The count of the denominations of the bills of $1, $5, and $10, are 15, 10, and 5, respectively.
In the question, we are given that there are 3 denominations of bills in a wallet: $1, $5, and $10. There are 5 fewer $5-bills than $1-bills. There are half as many $10-bills as $5-bills.
We are asked to find the count of each denomination, given there was altogether $115 in the bag.
We assume the number of $1-bills in the bag to be x.
Total amount in x bills of $1 = x * $1 = $x.
Given that there are 5 fewer $5-bills than $1-bills in the bag, number of $5-bills in the bag = x - 5.
Total amount in (x - 5) bills of $5 = (x - 5) * $5 = $5(x - 5).
Given that there are half as many $10-bills as $5-bills in the bag, number of $10-bills in the bag = (x - 5)/2.
Total amount in (x - 5)/2 bills of $10 = (x - 5)/2 * $10 = $5(x - 5).
Thus, the total amount in the bag = $x + $5(x - 5) + $5(x - 5).
But, the total amount in the bag = $115.
Thus, we get an equation:
$x + $5(x - 5) + $5(x - 5) = $115,
or, x + 5x - 25 + 5x - 25 = 115,
or, 11x = 115 + 50,
or, 11x = 165,
or, x = 165/11,
or, x = 15.
Thus, number of $1-bills = x = 15.
The number of $5-bills = x - 5 = 15 - 5 = 10.
The number of $10-bills = (x - 5)/2 = (15 - 5)/2 = 10/2 = 5.
Thus, the count of the denominations of the bills of $1, $5, and $10, are 15, 10, and 5, respectively.
The provided question is incomplete. The complete question is:
There are 3 denominations of bills in a wallet: $1, $5, and $10. There are 5 fewer $5-bills than $1-bills. There are half as many $10-bills as $5-bills. If there is $115 altogether, find the number of each type of bill in the wallet."
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If the diameter of a circular pond is x meter, what is the its circumference?
Answer:
piex
Step-by-step explanation:
the circumference of a circle is pie times the diameter of the circle.
1. In a class of 60 students, a survey was conducted, 30 students had applied for Addis Ababa University, 25 students applied for Bahir Dar University and 24 students applied for Wachemo University. 11 students applied for both Addis Ababa and Bahir Dar Universities, 6 applied for both Addis Ababa and Wachemo Universities, 9 applied for both Wachemo and Bahir Dar Universities while 4 applied neither of the aforementioned universities. Find number of students that applied at most two universities.
The number of students who applied at most two universities is 26 students.
How is the calculation for the number done?The population of students in a class = 60 students
Number of students who applied for Addis Ababa University = 30 students
Number of students who applied for Bahir Dar University = 25 students
Number of students who applied for Wachemo University = 24 students
Number of students who applied for Addis and Bahir = 11 students
Number of students who applied for Addis and Wachemo = 6 students
Number of students who applied for Wachemo and Bahir = 9 students
The number of students who applied at most two universities is 26 (11+ 6 + 9).
Thus, the number of students who applied at most two universities is 26.
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DIRE NEED OF HELP, pleaseee help
(not a lot of points sorry)
Answer:
C. Subtract 4 from both sides.
Step-by-step explanation:
You need the equation in the form x² + ax + b = 0 to then either try factoring or use the quadratic formula.
In order to achieve that, you need to first:
Subtract 4 from both sides.
Find the critical value Tc for the confidence level c=0.80 and sample size n=29
Using a calculator, the critical value for the t-distribution with a confidence level c=0.80 and sample size n=29 is of Tc = 1.3125.
How to find the critical value of the t-distribution?It is found using a calculator, with two inputs, which are given by:
The confidence level.The number of degrees of freedom, which is one less than the sample size.In this problem, the inputs are given as follows:
Confidence level of 80%.28 degrees of freedom, as there is a sample size of 29.Hence, using a calculator, the critical value for the t-distribution with a confidence level c=0.80 and sample size n=29 is of Tc = 1.3125.
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Solve the equation
7/4x-2=-5x+1
[tex]\frac{7}{4}[/tex] [tex]x\:-\:2\:=\:-5x\:+\:1[/tex]
Solution:[tex]\frac{7}{4}[/tex] [tex]x\:-\:2\:=\:-5x\:+\:1[/tex]
[tex]7x\: - \:8 \:=\: -20x\: + \:4 [/tex]
[tex]7x \:- \:8 \:+ \:20x \:= \:4[/tex]
[tex]7x\: + \:20x \:= \:4 \:+ \:8 [/tex]
[tex]27x\: = \:4\: + \:8[/tex]
Answer:[tex]x\:= [/tex] [tex]\frac{4}{9}[/tex]
#CarryOnLearning
Answer:
x = 4/9
Step-by-step explanation:
Solve for x
7/4 x -2 = -5x +1
Add 5x to each side
7/4 x -2+5x = -5x +1+5x
7/4 x + 5x -2 = 1
Get a common denominator for the x terms
7/4x +20/4x -2 = 1
Add 2 to each side
27/4 x -2+2 = 1+2
27/4 x = 3
Multiply each side by 4
27/4 x *4 = 3*4
27x = 12
Divide each side by 27
27x/27 = 12/27
x = 12/27
Simplify
x = 4/9
What is the area of the actual square window
shown in the scale drawing?
0.75 in.
Scale
1 in. = 2 m
Answer: 2.25 meters
Step-by-step explanation: 1 in = 2 meters. 0.75 is 75 percent of 1 so the length of the window is 75 percent of 2 which is 1.5. 1.5 squared is 2.25 so the length of the window is 2.25 meters
Find the value of z such that 0.8664 of the area lies between −z and z. Round your answer to two decimal places.
Using the normal distribution, the value of z is of z = 1.5.
Normal Probability DistributionThe z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.For this problem, considering the symmetry of the normal distribution, the area above the mean is given by:
0.8664/2 = 0.4332.
Hence z has a p-value of 0.5 + 0.4332 = 0.9332, hence the value of z is z = 1.5.
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Subtract: (c ^ 2 - 4c + 7) from (7c ^ 2 - 5c + 3)
subtracting (c ^ 2 - 4c + 7) from (7c ^ 2 - 5c + 3) would give 6c² - 9c -4
Substracting algebraic expressionsGiven the expressions as
(c ^ 2 - 4c + 7)
(7c ^ 2 - 5c + 3)
We are to substract expression 2 from expression 1
In doing this, we need to know the BODMAS rule ( bracket, of, division, multiplication, addition and subtraction). This would help in finding the solution
(7c ^ 2 - 5c + 3) - (c ^ 2 - 4c + 7)
Expand the bracket
7c² - 5c + 3 - c² - 4c + 7
collect like terms
7c²- c² - 5c - 4c + 3 - 7
Add or substract the like terms
6c² - 9c -4
Thus, subtracting (c ^ 2 - 4c + 7) from (7c ^ 2 - 5c + 3) would give 6c² - 9c -4
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Answer:6c^2-c-4
Step-by-step explanation:
(7c^2-5+3)-(c^2-4c+7)
7c^2-5c+3-c^2+4c-7
Rearrange the terms
7c^2-c^2-5c+4c+3-7
Combine like terms
6c^2-c-4
Cross Multiply With Fractional Ratios.
5 (1/2)
=
8 x
cross multiply to find the awnser
Answer:
5/16
Step-by-step explanation:
assuming you mean 5(1/2) = 8x
5(1/2) is the same as 5/2
so, 5/2 = 8x
5 = 16x
x= 5/16
urgent need of assistance
Answer:i got 329
Step-by-step explanation:
ASAP help me with this
Answer:
2160°
Step-by-step explanation:
[tex]180(14-2)=2160^{\circ}[/tex]
A recipe for lemon bars called for 9" X 13" pan. How many 1" X 1" bars can be cut? How many 2" X 2" bars can be cut? How much is wasted if your serve only 2" X 2" square bars?
The number of bars which can be cut for the 1" X 1" and 2" X 2" square bars are; 117 and 29 units respectively.
How many bars can be cut from the pan in each case?The total area of the given pan can be evaluated as follows;
Area = length × width
= 9 × 13
= 117 square units.
Hence, the number of 1" X 1" bars can be cut which can be cut from the pan;
= 117/(1×1)
= 117 1" X 1" bars.
For the 2" X 2" square bars, we have;
= 117/(2×2);
29 remainder 1 square unit.
Ultimately, one square unit of the pan is wasted for the 2" X 2" square bars.
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Create a two-column proof: Given: EAB and DCB are two right triangles. The figure has BED≅ BDE. Point B is the midpoint of segment AC. Prove: EAB≅ DCB
The two-column proof that shows that ΔEAB ≅ ΔDCB by SAS congruence theorem is explained below.
What is the the SAS Congruence Theorem?The Side-angle-side congruence theorem (SAS) that states that two triangles that are have two pairs of corresponding congruent sides and a pair of included corresponding congruent angles are congruent to each other.
What is an Isosceles Triangle?Any triangle with two equal base angles is referred to as an isosceles triangle, The sides opposite these base angles are also congruent to each other.
Given the diagram below, the proof is expressed as follows:
Statement 1: ΔEAB and ΔDCB are two right triangles
Reason 1: Given
Statement 2: ∠EAB ≅ DCB
Reason 2: Right angles
Statement 3: ∠BED ≅ BDE
Reason 3: Given
Statement 4: ΔBED is an isosceles triangle
Reason 4: Definition of isosceles triangle
Statement 5: BE ≅ BD
Reason 5: Definition of isosceles triangle
Statement 6: ΔEAB ≅ ΔDCB
Reason 6: SAS
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A phone company offers two monthly plans. Plan A costs $20 plus an additional $0.08 for each minute of calls. Plan B costs $16 plus an additional $0.13 for each minute of calls. For what amount of calling do the two plans cost the same? minutes What is the cost when the two plans cost the same?
u0ukj787y8fr7hjhy7 which one
If ABC and DEF are complementary, then the value of x will be,
90 - ABC = x
90 - 53 = x
x = 37°
Answer:
x=37
Step-by-step explanation:
complementary means when added up they bring 90
so, 53+x=90
x=90-53
x=37
mark me brainliest if it helped pls :)
What is the rise and the run please help
Answer:
-1
Step-by-step explanation:
Rise=2
Run=-2
2/-2=
-1
At the beach, Nardia collected triple the number of seashells that Pierre did. Together, they collected 52 seashells. Which equations represents p, the number of seashells that Pierre collected.
3 p + p = 52
3 + p = 52
52 + p = 3 p
52 + p = 3
Answer:
A
Step-by-step explanation:
p = Pierre shells
Nardia shells = 3p
3p + p = 52
Answer:
a
Step-by-step explanation:
The graph below shows the value of Edna's profits f(t), in dollars, after t months: graph of quadratic function f of t having x intercepts at 6, 0 and 18, 0, vertex at 12, negative 36, and passes through point 21, 41.25 What is the closest approximate average rate of change for Edna's profits from the 18th month to the 21st month?
The closest approximate average rate of change for Edna's profits from the 18th month to the 21st month is 14
How to determine the average rate of change?From the question, we have the following ordered pairs
x intercepts = (6,0) and (18, 0)
Vertex = (12, -36)
Points (21, 41.25)
The closest approximate average rate of change for Edna's profits from the 18th month to the 21st month is the calculated using
m = [f(21) - f(18)]/[21 - 18]
This becomes
m = [f(21) - f(18)]/3
Substitute the known values in the above equation
m = [41.25 - 0]/3
Evaluate the difference
m = 41.25/3
Evaluate the quotient
m = 13.75
Approximate
m=14
Hence, the closest approximate average rate of change for Edna's profits from the 18th month to the 21st month is 14
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Complete question
The graph below shows the value of Edna's profits f(t), in dollars, after t months:
What is the closest approximate average rate of change for Edna's profits from the 18th month to the 21st month?
See attachment for graph
PLEASE HELP ASAP WITH EXPLANATION: If f(x) = 2f(x − 1) for all integers x, and f(n) = 3 for some integer n, find the value of
[f(n − 5)][f(n + 5)].
Answer:F to the power of 2,N to the power of 2,—25,f to the power of 2
Step-by-step explanation: i really hope under stand
ASAP help me with this question PLEAZE
Answer:
38°
Step-by-step explanation:
EFGH is an isosceles trapezoid (a trapezoid with two congruent legs is isosceles)
∠HGF=70° (base angles of an isosceles trapezoid are congruent)
∠EGH=32° (angles in a triangle add to 180°)
∠FGE=38° (angle subtraction postulate)
3x + 3 = 6 + 6. solve for x
Answer:
x = 3
Step-by-step explanation:
3x + 3 = 6 + 6
3x + 3 = 12
3x = 12 - 3
3x = 9
x = 3
3 (3) + 3 = 6 + 6
9 + 3 = 12
12 = 12
Consider the following descriptions of the platonic solids use them to complete the table
Answer:
4, 6, 4
6, 12, 8
8, 12, 6
Step-by-step explanation:
Tetrahedron:
4 faces, 6 edges, 4 vertices
Cube:
6 faces, 12 edges, 8 vertices
Octahedron:
8 faces, 12 edges, 6 vertices
you can also use the v - e + f = 2 to check
A newsletter publisher believes that over 30% of their readers own a Rolls Royce. For marketing purposes, a potential advertiser wants to confirm this claim. After performing a test at the 0.05 level of significance, the advertiser failed to reject the null hypothesis.
The conclusion regarding the publisher's claim regarding the hypothesis is that have sufficient evidence to support the claim that the proportion is less than 30% of their readers own a Rolls Royce.
What is a null hypothesis?The null hypothesis is a statistical theory that suggests that no statistical relationship and significance exists in a set of given single observed variable, between two sets of observed data and measured phenomena.
Since we reject the null hypothesis , we have sufficient evidence to support the claim. In this case, we have sufficient evidence to support the claim that the proportion is less than 30% of their readers own a Rolls Royce.
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Complete question:
A newsletter publisher believes that less than 30% of their readers own a Rolls Royce. For marketing purposes, a potential advertiser wants to confirm this claim. After performing a test at the 0.02 level of significance, the advertiser decides to reject the null hypothesis. What is the conclusion regarding the publisher's claim?
Evaluate each ex
1) 3(6+7)
By using the PEMDAS order of operations, we get 3(6+7) = 39.
The equation be 3(6+7) then the correct answer is 34.
What is PEMDAS order of operations?The order of operations exists as a law that describes the proper sequence of stages for estimating a math expression. We can recognize the order utilizing PEMDAS: Parentheses, Exponents, Multiplication, Division (from left to right), Addition, and Subtraction (from left to right).
Given: 3(6+7)
By using the PEMDAS order of operations, we get
(6+7) = 13
Then we get
3(6+7) = 3 [tex]*[/tex] 13
= 39.
Therefore, the value of 3(6+7) = 39.
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Stillwater Junior high divides students into teams taught by a group of teachers. The table shows the number of students in each team.
The principal uses a computer to randomly select the name of a student from all the students in the school. With the computer program, it is possible to draw the name of the same student twice. If the principal selects the name of a student from the Voyagers on the first try, what is the probability she will draw the name of another student from the Voyagers on the second try?
A. 81/399
B. 41/200
C. 1/82
D. 21/100
Answer:
(A)81/399
Step-by-step explanation:
The probability that the Principal selects a voyager on the first try is
82/400
Since another student is to be selected, the total population has reduced by 1 and the number of voyagers has been reduced by 1.
Probability that another voyager is selected on the second try is
81/399
The correct answer is A.
Can you tell which 3-D shape this would make?
The three dimensional shape formed by the net shown below is a cube.
What is a three dimensional shape?A three dimensional shape is a shape that has length, width and height. Examples of three dimensional shapes are cone, cylinder, prism and pyramid.
A two dimensional shape is a shape that have both length and width. Examples of two dimensional shape are circle, rectangle, square.
The cube is a a three-dimensional solid object bounded by six square faces.
The three dimensional shape formed by the net shown below is a cube.
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4) One-fourth cup of yogurt contains 27.5 calories. How many calories are there in 3 1/2 cups of yogurt?
Answer:
385
Step-by-step explanation:
A two digit number has 6 more ones than tens. Twice the sum of the number and its reverse is 6 more than ten times the number. Find the number.
The number with the given characteristics is 17
How to determine the numbers?Let the tens be x and the units be y.
So, the number is 10x + y
The relationship between the digits is
y = x + 6
The relationship between the number and the reverse is
2(10x + y + 10y + x) = 6 + 10 * (10x + y)
Simplify the second equation
2(11x + 11y) = 6 + 100x + 10y
Open the brackets
22x + 22y = 6 + 100x + 10y
Substitute y = x + 6
22x + 22(x + 6) = 6 + 100x + 10(x + 6)
Expand
22x + 22x + 132 = 6 + 100x + 10x + 60
Collect like terms
22x + 22x - 100x - 10x = 6 + 60 - 132
Evaluate the like terms
-66x = -66
Divide by -66
x = 1
Substitute x = 1 in y = x + 6
y = 1 + 6
y = 7
Recall that the number is 10x + y
So, we have
Number = 10 * 1 + 7
Evaluate
Number = 17
Hence, the number is 17
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BECKY KUBIAK WISHES TO PURCHASE NEW APPLICANCES FOR HER HOME. THE
TOTAL COST FOR THE APPLICANCES IS $2900. TO FINANCE THE PURCHASE, BECKY
MUST PAY 20% DOWN, WITH THE BALANCE BEING FINANCED WITH A 24-MONTH
INSTALLMENT LOAN WITH AN APR OF 8.5%. DETERMINE BECKY’S TOTAL FINANCE
CHARGE AND HER MONTHLY PAYMENT.?
Using the monthly payment formula, it is found that:
Her monthly payments are of $105.46.The total finance charge is of $3,111.04.What is the monthly payment formula?It is given by:
[tex]A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}[/tex]
In which:
P is the initial amount.r is the interest rate.n is the number of payments.Considering that she must pay 20% down, the parameters are given by:
P = 0.8 x 2900 = 2320, r/12 = 0.085/12 = 0.007083, n = 24.
Hence the monthly payments are found as follows:
[tex]A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}[/tex]
[tex]A = 2320\frac{0.007083(1.007083)^{24}}{(1.007083)^{24} - 1}[/tex]
A = $105.46.
The total finance charge is composed by the down payment plus the 24 monthly payments, hence:
F = 0.2 x 2900 + 24 x 105.46 = $3,111.04.
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PLEASE HELP ME WITH THIS QUESTION ASAPP
Answer:
Trapezoid
Step-by-step explanation:
One pair of parallel sides.