The distance covered by a car moving with a speed of 36 km/h in 15m is (a) 0.9 km (b) 9.0 km (C) 90 km (d) 900 km​

False; finding it would require much more than a few days of observation.

The Doppler approach is a reliable way to find exoplanets. It examines the velocity and characteristics of the star and planet using the Doppler effect. The star and the planet both revolve around the same mass.

The periodic velocity change of the stellar spectrum brought on by an orbiting massive planet is discovered using Doppler spectroscopy.

Doppler spectroscopy tracks changes in the host star's light's hue to find periodic shifts in radial velocity. A star's spectrum is redshifted when it moves away from us and blueshifted when it moves toward us.

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The value is equal to 18.26*10^6 dollars/ounces.  

To find the answer, we have to know about the Cullinan diamond.

                     [tex]21.9 Ounce= 621.35g=400*10^6 dollars\\\\value=\frac{400}{21.9} *10^6dollars/ounce=18.26*10^6dollars/ounce[/tex]

Thus, we can conclude that, the value is equal to 18.26*10^6dollars/ounces.                  

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When charging a system with vapor refrigerant from a refrigerant cylinder the cylinder will become cold .

What is a refrigerant charging cylinder used for?

What type of refrigerant can be added as a liquid or a vapor?

Blends like R410a or 404a must be added to a system as a liquid. Pure refrigerants like R22 can be added in liquid or vapor states.

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[tex]\huge\underline{\underline{\boxed{\mathbb {EXPLANATION}}}}[/tex]

The heat capacity is given by the expression:

[tex]\longrightarrow \sf{\triangle Q= m \triangle C \triangle T}[/tex]

[tex]\longrightarrow \sf{Q= \: Heat}[/tex]

[tex]\longrightarrow \sf{M= \: Mass}[/tex]

[tex]\longrightarrow \sf{C= \: Specific \: Heat}[/tex]

[tex]\longrightarrow \sf{T= \: Temperature}[/tex]

[tex]\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}[/tex]

[tex] \leadsto[/tex] When the [tex] \bm{heat}[/tex] is measured in the calorimeter, we obtain a value, and since we know the mass of the material and we control the change in [tex] \bm{temperature}[/tex] , we can then determine the specific heat "C" by simply remplazing in the expression.

The heat capacity of a material is its ability to absorb heat energy. There are different methods to determine the heat capacity of a material, depending on the specific conditions and resources available. Here are some common approaches:

It's imperative to note that heat capacity can vary with temperature, pressure, and other factors. Therefore, measurements or data should ideally be conducted or referenced within the appropriate range of conditions relevant to the specific application or analysis.

The light will be travelling at its own speed 300,000 km/s which is the speed of the light.

One universal physical constant that is significant in many branches of physics is the speed of light in a vacuum, typically abbreviated as c. Its precise value is 299792458 meters per second or roughly 300000 kilometers per hour or 186000 miles per hour. The maximum speed at which common matter, energy, or any signal carrying information may move through space is c, according to the special theory of relativity.

Similar to how electromagnetic waves in wire cables move more slowly than c, light moves more slowly through transparent materials like glass or air. The refractive index n of a substance (n = c/v) is the ratio between c and the speed v at which light moves through it.

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The wavelength of radiowaves is 3.042 m.

The electromagnetic spectrum's longest wavelengths, which are found in radio waves, are normally found at frequencies of 300 gigahertz and below.

Frequency given, f = 98.6 MHz = 98.6 x [tex]10^{6}[/tex] cycles/second

Electromagnetic waves including radiowaves also travel at the speed of light.

Therefore, c = 3.0 x [tex]10^{8}[/tex] m/sec

Wavelength = speed/frequency

wavelength of 98.6 MHz = 3.0 x [tex]10^{8}[/tex]/98.6 x [tex]10^{6}[/tex] meters

=3.042 meters

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An electric dipole consists of a particle with a charge of 6 x 10⁻⁶ c at the origin and a particle with a charge of –6 x 10⁻⁶ c on the x axis at x = 3 x 10⁻³ m. Its dipole moment is 18 x 10⁻⁹ Cm

Dipole moment of a dipole is dependent on the charge of the dipole and the distance between the two charges.

Electric Dipole consists of two charges which are equal and opposite in charge i.e. positive and negative charges.

Given,

Dipole moment, p = ?

Charge, q = 6 x 10⁻⁶C

Distance between charges, d = 3 x 10⁻³ m

Dipole moment (p) is given by:

p = charge x distance between the two charges

p = 6 x 10⁻⁶ x 3 x 10⁻³ Cm

p = 18 x 10⁻⁹ Cm

The dipole moment for the given charge configuration is 18 x 10⁻⁹ Cm

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A solenoid with 500 turns is 0. 10 m long and carries a current of 4. 0. The strength of magnetic field at its center will be 2.5 * [tex]10^{-2}[/tex] H

Magnetic Field is the region around a magnetic material or a moving electric charge within which the force of magnetism acts.

A coil of wire which is designed to generate a strong magnetic field within the coil is called a solenoid. Wrapping the same wire many times around a cylinder creates a strong magnetic field when an electric current is passed through it. N denotes the number of turns the solenoid has.

Magnetic field at the center of the solenoid = mu0 * I * N / L

I = current in the solenoid

N = number of turns in the solenoid

L = length of the coil

B = 4π * [tex]10^{-7}[/tex] * 4 * 500 / 0.10

   = 251200 * [tex]10^{-7}[/tex] H

   = 2.5 * [tex]10^{-2}[/tex] H

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There will be no heat transmission, and the system's work is 25.27 Kj.

The calculation for total heat transfer and work production:

Provided,

The mass of r-134a = 0.7 kg

Initial pressure of the system, P₁ = 800 kpa

Initial temperature of r-134a, T₁ = 50°C = 273+ 50 = 323 K

Final pressure of the system, P₂ = 140 kpa

From the superheated refrigerant r-134a

P₁ = 800 kpa & T₁ = 50°C

the internal energy, u₁ = 263.87 Kj/kg &

the entropy, s₁ = 0.9803 Kj/kg .K

There won't be any heat transmission because the process is isentropic.

So, Q = 0 KJ

Due to the isentropic nature of the operation, the ultimate entropy is determined by

s₂ = s₁ = 0.9803 Kj/kg .K

From the r-134a superheated refrigerant

at P₂ = 140 kpa & entropy s₂ = 0.9803 Kj/kg .K

the internal energy,u₂ = 227.77 K/kg

The work on the system is provided by

W = m x (u₂-u₁)

W = 0.7 x(227.77 - 263.87)

W = 0.7 x (-36.1)

W = -25.27 KJ

A negative number means the system is doing the task.

As a result, there won't be any heat transfer, and the system will only have used 25.27 KJ of energy.

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The final velocity is v[tex]_{2}[/tex] =-0.2m/s , v[tex]_{1}[/tex] = -3.2 m/s

Given data,

Mass of glider A (M[tex]_{1}[/tex]) = 0.15 kg

Mass of glider B (M[tex]_{2}[/tex]) = 0.3 kg

Initial velocity of A (u[tex]_{1}[/tex]) = 0.80ms-1

Initial velocity of B ( u[tex]_{2}[/tex]) = -2.2m/s

Momentum and kinetic energy are conserved in elastic collision . So,

M[tex]_{1}[/tex]u[tex]_{1}[/tex]+M[tex]_{2}[/tex]u[tex]_{2}[/tex] = M[tex]_{1}[/tex]v[tex]_{1}[/tex]+M[tex]_{2}[/tex]v[tex]_{2}[/tex]

0.15×0.8+0.3x(-2.2) = 0.15v[tex]_{1}[/tex]+0.3v[tex]_{2}[/tex]

-0.54 = 0.15v[tex]_{1}[/tex]+0.3v[tex]_{2}[/tex]

Again if,

u[tex]_{1}[/tex]+v[tex]_{1}[/tex] =u[tex]_{2}[/tex]+v[tex]_{2}[/tex]

0.8 +v[tex]_{1}[/tex] =-2.2+v[tex]_{2}[/tex]

v[tex]_{1}[/tex]-v[tex]_{2}[/tex] = -3

Solving  for -0.54 = 0.15v[tex]_{1}[/tex]+0.3v[tex]_{2}[/tex] and v[tex]_{1}[/tex]-v[tex]_{2}[/tex] = -3 , we get

v[tex]_{2}[/tex] =-0.2m/s , v[tex]_{1}[/tex] = -3.2 m/s

Therefore,The final velocity is v[tex]_{2}[/tex] =-0.2m/s , v[tex]_{1}[/tex] = -3.2 m/s

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The Potential at the origin due to the four point charges located at  (0, 2), (0, -2), (2 , 0), and (-2 , 0) will be - [tex]45\times10^{4}[/tex] volts.

We have four point charges, each of charge [tex]2.5\times10^{-5}[/tex] C, are located on the x - axis and y - axis, one at each of the locations (0, 2), (0, -2), (2 , 0), and (-2 , 0).

We have to calculate the potential at the origin O(0,0).

The Electric field potential due to point charge ' q ' at a distance ' r ' meters apart is -

[tex]V(r) = \frac{1}{4\pi\epsilon_{o} } \frac{q}{r}[/tex]

Now, in the question given to us -

q = [tex]2.5\times10^{-5}[/tex]

Let us label the four points as - A (0, 2), B (0, -2), C (2 , 0), and D (-2 , 0).

Now, the potential due to charge located at point A will be -

[tex]V_{A} = \frac{1}{4\pi\epsilon_{o} } \frac{q}{r}\\V_{A} = \frac{1}{4\pi\epsilon_{o} } \frac{q}{r}\\V_{A} = 9\times10^{9}\times\frac{2.5\times10^{-5} }{2} \\V_{A} = 11.25\times10^{4}[/tex]

Now, the distance of the center from each point will be same = 2 m.

Hence, the potential due to each charge at the origin will be -

[tex]V_{A} =V_{B} =V_{C} =V_{D} = 11.25\times10^{4}[/tex]

Since, the potential is a scalar quantity, we can add the potential due to each charge using simple addition -

[tex]V_{A} +V_{B} +V_{C} +V_{D} = 4\times11.25\times= 45\times10^{4}[/tex] Volts

Hence, the potential at the center will be - [tex]45\times10^{4}[/tex] volts.

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The amount of heat generated is 654.5 joules.

q=mCΔT

Given,

m=100, C=0.385  j ⁄ g · °c,  [tex]T_{1} =18^{0}C , T_{2} =35^{0} C[/tex],

q=100*0.385*(35-18)= 654.5 j

Heat is defined as energy that is transferred to or from a thermodynamic system by means other than thermodynamic work or the movement of matter (e.g. conduction, radiation, and friction). Similar to thermodynamic work, heat transfer affects a system's surrounds in addition to the system itself; as a result, it is not a characteristic of the system alone, even while it helps to change the internal energy of the system, which is a property of the system alone. This differs from the common linguistic usage of the word "heat" as a system feature in and of itself. The quantity of energy that is transported as heat in a process is the amount of energy that has been transferred minus any thermodynamic work that has been done and any energy that has been contained in the substance being moved.

How much heat in joules will it take to raise the temperature of a 100. 0 g piece of copper from 18°c to 35°c? the specific heat capacity of copper is 0. 385 j ⁄ g · °c

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117 m/sec is the speed of a transverse wave in a rope of length 3. 1 m and mass 86 g under a tension of 380 n.

The wave speed v is given by

v= √τ/μ

​where τ is the tension in the rope and μ is the linear mass density of the rope.

The linear mass density is the mass per unit length of rope :

μ= m / L = (0.086 kg)/(3.1 m)=0.0277 kg/m.

v= [tex]\sqrt{ \frac{380 N}{0.0277 kg/m}}[/tex]  = 117.125 m/sec (approx. 117 m/sec

In physics, a transverse wave is a wave whose oscillations are perpendicular to the direction of the wave's advance. This is in contrast to a longitudinal wave which travels in the direction of its oscillations. Water waves are an example of transverse wave.

Transverse waves commonly occur in elastic solids due to the shear stress generated; the oscillations in this case are the displacement of the solid particles away from their relaxed position, in directions perpendicular to the propagation of the wave. These displacements correspond to a local shear deformation of the material. Hence a transverse wave of this nature is called a shear wave. Since fluids cannot resist shear forces while at rest, propagation of transverse waves inside the bulk of fluids is not possible.

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The change in heat q for the aluminum cup is 141 J.  

A substance's heat capacity is the amount of heat needed to increase its overall temperature by one degree. The heat capacity is known as the specific heat capacity or the specific heat if the substance's mass is unity.

change in heat -

The amount of heat Q that is transported to create a temperature shift depends on the substance and phase involved, the mass of the system, and the magnitude of the temperature change. (A) The temperature change and the amount of heat transported are directly inversely related.

The answer's sign dig is determined by a calculation's lowest sign digits.

The solution will need 3 digits because the temperatures are provided with 3 significant digits and the specified heat has 3 significant digits (the mass has 4 significant digits).

31.91 g   * 0.903 J/g-C  *  (26.1 - 21.2 C) = 141 J

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The effective lever arm will be enhanced if we utilize a big diameter string.

The perpendicular distance from the axis of rotation to the force's line of action is specified as the lever arm.

When a big diameter string is utilized, the effect of the diameter on the string of the lever arm will be enhanced.

This is due to the reason that if the radius of the pulley is R and the radius of the string is r, then the effective lever arm becomes R+r.

If the radius,r of the string is very minute such that its addition to the radius of the pulley, R will hardly make a change to the effective lever arm, then it is avoided. However, if the radius of the string is a big number then it can not be avoided as it can make significant errors in the calculation of the effective lever arm.

Hence, The effective lever arm will be enhanced if we utilize a big diameter string.

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When the magnetic field is heading west and the electric field is pointing up, the wave propagation will be in the north.

How do we find out the direction of wave propagation?

Electromagnetic waves (EM-waves), as we are aware, are transverse. Electric and magnetic fields are both perpendicular to one another in EM waves (E⊥B).

Transverse waves are waves in which the propagation direction is opposite the direction of amplitude. for instance, gravitational waves, light waves, and water waves.

In this instance, the magnetic field is heading west while the electric current is pointing up towards the screen's layout.

∴ E x B = κ

where E= the direction of the electric field,

B = the direction of the magnetic field,

κ = at a particular point, the direction of propagation

The aforementioned equation is right-handed. When we put our finger towards ourselves (away from the screen) and curl it to the west, and the thumb will indicate the wave propagation direction ( north side ).

The propagation of waves in our instance is in the north direction.

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_______________

h=7,5 m

g=10 m/s²

ρ=1000 kg/m³

_______________

p - ?

_______________

p=ρgh=1000 kg/m³ · 10 m/s² · 7,5 m = 75000 Pa = 75 kPa

Answer: = 25. 5 m

Explanation:

Solve for C using Pythagorean theorem:

1. [tex]\sqrt{a^{2}+b^{2} }=c[/tex]

2.  [tex]\sqrt{22.2 m ^{2} +12.6m^{2} } =c[/tex]

3. [tex]25.52646 m= c[/tex]

∴ Magnitude of the vector is 25.5 m

Alice's speed relative to the water should be 0.6 m/s in order to target the spot 90 meters south of the starting point on the bank of the other side.

Relative velocity refers to the velocity of an object with respect to another observer.

Velocity is speed in a given direction and is a vector quantity.

There is relative velocity between Alice and the water.

Let Alice's velocity relative to the river be x

Time it will take her to cross the river = 45/x

The displacement of the river in that time is given below as;

Displacement = velocity * time

Velocity of river = 1.20 m/s

time, t = 45/x

d = 90 m

90 = 1.2 * 45/x

90x = 54

x = 54/90

x = 0.6 m/s

Therefore, Alice's speed relative to the water should be 0.6 m/s.

In conclusion, relative velocity is the velocity of one object from the reference point of another object.

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Answer:

elastic energy

Explanation:

hope it helps you

A skater can spin faster by pulling her arms closer to her body or spin slower by spreading her arms out from her body due to conservation of angular momentum

What is the principle of conservation of angular momentum?

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The sum of vectors lie between 5 - 45

We all know that Vector is a quantity of Magnitude and Direction.

Couple of examples of Vector quantity are Acceleration, Displacement, Force, Momentum, Velocity

Let's solve the problem:

I A I is given as 20

I B I is given as 25

The sum of vectors lie between their maximum and minimum

Hence,

MIn < Sum of Vectors < Max

I A-B I < Sum of Vectors < I A + B I

I 20 - 25 I < Sum of Vectors < I A + B I

5 < Sum of Vectors < 45

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Sulphur

The missing element is sulphur

Here the compound is composed of  element X and chlorine.

it is given,

XCl (6) ----> 6Cl

mass = 13.1%

it is X and Cl = 100%-13.10%

                     = 86.90%

chlorine = 86.90            

X = 13.10

We assume 100g of sample

so according to the above solved data, in 100g of sample we have 86.90 g of chlorine.

now we split that chlorine into two moles of chlorine.

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The 60 degrees is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value.

It is given that axis of a polarizing filter to cut its intensity to one-fifth of its initial value.

It is required to find the angle between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value.

Suppose the angle between the polarizer and the axis of filter is θ.

The intensity of light that is passing after the filter is 0.2 l₀.

From the law of Malus, we have

I = I₀ [tex]cos^{2}[/tex]θ

0.2I₀= I₀ [tex]cos^{2}[/tex]θ

0.2 =  [tex]cos^{2}[/tex]θ

[tex]cos\\[/tex]θ = 0.447

θ = 60°

Thus the angle between the direction of polarized light and the axis of a polarizing filter is 60 degree.

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Answer:

conservation law, also called law of conservation, in physics, a principle that states that a certain physical property (i.e., a measurable quantity) does not change in the course of time within an isolated physical system.

Explanation:

The definition of a conservation law in physics asserts that a certain observable attribute of an isolated physical system doesn't change over time.

Answer: D. They are the coldest stars.

Explanation:

Answer:

the relationship between Newton first law of motion and inertia is there are two types of inertia: 1. Inertia of rest

2. Inertia of motion

Newton first law states that the body at rest stays at rest until it is acted by external or unbalanced force that is inertia of rest or body in motion remain in motion unless it is acted by unbalanced force or external force and this is inertia of motion.

Inertia is the tendency of an object to remain at motion or in rest.

Magnitude of Net force Required to accelerate a 1200kg car uniformly from 0m/s to 27m/s in 10s is 3240N.

Force can be found out using the relation of Force, mass and acceleration.

The relation of Force, mass and acceleration is as follows:

∴ Force = Mass × Acceleration

⇒ Force = 1200kg × Acceleration

Given:

Mass = 1200kg

Final Velocity = 27m/s

Initial Velocity = 0m/s

time = 10s

Now, to find out the acceleration we can use the first equation of motion:

∴ Final Velocity = Initial Velocity + Acceleration × time                

⇒ 27   = 0 + 10a                  

⇒ a = 2.7m/s²        

Putting acceleration in the above mentioned equation,  

∴ Force = 1200kg × Acceleration

⇒ Force = 1200kg × 2.7

⇒ Force = 3240N

Hence, the net force required to accelerate the car uniformly is 3240N.

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The answer is 3240 N.

Intial velocity [tex]$\mathrm{u}=0 \mathrm{~m} / \mathrm{s}$[/tex]

final velocity [tex]$\mathrm{v}=27 \mathrm{~m} / \mathrm{s}$[/tex]

time [tex]$t=10$[/tex] sec.

Newton's first equation of motion

[tex]$v=u+a t$[/tex], here a = acceleration

[tex]$\mathrm{so}_{0}=(v-u) / t$[/tex]

[tex]$a=(27.0-0) / 10$[/tex]

[tex]$a=2.7 \mathrm{~m} / \mathrm{sec}^{2}$[/tex]

Force [tex]$F=m a$[/tex]

Mass [tex]$\mathrm{m}=1200 \mathrm{~kg}$[/tex]

[tex]$F=1200 \times 2.7$[/tex]

[tex]$F=3240 N$[/tex]

What is acceleration?

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The Sahara and Australian deserts (among others) are associated with a sub-trpical high-pressure belt.

This location is for that reason a place of high stress. it's also called the pony range. Winds usually blow from excessive strain to low strain. So the winds from the subtropical region blow towards the Equator as change winds and some other winds blow toward Sub-Polar Low-pressure as Westerlies.

For the duration of the Northern Hemisphere's summer, the oceans are generally cooler in comparison to the warmer continents. In flip, cooler, denser maritime air that overlies the oceans serves to enhance surface pressures, paving the way for quite robust subtropical highs throughout summer.

The subtropical high-pressure belt vicinity is also referred to as the pony range. Those latitudes are characterized via calm winds and little precipitation.

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