PQRS is a cyclic quadrilateral.Chord RS is produced to T.K is a point on RS and W is a point on the circle such that QRKW is a parallelogram. PS and QW intersect at U. PST = 136° and Q₁ =100° Determine, with reasons, the size of: 8.1.1.R 8.1.2.P 8.1.3.PQW 8.1.4.U2​

Answer:

The amount of unexplained variance in a relationship between two variables is called: coefficient of alienation also called coefficient of nondetermination. A positive correlation between two variables would be represented in a scatterplot as. line sloping upwards. .

Step-by-step explanation:

Using proportions, it is found that:

A. The vegetables weigh 66 pounds.

B. 0.5 pints are dispensed after 25 seconds.

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

4 and 1/8 pounds is equivalent to 4.125 pounds. Since each pound has 16 ounces, the weight of the vegetable is of:

W = 16 x 4.125 = 66 pounds.

Every second, 0.16 gallons are dispensed. Hence the amount dispensed in 25 seconds is:

A = 25 x 0.16 = 4 gallons.

Each gallon has 8 pints, hence the number of pints dispensed is:

4/8 = 0.5 pints.

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When a detailed scoring guide or rubric is used to score open-ended questions, the result is scored.

The scoring guide assign points to special degrees of student performance. Instructors use them when a scholar's response can earn a number of the full possible factors, commonly for built-reaction items and performance responsibilities.

Rubrics and scoring guides were implemented into cutting-edge classrooms to offer college students higher know-how of what's being assessed, what standards grades are primarily based upon, and what clean and compelling product standards are addressed.

Even as scoring guides illustrate how college students can earn a certain amount of points for precise questions and responses, rubrics assign ratings primarily based on how well a pupil's reaction meets a degree of overall performance.

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Answer:

D) 14

Step-by-step explanation:

12+12+12 is 36 we don't know hold old the fourth sibling is so they are X

to get the average of 12.5 you need to add all the siblings ages then divide it by 4

(36+X)/4=14 so the other sibling is 14

Answer:

B

Step-by-step explanation:

12.5x3=37.5

37.5 +11.5 =49

49÷4 =12.25

The sum of the given series is 49 and it converges to infinity.

According to the statement

we have given that a series which is 7, -8, 64/7, 512/49

And we have to find that the series is converges or diverges.

So, For this purpose,

The nth term in the series is 6 multiplied by the (n-1)th power of -8/7:

So,

[tex]a_{1} = 7(\frac{-8}{7} )^{1-1}[/tex]

[tex]a_{2} = -8(\frac{-8}{7} )^{2-1}[/tex]

[tex]a_{3} = \frac{64}{7} (\frac{-8}{7} )^{3-1}[/tex]

And so on then

Sum of the series become to the nth partial sum

[tex]S_{N} = 7(1 +\frac{-8}{7} + ......+ (\frac{-8^(n-2)}{7^(n-2)}) + (\frac{-8^(n-1)}{7^(n-1)}))[/tex]

Multiplying both sides by -8/7 gives

[tex]\frac{-8}{7} S_{N} = 7(\frac{-8}{7} +\frac{-8^{2} }{7^{2}} + ......+ (\frac{-8^(n-1)}{7^(n-1)}) + (\frac{-8^n}{7^n}))[/tex]

and subtracting this from [tex]S_{N}[/tex] gives

[tex]\frac{-1}{7} S_{N} = 7(1-\frac{-8^n}{7^n} )[/tex]

[tex]S_{N} = 49 (-1 + (8/7)^n)[/tex]

Now the sum of the series is 49 and the it converges to infinity.

So, The sum of the given series is 49 and it converges to infinity.

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Answer:

x - 4 = 2y

Step-by-step explanation:

"four less than a number x" therefore; x - 4

"is twice another number y" therefore; 2y

We are required to fill in the solution to the question that we have here.

this is done below

Six pyramids are shown inside of a cube. The height of the cube is h units. The lengths of the sides of the cube are b. The area of the base of the cube,

B, is (b)*(b) square units.

The volume of the cube is (b)*(b)*(b) cubic units.

The height of each pyramid, h, is  b/2

b = 2h.

There are 6 square pyramids with the same base and height that exactly fill the given cube.

Therefore, the volume of one pyramid is (1/6)(b)(b)(2h)

or One-third Bh.

This is the term that is used to refer to the shape that is known to have a square base and the base could also be triangular. The parts of the base are known to have a connection at the top of the pyramid.

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answer is in the attachment below :)

goodluck!!

The second-order equation as its equivalent system of first-order equations is

[tex]\left[\begin{array}{ccc}u(1)\\\\v(1)\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}7.5\\\\9\end{array}\right][/tex]

An equivalent system that has the identical answer is known as an equivalent structure. Given a gadget of two equations, we can produce an equal system by way of replacing one equation by means of the sum of the 2 equations, or by way of changing an equation by means of a couple of of itself.

Systems of linear equations are equivalent if and handiest in the event that they have an equal set of solutions. In other phrases, two systems are equal if and only if each answer of one in all of them is likewise a solution of the opposite.

In the structures sciences, a machine equivalent system is the conduct of a parameter or thing of a machine in a way just like a parameter or component of a distinctive system. Similarity means that mathematically the parameters and additives will be indistinguishable from each different.

Taking v = u, we have:

u" + 4u' + 6u = 4sin(3t)

--> v' + 4v + 6u = 4sin(3t)

So the system of equations is:

u' = 0u + 1v

v' = -6u - 4v + 4sin(3t)

So we can write it as:

u(1) = 7.5

v(1) = u'(1) = 9

So the initial condition matrix is:

[tex]\left[\begin{array}{ccc}u(1)\\\\v(1)\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}7.5\\\\9\end{array}\right][/tex]

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Solving a linear equation, we will see that after 9 days he cuts the last section.

We know that the initial length of the piece of cloth is 20m, and the taylor each day cuts a piece of 2 meters of it.

So, the length as a function on the number of days, is:

L(x) = 20m - 2m*x

Here we just need to solve:

L(x) = 2m

Because the last cut is when the long piece measures 4 meters (in that case he does one cut and has the two final pieces of 2 meters).

Solving that, we get:

20m - 2m*x = 2m

20m - 2m = 2m*x

18m/2m = x = 9

After 9 days he cuts the last section.

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Answer:

10/13

Step-by-step explanation:

There are 52 cards in a standard deck. There are 4 queens (queen of spades, clubs, hearts, diamonds) and 36 (2 - 10 of four suites) number cards. Therefore the probability of drawing a queen or a number card is (4 + 36)/52 = 40/52 = 10/13.

[tex]-2(-1+2w)[/tex]

distribute

[tex]2-4w[/tex]

put in standard form

[tex]-4w+2[/tex]

Answer: a = 24 units²

Step-by-step explanation:

      Let us graph the figure given. This shape appears to be a trapezoid. Now, we can solve for the area. This shape also has a height of 4, which I forgot to show in the picture.

       In the formula, h is the height, a is a base, and b is the other base.

            [tex]\displaystyle a=\frac{a+b}{2} h[/tex]

            [tex]\displaystyle a=\frac{4+8}{2} 4[/tex]

            [tex]\displaystyle a=\frac{12}{2} 4[/tex]

            [tex]\displaystyle a=(6)4[/tex]

            [tex]\displaystyle a=24\; \text{units}^{2}[/tex]

The length of the bedroom exists at x = 9 and y = 6.

From the given information, we get

Then  [tex]$\frac{(1/4)}{(9/4)} = \frac{1}{x}[/tex]

Solve this for x.

simplifying the value of x we get

Equate (1/9) to 1/x.

x = 9 (feet).

Convert 1.5 inches to feet using a proportion:

[tex]$\frac{(1/4)}{(1.5)} = \frac{1}{y}[/tex]

Solve this for y.

simplifying the value of y we get

(1/4)y = 3/2

Multiply both sides of the equation by 4.

y = 6

Therefore, the length of the bedroom exists at x = 9 and y = 6.

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The value of x from the given diagram is -10

Two triangles are known to be similar if the ratio of their similar sides is equal. The diagram shown is similar to the required diagram.

Given the following parameters

<ABC = 2x

<BAC = 3x + 10

Equate the expression since both angles are equal. Substitute;

2x = 3x + 10

Subtract 3x from both sides

2x-3x = 3x-3x+10

-x = 10

x = -10

Hence the value of x from the given diagram is -10

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If the pth term of an arithmetic progression is q and qth term is p then the (p+q) th term is 0.

Given that the p th term of an A.P is q aand q th term is p.

We are required to find the (p+q) th term of that A.P.

Arithmetic progression is a sequence in which all the terms have common difference between them.

N th term of an A.P.=a+(n-1)d

p th term=a+(p-1)d

q=a+(p-1)d-------1

q th term=a+(q-1)d

p=a+(q-1)d---------2

Subtract equation 2 by 1.

q-p==a+(p-1)d-a-(q-1)d

q-p=pd-qd-d+d

q-p=d(p-q)

d=(p-q)/(q-p)

d=-(p-q)/(p-q)

d=-1

Put the value of d in 1.

q=a+(p-1)(-1)

q=a-p+1

a=q+p-1

(p+q) th term=a+(n-1)d

=q+p-1+(p+q-1)(-1)

=q+p-1-p-q+1

=0

Hence if the pth term of an A.P is q and qth term is p then the (p+q) th term is 0.

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Answer: Vertical: angles ABF and DBE. Adjacent: angles ABC and CBD

Step-by-step explanation:

vertical angles are angles that share a common point. they are right across from each other, and in this case, share point B. adjacent angles are angles that are directly next to each other, and share a line or segment. in this case, the two angles share the segment BC. hope this helps.

The computation shows that the total distance will be 260.52km.

From the information given, it was stated that the race has 78 laps through the town of Monte Carlo and that each lap of the race has a distance of 3.34 km.

Therefore, the total distance will be:

= 78 × 3.34

= 260.52 km

Therefore, the distance is 260.52km.

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The minimum and maximum values are (16/9)√3  and -(16/9)√3.

According to the statement

we have given that the function

First of all, since the constraint's graph is a circle, which is a closed loop, and f is continuous in [tex]R^2[/tex], there must exist a constrained global maximum and minimum value.

Lagrange Multipliers:

f(x,y) = xy^2

g(x,y) = x^2 + y^2

We want ∇f = λ∇g so we get the following system of equations

1. y^2 = 2λx

2. 2xy = 2λy

3. x^2 + y^2 = 4 ← The constraint.

Equation 2 implies that y = 0 or λ = x

We can ignore y = 0, since that will make f(x,y) = 0 and clearly f(x,y) takes on both positive and negative values subject to the constraint.

Plugging in the alternative, λ = x to equation 1 gives y^2 = 2x^2.

Plugging this into the constraint gives 3x^2 = 4 so that x^2 = 4/3 and y^2 = 8/3

Taking square roots gives

x = ±√(4/3) = ±(2/3)√3

y = ±√(8/3) = ±(2/3)√6

At the points < (2/3)√3 , ±(2/3)√6 >, f(x,y) = (16/9)√3 ← Maximum

At the points < -(2/3)√3 , ±(2/3)√6 >, f(x,y) = -(16/9)√3 ← Minimum

So, The minimum and maximum values are (16/9)√3  and -(16/9)√3.

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The value of x from the given diagram is 20

According to theorem, the right triangle altitude theorem is a result in elementary geometry that describes a relation between the altitude on the hypotenuse in a right triangle and the two line segments it creates on the hypotenuse.

Using the theorem above;

RT^2 = 9 * 16

RT^2 = 144

R = 12 units

Determine the value of x using the Pythagoras theorem;

x² =12² + 16²

x² = 144 + 256

x² = 400

Take the square root of both sides

x = √400

x = 20

Hence the value of x from the given diagram is 20

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Answer:

Use this equation to find out!

Step-by-step explanation:

Since you didn't specify the n-gon, you have to use this equation to find out!

Number of Diagonals = n(n-3)/2

Hope this helps! :)

Step-by-step explanation:

To find the Tth term of an arithmetic progression, you should use the formula: Tn: a + (n-1)d, whereby 'a' is the first term, you have to find 'n' and 'd' is the difference between the first 2 numbers to find out by how much the arithmetic progression is increasing or decreasing. Hence, 29/30 minus 4/5 equals to 1/6. 'a' is 4/5 and 'd' is 1/6.

Use the above formula by replace a and d then you'll get the answer. Hope this helps.

Using a proportional relationship, it is found that the unit rate of change is of 9.

The relation d = 9t is graphed at the end of the answer.

A proportional relationship is a function in which the output variable is given by the input variable multiplied by a constant of proportionality, that is:

y = kx

In which k is the constant of proportionality.

In this problem, we have d as a function of t, hence the relationship is:

d = kt.

When t increases by 0.2, d increases by 1.8, hence the constant is given as follows:

k = d/t = 1.8/0.2 = 9

The relation d = 9t is graphed at the end of the answer.

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Answer:

35x71+71x65+51x23+23+49=8,345

Step-by-step explanation:

Answer:

8345

Is the correct answer

Step-by-step explanation:

hope it will help you

Answer: d. 40 pounds

Step-by-step explanation: let e equal the number of pounds weigh on Earth and m equal the number of pounds weighs on Mars.

so

72m=180e

1m= 72m/72

e= 180/72 = 2.5

1m=2.5e

16m=1 x16

e= 16 x 2.5

e= 40

so therefore, 16m=40e

I hope this helps

From the given options we can say that the only one that represents the area of the sector is; A = n/360 * πr²

In circles, a sector is said to be a part of a circle made of the arc of the circle together with its two radii. This means that it is a portion of the circle formed by a portion of the circumference (arc) and radii of the circle at both endpoints of the arc.

The formula for Area of a sector is given as;

θ/360 * πr²

where;

θ is the central angle of the sector

r is radius

Now, looking at the given options we can say that the only one that represents the area of the sector is;

A = n/360 * πr²

where n is the central angle of the sector

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Answer:

A!

Step-by-step explanation:

Values of c and d make the equation true are c=6, d=2

Equations

                                [tex]\sqrt[3]{162x^{c}y^{5} } = 3x^{2} y^{3} \sqrt[3]{6y^{d} }[/tex]

                               [tex](\sqrt[3]{162x^{c}y^{5} })^{3} = (3x^{2} y^{3} \sqrt[3]{6y^{d} })^{3}[/tex]

                                 [tex]{162x^{c}y^{5} } = (3x^{2} y^{3} \sqrt[3]{6y^{d} })^{3}[/tex]

                                  [tex]{162x^{c}y^{5} } = 27x^{6} y^{3} ({6y^{d})[/tex]

                                     [tex]{x^{c}y^{5} } = x^{6} y^{3} ({y^{d})[/tex]

                                     [tex]{x^{c}y^{5} } = x^{6} y^{3+d}[/tex]

                                   c = 6

                                   d = 2

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Answer:

x = 8

y = -3

Step-by-step explanation:

Multiply the first equation with (-2)

(-2) * (x - 4y) = 20

-2x + 8y = -40 now find the sum of it with second equation

2x + 5y - 2x + 8y = 1 - 40 add like terms (2x will eliminate -2x)

13y = -39 divide both sides by 13

y = -3

Now we can use this to find the value of x

x - 4y = 20 rewrite the equation using the value we found for y

x - 4(-3) = 20 multiply (-4) and (*3) (product will be positive because we are multiplying two negatives)

x + 12 = 20 subtract 12 from both sides

x = 8

Her profit % was increased by 2.77%

Answer:

Solution Given:

discount =10%

profit =25%

S.P with 13% vat = Rs 5,085

S.P+Vat% of S.P= Rs 5,085

S.P(1+13%)=Rs 5,085

S.P=Rs 5,085/1.13

S.P =Rs 4,500

Again

M.P = S.P+discount% of M.P

M.P- discount% of M.P= Rs 4,500

M.P(1-10%)=Rs 4,500

M.P=Rs 4,500/0.9

M.P = Rs 5,000

Now

C.P= (S.P*100)/(1+profit%)

C.P=(4,500*100)/(100+25%)

C.P= Rs 3,600

Again

profit =S.P- C.P= Rs 4,500-Rs 3,600=Rs 900

Again

Due to the excessive demands of her items, she decreased the discount percent by 2%.

So,

New discount = 10%-2%=8%

New S.P= M.P -discount% of M.P

=M.P(1-discount%)

=Rs 5,000(1-8%)

=Rs 4,600

Again

Profit=S.P- C.P

New profit =Rs 4,600 - Rs 3,600=Rs 1,000

Profit% =profit/C.P*100%= 1000/3600*100=27.77%

Profit % increased =New profit%- profit%

=27.77-25

=2.77%

The true statement is (c) Amal's work is incorrect because it includes a positive two instead of a negative two in the answer

The complete question is added as an attachment

From the table, we have

Divisor = x^2 - 3x + 4

Quotient = 2x + 5

Dividend = -2x^3 + 11x^2 - 23x + 20

See that the signs of the leading coefficients of the dividend and the divisor are different

This means that the leading coefficient of the quotient must be negative

From the question, we have:

Quotient = 2x + 5

The expression 2x + 5 has a positive leading coefficient

Hence, the true statement is (c) Amal's work is incorrect because it includes a positive two instead of a negative two in the answer

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Answer: 8:3

Step-by-step explanation:

360:135

We can simplify both, dividing both of them by a common divisor (45)

360/45= 8

135/45= 3

The ratio in lowest terms is 8:3

the ratio of girls to boys in the school, expressed in the lowest terms, is 8:3.

To find the ratio of girls to boys in the school, we divide the number of girls by the number of boys.

Ratio of girls to boys = Number of girls / Number of boys

Ratio of girls to boys = 360 / 135

To express the ratio in the lowest terms, we can simplify the fraction by finding the greatest common divisor (GCD) of 360 and 135 and then dividing both the numerator and denominator by the GCD.

The GCD of 360 and 135 is 45.

Ratio of girls to boys = (360 / 45) / (135 / 45)

Ratio of girls to boys = 8 / 3

So, the ratio of girls to boys in the school, expressed in the lowest terms, is 8:3. This means that there are 8 girls for every 3 boys in the school.

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