Answer:
36 years
Explanation:
2 = 16 * (1/2)^n where n is the number of half lives
2/16 = (1/2)^n
1/8 = (1/2)^n
log (1/8) = log (1/2^n)
log(1/8) = n log (1/2)
log ( 1/8 ) / log(1/2) = n = 3 half lives
each half life is 12 years so 3 * 12 = 36 years
In the initial sequence of thorium-232 decay, an alpha particle is emitted followed by a beta particle. What is the product of these two steps?
Nuclear decay is a radioactive decay where energy is released by unstable nuclei. After thorium undergoes decay, actinium-228 will be the final product. Thus, option a is correct.
What is the alpha and beta decay?Alpha radioactive decay is the loss of two protons and neutrons from the element that results in a decrease of the atomic mass by 4 and atomic number of the element by two.
²³² Th₉₀ → ²²⁸Ra₈₈ + ⁴α₂
Beta radioactive decay is the increase of the atomic number but not the atomic mass of the element.
²²⁸Ra₈₈ → ²²⁸Ac⁸⁹ + β⁻
Therefore, option a. actinium-228 is the final product of the decay.
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Your question is incomplete, but most probably your full question was, In the initial sequence of thorium-232 decay, an alpha particle is emitted followed by a beta particle. What is the product of these two decay steps?
²³² Th → α particle + β particle + ?
actinium-228radium-228francium-228thorium-228the correct answer differs from these possibilitiesWhat is the "average atomic mass" of this set of pennies.
(can you guys also include a formula on how i can solve future problems like this, please.)
Answer:
A. 2.74g is the correct answer
Explanation:
Greetings![tex]average \: mass = \frac{(mass \: pre - 1982 \times abundance) + (mass \: post - 1982 \times abundance}{100 } \\ ave = \frac{ (3.1g \times 40.0) + (2.5g \times 60.0)}{100} \\ ave = \frac{124 + 150}{100} \\ ave = \frac{274}{10} = 2.74g[/tex]
where, the sum of abundance always have to be 100%
Thus, 40.0 +60.0= 100.0
Select true or false: the work done on the surroundings by the expansion of a gas is w = –pdv
The work done on the surroundings by the expansion of a gas is w = –pdv .The statement is true.
The work is the energy required to move a system or body or anything against a force is called work. The word done = force×distance
Work done in an isobaric process is given by
W = PΔV
Where W = Work done
P =pressure
ΔV = change in volume
In a free expansion , the gas is allowed to expand into a vacuum.
This happens so quickly , so there is no heat transferred . No work is done , because the gas does not display anything.
W = PΔV
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A 200. 0-ng sample of sodium-24 was stored in a lead-lined cabinet for 45 hours. The half-life of sodium-24 is 15 hours. How much sodium-24 remains?
Answer:
25 gm would be left
Explanation:
45 hours is 3 half lives
200 gm * 1/2 * 1/2 * 1/2 = 25 gm
According to the concept of half life , as 45 hours are equal to three half- lives after 3 half-lives 25 g of sodium-24 remains.
What is half-life?Half -life of a substance is defined as the time which is required for half of the quantity of a radioactive substance to get decayed.It is a term which is used in nuclear chemistry for describing how quickly unstable atoms undergo radioactive decay into other nuclear species by emitting particles or the time which is required for number of disintegrations per second of radioactive material to decrease by one half of its initial value.
In the given problem time is=45 hours and as 1 half life=15 hours , for 45 hours=45/15=3 half lives .
Amount of sodium-24 after 3 half lives= 200×1/2×1/2×1/2=25 grams.
Therefore, after 45 hours 25 g of sodium-24 remains.
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Enter your answer in the provided box. calculate the ph of a 0. 011 m naf solution. (ka for hf = 7. 1 × 10−4. )
pH value of a 0. 011 m naf solution is 8.57.
Solution
This problem uses the relationship between Kb and the dissociation constants which is expressed as Kw = KaKb. Calculations are as follows:
Kb = KaKb
1.00 x 10^-14 = 7.2 x 10^-4(x)
x = 1.39 x 10^-11
We now need to calculate the [OH¯] using the Kb expression:
1.39 x 10^-11 = x^2 / (0.30 - x)
The denominator can be neglected. Thus, x is 3.73 x 10^-6.
pOH = -log 3.73 x 10^-6 = 5.43
pH = 14-5.43 = 8.57
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A chemical by itself is harmless in the human body. However, in the
presence of lead, the chemical becomes toxic. This is the result of
Answer:
synergy
Explanation:
when two substances combine effects to be greater than just their sum of their individual effects
A 5.00 g sample of hydrated sodium tetraborate, Na2B4O7 x nH2O is heated to drive off the water. After heating, 2.64 g of anhydrous Na2B4O7 reasons. What is the value of "n" in the hydrate formula
The value of ''n" in the hydrate formula is 10
Moles of anhydrous sodium tetraborate:Mass of anhydrous NA2B4O7 = 2.64g
Molar mass of NA2B4O7 = 201.224 g/mol
Number of Moles of anhydrous NA2B4O7 = Mass of NA2B4O7 / Molar mass of NA2B4O7
= 2.64 / 201.224
= 0.0131 mol
Mass of water in 5.00g of NA2B4O7 = 5.00 - 2.64
= 2.36 g
Moles of water = 2.36 / 18.015
= 0.1307 mol
The whole number ratio = moles of water / moles of anhydrous sodium tetra borate
= 0.1307 / 0.0131
The whole number ratio = 10
Hence the value of n in the hydrate formula is 10.
NA2B4O7. 10H2O
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what are the harmful effects of ozone layer depletion on human being ?
Explanation:
harmful effects of ozone layer depletion on human being are as follows :
i. It increases in certain type of cancer.
ii. It increases in eyes cataracts.
iii. It increases in immune deficiency disorder.
iv. It changes the climate.
Strong pressure gradients are associated with uniformly cold temperatures.
a. true
b. false
Student e accounted for the equivalent weight found for succinic acid by analyzing its titration with naoh(aq) and concluding that it is:________
Student e accounted for the equivalent weight found for succinic acid by analyzing its titration with [tex]NaOH[/tex] (aq) and concluding that it is diprotic.
One mole of succinic acid required two mole of base to neutralize completely. In this titration phenolphthalein indicator is used to observe the completion of the reaction. In an aqueous solution, succinic acid readily ionize to form succenate. Succinic acid undergoes two successive deprotonation reaction.
The succinic acid results in succinate ( dicarboxylic acid dianion ) which is form by removal of a proton from both carboxy groups of succinic acid.
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If the heat of vaporization for water is 2260 joules/g. How many kilojoules are released when 5. 00 g of steam is converted to liquid at 100°c?
The latent heat of vaporization 5gram of steam converted to liquid at 100°C is 11.3 KJ.
The latent heat of vaporization for a given substance tells you how much energy is required for one mole of that substance to undergo a phase transition or go from a liquid to a gas, at its boiling point.
Joules per gram, an alternative to the more popular kilojoules per mole, are used to express the latent heat of vaporization for water.
Therefore, we must determine how many kilojoules per gram are needed for a certain sample of water to transition from a liquid to a vapor at its boiling point.
As you know, the conversion factor that exists between Joules and kilojoules is 1 kJ = 10³ J
2260 J/g will be equivalent to
[tex]2260 \frac{J}{g} . \frac{1kJ}{1000J } = 2.26 kJ/g\\\\[/tex]
As we know,
2260 = 2.26 . 10³
which means that 2.26 .10³ = 2260J
This is the latent heat of vaporization 5gram of water= 2260J/g × 5g
= 11,300J
= 11.3 KJ
Therefore, the latent heat of vaporization 5gram of steam converted to liquid at 100°C is 11.3 KJ.
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CaCO3(s) CaO(s) + CO₂(g)
3.25 mol CaCO3 decomposes according to the reaction above. What volume of CO2 gas is produced once the gas cools to STP?
Taking into account the reaction stoichiometry and the definition of STP, 72.8 L of CO₂ gas is produced once the gas cools to STP.
Reaction stoichiometryIn first place, the balanced reaction is:
CaCO₃ → CaO + CO₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
CaCO₃: 1 moleCaO: 1 moleCO₂: 1 moleSTP conditionsThe STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.
Moles of CO₂ formedThe following rule of three can be applied: if by reaction stoichiometry 1 mole of CaCO₃ form 1 mole of CO₂, 3.25 moles of CaCO₃ form how many moles of CO₂?
[tex]moles of CO_{2} =\frac{3.25 moles of CaCO_{3}x 1 mole of CO_{2}}{1 moleof CaCO_{3}}[/tex]
moles of CO₂= 3.25 moles
Then, 3.25 moles of CO₂ are formed when 3.25 moles of CaCO₃ decomposes.
Now, you can apply the following rule of three: if by definition of STP conditions 1 mole of CO₂ occupies a volume of 22.4 liters, 3.25 moles occupies how much volume?
[tex]volume= \frac{3.25 molesx22.4 L}{1 mole}[/tex]
volume= 72.8 L
Finally, 72.8 L of CO₂ gas is produced once the gas cools to STP.
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How many bonds can one carbon atom form with another carbon atom?
Answer:
four
Explanation:
i said so
What concentration of nacl solute particles in water will provide an isotonic eyedrop solution?
The concentration of [tex]NaCl[/tex] solute particles in water will provide an isotonic eyedrop solution is 0.9% w/v
The isotonic solution is calculated by multiply the quantity of each drug in the prescription by its sodium chloride equivalent E , and subtract this value from the concentration of sodium chloride which is isotonic with body fluids . For a solution to be termed isotonic ( equal tone ) it must have the same osmotic pressure as a specific bodily fluid.
Example : The concentration of [tex]NaCl[/tex] solute particles in water will provide an isotonic eyedrop solution is 0.9% w/v
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2C6H6(g) + 15O2(g) = 12CO2(g) + 6H2O(g)
2.0 moles C6H6 reacts with oxygen according to the reaction above. What volume of water vapor forms at STP?
At STP, the volume of water that is produced is 134.4 L.
What is the volume?Now we know that the equation of the reaction is;
2C6H6(g) + 15O2(g) = 12CO2(g) + 6H2O(g)
We can use the stoichiometry of the reaction to determine the volume of the water produced as follows;
2 mole of C6H6 produced 6 moles of water. If 1 mole of water occupies 22.4 L then 6 moles of water will occupy 6 * 22.4 L = 134.4 L
Thus, we can see that at STP, the volume of water that is produced is 134.4 L.
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Identify the classification of milk a aerosol b solid emulsion c solid aerosol d foam e emulsion
option (c) emulsion is the right answer
Emulsion is a classification of milk.
Describe an emulsion.In physical chemistry, an emulsion is a combination of two or more liquids in which one of the liquids is present as microscopic or ultramicroscopic droplets dispersed throughout the other.
How is emulsion used?Emulsions form as a result of the cleansing action of soaps.
(ii) The emulsification process is how lipids are broken down in the intestines.
(iii) Disinfectants and antiseptics combine with water to generate emulsions.
(iv) The emulsification technique is utilized to create medications.
How is an emulsion created?When two immiscible liquids, such as oil and water, are stirred together with an emulsifier—which might be a protein, phospholipid, or even a nanoparticle—emulsion is created.
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URGENT 80 POINTS AND BRAINLIEST FOR ANSWER
this wuestion or photo is on my chemistry DBA laster today, what is it? please explain possible questions and responses and answers to what may be asked.
i think it involves things like the reaction moving forward and what would do that or somehing but i am unsure. something online said stuff that raise pressure was the answer to something but why?
sorry if this is confusing i havent been given an actual question for this yet but need to know ahead of time.
A monosaccharide that contains 6 carbon atoms, one of which is in an aldehyde group, is classified as a(n)?
A monosaccharide that contains 6 carbon atoms, one of which is in an aldehyde group, is classified an Aldohexose.
Monosaccharides of specific sizes may be indicated by names composed of a stem denoting the number of carbon atoms and the suffix -ose.
For example, the terms triose, pentose, and hexose signify monosaccharides with, respectively, three, four, five, and six carbon atoms. Monosaccharides are also classified as aldoses or ketoses.
Those monosaccharides that contain an aldehyde functional group are called aldoses; those containing a ketone functional group on the second carbon atom are ketoses. Combining these classification systems gives general names that indicate both the type of carbonyl group and the number of carbon atoms in a molecule.
. Glucose and fructose are specific examples of an aldohexose and a ketohexose, respectively.
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In the cathode ray tube experiment, j. j. thomson passed an electric current through different gases inside a cathode ray tube in the presence of an electric field. in which two ways did this experiment change scientists’ understanding of the atom?
The two ways were,
It showed that atoms can be divided into smaller parts. It showed that all atoms contain electrons.What is Cathode ray tube experiment ?A cathode-ray tube, often known as a CRT, is a vacuum tube that houses one or more electron cannons that produce electron beams that are then bent to produce pictures on a phosphorescent screen. The visuals might be pictures (from a television or computer display), electrical waveforms (from an oscilloscope), radar targets, or other occurrences.
Tomson came to the conclusion that atoms can be divided into their constituent corpuscles (atoms are made up of smaller particles).
The electron was discovered in 1897 by J. J. Thomson.
His "plum pudding" concept from 1904 postulated that the positive charge contains embedded electrons.
With this model, he disproved his first theory (the atom was composed of immaterial vortices).
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The molar volume of copper (63.5 g.mol^–1 ) at 25°C is 7.09 cm^3.mol^–1. What is the density of copper at 25°C in g.cm^3?
Considering the definition of molar volume and density,the density of copper at 25°C is 8.96 [tex]\frac{g}{cm^{3} }[/tex].
Molar volumeMolar volume is an intensive property that indicates how much space one mole of a certain substance or compound occupies. In other words, the molar volume is the space occupied by one mole of a substance.
The expression to calculate the molar volume is:
Vm= V÷ n
where:
V is the occupied volume.n is the molar amount of the substance.DensityDensity is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.
In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.
Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
density= mass÷ volume
Relationship between molar volume and densityThe relationship between molar volume and density is reflected in the following expression, where the molar volume is calculated by dividing the molar mass (M) by the mass density (ρ):
Vm= M÷ρ
Density of copperIn this case, you know:
Vm= 7.09 [tex]\frac{cm^{3} }{mol}[/tex]M= 63.5 [tex]\frac{g}{mol}[/tex]ρ= ?Replacing in the relationship between molar volume and density:
7.09 [tex]\frac{cm^{3} }{mol}[/tex]= 63.5 [tex]\frac{g}{mol}[/tex]÷ρ
Solving:
7.09 [tex]\frac{cm^{3} }{mol}[/tex]×ρ= 63.5 [tex]\frac{g}{mol}[/tex]
ρ= 63.5 [tex]\frac{g}{mol}[/tex]÷7.09 [tex]\frac{cm^{3} }{mol}[/tex]
ρ= 8.96 [tex]\frac{g}{cm^{3} }[/tex]
Finally, the density of copper at 25°C is 8.96 [tex]\frac{g}{cm^{3} }[/tex].
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Why do you add hydroxide to your hexanediamine solution? what would occur if you did not add it?.
In the polymerization reaction, the lone pair electrons on the NH₂ groups of hexanediamine attack the C=O groups of the dicarboxylic acid in a nucleophilic substitution reaction as shown in the image.
Hydroxide is added to remove any H⁺ ions present and keep the hexanediamine in the deprotonated form, so that the NH₂ lone pair electrons are available for reaction.
What if you don't add it ?If hydroxide is not added, the NH₂ groups will get protonated by H⁺ ions present to give NH₃⁺ groups, which cannot react.
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A sample of an unknown gas is found to be non-reactive to flame tests and chemically reactive with limewater and bromothymol blue. Which gas is present in the sample?
The sample of gas that is unreactive to flame tests and chemically reactive with limewater and bromothymol blue is Carbon dioxide.
Flame tests are performed to identify the unknown metals or metalloids. Upon burning on the flame, a compound gives characteristic colour, that helps in identification.
Carbon dioxide extinguishes the flame itself when placed upon it. And it is known to turn the lime water milky when reacts. Carbon dioxide also changes the colour of bromothymol blue. The change in colour is observed due to certain chemical changes like change in pH, formation of carbonic acid and conversion into more acidic form.
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Calculate the molar solubility of silver(i) bromate with ksp = 5. 5×10-5. also, convert the molar solubility to the solubility. the molar solubility is ___________ and the solubility is ____________
The molar solubility is 7.4×[tex]10^{-3}[/tex] M and the solubility is 7.4×[tex]10^{-3}[/tex] g/L .
Calculation ,
The dissociation of silver bromide is given as ,
[tex]AgBr[/tex] → [tex]Ag ^{+}[/tex] + [tex]Br^{-}[/tex]
S
- S S
Ksp = [[tex]Ag ^{+}[/tex] ] [ [tex]Br^{-}[/tex] ] = [S] [ S ] = [tex]S^{2}[/tex]
S = √ Ksp = √ 5. 5×[tex]10^{-5}[/tex] = 7.4×[tex]10^{-3}[/tex]
The solubility =7.4×[tex]10^{-3}[/tex] g/L
The molar solubility is the solubility of one mole of the substance.
Since , one mole of [tex]AgBr[/tex] is dissociates and form one mole of each [tex]Ag ^{+}[/tex] and [tex]Br^{-}[/tex] ion . So, solubility is equal to molar solubility but unit is different.
Molar solubility = 7.4×[tex]10^{-3}[/tex] mol/L = 7.4×[tex]10^{-3}[/tex] M
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1. Convert these from plus-minus notation to significant figures notation.
a. 65.316 mL + 0.05 mL.
b. 5.2 cm + 0.1 cm
c. 1.8642 km ± 0.22 km
d. 16.8°C ±1°C
Answer: a. 65.37 mL
b. 5.3 cm
c. 2.08 km (plus) or 1.64 km (minus)
d. 18°C (plus) or 16°C (minus)
Explanation:
The way significant figures work when you're adding or subtracting, is you go to the answer with the least amount of decimal places. Take a. for example; you have 65.316 (3 places after the decimal) and 0.05 (2 places after the decimal place). Based off of this, you would round your answer to two places after the decimal. And when you have a whole number, like in d. you round to the nearest whole number, since there aren't any decimal places to round your answer to.
How much energy is required to melt 20 g of water starting at 0 o C?
(△H vap = 2265 J/g, △H fus = 334 J/g, c = 4.18 J/go C )
The energy required to melt 20 g of water (ice) starting at 0° C is 6680 J.
What is Heat?
Heat is a form of energy that is possessed by a system by virtue of its temperature. Its unit is Joule.
Enthalpy is the amount of the heat content of a system.
What is Heat Capacity?It is the amount of heat required to increase the temperature of a system by 1° C. It is an extensive property. Its unit is J/°C
Heat Capacity is given by
[tex]c= \frac{q}{\Delta T}[/tex]
where q = heat required
[tex]\Delta T[/tex] = change in temperature
Enthalpy of Fusion is the enthalpy change when 1 mole of a solid substance changes into its liquid state at its melting point.
Here, water in solid form (ice) melts into liquid form at 0°C
[tex]H_{2} O (s) \rightarrow H_{2} O(l) \\\Delta H_{fus } =334Jg^-^1[/tex]
We know,
[tex]\Delta H = \frac{m}{q}\\[/tex]
where m = given mass
q = heat required
[tex]q = \Delta H \times m[/tex]
q = 334 [tex]Jg^-^1[/tex] x 20 g
= 6680 J
Thus, the heat required to melt 20 g of water at 0°C is 6680 J
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Why is the citric acid cycle considered part of aerobic metabolism even though oxygen does not appear explicitly in any reaction because?
Succinate dehydrogenase is the citric acid cycle considered part of aerobic metabolism even though oxygen does not appear.
The respiratory complex II, also known as succinate dehydrogenase (SDH), succinate-coenzyme Q reductase (SQR), or SDH, is an enzyme complex that is present in the inner mitochondrial membrane of eukaryotic and numerous bacterial cells. SDH converts succinate to fumarate as part of the citric acid cycle. SDH shares structural similarities with fumarate reductase, an enzyme that catalyzes the reverse process during anaerobic respiration in bacteria. (1997, Hagerhall). Succinic semialdehyde dehydrogenase impairment is brought on by ALDH5A1 gene mutations. Instructions for creating the succinic semialdehyde dehydrogenase enzyme are found in the ALDH5A1 gene.
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What would the potential of a standard hydrogen electrode (s. h. e. ) be under the given conditions? [h ]=0. 84 mh2=2. 2 atm=298 k
The potential of a standard hydrogen electrode (s. h. e. ) be under the given conditions is - 0.029 V
Calculation ,
Formula used :
[tex]E_{cell}[/tex] = [tex]E_{cell}[/tex] ° - 0.059/n ㏒[tex]H_{2}[/tex]/ [tex][H^{+}]^{2}[/tex]
As we know that ,
[[tex]H^{+}[/tex]] = 0. 84 M
[tex]P_{H_{2}[/tex] = 2. 2 atm
Temperature ( T ) = 298 K
From reaction at electrode number of electrons involve ( n ) = 1
Standard electrode potential of standard hydrogen electrode [tex]E_{cell}[/tex] ° = 0
Putting the value of all data in equation ( i ) , we get
[tex]E_{cell}[/tex] = 0 - 0.059/1 ㏒2. 2 / [tex](0. 84)^{2}[/tex] = - 0.059 ㏒3.14 = - 0.059×0.497
[tex]E_{cell}[/tex] = - 0.029 V
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It takes 11. 2 kj of energy to raise the temperature of 145 g of benzene from 23. 0°c to 68. 0°c. what is the specific heat of benzene?
If we takes 11. 2 kj of energy to raise the temperature of 145 g of benzene from 23. 0°c to 68. 0°c, then the specific heat of benzene is
1716.475 J/kg.°C.
Specific Heat capacity is given as
Q = cm(t₂-t₁) ................[tex]equation 1[/tex]
Where Q = quantity of heat, c = specific heat of benzene, m = mass of benzene, t₁ = initial temperature, t₂ = final temperature.
[tex]C[/tex] = [tex]\frac{Q}{m_{(t2-t1)} } ...........equation 2[/tex]
Given:
[tex]Q = 11.2 kJ = 11200 J \\\\m= 145\\\\g = 0.145 kg\\\\t_{2} = 68.0 °C\\\\t_{1} = 23.0 °C[/tex]
Substitute into equation 2.
[tex]C = \frac{11200}{[0.145(68-23)]}\\\\ C= \frac{11200}{6.525}\\\\ C= 1716.475 J/kg °C[/tex]
Hence the specific heat of benzene = [tex]1716.475 J/kg °C[/tex]
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When 1. 0 l of 0. 00010 m naoh and 1. 0 l of 0. 0014 m mgso4 are mixed, would a precipitate be formed? show work
When 1. 0 l of 0. 00010 m NaOH and 1. 0 l of 0. 0014 m mgso4 are mixed, there will be no precipitate formed.
What is a precipitate?The precipitate is the solid concentration of a substance that is collected over a solution.
First, we determine the concentration of magnesium and hydroxide
(Mg2+) = 7.00 × 10⁻⁴
(OH−) = 5.00 × 10⁻⁵
Now, we calculate the solubility quotient
Qc = (Mg2+) (OH−) ²
Qc = 7.00 × 10⁻⁴ x (5.00 × 10⁻⁵)²
Qc = 1.75 x 10⁻¹²
The solubility product of the magnesium hydroxide is 1.80 x 10⁻¹¹ which is more than the solubility quotient. Thus, there will be no precipitate form.
Thus, there will be no precipitate formed because the solubility quotient we calculated is less than the solubility product.
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What is the specific heat of a metal if 175 j are needed in order to increase the temperature of a 50. g sample from 25 âc to 50. âc? report your answer with two significant figures.
Taking into account the definition of calorimetry, the specific heat of the metal is 0.14 [tex]\frac{J}{gC}[/tex].
CalorimetryCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where:
Q is the heat exchanged by a body of mass m.
c is specific heat substance.
ΔT is the temperature variation.
In this way, between heat and temperature there is a direct proportional relationship (Two magnitudes are directly proportional when there is a constant so that when one of the magnitudes increases, the other also decreases; and the same happens when either of the two decreases .).
The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat by the mass of the body.
Specific heat of the metal
In this case, you know:
Q= 175 Jm= 50 gc= ?ΔT= Tfinal - Tinitial= 50 C - 25 C= 25 CReplacing in the expression to calculate heat exchanges:
175 J= c× 50× 25 C
Solving:
c=[tex]\frac{175 J}{50 gx25C}[/tex]
c=0.14 [tex]\frac{J}{gC}[/tex]
Finally, the specific heat of the metal is 0.14 [tex]\frac{J}{gC}[/tex].
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