The angle between the hydrogen atoms in water (h2o) is slightly less than expected for a tetrahedral shape. this is because of the:_______.

Answers

Answer 1

The angle between the hydrogen atoms in water (h2o) is slightly less than expected for a tetrahedral shape. this is because of the extra electron repulsion from the lone pairs.

A water molecule consists of two hydrogen atoms and one oxygen atom. The three atoms make an angle; the H-O-H angle is approximately 104.5 degrees. The centre of each hydrogen atom is approximately 0.0957 nm from the centre of the oxygen atom.

In water, each hydrogen nucleus is covalently bound to the central oxygen atom by a pair of electrons that are shared between them. In H2O, only two of the six outer-shell electrons of oxygen are used for this purpose, leaving four electrons which are organized into two non-bonding pairs. The four electron pairs surrounding the oxygen tend to arrange themselves as far from each other as possible in order to minimize repulsions between these clouds of negative charge. This would ordinarily result in a tetrahedral geometry in which the angle between electron pairs (and therefore the H-O-H bond angle) is 109.5°. However, because the two non-bonding pairs remain closer to the oxygen atom, these exert a stronger repulsion against the two covalent bonding pairs, effectively pushing the two hydrogen atoms closer together. The result is a distorted tetrahedral arrangement in which the H—O—H angle is 104.5°.

About tetrahedral shape :

In geometry, a tetrahedron (plural: tetrahedra or tetrahedrons), also known as a triangular pyramid, is a polyhedron composed of four triangular faces, six straight edges, and four vertex corners. The tetrahedron is the simplest of all the ordinary convex polyhedra and the only one that has fewer than 5 faces.

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Related Questions

A full 15.0 L scuba tank at 295 K contains 144 moles of air and has a pressure of 234 atm. At the end of the dive, the tank has a pressure of 68.0 atm and a temperature of 280 K. How many moles of air are left in the tank?"

Answers

Answer:

44.1 L

Explanation:

Since volume is being held constant, we can use the following variation of the Ideal Gas Law to find the new pressure.

[tex]\frac{P_1}{T_1N_1}=\frac{P_2}{T_2N_2}[/tex]

In the equation, "P₁", "T₁", and "N₁" represent the initial pressure, temperature, and moles. "P₂", "T₂", and "N₂" represent the final pressure, temperature, and moles. Your answer should have 3 sig figs to match the sig figs of the given values.

P₁ = 234 atm                                 P₂ = 68.0 atm

T₁ = 295 K                                     T₂ = 280 K

N₁ = 144 moles                              N₂ = ? moles

[tex]\frac{P_1}{T_1N_1}=\frac{P_2}{T_2N_2}[/tex]                                              <----- Equation

[tex]\frac{234 atm}{(295 K)(144 moles)}=\frac{68.0 atm}{(280 K)N_2}[/tex]                        <----- Insert values

[tex]\frac{234 atm}{42480}=\frac{68.0 atm}{(280 K)N_2}[/tex]                                      <----- Multiply 295 and 144

[tex]0.00551=\frac{68.0 atm}{(280 K)N_2}[/tex]                                    <----- Simplify left side

[tex]1.54=\frac{68.0 atm}{N_2}[/tex]                                            <----- Multiply both sides by 280

[tex](1.54)N_2={68.0 atm}[/tex]                                   <----- Multiply both sides by N₂

[tex]N_2 = 44.1L[/tex]                                                <----- Divide both sides by 1.54

There will be approximately 49.7 moles of air in the tank at the end of the dive.

The Ideal Gas Law, which asserts the following, can be used to solve this problem:

PV = nRT

Where:

P = pressure

V = volume

n = moles of gas

R = ideal gas constant

T = temperature

Let us first use the given data to obtain the initial amount of moles of air in the tank:

[tex]P_1[/tex]= 234 atm

V = 15.0 L

[tex]T_1[/tex] = 295 K, and

R = 0.0821 L/(Kmol) atm.

Using the ideal gas law equation, we can solve for [tex]n_1[/tex]:

[tex]n_1 = (P_1 * V) / (R * T_1)[/tex]

= (234 atm * 15.0 L) / (0.0821 L·atm/(K·mol) * 295 K)

≈ 189.6 moles

Using the new pressure and temperature, we can determine the exact amount of air in the tank:

P2=68.0 atm and T2=280 K

We can determine [tex]n_2[/tex] by applying the same formula:

[tex]n_2 = (P_2 * V) / (R * T_2)[/tex]

= (68.0 atm * 15.0 L) / (0.0821 L·atm/(K·mol) * 280 K)

≈ 49.7 moles

As a result, there will be approximately 49.7 moles of air in the tank at the end of the dive.

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______________ occurs when water between the tires and the road builds until the tires begin to ride on a film of water, resulting in traction loss.

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Hydroplaning occurs when water between the tires and the road builds until the tires begin to ride on a film of water, resulting in traction loss.

The motor vehicles or aircraft tires passing over wet pavement may lose contact with sufficient speed or water depth for a particular given tread design. The tires lose the braking friction required for stopping and start to hydroplane or aquaplane when they come into contact with water. Wet road surfaces can cause tires to hydroplane . This could result in loss of control and steering ability.

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Explain the impact that changing the temperature has on a system in a state of dynamic equilibrium. what will happen when the temperature of an exothermic reaction mixture at equilibrium is increased?

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An endothermic reaction is favored by raising the temperature of a system in dynamic equilibrium. The mechanism absorbs the increased heat to offset the alteration you made. An exothermic reaction is favored by a system's temperature falling while it is in dynamic equilibrium.

Which of these reactions is endothermic?

Any chemical process that takes heat from its surroundings is said to be endothermic. The reaction's activation energy comes from the energy that was absorbed. This kind of reaction is characterized by its icy sensation.

How does an exothermic reaction work?

An exothermic reaction is one in which energy is given off as heat or light. In contrast to an endothermic process, which draws energy from its surroundings, an exothermic reaction transfers energy into the environment.

What kind of reaction is an exothermic reaction?

Materials like hydrocarbons reacting with oxygen to produce combustion products like water and carbon dioxide is an example of an exothermic process.

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what is the importance of metal reactivity series​

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Answer:

The reactivity series allows us to predict correctly how metals will react. Another importance is that so we can use displacement. We can spot a more reactive metal allowing us to displace a less reactive metal from a compound or an equation.

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Importance of Metal Reactivity Series are:

Metal Reactivity Series are used in Displacement reaction.It is used in the reaction between water and metals.In the reaction between metals and acids.

What are metal reactivity series?

Metal reactivity series is a chart of listing the metals in the order of decreasing reactivity.

As in Displacement reaction less reactive metal is displaced by more reactive metal. By metal reactivity series we came to know which metal is displaced by another metal.When the metals from Potassium and Calcium react with cold water             it will release Hydrogen gas.

See the below reaction:

K(s)        +            [tex]H_2O[/tex]   →           KOH(aq)              +                  1/2 [tex]H_2[/tex] (g)

Potassium      water              Potassium Hydroxide                Hydrogen

Metals like Lead and others which are more reactive than Lead can react with HCl and [tex]H_2SO_4[/tex] to form salts. We can predict the reaction by reactivity series.

Lets see the reaction between Lead with Hydrochloric acid and Sulphuric acid.

Pb (s)      + 2HCl (aq)           →              [tex]PbCl_2[/tex] (aq)           +       [tex]H_2[/tex] (g)

Lead        Hydrochloric acid          Lead chloride                  Hydrogen

Pb (s)      +   [tex]2H_2SO_4[/tex]             →     [tex]PbSO_4[/tex]              +   [tex]SO_2[/tex]                   +   [tex]H_2O[/tex]

Lead         Sulphuric acid            Lead Sulphate      Sulphur dioxide    water

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The conductivity of the solution in a reaction can be used to measure rates of reactions involving?

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The conductivity of the solution in a reaction can be used to measure rates of reactions involving aqueous electrolytes. The correct option is D.

What is conductivity?

Conductivity is a property that tells if a material can pass heat and light through it. Conductor are hose material that pass the heat and plight through it. Those material that do not transfer the heat are called non-conductor.

The conductivity of a solution in a reaction. To measure the change in the rates of a solution that involve the aqueous electrolyte, the conductivity of the solution is measured.

Thus, the correct option is D. aqueous electrolytes.

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The question is incomplete. Your complete question is given below:

These are the options:

Gaseous substances

brightly colored substances

organic compounds

aqueous electrolytes

A mixture of three gases, A, B and C, is at a total pressure of 6.11 atm. The partial
pressure of gas A is 1.68 atm; that of gas B; is 3.89 atm. What is the partial pressure
of gas C?
2.13 atm
2.21 atm
5.57 atm
0.54 atm

Answers

The partial pressure of gas C is 0.54atm. The correct option is D.

What is partial pressure?

The pressure that one of the gases in a mixture would exert if it were in the same volume on its own.

The total pressure of A, B and C is 6.11 atm.

The partial pressure of A is 1.68 atm

The partial pressure of B is 3.89 atm.

Total pressure = sum of partial pressures of all the gasses in that mixture

6.11atm = 1.68atm + 3.89atm + Pc

Pc = 6.11atm - (1.68 + 3.89) = 0.54atm

Thus, the partial pressure of C is 0.54atm. The correct option is D.

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True or
False
Consider the equilibrium c(s) h2o(g) co(g) h2(g), δh = 2296 j. The concentration of carbon will not change if gaseous water is added to the system

Answers

The statement that the concentration of carbon will not change if gaseous water is added to the system is false. The concentration of carbon will increase.

What is concentration?

Concentration of a substance is the present of a substance in a per-unit square of an area. It is the total amount of solute present in the solution.

The equilibrium is C(s) + H₂O(g) < - > CO(g) + H₂(g), ΔH = 2296 J.

If we increase or add the gaseous water in the system, the amount of carbon will increase because the carbon is a gas, and increasing the pressure will increase the volume of the gas, at Constant temperature.

Thus, the statement is false.

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If 45ml of water are added to 250ml of a 0.75 m k2so4 solution, what will the molarity of the diluted solution be

Answers

The molarity of the diluted solution is 4.16 M

Given:

volume of water = 45ml

volume of k2so4 = 250ml

Molarity of k2so4 = 0.75 M

To Find:

molarity of the diluted solution

Solution: Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution

M1V1 = M2V2

45*M1 = 250*0.75

M1 = 250*0.75/45

M1 = 4.16 M

So, Molarity of given solution is 4.16 M

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If the ph at the half-titration point of a monoprotic weak acid is 4. 2, what is the ka of the acid?.

Answers

The ka of the acid will be-

Ka=2.1106Finding the ka of the acid-The notion is that the pH of the solution will be equal to the pKa of the weak acid at the half-equivalence point.You know that at the equivalence point, the strong base will totally neutralize the weak acid if you're titrating a weak monoprotic acid, which I'll refer to as HA.

HA(aq)+OH−(aq)→A−(aq)+H2O(l)

Therefore, upon adding an equal number of moles of a weak acid and strong base, all of the weak acid's moles will be consumed, leaving you with A, the weak acid's conjugate base.At this point, you have added enough moles of the strong base to neutralize half of the weak acid molecules in the solution. This is known as the half equivalence point.The weak acid, the strong base, and the conjugate base are all in 1:1 mole ratios, indicating that what you consume from the weak acid and the strong base, you make as the conjugate base. The reaction will use half of the moles of the weak acid and produce just as many moles of the conjugate base.As a result, the solution will contain an equal number of moles of the weak acid and its conjugate base at the half equivalence point, indicating that you are now working with a buffer solution.As you are aware, the Henderson-Hasselbalch equation pH=pKa+log can be used to calculate the pH of a weak acid-conjugate base buffer ([conjugate base][weak acid])

You have the half-equivalence point when

[HA]=[A−]

it suggests that

log([HA][A−])=log(1)=0

As a result, it can be said that the pH of the solution and the pKa of the weak acid are equivalent at the half-equivalence point.

At the halfway point of equivalence: pH=pKa

The acid dissociation constant of the weak acid, Ka, determines the pKa. pKa=log(Ka), which indicates that Ka=10pKa.

Ka=10pH will be present when the two points are half equal.

Enter your value to determine Ka=105.67=2.1106.

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Enter your answer in the provided box. calculate the ph of a 0. 39 m ch3cooli solution. (ka for acetic acid = 1. 8 × 10−5. )

Answers

The pH of the solution is the negative logarithm of a proton or the hydrogen ion concentration. The pH of 0.39 M acetic acid solution (CH₃COONa) is 2.58.

What is pH?

The pH has been said to be the hydrogen ion concentration that can also be given by the pOH.

Given,

The acid dissociation constant Ka = 1.8 × 10⁻⁵

Concentration of acetic acid (C) = 0.39 M

The hydrogen ion concentration from Ka and molar concentration are calculated as:

H⁺ = √ Ka × C

= √1.8 × 10⁻⁵ × 0.39

= √0.00000702

= 0.0026

Now, pH from hydrogen ion is calculated as,

pH = - log [H⁺]

= - log [0.0026]

= 2.58

Therefore, the pH of acetic acid is 2.58.

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Calculate δs∘rxn for the reaction2no(g) o2(g)→2no2(g)express your answer to one decimal place and include the appropriate units

Answers

The δs∘rxn  for the reaction [tex]2NO(g) + O_{2}[/tex] → [tex]2NO_{2} (g)[/tex] will be -146 J/K.

Entropy would be a measurable physical characteristic and a scientific notion that is frequently connected to a condition of disorder, unpredictability, or uncertainty.

Entropy would be a measurement of the system's unpredictability or disorder. The entropy increases as randomness do. It has broad properties as well as a state function. It has the unit [tex]JK^{-1} mol^{-1}[/tex].

Entropy of the reaction can be calculated by the reaction.

Δ[tex]S^{0} rxn[/tex] = 2 mol × [tex]S^{0} (NO_{2} (g) - 2 mol[/tex] × [tex]S^{0} NO (g)[/tex] - 1 mol × [tex]S^{0} (O_{2} )[/tex]

Δ[tex]S^{0} rxn[/tex]  = 2 mol × 240 J/mol.K - 2 mol × 210 J/mol.K-1 mol  ×205.2 J/mol.K

Δ[tex]S^{0} rxn[/tex]  = -146.8 J/K

Therefore, the δs∘rxn  for the reaction [tex]2NO(g) + O_{2}[/tex] → [tex]2NO_{2} (g)[/tex] will be -146 J/K.

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What is the product of reduction of ethyl 4-oxobutanoate with sodium borohydride in ethanol at room temperature for 30 minutes?

Answers

The product of reduction of ethyl 4-oxobutanoate with sodium borohydride in ethanol at room temperature for 30 minutes is ethyl 4- hydroxybutanoate .

Sodium borohydride is a relatively selective reducing agent  Ethanolic solutions of Sodium borohydride reduces aldehyde , and ketone , in the presence of acid chloride , ester , epoxide , lactones , acids , nitriles , nitro groups.

The sodium borohydride does not reduce ester group because sodium borohydride is not strong enough and the electrophilicity at carbony carbon of ester is not more as compare toaldehyde , and ketone

The product of reduction of ethyl 4-oxobutanoate with sodium borohydride in ethanol at room temperature for 30 minutes is ethyl 4- hydroxybutanoate .

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The primary sources of the acidity in acid rain are the gases ________. o3 and vocs o3 and so2 so2 and nox nox and n2o h2so4 and no

Answers

The primary sources of acidity in acid rain are the gases SO[tex]_{2}[/tex] and NO[tex]_{x}[/tex] So, the correct option is (c) SO[tex]_{2}[/tex] and NO[tex]_{x}[/tex]

A chemical process that starts when gases like sulphur dioxide and nitrogen oxides are discharged into the atmosphere leads to acid rain. These substances have the ability to ascend very far into the sky, where they combine and react with oxygen, water, and other chemicals to produce acid rain, an additional form of acidic pollution.

Acidic particles corrode metal and hasten the deterioration of paint and stone. Power plants are the primary sources of SO[tex]_{2}[/tex] . Burning fossil fuels produces nitrogen dioxide (like gasoline). Cars, lorries, and power plants are the biggest producers of NO[tex]_{2}[/tex].

Therefore, The primary sources of the acidity in acid rain are the gases SO[tex]_{2}[/tex] and NO[tex]_{x}[/tex].So, the correct option is (c) SO[tex]_{2}[/tex] and NO[tex]_{x}[/tex]

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What term is best described as the rate of a chemical reaction at any instant in time?

Answers

Answer:

instantaneous rate would be the term.

A membrane is impermeable to charged molecules and does not allow passage of ions because of?

Answers

A membrane is impermeable to charged molecules and does not allow the passage of ions because the charged molecules possess polarity and the membrane possesses hydrophobic interiors.

Hydrophobic ions:

Charged hydrophilic molecules of all sizes, from small molecules to giant enzymes, can now be made more soluble via a technique called hydrophobic ion pairing. Hydrophobic molecules having hydrophilic moieties are ionically coupled with charged hydrophilic molecules, and the resulting uncharged complex is water-insoluble and will precipitate in aqueous conditions.

With polar solvents like water or alcohol, hydrophilic compounds can easily establish hydrogen bonds. Ionic (charged) groups with oxygen or nitrogen atoms make up the chemical structure of hydrophilic compounds. Typically, a substance's hydrophilicity is determined by its polarity. A molecule will be hydrophobic overall even if it has polar covalent bonds and these bonds are distributed symmetrically.

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If 38. 2 ml of a 0. 163 m KOH solution is required to neutralize 25. 0 ml of H2SO4 solution. Calculate the morality of the H2SO4 solution.

Answers

Answer:

.24 mol / liters

Explanation:

38. 2 ml = .0382 liters

.0382 liters times ( 0. 163 m KOH/1 liter) times ( 1 mol H2SO4/  1 mol koh) =

.006/.025 liters = .24 mol / liters

chegg

What volume of O2 is produced when 28. 5 g of hydrogen peroxide (H2O2) decomposes to form water and oxygen at 150°C and 2. 0 atm?

Answers

0.42 mol 7.3 L volume of O2 is produced when 28. 5 g of hydrogen peroxide (H2O2) decomposes to form water and oxygen at 150°C and 2. 0 atm

A moderate antiseptic used topically to treat minor burns, scrapes, and cuts is hydrogen peroxide. As a mouth rinse, it can be used to assist clear mucus or soothe minor oral irritation (caused, for example, by canker/cold sores, or gingivitis).

Stronger than chlorine, chlorine dioxide, and potassium permanganate, hydrogen peroxide is a potent oxidant.

Human blood is exposed to a hydrogen peroxide solution, which causes the peroxide to break down and release oxygen. Before transfusion, this process has been utilized to oxygenate banked blood.

When hydrogen peroxide comes into contact with skin, a chemical process takes place that causes hydrogen peroxide to turn white. When the solution oxidizes, oxygen bubbles that arise give the mixture a white, foamy appearance.

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A monosaccharide that consists of 5 carbon atoms, one of which is in a ketone group, is classified as a(n) _______

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A monosaccharide that consists of 5 carbon atoms, one of which is in a ketone group, is classified as a(n) ketopentose.

Ketone family

The suffix "-one" is added after locating the carbonyl group and, if necessary, designating it with a location number. Ketones are given their common names by first identifying the alkyl groups linked to the carbonyl (in alphabetical order), followed by the prefix "ketone." Several Regular Ketones. The three most significant ketones in terms of scale are acetone, methyl ethyl ketone, and cyclohexanone. Though less frequently than in general organic chemistry, they are still widespread in biochemistry. The simplest ketone is dimethyl ketone, or CH3COCH3, often known as acetone.

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How many milliliters of 0. 0850 m naoh are required to titrate 25. 0 ml of 0. 0720 m hbr to the equivalence point?

Answers

The final answer is 29.8 mL

Molar mass HCl = 36.5 g/mol

Mol HCl in 1.85 g = 1.85 g / 36.5 g/mol = 0.05068 mol

The molarity of the HCl solution is 0.0507 mol /L

Mol HCl in 50 mL = 50 mL / 1000 mL/L * 0.0507 mol /L = 0.002535 mol

This will require 0.002535 mol NaOH

1000 mL contains 0.0850 mol

The volume that contains 0.002535 mol

Volume = 0.002535 mol / 0.0850 mol /L *1000 mL/L = 29.8 mL

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The volume of 0.0850 M NaOH is required to titrate 25.0 ml of 0.0720 M is 21.176 ml.

What are normality and molarity?

Normality is defined as the number of equivalents per litre of the solution

It is given by

Normality = number of equivalents / 1 L of solution

Molarity is defined as the number of moles of solute present in one litre of solution

Molarity = moles of solute / 1 litre of solution

Relationship between molarity and normality

Normality = Molarity × Acidity or Basicity of a salt

Here, the Acidity Of NaOH is 1 and the basicity of HBr is also 1.

Thus, Normality = Molarity

We know, N₁V₁ = N₂V₂

We can also write it as M₁V₁ = M₂V₂

V1 = [tex]\frac{M_2V_2}{M_!}[/tex]

Substitute M₁ = 0.0850 M, M₂ = 0.0720 M, V₂= 25 ml

V1 = 21.176 ml

Hence, The volume of 0. 0850 m NaOH are required to titrate 25. 0 ml of 0. 0720 m is 21.176 ml.

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What atomic or hybrid orbitals make up the sigma bond between c2 and h in ethylene, ch2ch2?

Answers

Explanation:

According to orbital hybridization theory, in ethene the C atoms are using sp2 hybrid orbitals. This leaves one unhybridized p orbital available to form the second bond (Pi bond) in the C-C double bonds.

One sp2 hybrid orbital from each C atom overlap to form one sigma bond between the two carbon atoms. One p orbital from each C atom then overlap to form a pi bond that completes the C-C double bond. The H atoms are bonded via sigma bonds to the C atoms when the H s orbitals overlap with the remaining sp2 hybrid orbitals from each C.

Enter your answer in the provided box. calculate the ph at 25°c of a 0. 11 m solution of a weak acid that has ka = 9. 2 × 10−6. ph =

Answers

The pH at 25°c of a 0. 11 m solution of a weak acid that has ka = 9. 2 × 10−6 is 3.

What is base dissociation constant?

The base dissociation constant is termed as Kb. Throughout a base split into ts constituent ions in water is determined by its base dissociation constant.

Kb = [H+] [A-]/[HA]

Now, let the concentration of [H+] = [A-] = x

Given,

Ka = 9.2 × 10−6.

Firstly we will calculate the value of the concentration of [H+]

pKa = x^2/(0.11-x)

9.2 × 10−6 = x^2/(0.11-x)

x^2 = 1.012 × 10−6

x = 1.002 × 10^−3.

The concentration of [H+] = [A-] = 1.002 × 10^−3.

Now, we will find pH as

pH = -log[H+]

pH = -log(1.002 × 10^−3)

pH = 3

Thus we calculated that the pH of the solution is 3.

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Which pair of compounds is soluble in water?
a. lii and ca(no3)2
b. kno3 and caco3
c. hg2br2 and hg2i2
d. cus and na2s

Answers

Pair of LiI and Ca(NO3)2 is soluble in water.

Here LiI stands for lithium iodide and Ca(NO3)2 stands for Calcium Nitrate.

Water's polarity, which is the unequal sharing of electrons among its atoms, is what allows it to be such a great solvent. Typically, water is held together through this polarity of partial positive and negative charges. Positive is attracted to negative, making a cohesive structure. When polar compounds or ions are added to water, they break up into smaller components, or dissolve, to become part of the solution. The water's partial charges attract different parts of the compound, making them soluble in water.

Polar Molecules

Similar to ions, polar molecules are able to dissolve in water. Like water, polar molecules have partial positive and negative charges. The attraction between opposite partial charges helps polar molecules dissolve in water.

Water doesn't have a full positive or negative charge; instead, it possesses a partial positive and partial negative charge. This is because oxygen is a lot more electronegative than hydrogen. This means that oxygen draws more electrons to it than the hydrogen does. Since more electrons are moving towards the oxygen, it has a slightly higher negative charge than water's hydrogen atoms.

Let's look at another simple example: a carbon-fluorine bond. Since fluorine is more electronegative than carbon, it draws more electrons over to it, making it partially negative.

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A solution with a ph of 6 has ________ times as many hydrogen ions as a solution with a ph of 8.

Answers

Answer:

A solution with a ph of 6 has 100 times as many hydrogen ions as a solution with a ph of 8.

Explanation:

At 7 on the pH scale, a solution is neutral. Any pH lower than 7 is acidic and any pH above 7 is basic.

Acidity is a measure of the concentration of hydrogen ions in a solution. The more acidic a solution, the more hydrogen ions it has. Therefore, if the pH is decreasing, the hydrogen ion concentration is increasing.

The pH scale increases by a factor of 10. This means that for every one unit change, the hydrogen ion concentration changes tenfold. Therefore, if the pH is decreasing by 2 units (from pH 8 to pH 6), the hydrogen ion concentration should increase 100-fold (10 x 10 = 100).

Alkali metals nitrates on heating give the corresponding __ and oxygen.

Answers

Alkali metals nitrates on heating give the corresponding nitrogen dioxide and oxygen.

What are alkali metals?

These are the metals which forms alkali when dissolved in water. They are any of the soft, light, reactive metals of Group 1 of the periodic table.

Some examples of alkali metals are as follows:

LithiumSodiumPotassiumCesiumrubidiumfrancium

A periodic table is a tabular chart of the chemical elements according to their atomic numbers so that elements with similar properties are in the same column.

So therefore, alkali metals nitrates on heating give the corresponding nitrogen dioxide and oxygen.

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How many moles of sodium bromide can be produced from the reaction of 1. 03 moles of bromine gas with 0. 650 moles of sodium? 2 na(s) br2(g) ® 2 nabr(s)

Answers

There are 0. 650 moles of sodium bromide can be produced from the reaction of 1. 03 moles of bromine gas with 0. 650 moles of sodium .

Calculation ,

To find the number of moles of sodium bromide we have to write balanced chemical equation first .

[tex]2Na (s)+ Br_{2}(g)[/tex] → 2NaBr (s)

from the equation we can conclude that 2 moles sodium react with one mole of bromine to form 2 mole of sodium bromide .

But  1. 03 moles of bromine gas ( that is equal to the number of moles required in the equation) with 0. 650 moles of sodium ( that is half of required mole ) is given .

So, sodium is present as limiting reactant .

So , the number of sodium bromide formed is equal to the number of moles of sodium atom.

Hence ,  the number of sodium bromide formed =  0. 650 moles

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A. Would sucrase be classified as a oxidoreductase, a transferase, a lysase, an isomerase, a hydrolase, or a ligase enzyme? explain your choice. B. Could sucrase be used to break down another disaccharide, such as lactose? explain your reasoning.

Answers

Sucrose, a disaccharide (consisting of two monosaccharides), is table sugar.

A digestive enzyme called sucrase catalyses the breakdown of sucrose into its component sugars, fructose and glucose. One type, sucrase-isomaltase, is secreted at the brush boundary of the small intestine. Invertase, a form of the sucrase enzyme that is more frequently found in plants, also hydrolyzes sucrose but does it in a different way.

What does sucrase break down into ?

Maltose is converted to glucose by maltase. Succrase and lactase, respectively, break down other disaccharides like sucrose and lactose. Sucrase and lactase are enzymes that break down sucrose (also known as "table sugar") and lactose (sometimes known as "milk sugar"), respectively, into glucose and fructose.

Both the breakdown of maltose into glucose and the breakdown of sucrose into glucose and fructose are carried out by the enzyme's sucrase subunit.

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The "break-even" interest rate for year n that equates the return on an n-period zero-coupon bond to that of an n - 1 - period zero-coupon bond rolled over into a one-year bond in year n is defined as:_________

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The "break-even" interest rate for year n that equates the return on an n-period zero-coupon bond to that of an n - 1 - period zero-coupon bond rolled over into a one-year bond in year n is defined as the forward rate.

A forward rate is a specified price agreed by all parties involved for the delivery of a good at a specific date in the future. The use of forward rates can be speculative if a buyer believes the future price of a good will be greater than the current forward rate. Alternatively, sellers use forward rates to mitigate the risk that the future price of a good materially decreases.

Regardless of the prevailing spot rate at the time the forward rate meets maturity, the agreed-upon contract is executed at the forward rate. For example, on January 1st, the spot rate of a case of iceberg lettuce is $50. The restaurant and the farmer agree to the delivery of 100 cases of iceberg lettuce on July 1st at a forward rate of $55 per case. On July 1st, even if the price per case has decreased to $45/case or increased to $65/case, the contract will proceed at $55/case.

To extract the forward rate, we need the zero-coupon yield curve.

We are trying to find the future interest rate [tex]{\displaystyle r_{1,2}}{\displaystyle r_{1,2}}[/tex]  for time period  

[tex]{\displaystyle (t_{1},t_{2})}(t_1, t_2), {\displaystyle t_{1}}t_{1}[/tex]  and  [tex]{\displaystyle t_{2}}t_{2}[/tex]  expressed in years, given the rate  [tex]{\displaystyle r_{1}}r_{1}[/tex]  for

time period  [tex]{\displaystyle (0,t_{1})}(0, t_1)[/tex]  and rate [tex]{\displaystyle r_{2}}r_{2}[/tex]  for time period [tex]{\displaystyle (0,t_{2})}(0, t_2)[/tex].  To do this, we use the property that the proceeds from investing at rate  [tex]{\displaystyle r_{1}}r_{1}[/tex] for

time period [tex]{\displaystyle (0,t_{1})}(0, t_1)[/tex]  and then reinvesting those proceeds at rate

[tex]{\displaystyle r_{1,2}}{\displaystyle r_{1,2}}[/tex]  for time period  [tex]{\displaystyle (t_{1},t_{2})}(t_1, t_2)[/tex]  is equal to the proceeds from

investing at rate [tex]{\displaystyle r_{2}}r_{2}[/tex] for time period [tex]{\displaystyle (0,t_{2})}(0, t_2)[/tex].

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HELP PLS.. I’LL MARK U BRAINLIEST!

Answers

Old and inefficient mining smokestacks contaminate the soil around abandoned mine sites.

What are mines?

A mine is an area from which natural resources are extracted such as coal, metals, etc. A mine is known to be the source of many heavy metals as well as acid.

As such the statement that does not represent the impact of mining services is that; "Old and inefficient mining smokestacks contaminate the soil around abandoned mine sites".

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The delocalized cloud of π electrons in benzene is formed by the overlap of 6 ________ orbitals.
a. s
b. p
c. sp
d. sp2
e. sp3

Answers

The delocalized cloud of π electrons in benzene is formed by the overlap of 6 p-orbitals.

So, option B is correct one.

In the case of hydrocarbons, delocalisation occurs in benzene rings , where a hexagon of six carbon atoms has decalized electrons spread over the whole ring.

All of the carbon atoms in the benzene rings are [tex]sp^{2}[/tex] orbitals around the ring produces a framework of six sigma bonds, while the unhybridized p-orbitals which are perpendicular to this plane over in side-to-side fashion to form three pi-bonds.

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A container holds 265 mL of chlorine gas (Cl2). If the gas sample is at standard temperature and pressure (STP), what is its mass in grams?

Answers

The mass, in grams, of the chlorine gas will be 0.84 grams

Mass of gases at STP

At standard temperature and pressure, 22.4 L of gas has 1 mole of the gas in it.

This time, what we have is 265 mL of the gas at STP. 265 ml is equivalent to: 265/1000 = 0.265 L

If.

22.4 L = 1 mole

Then,

0.265 L = 0.265 x 1/22.4 = 0.01183 moles

This means that 0.01183 moles of chlorine is present in the gas at STP.

Mass of 0.01183 moles of chlorine = moles x molar mass.

The molar mass of chlorine gas is 71

Mass of the chlorine gas = 0.01183 x 71 = 0.84 grams

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