Mrs. Oliver drew a box plot to represent her students’ scores on a mid-term test.

Did not understand "full working pliz".

The answers to the service charge rate are:

This is the number of calls for the help desk

160000/3200 = 50per call

For the network center

735000/9800

= 75 per device that was monitored

For the Electronic mail

100000/10000 =

10 for the mail account

For local voice support

124600/8900

= 14 per phone extension

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Answer:

y=1/4x-1/2

Step-by-step explanation:

The statements with their correct matches in relation to 0 are:

When a building is 37 feet tall, it means that if 0 feet was the ground level, the building would be 37 higher than 0. This is the same for the basement which will be -13.7 in relation to a ground level of 0.

Erica jumping 2.5 feet above the ground is 2.5 in relation to 0feet and the scuba driver is -37 by the same relation to 0 feet.

Oliver owes his sister $25 which means that in relation to a state of no debt or $0, Oliver is -25 deep in debt.

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Using linear functions, the inequality that represents when Gilberta has more wallpaper left in her room than María has in hers is: t < 5.

A linear function is modeled by:

y = mx + b

In which:

For this problem, we consider:

Hence the amounts Gilberta and Maria have left after t hours are given by:

Gilberta has more papers when:

G(t) > M(t).

Hence:

35 - 4.3t > 30.5 - 3.4t

-0.9t < -4.5

Multiplying by -1:

0.9t < 4.5

t < 4.5/0.9

t < 5.

Hence the inequality is:

t < 5.

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Answer:

t < 5

Step-by-step explanation:

Other dude is right but here's the version without explanation

In order to make 3 dimensional object to 4 dimensional object, it's important to draw the 4 dimensional shape in a way that gives the illusion of the 3 dimensional object.

It should be noted that shapes play an important part in geometry.

Here, to make make 3 dimensional object to 4 dimensional object, it's important to draw the 4 dimensional shape in a way that gives the illusion of the 3 dimensional object.

Also, it should be noted that a 4D tesseract can be used to project the image.

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Answer:

400 km

Step-by-step explanation:

Distance = rate times time

Distance = 80(5)

Distance = 400

Answer:

x = 4

Step-by-step explanation:

You can solve for "x" by rearranging the equation and getting the "x" by itself on one side. Remember, whatever you do to one side of the equation, you must do to the other side.

-6 + x = -2                         <----- Original equation
+6         +6                        <----- Add 6 to both sides to isolate "x"

0 + x = 4                           <----- After the addition

x = 4                                 <----- Rewrite

Answer:

None of the above (x = 4) [tex] \sf {} [/tex]

Step-by-step explanation:

Now we have to,

→ find the required value of x.

The equation is,

→ -6 + x = -2

Then the value of x will be,

→ -6 + x = -2

→ x = -2 + 6

→ [ x = 4 ]

Hence, the value of x is 4.

The reason why we used plus or minus when taking the square root is because; The square root of terms separated by addition and subtraction cannot be calculated individually.

The general formula for a quadratic equation is;

ax² + bx + c = 0

Now, the steps to derive quadratic formula to find the roots of this equation are as follows;

Step 1; Divide both sides of the equation by a to get;

x² + (b/a)x + c/a = 0

Step 2; Transpose the quantity c/a to the right side of the equation to get; x² + (b/a)x =  -c/a

Step 3; Complete the square by adding b²/4a² to both sides of the equation to get; x² + (b/a)x + b²/4a² =  -c/a + b²/4a²

Step 4; Factor the left side and combine the right side to get;

(x + (b/2a))² = (b² - 4ac)/(4a²)

Step 5:  Extract the square-root of both sides of the equation to get;

x + (b/2a) = ±(√(b² - 4ac))/2a

The reason why we used plus or minus when taking the square root is because The square root of terms separated by addition and subtraction cannot be calculated individually.

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Solution:

Let x be the number

Triple the number=3x

According to the question,

3x+5=50

⇒3x+5−5=50−5          [Subtract 5 from both sides]

⇒3x=45

⇒ x = 45/3

​           [Divide 3 from both sides]

⇒x=15

∴15 is the required number. When it is tripled and increased by 5, we get 50.

Answer:

Step-by-step explanation:

t(-7)= 3(-7)= -21

s(-21)= 2-(-21)= 2 + 21= 23

Answer:

[tex]21 \sqrt{2} [/tex]

Step-by-step explanation:

See attached image.

Using equivalent angles, the solutions are given as follows:

a) [tex]x = \frac{15\pi}{23}[/tex].

b) [tex]x = \frac{9\pi}{62}, x = \frac{53\pi}{62}[/tex].

c) [tex]x = \frac{3\pi}{8}, \frac{11\pi}{8}[/tex]

Each angle on the second, third and fourth quadrants will have an equivalent on the first quadrant.

For item a, we have to find the equivalent angle on the 2nd quadrant, where the sine is also positive.

Hence:

[tex]\pi - \frac{8\pi}{23} = \frac{23\pi}{23} - \frac{8\pi}{23} = \frac{15\pi}{23}[/tex]

Hence [tex]x = \frac{15\pi}{23}[/tex].

For item b, if two angles are complementary, the sine of one is the cosine of the other.

Complementary angles add to 90º = 0.5pi, hence:

[tex]x + \frac{11\pi}{31} = \frac{\pi}{2}[/tex]

[tex]x = \frac{31\pi}{62} - \frac{22\pi}{62}[/tex]

[tex]x = \frac{9\pi}{62}[/tex]

The equivalent angle on the second quadrant is:

[tex]\pi - \frac{9\pi}{62} = \frac{62\pi}{62} - \frac{9\pi}{62} = \frac{53\pi}{62}[/tex]

Hence the solutions are:

[tex]x = \frac{9\pi}{62}, x = \frac{53\pi}{62}[/tex]

For item c, the angles are also complementary, hence:

[tex]x + \frac{\pi}{8} = \frac{\pi}{2}[/tex]

[tex]x = \frac{4\pi}{8} - \frac{\pi}{8}[/tex]

[tex]x = \frac{3\pi}{8}[/tex]

The tangent is also positive on the third quadrant, hence the equivalent angle is:

[tex]x = \pi + \frac{3\pi}{8} = \frac{8\pi}{8} + \frac{3\pi}{8} = \frac{11\pi}{8}[/tex]

Hence the solutions are:

[tex]x = \frac{3\pi}{8}, \frac{11\pi}{8}[/tex]

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The sample proportion [tex]$\hat{p}=0.22+0.033=0.253$[/tex].

We know that the confidence interval for sample proportion exists estimated as;

90% confidence interval = Sample proportion  Margin of Error

Here, let [tex]$\hat{p}[/tex] = sample proportion

Level of significance = 1 - 0.90 = 0.[tex]$(0.22,0.28)=\hat{p} \pm 1.645 \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$[/tex]10 or 10% Critical value of z at 5% (two-sided) level of significance exists 1.645.

So, 90% confidence interval [tex]$=\hat{p} \pm 1.645 \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$[/tex]

[tex]$0.22=\hat{p}-1.645 \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \ldots(1)$[/tex]

[tex]$0.28=\hat{p}+1.645 \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \ldots (2)[/tex]

From (1) and (2) , we get;

[tex]$&0.22+1.645 \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}=0.28-1.645 \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \\[/tex]

Simplifying the equation, we get

[tex]$&1.645 \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}+1.645 \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}=0.28-0.22 \\[/tex]

[tex]$&2 \times 1.645 \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}=0.06 \\[/tex]

[tex]$&\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}=\frac{0.06}{2 \times 1.645} \\[/tex]

[tex]$&\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}=0.02[/tex]

Now, squaring both sides, we get;

[tex]$\frac{\hat{p}(1-\hat{p})}{n}=0.0004 \\[/tex]

[tex]$n=\frac{\hat{p}(1-\hat{p})}{0.0004}[/tex]

Now, putting value of n in (1), we get;

[tex]$0.22=\hat{p}-1.645 \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$[/tex]

[tex]$0.22=\hat{p}-1.645 \times \sqrt{\frac{\hat{p}(1-\hat{p})}{\hat{p}(1-\hat{p})} \times 0.0004}$[/tex]

Simplifying the equation, we get

[tex]$0.22=\hat{p}-1.645 \times \sqrt{0.0004}$[/tex]

[tex]$0.22=\hat{p}-(1.645 \times 0.02)$[/tex]

[tex]$0.22=\hat{p}-0.033$[/tex]

[tex]$\hat{p}=0.22+0.033=0.253$[/tex].

The sample proportion [tex]$\hat{p}=0.22+0.033=0.253$[/tex].

Therefore, the correct answer is option D. 0.25.

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Answer:

43

Step-by-step explanation:

I would see a pattern like this

1 4 6 2 5 7 8 9 7 15 41 ?

------------------- ---------

start pattern key

then

15 = 8 × 2 - 1

a10 = a7 × a4 - a1

41 = 9 × 5 - 4

a11 = a8 × a5 - a2

? = 7 × 7 - 6 = 43

a12 = a9 × a6 - a3

Answer:

47

Step-by-step explanation:

3068 - 1266 - 1755 = 47

Answer:

The third number is 47.

Step-by-step explanation:

The sum of three numbers is 3068 - this can be expressed mathematically as:

[tex]\displaystyle{x + y + z = 3068}[/tex]

Given that two of the numbers are 1266 and 1755 (in order) then substitute x = 1266 and y = 1755:

[tex]\displaystyle{1266 + 1755 + z = 3068}[/tex]

Find the third number - solve for z-variable:

[tex]\displaystyle{3021 + z = 3068}\\\\\displaystyle{z = 3068-3021}\\\\\displaystyle{z = 47}[/tex]

Therefore, the third number is 47.

Answer:

=91.5384615385

Step-by-step explanation:

(59.5/65)x100= 91.5384615385

Answer:

86.9 km/h

Step-by-step explanation:

54 mph = 86.9046

Full number: 86.9046 km/h

Esto significa que debemos tener 58 páginas de plástico para contener las 517 tarjetas.´

Sabemos que cada página puede almacenar hasta 9 cartas.

Entonces queremos ver cuantos grupos de 9 cartas hay en el conjunto de 517, para ver esto tomamos el cociente entre 517 y 9.

N = 517/9  = 57.44

Y no podemos tener un numero racional, así que debemos redondear al proximo número entero, que es 58.

Esto significa que debemos tener 58 páginas de plástico para contener las 517 tarjetas.

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Step-by-step explanation:

4x-2y = 9 ...1

2x-y = -6 ...2

if ...2 × 2

4x-2y = -12

9 is not equal to -12

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

The side opposite to the largest angle is the longest side of a triangle.

[tex] \qquad \large \sf {Conclusion} : [/tex]

hence, we can conclude that longest side is e

( since it's opposite angle is the largest, i.e 86° )

Jet 1 moves with a speed of  672 mi/h, while jet 2 moves with a speed of  672 mi/h + 80mi = 752 mi/h.

Let's say that the rate (or speed) of the slower jet is R, then the rate of the faster jet is:

R + 80mi/h

Now, if we step on any of the two jets (such that we view it as if it doesn't move) the other jet will move with a speed equal to:

S = R + R + 80mi/h

We know that after 8 hours, the to jets are 11,392 mi apart, then we know that:

(R + R + 80mi/h)*8h = 11,392 mi

Now we can solve that for R:

2*R + 80mi/h = 11,392 mi/8h = 1,424 mi/h

R = 1,424 mi/h - 80mi/h)/2 = 672 mi/h

So Jet 1 moves with a speed of  672 mi/h, while jet 2 moves with a speed of  672 mi/h + 80mi = 752 mi/h.

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The types of study that we have hereare the

2. The question here would be

3. The answer that would be answered here would be

4. The question would be

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Triangle QRS was translated to form triangle TUV, hence both triangles have the same shape, same size and are congruent.

Transformation is the movement of a point from its initial location to a new location. Types of transformations are reflection, translation, rotation and dilation.

Rigid transformation preserves the shape and size of the figure. Reflection, translation, rotation are rigid transformations.

Triangle QRS was translated to form triangle TUV, hence both triangles have the same shape, same size and are congruent.

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Answer: All of the above

Step-by-step explanation:

I did the test

The contract price is $8,750,000

What is contract price?

Contract price means the amount Lao Construction Company charged the customer for total contract's execution.

We need to ascertain the percentage completion of the project first and foremost, which is the total costs incurred to date divided by the contract's total costs.

cost incurred to date=$ 1,500,000

total contract's cost=cost incurred to date+ expected future costs

total contract's cost=$1,500,000+$6,000,000

total contract's cost=$7,500,000

% completion=$1,500,000/$7,500,000

% completion=20%

gross profit recognized=(contract price*% completion)-costs incurred till date

gross profit recognized=$250,000

contract price=unknown(assume it is X)

% completion=20%

cost incurred to date=$ 1,500,000

$250,000=(20%*X)-$1,500,000

$250,000+$1,500,000=0.20X

$1,750,000=0.20X

X=$1,750,000/0.20

X=$8,750,000

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Answer:

46

Step-by-step explanation:

Answer:

46

According to question,

10% × x = 20

x = 20 ÷ 10%

x = 20 ÷ 0.1

x = 200

Now find 23% of x

23% × 200

0.23 × 200

46

The lists of the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9 that are possible is; 256

We are told that the last digit has to be either a one (1) or nine (9), then are two (2) options (>,<) for the remaining eight digits, so there are 2⁸ = 256 arraignments where each digit is either greater than or less than the preceding digits. This can be confirmed as below;

Numbers beginning with 1 = 8C0 = 1

Numbers beginning with 2 = 8C1 = 8

Numbers beginning with 3 = 8C2 = 28

Numbers beginning with 4 = 8C3 = 56

Numbers beginning with 5 = 8C4 = 70

Numbers beginning with 6 = 8C5 = 56

Numbers beginning with 7 = 8C6 = 28

Numbers beginning with 8 = 8C7 = 8

Numbers beginning with 9 = 8C8 = 1

Total lists of numbers possible = 1 + 8 + 28 + 56 + 70 + 56 + 28 + 8 + 1 = 256

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