A full 15.0 L scuba tank at 295 K contains 144 moles of air and has a pressure of 234 atm. At the end of the dive, the tank has a pressure of 68.0 atm and a temperature of 280 K. How many moles of air are left in the tank?"
Answers
Answer:
44.1 L
Explanation:
Since volume is being held constant, we can use the following variation of the Ideal Gas Law to find the new pressure.
[tex]\frac{P_1}{T_1N_1}=\frac{P_2}{T_2N_2}[/tex]
In the equation, "P₁", "T₁", and "N₁" represent the initial pressure, temperature, and moles. "P₂", "T₂", and "N₂" represent the final pressure, temperature, and moles. Your answer should have 3 sig figs to match the sig figs of the given values.
P₁ = 234 atm P₂ = 68.0 atm
T₁ = 295 K T₂ = 280 K
N₁ = 144 moles N₂ = ? moles
[tex]\frac{P_1}{T_1N_1}=\frac{P_2}{T_2N_2}[/tex] <----- Equation
[tex]\frac{234 atm}{(295 K)(144 moles)}=\frac{68.0 atm}{(280 K)N_2}[/tex] <----- Insert values
[tex]\frac{234 atm}{42480}=\frac{68.0 atm}{(280 K)N_2}[/tex] <----- Multiply 295 and 144
[tex]0.00551=\frac{68.0 atm}{(280 K)N_2}[/tex] <----- Simplify left side
[tex]1.54=\frac{68.0 atm}{N_2}[/tex] <----- Multiply both sides by 280
[tex](1.54)N_2={68.0 atm}[/tex] <----- Multiply both sides by N₂
[tex]N_2 = 44.1L[/tex] <----- Divide both sides by 1.54
There will be approximately 49.7 moles of air in the tank at the end of the dive.
The Ideal Gas Law, which asserts the following, can be used to solve this problem:
PV = nRT
Where:
P = pressure
V = volume
n = moles of gas
R = ideal gas constant
T = temperature
Let us first use the given data to obtain the initial amount of moles of air in the tank:
[tex]P_1[/tex]= 234 atm
V = 15.0 L
[tex]T_1[/tex] = 295 K, and
R = 0.0821 L/(Kmol) atm.
Using the ideal gas law equation, we can solve for [tex]n_1[/tex]:
[tex]n_1 = (P_1 * V) / (R * T_1)[/tex]
= (234 atm * 15.0 L) / (0.0821 L·atm/(K·mol) * 295 K)
≈ 189.6 moles
Using the new pressure and temperature, we can determine the exact amount of air in the tank:
P2=68.0 atm and T2=280 K
We can determine [tex]n_2[/tex] by applying the same formula:
[tex]n_2 = (P_2 * V) / (R * T_2)[/tex]
= (68.0 atm * 15.0 L) / (0.0821 L·atm/(K·mol) * 280 K)
≈ 49.7 moles
As a result, there will be approximately 49.7 moles of air in the tank at the end of the dive.
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Related Questions
What is regular (specular)
reflection?
A. when all light rays come in at different angles of
incidence
B. when the rays of light reflect at different angles
C. when all light rays reflect at the same angle
D. when all light rays are perpendicular
Answers
Answer:
specular reflection reflects all light which arrives from a given direction at the same angles where diffus reflection reflects light in a broad range of direction
Place the following in order of increasing dipole moment. I. Bcl3 ii. Bif2 iii. Bclf2.
Answers
The correct order of increasing dipole moment is as follows.
[tex]$B C l_{3} < B I F_{2} < B C l F_{2}$[/tex]
What is increasing dipole moment?When the separation of two opposite electrical charges is calculated then it is known as the dipole moment.The more the electronegativity of an atom more it will have in electrons towards itself. For example,[tex]$B C l_{3}$[/tex] electrons will be pulled towards the chlorine atom as it is more electronegative than the boron.Hence, the dipole moment is canceled out. So, it will have zero dipole moment. In[tex]$B I F_{2}$[/tex] and [tex]$B C l F_{2}$[/tex], fluorine is more electronegative and it is present in both the molecules.But chlorine is more electronegative than iodine atom. So, the dipole moment of [tex]$B C l F_{2}$[/tex] more than the dipole moment[tex]$B I F_{2}$[/tex]Thus, we can conclude that the correct order of increasing dipole moment is as follows.
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For the sequential deprotonations of a polyprotic acid, the equilibrium constants will typically?
Answers
For the sequential deprotonations of a polyprotic acid, the equilibrium constants will typically decrease with each successive ionization.
For explaining above statement let's take an example of polyprotic acid like phosphoric acid.
In the phospheric acid [tex]H_{3} PO_{4}[/tex], after deprotonation of one hydrogen results as [tex]H_{2} PO_{4}^{-}[/tex] and equilibrium constant as [tex]K_{1}[/tex] . [tex]H_{2} PO_{4}^{-}[/tex] donate one hydrogen results as [tex]H_{} PO_{4}^{-2}[/tex] and equilibrium constant as [tex]K_{2}[/tex] . Similarly, [tex]H_{} PO_{4}^{-2}[/tex] donate one hydrogen results as [tex]PO_{4}^{-3}[/tex] and equilibrium constant as [tex]K_{3}[/tex] . The removing of hygen ion from nuetral molecule is easier than removal of hydrogen ion from ionic species So, the value of [tex]K_{1}[/tex] is greater than [tex]K_{2}[/tex] and value of [tex]K_{2}[/tex] is greater than [tex]K_{3}[/tex].
So, the equilibrium constants of polyprotic acid will typically decrease with each successive ionization.
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g. Hot water at 100 °C is added to 300 g of water at 0 °C until the final temperature is 40 °C. Find the mass of the hot water added. The specific heat capacity of water is 4200 Jkg-¹°C¹.
Answers
Answer:
000
Explanation:
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name
is
God
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If the density of blood is 1. 060 g/ml. What is the mass of 6. 56 pints of blood?
Answers
Answer:
3290 gm
Explanation:
6.56 pints * 473.1765 ml/pint * 1.060 g/ml = 3290 gm
If the density of blood is 1. 060 g/ml. 3290 grams is the mass of 6. 56 pints of blood.
In the study of chemistry, physics, and engineering, comprehending and characterising different substances depend greatly on density, a fundamental physical attribute. It is described as the ratio of a material's mass to volume. Being an intense quality, density is solely reliant on the composition of the substance and is not dependent on its quantity.
1 pint=473.176 milliliters.
6.56 pints ×473.176 ml/pint = 3099.57 milliliters
Density of blood = 1.060 g/ml
Volume of blood = 3099.57 ml
Mass = Density × Volume
Mass = 1.060 g/ml × 3099.57 ml ≈ 3290 grams
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If the a of a monoprotic weak acid is 2. 6×10−6, what is the ph of a 0. 33 m solution of this acid?
Answers
The pH of the monoprotic weak acid is 2.79.
What are weak acids?The weak acids are the acids that do not fully dissociate into ions in the solution. Strong acids fully dissociate into ions.
The chemical reaction is HA(aq) ⇄ A⁻(aq) + H⁺(aq).
c (monoprotic acid) = 0.33 M.
Ka = 1.2·10⁻⁶
[A⁻] = [H⁺] = x
[HA] = 0.33 M - x
Ka = [A⁻]·[H⁺] / [HA]
2. 6 × 10⁻⁶ = x² / (0.33 M - x)
Solve quadratic equation: [H⁺] = 0.000524 M.
pH = -log[H⁺]
pH = -log(0.000524 M)
pH = 2.79
Thus, the pH of the monoprotic weak acid is 2.79
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Who invented the clay triangle?
Answers
A chemistry laboratory device is a clay triangle to support the crucible when heated to high temperatures. It consists of a three-sided triangle frame made of clay or ceramic material.
The heat can pass through the open sides and is evenly distributed throughout the crucible. Although the soil triangle is a common and commonly used piece of laboratory equipment, it is difficult to ascertain who actually invented it.
The design of the clay triangle probably changed over time as a result of diverse contributions from scientists and chemists working on building laboratory equipment. The soil triangle may not have had a clear beginning, as is the case with many scientific instruments, but it is considered an evolution in laboratory technology overall.
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He heat of solution of kcl is 17. 2 kj/mol and the lattice energy of kcl(s) is 701. 2 kj/mol. calculate the total heat of hydration of 1. 00 mol of gas phase k ions and cl– ions
Answers
The total heat of hydration of 1. 00 mol of gas phase [tex]K^{+}[/tex] ions and [tex]Cl^{-}[/tex]ions is - 684 kJ/mol.
Calculation ,
Given data ,
Heat of solution = 17. 2 kJ/mol
lattice energy of KCl(s) = 701. 2 kJ/mol.
heat of hydration = ?
The KCl is formed by[tex]K^{+}[/tex] ions and [tex]Cl^{-}[/tex]– ions
Δ[tex]H_{solution}[/tex] = U° + Δ[tex]H_{hydration}[/tex]
Δ[tex]H_{hydration}[/tex] = Δ[tex]H_{solution}[/tex] - U° = 17. 2 kJ/mol - 701. 2 kJ/mol = - 684 kJ/mol
Hence, heat of hydration of 1. 00 mol of gas phase [tex]K^{+}[/tex] ions and [tex]Cl^{-}[/tex] ions is - 684 kJ/mol.
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A substance moving from an area of high concentration to an area in which it has a low concentration is moving ______ the concentration gradient.
Answers
A substance moving from an area of high concentration to an area in which it has a low concentration is moving btween two concentration gradient.
What is diffusion?Diffusion can simply be defined as the movement of substances from a region of a high concentration to a region of lower concentration.
It is also the movement of substances from a region of a strong solution to a region of weak solution.
So therefore, a substance moving from an area of high concentration to an area in which it has a low concentration is moving btween two concentration gradient.
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Which are products of nuclear fusion? check all that apply. energy helium gas high temperatures hydrogen gas low pressure
Answers
The products created during nuclear fusion are Energy and Helium Gas
Overall, two positrons, two neutrinos (which convert two of the protons into neutrons), and energy are released along with the fusion of four protons into one alpha particle.
What is Nuclear fission ?Nuclear fission is a nuclear reaction in which low energy neutrons are used to smash the nucleus of an atom into smaller nuclei. In this process, a large amount of energy is released. Nuclear fission reactions are employed in nuclear power reactors due to their simplicity and high energy output.
What is Nuclear fusion ?When two or more atoms come together to produce one heavier nucleus, the process is known as nuclear fusion. This process releases a tremendous quantity of energy, far more than the energy
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Is this equation balanced and in the lowest form? 4NH3 → 2N2 + 6H2
A.
Yes, because there are equal amounts of atoms of each element on both sides.
B.
No, because the coefficients could be reduced to 2,1, and 3.
C.
Yes, because the coefficients are in their lowest whole number ratio.
D.
No, because the coefficients could be reduced to 2, 2, and 4.
Answers
Answer:
B.) No, because the coefficients could be reduced to 2,1, and 3.
Explanation:
The equation is not in its lowest molar ratio form. In this case, all of the coefficients can be divided by 2 and still result in whole numbers.
As such, the correct balanced equation is:
2 NH₃ ----> N₂ + 3 H₂
A d1 octahedral complex is found to absorb visible light, with the absorption maximum occurring at 503 nm. calculate the crystal-field splitting energy, δ , in kj/mol
Answers
237.9 KJ/mol⁻¹ crystal-field splitting energy is found to absorb visible light.
What is crystal-field splitting energy?The energy of the electron configuration in the ligand field less the energy of the electronic configuration in the isotropic field is known as the crystal field energy.
The core metal ion's d orbitals split into two groups with various energies in an octahedral complex. The energy of the electron transition, which is related to the wavelength of the emitted light, is equal to the energy of the crystal-field splitting.
Δ = E = ℎ c / λ
Where,
where ℎ is the Planck constant, 6.62*10⁻³⁴m²kg s⁻¹, and c is the speed of light, 3 x 10⁸m s⁻¹.
Δ = 6.62*10⁻³⁴m²kg s⁻¹ / 503 x 10⁻⁹
= 3.95 x 10⁻¹⁹
= 3.95 x 10⁻¹⁹
This value is the splitting energy per ion.
To convert it to J/mol, we should multiply it by Avogadro number, 6.022 x 10²³mol⁻¹
= 3.95 x 10⁻¹⁹ x 6.022 x 10²³mol⁻¹
= 237.9 KJ/mol⁻¹
Therefore, the crystal-field splitting energy is 237.9 KJ/mol⁻¹ .
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The malonic ester synthesis is a method for preparing carboxylic acids from alkyl halides. For each of the carboxylic acid products, draw the structure of the alkyl bromide that would be used in its synthesis.
Answers
Haloalkanes are another name for alkyl halides. Alkyl halides are substances in which halogen atoms have taken the place of one or more hydrogen atoms in an alkane (fluorine, chlorine, bromine, or iodine).
What is the structural property of alkyl bromide?Alkyl halides are halogen-substituted alkanes in which a halogen atom, such as fluorine, chlorine, bromine, or iodine, is used in place of one or more hydrogen atoms in an alkane. An alkyl halide has a link between the carbon atom and the halogen atom, which is sp3-hybridized and has a tetrahedral form.Vinyl halides are substances, as opposed to alkyl halides, in which a halogen atom is attached to a sp2-hybridized carbon atom of a carbon-carbon double bond (C=C). In contrast, aryl halides are substances in which a halogen atom is joined to an aromatic ring's sp2-hybridized carbon atom.Alkyl halides are further divided into primary, secondary, and tertiary alkyl halides based on the level of substitution at the carbon atom holding the halogen. The term "- carbon" refers to the carbon that is bound to a halogen atom. The term "-carbon" refers to the carbon atom that is connected to it. Greek alphabets are then used to represent the neighboring carbons (, and so on).To learn more about Alkyl halides click here-
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What volume of H2 gas will be produced if 60 L of ammonia, NH3, is decomposed into H2 and N2, assuming that all conditions are at STP?
a)
30 L
b)
90 L
c)
60 L
d)
120 L
e)
150 L
need answer ASAP!!
Answers
Answer:
I think the answer is c I'm not sure but probaly dont put c if your. ot sure try looking up the answers that helps me alot through my word
The volume of H₂ gas produced is approximately 90 L, Option (b) is correct.
To find the volume of H₂ gas produced when 60 L of ammonia (NH₃) is decomposed, we use the balanced chemical equation for the decomposition of ammonia:
2 NH₃(g) → 3 H₂(g) + N₂(g)
According to the equation, 2 moles of ammonia produce 3 moles of hydrogen gas (H₂). At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 liters.
First, calculate the moles of ammonia present in 60 L:
Moles of NH₃ = Volume / Molar Volume at STP = 60 L / 22.4 L/mol ≈ 2.68 moles
Using the stoichiometric ratio, 3 moles of H₂ are produced from 2 moles of NH₃. So, we can calculate the moles of H₂ produced:
Moles of H₂ = (3/2) * Moles of NH₃ ≈ (3/2) * 2.68 moles ≈ 4.02 moles
Now, find the volume of H₂ gas produced:
Volume of H₂ = Moles of H₂ * Molar Volume at STP = 4.02 moles * 22.4 L/mol ≈ 89.9 L
Rounded to one decimal place, the volume of H₂ gas produced is approximately 90 L, which corresponds to option b).
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How many milliliters of a 9. 0 mh2so4 solution are needed to make 0. 45 l of a 3. 5 m solution?
Answers
There are 1157.14 milliliters of a 9. 0 M [tex]H_{2} SO_4}[/tex] solution are needed to make 0. 45 L of a 3. 5 M solution.
Calculation,
The formula for the dilution of a solution is given as:
[tex]M_{1} V_{1}[/tex] = [tex]M_{2} V_{2}[/tex]
Where M is molarity and V is the volume of the solution in liters ( L ).
Given data,
[tex]M_{1}[/tex] = 9. 0 M
[tex]V_{1}[/tex] = 0. 45 L
[tex]M_{2}[/tex] = 3. 5 M
[tex]V_{2}[/tex] = ?
9. 0 M ×0. 45 = 3. 5 M × [tex]V_{2}[/tex]
[tex]V_{2}[/tex] in Lit = 9. 0 M ×0. 45/ 3. 5 M = 1.15 L
[tex]V_{2}[/tex] in the ml = 1.15 × 1000ml = 1157.14 ml
Volume in milliliters is 1157.14 .
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The major product expected from the sequential reaction of cyclopentene with br2/h2o, followed by sodium hydroxide is:
Answers
The major product expected from the sequential reaction of cyclopentene with [tex]Br_{2} /H_{2} O[/tex] , followed by sodium hydroxide is cyclopentene epoxide.
The treatment of cyclopentene with [tex]Br_{2} /H_{2} O[/tex] which is known as bromine water is an electrophilic substitution reaction.
In the first step the bromine molecule and the water molecule reacts each other and leads to formation of the bromohydrines . After that bromohydrines will break and we get halide anion i.e., bromine anion because bromine is more electronegativity and hydrin as a cation.
The cyclopentene will react with bromohydrin to give trans-2-bromopententanol and after reaction with base it give cyclopentane epoxide .
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For the reaction ag2s(s) ⇌ 2ag (aq) + s2−(aq). What happens to the equilibrium position if the amount of silver ion is halved?
Answers
The equilibrium shifts to the right.
What is Equilibrium law?According to this law, if a process in equilibrium is subjected to change in the factors that affect equilibrium, then the equilibrium shifts in a specific direction which tends to counteract the effect of change imposed.The common ion effect is a result of this lawFactors affecting equilibrium areChange in concentration of reactants or productChange in temperatureChange in pressureAdding an inert gasAccording to this law,
The concentration of the product is decreased and hence, the equilibrium shifts to the right.
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What mass of silver can be plated onto an object in 33. 5 minutes at 8. 70 a of current? ag (aq) e- → ag(s) 19. 6 g 9. 78 g 0. 326 g 3. 07 g 0. 102 g
Answers
Mass of silver can be plated onto an object in 33. 5 minutes at 8. 70 a of current is 19.55 g
Given, I=8.70A, t=33.5min=33.5*60=2010 sec, m of Ag = 19600g M=107.87 g/mol
From faradays law we can write q=I*t= 8.70*2010=17487 C.
moles of Ag =17487/ 19600=0.1812 moles
Ag deposited = 0.1812*107.87 = 19.55 g
SilverHaving the atomic number 47 and the Latin word argentum, which means "bright" or "white," silver is a chemical element. Its symbol is Ag. The highest electrical, thermal, and reflectivity of any metal are displayed by this transition metal, which is soft, white, and lustrous. The metal can be found in the Earth's crust in three different forms: as an alloy with other metals like gold and in minerals like argentite and chlorargyrite. It can also be found in its pure, free elemental form, also known as "native silver." During the refining of copper, gold, lead, and zinc, the majority of silver is created as a byproduct. As a valuable metal, silver has long been treasured.
What mass of silver can be plated onto an object in 33. 5 minutes at 8. 70 a of current? ag (aq) e- → ag(s) 19. 6 g 9. 78 g 0. 326 g 3. 07 g 0. 102 g
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For a typical titration, 0. 010 m naoh is the titrant (in the buret). if the initial buret reading is 2. 45 ml, and the final buret reading is 18. 70 ml, how much naoh was used for the titration?
Answers
16.25 ml NaOH was used for the titration.
Titration:"The process of calculating the quantity of a material A by adding measured increments of substance B, the titrant, with which it reacts until exact chemical equivalency is obtained (the equivalence point)" is the definition of titration.
A titration is a method for figuring out the concentration of an unknown solution by using a solution with a known concentration. Until the reaction is finished, the titrant (the known solution) is typically added from a buret to a known volume of the analyte (the unknown solution).
0. 010 m NaOH is the titrant (in the buret).
The initial buret reading is 2. 45 ml
The final buret reading is 18. 70 ml
The volume of NaOH = 18.70ml - 2.45 ml
= 16.25 ml
Therefore, 16.25 ml NaOH was used for the titration.
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What is the mass (g) of a piece of magnesium wire that produces 41. 8 ml of hydrogen gas collected over water at 21. 0 °c and at a pressure of 752 torr?
Answers
The mass (g) of a piece of magnesium wire that produces 41. 8 ml of hydrogen gas collected over water at 21. 0 °c and at a pressure of 752 torr is 0.041 gm.
Calculation,
According to ideal gas equation,
PV = nRT
Where, P is the pressure = 752 torr = 752 mmHg/760 mmHg/atm
P is the pressure in atm = 0.989atm
V is the volume = 41. 8 ml = 0.0418 L
R is the universal gas constant = 0.0821 Latm/mol K
T is the temperature = 21. 0 °C = 21. 0 + 273 = 294 K
n is the number of moles = ?
By putting value of P , V , T , and R in equation (i) we get,
0.989atm × 0.0418 L = n ×0.0821 Latm/mol K ×294 K
n = 0.989atm × 0.0418 L/0.0821 Latm/mol K×294 K = 0.00171 mol
Number of moles (n) = given mass/ molar mass = given mass/24.305
Mass = Number of moles×molar mass = 0.00171 mol×24.305 g/mol
Mass of the magnesium wire = 0.041 gm
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If a substance x has a solubility of 2. 4×10^−5 mg/l, and a molar mass of 188 g/mol. What is the molar solubility of the substance?
Answers
The molar solubility of the substance is 1.2 × [tex]10^{-10}[/tex] M if a substance x has a solubility of 2. 4 × [tex]10^{-5}[/tex] mg/l, and a molar mass of 188 g/mol.
Calculation ,
The number of moles dissolve in one liter of solution is called molar solubility.
Given Solubility = 2.4 × [tex]10^{-5}[/tex] mg/L
Solubility = 2.4 × [tex]10^{-5}[/tex] × [tex]10^{-3}[/tex] g/L = 2.4 × [tex]10^{-8}[/tex] g/L
Molar mass = 188 g/mol
Molar Solubility = 2.4 × [tex]10^{-8}[/tex] g/L / 188 g/mol = 0.012 × [tex]10^{-8}[/tex] mol/L
Molar Solubility = 1.2 × [tex]10^{-10}[/tex] M
Therefore , the molar solubility of the substance is 1.2 × [tex]10^{-10}[/tex] M
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During the nitrogen cycle, inorganic nitrogen from the atmosphere is converted into organic compounds. what is this process called? nitrogen cycle is illustrated with a missing step pointing from nitrogen (the atmosphere) to the roots of a plant. © 2016 cc-by-sa decomposition emission fixation transpiration
Answers
Nitrogen fixation -
The N2 must be changed through a procedure known as nitrogen fixation for it to be utilized by plants. Fixation transforms atmospheric nitrogen into forms that plants' root systems can absorb.What is the organic form of nitrogen?
Nitrate, nitrite, ammonium, and N2 gas are the main inorganic nitrogen forms. Numerous compounds, such as amino acids, proteins, nucleic acids, nucleotides, and urea, contain organic nitrogen.Learn more about Nitrogen fixation
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A sparingly soluble metal fluoride with formula mf2, where m is an unknown metal, has a ksp = 6. 65 x 10-6. calculate the concentration of f- in solution
Answers
A sparingly soluble metal fluoride with formula MF₂, where m is an unknown metal, has a Ksp = 6.65 x 10⁻⁶. The concentration of F⁻ in solution 2.36 x 10⁻³M
Ksp is called the Molar solubility product and S is the Molar solubility of an ion in a solution.
According to given formula, the dissociation of metal fluoride MF₂ occurs as follows in aqueous solution:
MF₂ ------> M⁺² + 2F⁻
S 2S
Ksp = [S] [2S]²
Ksp = 4S³
Given, Ksp = 6.65 x 10⁻⁶
On substituting,
6.65 x 10⁻⁶ = 4S³
S³ = 1.66 x 10⁻⁶
S = 1.18 x 10⁻³
So, Solubility of F⁻ ion = 2S
Solubility of F⁻ ion = 2(1.18 x 10⁻³)
Solubility of F⁻ ion = 2.36 x 10⁻³
Since Molarity of the ions is equal to the solubility of the ion in aqueous solution.
Hence, the concentration of F⁻ ion is 2.36 x 10⁻³M.
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3. 2.71x1022 molecules of CO2 to atoms I NEED HELP
Answers
2.71 x 10²² molecules of CO2 is equivalent to 2.71 x 10²² atoms.
What is number of molecules?The number of molecules in an element is the combination of atoms in that element.
The number of molecules of an element can be calculated by multiplying the number of moles of that element by Avogadro's number, which is 6.02 × 10²³.
However, the number of molecules in a substance is equivalent to the number of atoms in that substance.
Therefore, 2.71 x 10²² molecules of CO2 is equivalent to 2.71 x 10²² atoms.
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A buffer is prepared by adding 300. 0 ml of 2. 0 mnaoh to 500. 0 ml of 2. 0 mch3cooh. what is the ph of this buffer? ka= 1. 8 10-5(ans. 4. 92)
Answers
The Henderson-Hasselbalch equation can be used to determine the pH of the buffer from the pKa value. The pH of the buffer will be 4.75.
What is the Henderson-Hasselbalch equation?Henderson-Hasselbalch equation is used to determine the value of pH of the buffer with the help of the acid disassociation constant.
Given,
Acid disassociation constant (ka) = 1. 8 10⁻⁵
Concentration of NaOH = 2.0 M
Concentration of CH₃COOH = 2.0 M
pKa value is calculated as,
pKa = -log Ka
pKa = - log (1. 8 x 10⁻⁵)
Substituting the value of pKa in the Henderson-Hasselbalch equation as
pH = - log (1. 8 x 10⁻⁵) + log [2.0] ÷ [2.0]
pH = - log (1. 8 x 10⁻⁵) + log [1]
= 4.745 + 0
= 4.75
Therefore, 4.75 is the pH of the buffer.
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Acetophenone was treated by one equivalent of lda, followed by one equivalent of \it{tert}-butyl bromide. what are the most likely reaction products?
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The most likely reaction product when acetophenone was treated by one equivalent of LDA, followed by one equivalent of tert-butyl bromide.
The full form of LDA is the lithium diisopropyle amide. The enolates can acts as nucleophile in SN2 type reaction . Overall an alpha hydrogen is replaced with an alkyl group . This reaction is one of the more important for enolates because a carbon - carbon bond formed .
Example : when acetophenone was treated by one equivalent of LDA, which is base and abstract alpha hydrogen followed by one equivalent of tert-butyl bromide which gives tert-butyl bromide which is alkyl and such reaction is called alkylation.
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At 2525 °c, what is the hydroxide ion concentration, [oh−][oh−] , in an aqueous solution with a hydrogen ion concentration of [h ]=1. 5×10−6[h ]=1. 5×10−6 m?
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The hydroxide ion concentration [OH-] in an aqueous solution is 6.66 x 10⁻⁹ M
Experimental measurements of the pKw of water at 25ºC yielded a result of 14.0. The same method used to determine the pKa of all other water-soluble compounds that can function as acids in aqueous solution can also be used to determine this value from the examination of thermodynamic or electrochemical data for these aqueous solutions.
Water has a pkw=14
So it can be represented as,
[H+] [OH-] = 1×10^-14
Given [H+] = 1. 5×10^−6
So, [OH-] = (1*10^-14) / ( 1.5*10^-6)
= 6.66 x 10⁻⁹ M
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What is the oxidation number for n in the compound nh3? (recall that h usually has an oxidation number of 1.)
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The oxidation number for n in the compound [tex]NH_{3}[/tex] will be -3.
The charge an atom would have if all of its links to other atoms formed fully ionic could be known as the oxidation state, also known as the oxidation number. It describes how much an atom in a chemical molecule has been oxidized. The oxidation state can theoretically be positive, negative, and zero.
The oxidation number of N in [tex]NH_{3}[/tex] will be calculated as:
Let the oxidation number of H is 1.
[tex]NH_{3}[/tex] = 0
x + 3(1) = 0
x = -3.
Therefore, the oxidation number for N in the compound [tex]NH_{3}[/tex] will be -3.
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In what ways would adding the nabh4 too early would interfere with your reaction?
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NaBH4 is blind + will reduce other functional groups.
Functional groups:
The aldehyde group in o-vanillin would be converted to alcohol if it had been added during step one (imine production). Because the carbon is not sufficiently nucleophilic, p-toluidine would not attack and imine would not form in the maximum yield.
Regardless of the other atoms in the molecule, a functional group is a collection of atoms that have specific chemical characteristics. Covalent bonds bind the atoms in a functional group to the other molecules in the molecule as well as to one another. Examples: Alcohol, Aldehyde, Ketone, Carboxylic acid, Halogens, Double & Triple covalent bonds.
A carbonyl in which the carbon atom is linked to at least one hydrogen atom is called an aldehyde. An R-group or a hydrogen atom could be the other group joined to the carbonyl. Aldehydes are a highly reactive form of carbonyl because of the tiny size of the hydrogen atom, which makes it relatively simple for other molecules to approach the partial positive charge on the carbonyl carbon. Aldehydes are adaptable reactants used in numerous different organic synthesis processes. Numerous aldehydes also have unique tastes and odors.
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When nahco3 completely decomposes, it can follow this balanced chemical equation: 2nahco3 → na2co3 h2co3 determine the theoretical yields of each product using stoichiometry if the mass of the nahco3 sample is 3.80 grams. (show work for both) in an actual decomposition of nahco3, the mass of one of the products was measured to be 2.36 grams. identify which product this could be and justify your reasoning. calculate the percent yield of the product identified in part b. (show your work)
Answers
Theoretical yield = 2.397
The product could be sodium carbonate
percent yield = 98.456%
When nahco3 completely decomposes, it can follow this balanced chemical equation:
2nahco3 → na2co3 h2co3
If the mass of the NaHCO3 sample is 3.80 g, we must use stoichiometry to calculate the theoretical yields of each of the products.
mass of NaHCO₃ = 3.80 g
molar mass of NaHCO₃ = 84 g/mol
so the no of moles of NaHCO₃ = 3.80/84 = 0.0452 mol
You see, one mole of sodium carbonate and one mole of hydrogen carbonate are produced from two moles of sodium bicarbonate.
so, the no of moles of sodium carbonate = 0.0452/2 = 0.0226 mol
∴ mass of sodium carbonate ( Na₂CO₃) = no of moles of Na₂CO₃ × molar mass of Na₂CO₃
= 0.0226 × 106 ≈ 2.397 g
no of moles of hydrogen carbonate = 0.0452/2 = 0.0226 mol
mass of the hydrogen carbonate ( H₂CO₃) = no of moles of H₂CO₃ × molar mass of H₂CO₃
= 0.0226 × 62 g = 1.401 g
mass of one of the products was measured to be 2.36 g , from above data, we can say it must be sodium carbonate because value is the nearest of 2.397 g.
percentage yield = experimental yield/theoretical yield × 100
here experimental yield of Na₂CO₃ = 2.36 g
and theoretical yield of Na₂CO₃ = 2.397 g
∴ % yield = 2.36/2.397 × 100 ≈ 98.456%
Therefore the percentage yield of the product is 98.456%
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THEIR ANSWER IS RIGTH, ALL THREE PARTS
Theoretical yeild is 2.397, sodium bicarbonate is the possible product I chose, and percent yeild is 98.456