A 8.5-liter sample of a gas has 1.2 mole of the gas. if 0.65 mole of the gas is added, what is the final volume of the gas? temperature and pressure remain constant. 13 liters 14 liters 18 liters 21 liters

Answers

Answer 1

13 liters is the correct answer

13 liters is the final volume of the gas when the temperature and pressure remain constant.

v1/n1 = v2/n2

where,

v1 = initial volume = 8.5 liter

n1= initial mole of gas = 1.2 mole

n2= final mole of gas = 1.2+0.65= 1.85 mole

v2= final volume = ?

8.5 L/1.2 mol = v2/1.85 mol

7 L x 1.85 mol = v2/1.85 mol x 1.85 mol

13 L = v2

v2= 13 liter

What is a mole?A mole is an SI unit used to measure significant numbers of subatomic particles, such as atoms, molecules, or smaller particles. Any substance has an Avogadro number of molecules in a mole. The value of the Avogadro number is 6.02214076 × [tex]10^{23}[/tex].

How much is a mole of gas?

22.4 L

At STP (Standard Temperature and Pressure = 0 °C, 1 atm), an ideal gas has a volume of 22.41 L/mol.

What makes something a mole?Chemists use the term "mole" because atoms, molecules, and other particles are all very small and require a large amount to even weigh them. A mole is a measurement of the number of particles present, not their mass.

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Related Questions

To use the gas law constant r = 0.0821, the unit for temperature should be kelvin and the unit for pressure should be atmospheres. true false

Answers

The given statement "To use the gas law constant R=0.0821 the unit for temperature should be kelvin and the unit for pressure should be atmospheres" is -----true.

What is the ideal gas law?

The ideal gas law tells us about behavior of ideal gas through a equation and postulates.The ideal gas law is considered as ideal gas equation.

The ideal gas equation is given as.

PV = nRT

where,

P is pressure of the gasV is volume occupied by the gasn is number of moles of ideal gasT is temperatureR is constant known as universal gas constant.

The value of R depends upon units of temperature, pressure and volume.

Why is Kelvin used in gas laws?

The Kelvin scale is used in gas law problems because the pressure and volume of a gas depend on the kinetic energy or motion of the particles.

How are pressure and Kelvin temperature related?

It states that, at a constant volume, the pressure of a given amount of a particular gas is directly proportional to its Kelvin temperature. It can be written as: P ∝ T, or. P/T = k where k is a constant,

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number of oxygen atoms in 16 g of So2??

Answers

Now , we know that one mole of SO² Contains 2 Moles ( two ) of atoms of oxygen . Hence , 16 Grams of SO² Contains 0.5 Mole(s) of Oxygen

0.5

hope this helps you. :)

As a whole, plants tend to release more oxygen than carbon dioxide into the environment, but the ratios of gases differ at various times of the day. plants tend to take in more carbon dioxide during the day and release more oxygen. at night, they tend to take in more oxygen and excrete more carbon dioxide. how does the model support this phenomenon?

Answers

During the day, due to the existence of sunlight, the procedure of photosynthesis elevations over that of respiration. Photosynthesis uses carbon dioxide to produce carbohydrates removing oxygen as a byproduct. During the night, because there is no sunlight, the rate of photosynthesis decreases. This, therefore, drives the rate of respiration to surpass the speed of photosynthesis. In respiration, oxygen is consumed and carbon dioxide is dismissed.

What is photosynthesis?Photosynthesis is the process by which manufacturers use sunlight, water, and carbon dioxide to produce oxygen and energy in the form of sugar.The primary position of photosynthesis is to transform solar energy into chemical energy and then reserve that chemical energy for prospective use. For the most part, the planet's living designs are powered by this process.An illustration of photosynthesis is how plants convert sugar and significance from water, air, and sunlight into energy to grow. Description of photosynthesis is the procedure through which plants use water and carbon dioxide to assemble their food, grow and remove excess oxygen into the air.

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H2o is initially present in a state where its molecules are far apart. during a change of state, its molecules slow down. which change of state has most likely taken place?

Answers

H2o is initially present in a state where its molecules are far apart. during a change of state, its molecules slow down. Gaseous state to liquid state has most likely take place.

In the gaseous state, molecules of water are far away. Hence intermolecular forces are weak.

But when water vapours changes into liquid state molecules start coming closer. And hence intermolecular forces become strong.

Due to this entropy of water molecules decreases.

Thus from above we concluded that when water vapour changes into liquid its molecules is slow down.

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What products are formed in the following reaction

Answers

The correct product from this reaction is the structure in option D.

What is a secondary amine?

An amine is a compound that contains an alkyl group and an amino group. We know that we can obtain an amine from ammonia by replacing one or more hydrogen atoms with alkyl groups.

The compound as shown here is a secondary amine because two hydrogen atoms have been replaced with alkyl groups. We know that the reaction between the HCl and the amine produces an ionic compound owing to the fact that the nitrogen and the hydrogen from HCl are involved in a Dative bond.

As such, the correct product from this reaction is the structure in option D.

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If 160 grams of a 200-gram sample of gold-198 decay in 6.25 days, what is the half-life of gold-198?

Answers

The half-life of gold-198 is 2.77 days

Given:

mass of gold sample = 200-gram

mass of decay sample = 160 grams

time taken to decay = 6.25 days

To Find:

the half-life of gold-198

Solution: The amount of time it takes to disintegrate by half an initial amount. For a given reaction, a reactant's half-life t1/2 is the time it takes for its concentration to reach a value which is the arithmetic mean of its initial and final (equilibrium) value.

Since Au-198 is 200 g originally and it decays to 160 g, so 40g left

the fraction decay is 40/200 = 0.2

the time base is 6.25 days

ln0.2/6.25 = -0.25

k=ln2/half life therefore half-life = ln2/k = ln2/0.25

half life = 2.77 days

So, half life of gold is 2.77 days

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does anyone know the answer to this? is it A?

Answers

Answer:

1/2     ( the two answers given are not FRACTIONS)

Explanation:

Moles of  CH3OH   = 128 gm / 32 gm / mole   = 4 moles

Moles of water   72 gm / 18 gm /mole = 4

Mole fraction of CH3OH  =   4 / ( 4+4) = 4/8 = 1/2  

Please help.. I'm Giving Brainliest :)

Answers

Answer:

i think its -91.6

Explanation:

2 ( - 950.8) - (( - 1130.7) + ( - 393.5) + ( - 285.8))

The standard enthalpy change for the given reaction is approximately 91.9 kJ mol⁻¹.

The heat produced during a chemical reaction under specific conditions is known as the standard enthalpy change, abbreviated as H° (zero delta H). Standard conditions often refer to all reactants and products in their standard states, which are their most stable forms at 298 K and 1 bar (or 1 atm) pressure.

Hess's law, which states that the total enthalpy change of a reaction is equal to the sum of the enthalpy changes of its component phases, is used to calculate the standard enthalpy change of the reaction.

The following reaction is given:

[tex]\rm 2 NaHCO_3(s)--- > Na_2CO_3(s)+ CO_2(g) + H_2O(l)[/tex]

The relevant enthalpy changes of formation are:

ΔH°[NaHCO3(s)] = -950.8 kJ mol⁻¹

ΔH°[Na2CO3(s)] = -1130.7 kJ mol⁻¹

ΔH°[CO2(g)] = -393.5 kJ mol⁻¹

ΔH°[H2O(l)] = -285.8 kJ mol⁻¹

By using Hess's Law, the standard enthalpy change (ΔH°) for the reaction can be calculated as follows:

ΔH° = Σ (products) - Σ (reactants)

ΔH° = [ΔH°[[tex]\rm Na_2CO_3[/tex](s)] + ΔH°[[tex]\rm CO_2[/tex](g)] + ΔH°[H2O(l)]] - [2 × ΔH°[[tex]\rm NaHCO_3[/tex](s)]]

ΔH° = [-1130.7 kJ mol⁻¹ + (-393.5 kJ mol⁻¹) + (-285.8 kJ mol⁻¹)] - [2 × (-950.8 kJ mol⁻¹)]

ΔH° = [-1809.7 kJ mol⁻¹] - [-1901.6 kJ mol⁻¹]

ΔH° ≈ -1809.7 kJ mol⁻¹ + 1901.6 kJ mol⁻¹

ΔH° ≈ 91.9 kJ mol⁻¹

Hence, the standard enthalpy change for the given reaction is approximately 91.9 kJ mol⁻¹.

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What substance is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, cabr2(l)cabr2(l), and molten magnesium iodide, mgi2(l)mgi2(l)? assume standard conditions

Answers

Mg (Magnesium) is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, CaBr₂ (l) and molten magnesium iodide, MgI₂ (l).

What is Anode and cathode ?

The anode in the cell has been the negative electrode and attracts the positive ions in the solution. The cathode has been the positive electrode, and attract negative ions.

What is Electrolysis of Calcium Bromide ?

In electrolysis of Calcium bromide, Calcium will form at the cathode and Bromine will form at the anode.

The reaction is as follows:

2Br⁻ (aq) → Br₂ (g) + 2e⁻

What is Electrolysis of Magnesium Iodide ?

In electrolysis of magnesium Iodide, Magnesium will form at the anode Iodine will form at the cathode.

The reaction is as follows:

2I⁻ (aq) → I₂ (g) + 2e⁻

Thus from the above conclusion we can say that Mg (Magnesium) is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, CaBr₂ (l) and molten magnesium iodide, MgI₂ (l).

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How many grams of silver may be formed by the passage of 9,604 c through an electrolytic cell that contains a molten silver salt?

Answers

The grams of silver formed by the passage of 9,604 c through an electrolytic cell that contains a molten silver salt is 10.7g.

Acc. Faraday’s law of electrolysis,

W=(I×t×M) /nF

W=Faraday’s constant=96500

F=time M=molar mass

N=no. Of el.

It=9604C

Given,

Molar mass of silver=108g/mol.

n=1.

Then weight of silver deposited can be given as

W=(9604×108)/(96500×1)

= 10.7g

Thus we concluded that the silver deposited is 10.7g

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Given the following reaction: 2O3---->3O2. DeltaH of reaction=-286kJ/mol
What is the Delta H reaction of the reaction 3O2----->2O3

Answers

The enthalpy of reaction (ΔH) of the above chemical reaction is equal to -143 kJ/mol.

What is a chemical reaction?

A chemical reaction can be defined as a chemical process that involves the continuous transformation (rearrangement) of the ionic, atomic or molecular structure of a chemical element by breaking down and forming chemical bonds, in order to produce a new chemical compound while new bonds are formed.

What is a balanced equation?

A balanced chemical equation can be defined as a chemical equation wherein the number of atoms on the reactant (left) side is equal to the number of atoms on the product (right) side.

Next, we would write the properly balanced chemical equation for this chemical reaction:

                                    3/2O₂ -----> 2/2O₃

Therefore, the enthalpy of reaction (ΔH) of the above chemical reaction is half the enthalpy of reaction (ΔH) of the initial chemical reaction:

Enthalpy of reaction (ΔH) = ½ × -286 kJ/mol

Enthalpy of reaction (ΔH) = -143 kJ/mol.

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A solution of naf is added dropwise to a solution that is 0.0122 m in ba2 . when the concentration of f- exceeds ________ m, will precipitate. neglect volume changes. for , ksp = 1.7 x 10-6. 4. calculate the ph of a solution prepared by dissolving 0.270 mol of weak acid ha (ka = 1.77 x 10-4) and 0.260 mol of its conjugate base in water sufficient to yield 1.00 l of solution.

Answers

A solution of NaF is added to a solution that is 0.0144 M in Ba²⁺. When the concentration of F- exceeds 0.011 m, BaF₂ will precipitate.

Let's consider the solution of BaF₂.

BaF₂(s) ⇄ Ba²⁺(aq) + 2 F⁻(aq)

We can use the solubility product constant (Ksp) to find the equilibrium concentration of F⁻ when [Ba²⁺] is 0.0144 M.

When [F⁻] exceeds 0.011 M, BaF₂ will precipitate.

A solution of NaF is added to a solution that is 0.0144 M in Ba²⁺. When the concentration of F- exceeds 0.011 M, BaF₂ will precipitate.

What is BaF₂.?

BaF2 crystallizes in the cubic Fm3m space group and has a fluorite structural makeup. Eight comparable F1 atoms and Ba2+ are joined in a cubic shape with the body in the middle. The average Ba-F bond length is 2.72. Four comparable Ba2+ atoms are joined with F1 to create a mixture of corner- and edge-sharing FBa4 tetrahedra.

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The coefficient of performance (cop) of a refrigerator is defined as the ratio of?

Answers

The coefficient of performance (cop) of a refrigerator is defined as the ratio of " the work necessary to heat or cool something usefully."

The usable heating or cooling delivered to work required ratio, also known as the coefficient of performance, or COP, of a heat pump, refrigerator, as well as air conditioning system. Higher efficiency, less energy (power) usage, and thus reduced operational costs are all related to higher COPs.

Coefficient of performance formula:

[tex]K = Q_{H} / W_{in}[/tex]

where, K = Coefficient of performance, [tex]Q_{H}[/tex] = heat of pumps output, [tex]W_{in}[/tex] = work required by the system.

It is refrigeration's coefficient of performance (COP) will always be greater than 1.

Therefore, the coefficient of performance (cop) of a refrigerator is defined as the ratio of " the work necessary to heat or cool something usefully."

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A current of 5. 68 a is passed through a Fe(NO3)2 solution. How long, in hours, would this current have to be applied to plate out 7. 20 g of iron?

Answers

There are  1.2 hr would this current have to be applied to plate out 7. 20 g of iron .

Calculation ,

Given ; Current ( I ) = 5. 68 A

In [tex]Fe(NO_{3} )_{2}[/tex] , the valancy of Fe is +2 .

2 moles of [tex]e^{-}[/tex] are required for the decomposition of 1 mole of Fe .

7. 20 g  of Fe in moles  = 7. 20 g /55.845 g/mol =0.12 mole

x moles of  [tex]e^{-}[/tex] are required for the decomposition of 0.128 mole of Fe .

moles of   [tex]e^{-}[/tex] are required = 0.256 moles

Charge on 1 mole  of   [tex]e^{-}[/tex] = 96500 C

Charge on 0.256  mole  of   [tex]e^{-}[/tex] = 24704 C

Current ( I )= Q/t  

t =Q / I = 24704 C/5. 68 A = 4349 sec = 1.2 hr

Therefore , there are  1.2 hr would this current have to be applied to plate out 7. 20 g of iron .

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What is the molar mass of a protein if a 0. 30 l of solution containing 0. 45 g of the protein has an osmotic pressure of 0. 80 torr at 25∘c?

Answers

The molar mass of a protein if a 0. 30 l of solution containing 0. 45 g of the protein has an osmotic pressure of 0. 80 torr at 25∘c is 0.348 g/mol

Here we can apply the formula ∏ = iMRT, where ∏ = osmotic pressure = 0.80 - ( given ). This is only one part of the information we are given / can conclude in this case ....

i = van’t Hoff factor = 1 for a protein molecule,

R = gas constant = 62.36 L torr / K-mol,

T ( temperature in Kelvin ) = 25 + 273 - conversion factor C° + 273 = 298K

( Known initially ) ∏ = osmotic pressure = 0.80 torr

besides the part " M " in the formula, which we have no information on whatsoever, as we have to determine it's value.

_____

Substitute derived / known values to solve for M ( moles / liter ) -

∏ = iMRT

⇒ 0.80 = ( 1 )( M )( 62.36 )( 298 )

⇒ 0.80 = M( 18583.28 )

⇒ M = 0.80 / 18583.28 ≈ 4.3049 ....

_____

We know that M = moles / liter, so we can use this to solve for moles, and hence calculate the molar mass by the formula molar mass = g / mol -

M = mol / l

⇒ 4.3049 = 0.045 / 25 mL ( 0.030 L ),

0.045 / 0.030 = 1.5 g / L

⇒ 1.5 g = 4.3049 moles,

molar mass = 1.5 g = 4.3049 moles = 0.348 g / mol

Thus the concluded that the molar mass of protein is 0.348 g / mol.

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Calculate the kf of ag(nh3)2 from ag (aq) e- ⇋ ag(s) e0= 0. 81 v ag(nh3)2 (aq) e- ⇋ ag(s) 2nh3(aq) e0= 0. 39 v enter number as e notation (e. g. 2. 34e6 or 4. 56e-4)

Answers

The kf of Ag(NH₃)₂ for the given equation is 2.786 x 10⁷.

What is kf value?

kf value can be calculated by dividing the molal concentration with the freezing point of depression.

The reaction are given:

Ag+(aq) + e- ⇋ Ag(s) E0= 0.81 V

Ag(NH₃)₂ +(aq) + e- ⇋ Ag(s) + 2NH₃(aq) E0= 0.37 V

To get Kf of Ag(NH₃)₂  we will rearrange the above written equations

a. Ag +(aq) + e- ⇋ Ag(s) E0= 0.81 V

b. Ag(s) + 2NH₃(aq) ⇋ Ag(NH₃)₂ +(aq) + e- E0= - 0.37 V

Adding equation (a) and equation (b) we will get

Ag +(aq) + 2NH₃(aq) ⇋ Ag(NH₃)₂  + (aq) Eo = 0.81 -0.37 = 0.44 V

By the Ernst equation,

E = E° - 0.0591 logkf

Now Kf is calculated at equilibrium and at equilibrium E = 0,

The number of transfer of electron is 1 ( 1 e-) , n=1

E° = 0.44 V

Substituting all the values in Ernst equation

0 - 0.44 - 0.0591/ 1 logkf

logkf = 0.44/ 0.0591

kf = 10 (0.44/ 0.0591)

Kf = 2.786 x 10⁷

Hence, Kf of Ag(NH₃)₂ for the given equation is 2.786 x 10⁷.

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what type of solution do you have if you dissolve 20.2 g of potassium chlorate in 0.300 L

Answers

solution of potassium chlorate,

K

C

I

O

3

, has 20 grams of the salt dissolved in 100 grams of water at 70 C. Approximately how many more grams of the salt can be added to the solution before reaching the saturation point?

3) During a chemical reaction, atoms are ________. A) destroyed B) created C) rearranged D) destroyed and created

Answers

Answer: C- rearranged

Explanation:

Answer:

C

Explanation:

How many particles are there in 5 grams of sodium carbonate?

Answers

3.01× 1024 particles are the number of  particles are there in 5 grams of sodium carbonate.

How many particles are there in 5 grams of sodium carbonate?

There are 6.022 × 1023 particles in one gram of a substance according to Avogadro's number. So when we find out for 5 grams, then we multiply 5 with 6.022 × 1023, we get 3.01 × 1024 particles. For one gram atomic weight of hydrogen, one mole of hydrogen contains 6.022 × 1023 hydrogen atoms.

So we can conclude that 3.01× 1024 particles are the number of  particles are there in 5 grams of sodium carbonate.

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A solution is made by dissolving 6.93 grams of lead(II) nitrate into about 50 mL of water. The volume is then precisely brought up to 100 mL and the solution is saved as stock solution. A 50.0 mL aliquot* of this stock solution is then titrated with 0.222 M sodium phosphate. What would be the minimum number of milliliters (mL) of the the phosphate solution that are needed to completely precipitate (knock out) all the lead in this aliquot? (tolerance is ±0.1 mL)

Answers

6.32mL of phosphate solution is needed to completely neutralize the lead in this reaction.

What is a neutralization reaction?

A neutralization reaction is defined as the reaction between an strong acid and strong base to produce a salt and water.

The process of the reacting given volume of acids or bases for the determination of the concentration or volume of the acid or base which is required for neutralization is known as titration in volumetric analysis.

The formula used to determine the volume of the acid is given below:

(Ca × Va) /(Cb × Vb) = Na/Nb

where,

where Ca is the concentration of lead nitrate

Cb is the concentration of sodium phosphate

Va is the volume of lead nitrate

Vb is the volume of sodium phosphate

Na is the moles of lead nitrate

Nb is the moles of sodium phosphate

Concentration of lead nitrate = m/V

= 6.931/(0.1 × 331.2)

= 0.0281 M

Ca = 0.222M

Cb = 0.0281M

Na = Nb = 1

Va = ( 0.0281 × 50) /0.222

= 6.32 mL.

Thus, 6.32mL of phosphate solution is needed to completely neutralize the lead in this reaction.

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9.0 mol Na2S can from 9.0 mol CuS and 8.0 mol CuSO4 can form 8.0 mol Cus.
What mass of Cus forms during the reaction?
Cus; 95.62 g/mol

Answers

Answer:

765.0 grams CuS

Explanation:

The limiting reagent is the reactant which completely reacts before the other reactant(s) is used up. When 9.0 moles Na₂S and 8.0 moles CuSO₄ react, it appears that CuSO₄ is the limiting reagent. You can tell because it results in the production of less product.

You can determine the mass of CuS by multiplying the moles by the molar mass. It is important to arrange the ratio in a way that allows for the cancellation of units.

Molar Mass (CuS): 95.62 g/mol

8.0 moles CuS               95.62 g
-------------------------  x  -----------------------  =  765.0 grams CuS
                                         1 mole

Rutherford’s gold foil experiment gave evidence that an atom is mostly empty space. true false

Answers

The given statement is true .

What is Rutherford’s gold foil  experiment?A piece of gold foil was hit with alpha particles, which have a favorable charge. Most alpha particles went right around. This showed that the gold particles were mostly space.The Rutherford gold leaf investigation supposed that most (99%) of all the mass of an atom is in the middle of the atom, that the nucleus is very small (105 times small than the length of the atom) and that is positively captured.For the distribution experiment, Rutherford enjoyed a metal sheet that could be as thin as practicable. Gold is the most malleable of all known metals. It can easily be converted into very thin sheets. Hence, Rutherford established a gold foil for his alpha-ray scattering experimentation.

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How many minutes would be required to produce a mass of 6. 38 g al using a current of 12. 50 amps?

Answers

To produce a mass of 6. 38 g al using a current of 12. 50 amps the time required would be 7207.4 minutes.

What is faraday law?

It states that the chemical which is getting decomposed because of the flow of current within an electrolyte is directly proportional to the quantity of electricity passing through it.

                        W= Z × I × t    Z = 1 coulomb

                                               I = current

                                                t = time

substituting the values

                           Z= 96500/Eq.wt

​Al 3+ +3e − →Al n= 3

so, Eq= 27 / 3 = 9

t = W × Z / I

t = 9 × 96500 / 12.50

t = 7207.4 minutes.

Therefore the time required would be, 7207.4 minutes.

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Simon measured the density of a piece of metal
to be 11.70 g/cm³. However, the manufacturer
claims it has a density of 12.00 g/cm³. What is
the percent error of Simon's measurement?

Answers

From the question we know that 12 - 11.70 = 0.3  so 0.3 / 12 = 0.025 therefore Simon's percent error is 2.5%.

Percent error compares an estimate to an accurate value and expresses the difference among them as a percent. This statistic lets analysts recognize the scale of the mistake relative to the true cost. it's also referred to as percentage error as well as % mistakes.

Percentage errors Calculation Steps :

Subtract one cost from another.Divide the mistake by the exact or ideal price (not your experimental or measured value).Convert the decimal variety into a percentage by multiplying it by using 100.Add a percent or % symbol to record your percentage mistakes value.

Percentage error tells you the way huge your mistakes are when you degree something in an experiment. Smaller values suggest that you are close to the accepted or actual value. for instance, a 1% blunder means that you obtain very near the accepted value, whilst 45% means that you were pretty a long way off from the real value.

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How many neutrons are needed to initiate the fission reaction? u92235 ?10n⟶te52137 zr4097 210n

Answers

Neutrons are required. Atomic Radiation, Nuclear Graphite, and Effects

The fission reaction is often started by an impinging neutron, and each fission produces an average of 2.5 neutrons.

With the exception of the hydrogen nucleus, which has a single proton, neutrons are necessary for the stability of nuclei. Nuclear fission and fusion generate a tonne of neutrons.

Scattering tests and research on nuclear binding energies provide evidence for the nuclear forces' finite range. The neutron-proton (n-p) potential energy map in Figure 44.3a, which was created by scattering neutrons from a target containing hydrogen, illustrates the short range of the nuclear force. The n-p potential energy well is 40 to 50 MeV deep, and the nucleons are prevented from getting much closer than 0.4 fm by a strong repulsive component.

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We need to add one neutron to initiate the fission reaction.

What are nuclear reactions?

The reaction in which the identity or characteristics of an atomic nucleus change due to the bombarding of it with an energetic particle is known as a nuclear reaction.

The bombarding particle can be an alpha particle, a gamma-ray photon, a neutron, a proton, or a heavy ion.

What is nuclear fission?

In nuclear fission, an atom splits into lighter nuclei due to the bombarding of an energetic particle.

The reaction given is

[tex]_{92}^{235}U + .... _{0}^{1}n \rightarrow _{52}^{137}Te + _{40}^{97}Zr +_{0}^{1}n[/tex]

To find the number of neutrons we have to balance the reaction

Atomic mass on reactant side = 235 + 1 = 236

The atomic number on the reactant side = 92

Atomic mass on the products side = 137+97+2 = 236

The atomic number on the products side = 92

As the reaction is already balanced

We need to add one neutron to initiate the fission reaction.

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The _____ is the mass of tissue lying beside the fetus that allows nutrients and oxygen to pass from the mother's blood to the baby's blood

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A sizable organ that grows during pregnancy is the placenta. It is typically at the top or side of the uterine wall where it is attached. The placenta and your baby are joined by the umbilical cord. Through the placenta's filtering of the mother's blood and the umbilical cord, your baby receives oxygen, glucose, and other nutrients.

A sizable organ that grows during pregnancy is the placenta. It is typically at the top or side of the uterine wall where it is attached. The placenta and your baby are joined by the umbilical cord.

Blood from the mother filters oxygen, glucose, and other nutrients before traveling via the placenta and reaching your baby through the umbilical cord.

Blood from the mother filters oxygen, glucose, and other nutrients before traveling via the placenta and reaching your baby through the umbilical cord. Additionally, the placenta filters out elements that can be dangerous to your unborn child and eliminates waste products and carbon dioxide from your unborn child's blood.

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Risk premiums on corporate bonds tend to ________ during business cycle expansions and ________ during recessions, everything else held constant.

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Risk premiums on corporate bonds tend to decreases during business cycle expansions and increases during recessions, everything else held constant.

A bond that is sold for more than it is worth. when the prevailing interest rate is lower than the coupon rate.

Corporate bond risk premiums have become typically anticyclical, meaning they rise during recessions as well as fall throughout expansions of the business cycle.

Bonds that trade above their face value or cost more than their face value are referred to as premium bonds. Since its interest rate has been higher than those of the current market, a bond may trade at a premium. The bond's price may also increase as a result of the company's as well as the bond's credit ratings.

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The energy of the ground state in the bohr model is -13. 6 ev. the energy of the n = 2 is:_______

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Bohr's model explained the position of the electron, proton, and neutron in the atom of the element. The energy at the n = 2 level of the atom will be - 3.40 eV.

What is the principal quantum number (n)?

The principal quantum number (n) has been the distance of the electron of that atom in the nucleus and its energy in the structure. It can also be said to define the size of the atomic orbit.

n = 2 is the first excited state whose energy is calculated as:

Eₙ = − 13.6 ÷ n² eV

E₂ = - 13.6 eV ÷ 2²

= -3.40 eV

Therefore, -3.40 eV is the energy of electron at n = 2.

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Given substances f2, kr, cl2 and hbr rank them with respect to the highest boiling point?

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The Hbr has highest boiling point followed by Kr , [tex]Cl_{2}[/tex] and [tex]F_{2}[/tex] .

The Hbr has  highest boiling point due to presence of intermolecular H-bonding that is hydrogen bonding.

The electronegativity of bromine is greater than hydrogen atom. The electronegativity difference hydrogen atom and bromine atom is high. So, due to this a positive dipole is generated at hydrogen atom and partial negative charge, these partial charge is called dipole. In a HBr molecule one H-atom attracted by Br-atom of another atom by force of attraction and this partial force of attraction is called H-bonding.

Other all given molecules are arrange according to its molecular mass because boiling points is directly proportional to the molecular mass of molecule.

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Discuss potential advantages and disadvantages of using water as a solvent in organic chemistry.

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Potential advantages of using water as a solvent in organic chemistry are:

Natural resource, easy to obtain, lower cost.Avoiding biomass drying step.Facilitating recovery of inorganics contained in biomass.

Disadvantages of using water as a solvent in organic chemistry

Higher critical point, severe reaction conditions.Lower yields of water insoluble bio-oil.The bio-oil with higher oxygen content and lower calorific value.What is the most widely used liquefaction solvent?

Water is the most common liquefaction solvent. Not only is water an environmentally friendly solvent that is inexpensive and does not pollute the environment, but it also facilitates the recovery and recycling of inorganic matter contained in biomass in ionic form for eventual use as fertilizers.

Why is water called a universal solvent?Water dissolves many substances and is known as a universal solvent. We learned that, despite being a universal solvent, it can only dissolve polar molecules and that nonpolar molecules, even when mixed with water, form a separate layer.Many researchers around the world have studied the effect of liquefaction solvent type on the liquefaction behaviors of various biomasses, including lignocelluloses, algae, and sewage sludge.

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