Find the equation of the line that passes through point (6, 1) with the x-intercept of 2.

Answer:

f(x) = g(x) + 9 because it is shifted 9 to the right

Answer:

instruments are very important to the direction of the personal information and concerns about the direction

Using the law of cosines and sines, the measure of angle B is: 38.4°.

Law of cosines is: c = √[a² + b² ﹣ 2ab(cos C)]

Law of sines is: sin A/a = sin B/b = sin C/c

Use the law of cosines to find c:

c = √[12² + 18² ﹣ 2(12)(18)(cos 117)]

c ≈ 25.8

Use the law of sines to find angle B:

sin B/b = sin C/c

sin B/18 = sin 117/25.8

sin B = (sin 117 × 18)/25.8

sin B = 0.6216

B = sin^(-1)(0.6216)

B = 38.4°

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Answer:

he is more likely incorrect.

Step-by-step explanation:

Z = (ps - p0)/sqrt(p0(1-p0)/n)

ps = proportion sample

p0 = proportion null hypothesis (NCAA)

n = sample size

ps = 17 / 36/100 = 17/1 / 36/100 = 1700/36 =

= 47.22222222...%

Z = (0.47222... - 0.575)/sqrt(0.575(1 - 0.575)/36) =

= -0.10277777... /sqrt(0.244375 / 36) =

= -0.10277777... / 0.0823905... =

= -1.247446952... ≈ -1.25

p(-1.25) = 0.10565

0.10565 > 0.05

the null hypothesis is therefore likely, or at least cannot be rejected.

so, his claims are not supported, as surprising as this might feel given that the sample result itself is 10 points off the NCCA result, which feels to be a solid difference.

The answer choice which correctly draws a comparison between the end behaviours of the functions is; Choice C; They have the same end behavior as x approaches -∞ and same end behavior as x approaches ∞.

As given in the task content; the graph of the exponential function passes through (-4, 9), (0, 1), (1, 0), and (5, -2).

It therefore follows that as; x reduces (approaches -∞), the y value increases.

And, as x -increases (approaches +∞), the y-value decreases.

For the table, the values can be written as coordinates as follows; (-1,2), (0,4), (1,6), (2, 0), (3,-2).

Consequently, as x reduces (approaches -∞), the y- values decrease.

And, as x increases (approaches +∞), the y-values decrease.

Ultimately, the two functions in discuss can be concluded to have; Choice C.

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On looking for a pattern in the given data set, the quadratic model best describes the data.

2nd option is correct.

A data model represents the type of relationship between the variables of a data set.

Data models are of four types, namely, Linear, Cubic, Quadratic and Exponential data models.

Given data is:

Distance Traveled                      Average Speed(miles per hour)

(miles)

1                                                                7

2                                                               6.3

3                                                              5.67

4                                                              5.103

A quadratic model is the best data model for the given data set.

The pattern observed in the given data set observes the properties of a quadratic function.

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Answer:

Exponential is the correct answer.

Step-by-step explanation:

The dimensions based on the area given are 15cm by 20cm.

From the information given about the rectangle, the area is given as 300cm² and the margins are given as 1.5 and 2.

Therefore, the dimensions will be:

(1.5 × x) × (2 × x) = 300

1.5x × 2x = 300

3x² = 300

x² = 300/3

x² = 100

x = 10

Therefore the dimensions will be:

= 1.5x = 1.5 × 10 = 15

= 2x = 2 × 10 = 20

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We minimize the total area of the sheet

[tex]S = xy[/tex]

constrained by

[tex](x-4)(y-3) = 300[/tex]

Solve the constraint equation for [tex]y[/tex].

[tex](x-4)(y-3) = 300 \implies y-3 = \dfrac{300}{x-4} \implies y = 3 + \dfrac{300}{x-4} = \dfrac{3x+288}{x-4}[/tex]

Substitute this into [tex]S[/tex] and find the critical points.

[tex]S = \dfrac{3x^2+288x}{x-4} = 3x + 300 + \dfrac{1200}{x-4}[/tex]

[tex]\dfrac{dS}{dx} = 3 - \dfrac{1200}{(x-4)^2} = 0[/tex]

[tex]\implies \dfrac{1200}{(x-4)^2} = 3[/tex]

[tex]\implies (x-4)^2 = 400[/tex]

[tex]\implies x-4 = \pm20[/tex]

[tex]\implies x=-16 \text{ or } x = 24[/tex]

Of course [tex]x[/tex] can't be negative, so the page dimensions that minimize [tex]S[/tex] are [tex]x=24[/tex] and [tex]y=18[/tex].

Answer:

113

Step-by-step explanation:

first we need to divide 1000 by 8 to get 125.

Our prime number has to be less than 125.

The largest prime number less than 125 is 113.

Answer: Madison can travel 2.2 miles less than Anthony on one gallon of gas.

Step-by-step explanation:

The equation y = 39.1[tex]x[/tex] represents the number of miles, [tex]y[/tex], that madison can drive her car for every x gallons of gas.

Question: Madison can travel _ miles _ than Anthony on one gallon of gas.

Lets find how much Madison travels on 1 gallon of gas.

39.1(1) = 39.1

Therefore, Madison travels 39.1 miles on one gallon of gas.

Now lets solve for Anthony

Anthony travels 380.7 miles on 9 gallons of gas.

Therefore we can set up the equation:

9x = 380.7 to show that 9 gallons equates to 380.7 miles

to solve divide 9 from both sides

[tex]\frac{9x}{9} =\frac{380.7}{9}[/tex]

x = 41.3

So, Anthony travels 41.3 miles on one gallon of gas

Now find whether Madison travels more or less than Anthony on one gallon.

39.1 - 41.3 = -2.2

This means that Anthony can travel 2.2 miles more than Madison.

For your answer, this means that:

Madison can travel 2.2 miles less than Anthony on one gallon of gas

Hope this helped and have a nice day :)

Answer:

6x⁴ - 2x² +3

Step-by-step explanation:

[tex]\frac{12x^6-4x^4+6x^2}{2x^2}=6x^4 - 2x^2 + 3[/tex]

a. Recall that in polar coordinates, we can parameterize [tex]x=r\cos(\theta)[/tex] and [tex]y=r\sin(\theta)[/tex]. So, doing as the hint suggests, we have

[tex]r = 6\cos(\theta) + 8 \sin(\theta)[/tex]

[tex]\implies r^2 = 6r\cos(\theta) + 8r\sin(\theta)[/tex]

[tex]\implies \boxed{x^2 + y^2 = 6x + 8y}[/tex]

b. By completing the square, we get

[tex]x^2 + y^2 = 6x + 8y[/tex]

[tex]x^2 - 6x + y^2 - 8y = 0[/tex]

[tex]x^2 - 6x + 9 + y^2 - 8y + 16 = 25[/tex]

[tex](x-3)^2 + (y-4)^2 = 5^2[/tex]

which is the equation of the circle centered at (3, 4) with radius 5. Thus the area bounded by [tex]C[/tex] is [tex]\pi\cdot5^2 = \boxed{25\pi}[/tex].

c. This is made easier if you can consult a plot (attached). In the first quadrant, we have [tex]0\le\theta\le\frac\pi2[/tex], while the radial coordinate [tex]r[/tex] runs uninterrupted from the origin [tex]r=0[/tex] to the circle [tex]r=6\cos(\theta)+8\sin(\theta)[/tex]. So the area is

[tex]\displaystyle \int_0^{\pi/2} \int_0^{6\cos(\theta) + 8\sin(\theta)} r\,dr\,d\theta = \boxed{\frac12 \int_0^{\pi/2} \left(6\cos(\theta) + 8\sin(\theta)\right)^2 \, d\theta}[/tex]

d. Evaluate the integral.

[tex]\displaystyle \frac12 \int_0^{\pi/2} \left(36\cos^2(\theta) + 96\sin(\theta)\cos(\theta) + 64 \sin^2(\theta)\right) \, d\theta[/tex]

Simplify the integrand with the help of the identities

[tex]\cos^2(x) + \sin^2(x) = 1[/tex]

[tex]\sin(x)\cos(x) = \dfrac12 \sin(2x)[/tex]

[tex]\sin^2(x) = \dfrac{1 - \cos(2x)}2[/tex]

[tex]\displaystyle \frac12 \int_0^{\pi/2} \left(50 + 48\sin(2\theta) - 14 \cos(2\theta)\right) \, d\theta[/tex]

The rest is easy. You should end up with

[tex]\displaystyle \frac12 \int_0^{\pi/2} \left(6\cos(\theta) + 8\sin(\theta)\right)^2 \, d\theta = \boxed{24 + \frac{25\pi}2}[/tex]

a) The Cartesian equation that described curve C is x² + y² = 6 · x + 8 · y.

b) The area inside C is A = π · 5² = 25π square units.

c) The integral that computed the area inside curve C within the first quadrant is A = (1 / 2)∫ (6 · cos θ + 8 · sin θ)² dθ, for θ ∈ [0, 0.5π].

d) The integral evaluated at the given limits is equal to an area of 20.139π square units.

In this question we find a polar equation in explicit form. a) To find the equivalent form in rectangular coordinates, we must apply the following substitutions x = r · cos θ, y = r · sin θ:

r = 6 · cos θ + 8 · sin θ

r² = 6 · r · cos θ + 8 · r · sin θ

x² + y² = 6 · x + 8 · y       (1)

The Cartesian equation that described curve C is x² + y² = 6 · x + 8 · y.

b) Perhaps the equation represents a conic section, possibly a circunference. To prove this assumption, we must apply algebraic handling until standard form is obtained:

x² - 6 · x + y² - 8 · y = 0

x² - 6 · x + 9 + y² - 8 · y + 16 = 25

(x - 3)² + (y - 4)² = 5²          (1b)

Which indicates a circumference centered at point (h, k) = (3, 4) and with a radius of 5 units. By the area formula for a circle we find that the area inside C is A = π · 5² = 25π square units.

c) The polar form of the area integral is presented herein:

A = ∫ ∫ r dr dθ, for r ∈ [0, r(θ)] and θ ∈ [0, 0.5π]  

A = (1 / 2)∫ [r(θ)]² dθ, for θ ∈ [0, 0.5π]  

A = (1 / 2)∫ (6 · cos θ + 8 · sin θ)² dθ, for θ ∈ [0, 0.5π]  

The integral that computed the area inside curve C within the first quadrant is A = (1 / 2)∫ (6 · cos θ + 8 · sin θ)² dθ, for θ ∈ [0, 0.5π].

d) By algebraic handling, trigonometric formulas and integral properties:

A = 25 ∫ dθ  + 24 ∫ sin 2θ dθ - 14 ∫ cos 2θ dθ, for θ ∈ [0, 0.5π]  

A = 25 · θ - 12 · cos 2θ - 7 · sin 2θ, for θ ∈ [0, 0.5π]  

A = 20.139π

The integral evaluated at the given limits is equal to an area of 20.139π square units.  

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Step-by-step explanation:

since the y- axis stands for velocity (and the x-axus for time), speeding up means when the curve goes up (increasing velocity), and slowing down means when the curve goes down (decreasing velocity), all when reading the graph from left to right (small time values to larger time values).

(a)

speeding up

t in [0, 1)

or

0 <= t < 1

I would exclude t = 1, because at that point the slope is 0, there is no speeding up there.

slowing down

t in (1, 3)

or

1 < t < 3

the same argumentation for excluding 1 and 3, because there the slope of the curve turns 0 (just the turning point from one tendency to the other), and there is no speeding up or slowing down at these points.

(b)

speeding up

t in (1. 2)

or

1 < t < 2

slowing down

t in [0, 1) or in (2, infinity)

or

0 <= t < 1 || 2< t < infinity

we could use 3 instead of infinity, as this seems to be the last point of the drawn curve, but normally this kind of drawing tells me "infinity".

The answers to these questions are:

a. In the question we have the existence of the mean, the mode and the median hence the answer to this question is none.

b. if the measurement 14 is replaced by 2, the data that it is going to have the most effect on is going to be the mean. It would reduce the mean.

c. If the largest measurement is removed, it is going to have the most effects on the mean and the median.

d. If the data is skewed then the mean of the data set is going to be greater.

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Step-by-step explanation:

We can determine whether the change represents exponential growth or decay by seeing whether the number being raised to x is between 0 and 1, or greater than 1.

In the equation [tex]y = 540(1.04)^x[/tex], y will increase every time that x increases, as we are multiplying by a number greater than 1 every time.

Hence, this exponential function represents exponential growth.

The percentage rate of increase for this function would be how much the y-value increases each time. Since we are multiplying by 1.04, each time the new value is 104% the original y-value. Hence, the percentage increase is 4%.

If the Hansens want to reduce their expected estate tax liability prior to the death of either of the spouses, they could initiate a Marital Transfer.

A Marital transfer simply means that the Hansens should bequest their assets to each each other in case either of them die.

If this happens, the surviving spouse will not be charged any estate taxes because bequests to spouses are not subject to taxation.

To do this, the Hansens should put it into both of their wills that they plan to gift/ bequest their assets to their spouse if they die.

The big disadvantage of using a marital transfer however, is that the estate will still be subject to taxes when the surviving spouse dies. All the estate taxes that had been avoided would then be incurred by the estate but only after the death of both spouses.

In conclusion, they should use a marital transfer.

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The total cost of the materials calculated by the worker on the notebook is $325.52

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depend on any other variable for its value while a dependent variable is a variable that depends on other variable.

The total cost of materials = 7(43.75) + 2(4.69) + 9.89 = $325.52

The total cost of the materials calculated by the worker on the notebook is $325.52

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Answer: Interior Angle

Step-by-step explanation:

The angle BAD is fully enclosed, it is on the inside

The glass will contain 89.086 milliliters of juice with 7 ice cubes, using the equation of the line of best fit, y =  -29.202x + 293.5.

In the question, we are informed that the equation of the line of best fit, for the, scatter plot with x representing the number of ice cubes and y representing the milliliters of juice is given as y =  -29.202x + 293.5.

We are asked to tell how many milliliters of juice will be in a glass with 7 ice cubes based on the line of best fit.

To find the milliliters of juice in the glass with 7 ice cubes, we substitute x = 7, in the equation of the line of best fit, to get a value of y, representing the milliliters of juice in the glass.

Thus,

y =  -29.202x + 293.5,

or, y =  -29.202(7) + 293.5 {Substituting x = 7},

or, y = -204.414 + 293.5,

or, y = 89.086.

Thus, the glass will contain 89.086 milliliters of juice with 7 ice cubes, using the equation of the line of best fit, y =  -29.202x + 293.5.

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Using the binomial distribution, the probability that:

(a) Exactly 29 of them are spayed or neutered, that is, P(X = 29) = 0.1163.

(b)  At most 29 of them are spayed or neutered, that is, P(X ≤ 29) = 0.6648.

(c)  At least 28 of them are spayed or neutered, that is, P(X ≥ 28) = 0.5714.

(d) Between 28 and 32 (including 28 and 32) of them are spayed or neutered, that is, P(28 ≤ X ≤ 32) = 0.48345.

A binomial distribution, with a success rate of p on each trial, gives us the probability of x number of success in n number of trials, using the formula:

P(X = x) nCx.pˣ.qⁿ⁻ˣ, where q = 1 - p.

In the question, we are informed that 61% of owned dogs in the United States are spayed or neutered, and are given that 46 owned dogs are randomly selected.

This can be seen as a binomial probability distribution, with n = 46, and p = 61% = 0.61, q = 1 - p = 1 - 0.61 = 0.39.

(a) We are asked for the probability of exactly 29 of them being spayed or neutered.

Thus, x = 29, and we need to find P(X = 29).

Using the given calculator, P(X = 29) = 0.1163.

(b) We are asked for the probability of at most 29 of them being spayed or neutered.

Thus, we need to find P(X ≤ 29).

Using the given calculator, P(X ≤ 29) = 0.6648.

(c) We are asked for the probability of at least 28 of them being spayed or neutered.

Thus, we need to find P(X ≥ 28).

Using the given calculator, P(X ≥ 28) = 0.5714.

(d) We are asked for the probability between 28 and 32 of them are spayed or neutered.

Thus, we need to find P(28 ≤ X ≤ 32), which can be shown as;

P(28 ≤ X ≤ 32) = P(X ≤ 32) - P(X < 28).

Using the given calculator, P(X ≤ 32) = 0.91209.

Using the given calculator, P(X < 28) = 0.42864.

Thus, P(28 ≤ X ≤ 32) = P(X ≤ 32) - P(X < 28) = 0.91209 - 0.42864 = 0.48345.

Thus, using the binomial distribution, the probability that:

(a) Exactly 29 of them are spayed or neutered, that is, P(X = 29) = 0.1163.

(b)  At most 29 of them are spayed or neutered, that is, P(X ≤ 29) = 0.6648.

(c)  At least 28 of them are spayed or neutered, that is, P(X ≥ 28) = 0.5714.

(d) Between 28 and 32 (including 28 and 32) of them are spayed or neutered, that is, P(28 ≤ X ≤ 32) = 0.48345.

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The correct option regarding Talia factoring is given by:

Talia needs to factor out a negative from one of the groups so the binomials will be the same.

The expression is given by:

(15x² - 3x) + (-20x + 4).

Her first step was:

3x(5x - 1) + 4(-5x + 1)

After that, she did not factor out anything more out of the expression. However, looking at the two terms of the addition, we can realize that:

(-5x + 1) = -(5x - 1), hence she should factor out the negative.

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Step-by-step explanation:

Let ABC be the equilateral triangle. Let AE, BD and CF be the medians. A meridian divides a side into two equal parts. Hence, proved that medians of an equilateral triangle are equal .

The chances of it happening more than once in 4 trials is 13%

From the information given, we have can deduce that;

Probability of 1 trial = 55%

= 55/ 100

Find the ratio

= 0. 55

We are to find the probability of it happening more than once in 4 different trials

If the probability of it happening in one trial is 555 which equals 0. 55

Then the probability of it happening in 1 in 4 trials is given as;

P(1/4 trials) = 1/ 4 × 55%

P(1/4 trials) = 1/ 4 × 0. 55

Put in decimal form

P(1/4 trials) = 0. 25 × 0. 55

P(1/4 trials) = 0. 138

But we have to know the percentage

= 0. 138 × 100

Multiply the values, we have

= 13. 8 %

Thus, the chances of it happening more than once in 4 trials is 13%

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Answer:

C

Step-by-step explanation:

This is a translation 5 units left and 5 units dowh.

Here, the translation is [tex]T < 5,-5 >[/tex].

Here, the translation is given as: [tex]y=2(x-5)+5\longrightarrow y=2(x-0)+0[/tex].

i.e. [tex]y=2(x-5)+5\longrightarrow y=2(x-5+5)+(5-5)[/tex].

So, the graph of [tex]y[/tex] moves 5 units to the right and (-5) units to the up i.e., 5 units to the down.

Therefore, here, the translation is [tex]T < 5,-5 >[/tex].

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Answer:

-13

Step-by-step explanation:

First, we will find the value of j(2) first.

j(2) = -2(2) = -4

next, we will solve h[j(2)].

h[j(2)] = h(-4) = 3(-4) - 1 = -12 - 1 = -13

Step-by-step explanation:

x = a + 7

y = b-a

To prove

x + y = b + 7.

=a+7+b-a

=a-a+7+b

=0 + 7+b

= b+7

Proved ✅

Answer:

40°, 50°, and 90°

Step-by-step explanation:

Let the smallest angle be x.

Then, the other small angle is x+10.

The acute angles of a right triangle are complementary, so x+x+10=90, and thus x=40.

So, the acute angles measure 40° and 50°.

Therefore, the three angles are 40°, 50°, and 90°.

Answer: C

Step-by-step explanation:

The line [tex]y=x+2[/tex] is shaded below and is solid.

This eliminates all the options except for C.

The irrational number on set B is given by: [tex]\sqrt{5}[/tex]

Irrational numbers are numbers that cannot be represented by fractions. The two most common examples are:

In the set B given in this problem, the only number that is irrational is [tex]\sqrt{5}[/tex], as it is a non-exact root.

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Answer:

incenter

Step-by-step explanation:

The most convenient way to capture [tex]D[/tex] is with the parameterization

[tex]D = \left\{(x,y) \mid -1 \le y \le 3 \text{ and } -\dfrac{y+1}2 \le x \le y+1\right\}[/tex]

so we only need one iterated integral.

[tex]\displaystyle \iint_D e^{x-y} \, dA = \int_{-1}^3 \int_{-(y+1)/2}^{y+1} e^{x-y} \, dx \, dy[/tex]

Compute the integral with respect to [tex]x[/tex].

[tex]\displaystyle \int_{-(y+1)/2}^{y+1} e^{x-y} \, dx = e^{x-y} \bigg|_{x=-(y+1)/2}^{x=y+1} = e^{(y+1)-y} - e^{-(y+1)/2-y} = e - e^{-(3y+1)/2}[/tex]

Compute the remaining integral.

[tex]\displaystyle \int_{-1}^3 \left(e - e^{-(3y+1)/2}\right) \, dy = \left(ey + \frac23 e^{-(3y+1)/2}\right)\bigg|_{y=-1}^{y=3} \\\\ ~~~~~~~~ = \left(3e + \frac23 e^{-(9+1)/2}\right) - \left(-e + \frac23 e^{-(-3+1)/2}\right) \\\\ ~~~~~~~~ = \boxed{\frac{10e}3 + \frac2{3e^5}}[/tex]

If we had chosen the opposite order of variables, we would have used

[tex]D = \left\{(x,y) \mid -2 \le x \le 4 \text{ and } \max\left(-2x-1,x-1\right)\le y\le3\right\}[/tex]

where

[tex]\max(-2x-1, x-1) = \begin{cases} -2x-1 & \text{when } x<0 \\ x-1 & \text{when } x\ge0\end{cases}[/tex]

so we would have needed two iterated integrals,

[tex]\displaystyle \iint_D e^{x-y} \, dA = \int_{-2}^0 \int_{-2x-1}^3 e^{x-y} \, dy \, dx + \int_0^4 \int_{x-1}^3 e^{x-y} \, dy \, dx[/tex]