

h = 4.33

This is calculated as:

A = 0.5 * (10 + 15) * 4.33

Evaluate

A = 54.125

Hence, the area of the tarp is 54.125 square feet

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Answer:

In the image

Hope this helps!

Step-by-step explanation:

To find the height, first find that ∠D is 60°. This means the height of the trapezoid is approximately 4.3 feet. So, the area of the tarp is approximately 53.7 square feet.

Answer:

t = 21

Step-by-step explanation:

The ball strikes the groujd when h = 0.

[tex]-3.2t^2 + 54.4t+268.8=0 \\ \\ 32t^2 - 544t-2688=0 \\ \\ t^2 - 17t-84=0 \\ \\ (t-21)(t+4)=0 \\ \\ t=-4, 21[/tex]

Since time must be positive, t = 21.

Based on the cost and revenue functions to the company for selling x items, the domain of C(x) is [0, 100].

The range of C(x) is (200, 4,200).

The domain would be the lowest capacity and the maximum capacity. As these are physical units to sell, the lowest unit would be 0 units as units can't be negative.

The maximum capacity is given as 100 items so the domain is:

= [0, 100]

The range is:

When x is 0, the function gives C(x) as:

= 40(0) + 200

= 200

When x is the maximum of 100, the C(x) is:

= 40(100) + 200

= 4,200

Range is:

(200, 4,200)

Full question is:

What is the domain and range of C(x)?

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Answer:

  D.  x = -7/3

Step-by-step explanation:

A graphical solution is often easier when the problem is written in the form f(x) = 0. That way, the x-intercept(s) of the function f(x) will be the solution.

The desired form can be found by subtracting 16 from both sides of the equation:

  [tex]\left(\dfrac{1}{64}\right)^{-x-3}=16\qquad\text{given}\\\\\left(\dfrac{1}{64}\right)^{-x-3}-16=0\quad\Longrightarrow\quad f(x)=\left(\dfrac{1}{64}\right)^{-x-3}-16[/tex]

A graph is attached, showing x=-7/3 is the solution.

Using powers of 4, the equation can be rewritten ...

  [tex]\left(\dfrac{1}{4^3}\right)^{-x-3}=4^2\qquad\text{given}\\\\4^{3(x+3)}=4^2\\\\3(x+3)=2\qquad\text{equating exponents, or taking base-4 logs}\\\\x=\dfrac{2}{3}-3=\boxed{-\dfrac{7}{3}}\qquad\text{divide by 3, subtract 3}[/tex]

Hi

6% increase is multiply by 1,06

done 40 times

so : 250* 1,06^40 = 2571 ,

The inequalities in the system of inequalities are y > x² – 2x – 3 and y > 3x + 4

The graph that completes the question is added as an attachment

The parabola

It has a vertex of (1,  -4)

So, we have:

y = a(x - 1)^2 - 4

It passes through (3, 0).

So, we have:

0 = a(3 - 1)^2 - 4

This gives

4a - 4 = 0

Solve for a

a = 1

Substitute a = 1 in y = a(x - 1)^2 - 4

y = (x - 1)^2 - 4

Expand

y = x^2 - 2x + 1 - 4

y = x^2 - 2x - 3

The inner part is shaded.

So, we have:

y > x^2 - 2x - 3

The linear equation

It passes through (0, 4).

So, we have:

y = mx + 4

It passes through (1, 7).

So, we have:

7 = m + 4

Solve for m

m = 3

Substitute m = 3 in y = mx + 4

y = 3x + 4

The upper part is shaded.

So, we have:

y > 3x + 4

Hence, the inequalities in the system of inequalities are y > x² – 2x – 3 and y > 3x + 4

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Answer: 22

Step-by-step explanation:

Number of floor tiles = (5.4m × 4.2m) ÷ 1m²

Number of floor tiles = 22.68

Minimum number of floor tiles = 22

Answer:

5.3333333 or 5 [tex]\frac{1}{3}[/tex]

Step-by-step explanation:

30 divided by 2 equals 15.

80 divided by 15 equals 5.3333333 or 5 [tex]\frac{1}{3}[/tex].

The required probabilities are:

A) P(D or 5) = 4/13

B) P(H and J) = 1/13

C) P(J or 8) = 2/13

D) P(H or S) = 1/2

E) P(R and F) = 3/26

F) P(R or Q) = 7/13

The ratio of favorable outcomes to the total outcomes of an event is said to be its probability.

P(E) = n(E)/n(S)

It is given that a single card is drawn at random from a standard deck of 52 cards.

So, the sample space consists of 52 cards in total

From those,

4 suits: Hearts, Clubs, Spades, Diamonds

Each of the suit has 13 cards: { Ace, 2,3,4,5,6,7,8,9,10, Jack, Queen, King}

There are 26 Red cards and 26 Black cards.

A) The probability of drawing a diamond or a 5:

P(D or 5) = P(D) + P(5) - P(D and 5)

               = 13/52 + 4/52 - 1/52

               = 16/52 = 4/13

B) The probability of drawing a heart and a jack:

P(H and J) = P(H) × P(J) (Since they are independent events)

                 = 13/52 × 4/13

                 = 1/13

C) The probability of drawing a jack or 8:

P(J or 8) = P(J) + P(8) - P(J and 8)

              = 4/52 + 4/52 - 0

              = 2/13

D) The probability of drawing a heart or a spade:

P(H or S) = P(H) + P(S) - P(H and S)

               = 13/52 + 13/52 - 0

               = 26/52 = 1/2

E) The probability of drawing a red and face card:

P(R and F) = P(R) × P(F) (Since they are independent)

                 = 26/52 × 12/52

                 = 1/2 × 3/13

                 = 3/26

(There are three face cards- jack, king, and queen: each of 4)

F) The probability of drawing a red card or a queen:

P(R or Q) = P(R) + P(Q) -P(R and Q)

               = 26/52 + 4/52 - 2/52

               = 28/52 = 7/13

Thus, the required probabilities are calculated.

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The common ratio of the given sequence is -1/4. In a geometric sequence, the common ratio is the value that is in between each number in the sequence.

The ratio of the value of a term in the sequence to the value of the previous term in the sequence is said to be the common ratio. I.e.,

C.R = (nth term)/(n - 1)th term

The given sequence is 64, -16, 4, -1, ...

Taking the ratio of the second term to the first term, we get

-16/64 = -1/4

Similarly, the ratio of the third term to the second term,

4/16 = -1/4

Since the ratios are equal, then the common ratio of the sequence is -1/4.

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The parent function f(x) = x will undergo 3 transformations. The first transformation is vertically stretched by a factor of 2. Next, the graph will shift 4 units to the right. Finally, the graph will shift 2 units up

The function is given as:

f(x) = x

This represents the parent function.

Start by stretching the function vertically by a factor of 2

This gives

f'(x) = 2x

Next, we shift the graph 4 units to the right

This gives

f''(x) = 2(x - 4)

Finally, we shift the graph 2 units up

This gives

f'''(x) = 2(x - 4) + 2

The number of transformations above is 3

Hence, the complete statement is:

The parent function f(x) = x will undergo 3 transformations. The first transformation is vertically stretched by a factor of 2. Next, the graph will shift 4 units to the right. Finally, the graph will shift 2 units up

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Using it's concept, the experimental probability that in a group of 4 students, at least one of them has green eyes is of 0.45 = 45%.

A probability is given by the number of desired outcomes divided by the number of total outcomes. An experimental probability is calculated considering the results of previous trials.

In this problem, there were 20 trials. The digit 9, which represents a student with green eyes, appears at least once in 9 of the the trials, hence the probability is:

p = 9/20 = 0.45 = 45%.

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The required sales in dollars needed to achieve managements target is $607,5000.

Net income is total revenue less total cost. Total cost is the sum of fixed cost and variable cost. Fixed cost is the cost that remains constant regardless of the level of output. e.g. rent. Variable cost is the cost that varies with output e.g. wages.

Net income = sales - total cost

Net income = sales - (fixed cost + variable cost)

$67,500 = sales - ($175,500 + 0.6sales)

$67,500 = sales - $175,500 - 0.6sales

$67,500 + $175,500 = sales - 0.6sales

243,000 = 0.4sales

sales = 243,000 / 0.4

sales = $607,500

Here is the complete question:

For Pharaoh Company, variable costs are 60% of sales, the fixed costs are $175,500. Managements net income goal is $67,500.Compute the required sales in dollars needed to achieve managements target net income of $67.500.

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Answer:

A convenient formula to use is

S = ((1 + i)^n - 1) / i where S is the value of 1$ deposited for n periods at an interest rate of i

in this case n = 12 * 28 = 336 periods of deposit at an interest rate of

.0021 / 12 = .00175 = i

S = (1.00175^336 - 1) / .00175 = 456.8338  the value of 1$ after 336 periods

350 * 456.8338 = 159891.81   the value of 350 deposited monthly

Note that 350 * 336 would be 117,600

One must be careful to distinguish the above formula from

(1 - (1 + i)^-n) / i which gives the value of 1$ when the borrower is "paying" an interest rate of i - this would be the case for a mortgage - or what is  the value of 1$ paid for n periods when paying an interest rate of i

Answer:

[tex]y=\left|\dfrac{1}{2}x-\dfrac{5}{2}\right|+3[/tex]

Step-by-step explanation:

Given equation:

[tex]y=\left|\dfrac{1}{2}x-2\right|+3[/tex]                            

Translation

[tex]f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}[/tex]

When translating a graph to the right, subtract the number of units from the x variable.

Translating the given graph one unit to the right:

[tex]f(x-1) \implies y=\left|\dfrac{1}{2}(x-1)-2\right|+3[/tex]

Simplifying:

[tex]\implies y=\left|\dfrac{1}{2}(x-1)-2\right|+3[/tex]

[tex]\implies y=\left|\dfrac{1}{2}x-\dfrac{1}{2}-2\right|+3[/tex]

[tex]\implies y=\left|\dfrac{1}{2}x-\dfrac{5}{2}\right|+3[/tex]

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Step-by-step explanation:

a)

z = (140 - 118)/16 = 22/16 = 11/8 = 1.375 ≈ 1.38

in the z-table this gives us the p-value : 0.91621

that is the probability of values 140 and below.

for above 140 we need to calculate the value of the other side of the bell-curve :

1 - 0.91621 = 0.08379

b)

z = (90 - 118)/16 = -28/16 = -7/4 = -1.75

in the z-table this gives us the p-value : 0.04006

that is the probability of values of 90 and below.

The measures of the angles are

Angle JPK

The given parameters are:

∠KPL = 46°

∠NPH = 25°

∠MPN = ∠NPH

By vertical angle theorem, we have:

∠JPK = ∠MPH

Where

∠MPH = ∠MPN + ∠NPH

This gives

∠MPH = ∠NPH + ∠NPH

So, we have:

∠MPH = 25° + 25°

Evaluate

∠MPH = 50°

Recall that:

∠JPK = ∠MPH

So, we have:

∠JPK = 50°

Hence, the measure of angle ∠JPK is 50°

Angle LPM

The angle on a straight line is 180°.

So, we have:

∠LPM +  ∠KPL + ∠MPH = 180°

This gives

∠LPM +  46° + 50° = 180°

Evaluate

∠LPM = 84°

Hence, the measure of angle ∠LPM is 84°

Angle NPM

In (a), we have:

∠NPM = ∠NPH

This gives

∠NPM = 50°

Hence, the measure of angle ∠NPM is 50°

Angle JPI

By vertical angle theorem, we have:

∠JPI = ∠LPM

So, we have:

∠JPI = 84°

Hence, the measure of angle ∠JPI is 84°

Angle HPI

By vertical angle theorem, we have:

∠HPI = ∠KPK

So, we have:

∠HPI = 46°

Hence, the measure of angle ∠HPI is 46°

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Answer:

3

Step-by-step explanation:

A + B is calculated by adding the same positions in both matrices.

and position (2, 3) in A+B is therefore the sum of position (2, 3) in A plus the position (2, 3) in B, which is then

-4 + 7 = 3

Since the values on both sides are equal, hence the system of equation given has no solution

Simultaneous equations are equations that consists of two or more equation and unknowns.

Given the equation below

2х+4у=4

x + 2y = 3

​

From equation 2;

x = 3 - 2y

Substitute into equation 1

2(3-2y) + 4y = 4

Expand

6 - 4y + 4y = 4

6 = 4

Since the values on both sides are equal, hence the system of equation given has no solution

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Answer:

Angle CGB is an acute angle because it's less than 90°

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

Angles having measure less than 90° are considered as Acute angles.

in the given figure,

The Acute angle is :

Answer:

[tex]2 {x}^{2} + 7xy - 15 {y}^{2} [/tex]

Step-by-step explanation:

We can use the rainbow expansion method to find the expression.

[tex](2x - 3y)(x + 5y) \\ = 2 {x}^{2} + 10xy - 3xy - 15 {y}^{2} \\ = 2 {x}^{2} + 7xy - 15 {y}^{2} [/tex]

Mathematical expression involves an equation that may consist of numbers only or combined with alphabets, which may also be given in the form of a statement. Therefore the required statement in the question is option C. Add 3 to the product of one-fourth and 8, then divide by 5.

Mathematical expression involves an equation that may consist of numbers only or combined with alphabets, which can be given in the form of a statement. When a given expression consists of both numbers and alphabets, then it forms an algebraic expression. It can also be given in the form of a statement.

Given in the question:

([tex]\frac{1}{4}[/tex] x 8 + 3) ÷ 5

This can be given in a statement form as; Add 3 to the product of one-fourth and 8, then divide by 5.

The appropriate statement that describes the given expression is: Add 3 to the product of one-fourth and 8, then divide by 5 i.e Option C.

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If there are 23 students study Economics,6 students study both government and economics and 48 students study either government or economics or both then there are 31 students study government, 17 students study economics only and 25 students are there who study government only.

Given that in a secondary school class, 23 students study Economics, 6 students study both government and economics. 48 students study either government or Economics or both.

We are required to find :

Suppose E represents economics students and G students government students. In this way:

E=23

G∩E=6  (And represents intersection between sets)

G∪E=48 (Or represents union of sets)

G∪E=G+E-G∩E

48=G+23-6

G=48-17

G=31

Economics only=E-G∩E

=23-6

=17

Governments only=G-G∩E

=31-6

=25

Hence if there are 23 students study Economics,6 students study both government and economics and 48 students study either government or economics or both then there are 31 students study government, 17 students study economics only and 25 students are there who study government only.

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Answer:

0.45 per egg

Step-by-step explanation:

since it's 3 dozen that mean it's gonna be 36 eggs divided by 16.20 so it's 0.45 per egg

The central angle in the circle is ∠DAC,major arc is BED, minor arc is ADC and BC=(5π*BD)/18.

Given that BD is diameter of the circle and angle BAC is 100°.

We are required to find the central angle, major arc, minor arc, m BEC, BC.

Angle is basically finding out the intensity of inclination of something on the surface.

In the circle central angles are many like BAC and CAD. We can write CAD as DAC also.

Major arc of a circle is that arc whose length is larger than all other arcs in the circle.

In our circle the major arc is arc BED.

Minor arc of a circle is that arc whose length is smaller.

In our circle the minor arc is arc ADC.

We know that arc's length is 2πr(Θ/360)

In this way BC=2π*(BD/2)*100/360

=(5π*BD)/18

We cannot find angle BEC.

Hence the central angle in the circle is ∠DAC,major arc is BED, minor arc is ADC and BC=(5π*BA)/18.

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