The Laplace transform of the given function is [tex]f(s)=\frac{1-e^{-5s}(1-5s) }{s^{2} }[/tex]
Given,
[tex]f(t)=\left \{ {{t, 0\leq t < 5} \atop {0,t\geq 5}} \right.[/tex]
Write the function in unit step function.
[tex]f(t)=t(u_{0}(t)-u_{5} (t))[/tex]
= [tex]t(1-u_{5}(t))[/tex] ∵[tex]u_{0} (t)=1[/tex]
= [tex]t-tu_{5} (t)[/tex]
[tex]f(t)=t-tu_{5} (t)[/tex]
In order to make it easier to take the Laplace transform of the function, we can follow the steps:
[tex]f(t)=t-tu_{5} (t)[/tex]
= [tex]t-(t-5+5)u_{5} (t)[/tex]
= [tex]t-(t-5)u_{5} (t)+5u_{5} (t)[/tex]
[tex]f(t)=t-(t-5)u_{5} (t)+5u_{5} (t)[/tex]
We need to find the Laplace transform of f(t).
Apply Laplace transform on both sides,
£[tex][f(t)=[/tex]£[tex](t)-[/tex]£[tex](t-5)u_{5} (t))+5[/tex]£[tex](u_{5} (t))[/tex]
= [tex]\frac{1}{s^{2} } -e^{-s}[/tex]£[tex](t)+5(\frac{e^{-5s} }{s} )[/tex]
= [tex]\frac{1}{s^{2} } -e^{-5s} (\frac{1}{s^{2} } )+\frac{5se^{-5s} }{s^{2} }[/tex]
= [tex]\frac{1-e^{-5s}+5se^{-5s} }{s^{2} }[/tex]
= [tex]\frac{1-e^{-5s}(1-5s) }{s^{2} }[/tex]
[tex]f(s) =\frac{1-e^{-5s}(1-5s) }{s^{2} }[/tex]
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Determine whether the given set of functions is linearly independent on the interval (−[infinity], [infinity]). f1(x) = x, f2(x) = x2, f3(x) = 6x − 2x2 linearly dependent linearly independent
The given set of functions are not linearly independent.
Given,
[tex]f_{1} (x) = x\\f_{2} (x) = x^{2} \\f_{3} (x) = 6x-2x^{2}[/tex]
We need,
[tex]c_{1} f_{1} (x)+c_{2} f_{2} (x)+c_{3} f_{3}(x)=0[/tex]
Substituting the values in equation we get,
[tex]c_{1} x+c_{2} x^{2} +c_{3} (6x-2x^{2} )=0\\[/tex]
Computing the equation we get,
[tex]c_{1} x+c_{2} x^{2} +c_{3} 6x-c_{3} 2x^{2}=0[/tex]
[tex](c_{1} +6c_{3} )x+(c_{2} -2c_{3} x^{2} =0[/tex]
This resolves to two equations
[tex](c_{1} +6c_{3})x =0\\(c_{2} -2c_{3} )x^{2} =0[/tex]
These will have an infinite set of solutions:
[tex]c_{1} =-6c_{3} \\c_{2} =2c_{3}[/tex]
Two functions are said to be linearly independent if neither function is a constant multiple of the other.
Here, it is clear that the given functions are not linearly independent.
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PLEASE HELP IM STUCK PLS
Answer:
y is equal to -16
Answer:
y = 8
Step-by-step explanation:
We can use proportions for this question since y varies directly with x. This means that if x changes, y changes along with the x, and vice versa.
When y = -8, x = 4, so the proportion will be -8 : 4.
We need to find the y when x is 4, so our equation will be:
-8 : 4 = y : -4
Since the proportion will be the same.
Next, we multiply the inner two numbers, and the outer two numbers, saying that the values are the same.
4y = 32
y = 8
So y = 8 will be our answer!
A prism is created using 2 regular pentagons as bases. The apothem of each pentagon is 2.8 centimeters.
A regular pentagonal prism is shown. The apothem of each pentagon is 2.8 centimeters. The height of the prism is (2 x + 1). All sides of the pentagon are congruent.
Which expression represents the volume of the prism, in cubic centimeters?
9x2 + 7x
14x2 + 7x
16x2 + 14x
28x2 + 14x
the expression that represents the volume of the prism is 14x² + 7x cubic centimeters. Option 2
What is the volume of a pentagonal prism?The volume of a pentagonal prism is determined using the formula;
V = 5/2abh
where
a is the apothemh is the height of the prismb is the base of the prismNow, let's substitute the values given
Let the base be 'x'
The apothem is 2. 8 centimeters
height is 2x + 1
Volume = 5/ 2 × 2. 8 × x × (2x + 1)
Volume = 14/ 2 × x(2x + 1)
Volume = 7x(2x + 1)
Volume = 14x² + 7x
Thus, the expression that represents the volume of the prism is 14x² + 7x cubic centimeters. Option 2
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What expression represents the volume of the prism, in cubic units? one-halfx3 one-halfx2 x 2x3 2x2 x
Volume of prism = [tex]\frac{1}{2x^{3} } + x^{2}[/tex]
Given that:
The oblique prism below has an isosceles right triangle base and the length of the base is x
=> the area of the base: [tex]\frac{1}{2}[/tex] × x × x = [tex]\frac{1}{2}[/tex]
The vertical height of the prism is (x + 2)
=> The volume of the oblique prism is:
V = the base area * the vertical height
<=> V = [tex]\frac{1}{2}[/tex] [tex]x^{2}[/tex] (x + 2)
<=> V = [tex]\frac{1}{2x^{3} } + x^{2}[/tex]
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If amy cuddy and her research team originally established a sample size of n=200 (100 in each group) and then discovered that 86% of the high-power group (86 of 100) took a gambling risk while 60% of the low-power group (60 of 100) took the risk, then the p-value would have been much lower than that originally found in question 1. this p-value would have been less sensitive and would have provided stronger evidence for the researcher's hypothesis. state the p-value, rounding to 5 decimal places.
The p-value that would be given as the evidence would be given as p-value = 0.00002 and also P value = 0.00003
How to solve for the p valueThe sample size of the first sample = 100
x1 = success 0f 86%
We have to find the proportion of this = 0.86
The sample size of the second sample n2 = 100
x12 = success 0f 60%
We have to find the proportion of this = 60/100
= 0.6
The difference = 0.86-0.6= 0.26
Next we have to find the pooled proportion. This is taken given as p = (x1+x2)/(n1+n2) this gives us 0.73
Next we have to find the standard error
= √(p*(1-p)*(1/n1+ 1/n2)= 0.06279
Z stat = (0.26-0)/0.0628= 4.1411
From here the p value would have to be
p-value = 0.00002 and also
P value = 0.00003
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The SkyWheel has 42 glass enclosed gondolas. What is the measure of each central angle between gondola cars, to the nearest hundredth degree? (just write the numerical answer, no units) (5 points)
Answer:
8.57.
Step-by-step explanation:
that would be 360/42
= 8.5714
(8x2-4x-8)(2x2+3x+2)
Answer: 12x squared + 2x + 96
Step-by-step explanation: We first simplify the parentheses. 8x2 = 16 - 4x - 8 = 16-8-4x = 8-4x. 2x2 = 4 +3x+2 = 4+2+3x = 6+3x. So, we are left with (16-4x)(6+3x). We rearrange the problem so it looks like this: (-4x + 16)(3x + 6). -4x(3x+6) + 16(3x+6). Now we just multiply. And, we get 12 x squared + 2x + 96
Consider this function. f ( x ) = 1 /2 x + 1 /4 Which graph represents the inverse of function f? Which graph represents the inverse of function f?
The inverse function of f(x) = 1/2x + 1/4 is f-1(x) = 2x - 1/2
How to determine the graph of the inverse function?The function is given as:
f(x) = 1/2x + 1/4
Rewrite the function as
y = 1/2x + 1/4
Swap the positions of x and y
x = 1/2y + 1/4
Multiply through by 4
4x = 2y + 1
Subtract 1 from both sides
2y = 4x - 1
Divide by 2
y = 2x - 1/2
Rewrite as an inverse function
f-1(x) = 2x - 1/2
Hence, the inverse function of f(x) = 1/2x + 1/4 is f-1(x) = 2x - 1/2
See attachment for the graph of the inverse function
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Answer:
Step-by-step explanation:
e graph opens upward, and it has a vertex of (0,0)
What is vertex?
The vertex of an equation is the minimum or the maximum point on the graph of the equation
The equation of the graph is given as:
The above equation represents an absolute value function
An absolute value function is represented as:
So, by comparison, we have:
This means that the graph opens upward, and it has a vertex of (0,0)
See attachment for the graph of
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Quick algebra 1 question for 10 points!
Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!
Answer: y ≥ [tex]\frac{3}{2}[/tex]x + 3
Step-by-step explanation:
Since the shaded area is above the line, we will use either > or ≥ for our inequality.
Next, since this is a solid line we will use the ≥ symbol for our inequality. This means the answer is the first option.
Pretest: Unit 3
Question 12 of 28
A ladder leans against a 15-foot-tall building to form a right triangle. The
ladder is placed so it is 8 feet from the base of the building. What is the
length of the ladder?
A. 289 ft
OB. 17 ft
O C. 13 ft
D. 161 ft
←BREMQU
Building
15 ft
Ladder
8 ft
42
XA
18
Complete the ratio table to convert the units of measure from ounces to grams or grams to ounces.
Ounces Grams
111 282828
333
140140140
The ratio illustrates that the values will be 3146.7945 gram, 9440.3835 gram, and 3968.93 grams.
How to illustrate the information?It should be noted that 1 ounce is equivalent to 28.3495 gram.
Therefore, 111 ounces will be:
= 111 × 28.3495 gram
= 3146.7945 gram
333 ounces will be:
= 333 × 28.3495 gram
= 9440.3835 gram
140 ounces will be:
= 140 × 28.3495 gram
= 3968.93 grams
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Complete the equation.
2 x 4 =
x 2
2x4=8
8x2=16
the answer is 16
Find the first four partial sums, s1,s2,s3,s4, and the nth partial sum of the squence an=log(nn+1).
The first four partial sums of the sequence are S₁ = 0.3010, S₂ = 0.9999, S₃ = 2.447, S₄ = 4.8569.
In this question,
A sequence is a set of things (usually numbers) that are in order. A partial sum is the sum of part of the sequence.
The sequence is [tex]a_{n} =log(n^{n}+1 )[/tex]
The first four partial sum S₁, S₂, S₃, S₄ can be calculated by substituting n = 1,2,3,4 in the sequence.
S₁ can be calculated as
S₁ = a₁
⇒ [tex]a_{1} =log(1^{1}+1 )[/tex]
⇒ [tex]a_{1} =log(1+1 )[/tex]
⇒ [tex]a_{1} =log(2 )[/tex]
⇒ [tex]a_{1} =0.3010[/tex]
Now, S₁ = 0.3010
S₂ can be calculated as
S₂ = a₁ + a₂
⇒ [tex]a_{2} =log(2^{2}+1 )[/tex]
⇒ [tex]a_{2} =log(4+1 )[/tex]
⇒ [tex]a_{2} =log(5 )[/tex]
⇒ [tex]a_{2} =0.6989[/tex]
Now, S₂ = 0.3010 + 0.6989
⇒ S₂ = 0.9999
S₃ can be calculated as
S₃ = a₁ + a₂ + a₃
⇒ [tex]a_{3} =log(3^{3}+1 )[/tex]
⇒ [tex]a_{3} =log(27+1 )[/tex]
⇒ [tex]a_{3} =log(28)[/tex]
⇒ [tex]a_{3} =1.4471[/tex]
Now, S₃ = 0.3010 + 0.6989 + 1.4471
⇒ S₃ = 2.447
S₄ can be calculated as
S₄ = a₁ + a₂ + a₃ + a₄
⇒ [tex]a_{4} =log(4^{4}+1 )[/tex]
⇒ [tex]a_{4} =log(256+1 )[/tex]
⇒ [tex]a_{4} =log(257 )[/tex]
⇒ [tex]a_{4} =2.4099[/tex]
Now, S₄ = 0.3010 + 0.6989 + 1.4471 + 2.4099
⇒ S₄ = 4.8569
Hence we can conclude that the first four partial sums of the sequence are S₁ = 0.3010, S₂ = 0.9999, S₃ = 2.447, S₄ = 4.8569.
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Jason left a bin outside in his garden to collect rainwater. he notices that 1 over 5 gallon of water fills 2 over 3 of the bin. write and solve an expression to find the amount of water that will fill the entire bin
The amount of water that will serve the entire container exists 3/10 gallons.
What is an expression?An expression exists a sentence with a minimum of two numbers or
variables and at least one math function.
Given: 1 over 5 gallons of water serve 2 over 3 of the container.
(1/5) gallon / (2/3) container = x gallons / 1 container
cross-multiplying the above equation, we get
1/5 = (2/3)x
multiply both sides by the reciprocal of 2/3 = 3/2
(3/2) (1/5) = x = 3/10 gallons serve the total container
Each 1/10 of a gallon serve 1/3 of the container
So 3(1/10) gallons serve 3(1/3)bins
3/10 gallons serve a whole container.
The amount of water that will serve the entire bin container exists 3/10 gallons.
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A company currently pays a dividend of $2.6 per share (d0 = $2.6). it is estimated that the company's dividend will grow at a rate of 24% per year for the next 2 years, and then at a constant rate of 8% thereafter. the company's stock has a beta of 1.8, the risk-free rate is 7.5%, and the market risk premium is 4.5%. what is your estimate of the stock's current price?
The stock's current price is 53.413455.
What is CAPM ?
The capital asset pricing model (CAPM) is an idealized portrayal of how financial markets price securities and thereby determine expected returns on capital investments. The model provides a methodology for quantifying risk and translating that risk into estimates of expected return on equity.The capital asset pricing model (CAPM) to know the value of the stock
[tex]Ke = rf + \beta ( r_{m} - r_{f} )[/tex]
risk free = 0.085
premium market =(market rate - risk free) = 0.045
beta(non diversifiable risk) 1.3
Ke = 0.085 + 1.3(0.045)
Ke = 0.14350
Now we need to know the present value of the future dividends:
D0 = 2.8
D1 = D0 × ( 1 +g ) = 2.8 = 2.8 * 1.23 = 3.444
D2 3.444 x 1.23 = 4.2361200
The next dividends, which are at perpetuity will we solve using the dividned grow model
[tex]\frac{divends}{return - growth} = Intrinsic value[/tex]
In this case dividends will be:
4.23612 x 1.07 = 4.5326484
return will be how return given by CAPM and g = 7%
plug this into the Dividend grow model.
[tex]\frac{4.5326484}{0.1435 - 0.07} = Intrinsic value[/tex]
value of the dividends at perpetity: 61.6686857
Finally is important to note this values are calculate in their current year. We must bring them to present day using the present value of a lump sum:
[tex]\frac{principal}{(1 + rate)^{time} } = PV[/tex]
[tex]\frac{3.444}{(1 + 1. 1435)^{1} } =PV[/tex]
3.011805859
[tex]\frac{4.23612}{( 1 + 0.1435)^{2} } = PV[/tex]
3.239633762
[tex]\frac{61.6686857}{(1 + 0.1435)^{2} } = PV[/tex]
47.16201531
We add them and get the value of the stock is 53.413455.
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The following data are the temperatures of effluent at discharge from a sewage treatment facility on consecutive days: Sample No.1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 Temperature 40 45 49 47 52 45 51 46 44 48 51 50 56 44 48 50 49 50 46 46 49 49 51 50 Use the data above to calculate the descriptive statistics.
The descriptive statistics for the above data is given as follows:
X = 12.5
What is Descriptive Statistics?
A set of concise descriptive coefficients that describe a particular data set indicative of a whole or sample population is known as descriptive statistics.
For X (mean) = [tex]{\displaystyle X={\frac {1}{n}}\sum _{i=1}^{n}X_{i}[/tex]
= 300/24
= 12.5
For sample variance = [tex]s^2 = \frac{1}{n-1}\biggl[\, \sum_{i=1}^n X_i^2 - \frac{\Bigl(\,\sum\limits_{i=1}^n X_i\Bigr)^{\!2}}{n} \biggr][/tex]
= (1/(24-1) (4,900 - (300²/24)
= 50
Standard deviation s = √s²
= √50
= 7.0711
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_______ 2. Find the length of PQ
A. 4.5π units
B. 9π units
C. 54π units
D. 12π units
Answer:
D
Step-by-step explanation:
Pq=opp/hyp
(135+12)=180
I dont know this, please can someone help
The table of values for y=1/2x-1 is completed as follows:
x y
-2 -2
-1 -3/2
0 -1
1 -1/2
2 0
3 1/2
Exactly one value from the set of second components of the ordered pair is connected with each value from the set of first components of the ordered pairs in a relation known as a function.
Given function: y=1/2x-1
For x = -2
Value of y = -2
For x = -1
Value of y = 1/2(-1)-1 = -3/2
For x = 0
Value of y = 1/2(0)-1 =-1
For x = 1
Value of y = 1/2(1)-1 = -1/2
For x = 2
Value of y = 0
For x = 3
Value of y = 1/2(3)-1 = 1/2
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30 POINTS HELP PLS!!!!!!!
i really hate how we actually have to type something.
Quick algebra 1 question for 10 points!
Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!
Answer:
[tex]\textsf{A. } y=3x^2+10x-8[/tex]
Step-by-step explanation:
We are given the information that a function has zeros at x = ⅔ and x = -4. In order to find the function that has those zeros, we can substitute the value of the zeros into each function. If the value of a function equates to zero with both values, then that is the function we are looking for.
..................................................................................................................................................
Standard Form of a Quadratic: ax² + bx + c = 0.
..................................................................................................................................................
[tex]\large \text{$y = 3x^2+10x-8 \implies 0=3x^2+10x-8$}[/tex]
[tex]\boxed{\begin{minipage}{15 em}{\text{$x=\dfrac{2}{3}$}} \\ \\\implies 0=3\left(\dfrac{2}{3}\right)^2+10\left(\dfrac{2}{3}\right)-8\\\\\implies 0=3\left(\dfrac{4}{9}\right)+10\left(\dfrac{2}{3}\right)-8\\\\\implies 0=\not{3}\left(\dfrac{4}{\not{9}\ 3}\right)+\dfrac{20}{3}-8\\\\\implies 0=\dfrac{4}{3}+\dfrac{20}{3}-8\\\\\implies 0=\dfrac{24}{3}-8\\\\\implies 0=0\ \checkmark\end{minipage}}[/tex] [tex]\boxed{\begin{minipage}{15 em}{\text{$x=-4$}} \\ \\\implies 0=3(-4)^2+10(-4)-8\\\\\implies 0=3(16)-40-8\\\\\implies 0=48-48\\\\\implies 0=0\ \checkmark\end{minipage}}[/tex]
..................................................................................................................................................
[tex]\large \text{$y = 2x^2-5x-12 \implies 0=2x^2-5x-12$}[/tex]
[tex]\boxed{\begin{minipage}{15 em}{\text{$x=\dfrac{2}{3}$}} \\ \\\implies 0=2\left(\dfrac{2}{3}\right)^2-5\left(\dfrac{2}{3}\right)-12\\\\\implies 0=2\left(\dfrac{4}{9}\right)-\dfrac{10}{3}-12\\\\\implies 0=\dfrac{8}{9}-\dfrac{10}{3}-12\\\\\implies 0=\dfrac{8}{9}-\dfrac{10\times3}{3\times3}-\dfrac{12\times9}{9}\\\\\implies 0=\dfrac{8}{9}-\dfrac{30}{9}-\dfrac{108}{9}\\\\\implies0=-\dfrac{22}{9}-\dfrac{108}{9}\\\\\implies 0=-\dfrac{130}{9}\ \textsf{X}\end {minipage}}[/tex] [tex]\boxed{\begin{minipage}{15 em}{\text{$x=-4$}} \\ \\\implies 0=2(-4)^2-5(-4)-12\\\\\implies 0=2(16)+20-12\\\\\implies 0=32+20-12\\\\\implies 0=40\ \textsf{X}\end{minipage}}[/tex]
..................................................................................................................................................
[tex]\large \text{$y = 2x^2+5x-12 \implies 0=2x^2+5x-12$}[/tex]
[tex]\boxed{\begin{minipage}{15 em}{\text{$x=\dfrac{2}{3}$}} \\ \\\implies 0=2\left(\dfrac{2}{3}\right)^2+5\left(\dfrac{2}{3}\right)-12\\\\\implies 0=\dfrac{8}{9}\right)+\dfrac{10}{3}-12\\\\\implies 0=\dfrac{8}{9}\right)+\dfrac{10\times3}{3\times3}-\dfrac{12\times9}{9}\\\\\implies 0=\dfrac{8}{9}+\dfrac{30}{9}-\dfrac{108}{9}\\\\\implies0=\dfrac{38}{9}-\dfrac{108}{9}\\\\\implies 0=-\dfrac{70}{9}\ \textsf{X}\end{minipage}}[/tex] [tex]\boxed{\begin{minipage}{15 em}{\text{$x=-4$}} \\ \\\implies 0=2(-4)^2+5(-4)-12\\\\\implies 0=2(16)-20-12\\\\\implies 0=32-32\\\\\implies 0=0\ \checkmark\end{minipage}}[/tex]
..................................................................................................................................................
[tex]\large \text{$y = 3x^2-10x-8 \implies 0=3x^2-10x-8$}[/tex]
[tex]\boxed{\begin{minipage}{15 em}{\text{$x=\dfrac{2}{3}$}} \\ \\\implies 0=3\left(\dfrac{2}{3}\right)^2-10\left(\dfrac{2}{3}\right)-8\\\\\implies 0=3\left(\dfrac{4}{9}\right)-\dfrac{20}{3}-8\\\\\implies 0=\not{3}\left(\dfrac{4}{\not{9}\ 3}\right)-\dfrac{20}{3}-8\\\\\implies 0=\dfrac{4}{3}-\dfrac{20}{3}-\dfrac{8\times3}{3}\\\\\implies 0=-\dfrac{16}{3}-\dfrac{24}{3}\\\\\implies 0=-\dfrac{40}{3}\ \textsf{X}\end{minipage}}[/tex] [tex]\boxed{\begin{minipage}{15 em}{\text{$x=-4$}} \\ \\\implies 0=3(-4)^2-10(-4)-8\\\\\implies 0=3(16)+40-8\\\\\implies 0=48+40-8\\\\\implies 0=80\ \textsf{X}\end{minipage}}[/tex]
..................................................................................................................................................
Therefore, the function whose zeros are ⅔ and -4 is [tex]y=3x^2+10x-8[/tex].
A portion of the Quadratic Formula proof is shown. Fill in the missing statement.
x²+x+
X+
a
X+
2a
b
2a
Statements
2a
2a
= ±₁
==
4ac b²
+
4a² 4a²
b²-4ac
4a²
b²-4ac
4a²
b²-4ac
4a²
?
Reasons
Find a common denominator on the right side of the equation
Add the fractions together on the right side of the equation
Rewrite the perfect square trinomial on the left side of the equation as a binomial squared
Take the square root of both sides of the equation
Simplify the right side of the equation
[tex]x+\frac{b}{2a}=\pm \frac{\sqrt{b^2 -4ac}}{2a}[/tex]
The lifeguards at the beach post information of surfers by placing 3 flags, one above the other, on a flag pole. If there are 8 different flags available, how many possible signals can be flown?
Answer:
336
Step-by-step explanation:
They can place 1 of 8 frags on the bottom.
Now they have 7 flags left.
They can place 1 of 7 flags in the middle.
Now they have 6 flags left.
The can place 1 of 6 flags on top.
8 × 7 × 6 = 336
BRAINLIEST!
On a number line, the coordinates of P and Q are 8 and 48, respectively. The midpoint of PQ is B, the midpoint of BQ is C, and the midpoint of PC is D. What is the coordinate of D?
Answer:
23 is the answer
Can anyone help me solve these linear systems using substitution?
1. 3x-y=4
x+2y=6
2. 2x-y= -39
x+y= -21
3. 2x+y =11
6x-5y =9
The system of the linear systems of equation using substitution is;
x = 2, y = 2 x = -20, y = -1Linear equation3x-y=4
x+2y=6
from (2)
x = 6 - 2y
substitute into (1)
3x-y=4
3(6 - 2y) - y = 4
18 - 6y - y = 4
- 6y - y = 4 - 18
-7y = -14
y = 2
Substitute into
x+2y=6
x + 2(2) = 6
x + 4 = 6
x = 6 - 4
x = 2
2. 2x-y= -39
x+y= -21
From (2)
x = -21 - y
substitute into
2x-y= -39
2(-21 - y) - y = -39
-42 - 2y - y = -39
- 2y - y = -39 + 42
- 3y = 3
y = 3/-3
y = -1
substitute into
x+y= -21
x + (-1) = -21
x - 1 = -21
x = -21 + 1
x = -20
3. 2x+y =11
6x-5y =9
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What is the measure of 28?
O 90⁰
O 60°
O 180°
O 120°
Answer: 120
Step-by-step explanation:
Answer:
B. 60°
Step-by-step explanation:
Angle 4 and angle 8 are equal. Find the measure of angle 4 to know the measure of angle 8.
∠4=∠8
180-120=60
∠4=60°
Since angle 4 equals 60 degrees, angle 8 also equals 60 degrees.
Hope this helps!
Pls help 15. Find the exact area of the shaded region of the circle shown in the diagram.
Answer:
The shaded region is 9.83 cm²Step-by-step explanation:
Refer to attached diagram with added details.
GivenCircle O with:
OA = OB = OD - radiusOC = OD = 2 cmTo findThe area of segment ADB.SolutionSince r = OC + CD, the radius is 4 cm.
Consider right triangles OAC or OBC:
They have one leg of 2 cm and hypotenuse of 4 cm, so the hypotenuse is twice the short leg.Recall the property of 30°x60°x90° triangle:
a : b : c = 1 : √3 : 2, where a- short leg, b- long leg, c- hypotenuse.It means OC: OA = 1 : 2, so angles AOC and BOC are both 60° as adjacent to short legs.
In order to find the shaded area we need to find the area of sector OADB and subtract the area of triangle OAB.
Area of sector:
A = π(θ/360)r², where θ- central angle,A = π*((mAOC + mBOC)/360)*r²,A = π*((60 + 60)/360))(4²) = 16.76 cm².Area of triangle AOB:
A = (1/2)*OC*(AC + BC), AC = BC = OC√3 according to the property of 30x60x90 triangle.A = (1/2)(2*2√3)*2 = 4√3 = 6.93 cm²The shaded area is:
A = 16.76 - 6.93 = 9.83 cm²Write as a single term from Pascal's Triangle in the form t_nr(1 mark)
t_13,8 + t_13,9
¹³C₈ + ¹³C₉ as a single term from Pascal's Triangle is ¹⁴C₉
What is Pascal's triangle?
Pascal's triangle is a triangle written in such a way that it forms the coefficients of a binomial expansion. The coefficients of the terms are gotten through combination.
What is combination?Combination is the number of ways r in which n objects can be selected. It is given by ⁿCₓ = n!/x!(n - x)!
How to write a single term from Pascal's Triangle in the form t_nr = t_13,8 + t_13,9.Since we have ¹³C₈ + ¹³C₉ and we want to write it as a single term, we have that
¹³C₈ = 13!/8!(13 - 8)! = 13!/8!5! and ¹³C₉ = 13!/9!(13 - 9)! = 13!/9!4!So, ¹³C₈ + ¹³C₉ = 13!/8!5! + 13!/9!4!
= 13!/(8! × 5 × 4!) + 13!/(9 × 8! × 4!)
= 13!/8!4![1/5 + 1/9]
= 13!/8!4! × [(9 + 5)/45]
= 13!/8!4! × 14/45]
= 13!/8!4! × 14/(9 × 5)]
= 14 × 13!/8! × 9 × 4! × 5)]
= 14!/9!5!
= 14!/9!(14 - 9)!
= ¹⁴C₉
So, ¹³C₈ + ¹³C₉ as a single term from Pascal's Triangle is ¹⁴C₉
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The difference of two numbers is 3/4. The sum of the two numbers is 9 1/4. Find the number
8x + 2y =16
standard form
1) m=
2 y - intercept x - intercept
Answer:
m=-4
y-intercept=8
x-intercept=2
Step-by-step explanation:
Please see attachment.
y-intercept=8
The y-intercept is where the line crosses the y-axis.
x-intercept=2
The x-intercept is where the line crosses the x-axis.
m=-4
If you do not know how to find slope by looking at graph, use slope formula.
(y2-y1)/(x2-x1)
Choose 2 points. You may use the x and y intercepts.
(2,0) and (0,8)
(8-0)/(0-2)=8/-2=-4
Hope this helps!
HALP
What is the range of possible sizes for side xxx?
Answer:
See below
Step-by-step explanation:
Using triangle side rule : The sum of any two sides must be greater than the third side
.5<x<16.5
The range of possible sizes for side x for given triangle is 0.5<x<16.5.
In the given triangle, one side measures 8.5 units, other side is 8.0 units and third side is x units.
The length of one side of a triangle must be greater than the difference and less than the sum of the lengths of the other two sides.
Here, the range of x is 8.5-8.0<x<8.5+8.0
0.5<x<16.5
Therefore, the range of possible sizes for side x for given triangle is 0.5<x<16.5.
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