What is the least common multiple of 6x^2+39x-21 and 6x^2+54x+84?

What Is The Least Common Multiple Of 6x^2+39x-21 And 6x^2+54x+84?

Answers

Answer 1

12x² + 102x² + 114x - 84

Answer:

Solution Given:

1st term: 6x²+39x-21

Taking common

3(2x²+13x-7)

doing middle term factorization

3(2x²+14x-x-7)

3(2x(x+7)-1(x+7))

3(x+7)(2x-1)

2nd term: 6x²+54x+84

taking common

6(x²+9x+14)

doing middle term factorization

6(x²+7x+2x+14)

6(x(x+7)+2(x+7))

2*3(x+7)(x+2)

Now

Least common multiple = 2*3(x+7)(2x-1)(x+2)

2(x+2)(6x²+39x-21)

(2x+4)(6x²+39x-21)

2x(6x²+39x-21)+4(6x² + 39x-21)

12x³+78x² - 42x+4(6x² + 39x-21)

12x³+78x² - 42x + 24x² + 156x-84

12x³ + 102x²-42x + 156x - 84

12x² + 102x² + 114x - 84

Answer 2

Answer:

[tex]12x^3+102x^2+114x-84[/tex]

Step-by-step explanation:

Given polynomials:

[tex]\begin{cases} 6x^2+39x-21\\6x^2+54x+84 \end{cases}[/tex]

Factor the polynomials:

Polynomial 1

[tex]\implies 6x^2+39x-21[/tex]

[tex]\implies 3(2x^2+13x-7)[/tex]

[tex]\implies 3(2x^2+14x-x-7)[/tex]

[tex]\implies 3[2x(x+7)-1(x+7)][/tex]

[tex]\implies 3(2x-1)(x+7)[/tex]

Polynomial 2

[tex]\implies 6x^2+54x+84[/tex]

[tex]\implies 6(x^2+9x+14)[/tex]

[tex]\implies 6(x^2+7x+2x+14)[/tex]

[tex]\implies 6[x(x+7)+2(x+7)][/tex]

[tex]\implies 6(x+2)(x+7)[/tex]

[tex]\implies 2 \cdot 3(x+2)(x+7)[/tex]

The lowest common multiplier (LCM) of two polynomials a and b is the smallest multiplier that is divisible by both a and b.

Therefore, the LCM of the two polynomials is:

[tex]\implies 2 \cdot 3(x+7)(x+2)(2x-1)[/tex]

[tex]\implies (6x^2+54x+84)(2x-1)[/tex]

[tex]\implies 12x^3+108x^2+168x-6x^2-54x-84[/tex]

[tex]\implies 12x^3+102x^2+114x-84[/tex]


Related Questions

what is 7/8 - 1/2 as a fraction

Answers

Answer: 3/8

Step-by-step explanation:

1/2 is also 4/8 so you subtract 4/8 from 7/8 to get 3/8

HELPP PLSSS I NEED HELP!!!

Answers

Answer:

(3+3) x (3+1)

Step-by-step explanation:

free

Given :

We have give 4 numbers that are 1,3,3,3. we have to apply operations on it to make it 24.

Solution :

» (1 + 3) × (3 + 3)

» (4) × (6)

» 24

Here's our answer..!!

A barn that holds hay for the cows is shown below. If you see the hay for $1.50 per cubic foot, how much money could
you make if the barn is completely full?

Answers

If the price of 1 cubic foot of hay is $10 then the money needed is $15.

Given the price of 1 cubic foot of hay be $10 and the amount of hay be $1.50.

We are required to find the amount of money needed to buy the hay.

We know that the amount of money that can be spend on something is the product of price of one unit and number of units.

Product is the result when two numbers are multiplied with each other.

Total money =Price of 1 cubic foot*$1.50

=10*1.50

=$15

Hence if the price of 1 cubic foot of hay is $10 then the money needed is $15.

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Question is incomplete, the right question is as under:

1.5 cubic foot hay is required to fill a room completely. Calculate the amount we have to pay to fill the room completely if the price of 1 cubic foot is $10?

Volume oblate spheroid

Answers

The volume of the oblate spheroid is approximately equal to 75.398 cubic feet.

What is the volume of an oblate spheroid?

In this problem we have the shape of an ellipse centered at origin, whose vertex form is shown below:

x² / a² + y² / b² = 1        (1)

Where a, b are the lengths of the semiaxes, in feet.

An oblate spheroid is generated by revolving half of the ellipse about the y-axis. Oblate spheroids are a kind of ellipse:

x² / a² + y² / b² + z² / a² = 1       (2)

Where a, b, c are the lengths of the semiaxes, in feet.

And the volume of the oblate spheroid is:

V = (4 / 3) · π · a² · b      (3)

If we know that a = 3 ft, b = 2 ft, then the volume of the oblate spheroid is:

V = (4 / 3) · π · (3 ft)² · (2 ft)

V ≈ 75.398 ft³

The volume of the oblate spheroid is approximately equal to 75.398 cubic feet.

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The scatter plot shows the relationship between the test scores of a group of students and the number of hours they exercise in a week:

On a grid, Label Hours of Exercise on x axis and Test Scores on y axis. The title of the graph is Test Scores and Exercise. The scale on the x axis shows the numbers from 0 to 10 at increments of 1, and the scale on the y axis shows numbers from 0 to 100 at increments of 10. Dots are made at the ordered pairs 1.1, 12 and 1, 30 and 2.1, 21 and 2.5, 42 and 3.5, 30 and 3.5, 45 and 4, 55 and 5, 45 and 5.5, 60 and 5.5, 70 and 6.5, 40 and 7, 50 and 7.5, 80 and 8, 75, and 8.5, 60 and 9, 75. The ordered pair 9, 15 is circled and labeled as T. All the other points are put in an oval and labeled as P.

Part A: What is the group of points labeled P called? What is the point labeled T called? Give a possible reason for the presence of point T. (5 points)

Part B: Describe the association between students' test scores and the number of hours they exercise. (5 points)

Answers

It should be noted that Group A is a cluster of points with similar property or relationship and Point B is an outlier. This is the point outside of the common relationship in the scatterplot

What is a scatterplot?

It should be noted that scatter plots are the graphs that present the relationship between two variables in a data-set. It represents data points on a two-dimensional plane or on a Cartesian system.

In this case, the independent variable or attribute is plotted on the X-axis, while the dependent variable is plotted on the Y-axis.

The association between students' test scores and the number of hours they exercise is that there is a negative tendency. As number of hours spent on computer games increase, the test scores decrease.

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Find the mode for the scores 3,760, 5,200, 8,750, 4,400, 5,250

Answers

Answer:

no mode

Step-by-step explanation:

no number appears more than once

therefore there is no mode

Find the gradient of the line joining the points P(2,5) and Q(4,-2).​

Answers

Answer is -7/2

Gradient or slope is found by change in y over change in x.
Or
(y2 - y1) over (x2 - x1)

So
(-2 -5) over (4-2)
= -7/2

The Bourassas decide to sell a home for $440,000. They are charged a real estate commission of 8% of the selling price, title insurance that is 1.4% of the selling price, and an escrow fee of $775.
(a)
What amount (in dollars) do the Bourassas receive after fees?
$
(b)
What percentage of the selling price was fees? Round to the nearest tenth of a percent.
%

Answers

The amount received net of expenses is $397865 and the percentage of the sale price was 10%.

Given that Bourassas decides to sell a house for $ 440,000. You will be charged a real estate fee of 8% of the sale price, property insurance of 1.4% of the sale price, and an escrow fee of $ 775.

The declared retail price is $ 440,000.

Real estate commission = 8% of the sale price

Real Estate Fee = (8/100) × 440000

Real Estate Fee = 8 × 4400

Real Estate Fee = $ 35,200

Security insurance costs of the title = 1.4% of the sale price

Cost of title insurance = (1.4 / 100) × 440 000

Cost of title insurance = 1.4 × 4400

Title Insurance Cost = $ 6160

The escrow fee assigned is $ 775.

(a) In determining the amount received after deducting the sale price of the property commission, title insurance and escrow fees, we receive

Amount received after fees = sale price - real estate commission - title insurance - escrow fees

Amount received after fees = 440000-35200-6160-775

The amount received after fees = $397865

(b) To find the percentage of sale price, add together all the terms real estate commission, title insurance and escrow fees and divide by the sale price we get

Percentage of selling price=((35200+6160+775)/440000)×100

Percentage of sale price = (42135/440000) × 100

Percentage of sale price = 9.57

Percentage of sale price = 10% (rounded down)

Hence Bourassas decides to sell a house for $440,000, then the amount Bourassas will receive after expenses is $397,865 and the percentage of the sale price of expenses is 10%.

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PLEASE HELP ME WITH THIS QUESTION I NEED HELP

Answers

Answer:

True

Step-by-step explanation:

This is true in an equilateral triangle.

I need help… a lot of it im so confused

Answers

1)

[tex] \sqrt[3]{b {}^{2} } = b {}^{ \frac{2}{3} } [/tex]

2)

[tex]f(4) = 2(3) {}^{4} = 2 \times 81 = 162[/tex]

3)

[tex]f( \frac{1}{2} ) = \frac{1}{3} (9) {}^{ \frac{1}{2} } + 5 = \frac{ \sqrt{9} }{ 3} + 5 = 6[/tex]

4)

[tex]f(5) = - 4(2) {}^{ - 5 + 1} = - 4(2) {}^{ -4} = \frac{2 {}^{2} }{2 {}^{4} } = \frac{1}{2 {}^{2} } = \frac{1}{4} [/tex]

5)

[tex]f(10) = 2e {}^{0.15 \times 10} = 2e {}^{1.5} = 8.96[/tex]

6)

[tex]y = 10(b) {}^{x} \: \: \\ 10 = 10(b) {}^{0} \: duh \\ 2 = 10b {}^{1} \\ b = \frac{2}{10} = \frac{1}{5} [/tex]

7)

[tex]y = a(b) {}^{x} \\ 3 = a(b) {}^{0} \\ a = 3 \\ \\75 = 3(b) {}^{2} \\ b {}^{2} = 25 \\ b = + 5 \: \: \: or \: \: \: \: b = - 5[/tex]

8)

[tex]s = 1000(1 + \frac{0.045}{4} ) {}^{4 \times 10} = 1564.38[/tex]

9)

[tex]s = 2500.e {}^{0.07 \times 20} = 10138[/tex]

Find one possible missing coordinate so that the point becomes a solution to the given inequality.



(x,6) is a solution to 6x−6>y .

Answers

Answer:

Step-by-step explanation:

6x-6>y

put y=6

6x-6>6

6x>12

x>12/6

x>2

(3,6) is one solution.

. What are the values a b and c In the following quadratic equation ? -6x^2-8x+12=0

Answers

Answer:

a = -6

b = -8

c = 12

Step-by-step explanation:

Quadratic equations follow the general structure:

ax² + bx + c = 0

In this equation, "a" and "b" serve as coefficients which modify the variables and "c" represents the y-intercept. Since the given equation is in the quadratic form, you can easily identify which values match the variables.

-6x² - 8x + 12 = 0

a = -6

b = -8

c = 12

Someone please help me with this thank you!

Answers

Answer:

50°

Step-by-step explanation:

Note EFGH is an isosceles trapezoid.

∠HGF=77° (base angles of an isosceles trapezoid are congruent)

∠EGH=27° (angles in a triangle add to 180°)

∠FGE=50° (angle subtraction postulate)

When it is Noon (12 pm) in London, it is 10pm in Sydney, Australia. Dan in London rings his friend Boski in Sydney at 15:30pm on Christmas Day. What time is it in Sydney?
A. 1am
B. 1:30am
C. 2am
S. 2:30am

Answers

The time at Sydney when Dan rings his friend is 1 : 30 am (option B).

What is the time at Sydney?

The first step is determine the time difference between London and Sydney.

Time difference = time at Sydney - time at London

( 12 + 10pm) - 12pm

22pm - 12pm = 10 hours

The second step is to add the time difference to the time it was when Dan rang.

15 : 30 pm + 10pm = 25 : 30

We know that there are only 24 hours in day, so subtract 24 hours from 25 : 30

25 : 30 - 24 = 1 : 30 am

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72 is 15% of what number?

Answers

Answer: 480

Step-by-step explanation:

72/3 is 5% of the number we are looking for.
72/3=24
24*20 will be 100%
480 is 100%

We apply the rule of three simple direct

72 is 15% of what number?

Quantity          %

  72---------------15

   x---------------100

We solve

[tex]\boldsymbol{\sf{x=\dfrac{72\times100 }{15}=\dfrac{7200}{15}=480 }}[/tex]

Answer: 72 is 15% of 480.

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What is the slope of the line that passes through the points (8, 0) and (-4, -8)?
Write your answer in simplest form.

Answers

Answer:

Step-by-step explanation:

(-8 - 0)/(-4 - 8)= -8/-12 = 2/3

The slope of the line that passes through the points (8, 0) and (-4, -8) exists at 0.66667.

How to estimate the slope of the line?

The slope or gradient between two points in the Cartesian coordinate system. The slope exists the amount of slant a line retains and can maintain a positive, negative, zero, or undefined value.

Using the slope formula [tex](y_2 - y_1)/(x_2 - x_1)[/tex]

[tex]x_1 = 8, y_1 = 0[/tex] and [tex]x_2 = -4 , y_2= -8[/tex]

slope [tex]= (y_2 - y_1)/(x_2 - x_1)[/tex]

= ((-8) - 0) / ((-4) - (8))

= (-8) / (-12) = (-2) / (-3)

= 0.66667

Therefore, the slope of the line that passes through the points (8, 0) and (-4, -8) exists at 0.66667.

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AMERICAN AIRLINES HAS A POLICY OF BOOKING AS MANY AS 15 PEOPLE ON AN AIRPLANE THAT CAN SEAT ONLY 14. (PAST STUDIES HAVE REVEALED THAT ONLY
85% OF THE BOOKED PASSENGERS ACTUALLY ARRIVE FOR THE FLIGHTS.) FIND THE PROBABILITY THAT IF AMERICAN AIRLINES BOOKS 15 PEOPLE, NOT ENOUGH SEATS
WILL BE AVAILABLE

Answers

Using the binomial distribution, there is a 0.0874 = 8.74% probability that not enough seats will be available.

What is the binomial distribution formula?

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.

For this problem, the values of the parameters are given by:

n = 15, p = 0.85.

The probability that not enough seats will be available is P(X = 15), as the only outcome in which not enough seats will be available is when all 15 people who bought the ticket show up, hence:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 15) = C_{15,15}.(0.85)^{15}.(0.15)^{0} = 0.0874[/tex]

0.0874 = 8.74% probability that not enough seats will be available.

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find the zeros x^4-2x^3-44x^2-88x-32

Answers

The zeros which are the roots of the polynomial expressions are:

x = -4; x = - 2;  x = 4 - 2√5;  x = 2(2 + √5)

What are the zeros of a polynomial expression?

The zeros of a polynomial f(x) are really the values of x that answer the equation f(x) = 0. Thus, f(x) is a function of x, and the polynomial zeros refer to the values of x, which makes the f(x) value equal to zero. The digit of zeros in a polynomial is decided by the degree of equation f(x) = 0.

For a polynomial, there may be specific values of the variable for which the polynomial is zero. These are known as polynomial zeros. They are also known as polynomial roots. In essence, we look for the zeros of quadratic equations to discover the solutions to the given equation.

From the given equation, the zeros of x^4-2x^3-44x^2-88x-32 can be computed as follows:

Using the rational root theorem:

[tex]\mathbf{= (x+2)\dfrac{x^4-2x^3-44x^2-88x-32}{x+2} }[/tex]

[tex]\mathbf{=(x+2) (x^3-4x^2-36x-32) }[/tex]

By factorization, we have:

= (x + 2) (x + 4) (x² - 8x - 4)

The zeros which are the roots of the polynomial expressions are:

x = -4; x = - 2;  x = 4 - 2√5;  x = 2(2 + √5)

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How many grams of the isotope remains after 90 days?

Answers

Answer:

84,08964 [gr.].

Step-by-step explanation:

for more details see in the attachment.


Compute the probability of event E if the odds in favor of E are 28 to 29.

Answers

Answer:

28/57

Step-by-step explanation:

odds in favor of event occurring = (probability event occurs)/(probability event does not occur)

Let p = probability event occurs.

Then the probability the event does not occur is 1 - p.

Let the odds = a/b.

a/b = p/(1 - p)

a(1 - p) = bp

a - ap = bp

bp + ap = a

p(a + b) = a

p = a/(a + b)

p = 28/(28 + 29)

p = 28/57

As per the given scenario, the probability of event E is 28/57 or approximately 0.4912.

What is probability?

Probability is a measure of the likelihood or chance of an event occurring. It is usually expressed as a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain to occur.

If the odds in favor of an event E are "a to b," then the probability of E is given by:

P(E) = a / (a + b)

In this case, the odds in favor of E are 28 to 29, which means that there are 28 favorable outcomes for E and 29 unfavorable outcomes against E.

So, using the formula above, we can compute the probability of E as:

P(E) = 28 / (28 + 29)

P(E) = 28 / 57

Therefore, the probability of event E is 28/57 or approximately 0.4912.

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Answers for number 32 and 31

Answers

Answer:

32: X=54

31: Xx54+74

What are the coordinates of the vertex of the parabola with the equation y = x2 + 2x – 3?

A
(-1, -4)

B
(1, -4)

C
(3, -4)

D
(-3, 12)

Answers

Answer:

  A.  (-1, -4)

Step-by-step explanation:

The vertex can be found by converting the equation from standard form to vertex form.

Vertex

Considering the x-terms, we have ...

  y = (x^2 +2x) -3

where the coefficient of x is 2. Adding (and subtracting) the square of half that, we get ...

  y = (x^2 +2x +(2/2)^2) -3 -(2/2)^2

  y = (x +1)^2 -4

Compare this to the vertex form equation ...

  y = a(x -h)^2 +k

which has vertex (h, k).

We see that h=-1 and k=-4. The vertex is (h, k) = (-1, -4).

On the attached graph, the vertex is the turning point, the minimum.

Find the surface area of the composite figure 4 cm 13 cm 3 cm 4 cm 12 cm SA = [?] cm² 5 cm 3 cm.

Answers

area of rectangle ( bottom)
12x4=48

side of rectangle ( 2 of them)
4x3x2=24

length of rectangle (2 of them)
12x3x2=72

area of triangle facing us ( 2 of them)
1/2x5x12x2= 60

top part of triangle
13x4= 52

back part of triangle :
4x5=20

total = add them all together
= 276

1 Which is the greatest 4- digit number divisible by 6?......​
As fast as when u are running to save ur mom life

Answers

Answer:

The greatest four-digit number that is divisible by 6 is 9996

Step-by-step explanation:

9,996 / 6 = 1,666

I am confused. Can somebody explain this to me?
Maryann can paint a wall in 45 minutes. It takes her brother Junior 1 hour and 45 minutes to paint the same wall. How many minutes would it take Maryann and Junior to paint the wall, if they work together? Answer as a decimal to the nearest tenth.

Answers

Answer: If they worked together, it would take 31.5 minutes

Step-by-step explanation:

There's a certain formula for equations like this:

[tex]\frac{1}{t1} +\frac{1}{t2}=\frac{1}{tb}[/tex]

t1= the time it took for the first person to complete the task.

t2= the time it took for the second person to complete the task.

tb= the time it took for both of them to complete the task.

We have the values for both t1 and t2, but not for tb.

t1= 45

t2= 105

tb= x

[tex]\frac{1}{45} +\frac{1}{105} = \frac{1}{x}[/tex]

Now it's simple algebra, and all we need to do is solve for x

The LCM for both fractions is 315, so now we multiply BOTH sides of the equation by 315.

[tex]\frac{315}{45} + \frac{315}{105} = \frac{315}{x}[/tex]

This will simplify nicely, so now we just need to get x on the other side.[tex]7 + 3 = \frac{315}{x} \\\\\ 10*x = \frac{315}{x} * x[/tex]

[tex]10x = 315 \\\\x = 31.5[/tex]

P = √mx_ £x MX t make x the subject
[tex]p = \sqrt{ \frac{mx}{t} } - t {}^{2}x \: \: make \: x \: the \: subject [/tex]

Answers

So, making x subject of the formula, x = [m - 2pt³ ±√(m²  - 4pt²m)]/{2t⁵}

How to make x subject of the formula?

Since p = √(mx/t) - t²x

So, p + t²x = √(mx/t)

Squaring both sides, we have

(p + t²x)² = [√(mx/t)]²

p² + 2pt²x + t⁴x² = mx/t

Multiplying through by t,we have

(p² + 2pt²x + t⁴x²)t = mx/t × t

p²t + 2pt³x + t⁵x² = mx

p²t + 2pt³x + t⁵x² - mx = 0

t⁵x² + 2pt³x - mx + p²t = 0

t⁵x² + (2pt³ - m)x + p²t = 0

Using the quadratic formula, we find x.

[tex]x = \frac{-b +/-\sqrt{b^{2} - 4ac} }{2a}[/tex]

where

a = t⁵, b = (2pt³ - m) and c =  p²t

Substituting the values of the variables into the equation, we have

[tex]x = \frac{-(2pt^{3} - m) +/-\sqrt{(2pt^{3} - m)^{2} - 4(t^{5})(p^{2}t) } }{2t^{5} }\\= \frac{-(2pt^{3} - m) +/-\sqrt{4p^{2} t^{6} - 4pt^{2}m + m^{2} - 4p^{2}t^{6} } }{2t^{5}}\\= \frac{-(2pt^{3} - m) +/-\sqrt{m^{2} - 4pt^{2}m } }{2t^{5}}\\= \frac{m - 2pt^{3} +/-\sqrt{m^{2} - 4pt^{2}m } }{2t^{5}}[/tex]

So, making x subject of the formula,  [tex]x = \frac{m - 2pt^{3} +/-\sqrt{m^{2} - 4pt^{2}m } }{2t^{5}}[/tex]

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Two buses leave a station at the same time and travel in opposite directions. One bus travels 18 miles per hour faster than the other. If the two buses are 744 miles apart after 6 hours, what is the rate of each bus?

Answers

Answer:

53 mph   and  71 mph

Step-by-step explanation:

bus 1 rate = x

bus 2 rate = x + 18

rate times time = distance

( x    +    x+18) * 6 = 744

(2x+18) * 6 = 744

2x + 18 = 124

2x = 106

x = 53       the other bus is  53 + 18 =  71  mph

Which pair of functions are inverses of each other? O A. F(a) = I - 9 and g(2) = 2*9 O B. Ax) = 5x - 11 and g(a) = 2+11 O C. F(a) = V2m and g(2) = (3) ° O D. f(a) = ; + 8 and g(x) = 6x - 8 SUBMIT

Answers

The pair of functions that are inverses of each other is (a) f(x) = 5x - 11 and g(x) = (x + 11)/5

How to determine the function and the inverse?

The complete question is added as an attachment

Function 1

f(x) = 5x - 11 and g(x) = (x + 11)/5

Represent 5x - 11 with y in f(x) = 5x - 11

y = 5x - 11

Swap x and y

x = 5y - 11

Add 11 to both sides

x + 11 = 5y

Divide by 5

y = (x + 11)/5

Express as a function

g(x) = (x + 11)/5

From the question, we have:

f(x) = 5x - 11 and g(x) = (x + 11)/5

This means that the function g(x) is an inverse of the function f(x)

Hence, the pair of functions that are inverses of each other is (a) f(x) = 5x - 11 and g(x) = (x + 11)/5

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Which of the following is the solution to 8√3 + 7√3?


15√9


15√6


15√3


56√3






Which of the following is the solution to √15 * √45 simplified?


√675


8√3


15√15


15√3







Which of the following is the solution to 15√10 - 3√10?


12√10


5√10


12√100


45√10

Answers

Answer:

Q1: Third Choice. 15√3

Q2: Fourth Choice. 15√3

Q3: First Choice. 12√10

Step-by-step explanation:

Question 1: Which of the following is the solution to 8√3 + 7√3?

Given expression

8√3 + 7√3

Simplify by addition

Remember that terms with the same radical part can add together directly

= (8 + 7) √3

[tex]\Large\boxed{=15\sqrt{3} }[/tex]

Question 2: Which of the following is the solution to √15 * √45 simplified?

Given expression

√15 × √45

Factorize each radical

= √(3 × 5) × √(9 × 5)

= √3 × √5 × √9 × √5

Simplify necessary radicals

= √3 × √5 × 3 × √5

= 3 × √3 × √5 × √5

Simplify by multiplication

When radicals multiply, combine them under one radical sign

= 3√3 × √(5 × 5)

= 3√3 × 5

[tex]\Large\boxed{=15\sqrt{3} }[/tex]

Questions 3: Which of the following is the solution to 15√10 - 3√10?

Given expression

15√10 - 3√10

Simplify by subtraction

Remember that terms with the same radical part can subtract each other directly

= (15 - 3) √10

[tex]\Large\boxed{=12\sqrt{10} }[/tex]

Hope this helps!! :)

Please let me know if you have any questions

ASAP help me with this question

Answers

Answer:

SAS and SSA

Kindly award branliest

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

Congruency refers to the criteria of making two identical shapes that can hide each other properly when overlapped.

The criterias that guarantee congruence are :

SSS

SAS

ASA

AAS

[tex] \qquad \large \sf {Conclusion} : [/tex]

Correct options are : b, c, d, e

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