Claire buys a condo for $350,000. The value of the condo appreciates on average 5% per year where she
bought the condo
If you know the rest of the problems on the page then that would help;)

a) The slope of the secant lines are: q = 5, f(q) = 2,076: m = - 131.1, q = 10, f(q) = 1,299: m = - 106.8, q = 20, f(q) = 357: m = - 81.6, q = 25, f(q) = 84: m = - 68.1, q = 30, f(q) = 0: m = - 51.

b) The estimated slope of the line tangent to the curve at the point (x, y) = (15, 765) is - 94.2 gallons per minute.

In this problem we must determine the slope of several lines based on the information given by the table and using the secant line formula:

m = [f(q) - f(p)] / (q - p)     (1)

If we know that a = 15 and p = 765, then the slope of the secant lines are:

q = 5, f(q) = 2,076

m = [2,076 - 765] / (5 - 15)

m = - 131.1

q = 10, f(q) = 1,299

m = [1,299 - 765] / (10 - 15)

m = - 106.8

q = 20, f(q) = 357

m = [357 - 765] / (20 - 15)

m = - 81.6

q = 25, f(q) = 84

m = [84 - 765] / (25 - 15)

m = - 68.1

q = 30, f(q) = 0

m = [0 - 765] / (30 - 15)

m = - 51

The slope of the line tangent to the curve at the point (x, y) = (15, 765) can be estimated by averaging the slopes of the closest secant lines:

m' = [(- 106.8) + (- 81.6)] / 2

m' = - 94.2

The estimated slope of the line tangent to the curve at the point (x, y) = (15, 765) is - 94.2 gallons per minute.

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The z-score for a data value of 19 if the mean of a set of data is 37 and the standard deviation is 8.6 is -2.09

From the question, the given parameters about the distribution are

Mean value of the set of data = 37

Standard deviation value of the set of data = 8.6

The actual data value = 19

The z-score of the data value is calculated using the following formula

z = (x - mean value)/standard deviation

Substitute the given parameters in the above equation

z = (19 - 37)/8.6

Evaluate the difference of 19 and 37

z = -18/8.6

Evaluate the quotient of -18 and 8.6

z = -2.09

Hence, the z-score for a data value of 19 if the mean of a set of data is 37 and the standard deviation is 8.6 is -2.09

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Answer:

1 (3.66)

2(3.5)

3(5.25)

The expected value for the drilling company, using a discrete distribution, is of -$9,125, that is, a loss of $9,125.

The expected value of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.

Considering the cost that it takes to sink a test well, and the probabilities of each outcome, the discrete distribution is given by:

Hence the expected value is given as follows:

E(X) = 300000 x 0.025 + 130000 x 0 .05 - 25000 x 0.925 = -$9,125.

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Answer:

Step-by-step explanation:

1.733707699

could you brainlyest me?

The local minimum over the interval [-3,-1] is 0, the local maximum over the interval [-1,0] is 4.39, local minimum over the interval[0,3]is -32.

Given a graph of a function.

We are required to find:

A)Local minimum over the interval [-3,-1],

B) Local maximum over the interval [-1,0],

C) Local minimum over the interval [0,3].

We know that local maximum is a point after which the value of function starts decreasing and the local minimum is a point after which the value of function starts increasing.

When we see the graph from x=-3 to x=-1 we can find that the highest point is where the value of f(x) is minimum and after which the graph is increasing is at x=-2 and y=0, so the value of local minimum will be 0.

When we see the graph from x=-1 to x=0 we can find that the highest point is where the value of f(x) is maximum and after which the graph is decreasing is at  y=4.39, so the value of local maximum will be 4.39.

When we see the graph from x=0 to x=3 we can find that the highest point is where the value of f(x) is minimum and after which the graph is increasing is at  y=-32, so the value of local minimum will be -32.

Hence the local minimum over the interval [-3,-1] is 0, the local maximum over the interval [-1,0] is 4.39, local minimum over the interval[0,3]is -32.

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The times interest earned ratio for 20Y8 and 20Y9 are 11 and 12.6 respectively.

The change in the times interest earned ratio is favorable.

According to the question,

In 20Y8 and 20Y9, Averill Products Inc. disclosed the following on its income statement:

For 20Y9,

Interest expense= $440,000

Income before income tax expense= $5,544,000

Times interest earned ratio= 5544000/440000 = 12.6

For 20Y8,

Interest expense=$400,000

Income before income tax expense=$4,400,000

Times interest earned ratio= 4400000/400000 =11

As the times interest earned ratio for 20Y9 is greater than that for 20Y8,the change in the times interest earned ratio is favorable.

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Answer:

55

Step-by-step explanation:

[tex]\sqrt{3018+\sqrt{36+\sqrt{169} } }[/tex]

= [tex]\sqrt{3018+\sqrt{36+13} }[/tex]

= [tex]\sqrt{3018+\sqrt{49} }[/tex]

= [tex]\sqrt{3018+7}[/tex]

= [tex]\sqrt{3025}[/tex]

= 55

Answer:

Step-by-step explanation:

....

The chances that NEITHER of these two selected people were born after the year 2000 is 0.36

The given parameters are:

Year = 2000

Proportion of people born after 2000, p = 40%

Sample size = 2

The chances that NEITHER of these two selected people were born after the year 2000 is calculated as:

P = (1- p)^2

Substitute the known values in the above equation

P = (1 - 40%)^2

Evaluate the exponent

P = 0.36

Hence, the chances that NEITHER of these two selected people were born after the year 2000 is 0.36

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The stages to utilize to construct a frequency distribution table utilizing Sturge's approximation are as follows:

The steps to create a frequency distribution table utilizing Sturge's approximation exist as follows;

Step 1: Estimate the range of the data:

This exists simply by finding the difference between the biggest and the least values.

Step 2: Decide on the inaccurate number of classes in which the provided data exist to be grouped. The formula for this is;

K = 1 + 3.322logN

where; K= Number of classes

logN = Logarithm of the whole number of observations.

Step 3: Specify the approximate class interval size:

This exists acquired by splitting the range of data by the number of classes and exists symbolized by h class interval size.

Step 4: Find the starting point:

The lower class limit should take care of the least value in the raw data.

Step 5: Determine the remaining class boundaries:

When you have reached the lowest class boundary, then you can count the class interval size to the lower class boundary to obtain the upper-class boundary.

Step 6: Circulate the data into separate classes.

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Answer:

Each Cat video gets 750 comments

Each dog video gets 450 comments

Hope this helps you!

Answer:

He gets 750 comments on the cat videos and 450 on the dog videos the answer to the second question is yes

Step-by-step explanation:

khan :)

it should be 70 percent

Step-by-step explanation:

100 subtract by 30 is 70 percent

Answer:

219.4

Step-by-step explanation:

Find the number in the tenth place 3 and look at the one place to the right for rounding digit 7. Round up if this number is greater than or equal to 5 and round down if it is less than 5. So the answer is 219.4

Answer:

10b/y^2

Step-by-step explanation:

Hope this helps! :)

The amount that was invested are at 3% = 400000, at 4% = 500000 and at 2% = 100000

We have x + y + z = 1000000

((1+0.03)x - x)+ ((1+0.04)y - y) + ((1 + 0.02)z-z) = 34000

4z + x + z = 1000000

((1+0.03)4z - 4z)+ ((1+0.04)y - y) + ((1 + 0.02)z-z) = 34000

((1+0.03)4z - 1)+ ((1+0.04)y - 1) + ((1 + 0.02)z-1) = 34000

12/100z + 4/100y +2/100z = 34000

2y + 7z = 1700000

-2y - 10z = -2000000

2y + 7z = 1700000

Solve through the use of the simultaneous linear equation

z = 100000

y = 500000

x = 400000

The amount that was invested are at 3% = 400000, at 4% = 500000 and at 2% = 100000

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The value of x in (1/6)/2 = x/3 is 1

The equation is given as

(1/6)/2 = x/3

Cross multiply in the above equation

x * 2 = (1/6) * 3

This gives

x * 2 = 1/2

Cross multiply

x = 2 * 1/2

This gives

x = 1

Hence, the value of x in (1/6)/2 = x/3 is 1

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Answer:

the perpendicular bisector

Explanation:

The perpendicular bisector will intersect the segment at its midpoint.

Answer:

Step-by-step explanation:

Comment and Answer

This is a very well laid out proof. It would good for you to see how carefully this this proof has been set up.

Step Three says

DE = DF ÷ 2

The problem is that at least 2 of the choices will work. I think the best reason is that it is the definition of bisect. The previous statement says in language what  statement three says in algebraic notation. So statement 2 is the given statement. Statement 3 tells us that DE is 1/2 DF because it is bisected.

Answer A

Answer:(5-1)(7-1)

Step-by-step explanation:

We have give 4 numbers that are 1,1,5,7. we have to apply operations on it to make it 24.

» ( 7 - 1) × (5 - 1)

» (6) × (4)

» 24

Here's our answer..!!

For only 4 wire transfers, Checking account A has a monthly fee of $54, while checking account B has a monthly fee of $55, so the correct option is D.

Checking account A charges a monthly fee of $12, plus $10.50 for each wire transfer, then the total cost if you make 4 wire transfers is:

C = $12 + $10.50*4 = $54

For checking account B, we have a fixed cost of $21, plus $8.50 per each wire transfer, then the total cost for 4 wire transfers is:

C'  = $21 + 4*$8.50  = $55

So, if you make only 4 wire transfers per month, checking account A is a better option.

Then we can see that the correct option is D.

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Answer:

43 degrees

Step-by-step explanation:

First, notice that we can draw a right triangle to represent this situation. The vertical leg of the triangle corresponds to the tower, and the horizontal leg corresponds to the shadow. The height of the tower, 114, is OPPOSITE, and the length of the shadow, 121, is ADJACENT to the angle of elevation to the top of the tower. Remember SOH CAH TOA, we can use TAN to find the angle since we know the values of O and A.

TAN(x) = O/A

TAN(x) = 114/121

x = ARCTAN(114/121)

x = 43

The most reasonable unit to measure the time spent at school on an average school day is in hours.

In anything we are going to measure, we have to pay special attention to the unit. When doing this, we want to keep the absolute value of the measure, that is, the number small, hence the do this conversion of units may be used.

For example, it is easier and more practical to say one day instead of 87,840 seconds. The same logic is applied to this problem, in which the most reasonable unit to measure the time spent at school on an average school day is in hours, as it keeps the numerical measure smaller than it would be in minutes or seconds.

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Answer:

11=12

they are not equal to each other

Step-by-step explanation:

8+(6/2)=17-5

8+3=12

11=12

hope this helps

Step-by-step explanation:

Notice that the main vertices (-15,4) and (5,4) both have the same y coordinate. This means that the focal axis is horizontal so we have a horizontal ellispe.

Equation of a horizontal ellipse is

[tex] \frac{(x - h) {}^{2} }{ {a}^{2} } + \frac{(y - k) {}^{2} }{ {b}^{2} } = 1[/tex]

I'll explain the variables.

Step 1: Find the center.

The center (h,k) is the midpoint of either the main or co vertices. It doesn't matter because of the definition of an ellipse.

So using the midpoint formula, let find the midpoint of the main vertices.

[tex]( \frac{ - 15 + 5}{2} ) = - 5[/tex]

[tex] \frac{4 + 4}{2} = 4[/tex]

So our center is (-5,4) so as of right now we have

[tex] \frac{(x + 5) {}^{2} }{ {a}^{2} } + \frac{(y - 4) {}^{2} }{ {b}^{2} } = 1[/tex]

Step 2: The variable a represents the semi major axis. This

basically means what is the distance from the center to either main vertex.

Here, let use (5,4). Using (5,4), our main vertex and (-5,4), our center.

Use the distance formula

[tex]a= \sqrt{(5 - ( - 5) {}^{2} + (4 - 4) {}^{2} } [/tex]

[tex]a = \sqrt{100} [/tex]

[tex]a= 10[/tex]

So our distance is 10, this means a=10

Step 3: The variable b represent the semi minor axis. This basically the distance from the center to either co vertex.

Using the distance formula,

[tex]b = \sqrt{ (- 5 - ( - 5) {}^{2} + (4 - 11) {}^{2} } [/tex]

[tex]b = \sqrt{49} [/tex]

[tex]b = 7[/tex]

So b=7, so finally we plug a=10, b=7

[tex] \frac{(x + 5) {}^{2} }{100} + \frac{(y - 4) {}^{2} }{49} = 1[/tex]

The piecewise defined function is

f(t) = 800 * 1.5^t for 0 - 2

f(t) = 2700 * 1.05^t-3 for 3 to 9

On the domain of t = 0 to 2, we have:

f(0) = 800

f(1) = 1200

f(2) = 1800

The above function is a piecewise function with the following definition

f(0) = 800 --- initial value

r = 1200/800 = 1.5 --- rate

The function is then represented as:

f(t) = f(0) * r^t

This gives

f(t) = 800 * 1.5^t

On the domain of t = 3 to 9, we have:

f(3) = 2700

f(4) = 2835

The above function is a piecewise function with the following definition

f(3) = 800 --- initial value

r = 2835/2700 = 1.05 --- rate

The function is then represented as:

f(t) = f(3) * r^t-3

This gives

f(t) = 2700 * 1.05^t-3

Hence, the piecewise defined function is

f(t) = 800 * 1.5^t for 0 - 2

f(t) = 2700 * 1.05^t-3 for 3 to 9

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Answer:

Step-by-step explanation:

in the smallest triangle (BCD) you have an angle of 90° and one of 63°, the sum of the internal angles in a triangle is 180°, remove the known angles from 180 ° and you will have the measure of the CBD angle

180 - 63 - 90 =

27°

Answer:

27°

Step-by-step explanation:

180°-90°-63° = 27°

Answer: A

Step-by-step explanation: Because it can be simplified twice.

The addition of the polynomials x⁴ - 3x + 1, 4x² - 2x + 8, x³ - 9 in descending powers of x is x⁴ + x³ + 4x² - 5x.

Adding the polynomial

(x⁴ - 3x + 1) + (4x² - 2x + 8) + (x³ - 9)

= x⁴ - 3x + 1 + 4x² - 2x + 8 + x³ - 9

= x⁴ + x³ + 4x² - 3x - 2x + 1 + 8 - 9

= x⁴ + x³ + 4x² - 5x

Therefore, the addition of the polynomials x⁴ - 3x + 1, 4x² - 2x + 8, x³ - 9 in descending powers of x is x⁴ + x³ + 4x² - 5x.

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