Answer: The point of intersection of angle bisectors of the 3 angles of triangle ABC is the incenter . The incircle touches each side of the triangle
I need help
Please help ASAP
Answer:
The volume of the solid is [tex]1,021m^3[/tex]
Step-by-step explanation:
1. Cylinder
For find the volume of a cylinder we use the next formula:
[tex]V_{cylinder} = \pi h r^2 = \pi \cdot 9m\cdot (5m)^2 \approx 706.86m^3[/tex]
Then the volume of the cylinder is equal to [tex]706.86m^3[/tex]
2. Cones
For find the volume of a cone we use the next formula:
[tex]V_{cone} = \pi \frac{h}{3} r^2 = \pi \cdot \frac{6m}{3} \cdot (5m)^2 \approx 157.08m^3[/tex]
However there are two cones so we have to multiply the volume of one cone for two and we get the total volume for the cones which is [tex]314.16m^3[/tex]
3. Sum of the volumes
Finally we sum the volumes of the cylinder and the cones for get the final result
[tex]V_{cylinder} + V_{cones} = 706.86m^3 + 314.16m^3 \approx 1021m^3[/tex]
So approximating the result is [tex]1021m^3[/tex]
△ABC has vertices A(-2, 0), B(0,8), and C(4,2) Find the equations of the three altitudes of △ABC
The equations of the three altitudes of triangle ABC include the following:
3y - 2y - 4 = 0.y + 3x - 8 = 0.4y + x - 6 = 0.What is a triangle?A triangle can be defined as a two-dimensional geometric shape that comprises three (3) sides, three (3) vertices and three (3) angles only.
What is a slope?A slope is also referred to as gradient and it's typically used to describe both the ratio, direction and steepness of the function of a straight line.
How to determine a slope?Mathematically, the slope of a straight line can be calculated by using this formula;
[tex]Slope, m = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope, m = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}[/tex]
Also, the point-slope form of a straight line is given by this equation:
y - y₁ = m(x - x₁)
Assuming the following parameters for triangle ABC:
Let AM be the altitudes on BC.Let BN be the altitudes on CA.Let CL be the altitudes on AB.For the equation of altitude AM, we have:
Slope of BC = (2 - 8)/(4 - 0)
Slope of BC = -6/4
Slope of BC = -3/2
Slope of AM = -1/slope of BC
Slope of AM = -1/(-3/2)
Slope of AM = 2/3.
The equation of altitude AM is given by:
y - y₁ = m(x - x₁)
y - 0 = 2/3(x - (-2))
3y = 2(x + 2)
3y = 2x + 4
3y - 2y - 4 = 0.
For the equation of altitude BN, we have:
Slope of CA = (2 - 0)/(4 - (-2))
Slope of CA = 2/6
Slope of CA = 1/3
Slope of BN = -1/slope of CA
Slope of BN = -1/(1/3)
Slope of BN = -3.
The equation of altitude BN is given by:
y - y₁ = m(x - x₁)
y - 8 = -3(x - 0)
y - 8 = -3x
y + 3x - 8 = 0.
For the equation of altitude CL, we have:
Slope of AB = (8 - 0)/(0 - (-2))
Slope of AB = 8/2
Slope of AB = 4
Slope of CL = -1/slope of AB
Slope of CL = -1/4
The equation of altitude CL is given by:
y - y₁ = m(x - x₁)
y - 2 = -1/4(x - 4)
4y - 2= -(x - 4)
4y - 2= -x + 4
4y + x - 2 - 4 = 0.
4y + x - 6 = 0.
In conclusion, we can infer and logically deduce that the equations of the three altitudes of triangle ABC include the following:
3y - 2y - 4 = 0.y + 3x - 8 = 0.4y + x - 6 = 0.Read more on point-slope form here: brainly.com/question/24907633
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A new baby grew 3/4 of an inch in June and 7/16? 4- in July. How many total inches did the baby grow during these two months?
Answer:
The baby grew 1 3/16 inches
Step-by-step explanation:
A new baby grew:
3/4 of an inch in June,7/16 of an inch in July.Total inches during two months:
3/4 + 7/16 = Fractions with different denominators3*4/(4*4) + 7/16 = Multiply the first fraction by 4 12/16 + 7/16 = Add numerators19/16 = Numerator is greater than denominator(16 + 3)/16 = Convert to mixed fraction16/16 + 3/16 = 1 + 3/16 = 1 3/16 AnswerWhat percent of 50 is 15?
A. 0.3%
B. 7.5%
C. 30%
D. 35%
Answer:30%
Step-by-step explanation:
10% of 50 is 50/10 so 10% is 5
15/5=3 so its three lots of 10%
3*10%=30%
Distance between two points
What is the length of the line?
Answer: B
Step-by-step explanation:
The horizontal change is 6.
The vertical change is 5.
So, the distance is [tex]\sqrt{6^2 + 5^2}=\sqrt{61}[/tex]
1.
Berkley is flying a kite. The string is all the way out, which means it is 425 meters away. Berkley is looking up at the kite at an angle of 42°. Berkley's dog is watching the kite too and the angle from Berkley to the dog to the kite is 87°. How would you find the distance between the kite and the dog? Is it possible? Explain your answer using the law of sines.
Using the law of sines, it is found that the distance between the kite and the dog is of 284.77 meters.
What is the law of sines?Suppose we have a triangle in which:
The length of the side opposite to angle A is a.The length of the side opposite to angle B is b.The length of the side opposite to angle C is c.The lengths and the sine of the angles are related as follows:
[tex]\frac{\sin{A}}{a} = \frac{\sin{B}}{b} = \frac{\sin{C}}{c}[/tex]
For the situation described, we have that:
The height is opposite to the angle of 42º.The 425 meters are opposite to the angle of 87º.Hence:
[tex]\frac{\sin{42^\circ}}{h} = \frac{\sin{87^\circ}}{425}[/tex]
Applying cross multiplication:
[tex]h = 425\frac{\sin{42^\circ}}{\sin{87^\circ}}[/tex]
h = 284.77 meters.
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Donna has a $300 loan through the bank she is charged a simple rate The total interest she paid on the loan was $63 As a percentage what was the annual interest rate on her loan
The annual interest rate is 21%
How to determine the annual interest rate?The given parameters are
Loan Amount, P = $300
Interest, I = $63
Number of years, T = 1
The annual interest rate is calculated as
I = PRT
Substitute the known values in the above equation
63 = 300 * R * 1
Evaluate the product
300R = 63
Divide through by 300
R = 21%
Hence, the annual interest rate is 21%
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In how many possible ways can this be accomplished if there are 25 members on the board of directors
Explanation:
There are 25 choices for president. Then we have 25-1 = 24 choices for the secretary, and 24-1 = 23 choices for treasurer. This countdown (25,24,23) is because any given person cannot serve in more than one position.
Multiply out those values: 25*24*23 = 13800
Side note: you could use the nPr permutation formula as an alternative path. Plug in n = 25 and r = 3.
Find f. f ″(x) = x^−2, x > 0, f(1) = 0, f(6) = 0
If you do in fact mean [tex]f(1)=f(6)=0[/tex] (as opposed to one of these being the derivative of [tex]f[/tex] at some point), then integrating twice gives
[tex]f''(x) = -\dfrac1{x^2}[/tex]
[tex]f'(x) = \displaystyle -\int \frac{dx}{x^2} = \frac1x + C_1[/tex]
[tex]f(x) = \displaystyle \int \left(\frac1x + C_1\right) \, dx = \ln|x| + C_1x + C_2[/tex]
From the initial conditions, we find
[tex]f(1) = \ln|1| + C_1 + C_2 = 0 \implies C_1 + C_2 = 0[/tex]
[tex]f(6) = \ln|6| + 6C_1 + C_2 = 0 \implies 6C_1 + C_2 = -\ln(6)[/tex]
Eliminating [tex]C_2[/tex], we get
[tex](C_1 + C_2) - (6C_1 + C_2) = 0 - (-\ln(6))[/tex]
[tex]-5C_1 = \ln(6)[/tex]
[tex]C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)[/tex]
Then
[tex]\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}[/tex]
Juan bought a table on sale for $459. This price was 32% less than the original price. What was the original price?
Answer:
675
Step-by-step explanation:
100%-32%=68%
459/0.68= 675
Hope this helps! :)
what is the length of the interval of solutions to the inequality 1≤3-4x≤9?
Answer: -3 ≤ x ≤ -1
Step-by-step explanation:
1 ≤ 3 - 4x ≤ 9
1 + 3 ≤ - 4x ≤ 9 + 3; Add 3 on all sides
4 ≤ -4x ≤ 12
1 ≤ -x ≤ 3; Divide 4 on all sides
-1 ≥ x ≥ -3; Multiply -1 on all sides(FYI: When multiplying or dividing negative numbers in inequalities, make sure to reverse the signs as well)
Answer:
2
Step-by-step explanation:
1≤3-4x≤9
subtract 3
1-3≤3-4x-3≤9-3
-2≤-4x≤6
divide by 2
-1≤-2x≤3
multiply by -1
1≥2x≥-3
or
-3≤2x≤1
divide by 2
[tex]-\frac{3}{2} \leq \frac{2x}{2} \leq \frac{1}{2} \\-\frac{3}{2} \leq x\leq \frac{1}{2} \\[/tex]
length of interval
[tex]=\frac{1}{2} -(\frac{-3}{2} )\\=\frac{1}{2} +\frac{3}{2} \\=\frac{1+3}{2} \\=\frac{4}{2} \\=2[/tex]
giving brainliest!!!!!!!!!!!!!!!!!!!!!!!!!
Answer: [tex]\pm1,\pm3,\pm5, \pm15[/tex]
Step-by-step explanation:
We can list the possible rational roots of this polynomial using the Rational Root Theorem. This theorem states that all the possible rational roots of an equation follow the structure [tex]\frac{p}{q}[/tex], where p is any of the factors of the constant term and q is any of the factors of the leading coefficient.
In this example, -15 is the constant term and 1 is the leading coefficient ([tex]x^4[/tex] has a coefficient of 1).
The factors of -15 are [tex]\pm1,\pm3,\pm5, \pm15[/tex], while the factors of 1 are [tex]\pm1[/tex]. p is can be any one of the factors of -15, while q can be any of the factors of 1.
[tex]\frac{\pm1,\pm3,\pm5, \pm15}{\pm1}[/tex]
The possible roots can be any of the numbers on the top divided by any of the numbers on the bottom. Since dividing by 1 or -1 won't change any of the numbers on the top, the rational roots of this function are [tex]\pm1,\pm3,\pm5, \pm15[/tex].
Buns,cost 40p each. Cakes cost 55p each. I spend exactly £4.35 on buns and cakes.
How many of each did I buy?
Someone pls help me, I’m so stuck lol
By solving a linear equation, we conclude that you bought 4 buns and 5 cakes.
How many of each did I buy?
We will define the two variables:
x = number of buns bought.y = number of cakes bought.We know that you spent exactly £4.35, then we only need to solve the linear equation:
x*0.40 + y*0.55 = 4.35
We need to solve that equation for x and y, such that the values of x and y can only be positive whole numbers.
We can rewrite the equation as:
y*0.55 = 4.35 - x*0.40
y = (4.35 - x*0.40)/0.55
Now we only need to evaluate it in different values of x, and see for which value of x, the outcome y is also a whole number.
We will see that for x = 4, we have:
y = (4.35 - 4*0.40)/0.55 = 5
So you bought 4 buns and 5 cakes.
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40p + 55p = 95p
435p ÷ 95p = 4.57...
So, the sum of the two pairs can go into £4.35 four times.
That meant if I increase the buns & cakes four times, it will help me get closer to the sum of £4.35 & work out which was extra
(40 x 4 = 160) & (55 x 4 = 220)
160 + 220= 380p or £3.80
Adding them up I get 380 pence & that's 55p short to getting to the sum of 435p or £4.35
(435-380=55p)
Thus, the extra is the cake, meaning you bought 4 buns and 5 cakes.
Hope this helps!
(06.04 MC)
If [tex]\int\limits^3_ {-2} \, [2f(x)+2]dx=18[/tex] and [tex]\int\limits^1_ {-2} \, f(x)dx =8[/tex], then [tex]\int\limits^3_ {1} \, f(x)dx[/tex] is equal to which of the following?
4
0
−2
−4
[tex]\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}[/tex]
◉ [tex]\large\bm{ -4}[/tex]
[tex]\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}[/tex]
Before performing any calculation it's good to recall a few properties of integrals:
[tex]\small\longrightarrow \sf{\int_{a}^b(nf(x) + m)dx = n \int^b _{a}f(x)dx + \int_{a}^bmdx}[/tex]
[tex]\small\sf{\longrightarrow If \: a \angle c \angle b \Longrightarrow \int^{b} _a f(x)dx= \int^c _a f(x)dx+ \int^{b} _c f(x)dx }[/tex]
So we apply the first property in the first expression given by the question:
[tex]\small \sf{\longrightarrow\int ^3_{-2} [2f(x) +2]dx= 2 \int ^3 _{-2} f(x) dx+ \int f^3 _{2} 2dx=18}[/tex]
And we solve the second integral:
[tex]\small\sf{\longrightarrow2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 2 \int ^3_{-2} f(x)dx + 2 \cdot(3 - ( - 2)) }[/tex]
[tex]\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} 2dx = 2 \int ^3_{-2} f(x)dx + 2 \cdot5 = 2 \int^3_{-2} f(x)dx10 = }[/tex]
Then we take the last equation and we subtract 10 from both sides:
[tex]\sf{{\longrightarrow 2 \int ^3_{-2} f(x)dx} + 10 - 10 = 18 - 10}[/tex]
[tex]\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx = 8}[/tex]
And we divide both sides by 2:
[tex]\small\longrightarrow \sf{\dfrac{2 { \int}^{3} _{2} }{2} = \dfrac{8}{2} }[/tex]
[tex]\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx=4}[/tex]
Then we apply the second property to this integral:
[tex]\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 4}[/tex]
Then we use the other equality in the question and we get:
[tex]\small\sf{\longrightarrow 2 \int ^3_{-2} f(x)dx = 2 \int ^3_{-2} f(x)dx = 8 + 2 \int ^3_{-2} f(x)dx = 4}[/tex]
[tex]\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =4}[/tex]
We substract 8 from both sides:
[tex]\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx -8=4}[/tex]
• [tex]\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =-4}[/tex]
What is the value of 2 + (- 2/3)^2 ÷ 1/3 ?
16
3
-2
0
Answer:
3
Step-by-step explanation:
2+ (-2/3)^2 ÷ 1/3
make -2/3 postive because its being raised by an even exponent
you never divide by fractors so make 1/3 into 3 and make it multiplication
2+ (2/3)^2 × 3
raise the fraction to the power of 2
2+ (4/9)× 3
cancel out the GCF
2+ 4/3
add
10/3
simplify
3.3 ≅ 3
For the rhombus, what are the slopes of the two diagonals? DO NOT introduce any new variables.
The slopes of the two diagonals of the rhombus are: A. b - f/a - e and -a + e/b - f.
What is the Slope of a Line Segment?To find the slope, the formula used is: change in y/change in x.
If two lines are perpendicular to each other, their slope values will be negative reciprocals.
What is the Diagonals of a Rhombus?In a rhombus, the two diagonals in the rhombus bisects each other at angle 90 degrees. This means that the two diagonals of a rhombus are perpendicular to each other. Therefore, the slope of the diagonals of any rhombus would be negative reciprocals.
The slope of the diagonals of the rhombus given would therefore be negative reciprocals to each other.
Given two endpoints of one of the diagonals as:
(a, b) = (x1, y1)
(e, f) = (x2, y2)
Slope (m) = change in y / change in x = b - f/a - e
The negative reciprocal of b - f/a - e is -a + e/b - f.
Therefore, the slopes of the two diagonals are: A. b - f/a - e and -a + e/b - f.
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a tree 20 feet tall with a circumference of 3 ft has a vine wound around 7 times. How long is the vine?
The length of the vine is 21 ft
what is the circumference of a circle?
the circumference is the perimeter of a circle
the perimeter of the circle = 2πr = 3 ft
the vine is 7 times the perimeter
length of vine = 7×3= 21 ft
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If the tree is 20 feet tall with circumference 3 feet then the length of vince is around 21 feet.
Given the height of tree is 20 feet and the circumference of tree is 3 feet.
We have to find the length of vine.
Circumference is the perimeter of a circular object. Because the trunk of a tree is in shape of circle so the perimeter of the trunk is 2πr.
We have been given the circumference of tree be 3 feet.
Circumference=2πr
Because vine is 7 times the circumference so the length of vine being:
Length of vine=7*3
=21 feet.
Hence if the tree is 20 feet tall with circumference 3 feet then the vince is around 21 feet long.
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Which equation has no solution?
4(x + 3) + 2x = 6(x + 2)
5 + 2(3 + 2x) = x + 3(x + 1)
5(x + 3) + x = 4(x + 3) + 3
4 + 6(2 + x) = 2(3x + 8)
Answer:
equation 1 has no solution
Step-by-step explanation:
when you compare each of the equations, all the equations gives a correct answer with the exception of equation 1
. Which of the following statements is not true?
a. If x = 1, then x² = 1.
b. If x²= 1, then x = 1.
c. If x=-1, then x² = 1.
d. x² = 1.if and only if x = 1 or x = -1.
Answer:
If x^2 = 1, then x = 1 is NOT true because x can also be -1.
Newton's Law of Cooling states that the rate of change of the temperature of an object, T, is proportional to the difference of T and the temperature of the region, TR or dT over dt equals k times the quantity T minus T sub R end quantity. An object with core temperature of 1200°F is removed from a fire and placed in a region with a constant temperature of 80°F. After 1 hour, its core temperature is 830°F. What is the object's core temperature 4 hours after it is taken off the fire? (1 point)
Answer:
305 °F
Step-by-step explanation:
The core temperature of the object after 4 hours can be found using an exponential decay formula to model the decay of the difference between core temperature and ambient.
Cooling ModelThe solution to the differential equation described by Newton's law of cooling is the exponential equation ...
y = ab^t +c
where 'a' is the initial core temperature difference from ambient, 'b' is the decay factor of that difference in 1 unit of time period t. 'c' is the ambient temperature.
For this problem, the ambient temperature is c=80, and the differences of interest are ...
a = 1200 -80 = 1120
b = (830 -80)/1120 = 75/112
Using these values in the model gives ...
y = 1120(75/112)^t +80 . . . . . . where y(t) is the core temperature at time t
Note that units of time are hours.
ApplicationWe want y when t=4.
y = 1120(75/112)^4 +80 ≈ 1120(0.20108) +80 ≈ 305.212
The core temperature after 4 hours is about 305 °F.
__
Additional comment
The differential equation will have a solution of the form ...
[tex]T-T_R=(T_0-T_R)e^{kt}[/tex]
where k = ln(75/112) ≈ -0.40101
In the above, we defined b = e^k = 75/112. Accuracy with this fraction can be better than using a truncated value of k.
urgently need help please help
Answer: 40
Step-by-step explanation:
Sub x=4 into 3x²-2x+1
∴ 3(4)²-2(4)+1
=3(16)-8+1
=48-8+1
=40
Answer:
41
Step-by-step explanation:
substitute the x to 4
so 3(4)² - 2(4) + 1 = 41
An older person is 9 years older than four times the age of a younger person the sum of their ages is 24 find their ages
Step-by-step explanation:
let the younger person be x and older be y
4x + 9 = 24
4x = 15
x = 3.75
y = 24 - 3.75
y = 20.25
(x+ 3/8 ) 2 + y 2 =1
what is the radius & units?
The radius of the circle of the circle equation (x + 3/8)^2 + y^2 = 1 is 1 unit
How to determine the radius of the circle?The circle equation of the graph is given as:
(x + 3/8)^2 + y^2 = 1
The general equation of a circle is represented using the following formula
(x - a)^2 + (y - b)^2 = r^2
Where the center of the circle is represented by the vertex (a, b) and the radius of the circle is represented by r
By comparing the equations (x - a)^2 + (y - b)^2 = r^2 and (x + 3/8)^2 + y^2 = 1, we have the following comparison
(x - a)^2 = (x + 3/8)^2
(y - b)^2 = y^2
1 = r^2
Rewrite the last equation as follows:
r^2= 1
Take the square root of both sides of the equation
√r^2 = √1
Evaluate the square root of 1
√r^2 = 1
Evaluate the square root of r^2
r = 1
Hence, the radius of the circle of the circle equation (x + 3/8)^2 + y^2 = 1 is 1 unit
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solve the simultaneous equation 2x+y=22 =12, x + 24+2 = 18, 2x -y +22=16
The solution for the simultaneous equations 2x + y - 2z = 12, x + 2y +z =18 and 2x - y + 2z =16 are x = 7, y = 4 and z = 3
What are linear equations?Linear equations are equations that have constant average rates of change, slope or gradient
How to determine the solution to the simultaneous equations?A system of linear equations is a collection of at least two linear equations.
In this case, the system of equations is given as
2x + y - 2z = 12,
x + 2y +z =18
2x - y + 2z =16
Eliminate y and z in the equations by adding the first and the third equation together
This gives
2x + y - 2z = 12,
+
2x - y + 2z =16
--------------------------
4x = 28
Divide both sides by 4
x = 7
Substitute x = 7 in x + 2y +z =18 and 2x - y + 2z =16
7 + 2y +z =18
2(7) - y + 2z =16
This gives
2y + z = 11
-y + 2z= 2
Multiply -y + 2z= 2 by 2
-2y + 4z= 4
Add -2y + 4z= 4 and 2y + z = 11
5z = 15
Divide by 5
z = 3
Substitute z = 3 in -y + 2z= 2
-y + 2*3= 2
Evaluate
y = 4
Hence, the solution for the simultaneous equations 2x + y - 2z = 12, x + 2y +z =18 and 2x - y + 2z =16 are x = 7, y = 4 and z = 3
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Anthony travels from Newcastle to Manchester at an average speed of 65 miles per hour.
The journey takes him 2 hours and 15 minutes.
Declan makes the same journey in 2 hours and 35 minutes.
(a) Work out Declan's average speed for the journey.
Answer:
See below
Step-by-step explanation:
Distance = rate * time
= 65 m/hr * 2 1/4 hr = 146.25 miles
rate = distance / time
for Declan : rate = 146.25 miles / (2 hrs + 35/60 min) = 56.61 mph
What is the difference? \frac{x+5}{x+2}-\frac{x+1}{x^{2}+2x}
Answer:
Step-by-step explanation:
x² + 2x = x(x + 2)
[tex]\sf \dfrac{x +5}{x + 2}-\dfrac{x+1}{x^2+2x}=\dfrac{x + 5}{x +2}-\dfrac{x+1}{x(x+2)}[/tex]
LCM = x(x+2)
[tex]\sf =\dfrac{(x+5)*x}{(x+2)*x}-\dfrac{x+1}{x(x+2)}\\\\=\dfrac{x*x + 5*x}{x^2+2x}-\dfrac{x+1}{x^2+2x}\\\\=\dfrac{x^2+5x - (x+1)}{x^2+2}\\\\=\dfrac{x^2+5x -x - 1}{x^2+2x)}\\\\=\dfrac{x^2+4x-1}{x^2+2x}[/tex]
Write 2.154 × 10∧5 in decimal form.
The decimal notation for the given value in scientific notation is 215400.
How to convert from scientific to decimal notation?Very large or very small numbers are denoted in scientific notation to simplify complex calculations.
The scientific notation is represented by: a × 10ⁿ
Wher a - any number or decimal number
n - the power of 10; it is an integer number
To convert this into decimal notation,
If the value of n is positive, then the decimal point in the 'a' moves right. (OR)If the value of n is negative, then the decimal point in the 'a' moves left.Calculation:The given number is in the scientific notation,
2.154 × 10⁵
Since the power of 10 is positive, the decimal point in the number 2.154 moves towards the right. I.e,
2.154 × 10⁵ = 215400
Here power is 5. So, the decimal point moved five places to the right.
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Help I can’t figure out anything with this question
Answer: Look in step-by-step explanation
Step-by-step explanation:
Area has a unit of cm^2 or m^2, whilst Volume has a unit of cm^3 or m^3
Using this information, we can see that we have to square both sides of the similarity ratio for the area ratio and cube both sides of the similarity ratio for the volume ratio
For example, question 2 states that the similarity ratio is 3:6, so the area ratio is 3^2:6^2 or 9:36 and the volume ratio is 3^3:6^3 = 27:216
You can do the rest from here
Determine the domain:
[tex]f(x) = \frac{ln(ln(x + 1))}{e {}^{x} - 9 } [/tex]
The denominator cannot be zero, so
[tex]e^x - 9 = 0 \implies e^x = 9 \implies x = \ln(9)[/tex]
is not in the domain of [tex]f(x)[/tex].
[tex]\ln(x)[/tex] is defined only for [tex]x>0[/tex], and we have
[tex]\ln(x+1) > 0 \implies e^{\ln(x+1)} > e^0 \implies x+1 > 1 \implies x>0[/tex]
so there is no issue here.
By the same token, we need to have
[tex]x+1 > 0 \implies x > -1[/tex]
Taking all the exclusions together, we find the domain of [tex]f(x)[/tex] is the set
[tex]\left\{ x \in \Bbb R \mid x > 0 \text{ and } x \neq \ln(9)\right\}[/tex]
or equivalently, the interval [tex](0,\ln(9))\cup(\ln(9),\infty)[/tex].
A right pyramid has a height of 3 inches and a square base with side length of 5 inches. What is the volume of the pyramid?
The volume of this pyramid is ______
cubic inches.
PLEASE MY LAST QUESTION
Answer: 25 in³
Step-by-step explanation:
We can calculate the volume of the pyramid by first calculating the volume of a prism with the same dimensions, and then dividing by 3 (all pyramids a volume that's [tex]\frac{1}{3}[/tex] of the volume of a prism with the same dimensions).
The volume of a prism is its base area times its height. The base would be a square, so its area is 5², which is 25. The height is 3 inches, making the prism's volume 75 in³.
The volume of the pyramid would be one-third of this value, which is 75[tex]75\div3[/tex] which is 25 in³.