What is the volume of the box pictured below?

fractions 3 and 1 over 10 cubic feet
fraction 3 and 2 over 5 cubic feet
fraction 6 and 5 over 8 cubic feet
fraction 8 and 3 over 4 cubic feet

Answer:

A

Step-by-step explanation:

First, we should put this equation in slope-intercept form by isolating y.

Thus, we have:

[tex]2x-\frac{4}{3}y=4\\ -\frac{4}{3}y=4-2x\\ y=\frac{3}{2}x-3[/tex]

The slope-intercept equation shows that the y-intercept is -3 and the slope is 3/2.

Only answer A meets these requirements.

x[x²-25] - [x³+8] = 17

x³- 25x - x³- 8 = 17

-25x = 17 + 8

-25x = 25

x = -1

Answer:

484 Students

Step-by-step explanation:

This is simple probability. Assuming 22/80 students walk to school within a small population, and there are 1760 students at the school, there should be (22/80)*1760 students that walk to school in total. (This is just theoretical). This is 484 students.

A trapezoid is a plane figure bounded by four sides. Therefore, the required answers are given below;

a) ΔADE = ΔBCF (Side-Angle-Side congruent property)

b) DE = 5 cm and CF = 5 cm

c) AE = 12 cm

Plane figures are shapes that are formed by straight boundaries referred to as sides. Examples include; square, rectangle, trapezium, etc.

A trapezoid is a family of quadrilaterals., these are figures that have four straight sides.

In the given question, the required answers are:

a) To prove that ΔADE = ΔBCF

Thus,

AE ⊥ DC  (given)

BC ⊥ DC  (given)

<AED = <BFC = [tex]90^{o}[/tex]

AE = BF (height of the trapozoid)

<ADE ≅ <BCF (congruent property of two triangles)

Therefore, it can be concluded that;

ΔADE = ΔBCF (Side-Angle-Side congruent property)

b) Given that AB = 8 cm, and DC = 18 cm.

Then,

CD = DE + EF + FC

18 = DE + 8 + FC   (since EF = AB)

18 - 8 = 2 DE     (since DE = FC)

DE = 5 cm

Thus, DE = 5 cm and CF = 5 cm

c) To determine the value of AE, we have to apply the Pythagoras theorem. So that;

[tex]/Hyp/^{2}[/tex] = [tex]/Adj 1/^{2}[/tex] + [tex]/Adj 2/^{2}[/tex]

[tex]13^{2}[/tex] = [tex]AE^{2}[/tex] + [tex]5^{2}[/tex]

169 - 25 =  [tex]AE^{2}[/tex]

[tex]AE^{2}[/tex] = 144

AE = [tex]\sqrt{144}[/tex]

     = 12

AE = 12 cm

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Step-by-step explanation:

Answer:

31 and 37

Step-by-step explanation:

Those are the only two numbers

Answer:

The two numbers between 30 and 40 which have only 2 factors are -

31 and 37

Hope it helps you.

This statement is true that the In c 11 you cannot use a range-based for loop to modify the contents of an array unless you declare the range variable as a reference variable.

According to the statement

we have given that the one statement and we have to tell that the those statement is true or false after analyzing it.

So,

In C++ 11 is  a programming language which is used to write the coding. And in this language you cannot use a range-based for loop to modify the contents of an array unless you declare the range variable as a reference variable.

Because in the coding it is not possible that the you can make loop without declare the random variable in the loop.

Due to this reasons without declare the variable it is not possible.

So, This statement is true that the In c 11 you cannot use a range-based for loop to modify the contents of an array unless you declare the range variable as a reference variable.

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Answer:

Multiply 3 and 4, then subtract that total from 5.

Step-by-step explanation:

You would need to follow P.E.M.D.A.S.

Parentheses, Exponents, Multiply & Divide, Add & Subtract

Hope that helps! Let me know if you need more help. Please mark me as brainliest!

Answer:

x = 6

Step-by-step explanation:

put '3' in where 'y' is :

7x + 2(3) = 48

7x + 6 = 48              subtract 6 from both sides of the equation

7x = 42                 divide both sides by 7

x = 6

The graph that shows the solutions for the inequality, y > -1/3x + 1 is: C. Graph A.

The inequality sign, ">" means that the graph of the inequality has a dashed line where the shaded part is above the boundary line and the boundary line is dashed or dotted. If "≥" is used, the boundary line would not be dashed or dotted and the shaded area would be above it.

On the other hand, "<" is used when the shaded area is below the boundary line and the boundary line is a dashed line. If "≤" was used, the boundary line won't be dashed or dotted, while the shaded area would be below the boundary line that is not dotted.

Given y > -1/3x + 1, the slope (m) = change in y / change in x is -1/3.

Graph A has a slope of -1/3 and the shaded part is above the boundary line.

Therefore, the graph that shows the solutions for y > -1/3x + 1 is: C. Graph A.

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Answer:

Step-by-step explanation:

9. the set containing all objects or elements and of which all other sets are subsets.

10. complement --> the amount in only one of teh sets

intersection --> the amount in both sets

11. 14 or -14

13. 46 1/2

14. 2 31/120

15. 1100% profit

16. 1200 gm

17. cube root of 7?

18. 6000 per year

Answer:

65°

Step-by-step explanation:

JM = JK (all sides of a rhombus are equal)

Angle JKM = 25° (isosceles triangle)

Angle JKL = 50° (consecutive angles of rhombus)

Angle MKL = 25° (angle subtraction)

Angle MLK = 130° (opposite angles of a rhombus)

Angle KLN = 50° (angles on a straight line)

Angle LKN = 40° (angle sum of triangle)

Angle MKN = 65° (angle addition)

Answer:

P = 1/3

P = 0.333

Step-by-step explanation:

There are 6 marbles in the pack, two of them are yellow.

[tex]P=\frac{2}{6} =\frac{1}{3}[/tex]

Hope this helps

Answer:

  a.  1080

  b.  405

Step-by-step explanation:

Function evaluation is often conveniently done using a calculator. Many calculators know about the order of operations, so can be used without fear of an incorrect evaluation.

Put the value where the variable is and do the arithmetic.

  f(x) = 40(3^x)

  f(3) = 40(3^3) = 40(27) = 1080

  g(x) = 5(3^(x+1))

  g(3) = 5(3^(3+1)) = 5(3^4) = 5(81) = 405

EachEach value of time elapsed (in seconds) corresponding instantaneous velocity (in feet/second) are:2s= 96, 3s = 64, 4s= 32, 5s = 0, 6s = -32, 7s = -64. 8s= -96, 9s= -128.

Given equation:

f(t) = -16t² +160t

Velocity (v)=df(t)/dt

=-2×16t²+ 160t

=-32t+160

Hence:

-32t+160

1.     -32×(1) + 160 =    128ft/s

2.    -32×(2) + 160 =    96ft/s

3.    -32×(3) + 160 =    64ft/s

4.    -32×(4) + 160 =     32m/s

5.    -32×(5) + 160 =     0m/s

6.   -32×(6) + 160 =   -32m/s

7.    -32×(7) + 160 =    -64m/s

8.   -32×(8) + 160 =    -96m/s

9.    -32×(9) + 160 =   -128m/s

The pairs are;

2s= 96

3s = 64

4s= 32

5s = 0

6s = -32

7s = -64

8s= -96

9s= -128

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Answer: 5 cm

Step-by-step explanation:

B = [tex]\sqrt{13^{2} -12^{2} } = 5[/tex]

Answer:

OPTION C, 5

Step-by-step explanation:

Using the formula, substitute the hypotenuse and the other leg of the right triangle.

13²=12²+b²

Rearrange appropriately.

13²-12²=c²

Convert.

13²=169

12²=144

Apply and work out.

169-144= 25

c²=25

c=√25

c=5

OPTION C is therefore the answer.

Please comment below if you need more help! :)

Answer: 1223.07

Step-by-step explanation: you don't round up

Answer: [tex]\Large\boxed{x=6.5}[/tex]

Step-by-step explanation:

Given equation

-9 - (x + 1) = -2 - (3x - 5)

Expand the parenthesis

-9 - x - 1 = -2 - 3x + 5

Combine like terms

-9 - 1 - x = -2 + 5 - 3x

-10 - x = 3 - 3x

Add 3x on both sides

-10 - x + 3x = 3 - 3x + 3x

-10 + 2x = 3

Add 10 on both sides

-10 + 2x + 10 = 3 + 10

2x = 13

Divide 2 on both sides

2x / 2 = 13 / 2

[tex]\Large\boxed{x=6.5}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

if you end up landing on a heads you should walk away with a $1.46

The probability that it also rained that day is to be considered as the 0.30 and the same is to be considered.

The extent to which an event is likely to occur, measured by the ratio of the favorable cases to the whole number of cases possible.

The probability that the temperature is lower than 80°F and it rained can be measured by determining the number at the intersection of a temperature that less than 80°F and rain.

So, This number is 0.30.

Hence, we can say that it was less than 80°F on a given day, the probability that it also rained that day is 0.30.

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The above question is incomplete.

The conditional relative frequency table was generated using data that compared the outside temperature each day to whether it rained that day. A 4-column table with 3 rows titled weather. The first column has no label with entries 80 degrees F, less than 80 degrees F, total. The second column is labeled rain with entries 0.35, 0.3, nearly equal to 0.33. The third column is labeled no rain with entries 0.65, 0.7, nearly equal to 0.67. The fourth column is labeled total with entries 1.0, 1.0, 1.0. Given that it was less than 80 degrees F on a given day, what is the probability that it also rained that day?

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Answer: Its 0.3 so the first one

Step-by-step explanation:

Im 101% sure

Answer:

Ascending Order: 0.432 < 0.5734 < 0.76373

Descending Order: 0.76373 < 0.5734 < 0.432

Step-by-step explanation:

Check the tenths place of the decimal number and order them accordingly. If the tenths place is the same for two decimal numbers, go on to the next corresponding place to compare their values.

Profit decreased by 7.5%

Answer:

Solution Given:

Marked Price= Rs 6,000

discount =20%

Selling Price =M.P- discount% of M.P

=M.P(1-discount%)

=6000(1-20%)

= Rs 4,800

Again

Profit = 20%

Cost Price=(S.P*100)/(100+profit%)

= (4800*100)/(100+20%)

= Rs 4,000

For discount 25%

Marked Price =Rs 6,000

Selling Price =M.P - discount% of M.P

=M.P(1-discount%)

=6000(1-25%)

=Rs 4,500

Profit = S.P- C.P= Rs 4,500- Rs 4,000=Rs 500

Profit %=Profit/C.P* 100%= 500/4000*100 = 12.5%

Profit % decreased from 20% to 12.5%

Profit decreased by 7.5%

Answer:

7.5%

Step-by-step explanation:

Marked Price

Rs 6,000

Discounted Price

If the price is discounted by 20%, then the discounted price is 80% of the marked price:

[tex]\implies \sf Discounted\:Price =80\% \textsf{ of marked price}[/tex]

[tex]\implies \sf Discounted\:Price =0.8 \times 6000[/tex]

[tex]\implies \sf Discounted\:Price = 4800\:Rs[/tex]

Cost Price

If the dealer makes 20% when selling the watch at the discounted price, then the cost price is:

[tex]\implies \sf Cost\:Price=\dfrac{100\%}{120\%} \times 4800[/tex]

[tex]\implies \sf Cost\:Price=\dfrac{4800}{1.2}[/tex]

[tex]\implies \sf Cost\:Price=4000\:Rs[/tex]

Discount of 25%

If the price is discounted by 25%, then the discounted price is 75% of the marked price:

[tex]\implies \sf Discounted\:Price =75\% \textsf{ of marked price}[/tex]

[tex]\implies \sf Discounted\:Price =0.75\times 6000[/tex]

[tex]\implies \sf Discounted\:Price = 4500\:Rs[/tex]

Profit after 25% discount

[tex]\implies \sf Profit=\dfrac{discounted\:price}{cost\:price}-1 \times 100[/tex]

[tex]\implies \sf Profit=\dfrac{4500}{4000}-1 \times 100[/tex]

[tex]\implies \sf Profit=12.5\%[/tex]

Therefore, the profit decreased from 20% to 12.5% which means the profit percent decreased by 7.5%.

The results of the division of polynomials are given as follows:

Considering that x² - 9 is the subtraction of perfect squares, we have that:

x² - 9 = (x - 3)(x + 3)

Hence the division is:

h(x) = (x - 3)(x + 3)/(x - 3) = x + 3.

Considering that x² - 16 is the subtraction of perfect squares, we have that:

x² - 16 = (x - 4)(x + 4)

Hence the division is:

h(x) = (x - 4)(x + 4)/(x - 4) = x + 4.

Considering that the roots of x² - 4x + 3 are x = 1 and x = 3, we have that:

x² - 4x + 3 = (x - 1)(x - 3).

Hence the division is:

h(x) = (x - 1)(x - 3)/(x - 3) = x - 1.

Considering that the roots of x² + 4x - 5 are x = -5 and x = 1, we have that:

x² + 4x - 3 = (x + 5)(x - 1).

Hence the division is:

h(x) = (x + 5)(x - 1)/(x - 1) = x + 5.

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If a salesperson has 7 customers in denver and 13 customers in reno then there are 20 different ways in which he can make calls.

Given that the salesperson has 7 customers in denver and 13 customers in reno.

We are required to find the number of ways in which he can make use of telephone.

Number of customers in denver=7

Number of customers in reno=13

Total customers=20

Since he can talk to one customer at one time and he can either choose customer from denver or reno, the number of ways by using combinations will be [tex]7C_{1}[/tex]+[tex]13C_{1}[/tex]

=7+13

=20 ways.

Hence if a salesperson has 7 customers in denver and 13 customers in reno then there are 20 different ways in which he can make calls.

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The total amount he puts towards emergency savings is $74

The correct option is C.

His total weekly deposits are as follows: 219+115+40+20+10+40+15 = 459

Now

that we are aware, his weekly deposits total $459 in total.

His total remuneration is $498 due to an error in his addition of the numbers.

The amount he has each week will be determined by deducting his deposits from his paycheck:

498-459 = 39

He contributes two equal payments of $20 and $15 to his emergency fund.

His entire contribution to emergency savings is = 20 + 15 = 35.

Only need to add the additional $39

To determine how much he can set aside each week for emergency savings, multiply his total emergency savings by 35 dollars:

39+35 = 74

the total per week that he can put towards emergency savings = $74

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I understand that the question you are looking for is:

Mr. Thom makes $25,900/year salary as a document processor. He has made the following chart in order to divide his weekly paycheck into his accounts: Expense type Account Weekly deposits Essential (Fixed) 1st Checking account $219 Essential (Variable) 1st Checking account $115 Non-essential 2nd Checking account $40 Other (Unexpected) Emergency savings account $20 Other (Pictable) Education investment fund $10 Other (Pictable) Retirement investment fund $40 Other (Pictable) Emergency savings account $15 Total paycheck $498 Unfortunately, he has made a mistake in adding the numbers and has not allocated all of the paycheck. If he deposits the difference into the two emergency savings accounts, how much total per week can he then put towards emergency savings?

a. $40

b. $60

c. $74

d. $55

Answer: C. $74

Step-by-step explanation:  C. $74.00

45 candidates are expected to be rejected.

What is a percentage in math?

Here, we want to calculate the number of candidates to be rejected

The number of candidates to be rejected can be calculated from;

100% - (28% + 12%) = 60%

So 60% of the 75 interviewed are to be rejected

Thus, we have

60/100 * 75

= 45

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A semicircle is a part of a circle, and it is referred to as half of a given circle. Thud the area of the semi-circle window is 982 [tex]in^{2}[/tex].

A circle is a shape that is bounded by a curved path which is referred to as the circumference. Some parts of a circle are radius, diameter, sector, arc, semi-circle, circumference, etc.

A semicircle is a part of a circle, and it is referred to as half of a given circle.

such that:

Area of a circle = [tex]\pi[/tex] [tex]r^{2}[/tex]

and

area of a semicircle = [tex]\frac{\pi r^{2} }{2}[/tex]

where: r is the radius of the circle, and [tex]\pi[/tex] is a constant with a value of [tex]\frac{22}{7}[/tex].

Thus from the given question, it can be inferred that;

r = [tex]\frac{50}{2}[/tex]

 = 25

r = 25 in

Thus, the area of the semi-circle can be determined as;

area of the semi-circle = [tex]\frac{1}{2}[/tex] * [tex]\frac{22}{7}[/tex] * [tex]25^{2}[/tex]

                                      = 982.1429

area of the semi-circle = 982.14 [tex]in^{2}[/tex]

The area of the semi-circle window is approximately 982 [tex]in^{2}[/tex].

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Answer Section 1. <3
Heyy, I'm sunny and I'm here to help you :)
(P.S: answer in explanation)

----------------------------------------------------------------------------------------------------------
Explanation Section:

It is false

If f(x) is a function , then for each value of x there should be  a single y values

For input 0 there is a output 0

for input 10, the output is 2

for input 15, output is 3

For input 5, we have two output 1 and 3

for single input 5, the function cannot have two outputs 1  and 3

So this f(x) is not a function

Bye! - SunnyBunny <3

The given expression 2^8 * 8^2 * 4^-4 can be written in the exponential form 2^n as 2^6.

The exponential form is a more convenient way to write repetitive multiplication of the same integer by using the base and its exponents.

For example:

If we have a*a*a*a, it can be written in exponential form as:

=a^4

where

The power in this format reflects the number of times we multiply the base by itself. The exponent is also known as the index or power. 

From the information given:

We can write 2^8 * 8^2 * 4^-4 in form of 2^n as follows:

[tex]\mathbf{= 2^8\times (2^3)^2 \times (2^2)^{-4} }[/tex]

[tex]\mathbf{= 2^8\times (2^6) \times (2^{-8}) }[/tex]

[tex]\mathbf{= 2^{8+6+(-8)}}[/tex]

[tex]\mathbf{= 2^{6}}[/tex]

Therefore, we can conclude that by using the exponential form, the given expression 2^8 * 8^2 * 4^-4 in the form 2^n is 2^6.

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