Based on the calculations, the number of blue marbles in this bag is equal to 15 blue marbles.
Given the following data:
Total number of marbles = 20 marbles.Probability of not selecting a blue marble = ¼.How to calculate the number of blue marbles?In this exercise, you're required to calculate the number of blue marbles considering the fact that the probability of not selecting a blue marble from this bag is ¼.
First of all, we would determine the probability of actually selecting a blue marble from this bag as follows:
Probability = 1 - nP(B).
Probability = 1 - ¼.
Probability = ¾.
Now, we can calculate the number of blue marbles:
P(B) = total number of blue marbles/total number of marbles
¾ = B/20
4B = 60
B = 60/4
Blue marbles, B = 15 blue marbles.
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Answer: 15 marbles
Explanation:
The probability of NOT picking/selecting a blue marble is 1/4. 1/4 of 20 is 5, which means that 5 marbles aren't blue. That leaves 15 marbles, which means that there is a 3/4 probability of selecting a blue marble from the bag (3/4 of 20 is 15).
Therefore, our desired answer is 15 marbles.
To receive credit fWhich of the following can you use during a quiz?
Question 4 options:
a)
Notes
b)
Textbook
c)
Both A or B
d)
You cannot use the textbook or notes on a quiz.or a course, your overall average must be above?
Answer:
D
Explanation:
you can't use textbook or note on a quiz
I delined one of my high school offeres, and accepted to go to discovery program, and fail the discovery program what can I do?
Answer:
I don't know
Explanation:
I don't know
sorry for it ;
I am really sorry
Serum cholesterol levels of 100 hypertensive patients were recorded. Mean cholesterol level was 190 mg/d1. The data was symmetrically distributed around the mean. Roughly 68% of the patients had serum cholesterol level between 175 mg/dl and 205 mg/dl. a. Calculate the standard error b. What will be the range of 95% confidence interval?
The standard error is 1.5.
The range of 95% confidence interval is 160 mg/dL and 220 mg/dL
What is the standard error of the distribution?The standard error of the distribution is calculated as follows:
Standard error = standard deviation/√Nwhere N is the number of participants = 100
From the empirical rule of a normal or symmetrical distribution;
68% of the data lies within one standard deviation95% percent within two standard deviations, and99.7% within three standard deviations from the mean.Therefore, 175 mg/dl and 205 mg/dl lie one standard deviation from the mean.
One standard deviation = 175 - 190 or 205 - 190 = ±15
Standard deviation = 15
a. Solving for the standard error using the equation above;
Standard error = 15/√100
Standard error = 1.5
b. The range of 95% confidence interval is two standard deviations away from the mean.
Range of values two standard deviations from the mean = 190 - (2*15) and 190 + (2 * 15)
Range of values two standard deviations from the mean = 160 mg/dL and 220 mg/dL
Therefore, the range of 95% confidence interval is 160 mg/dL and 220 mg/dL
In conclusion, the standard error is calculated from the standard deviation and the sample size.
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Listed below are body temperatures from five different subjects measured at 8 AM and again at 12 AM. Find the values of d and s.. In general, what does
represent?
Temperature (°F) at 8 AM 98.4 98.7 97.5 97.3
97.1
Temperature (°F) at 12 AM 99.0 99.3 97.9 96.9 97.5
Let the temperature at 8 AM be the first sample, and the temperature at 12 AM be the second sample. Find the values of d and s..
d=
(Type an integer or a decimal. Do not round.)
The mean of the temperature based on the information given is -3.2.
How to calculate the mean?The difference in the temperature based on the information will be:
98.4 - 99.0 = -0.6
98.7 - 99.3 = -0.6
97.5 - 97.9 = -0.4
97.3 - 96.9 = 0.4
97.1 - 97.5 = -0.4
Total = -1.6
The mean will be:
= -1.6/5
= -3.2
Also, the standard deviation is 2.8. This simony illustrates how spread the numbers are in the information given.
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Part A: Explain the meaning of these terms and how each relates to the scientific method.
1. Variables
2. Demand characteristic
3. Theory
4. Experiment
5. Data
6. Hypothesis
7. Case study
8. Dependent variable
9. Survey
10. Naturalistic
11. Design
12. Stimulus
13. Independent variable
14. Control group
15. Conclusion
16. random
ont describes part of the design, theory, variable or a hypothesis of
Below is the meaning of each term and how each relates to the scientific method:
Variables can be understood as a concept that expresses a value, classification or measure in scientific research.Demand characteristics relate to the needs and interest in scientific research.Theory is the set of untested arguments that justify information.Experiment is a systematic way of exploring data and information, for the accomplishment of the scientific study.Data is a set of research records that serve as the basis for a scientific study.Hypothesis is an assertion about a research question, proposing an expected result.Case study is the explanation of real phenomena through the collection and demonstration of qualitative data.Dependent variable is the factor that changes in relation to the manipulation of the independent variable.Survey is a research method to collect qualitative and quantitative data and information that will inform the research.Naturalistic is a theory about the knowledge of the world and its phenomena explained through the scientific method.Design is the scientific method whose purpose is the development of products and services to enhance the human experience.Stimulus are items of different natures used to promote a reaction of the components of a scientific study.Independent variable is the variable manipulated in a scientific study for the purposes of analysis and observation.Control group are groups that serve as parameters for the results of a research, not being manipulated, only compared.Conclusion the final part of the work, the synthesis of the considerations found through the testing of the theory and hypothesis.Random a choice from a representative sample of a larger population in a study.What is scientific methodology?It is a set of methods and techniques structured and organized in a complex way to test a theory, find new concepts and knowledge through research, study, experimentation and analysis.
Therefore, the scientific methodology helps the development of society through the production of reliable and tested knowledge in order to assist in social and technological progress.
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bona has a stated reaction to a sound of a loud < >. immediately before the loud pop, a light flashes. after several times. Bona has started reaction to the flash of lighy. What is UCS? What is CR? What is NS? What is UCR?
The UCS is known to be the loud pop
What is CR?The CR is known to be a light flashes
What is NS?The NS is the reaction of bona
What is UCR?The UCR flash of light.
What is an unconditioned response?In classical conditioning, an unconditioned response is known to be that behavior that is said to be unlearned response that takes place as a sort of natural reaction to the unconditioned stimulus.
Hence, The UCS is known to be the loud pop.
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1. A box contains six identical balls, numbered from 1 to 6. One ball is randomly selected from the box. What is the probability that the ball will show a 5?
Answer:
The probability of ball 5=1/6
Explanation:
This is because in 1 to 6, there is only one 5 numbered ball out of the total number of balls which is 6.
The sum of three numbers is 100. The second number is 2 times the third. The third number is 8 less than the first. What are the numbers?
Answer:
19, 54 and 27
Explanation:
54 is 2 times of 27 and 27-8=19
19+54+27=100
Consider an experiment of tossing two fair dice and noting the outcome on each die. The whole sample space consists of 36 elements. Now, with each of these 36 elements associate values of two random variables, X and Y, such that X≡ sum of the outcomes on the two dice, Y ≡ |difference of the outcomes on the two dice|. Construct joint probability mass function.
The joint probability mass function based on the given experiment is as seen in the attached file.
How to construct a joint probability mass function?
The whole sample space consists of 36 elements, i.e.,
Ω = {ω_ij = (i, j) : i, j = 1, ....6}
Now, with each of these 36 elements associate values of two random variables, X₁ and X₂, such that;
X₁ ≡ sum of the outcomes on the two dice.
X₂ ≡ |difference of the outcomes on the two dice|
That is;
X(ω_ij) = X₁(ω_ij) + X₂(ω_ij) = (i + j, |i - j|) i, j = 1, 2, ...., 6
Then, the bivariate rv X = (X₁, X₂) has the following joint probability mass
function (empty cells mean that the pmf is equal to zero at the relevant values of the rvs).
The joint probability mass function is seen in the attached file.
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