A 750 kg car is stalled on an icy road during a snowstorm. A 1000 kg car traveling eastbound at 13 m/s collides with the rear of the stalled car. After being hit, the 750 kg car slides on the ice at 4 m/s in a direction 30 ∘ north of east.
A) What is the magnitude of the velocity of the 1000 kg car after the collision?
B) What is the direction of the velocity of the 1000 kg car after the collision?
C) Calculate the ratio of the kinetic energy of the two cars just after the collision to that just before the collision. (You may ignore the effects of friction during the collision.)

Answers

Answer 1

(a) The magnitude of the velocity of the 1000 kg car after the collision is 10.5 m/s.

(b) The direction of the velocity of the 1000 kg car after the collision is 8.2 ⁰ north west.

(c) The ratio of the kinetic energy of the two cars just after the collision to that just before the collision is 0.72.

Velocity of the 1000 kg after the collision

Apply the principle of conservation of linear momentum as follows;

Final velocity in x direction

m₁u₁  +  m₂u₂ = m₁v₁x  +  m₂v₂x

where;

m₁ is mass of 750 kg caru₁ is initial velocity of 750 kg massm₂ is mass of 1000 kg caru₂ is initial velocity of 1000 kg massv₁ is final velocity of 750 kg massv₂ is final velocity of 1000 kg mass

750(0) + 1000(13) = 750(4 cos 30)   +   1000v₂x

13000 = 2,598.1  +   1000v₂x

10,401.9 = 1000v₂x

v₂x  =  10.4 m/s

Final velocity in y direction

m₁u₁  +  m₂u₂ = m₁v₁y  +  m₂v₂y

750(0) + 1000(0) = 750(4 sin 30)   +   1000v₂y

0 = 1500 +  1000v₂y

v₂y  = -1500/1000

v₂y  = -1.5 m/s

Resultant final velocity

v = √(v₂ₓ² + v₂y²)

v = √[(10.4)² + (-1.5)²]

v = 10.5 m/s

Direction of the final velocity of 1000 kg car

tanθ = v₂y/v₂ₓ

tanθ = -1.5/10.4

tanθ =  -0.144

θ = arc tan(-0.144)

θ = 8.2 ⁰ north west

Kinetic energy of the cars before the collision

K.Ei = 0.5m₁u₁²  +  0.5m₂u₂²

K.Ei = 0.5(750)(0)²  +  0.5(1000)(13)²

K.Ei = 84,500 J

Kinetic energy of the cars after the collision

K.Ef = 0.5(750)(4)²  +  0.5(1000)(10.5)²

K.Ef = 61,125 J

Ratio of the kinetic energy

K.Ef/K.Ei = 61,125/84,500

K.Ef/K.Ei = 0.72

Thus, the magnitude of the velocity of the 1000 kg car after the collision is 10.5 m/s.

The direction of the velocity of the 1000 kg car after the collision is 8.2 ⁰ north west.

The ratio of the kinetic energy of the two cars just after the collision to that just before the collision is 0.72.

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Related Questions

As mass increases, which of the following is always true?
a. volume decreases
b. density decreases
c. inertia increases
d. all of these

Answers

As mass increases, the following which is found to be always true is a corresponding increase in the inertia and is therefore denoted as option C.

What is Inertia?

This is defined as the property of a body to resist changes in velocity or motion. Such feature is characterized by the body having the tendency to remain at rest or in uniform motion unless an external force acts on it.

When mass increase, inertia also increases due to the large amount of force which is needed to change the direction or motion of a body in this scenario. On the other hand, when mass decreases, there is a corresponding decrease in the inertia which is present in a given body over a period of time.

This is therefore the reason why mass of a body is directly proportional to its inertia and makes it the most appropriate choice.

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If a body has a velocity 50 m s-1
and the uniform acceleration is 5 m s-2, find the time it takes to travel a distance
of 240 m.

Answers

Answer:

Using the relation V^2 = U^2 + 2× a× S

V^2 = 50^2 + (2× 5 × 240 )

V^ 2 = 2500 + 2400

V^ 2 = 4900

V= (4900)^0.5 = 70 m/s

hence, velocity at a distance of 240 m will be 70m/s.

Now using the relation,

V= U + a× t

70 = 50 + 5 × t

20 = 5 × t

t = 20/5 = 4m/s

hence , time required to travel a distance of 240m will be 4s.

The magnitude of the net torque

Answers

Answer:

The magnitude of a torque about a fixed axis is calculated by finding the lever arm to the point where the force is applied and using the relation |→τ|=r⊥F | τ → | = r ⊥ F , where r⊥ is the perpendicular distance from the axis to the line upon which the force vector lies.

Explanation:

:)

Explain the changes that occur during upstoke and downstoke of water pump with diagram​

Answers

Answer: Downstroke: When the handle of a water pump is lifted up, the piston is pushed down. It is downstroke of the piston. In this condition, the volume of part A decreases and water pressure increases in this part. The increased pressure shuts the valve ‘A’ and opens the valve ‘B’ It makes the water of part A into pass part B of the cylinder.

Upstroke: When the handle is pushed down, it lifts the piston up. It is upstroke. During upstroke, the volume of part A increases and water Downstroke Upstroke pressure at that part decreases. It makes valve A opened and valve B closed. Thus, the water from the source enters into part A of the cylinder. The water of part B is lifted up and it comes out from the spout.

Explanation:

How can i find Air velocity??????????????

Answers

Answer: By dividing airflow by duct cross section.

Explanation:

In short, air velocity in the ducts is calculated by dividing airflow by duct cross-section. Airflow is expressed as a simple number. Example: Air conditioner has a max. airflow of 600 CFM.

2. Three blocks, A,B and C of mass 2kg. 3kg. 5kg respectively kept side by side with one another are accelerated at 2m/s2 across a smooth horizontal surface by a force F evaluated the magnitude of F and what force the blocks exert on each other.​

Answers

Answer:

Total mass of combination = 2+3+5 = 10kg.

Acceleration produced = 2m/s^2

hence force =( total mass × acceleration)= (2×10)= 20 N.

Net force on 3kg block = acceleration × mass = (2 × 2 )= 4 N

applied force on 2 kg block = 20N

Force between 2 kg and 3 kg block = (20-4) = 16N. ans

Net force on 3 kg block = 3 × 2 =6N.

Applied force on 3 kg block due to 2 kg block = 16N.

hence, force between 3 kg and 5 kg block = (16-6) = 10N .

answers:-

(a) 20 N

(b) 16N

(c) 10 N

If the atomic mass of Sodium-18 is 18.02597 u, what is the binding energy?

Answers

Answer:

The binding energy of sodium Na=5.407791×10⁹J

Explanation:

Greetings !

Binding energy, amount of energy required to separate a particle from a system of particles or to disperse all the particles of the system. Binding energy is especially applicable to subatomic particles in atomic nuclei, to electrons bound to nuclei in atoms, and to atoms and ions bound together in crystals.

Formula : Eb=(Δm)c²where:Eb= binding energy .Δm= mass defect(kg) c= speed of light 3.00×10⁸ms¯¹Given valuesm= 18.02597c=3.00×10⁸ms¯¹

required valueEb=?

Solution:Eb=(Δm)c²Eb=(18.02597)*(3.00*10⁸ms¯¹Eb=5.407791*10⁹J

what is buoyant force​

Answers

Answer:

When an object is immersed in water. it is pulled downwards due to gravitational pull of earth. Water exerts upward force on the object. This makes object rise up. This upward force is called buoyancy or upthrust.

Which of the following is a force acting between objects that do not touch? Pls answer in 5-10 min!
Normal force
Frictional force
Electrical force
Applied force

Answers

Answer:

Electrical force

Explanation:

The electrons aren't actually touching each other. Normal is something on something pushed by gravity by they are touching, frictional is rubbing, applied is pushing

At the very end of 500 DAYS OF SUMMER, Tom (Joseph Gordon-Levitt) is so heartbroken by
Summer's rejection, that he vows to avoid any more romantic entanglements. As he observes "There
are no miracles. There's no such thing as fate. Nothing's meant to be."
True
False

Answers

He observes that "There are no miracles. There's no such thing as fate. Nothing's meant to be." this is a false statement.

What is the Definition of miracle?

The term miracle is known to be something that is said to be an extraordinary event and it is one that often manifest in a kind of a divine intervention in the lives and affairs of human such as healing miracles, miracle jobs, miraculous meeting, etc.

Note that bad things that happens to people often makes them not to believe in the extraordinary but it does exist.

Hence, He observes that "There are no miracles. There's no such thing as fate. Nothing's meant to be." this is a false statement.

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Why do planets speed up as they get closer to the sun?:
A. air resistance
B. friction
C. gravity
D. tension

Answers

Answer:

C

Explanation:

Gravity is the main reason that make our planets to pull each other

A sensor that generates voltages in the range of -2V..+2V for 0..400kg weight values Design a balance circuit with LCD display. ; fosc=4MHz​

Answers

39-72 may it not nah he 472=5

Show that time period of revolution an electron beam in uniform magnetic field is independent of velocity and radius of path

Answers

Since T = 2πm/Be the period of revolution of the electron is independent of velocity and radius of path

How to show that time period of revolution an electron beam in uniform magnetic field is independent of velocity and radius of path?

For an electron moving in a uniform magnetic field, the force on the electron is given by

F = Bev where

B = magnetic field, e = electron charge and v = speed of electron

Also, this magnetic force equals the centripetal force on the electron, F'

F' = mv²/r where

m = mass of electron, v = speed of electron and r = radius of path

Since both forces are equal,

F = F'

Bev = mv²/r

Be = mv/r

We know that angular speed, ω = v/r. So,

Be = mω

Also, angular speed, ω = 2π/T where T = period of revolution of electron

So, Be = m2π/T

Making T subject of the formula, we have

T = 2πm/Be

so, since T = 2πm/Be the period of revolution of the electron is independent of velocity and radius of path

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Complete the missing information from the circuit

Answers

From the first circuit (see attached), it is correct to state that I₄ = 40mA. See the explanation below.

What is a circuit?

A path that is designed to transport electric current is that is referred to as a circuit.

How do we compute for the missing details?

I = 200mA

= 20mA + 140mA + I₄

I₄ = 200 - 160

I₄ = 40mA

From the above, we can rightly posit:

R₄ = 3/(40x 10⁻³)

= 75 Ω

Hence

V₆ =  V₄ - V₅

= 3v - 2v

= 1v

R₆ therefore, =

V₆/I₆

= 1/ (40 x 10 ⁻³)

= 14.28 Ω

I₃ = I₄ + I₆

= 40 + 140

= 180mA

R₃ = 9/(180 x 10⁻³)

= 50Ω

R₂ = 12/20 x (10⁻³)

= 60 Ω

Then,

Vbattery =

200 x 10⁻³ x90

= 18 volts

The above indices is used to complete the image. See Circuit Image II.

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Please help, Class ends today!! will give brainiest if correct.
Fill in the blanks with agree or disagree
A list of planet-star radius ratios is an example of evidence.
I ____________ with this statement
Explain your answer, using an example from your investigation about habitable worlds.

Answers

A list of planet-star radius ratios is an example of evidence. I agree with this statement.

Why do i agree with the statement above?

I agree with A list of planet-star radius ratios is an example of evidence because the Sample records that are taken for planet-star radius ratio are known to often gives a kind of an improved approximate of the stellar characteristics in regards to the smallest stars in the Kepler target list.

What does a planets radius mean?

The planetary radius is known to be the distance that exist between a what we see as planet's center and its surface.

Therefore, one can say that planetary radius is known to be a measure of a given planet's size.

So, A list of planet-star radius ratios is a sample evidence and I do affirm the above  statement.

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method to separate the .
sand+iron fillings​

Answers

Answer:

by using a magnetic field

Use a magnet to attract the iron fillings from the sand!

Hope this helps!

Examine the roller coaster track above. Assume there is negligible friction as the roller coaster moves from position A to position F. Also assume that the roller coaster has minimal kinetic energy at point A. Create three different models below to describe the kinetic energy, the potential energy, and the total energy of the roller coaster at point E. Examples of models include, but are not limited to: pie charts, bar graphs, equations, textual descriptions, and analogies.

Answers

At point E

the kinetic energy of the rollercoaster is small compared to the potential energythe potential energy is greater than the kinetic energythe total energy is a mixture of potential and kinetic energy

What is the energy of the roller coaster at point E?

The energy of a roller coaster could either be potential energy, kinetic energy or a combination of both potential and kinetic energy.

Using analogies, the energy of the roller coaster at point E can be compared to a falling fruit from a tree which falls onto a pavement and is the rolling towards the floor. Point E can be compared to the midpoint of the fall of the fruit.

At point E

the kinetic energy of the rollercoaster is small compared to the potential energythe potential energy is greater than the kinetic energythe total energy is a mixture of potential and kinetic energy

In conclusion, the energy of the rollercoaster at E is both Kinetic and potential energy,

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A centrifuge in a medical laboratory rotates at an angular speed of 3,750 rev/min. When switched off, it rotates through 48.0 revolutions before coming to rest. Find the constant angular acceleration (in rad/s²) of the centrifuge.


______rad/s²

Answers

The constant angular acceleration (in rad/s²) of the centrifuge is 255.66 rad/s².

Constant angular acceleration of the centrifuge

The constant angular acceleration of the centrifuge is calculated as follows;

ωf² = ωi² - 2αθ

where;

ωf is the final angular velocity ωi is initial angular velocityθ is angular displacementα is angular acceleration

When the centrifuge is switched off, the final angular velocity = 0

Initial angular velocity: ωi = 3,750 rev/min x 2π rad/rev x 1 min/60 s = 392.7 rad/s

angular displacement: θ = 48 rev = 48 rev x 2π rad/rev = 301.6 rad

0 = ωi² - 2αθ

2αθ = ωi²

α = ωi²/2θ

α = (392.7²) / (2 x 301.6)

α = 255.66 rad/s²

Thus, the constant angular acceleration (in rad/s²) of the centrifuge is 255.66 rad/s².

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A uniform linear charge of 3.0 nC/m is distributed along the y axis from y = -3 m to y=2m. Which of the following integrals is correct for the magnitude of the electric field at y = 4 m on the y axis?

Answers

[tex]E = \int\limits^2_{-3} {} \, \frac{27dy}{( 4 - y)^2}[/tex] is the integrals for the magnitude of the electric field.

A characteristic of electricity exists at every location in space when charge of any kind is present. The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the strength and direction of the electric field.

The formula for the electric field due to a point charge is:

[tex]E = \frac{kq}{r^2}[/tex]

Here q is the charge, r is the distance from the charge, and k = 8.99 × [tex]10^9 Nm^2/ C^2[/tex]

Imagine an infinitely - tiny portion of this charge distribution that has a charge [tex]dq[/tex]. This charge produces an electric field dE with magnitude:

                           [tex]\int\limits^ {} \, dE = \int\limits^ {} \, \frac{k dq}{r^2}[/tex]

                               [tex]E = \int\limits^ {} \, \frac{k dq}{r^2}[/tex]

Here, λ = 3.0 nC/m dq

           = λ.dy dE = ∫k.dq

From y = -3 m to y = 2 m, there is a 3.0 nC/m uniform linear charge distributed along the y axis.

The integrals for the magnitude of the electric field at y = 4 m on the y axis:

[tex]E = k \lambda \int\limits^2_{-3} {} \, \frac{dy}{( 4 - y)^2}[/tex]

[tex]E = \int\limits^2_{-3} {} \, \frac{27dy}{( 4 - y)^2}[/tex]

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How much time is required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 10^5 km?

Answers

The amount of time required for reflected sunlight to travel from the moon to the earth according to the given distance between then and the speed of light is; 1.28 seconds.

How long does it take reflected sunlight to each the earth from the moon?

It follows from the task content that the time required for the reflected sunlight to reach the earth can be evaluated if the speed of light is known in which case, the speed of light, c = 3× 10⁸ m/s.

Consequently, we have time taken, t evaluated as follows;

Time taken, t = distance/speed

t = 3.85 ×10⁵ × 10³/3× 10⁸

t = 3.85/3

t = 1.28 seconds.

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Which of the following phrases describes power?
A. How much energy is lost in friction
B. How much energy is lost in heat
OC. The rate energy is consumed
OD. The rate an object is moving

Answers

The rate energy is consumed this statement describes power.

Hence, Option C is correct answer.

How can we understand that this statement can describe power?

Power is related to energy by that it is the rate at which energy is transferred.

What is Power ?

It is a measure of the rate at which work is done.

According to the definition of power, Power is the amount of energy transferred or converted or consumed per unit time.

SI unit of power is watt.

By definition, 1 watt is equal to one joule of work done per second. So if P represents power in watts, E is the change in energy (number of joules) and t is the time taken in seconds then:

P=[tex]\frac{E}{t}[/tex]= [tex]\frac{1 Joule}{1 Second}[/tex]= 1 Watt.

Thus from the above conclusion we can say that, The rate energy is consumed describes power.

Hence, Option C is correct answer

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Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.52 cm. If the potential difference across the plates was 24.0 kV, find the magnitude of the electric field (in V/m) in the region between the plates.

________V/m

Answers

The electric filed in V/m is 1.58 * 10^6 V/m

What is the electric field?

We know that the electric field is obtained as the ratio of the voltage to the distance that separates the plates.

Thus;

E = V/d

E = electric field

V = voltage

d = distance of separation

E = 24 * 10^3 V/1.52 * 10^-2 m

E = 1.58 * 10^6 V/m

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find the volume of the tire with dimensions
● Tire diameter: 26”
● Tube width diameter: 2.125”

Answers

The volume of the tire at the given diameter and thickness of tube is determined as  1,128.2 cubic inch.

What is volume?

Volume is a scalar quantity expressing the amount of three-dimensional space enclosed by a closed surface.

Volume of the tire

The volume of the tire is the measure of the product of area and thickness of the tire.

The volume of the tire is calculated as follows;

Radius of the tire = 0.5 x 26" = 13"

Volume of the tire = Area x thickness

Volume of the tire = πr² x h

where;

r is the radius of the tireh is the thickness of the tube

Volume of the tire = π(13)² x (2.125)

Volume of the tire =  1,128.2 cubic inch

Thus, the volume of the tire at the given diameter and thickness of tube is determined as  1,128.2 cubic inch.

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2. Two particles P and Q are shot vertically up. T
Particle P is first up with a velocity 40ms-¹. After
4s, particle Q is also shot up. Find 01 -
(a) where the two particles meet, if at the point of
meeting, P has velocity of 15ms™¹.
(b) the velocity with which Q is shot. (g = 10ms-²)
(000)(9)

Answers

Free Fall under gravity and time of meeting is used to find out the required answer.

∴ Let us assume, the upward direction to be positive and and downward direction to be negative.

Given, Velocity of P, = 40m/s

Distance travelled by P,

∴Using First Equation of motion for particle P,

v = u + at

⇒ 0 = 40 + (-10)t

⇒ t = 4s  ; which is the time taken by P to rise up

Now, Maximum Height(s) reached by particle P,

∴Using second equation of motion,

s = ut + 1/2at²

⇒ s = 40×4 + 1/2 × (-10) × 4²

⇒ s = 80m

a) Particle P is falling when Q is shot up after 4s from the initial time

∴ Using third equation of motion using Free Fall under Gravity,

V² = U² + 2aH₁

⇒ H₁ = 15² - 0/ 2(-10)

⇒ H₁ = 11.25m

Hence, Particle P and Q meet at a distance (H₂) from ground,

∴ Height, H₂ = s - H

⇒ H₂ = 80 - 11.25 = 68.75m

Hence, Particle P and Q meet at a distance of 68.75m from ground.

∴ Using First equation of motion for Particle P using the Time of Meeting,

v = u + at₁

⇒ 15 = 0 + (-10) t₁

⇒ t₁ = 1.5s  ; which is equal to the fall time of P and Rise time of Q

b) For particle Q

∴ Using second equation of motion,

H₂ = u₂t₁ + 1/2at₁

⇒ 11.25 = u₂ × 1.5 + 1/2 (-10) × 1.5

⇒ u₂ = 15 m/s

Hence, the Velocity with which Particle Q was shot is 15m/s in the upward direction.

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8- A bottle of water weighs 25 pounds. If the bottle weighs 5 pounds, how many gal does it contain ?​

Answers

A bottle of water weighs 25 pounds. If the bottle weighs 5 pounds, then it contains  0.599132136584 gal .

A bottle weighs 25 pounds ,

we know that 1 Gallon = 8.34 Lb

so, 25 lb = 2.995660682922 gal

and if the bottle weighs 5 pounds then ,

5 lb = 0.599132136584 gal

hence, 2.4 gal less.

Define pound.

a. a unit of weight equivalent to l6 ounces avoirdupois (453.59237 grams), the fundamental unit of weight in the FPS system;

b. a unit of weight equal to 12 ounces troy or 12 ounces apothecaries' (373.2418 grams).

It is an imperial unit of mass or weight measurement.

Define gallons.

In both imperial and US customary units, the gallon is a unit of volume.

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It is useful to use a _________ to demonstrate how an electric circuit works

Answers

It is useful to use a model in order to demonstrate how an electric circuit works.

What is a model?

In science, a model is a graphical representation that my result useful to predict the behavior of the components of a given system that works together to produce a particular outcome.

For example, an electrical circuit can be modeled by taking into account resistance, voltage, and intensity as parameters of functioning.

The electrical circuits are graphically represented by modeling the movement or flow of negatively charged electrons (e-) from the negative pole to the positive pole of a closed electric circuit.

In conclusion, it is useful to use a model (ie., a scientific model) to demonstrate how an electric circuit works.

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Can we take water instead of clock oil in Milikan oil drop experiment. Explain.​

Answers

Answer:

No you can't cuz,if you put water instead of clock oil in Millikan oil drop your experiment will fail and it won't turn out the way you wanted it to be

7. Four perpendicular forces, 2 N, 3 N, 9 N and 10 N act on object P as shown in Diagram 2. 10 N A B 9 N 3 N 2 N P Diagram 2 What is the magnitude of the resultant force? 10 N C 18 N 14 N D 20 N​

Answers

Answer: R=

A

2

+B

2

+2ABcosθ

θ=90

o

cos90

o

=0

R=

A

2

+B

2

=

3N

2

+4N

2

=5N

Explanation:

(a) Convert 45.0° to radians.
_______ rad

(b) Convert 13.0 rad to revolutions.
________ rev

(c) Convert 76.5 rpm to rad/s.
__________ rad/s

**Remember that there are 2 in one revolution, and 60 seconds in 1 minute. rad/s

Answers

(a) Converting 45.0° to radians is 0.785 radian.

(b) Converting 13.0 rad to revolutions is 2.1 rev.

(c) Converting 76.5 revolution per minute to rad/s is 8.02 rad/s.

Degrees to radian

To convert 45.0 degrees to radians, we use the following method;

180⁰ = π radians

45⁰ = ?

= (45 x π)/180

= 0.785 radian

Radian to revolutions

2π radians = 1 rev

13 radians = ?

= (13)/(2π)

= 2.1 rev

Revolution per minute to radians per second

= 76.6 rev/min x 2π rad/rev x 1 min/60 s

= 8.02 rad/s

Thus, converting 45.0° to radians is 0.785 radian.

Converting 13.0 rad to revolutions is 2.1 rev.

Converting 76.5 revolution per minute to rad/s is 8.02 rad/s.

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When there is a imbalance in the body system and the body can’t maintain homeostasis how might other systems respond

Answers

Answer:

the stomach has too much oxygen stored inside

Other Questions
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