Answer: negative slope
constant slope
decreasing function
B-C-E
Step-by-step explanation:negative slope
constant slope
decreasing function
Find the m of
Find the m of
Can someone help I’m so very confused on how I even start this??
Both of these problems will be solved in a similar way, but with different numbers. First, we set up an equation with the values given. Then, we solve. Lastly, we plug into the original expressions to solve for the angles.
[23] ABD = 42°, DBC = 35°
(4x - 2) + (3x + 2) = 77°
4x+ 3x + 2 - 2 = 77°
4x+ 3x= 77°
7x= 77°
x= 11°
-
ABD = (4x - 2) = (4(11°) - 2) = 44° - 2 = 42°
DBC = (3x + 2) = (3(11°) + 2) = 33° + 2 = 35°
[24] ABD = 62°, DBC = 78°
(4x - 8) + (4x + 8) = 140°
4x + 4x + 8 - 8 = 140°
4x + 4x = 140°
8x = 140°
8x = 140°
x = 17.5°
-
ABD = (4x - 8) = (4(17.5°) - 8) = 70° - 8° = 62°
DBC =(4x + 8) = (4(17.5°) + 8) = 70° + 8° = 78°
which number set(s) does -10 belong to
irrational numbers
whole numbers
rational numbers
integers
real numbers
counting or natural numbers
No number set describes this number.
The number set(s) that - 10 belong to are rational numbers, integers and real numbers. Option C, D and E
Number sets of negative numbersA rational number can be defined as a number expressed as the ratio of two integers, where the denominator is not be equal to zer0
- 10 can be written as = 1/ 10
Integers are whole number that could be positive, negative and even zero
- 10 is a negative whole number
Real numbers are numbers with continuous quantity that can represent distance along a number line
-10 can represent distance along a number line.
Thus, the number set(s) that - 10 belong to are rational numbers, integers and real numbers. Option C, D and E
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Please help and explain.
Considering the given graph, we have that:
The slope of the graph of the function is equal to 1 for x between x = -3 and x = -2.The slope of the graph is equal to 0 for x between x = 3 and x = 4.The greatest value of y is y = 4.The smallest value of y is y = -3.How to find the slope of a function?The slope of a function, given two points, is given by the change in y divided by change in x.
When x = -3, y = -3, and while x = -2, y = -2, hence when x changes by 1, y also changes, hence the slope of the graph of the function is equal to 1 for x between x = -3 and x = -2.
When x = 3, y = 4, and when x = 4, y = 4, hence the slope of the graph is equal to 0 for x between x = 3 and x = 4.
Looking at the vertical axis:
The greatest(top) value of y is y = 4.The smallest(bottom) value of y is y = -3.More can be learned about the graph of a function at https://brainly.com/question/19376563
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does someone mind helping me with this? Thank you!
Help me pls i very need your answer
[tex]x = \frac{\sqrt{5} + 1}{2} \approx 1.618033989[/tex]
pls help questions 1-2
1) a) The volume of the sphere is 100 cubic centimeters.
b) The volume of the cylinder is 200 cubic centimeters.
2) The volume of the cone is 175 cubic centimeters.
What is the volume of a submerged object?
Herein we have two case of submerging solids into recipients full of liquid, the volume of the objects is equal to the volume of the displaced liquid. Now we proceed to calculate the volume of each object:
Point 1 - Part A:
0.8 L - 0.5 L = 3 · x
0.3 = 3 · x
x = 0.1 L
x = 100 cm³
The volume of the sphere is 100 cubic centimeters.
Point 1 - Part B:
0.8 L - 0.5 L = x + y
0.3 = x + y
0.3 = 0.1 + y
y = 0.2 L
y = 200 cm³
The volume of the cylinder is 200 cubic centimeters.
Point 2:
350 mL = 2 · z
z = 175 mL
z = 175 cm³
The volume of the cone is 175 cubic centimeters.
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Find the most general antiderivative of the function. (check your answer by differentiation. use c for the constant of the antiderivative. ) g(t) = 8 t t2 t
The most general antiderivative of the given function g(t) is (8t + t³/3 + t²/2 + c).
The antiderivative of a function is the inverse function of a derivative.
This inverse function of the derivative is called integration.
Here the given function is: g(t) = 8 + t² + t
Therefore, the antiderivative of the given function is
∫g(t) dt
= ∫(8 + t² + t) dt
= ∫8 dt + ∫t² dt + ∫t dt
= [8t⁽⁰⁺¹⁾/(0+1) + t⁽²⁺¹⁾/(2+1) + t⁽¹⁺¹⁾/(1+1) + c]
= (8t + t³/3 + t²/2 + c)
Here 'c' is the constant.
Again, differentiating the result, we get:
d/dt(8t + t³/3 + t²/2 + c)
= [8 ˣ 1 ˣ t⁽¹⁻¹⁾ + 3 ˣ t⁽³⁻¹⁾/3 + 2 ˣ t⁽²⁻¹⁾/2 + 0]
= 8 + t² + t
= g(t)
The antiderivative of the given function g(t)is (8t + t³/3 + t²/2 + c).
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Determine what type of model best fits the given situation: the membership of the local pta increases by 3 members a day for each day during the month of september.
Type of model best fits the given situation linear. Since it has a constant of +3 everyday.
What is a linear equation in math?
A linear equation only has one or two variables. No variable in a linear equation is raised to a power greater than 1 or used as the denominator of a fraction. When you find pairs of values that make a linear equation true and plot those pairs on a coordinate grid, all of the points lie on the same line.linear type of model best fits the given situation.the membership of the local pta increases by 3 members a day for each day during the month of September.
Since it has a constant of +3 everyday.
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I need help im bad at math
Answer: 243
Step-by-step explanation:
If you divide the 18 inch by two to get the r, you will get 9. So you should multiple the 3 and the 9 square. So it should be 3x81=243
please help meeeeee please please please
Answer:
quadratic: -3x²linear: 0x or "none"constant: 1Step-by-step explanation:
This is a question about naming parts of a polynomial. The attached image has more on the subject.
DegreeThe word "degree" refers to the number of times a variable is a factor in a term. When there is only one variable, the degree of the term is the exponent of the variable. A missing exponent is understood to be 1. A missing variable is understood to have a degree of 0.
When there are two or more variables, the degree of the term is the sum of their exponents.
In some cases, we're only interested in the degree associated with a particular variable. For example, 7x²y³ is a 5th-degree term that is 2nd degree in x and 3rd degree in y.
Quadratic termA "quadratic" term is one that has degree 2, or one in which the variable of interest has degree 2.
In the given function definition, the term -3x² is the quadratic term.
Linear termA "linear" term is one that has degree 1.
In the given function definition, there is no linear term.
If you must identify one, it would be 0x, a degree-1 term with a coefficient of 0.
Constant termA "constant" term is one that has no variables, or no variables of interest. It has degree zero.
For example, in the expression x² +2ax +a², when we are concerned with the variable x, the a² term is called the "constant" term because it does not contain the variable x. The same expression could be considered as a quadratic in 'a', in which case the x² term would be the "constant term."
In the given function definition, the term 1 is the constant term.
State what additional information is required in order to know the
triangles are congruent using the theorem or postulate listed.
Answer: line ZX is congruent to line VX (option 4)
Step-by-step explanation:
We already know <X is congruent to <X, we also know that line YX is congruent to line XW. Now all we need is one more line adjacent to X which is going to be ZX ad VX
What are the values of a such that the average value of f(x) = 1 2x − x 2 on [0, a] is equal to 1?
The average value of the given function is [tex]f_{avg} = \frac{-2a^{2} + 6a + 6 }{6}[/tex].
According to the statement
we have given that the function f(x) and we have to find the average value of that function.
So, For this purpose, we know that the
The given function f(x) is
[tex]f(x) = -x^{2} + 2x +1[/tex]
And now integrate this function with the limit 0 to a then
[tex]f_{avg} = \frac{1}{b - a} \int\limits^a_0 {f(x)} \, dx = -x^{2} + 2x +1[/tex]
Now integrate this then
[tex]f_{avg} = \frac{1}{a} \int\limits^a_0 {-x^{2} + 2x +1} \, dx[/tex]
Then the value becomes according to the integration rules is:
[tex]f_{avg} = \frac{1}{a} \int\limits^a_0 {-\frac{x^{3} }{3} + \frac{2x^{2} }{2} +x} \,[/tex]
Now put the limits then answer will become as output is:
[tex]f_{avg} = \frac{1}{a} [ {-\frac{a^{3} }{3} + \frac{2a^{2} }{2} +a} \,][/tex]
Now solve this equation then
[tex]f_{avg} = [ {-\frac{a^{2} }{3} + \frac{2a }{2} +1} \,][/tex]
Now
[tex]f_{avg} = \frac{-2a^{2} + 6a + 6 }{6}[/tex]
This is the value which represent the average of the given function in the statement.
So, The average value of the given function is [tex]f_{avg} = \frac{-2a^{2} + 6a + 6 }{6}[/tex].
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solve for x
2^x,2^4=2^3x
Answer:
x=2
Step-by-step explanation:
2^x *2^4=2^3x
using law of indices
2^x+4=2^3x
x+4=3x
4=3x-x
4=2x
2=x
How many cookies did he eat in 3.45
Answer:
20 cookies
Step-by-step explanation:
8 in 1.5 minutes
so we want to find how many in 3.75 minutes since 3 + 45/60 = 3.75
so then its 1.5*2 = 3 so 8*2 = 16 to get that 16 cookies in 3 minutes
then we still have .75 left so then divide 8/2 to get 4 cookies in 0.75 minutes
16+4 = 20
you can also just find how many in 0.25 minutes (15 seconds) you get 6/8
multiply that by 3.75/0.25 = 15 you get 15*(8/6) = 20
Find the area of the shaded region if the dimensions of the unshaded region are 18ft x 22ft . use 3.14 for π as necessary.
The area of the shaded region in the given image is: 1,111.84 ft²
How to Find the Area of a Shaded Region?To find the area of the shaded region in the image given, find the areas of the unshaded region, then subtract it from the total area of the whole figure.
Area of the total figure = area of two semicircles + area of the rectangle.
Dimensions of the rectangle is given as, 18ft x 22ft.
Area of the rectangle = 18ft × 22ft = 396 ft²
The diameter of each of the semicircle = 7 + 7 + 18 = 32 ft
The radius of each of the semicircle = 1/2(32) = 16 ft
Area of the two semicircles = 2(1/2 × πr²) = 2(1/2 × 3.14 × 16²)
Area of the two semicircles = 803.84 ft²
Area of the rectangle = 32 × 22 = 704 ft²
The total area = 704 + 803.84
The total area = 1,507.84 ft²
The area of the shaded region = 1,507.84 - 396
The area of the shaded region = 1,111.84 ft²
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math help !!!!!!!!!!!!!!!
The values of b, h and k are (c) b = 2, h = -2 and k = -9
How to determine the values of b, h and k?The logarithmic function is given as:
f(x) = log₂(x + 2) - 9
A logarithmic function is represented as:
f(x) = logb(x - h) + k
By comparing both equations, we have
b = 2
h = -2
k = -9
Hence, the values of b, h and k are (c) b = 2, h = -2 and k = -9
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Write a polynomial of least degree with rational coefficients and with the root
–15+10[tex]\sqrt{6\\}[/tex]
Answer:
p(x) = x² +30x -375
Step-by-step explanation:
When a quadratic has real rational coefficients, any irrational or complex roots come in conjugate pairs.
Factored formA root of p means (x -p) is a factor of the polynomial. Here, we have roots of -15+10√6 and -15-10√6, so the factored form can be written ...
p(x) = (x -(-15 +10√6))(x -(-15 -10√6))
Using the factoring of the difference of squares, we can write this as ...
p(x) = (x +15)² -(10√6)²
Standard formExpanding the factored form, we can write the polynomial as ...
p(x) = x² +30x +225 -600
p(x) = x² +30x -375
Using synthetic division what is (3x² + 7x - 18) = (x - 3)
Answer:
3x + 16 + 30/x - 13
Step-by-step explanation:
y=alpha sinx +beta cosx is the solution of d^2y/dx^2+dy/dx=0 where (alpha and beta are constant)
The expression y = α · sin x + β · cos x is a solution of the ordinary differential equations if and only if (α, β) = (0, 0).
When a given equation is a solution of an ordinary differential equation
According to the statement, we must find in what conditions a given expression may be a solution of an ordinary differential equation. Then, first and second derivatives of the equation are:
y' = α · cos x - β · sin x (1)
y'' = - α · sin x - β · cos x (2)
Then, we substitute on the ordinary differential equation:
(- α · sin x - β · cos x) + (α · cos x - β · sin x) = 0
And by algebraic handling we simplify the resulting expression:
- (α + β) · sin x + (α - β) · cos x = 0
Where each coefficient represents a constant of a linear combination:
α + β = 0
α - β = 0
Then, the solution of the system of linear equations is (α, β) = (0, 0). The expression y = α · sin x + β · cos x is a solution of the ordinary differential equations if and only if (α, β) = (0, 0).
RemarkThe statement is incomplete and complete form cannot be found, then we decided to create a new statement:
Please prove that y = α · sin x + β · cos x is the solution of the differential equation d²y / dx² + dy /dx = 0 where the following condition is observed, if and only if α = β = 0.
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A simple random sample of size 30 is drawn from a population of size 200. if the population mean is 57 and the population standard deviation is 6, what is the standard error of the mean?
Answer:
1.0954.
Step-by-step explanation:
Standard error = std dev / √n
= 6 / √30
= 1.0954.
Determine the velocity vector of the given path. r(t) = (9 cos2(t), 3t − t3, 2t)
The velocity vector of the given path r(t) = (9cos2(t), 3t - t^3, 2t) is [tex]v = 9sint\hat{i}+(3-3t^{2} )\hat{j} +2\hat{k}[/tex].
According to the given question.
We have a path
r(t) = (9cos2(t), 3t - t^3, 2t)
So, the vector form of the above vector form can be written as
[tex]r(t) = 9cos2(t)\hat{i}+ (3t - t^{3} )\hat{j} + 2t\hat{k}[/tex]
As, we know that the rate of change of position of an object is called velocity vector.
Therefore, the velocity vector of the given path r(t) = (9cos2(t), 3t - t^3, 2t) is given by
[tex]v = \frac{d(r(t))}{dt}[/tex]
[tex]\implies v = \frac{d(9cost\hat{i}+(3t-t^{3})\hat{j}+2t\hat{k} }{dt}[/tex]
[tex]\implies v = \frac{d(9cost\hat{i})}{dt} +\frac{d(3t-t^{3})\hat{j} }{dt} +\frac{d(2t)}{d(t)}[/tex]
[tex]\implies v = 9sint\hat{i}+(3-3t^{2} )\hat{j} +2\hat{k}[/tex]
Hence, the velocity vector of the given path r(t) = (9cos2(t), 3t - t^3, 2t) is [tex]v = 9sint\hat{i}+(3-3t^{2} )\hat{j} +2\hat{k}[/tex].
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At which points on the curve y = 1 60x3 − 2x5 does the tangent line have the largest slope?
The tangent line has the largest slope at x = 3√2 and x = -3√2 on the curve y = 1 + 60x³ − 2x⁵.
First, let's find the derivative of the given function y = 1 + 60x³ − 2x⁵ using the power rule for differentiation:
dy/dx = 0 + 3(60)x² - 5(2)x⁴
= 180x² - 10x⁴
To find the critical points, we set the derivative equal to zero and solve for x:
180x² - 10x⁴ = 0
Factoring out common terms, we get:
10x²(18 - x²) = 0
Setting each factor equal to zero, we have:
10x² = 0 or 18 - x² = 0
From the first equation, we find x = 0.
From the second equation, we have:
18 - x² = 0
x² = 18
Taking the square root, we get:
x = ±√18
= ±3√2
So the critical points are x = 0, x = 3√2, and x = -3√2.
Now we need to evaluate the slope at these critical points. We can do this by plugging each x-value into the derivative:
When x = 0:
dy/dx = 180(0)² - 10(0)⁴ = 0
When x = 3√2:
dy/dx = 180(3√2)² - 10(3√2)⁴ = 180(18) - 10(216) = 3240 - 2160 = 1080
When x = -3√2:
dy/dx = 180(-3√2)² - 10(-3√2)⁴ = 180(18) - 10(216) = 3240 - 2160 = 1080
The slope is 0 when x = 0 and 1080 when x = 3√2 or x = -3√2.
Therefore, the tangent line has the largest slope at x = 3√2 and x = -3√2 on the curve y = 1 + 60x³ − 2x⁵.
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The complete question is as follows:
At which points on the curve y = 1 + 60x³ − 2x5⁵ does the tangent line have the largest slope?
a
a
¹2-5, find £r(:)
=
En
n=l
n=1
b
Given that Σ
[tex]\sum^{\infty}_{n=1} (a/b)^n=5 \\ \\ =\frac{a/b}{1-\frac{a}{b}}=5 \\ \\ \frac{a}{b-a} =5 \\ \\ \frac{a}{b}=\frac{5}{6}[/tex]
So, we need to find
[tex]\sum^{\infty}_{n=1} n(5/6)^n
[/tex]
Let this sum be S.
Then,
[tex]S=(5/6)+2(5/6)^2 +3(5/6)^3+\cdots \\ \\ \frac{5}{6}S=(5/6)^2 + 2(5/6)^3+\cdots \\ \\ \implies \frac{1}{6}S=(5/6)+(5/6)^2+(5/6)^3+\cdots=5 \\ \\ \implies S=\boxed{30}[/tex]
FIRST CORRECT ANSWER WILL GET BRAINLIEST
Answer:
(c) f(g(3)) > g(f(3))
Step-by-step explanation:
The relationship between the function values can be found by evaluating the functions.
f(g(3))The order of operations tells us we must first evaluate g(3).
g(x) = -3x +15
g(3) = -3(3) +15 = 6
Then we can evaluate f(x) for x=6:
f(x) = 7x
f(6) = 7(6) = 42
So, the composition is ...
f(g(3)) = 42
g(f(3))As above, we must first evaluate f(3):
f(3) = 7(3) = 21
Then we can evaluate g(x) for x=21:
g(21) = -3(21) +15 = -63 +15 = -48
That means the composition is ...
g(f(3)) = -48
ComparisonThe first is greater than the second.
42 > -48
f(g(3)) > g(f(3))
subtract 2/9-2/15. enter your answer below as a fraction in lowest terms, using the slash (/) as the fraction bar.
Answer:
2/9 - 2/15
Solution
LCM = 45
45 ÷9 ×2 = 10
45÷ 15 ×2 = 6
10 - 6 = 4
ANSWER = 4/45
Answer:
l
Step-by-step explanation:
take the lcm of 9 and 15. it will be 45 . than continue
identify the TRUE statement relating to a property of the function y = sin x
A. one cycle of the function is 180 degrees
B. The maximum and minimum values of the function are 1 and -1 respectively
C. The amplitude of the function is 2 units
D. The equation of the baseline is y = -1
The true statement relating to a property of the function y =sin x is that the maximum and minimum values of the function are 1 and -1 respectively. Option B
Properties of the function
The following are the properties of the sin trigonometric ratio of the function;
The sine graph rises till +1 and then falls back till -1 from where it rises again.The function y = sin x is an odd functionThe domain of y = sin x is the set of all real numbersThe range of sine function is the closed interval [-1, 1]The amplitude of the function is half its range valueOne cycle of the function is 6. 28From the above listed deductions, we can see that the true statement about the function y = sin x is that the range which is always known as the maximum and minimum values of the function are 1 and - 1 respectively.
Thus, the true statement relating to a property of the function y =sin x is that the maximum and minimum values of the function are 1 and -1 respectively. Option B
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Write 7.21 as a mixed number in simplest form. 7.21 =
Answer:7 21/100
Step-by-step explanation: We will covert 7.21 into a fraction. .21 = 21/100. Since 21 can only be divided by 3 and 7, the simplest form of 21/100 is 21/100. So, the mixed number is 7 and 21/100
Answer:
7 and 21/100
Step-by-step explanation:
Since .01 is 1/100, 7.21 will be 7 and 21/100. There is no way to further simplify this, therefore, it is our final answer. Hope this helps! :)
When constructing a perpendicular line through a point on a line, how can you verify that the lines constructed are perpendicular? (1 point)
Check the angles used in the construction with a straightedge to ensure consistency.
Check the distance along the lines at several places with a compass to ensure they are the same length.
Check the intersecting lines with the corner of a piece of paper to ensure the lines create 90° angles.
Check the distance between the lines at several places with a compass to ensure they are equidistant
If you know the slope of the lines, you can also use these methods:
- see if the slopes multiplied by each other are -1 (should be if they're perpendicular)
- test if the slopes are opposite reciprocals (if they are, they are perpendicular)
What is the total number of common tangents that can be drawn to the circles
The total number of common tangents that can be drawn to the circles is 2.
What is a tangent?A tangent serves as line that touches the circle at a single point whereby the point where tangent meets the circle is the tangency.
A tangent to a circle can be described as the straight line that touches the circle at only one point.
Therefore, from the definition, The total number of common tangents that can be drawn to the circles is 2.
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Which equation represents y = −x2 + 4x − 1 in vertex form?
The vertex form of the equation y = -x^2 + 4x - 1 is y = -(x - 2)^2 + 3
How to determine the vertex form of the quadratic equation?The quadratic equation is given as:
y = -x^2 + 4x - 1
Differentiate the above quadratic equation.
This is done with respect to x by first derivative
So, we have:
y' = -2x + 4
Set the derivative to 0
-2x + 4 = 0
Subtract 4 from both sides of the equation
-2x + 4 - 4 = 0 - 4
Evaluate the difference in the above equation
-2x = -4
Divide both sides of the above equation by -2
x = 2
Rewrite as
h = 2
Substitute 2 for x in the equation y = -x^2 + 4x - 1
y = -2^2 + 4 *2 - 1
Evaluate the equation
y = 3
Rewrite as:
k = 3
A quadratic equation in vertex form is represented as:
y = a(x - h)^2 + k
So, we have:
y = a(x - 2)^2 + 3
In the equation y = -x^2 + 4x - 1, a = -1
So, we have:
y = -(x - 2)^2 + 3
Hence, the vertex form of the equation y = -x^2 + 4x - 1 is y = -(x - 2)^2 + 3
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