2C2H2(g)+5O2(g)=4CO2(g)+2H2O(g)

How many liters of C2H2 are required to product 12.0 moles CO2, assuming the reaction is at STP?

The element magnesium is often in fireworks because it burns with bright white light. It adds white sparks and hence, improves the overall brilliance of a firework.

The reaction is as follows:

                        [tex]2Mg (s) + O_2 (g) \rightarrow 2MgO(s) + energy[/tex]

The reaction is exothermic in nature.

                        [tex]Mg(s)+ 2H_2O \rightarrow Mg(OH)_2(s) + H_2 (g)[/tex]

                        [tex]Mg(s)+CO_2 \rightarrow 2MgO(s)+ C(s)[/tex]

As magnesium is highly flammable and burns with white bright light, hence it is used in fireworks to improve its overall experience.

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in the periodic tables

elements in the same column have the same charge

in a compound oxidation numbers have to equal 0

1.

sulfur in Li2SO3

charges :

Li = +1 S = +4 O = -2

multiply the charge with the subscripted number next to the element

Li = +1

Li2 = +2

O = -2

O3 = -8

in a compound oxidation numbers have to equal 0

+2 S -6 = 0

S -4 = 0

S = +4

Sulfur = +4

2.

MgCl2

Mg = +2

+2 Cl2 = 0

Cl2 = -2

Cl by itself = -2 divided by 2 = -1

Chlorine  = -1

3.

SiO2

Silicon = +4

4.

Sulfur in H2SO4

H: +1 S: +6 O: -2

H2SO4

H2 : +2 O4: -8

+2 +S -8 = 0

S - 6 = 0

S = +6

Sulfur = +6

5.

Sulfur in SO4^2-

Sulfur in SO4

Sulfur = +4

6.

Manganese in MnO4^-

Manganese in MnO4

Manganese = +4

7.

Cr2O7^2-

Dichromate

Cr in Cr2O7^2- or Cr2O7-2-

Cr: +6 O: -2

The enthalpy change of the reaction is -44.79 kJ/mol.

We can define the enthalpy change as the energy that is given out or taken in in a reaction. it can be calculated from the enthalpies of formation of species by the use of the relation;

ΔH = ∑Enthalpy of formation of products -  ∑Enthalpy of formation of reactants

ΔHfC2H4(g) = +52kJ/mol

ΔHf H2O(g) = - 241.82 kJ/mol

ΔHf CH3CH2OH(g)= -234.61 kJ/mol

ΔHrxn  = (-234.61) - [52 + (- 241.82 )]

ΔHrxn  = (-234.61) - (-189.82)

ΔHrxn  = -44.79 kJ/mol

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The value 6.0 x 10^3- 2.3 × 10^3 in scientific notation is 3.7 × 10^3.

Scientific notation is a way to write very large or very small numbers so that they are easier to read and work with.

You express a number as the product of a number greater than or equal to 1 but less than 10 and an integral power of 10 .

There are two reasons to use scientific notation.

Given,

= 6.0 x 10^3- 2.3 × 10^3

= (6.0 - 2.3) × 10^3

= 3.7 × 10^3

Thus, we find that the value 6.0 x 10^3- 2.3 × 10^3 in scientific notation is 3.7 × 10^3.

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Molality of C2H5OH is 1.1.27m.



What is Molality?

Molality is no.of moles present in One Kg solution .

Molality is represented by m

m= no.of moles/ weigt of solution in kg

Given is Molarity= 51.30M

molar mass of C2H5OH is 46g / mol , Density =0.9349g/ ml

Density=m/V

V = 107 ml

Molarity= no of moles/ Volume

51.5×46×107= x × 1000

weight of C2H5OH = 27.7g

molality = 27.7/1000××46

m= 1.27m

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Answer:

1 x 10⁻¹¹ M

Explanation:

(Step 1)

Determine the pH.

pH = -log[H⁺]

pH = -log[1 x 10⁻³ M]

pH = 3

(Step 2)

Determine the pOH.

pH + pOH = 14

3 + pOH = 14

pOH = 11

(Step 3)

Determine the hydroxide (OH⁻) concentration.

[OH⁻] = 10^-pOH

[OH⁻] = 10⁻¹¹

[OH⁻] = 1 x 10⁻¹¹ M

Answer:

B.) 129.9 grams

Explanation:

To find the mass, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

The specific heat of copper is 0.385 J/g°C. Knowing this, you can plug the given values into the equation and simplify to isolate "m".

Q = mcΔT                                                            <----- Equation

5000 J = m(0.385 J/g°C)(200 °C - 100 °C)        <----- Insert values

5000 J = m(0.385 J/g°C)(100)                            <----- Subtract

5000 J = m(38.5)                                                <----- Multiply 0.385 and 100

129.9 = m                                                             <----- Divide both sides by 38.5

Answer:

the answer is A

Explanation:

The weak ionization constant (Ka) for HNO₂ is:

[tex]\displaystyle K_a = \frac{[H^+][NO_2^-]}{HNO_2}[/tex]

Acid-ionization constant Ka can be described as a quantitative measure of the strength of an acid in solution. It can be represented as the equilibrium constant for a chemical reaction:

[tex]{\displaystyle {\ce {HA \longrightarrow A^- + H^+}}}[/tex]

The chemical species HA can dissociate into A⁻ the conjugate base of the acid and a hydrogen ion, H⁺. In equilibrium, when the concentrations will not change over time, because both forward and backward reactions have the same rate.

The ionization constant can be described as the ratio of products and reactants raised to stoichiometric powers.

The dissociation constant is defined as:

[tex]{\displaystyle K_{\text{a}}=\mathrm {\frac {[A^{-}][H^{+}]}{[HA]}} }[/tex]

Given the dissociation of the HNO₂ as follows:

HNO₂  ⇄  H⁺ + NO₂⁻

The weak ionization constant (Ka) for HNO₂  is equal to:

[tex]\displaystyle K_a = \frac{[H^+][NO_2^-]}{[HNO_2]}[/tex]

Therefore, option A is correct.

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Answer:

hydrogen bonding

Explanation:

I just think it is I am not sure

Answer: C. Dipole-dipole interactions.

Answer:

15 is not a correct scientific measurement.

Explanation:

Is this helpful for You

Answer:

D. 1kg Aluminium

Explanation:

First of all, you have to know that you were given two quantities, volume and mass.

The relationship between both quantities is given by the formula of density which is:

Density = Mass / Volume

Volume = Mass / Density

Since mass is constant, it means that the volume is inversely proportional to the density.

Volume = k / Density where k is a constant.

This means that the substance with the lowest density would have the highest volume and the one with the highest density would have the highest lowest.

The density of the substances are given as:

Lead = 11.2

Iron = 7.874

Gold = 19.3

Aluminium = 2.7

This means that Aluminium would have the highest volume as its the least dense.

∆H for given reaction -847kJ

So

2 mol of Al releases 847KJ heat

4 mol Al releases

∆H=-1694KJ

It is given that the energy released during the reaction of 2 moles of Al metal is - 847 KJ. The n the heat energy released by 4 moles of Al will be - 1694 KJ.

The enthalpy change of a reaction is the heat energy absorbed or released by a reaction. For an endothermic reaction, the heat energy is absorbed and the enthalpy change is positive. For an exothermic reaction, where the energy is released, the enthalpy change will be negative.

The heat energy change during a reaction is equal to the product of mass, specific heat and temperature difference of the substanc eunder reaction or phase transition.

Given that, the heat evolved by 2 moles of Al is - 847 kJ. Then, the heat evolved when 4 moles of Al reacted is calculated as follows:

(4 × - 847) / 2 = - 1694 KJ.

Therefore, the heat energy released is  - 1694 KJ.

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The three disadvantages of hard water are:

1. Hard water is unsuitable for washing because soap does not readily create a lather in it.

2. Soap may react and produce, wasting the soap.

3. Due to the development of calcium and magnesium carbonates, tea kettles will get furred.

Water that contains a lot of minerals is referred to as hard water. In limestone, chalk, or gypsum deposits, which are mostly composed of calcium and magnesium carbonates, bicarbonates, and sulphates, hard water is created as a result of percolation. A moderate health advantage from drinking hard water is possible. In industrial settings where water hardness is regulated to prevent expensive breakdowns in boilers, cooling towers, and other water-handling equipment, it can present serious issues. Hard water is frequently detected in home settings by the build-up of lime scale in kettles and water heaters as well as by the absence of foam when soap is agitated in water. Wherever there is a worry about water hardness, water softening is frequently employed to lessen the negative impacts of hard water.

write three disadvantages of hard water.​

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Answer:

2.56 moles

Explanation:

7.2 M is 7.2 moles/L

356 mL = .356 Liters

x moles / .356 Liters = 7.2 M (moles/L)

x = .356 * 7.2 = 2.5632 moles

Answer:

9.89 x 10²³ molecules H₂S

Explanation:

To find the molecules of H₂S, you need to (1) convert grams S to moles S (via the atomic mass of sulfur), then (2) convert moles S to moles H₂S (via the mole-to-mole ratio from equation coefficients), and then (3) convert moles H₂S to molecules H₂S (via Avogadro's Number). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.

Atomic Mass (S): 32.065 g/mol

2 H₂S(s) + SO₂(g) -----> 3 S(s) + 2 H₂O(l)

Avogadro's Number:

6.022 x 10²³ molecules = 1 mole

79.0 g S           1 mole            2 moles H₂S          6.022 x 10²³ molecules
---------------  x  ---------------  x  ----------------------  x  -------------------------------------  =
                        32.065 g            3 moles S                          1 mole

=  9.89 x 10²³ molecules H₂S

Answer:

Sulfur

Explanation:

In general, elements are more reactive the more electronegative they are. The most electronegative elements are at the top-right of the periodic table. Since sulfur (S) is one unit up and one unit to the right of arsenic (As), it is considered more electronegative, and therefore more reactive, than arsenic.

Answer:

Refer to the attached page,

I've done the calculation over there

The best way to represent the concentration of a 1.75 M K2CrO4 solution is 1.75% K2CrO4 (option A).

Molarity is the concentration of a substance in solution, expressed as the number moles of solute per litre of solution.

The molarity is a measure of the concentration of a chemical species, in particular of a solute in a solution, in terms of amount of substance per unit volume of solution.

The molarity is measured in mol/L or M, hence, it can be said that the molarity of a solution is 0.1M.

However, the concentration of a solution is best represented by using %. In accordance with this question, the best way to represent the concentration of a 1.75 M K2CrO4 solution is 1.75% K2CrO4.

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The equilibrium constant of a reaction, [tex]K_{c}[/tex]  = 6.44 * 10⁵; option C.

Equilibrium constant, [tex]K_{c}[/tex] of a reaction is a measure of the ratio of the equilibrium concentration of the products of a reaction, to the equilibrium concentration of the reactants; with each concentration raised to the exponent corresponding to the coefficient in the balanced equation of the reaction.

[tex]K_{c} = \frac{(products)^{a}}{(reactants)^{b}}[/tex]

The balanced equation of the given reaction is as follows:

The concentrations at equilibrium of the species are as follows:

[NO] = 0.0542 M,

[O₂] = 0.127 M, and

[NO₂] = 15.5 M

Equilibrium constant, [tex]K_{c}[/tex] = (15.5)²/(0.127) * (0.0542)²

[tex]K_{c}[/tex]  = 6.44 * 10⁵

In conclusion, the equilibrium constant of a reaction, tells on in which direction, the reaction is favored at equilibrium.

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A. The balanced chemical reaction of Sodium metal and Water is 2Na  +  2H₂O  →  2NaOH    +   H₂.

A balanced equation contains the same number of each type of atoms on both the left and right sides of the reaction arrow.

Sodium metal reacts rapidly with water to form a colourless solution of sodium hydroxide (NaOH) and hydrogen gas (H2).

The balanced chemical reaction is written below;

2Na  +  2H₂O  →  2NaOH    +   H₂

Thus, the balanced chemical reaction of Sodium metal and Water is 2Na  +  2H₂O  →  2NaOH    +   H₂.

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Answer:

0.429 M

Explanation:

To find the molarity, you need to (1) convert grams to moles (using the molar mass), then (2) convert mL to L, and then (3) calculate the molarity (using the molarity ratio).

(Step 1)

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

18.8 grams NaCl               1 mole
--------------------------  x  ------------------------  =  0.322 moles NaCl
                                     58.443 grams

(Step 2)

1,000 mL = L

 750.0 mL                1 L
------------------  x  -----------------  =  0.7500 L
                            1,000 mL

(Step 3)

Molarity (M) = moles / volume (L)

Molarity = 0.332 moles / 0.7500 L

Molarity = 0.429 M

Answer:

23.55 L

Explanation:

USe the following 'identity' of gs laws

P1 V 1 / T1 = P2 V2 / T2         ( T must be in Kelvin)

re arrange to

P1 V 1  T2  /  (T1 P2)   = V2       NOW SUB IN THE VALUES

752 * 34.2 * ( 34 + 273.15) / [( 229 + 273.15) * 668]   = V2 = 23.55 L

Answer:

52.07 L H₂

Explanation:

Before you can find the volume of H₂, you need to find the moles of H₂. To do this, you need to (1) convert grams Mg to moles (via the atomic mass) and then (2) convert moles Mg to moles H₂ (via the mole-to-mole ratio from equation coefficients).

Atomic Mass (Mg): 24.30 g/mol

1 Mg(s) + 2 HCl(aq) ---> MgCl₂(aq) + 1 H₂(g)
^                                                         ^

56.49 g Mg           1 mole               1 mole H₂
-------------------  x  -----------------  x  --------------------  =  2.32 moles H₂
                              24.30 g            1 mole Mg

Now that you know the moles of H₂, you need to determine the volume at STP. To do this, you need to set up a proportion comparing the mole value versus the volume. Then, you can cross-multiply to solve for the unknown volume. The final answer should have 4 sig figs to match the given values.

 1 mole            2.32 moles
--------------  =  --------------------                      <----- Set up proportion
  22.4 L                 ? L

(1 mole) x ? L = 52.07                                 <----- Cross-multiply

? L = 52.07                                                <----- Divide both sides by 1 mole

Answer:

The volume of the gas sample at standard pressure is 819.5ml

Explanation:

Solution Given:

let volume be V and temperature be T and pressure be P.

[tex] V_1=250ml[/tex]

[tex] V_2=?[/tex]

[tex] P_{total}=735 mmhg[/tex]

1 torr= 1 mmhg

42.2 torr=42.2 mmhg

so,

[tex] P_{water}=42.2mmhg[/tex]

[tex] T_1=35°C=35+273=308 K[/tex]

Now

firstly we need to find the pressure due to gas along by subtracting the vapor pressure of water.

[tex] P_{gas}=P_{total}-P_{water} [/tex]

=735-42.2=692.8 mmhg

Now

By using combined gas law equation:

[tex]\frac{P_1*V_1}{T_1} =\frac{P_2*V_2}{T_2}[/tex]

[tex]V_2=\frac{P_1*}{P_2}*\frac{T_2}{T_1} *V_1[/tex]

[tex]V_2=\frac{P_gas}{P_2}*\frac{T_2}{T_1} *V_1[/tex]

Here [tex]P_2 \:and\: T_2[/tex] are standard pressure and temperature respectively.

we have

[tex]P_2=750mmhg \:and\: T_2=273K[/tex]

Substituting value, we get

[tex]V_2=\frac{692.8}{750}*\frac{273}{308} *250[/tex]

[tex]V_2= 819.51 ml[/tex]

The statement that is a part of Kinetic Molecular Theory (KMT) is Molecules in a gas move rapidly. That is option B.

Kinetic Molecular Theory (KMT) is defined as the theory that describes the physical behaviour of gases.

The Kinetic Molecular Theory (KMT) include the following:

Therefore, the statement that is a part of Kinetic Molecular Theory (KMT) is Molecules in a gas move rapidly.

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Answer:

B.) [tex]K_{eq} = \frac{[SO_3][NO]}{[SO_2][NO_2]}[/tex]

Explanation:

The general equilibrium expression looks like this:

[tex]K_{eq} = \frac{[C]^c[D]^d}{[A]^a[B]^b}[/tex]

In this expression,

-----> K = equilibrium constant

-----> uppercase letters = formulas

-----> lowercase letters = balanced equation coefficients

The products are in the numerator and the reactants are in the denominator. Since all of the molecules are gases, they should all be included in the expression. Since the coefficients in the balanced equation are all 1, they do not need to be represented in the expression.

The equilibrium constant expression is:

[tex]K_{eq} = \frac{[SO_3][NO]}{[SO_2][NO_2]}[/tex]

Answer:

they're both completely different games

Explanation:

Answer: uh.. tricky

Explanation:

Answer:

Explanation:

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Answer:

1.) 17.76 moles H₂O

2.) 323.1 g HCN

Explanation:

1.) An equation is balanced when there is an equal amount of each element on both sides of the reaction. The quantities can be modified by adding coefficients in front of the molecules.

The unbalanced equation:

Al₄C₃(s) + H₂O -----> Al(OH)₃(s) + CH₄(g)

Reactants: 4 aluminum, 3 carbon, 2 hydrogen, 1 oxygen

Products: 1 aluminum, 1 carbon, 7 hydrogen, 3 oxygen

The balanced equation:

Al₄C₃(s) + 12 H₂O -----> 4 Al(OH)₃(s) + 3 CH₄(g)

Reactants: 4 aluminum, 3 carbon, 24 hydrogen, 12 oxygen

Products: 4 aluminum, 3 carbon, 24 hydrogen, 12 oxygen

Now that the equation is balanced, you can use the relevant coefficients to construct a mole-to-mole ratio. This will allow you to convert between moles Al₄C₃ to moles H₂O.

 1.48 moles Al₄C₃           12 moles H₂O
----------------------------  x  ------------------------  =  17.76 moles H₂O
                                         1 mole Al₄C₃

2.) To find the mass of HCN, you need to (1) convert grams NH₃ to moles NH₃ (via molar mass), then (2) convert moles NH₃ to moles HCN (via mole-to-mole from equation coefficients), and then (3) convert moles HCN to grams HCN (via molar mass). It is important to arrange the coefficients in a way that allows for the cancellation of units.

Molar Mass (NH₃): 14.009 g/mol + 3(1.008 g/mol)

Molar Mass (NH₃): 17.033 g/mol

Molar Mass (HCN): 1.008 g/mol + 12.011 g/mol + 14.009 g/mol

Molar Mass (HCN): 27.028 g/mol

2 CH₄(g) + 3 O₂(g) + 2 NH₃(g)  ------> 2 HCN(g) + 6 H₂O(g)

203.6 g NH₃            1 mole            2 moles HCN           27.028 g
---------------------  x  ----------------  x  ------------------------  x  -----------------  =
                                17.033 g           2 moles NH₃             1 mole

=  323.1 g HCN