Answer: If your opponent is winning 3:1 then they are probably better then you if they are winning more then you are. (or you are just having a bad day)
Posterior probability of scenario A: P(A|data) ≈ (0.0625 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.134
Posterior probability of scenario B: P(B|data) ≈ (0.216 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.466
Posterior probability of scenario C: P(C|data) ≈ (0.05184 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.400
Let's denote the three possibilities as follows:
A: Equally talented, each player has a 0.5 probability of winning a game.
B: You are slightly better, with a 0.6 probability of winning a game.
C: Your opponent is slightly better, with a 0.6 probability of winning a game.
Given that you won the second game but lost the first, third, and fourth games, we want to find the probability of scenario C given this outcome. Let P(C) represent the prior probability of scenario C being true.
According to the given information, each of the three scenarios (A, B, and C) is equally likely, so P(A) = P(B) = P(C) = 1/3.
Now, let's update the probabilities based on the outcome of the match:
In scenario A:
The probability of winning the second game is 0.5, and the probability of losing the first, third, and fourth games is 0.5 each. Therefore, the overall probability of the observed outcome in scenario A is (0.5 * 0.5 * 0.5 * 0.5) = 0.0625.
In scenario B:
The probability of winning all three games (assuming you are slightly better) is (0.6 * 0.6 * 0.6) = 0.216.
In scenario C:
The probability of winning the second game (assuming your opponent is slightly better) is 0.4, and the probability of losing the first, third, and fourth games is 0.6 each. Therefore, the overall probability of the observed outcome in scenario C is (0.4 * 0.6 * 0.6 * 0.6) = 0.05184.
Now, we can update the probabilities based on Bayes' theorem:
Posterior probability of scenario A: P(A|data) = (P(data|A) * P(A)) / (P(data|A) * P(A) + P(data|B) * P(B) + P(data|C) * P(C))
Posterior probability of scenario B: P(B|data) = (P(data|B) * P(B)) / (P(data|A) * P(A) + P(data|B) * P(B) + P(data|C) * P(C))
Posterior probability of scenario C: P(C|data) = (P(data|C) * P(C)) / (P(data|A) * P(A) + P(data|B) * P(B) + P(data|C) * P(C))
P(data|A) = 0.0625
P(data|B) = 0.216
P(data|C) = 0.05184
Plugging in the values, we get:
Posterior probability of scenario A: P(A|data) ≈ (0.0625 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.134
Posterior probability of scenario B: P(B|data) ≈ (0.216 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.466
Posterior probability of scenario C: P(C|data) ≈ (0.05184 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.400
So, after the match, the posterior probability that your opponent is slightly better than you is approximately 0.400 or 40%.
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What is the solution to 3/2b + 5 < 17? Explain how.
(1) b < 8
(2) b > 8
(3) b < 18
(3) b > 18
Answer:
[tex] \blue{b < 8}[/tex]
Answer 1 is correct
Step-by-step explanation:
[tex] \frac{3}{2} b + 5 < 17[/tex]
Take 5 to the right side.
[tex] \frac{3}{2} b < 17 - 5 [/tex]
[tex]\frac{3b}{2} < 12 [/tex]
Multiply both sides by 2.
[tex]3b <12 \times 2[/tex]
[tex]3b < 24[/tex]
Divide both sides by 3.
[tex]b < 8[/tex]
A package is oscillating on a spring scale with a period of 5.00 s. at time t = 0.00 s the package has zero speed and is at x = 8.50 cm. at what time after t = 0.00 s will the package first be at x = 4.50 cm?
Under the assumption of simple harmonic motion, the package will be at x = 4.50 centimeters at a time of 0.805 seconds.
How to analyze an object on simple harmonic motion
Simple harmonic motion is a kind of periodic motion represented by sinusoidal functions. Physically speaking, it is a good approximation for periodic motion due to small perturbations and with absence of frictions and viscous forces on the system.
The position of an object under simple harmonic motion is described by the following equation:
x (t) = A · cos (2π · t / T + Ф) (1)
Where:
A - Amplitude, in centimetersT - Period, in secondsФ - Angular phase, in radiansx(t) - Position, in centimetersIf we know that T = 5 s, A = 8.50 cm, Ф = 0 rad and x = 4.50 cm, then the time when the package will reach x = 4.50 cm is:
4.50 = 8.50 · cos (2π · t / 5)
9 / 17 = cos (2π · t / 5)
0.322π = 2π · t / 5
t = 0.805 s
Under the assumption of simple harmonic motion, the package will be at x = 4.50 centimeters at a time of 0.805 seconds.
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How many 5-letter words can be made using exactly 5 of the letters from
TEXAS and MEXICO? Letters may only be used as many times as they appear. (For
example, XETEX is allowed. However, MATEA is not allowed, since the A appears twice
in MATEA but only once in the given words.)
The total number of ways by words are formed is 35 ways.
According to the statement
We have given that the 5 letters and we have to make word from them and the letters are repeated as equal to letters in given words.
And we have to find the possible ways.
So, The given words are:
TEXAS and MEXICO
Here X = 2 and E = 2 and all other words are one time used words.
We can find possible ways by use of combination and permutation.
So,
Total number of ways = [tex]3C_{1} ^{5} + 2C_{2} ^{5}[/tex]
here 3 because three letters are not repeatable and 2 letters are repeated for 2 times.
So,
Total number of ways = [tex]3C_{1} ^{5} + 2C_{2} ^{5}[/tex]
Total number of ways = [tex]3(\frac{5!}{1!} ) + 2(\frac{5!}{2!*3!} )[/tex]
Total number of ways = [tex]3(5) + 2(10)[/tex]
Total number of ways = 15 + 20
Total number of ways = 35.
So, The total number of ways by letters are formed is 35 ways.
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What is the solution set 5.5x+15.5>32
Answer:
(3, ∝) or all values of x greater than +3
Step-by-step explanation:
The inequality is [tex]5.5x + 15.5 > 32[/tex]
Subtracting 15.5 from both sides yields
5.5x > 32 - 15.5 or 5.5x > 16.5
Dividing by 5.5 on both sides yields
x > 16.5/5.5 or x > 3
This means the inequality is valid for all values of x > 3
The solution set is the interval (3, ∝ )
To promote a new brand of shoes, a shoe store will run
a promotion using a jar containing 3 red balls marked
"10% off," 2 white balls marked "30% off," and
1 green ball marked "60% off." Each customer will
randomly select 1 ball from the jar to determine the
discount that the customer will receive on any single
pair of the new brand of shoes. Given that the new
brand of shoes regularly costs $60 per pair, what is the
average discount amount, in dollars, that the store can
expect to give each customer due to this promotion?
Based on the percentage discount that one gets from the promotion using a jar, the average discount amount the shoe store can expect to give each customer is $15.
How much discount will the shoe store give on average?The average discount in percentages will be:
= (3/6 x 10%) + (2/6 x 30%) + (1/6 x 60%)
= 5% + 10% + 10%
= 25%
The average discount in cash amounts is:
= 25% x 60
= $15
In conclusion, the average discount amount that the store can expect to give each customer in dollars is $15.
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Plot the axis of symmetry and the point where the maximum value occurs for this function: h(x) = -(x 2)2 8.
See attachment for the axis of symmetry and maximum point.
What is a function?A function from a set X to a set Y allocates exactly one element of Y to each element of X. The set X is known as the function's domain, while the set Y is known as the function's codomain. Originally, functions were the idealization of how a variable quantity depends on another quantity.To plot the axis of symmetry:
The given function is: [tex]h(x) = -(x+2)^{2} +8[/tex]This function is in the form: [tex]g(x) = a(x-h)^{2} +k[/tex]Where the axis of symmetry is given by, x = h.y comparison, we have -h=2.This implies h=-2Therefore the axis of symmetry is x = -2.
Therefore, the maximum value occurs at the vertex, given by (h,k)=(-2,8).
So, see attachment for the axis of symmetry and maximum point.
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What is the smallest positive integer having eactly 5 different positive integer divisors?
The smallest positive integer having exactly 5 different positive integer divisors is 60.
What are positive integers?Positive integers are the numbers that we use to count: 1, 2, 3, 4, and so on. A collection of positive integers excludes numbers with a fractional element that is not equal to zero and negative numbers. Positive integers can be used for addition, subtraction, multiplication, and division operations.To find the smallest positive integer having exactly 5 different positive integer divisors:
Take out the LCM of 1,2,3,4, and 5.The LCM of 1,2,3,4, and 5 is 60.Therefore, the smallest positive integer having exactly 5 different positive integer divisors is 60.
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which expression shows how the distribuive property can be used to multiply 8x29?
The expression which shows how the distributive property of the can be used to multiply 8×29 as in the task content is; 8(20 + 9).
Which expression can be used to show how the distributive property can help multiply 8×29?It follows from the task content that the given product to be multiplied is; 8×29.
Consequently, it follows from convention that the distributive property of multiplication allows that the multiplication in this case can be rewritten as follows;
8×29 = 8 (20 + 9)
Hence, we have; (8×20) + (8×9).
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help fast pls!
it doesn't have to be a long explanation i just need the answer and a lil blurb to know ur not lying tysm!!!
Answer:
c 0.5⁻ˣ
Step-by-step explanation:
The slowest rate is:
0.5⁻ˣ
Arc CD is Two-thirds of the circumference of a circle. What is the radian measure of the central angle?
StartFraction 2 pi Over 3 EndFraction radians
StartFraction 3 pi Over 4 EndFraction radians
StartFraction 4 pi Over 3 EndFraction radians
StartFraction 3 pi Over 2 EndFraction radians
Using proportions, it is found that the radian measure of the central angle is given as follows:
[tex]\frac{4\pi}{3}[/tex] radians.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.
The entire circumference is equivalent to a central angle of [tex]2\pi[/tex] radians. Hence the radian measure of the central angle considering two-thirds of the circumference is given as follows:
[tex]\frac{2}{3} \times 2\pi = \frac{4\pi}{3}[/tex]
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Answer:
Step-by-step explanation:
c edge
using the order of operations, which operation in the expression 3x2-2³÷4 should be completed first
A.multiply 3 and 2
B.divide 2³ by 4
C.cube 2
D.subtract 2³ from 2
Answer:
C. Cube 2.
Step-by-step explanation:
Using PEMDAS the first operation to be done is E (Exponent) which is
2³.
In first gear, or low gear, an automobile's engine runs about three times as fast as the drive shaft. In second gear, the
engine does not have to run as fast; usually it runs about 1.6 times faster than the drive shaft. Finally, in third, or high
gear, the engine runs at the same speed as the drive shaft.
Engine speed = 2,100 r.p.m.
Transmission in first gear
Drive-shaft speed:
Engine is currently in first gear as mentioned in question
Speed=2100rpmDrive shaft speed be x
3x=2100x=700rpmAnswer:
700 rpm
Step-by-step explanation:
A driveshaft is a shaft that transmits mechanical power.
Its speed is measured in rpm (revolutions per minute).
Engine speed
First gear: 3 × drive-shaft speedSecond gear: 1.6 × drive-shaft speedThird gear: equal to drive-shaft speedGiven engine speed:
2,100 rpmTherefore, the drive-shaft speeds in the different gears are:
First gear
Drive-shaft speed = 2100 ÷ 3 = 700 rpm
Second gear
Drive-shaft speed = 2100 ÷ 1.6 = 1312.5 rpm
Third gear
Drive-shaft speed = 2100 rpm
Using Euler's formula, how many
edges does a polyhedron with 9
faces and 14 vertices have?
[?] edges
Euler's Formula: F+ V=E+2
Answer:
Euler's Formula = F+V=E+2
F=9
V=14
So, 9+14=E+2
23=E+2
23-2=E
21=E
Hence, E (edges) = 21
Step-by-step explanation:
Solve the given initial-value problem. y'' 4y' 5y = 35e−4x, y(0) = −5, y'(0) = 1
The solution for the initial value problem is [tex]y_{g} = e^{-2x} (-12cos(x) + 5sin(x)) + 7e^{-4x}[/tex]
Given,
y" + 4y' + 5y = 35[tex]e^{-4x}[/tex]
y(0) = -5
y'(0) = 1
Solve this homogenous equation to get [tex]y_{h}[/tex]
According to differential operator theorem,
[tex]y_{h}[/tex] = [tex]e^{ax}[/tex]( A cos (bx) + B sin (bx)), where A and B are constants.
Therefore,
y" + 4y' + 5y = 0
([tex]D^{2}[/tex] + 4D + 5)y = 0
D = -2± i
[tex]y_{h} = e^{-2x} ( A cos (x) + B sin (x))[/tex]
Now, solve for [tex]y_{p}[/tex]
A function of the kind [tex]ce^{-4x}[/tex] is the function on the right, we are trying a solution of the form [tex]y_{p} =ce^{-4x}[/tex], here c is a constant.
[tex]y_{p} " + 4y_{p} ' + 5y_{p} = 35e^{-4x} \\=16ce^{-4x} -16ce^{-4x} +5ce^{-4x} = 35e^{-4x} \\= 5ce^{-4x} =35e^{-4x} \\c=\frac{35}{5} =7\\y_{p} =7e^{-4x}[/tex]
Then the general solution will be like:
[tex]y_{g} =y_{h} +y_{p} \\[/tex]
= [tex]e^{-2x} (Acos(x)+Bsin(x))+7e^{-4x}[/tex]
[tex]y_{g}(0)=-5=A+7=-12\\y_{g} '(0)=e^{-2x} (-Asin(x)+Bcos(x))-2e^{-2x} (Acos(x)+Bsin(x))-28e^{-4x} \\y'_{g} (0)=1=B-2A-28\\[/tex]
B = 1 - 24 + 28 = 5
Then the solution for the given initial value problem is
[tex]y_{g} =e^{-2x} (-12cos(x)+5sin(x))+7e^{-4x}[/tex]
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Quick algebra 1 question for 10 points!
Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!
Answer:
22
Step-by-step explanation:
| 2^3 - 4*3^2 | - 4 = | 8 - 36| - 4 = 28-4 = 24
what is the equation of 7.2+c=19 ?
7.2 + c = 19
c = 19 - 7.2
c = 11.8
Answer:
Your answer is 5.
Step-by-step explanation:
7.2 + c = 19
or, 14 + c = 19
or, c = 19 - 14
or, c = 5 ans.
Hope its helpful :-)
Examine the ratios to find the one that is not equivalent to the others.
StartFraction 2 Over 5 EndFraction = StartFraction 6 Over 10 EndFraction = StartFraction 8 Over 20 EndFraction = StartFraction 12 Over 30 EndFraction
Which ratio is different from the other three?
The ratio is different from the other three is StartFraction 6 Over 10 EndFraction; 6/10.
RatioA ratio is a number representing a comparison between two named things.
StartFraction 2 Over 5 EndFraction = StartFraction 6 Over 10 EndFraction = StartFraction 8 Over 20 EndFraction = StartFraction 12 Over 30 EndFraction
2/5 = 6/10 = 8/20 = 12/30
2/5 = 0.4
6/10 = 0.6
8/20 = 0.4
12/30 = 0.4
Therefore, the ratio is different from the other three is StartFraction 6 Over 10 EndFraction; 6/10
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use the compound interest formulas A=P e^rt to solve the problem given. round answers to the nearest cent.
Find the accumulated value of an investment of $15,000 for 6 years at an interest rate of 5.5% if the money is a. compounded semiannually; b. compounded quarterly; c. compounded monthly; d. compounded continuously.
Answer:
a) $20,771.76
b) $20,817.67
c) $20,484.80
d) $20,864.52
Step-by-step explanation:
Compound Interest Formula
[tex]\large \text{$ \sf A=P\left(1+\frac{r}{n}\right)^{nt} $}[/tex]
where:
A = final amountP = principal amountr = interest rate (in decimal form)n = number of times interest applied per time periodt = number of time periods elapsedPart (a): semiannually
Given:
P = $15,000r = 5.5% = 0.055n = 2t = 6 yearsSubstitute the given values into the formula and solve for A:
[tex]\implies \sf A=15000\left(1+\frac{0.055}{2}\right)^{2 \times 6}[/tex]
[tex]\implies \sf A=15000\left(1.0275}{2}\right)^{12}[/tex]
[tex]\implies \sf A=20771.76[/tex]
Part (b): quarterly
Given:
P = $15,000r = 5.5% = 0.055n = 4t = 6 yearsSubstitute the given values into the formula and solve for A:
[tex]\implies \sf A=15000\left(1+\frac{0.055}{4}\right)^{4 \times 6}[/tex]
[tex]\implies \sf A=15000\left(1.01375}\right)^{24}[/tex]
[tex]\implies \sf A=20817.67[/tex]
Part (c): monthly
Given:
P = $15,000r = 5.5% = 0.055n = 12t = 6 yearsSubstitute the given values into the formula and solve for A:
[tex]\implies \sf A=15000\left(1+\frac{0.055}{12}\right)^{12 \times 6}[/tex]
[tex]\implies \sf A=15000\left(1+\frac{0.055}{12}\right)^{72}[/tex]
[tex]\implies \sf A=20484.80[/tex]
Continuous Compounding Formula
[tex]\large \text{$ \sf A=Pe^{rt} $}[/tex]
where:
A = Final amountP = Principal amounte = Euler's number (constant)r = annual interest rate (in decimal form)t = time (in years)Part (d): continuous
Given:
P = $15,000r = 5.5% = 0.055t = 6 yearsSubstitute the given values into the formula and solve for A:
[tex]\implies \sf A=15000e^{0.055 \times 6}[/tex]
[tex]\implies \sf A=20864.52[/tex]
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16. A rectangle's area is 18 m². Its perimeter is 18
m. One side is
(A)2 m
(B) 6 m
(C) 9 m
(D) 18 m
The answer of your question is option (B)
Which statements describe characteristics of a geometric sequence? check all that apply.
The Option A is correct that tells us that the There is a common ratio between the terms which represent the Characteristics of the G.P. Series.
According to the statement
we have to explain the characteristics of the Geometric Sequence.
So, For this purpose
We know that the
A geometric progression, also known as a geometric sequence, is a sequence of non-zero numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio.
From its definition it is clear that the
There is a common ratio between the terms.
And this point represent the characteristics of the Geometric Sequence not all other points.
Now, The option A is the correct rather than the other options.
So, The Option A is correct that tells us that the There is a common ratio between the terms which represent the Characteristics of the G.P. Series.
Disclaimer: This question was incomplete. Please find the full content below.
Question:
Which statements describe characteristics of a geometric sequence? Check all that apply.
a.There is a common difference between terms
b.Each term is multiplied by the same number to arrive at the next term.
c.The sequence increases or decreases in a linear pattern
d.There is a common ratio between terms
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Select the correct responses in the table.
The relationship between two numbers is described below, where xrepresents the first number and y represents the second number.
The square of the first number is equal to the sum of the second number and 16. The difference of 4 times the second number and 1 is equal to
the first number multiplied by 7.
Select the equations that form the system that models this situation. Then, select the solution(s) of the system.
Equations
y² +16=x
x²=y+16
1-4y=7x
(2x)² =y+16
7y-1=4x
4y-1 =7x
(1,15)
(2.-12)
Solutions
(5,9)
(8,48)
(9,3)
The system that can help to model this are
x² = y + 164y - 1 = 7xHow to solve for the system of equationWe have the following equation. Remember that a good understanding of the question is what would help us to write the equation
The condition says:
The square of first number is equal to the sum of the second number and 16:
First number = x. Square of x = x²
second number = y + 16
For the second
The difference of 4 times the second number and 1 is equal to the first number multiplied by 7:
second number is y
4*y - 1= x*7
= 4y - 1 = 7x
Hence we would have the following as our equations
x² = y + 16
4y - 1 = 7x
The solution to the equation when graphed = 5, 9
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A circle is formed using a ribbon which has a radius of 28 cm. If a square has to be formed using the same ribbon, determine the length of the side of the square formed using the ribbon.
The length of the side of the square is [tex]44 cm[/tex].
What is a Circle?A circle is made up of all points in the same plane that are equidistant from one another. Only the bordering points make up the circle.The following are a few examples of circles in daily life: the bicycle's wheel. Dinner dish. Coin.A circle is a particular type of ellipse in mathematics or geometry where the eccentricity is zero and the two foci are congruent. A circle is also the location of points evenly spaced apart from the center. The radius of a circle is measured from the center to the edge.Determine the length of the side of the square:
Radius of circle[tex]=28.[/tex]
Circumference[tex]=2\pi r[/tex]
[tex]2\pi (28)=176[/tex]
Side of the square[tex]=\frac{176}{4} =44cm.[/tex]
The length of the side of the square is [tex]44 cm[/tex].
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At what rate of interest will the sum of Rs . 5000 give an interest of Rs . 1450 in 1year ?
Answer:
I = (PTR)/100
1450=(5000*1*R)/100
1450*100=5000R
145000/50000=R
29=R
Step-by-step explanation:
We know,
[tex] S.I. = \rm\cfrac{P*R*T}{100}[/tex]
Given,
Principal P = 5000
Rate R = R(Assume)
Time T = 1
Interest = 1450
Plug:
[tex]1450 = \frac{5000 \times r \times 1}{100} [/tex]
Solve:
[tex]1450 \times 100 = 5000 \times r[/tex]
[tex]145000 \div 5000 = r[/tex]
[tex]r \: = \: 29 \%[/tex]
Rate = 29
Therefore,the rate of Interest is 29%.
Write the equation of the line passing through the point (a, b) and having a slope m.
The equation of the line is b = am + c
What are linear equations?Linear equations are equations that have a constant slope, average rate of change or gradients
How to determine the line equation?The point is given as
(x, y) = (a, b)
The slope is given as
Slope = m
A linear equation is represented as
y = mx + c
Where me represents the slope
Substitute (x, y) = (a, b)
b = am + c
Hence, the equation of the line is b = am + c
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Find the co-ordinates of a point which lies on the line joining M(7, -3) and N(-2,-5). If x ordinates of that point is 3.
Answer:
(3, -3 8/9)
Step-by-step explanation:
Use a slope calculation or a graph to find the slope of the line.
m = (y-y)/(x-x)
m = (-3- -5)/(7- -2)
m = 2/9
Then write the equation of the line. I used point-slope form. (You could use y=mx+b, slope-intercept form, but you'd have to first calculate b as well)
Point-slope form:
y -Y = m(x-X)
y - -3 = 2/9(x- 7)
y + 3 = 2/9(x - 7)
We know the x-coordinate of the point we're looking for is 3. Fill that in as well and calculate the y that goes with it.
y + 3 = 2/9(3-7)
y+3=2/9(-4)
y = -8/9 - 3
y = -3 8/9
In decimal form this is -3.8888repeating
see image.
The point at x=3 on the line between M(7,-3) and N(-2,-5) is (3, -3 8/9).
1.Name 4 other angles whose cosine is the same as cos pi/3 . Explain using mathematical language how you know this is true.
2.Is this statement true or false? Explain your answer.
All angles that have the same cosine will have the same sine.
The trigonometry illustrates that the four angles whose cosine is the same as cos pi/3 will be 7∏/3, 13∏/3, 19∏/3, and 31∏/3
How to illustrate the information?From the information, given cos (x), the value that is similar to cos x will be the sum of the angle and multiple of 360.
Therefore, for the angle cos(∏/3), the angles that are similar to this angle will be expressed as Cos(2∏n + ∏/3) where n is any positive integer.
Then the other four angles will be 7∏/3, 13∏/3, 19∏/3, and 31∏/3. Also, the statement that all angles that have the same cosine will have the same sine is false. The sine of an angle is simply equal to the cosine of the complementary angle.
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Find the radius of a circle with
circumference of 23.55 feet.
Use 3.14 for í.
Hint: C = 2πr
radius = [?] feet please explain your answer so I can understand how to do the rest
Answer:
r = 3.75
Step-by-step explanation:
C = 2(pi)r (write equation)
r = c / 2pi (rearrange for r)
r = 23.55 / 2(3.14) (plug in variables)
r = 23.55 / 6.28 (simplify)
r = 3.75 (solve)
Given f(x) = 3x - 5 which statement is true? Explain how.
(1) f(0) = 0
(2) f(3) = 4
(3) f(4) = 3
(4) f(5) = 0
Answer:
(2)
Step-by-step explanation:
by substituting the values of x into f(x) and evaluating
f(0) = 3(0) - 5 = 0 - 5 = - 5 ≠ 0
f(3) = 3(3) - 5 = 9 - 5 = 4 ← True
f(4) = 3(4) - 5 = 12 - 5 = 7 ≠ 3
f(5) = 3(5) - 5 = 15 - 5 = 10 ≠ 0
Hence, statement 2 is true for the equation f(x) = 3x-5
What is equation?The definition of an equation in algebra is a mathematical statement that proves two mathematical expressions are equal.
Types of Equations:
Linear Equation: More than one variable may be present in a linear equation. An equation is said to be linear if the maximum power of the variable is consistently 1.
Quadratic Equation: This equation is of second order. At least one of the variables in a quadratic equation needs to be raised to exponent 2.
Cubic Equation: A third-order equation is this one. At least one of the variables in cubic equations needs to be raised to exponent 3.
Rational Equation: A fractional equation having a variable in the numerator, denominator, or both is referred to as a rational equation.
Substituting the values of x into f(x) and evaluating
f(x) = 3x - 5
put x = 0
f(0) = 3(0) - 5
= 0 - 5 = - 5
put x = 3
f(3) = 3(3) - 5
= 9 - 5
= 4
put x = 4
f(4) = 3(4) - 5
= 12 - 5
= 7
put x = 5
f(5) = 3(5) - 5
= 15 - 5
= 10
hence statement 2 is true.
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There was an earthquake in San Francisco April 18, 1906. More recently there was another earthquake in Columbia June 27, 2014. Earthquakes are measured using the associated amplitude on the Richter scale. Let a1 be the amplitude for the San Francisco earthquake and a2 be the amplitude for the Columbian earthquake.
San Francisco earthquake equations is below:
R1=log(a1/T)+B=7.8
Columbia earthquake equations is below:
R2=log(a2/T)+B=5.6
a. Use the properties of logs to determine how many more times severe was the San Francisco earthquake? The severity is equal to the ratio below: a1/a2
Solving a logarithmic equation, it is found that the San Francisco earthquake was 24.71 times more intense than the Columbian earthquake.
How to find the ratios of the intensity of earthquakes?As given in the problem, the intensities of the earthquakes are given by logarithms of base 10. Then, supposing that the intensities are R1 and R2, with R1 greater than R2, the ratio of the intensities, that is, how much intense R1 is than R2, is given as follows:
[tex]r = 10^{\frac{R_1}{R_2}}[/tex]
For this problem, the intensities are given as follows:
San Francisco: R1 = 7.8.Columbia: R2 = 5.6.Then, the ratio of the intensities is given as follows:
[tex]r = 10^{\frac{7.8}{5.6}} = 24.71[/tex]
The San Francisco earthquake was 24.71 times more intense than the Columbian earthquake.
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A square field was enlarged by adding 5 feet to the length and width of the original field. if the area of the enlarged field is 576 square feet, what was the side length of the original field?
The side length of the original field is 19 feet.
What is square?
A square is a special kind of rectangle (an equilateral one) and a special kind of parallelogram (an equilateral and equiangular one). A square has four axes of symmetry, and its two finite diagonals (as with any rectangle) are equal. Bisection of a square by a diagonal results in two right triangles.Suppose the original square is x feet wide. Since its the length and width are the same,
So, length of side of enlarged field = x+5
Area of new enlarged field = side² = ( x + 5 )²
So, the enlarged shape would be = ( x + 5 ) ( x + 5)
Then , ( x + 5 ) ( x + 5) = 576
( x + 5 )²= 576
x + 5 = √576
x + 5 = 24
x = 24 - 5 ⇒ 19
Hence, The side length of the original field is 19 feet.
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