Answer:
C
Step-by-step explanation:
Which of the following is the solution to the inequality below? 9 - 3x >= 2(x - 3) A . x <= 15 B. x >= 15 C. x >= 3 D. x <= 3
Answer: [tex]x \leq 3[/tex]
Step-by-step explanation:
[tex]9-3x \geq 2(x-3)\\\\9-3x \geq 2x-6\\\\15-3x \geq 2x\\\\15 \geq 5x\\\\3 \geq x\\\\x \leq 3[/tex]
Find (g*f)(3)
f(x)= 7x + 8
g(x)= -1/x
Answer:
-21-24/x
Step-by-step explanation:
f(x) is a function on his own which is f(x)=7x+8
we multiple it with another function which is g(x)=-1/x
that gives us (g*f)=-7-8/x
then multiple it by 3 we have -21-24x
Which choice is equivalent to the expression below?
√6 +2√√3+√27-√12
A. 53-6
OB. 2√3-√21
OC. 3√3+√6
OD. 5√3
The Evaluating expression √6 +√6+√27-√12 become √3(2√2+ 1) after simplification.
According to the statement
We have given that one evaluating expression which is √6 +√6+√27-√12
And we have to simplify this expression by evaluating it.
So, Given expression is:
√6 +√6+√27-√12
√6 +√6+√(9*3)-√(4*3)
√6 +√6+3√(3)-2√(3)
√6 +√6+√3( 3-2)
After evaluating the expression it become
√6 +√6+√3(1)
√(3*2) +√(3*2) +(1)√3
Take common from above expression then
√3(√2 +√2 ) +√3
√3(2√2) +√3
√3(2√2+ 1)
Now the expression √6 +√6+√27-√12 become √3(2√2+ 1) after simplification.
So, The Evaluating expression √6 +√6+√27-√12 become √3(2√2+ 1) after simplification.
Disclaimer: This question was incomplete. Please find the full content below.
Question:
Which choice is equivalent to the expression below?
√6 +√6+√27-√12
A. √3(2√2+ 1)
B. 2√3-√21
C. 3√3+√6
D. 5√3
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Two regular 6-sided dice are tossed. Compute the probability that the sum of the pips on the upward faces of the 2 dice is the following. 8
Answer: 5/36
Step-by-step explanation:
Attached as an image. Please help.
The general solution of the logistic equation is y = 14 / [1 - C · tⁿ], where a = - 14² / 3 and C is an integration constant. The particular solution for y(0) = 10 is y = 14 / [1 - (4 / 10) · tⁿ], where n = - 14² / 3.
How to find the solution of an ordinary differential equation with separable variablesHerein we have a kind of ordinary differential equation with separable variables, that is, that variables t and y can be separated at each side of the expression prior solving the expression:
dy / dt = 3 · y · (1 - y / 14)
dy / [3 · y · (1 - y / 14)] = dt
dy / [- (3 / 14) · y · (y - 14)] = dt
By partial fractions we find the following expression:
- (1 / 14) ∫ dy / y + (1 / 14) ∫ dy / (y - 14) = - (14 / 3) ∫ dt
- (1 / 14) · ln |y| + (1 / 14) · ln |y - 14| = - (14 / 3) · ln |t| + C, where C is the integration constant.
y = 14 / [1 - C · tⁿ], where n = - 14² / 3.
If y(0) = 10, then the particular solution is:
y = 14 / [1 - (4 / 10) · tⁿ], where n = - 14² / 3.
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AN ARTICLE STATED THAT “INTERNAL SURVEYS PAID FOR BY DIRECTORY ASSISTANCE PROVIDERS SHOW THAT EVEN THE MOST ACCURATE COMPANIES GIVE OUT WRONG NUMBERS 15% OF THE TIME.” ASSUME THAT YOU ARE TESTING SUCH A PROVIDER BY MAKING 10 REQUESTS AND ALSO ASSUME THAT THE PROVIDER GIVES THE WRONG TELEPHONE NUMBER 15% OF THE TIME. FIND THE PROBABILITY OF GETTING ONE WRONG NUMBER.
Using the binomial distribution, there is a 0.3474 = 34.74% probability of getting one wrong number.
What is the binomial distribution formula?The formula is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.For this problem, the values of the parameters are given by:
p = 0.15, n = 10.
The probability of getting one wrong number is P(X = 1), hence:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
P(X = 1) = C(10,1) x (0.15)¹ x (0.85)^9 = 0.3474
0.3474 = 34.74% probability of getting one wrong number.
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If log103 0.4771,
evaluate log100.0003.
Round your answer to four decimal
places.
Answer:
log(0.0003) = -3.5229
Step-by-step explanation:
The rules of logarithms tell you ...
log(ab) = log(a) +log(b)
Applicationlog(0.0003) = log(3×10^-4) = log(3) +log(10^-4)
= log(3) -4 = 0.4771 -4
log(0.0003) = -3.5229
__
Additional comment
If you do much work with logarithms, you find that negative logarithms are generally expressed using a positive mantissa with a negative add-on. Often, that negative add-on is -9, so this would be ...
5.4771-9
This helps when taking antilogs, as you look up 0.4771 in the table to see that the multiplier is 3.
If you were to look up 0.5229, you would find 3.333, meaning the multiplier is 1/3.333 and the antilog of -3.5229 is (10^-3)/3.333. This may not be a convenient value to work with.
What is the multiplicative rate of change of the function? which answer is it? These are the options 1/5, 2/5, 2, or 5
A store is having a 20% off sale. The sale price of an item with price p is p - 0.2p. What is an equivalent expression.
what’s the approximate value of tan 1
Answer: tan 1 radians = 1.557, tan 1 degrees = 0.017
Although all of the following systems can be solved via the substitution method, substitution would be the best method for solving which system.
Group of answer choices
Using the substitution method, the system of equation that is easily solved is:
c. y = 2x + 3
2x + y = 5
How to Solve A System of Equations Using the Substitution Method?Using the substitution method to solve a system of equations is best when one of the equations have one isolated variable that we can simply plug its value into the second equation.
For example, given the system of equations:
y = 2x + 3 --> eqn. 1
2x + y = 5 --> eqn. 2
Substitute y = (2x + 3) into eqn. 2 and find x:
2x + y = 5 --> eqn. 2
2x + 2x + 3 = 5
4x + 3 = 5
4x = 5 - 3
4x = 2
x = 2/4
x = 1/2
Substitute x = 1/2 into eqn. 1 to find y
y = 2x + 3 --> eqn. 1
y = 2(1/2) + 3
y = 1 + 3
y = 4
From the above, we can see that the system of equations that is quite easy to solve using the substitution method is:
c. y = 2x + 3
2x + y = 5
The rest of the equations are quite different and not as straightforward as solving as this using the substitution method.
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need heeeelp please
Answer:
4[tex]v^{7}[/tex]x³(7[tex]y^{6}[/tex] - 3v²[tex]x^{6}[/tex])
Step-by-step explanation:
28[tex]v^{7}[/tex]x³[tex]y^{6}[/tex] - 12[tex]v^{9}[/tex][tex]x^{9}[/tex] ← factor out 4[tex]v^{7}[/tex]x³ from each term
= 4[tex]v^{7}[/tex]x³(7[tex]y^{6}[/tex] - 3v²[tex]x^{6}[/tex])
Which of the following is not irrational? (a) (2-√3)2 (b)(√2+√3)2 (c) (√2-√3)(√2+√3) (d)27√7
Answer: (c)
(√2-√3)(√2+√3)
Step-by-step explanation:
An irrational number is one that cannot be expressed as the ratio of two integers. In other words it cannot be expressed as [tex]\frac{x}{y}[/tex] where x and y are integers
[tex]\sqrt{2}[/tex] is irrational
[tex]\sqrt{3}[/tex] is irrational
In fact the square root of any prime number is irrational. So [tex]\sqrt{5}[/tex], [tex]\sqrt{7}[/tex] etc are irrational. But [tex]\sqrt{9}[/tex] is not irrational since it evaluates to 3 which can be expressed as [tex]\frac{3}{1}[/tex]
Any expression that contains the square root of a prime number is also irrational
Looking at the choices we see that choices (a), (b) and (d) all evaluate to expressions containing square roots of primes
(a) (2-√3)2 = 4 - 2√3 . Hence irrational
(b) √2+√3)2 = 2√2+2√3. Hence irrational
(d) 27√7 is irrational
Let's look at choice (c)
(√2-√3)(√2+√3)
An expression [tex](a+b)(a-b)[/tex] can be evaluated as [tex]a^{2} - b^{2}[/tex]
Here a = √2, [tex]a^{2}[/tex] =[tex]a = \sqrt{2}\\ a^2 = (\sqrt{2} )^2 = 2\\\\b = \sqrt{3} \\b^2 = (\sqrt{3} )^2 = 3\\\\a^2 - b^2 = 2-3 = -1\\[/tex]
This is a whole number(integer) and all integers are rational numbers
Hence correct answer is (c)
Set W consists of the even whole numbers from 2 to 20, inclusive. If a number is selected at random from set W, then what is the probability that the number is a
multiple of 4 and also a multiple of 6?
Answer:
1/19
Step-by-step explanation:
The number in the set that are a multiple of both 4 and 6 is 12.
This is one number out of the 19 numbers in the set, so the probability is 1/19.
List these fractions from
least to greatest 3/8 5/8 4/8 2/8 7/8
Answer: 2/8, 3/8, 4/8, 5/8, 7/8
Step-by-step explanation:
Since they all have a common denominator, we can list them based on their numerator without having to worry about the denominator.
2/8 < 3/8 < 4/8 < 5/8 < 7/8
what the difference between graphing lines and graphing inequalities?
what the difference between arithmetic and geometric ?
how do you explain using sigma notation ?
how to simplify into logarithmic?
Answer:
Step-by-step explanation:
graphing lines is just what it sounds like, you are taking the equation of the line and putting it on the graph. graphing inequalities shows the area of the coordinate plane that satisfies the inequality, it almost always splits the graph.
arithmetic: -6 , 1 , 8 , 15 , 22
geometric: 2 , 4 , 8 , 16, 32
NO LINKS!! Please help me with this problem
[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
The given figure shows a vertical hyperbola with its centre at origin, and as we observe the figure, we can conclude that :
Length of transverse axis is :
[tex]\qquad \sf \dashrightarrow \: 2b = 12[/tex]
[tex]\qquad \sf \dashrightarrow \: b = 6[/tex]
length of conjugate axis is :
[tex]\qquad \sf \dashrightarrow \: 2a = 8[/tex]
[tex]\qquad \sf \dashrightarrow \: a = 4[/tex]
Equation of hyperbola ~
[tex]\qquad \sf \dashrightarrow \: \cfrac{ {y}^{2} }{ {b}^{2} } - \cfrac{ {x}^{2} }{ {a}^{2} } = 1[/tex]
plug in the values ~
[tex]\qquad \sf \dashrightarrow \: \cfrac{ {y}^{2} }{ {6}^{2} } - \cfrac{ {x}^{2} }{ {4}^{2} } = 1[/tex]
[tex]\qquad \sf \dashrightarrow \: \cfrac{ {y}^{2} }{ {36}^{} } - \cfrac{ {x}^{2} }{ {16}^{} } = 1[/tex]
Answer:
[tex]\dfrac{y^2}{36}-\dfrac{x^2}{16}=1[/tex]
Step-by-step explanation:
Standard form equation of a vertical hyperbola
[tex]\dfrac{(y-k)^2}{a^2}-\dfrac{(x-h)^2}{b^2}=1[/tex]
where:
center = (h, k)vertices = (h, k±a)co-vertices = (h±b, k)foci = (h, k±c) where c² = a² + b²[tex]\textsf{asymptotes}: \quad y =k \pm \left(\dfrac{a}{b}\right)(x-h)[/tex]Transverse axis: x = hConjugate axis: y = kFrom inspection of the graph:
center = (0, 0) ⇒ h = 0, k = 0vertices = (0, 6) and (0, -6) ⇒ a = 6co-vertices = (4, 0) and (-4, 0) ⇒ b = 4Substitute the found values into the formula:
[tex]\implies \dfrac{(y-0)^2}{6^2}-\dfrac{(x-0)^2}{4^2}=1[/tex]
[tex]\implies \dfrac{y^2}{36}-\dfrac{x^2}{16}=1[/tex]
Simplify each expression. Select the correct answer from the drop-down menu.
−6(3i)(−2i) =
2(3 − i)(−2 + 4i) =
Answer:
Step-by-step explanation
-6(3i)(-2i)=-6(3i*-2i)=-6*-6i²=36i²
2(3-i)(-2+4i)=(6-2i)(-2+4i)=-12+24i+4i-8i²=-8i²+28i-12
Answer:
1. -36
2. -4+28i
3. 10+8i
Step-by-step explanation:
EDGE2022
Divide. write your answer in simplest form. 7/9 divided by 8/15
Answer:
Step-by-step explanation:
7/9 * 15/8 = 105/72 = 35/24
Please help me with this question!!!!,
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
The contrapositive of the statement is False.
Because we already know, Cube is a 3 - dimensional shape with 6 faces, all its sides are equal and all faces are congruent.
But the contrapositive of the statement is not true, because not only cube has six faces.
There are other 3 - D shapes that have 6 faces.
[tex] \qquad \large \sf {Conclusion} : [/tex]
The contrapositive of the statement is false.
If f ( x ) = x 2 and g ( x )= 2x - 2,
find f ( g ( 7 ) )
Answer:
144
Step-by-step explanation:
First find g(7) --
[tex]g(7)=2(7)-2\\=14-2\\=12[/tex]
Then plug 12 into f(x) --
[tex]f(12)=(12)^{2} \\=144[/tex]
8x+4y=7
6x-8y=41
using ELIMINATION METHOD
Answer:
([tex]\frac{5}{2}[/tex] , - [tex]\frac{13}{4}[/tex] )
Step-by-step explanation:
8x + 4y = 7 → (1)
6x - 8y = 41 → (2)
multiplying (1) by 2 and adding to (2) will eliminate y
16x + 8y = 14 → (3)
add (2) and (3) term by term to eliminate y
22x + 0 = 55
22x = 55 ( divide both sides by 22 )
x = [tex]\frac{55}{22}[/tex] = [tex]\frac{5}{2}[/tex]
substitute this value into either of the 2 equations and solve for y
substituting into (1)
8([tex]\frac{5}{2}[/tex] ) + 4y = 7
20 + 4y = 7 ( subtract 20 from both sides )
4y = - 13 ( divide both sides by 4 )
y = - [tex]\frac{13}{4}[/tex]
solution is ( [tex]\frac{5}{2}[/tex] , - [tex]\frac{13}{4}[/tex] )
Write an inequality for the following statement, 1 is greater than x
The inequality suitable if 1 is greater than x is x<1.
Given that 1 is greater than x.
We are required to form an inequality which shows that 1 is greater than x.
Inequality is like an equation showing relationship between two or more variables.It is mostly not found in equal to form.
It shows the range of quantities.
When 1 is greater than x means the greater than sign will be used for 1 not x and the inequality will be as under:
x<1
We have not used equal to sign because 1 is greater than x not equal to x.
Hence the inequality suitable if 1 is greater than x is x<1.
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need heeeelp please
Answer:
please how
Step-by-step explanation:
I will help ypu
50 POINTS PLEASE HELP I NEED ANWSER NOW what would the reflection look like
Answer:
Point C will be at (3,1), Point B will be at (7,1) and Point A will be at (7,5)
Step-by-step explanation:
100 000 , 10 000 , 1000 , 100 , A , B
The two missing numbers in the pattern are:
A=___?
B=___?
The two missing numbers in the pattern are 10 and 1
How to determine the missing numbers?The sequence is given as:
100 000 , 10 000 , 1000 , 100 , A , B
From the above sequence, the next term is the quotient of the current term and 10.
So, we have:
A = 100/10 = 10
B = A/10 = 10/10 = 1
Hence, the two missing numbers in the pattern are 10 and 1
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The points
(−1.2,2.9) and (2.9,9.46) are on the graph of a linear relationship between two variables, x and y
Write a formula that expresses
y in terms of x
What is the value of y when x=115
[tex](\stackrel{x_1}{-1.2}~,~\stackrel{y_1}{2.9})\qquad (\stackrel{x_2}{2.9}~,~\stackrel{y_2}{9.46}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{9.46}-\stackrel{y1}{2.9}}}{\underset{run} {\underset{x_2}{2.9}-\underset{x_1}{(-1.2)}}}\implies \cfrac{6.56}{2.9+1.2}\implies \cfrac{6.56}{4.1}\implies 1.6[/tex]
[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2.9}=\stackrel{m}{1.6}(x-\stackrel{x_1}{(-1.2)}) \\\\\\ y-2.9=1.6(x+1.2)\implies y-2.9=1.6x+1.92\implies \boxed{y=1.6x+4.82} \\\\\\ \textit{when x = 115, what is "y"?}\qquad y=1.6(115)+4.82\implies y=188.82[/tex]
please help this is affecting my grade pls help i beg of you <3
Answer:
C - On the number line, move 3 units to the left. End at -7. The dolphin was 7 feet below sea level.
Step-by-step explanation:
The dolphin's starting point was -4 (4 feet below sea level). If the dolphin if diving down by 3 feet, you add -3 to its starting point.
-4 + -3 = -7.
find the domain of the function expressed by the formula:
y=1/x-7
The domain of the function is x ≠ 7
How to determine the domain?The function is given as:
y = 1/x - 7
Set the denominator not equal to 0
x - 7 ≠ 0
Add 7 to both sides
x ≠ 7
Hence, the domain of the function is x ≠ 7
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1) The following scatterplot shows the percentage of the vote a candidate received in the 2016 senatorial elections
according to the voter's income level based on an exit poll of voters conducted by a news agency. The income
levels 1-8 correspond to the following income classes:
1 = Under $15,000; 2 = $15-30,000; 3 = $30-50,000; 4 = $50-75,000; 5 = $75-100,000;
6 = $100-150,000; 7 = $150-200,000; 8 = $200,000 or more.
Use the election scatterplot to determine whether there is a correlation between percentage of vote and income
level at the 0.01 significance level with a null hypothesis of ρs = 0.
A) The test statistic is between the critical values, so we fail to reject the null hypothesis. There is no
evidence to support a claim of correlation between percentage of vote and income level.
B) The test statistic is not between the critical values, so we fail to reject the null hypothesis. There is no
evidence to support a claim of correlation between percentage of vote and income level.
C) The test statistic is between the critical values, so we reject the null hypothesis. There is sufficient
evidence to support a claim of correlation between percentage of vote and income level.
D) The test statistic is not between the critical values, so we reject the null hypothesis. There is sufficient
evidence to support a claim of correlation between percentage of vote and income level
The answer to the question is B. The test statistic is not between the critical values, so we reject the null hypothesis. There is sufficient evidence to support a claim of correlation between percentage of vote and income level.
What is the scatter plot?This is the plot that shows the relationship between two different variables along a straight line. All of the points that are known to have a relationship between these variables would fall under this line. Other parts that fall outside the line are regarded as the outliers in the plot.
In this particular question, the outlier is seen to be outside of the critical values so we have to conclude that the solution is B. We fail to reject the null hypothesis.
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