Answer:
Accurate AND Precise
On Wednesday, 1/3 of the students in Mr. Short's homeroom had drama practice, and 1/4 of his other homeroom students had band practice. If 6 students had band practice, how many students are in Mr. Short's homeroom?
Answer:
36
Step-by-step explanation:
Honestly, I'd work this out visually (see image) by drawing a rectangle and dividing it up. But if you need to show the math, here's how to do it:
Let x = the number of students in the homeroom
1/3 x have drama
1/4 (x - 1/3x) have band, and we are told 6 students have band, so
1/4 (x - 1/3 x) = 6
1/4 (2/3 x) = 6
2/12 x = 6
1/6 x = 6
6 × 1/6 x = 6 × 6
1 x = 6 × 6
x = 36
Answer:
36
Step-by-step explanation:
Let n be the total number of students in Mr. Short's homeroom. Then, working backward, we see that
6 = 1/4(1 - 1/3)n = 1/4(2/3)n = 1/6n,$
so n = 6 x 6 = 36 students.
How does changing the function from f(x) = -5 cos 2x to g(x) = -5 cos 2x-3 affect the range of the function?
Each element in the range of g(x) is 3 less than the corresponding element in the range of f(x).
Answer:
See below.
In short, by having vertical shift will affect range from -1 ≤ y ≤ 1 to -1 + a ≤ y ≤ 1 + a
Step-by-step explanation:
Generally, a cosine function without vertical shift will always have range equal to -1 ≤ y ≤ 1
If there is given vertical shift, our range will change to -1 + a ≤ y ≤ 1 + a
An example is if we are given the function of cos(x), this always has range of -1 ≤ y ≤ 1 because there is no vertical shift.
But if we have cos(x) + 1, we have vertical shift which is 1. Then the range will be -1+1 ≤ y ≤ 1+1 which equals to 0 ≤ y ≤ 2.
Hence, the function of -5cos(2x) has only range of -1 ≤ y ≤ 1 but the function of -5cos(2x) - 3 will have range of -1-3 ≤ y ≤ 1-3 which equals to -4 ≤ y ≤ -2
The first 5 terms of a sequence are 2 8 14 20 26 Find the nth term
Answer: [tex]\Large\boxed{a_n=6n-4}[/tex]
Step-by-step explanation:
Given sequence
2, 8, 14, 20, 26
Determine the pattern
2 + 6 = 8
8 + 6 = 14
14 + 6 =20
20 + 6 = 26
For each term, add 6 to get the next term
Determine the type of sequence
Since it continuously adds 6, the common difference is 6, which means it is an arithmetic sequence
Given the arithmetic sequence formula
aₙ = a₁ + d (n - 1)
a₁ = 1st term of a sequenceaₙ = nth term of a sequencen = nth positiond = Common differenceSubstitute values into the formula
aₙ = (2) + (6) (n - 1)
aₙ = 2 + 6 (n - 1)
aₙ = 2 + 6n - 6
aₙ = 2 - 6 + 6n
[tex]\Large\boxed{a_n=6n-4}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
Given sequence :-
2 , 8 , 14 , 20 , 26...Solution :-
We need to calculate the nth term of the given sequence.
Common difference (d) = 8 - 2 => 6First term of sequence (a) = 2We know that,
tn = a + (n - 1) dApplying the values here.
>> tn = 2 + (n - 1) 6
>> tn = 2 + (n - 1) × 6
>> tn = 2 + 6n - 6
>> tn = 6n - 4
Therefore, nth term of the sequence is (6n - 4).
Evaluate the following integral (Calculus 2) Please show step by step explanation!
Answer:
[tex]4\ln \left| \dfrac{1}{3}\sqrt{9+(\ln x)^2} + \dfrac{1}{3}\ln x \right|+\text{C}[/tex]
Step-by-step explanation:
Fundamental Theorem of Calculus
[tex]\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))[/tex]
If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.
Given indefinite integral:
[tex]\displaystyle \int \dfrac{4}{x\sqrt{9+(\ln(x))^2}}\:\:\text{d}x[/tex]
Rewrite 9 as 3²:
[tex]\implies \displaystyle \int \dfrac{4}{x\sqrt{3^2+(\ln(x))^2}}\:\:\text{d}x[/tex]
Integration by substitution
[tex]\boxed{\textsf{For }\sqrt{a^2+x^2} \textsf{ use the substitution }x=a \tan\theta}[/tex]
[tex]\textsf{Let } \ln x=3 \tan \theta[/tex]
[tex]\begin{aligned}\implies \sqrt{3^2+(\ln x)^2} & =\sqrt{3^2+(3 \tan\theta)^2}\\ & = \sqrt{9+9\tan^2 \theta}\\ & = \sqrt{9(1+\tan^2 \theta)}\\ & = \sqrt{9\sec^2 \theta}\\ & = 3 \sec\theta\end{aligned}[/tex]
Find the derivative of ln x and rewrite it so that dx is on its own:
[tex]\implies \ln x=3 \tan \theta[/tex]
[tex]\implies \dfrac{1}{x}\dfrac{\text{d}x}{\text{d}\theta}=3 \sec^2\theta[/tex]
[tex]\implies \text{d}x=3x \sec^2\theta\:\:\text{d}\theta[/tex]
Substitute everything into the original integral:
[tex]\begin{aligned} \implies \displaystyle \int \dfrac{4}{x\sqrt{9+(\ln(x))^2}}\:\:\text{d}x & = \int \dfrac{4}{3x \sec \theta} \cdot 3x \sec^2\theta\:\:\text{d}\theta\\\\ & = \int 4 \sec \theta \:\: \text{d}\theta\end{aligned}[/tex]
Take out the constant:
[tex]\implies \displaystyle 4 \int \sec \theta\:\:\text{d}\theta[/tex]
[tex]\boxed{\begin{minipage}{7 cm}\underline{Integrating $\sec kx$}\\\\$\displaystyle \int \sec kx\:\text{d}x=\dfrac{1}{k} \ln \left| \sec kx + \tan kx \right|\:\:(+\text{C})$\end{minipage}}[/tex]
[tex]\implies 4\ln \left| \sec \theta + \tan \theta \right|+\text{C}[/tex]
[tex]\textsf{Substitute back in } \tan\theta=\dfrac{1}{3}\ln x :[/tex]
[tex]\implies 4\ln \left| \sec \theta + \dfrac{1}{3}\ln x \right|+\text{C}[/tex]
[tex]\textsf{Substitute back in } \sec\theta=\dfrac{1}{3}\sqrt{9+(\ln x)^2}:[/tex]
[tex]\implies 4\ln \left| \dfrac{1}{3}\sqrt{9+(\ln x)^2} + \dfrac{1}{3}\ln x \right|+\text{C}[/tex]
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Quick algebra 1 question for 25 points!
Only answer if you know the answer, Tysm!
Using a quadratic regression equation, it is found that the prediction of volunteers in year 10 is of:
A. 47.
How to find the equation of quadratic regression using a calculator?To find the equation, we need to insert the points (x,y) in the calculator.
In this problem, we have that the function initially increases, then it decreases, which means that it is a quadratic function. The points (x,y) to be inserted into the calculator are given as follows:
(1, 20), (2,17), (3, 16), (4,16), (5,18), (6,21), (7,25), (8,31)
Inserting these points into the calculator, the prediction of y for a value of x is given as follows:
y = 0.702x^2 - 4.726x + 23.857
Hence, when x = 10, the prediction is:
y = 0.702 x 10² - 4.726 x 10 + 23.857
y = 47.
Hence option A is correct.
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Mr. Salazar assigns the same number of homework questions each school day. The ratio table below shows the total number of homework questions assigned after a certain number of school days.
Homework
Number of days
Total number of questions
4
20
8
40
11
55
16
?
After 16 days, how many total homework questions have been assigned?
After 16 days, the total homework questions that have been assigned would be 80 questions.
How many homework questions would be assigned after 16 days?
Ratio expresses the equivalent relationship between two numbers. It shows the frequency of the number of times that one value is contained within other value(s).
A ratio table can be described as table that shows equivalent values between two numbers.
The first step is to determine the ratio between the number of days and the total number of questions.
Ratio = money saved / money earned
8/10 = total number of questions / number of days
55 / 11 = 5
Now, multiply the ratio gotten in the previous step by the number of days
Total number of homework questions = number of x ratio
5 x 16 = 80 questions
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Find the value of x if m2 = 4x - 2.
68⁰
2
The value of x is 11 1/2 OR 11.5
Calculating the measure of anglesFrom the question, we are to determine the value of x
In the given diagram, we have two isosceles triangles
Since base angles of isosceles triangles are equal,
Then, each of the base angles of the isosceles triangle is 68°
Then, we can write that
m ∠2 + 68° + 68° = 180° (Sum of angles in a triangle)
From the given information,
m ∠2 = 4x - 2
Then,
4x -2 + 68° + 68° = 180°
4x = 180 - 68 - 68 +2
4x = 46
x = 46/4
x = 11 1/2 OR 11.5
Hence, the value of x is 11 1/2 OR 11.5
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Complete the equation of the line through
(-10, 3) and (-8, -8).
The answer is y = -5.5x - 52.
First, let's find the slope of the line.
m = Δy/Δx
m = -8 - 3 / -8 - (-10)m = -11 / -8 + 10m = -11/2m = -5.5Now, substitute the slope and one of the given points in the point slope equation.
y - y₁ = m (x - x₁)
y - 3 = -5.5 (x - (-10))y - 3 = -5.5 (x + 10)y - 3 = -5.5x - 55y = -5.5x - 52Answer: y=-5,5x-52.
Step-by-step explanation:
Equation of a straight line
[tex]\displaystyle\\\boxed {\frac{x-x_1}{x_2-x_1}=\frac{y-y_1}{y_2-y_1} }[/tex]
[tex](-10;3)\ \ \ \ \ (-8;-8).\\\displaystyle\frac{x-(-10)}{-8-(-10)} =\frac{y-3}{-8-3}\\ \frac{x+10}{-8+10}=\frac{y-3}{-11} \\ \frac{x+10}{2}=\frac{y-3}{-11} \\-11*(x+10)=2*(y-3)\\-11x-110=2y-6\\2y=-11x-104\ |:2\\y=-5,5x-52.[/tex]
How many fruits did Anna get?
Answer: Anna got 30
Step-by-step explanation: 2x+3y=25
15+10=25
Quick algebra 1 question for 10 points!
Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!
Answer:
See image
Step-by-step explanation:
Using a graphing calculator, first press the Y= button at the top left.
Then enter the equation given in the question.
Next, press 2nd then graph, and you will get the table. Put in whatever values for x to get y.
So your answer is 48, 18, 0, -6, 0, -18, 0, 48
17. In a spelling competition, school X had 12 more participants than school Y and 18 fewer participants than school Z. The ratio of the number of boys to the number of girls in school X, Y and Z were 1:2, 1:5 and 2: 1 respectively. There were 50 more girls than boys in total from the 3 schools. How many participants from the 3 school were there in all?
There were 204 participants from the three schools
How to determine the number of participants?The given parameters are:
X = 12 + Y
X = Z - 18
Girls = Boys + 50
The ratios of the number of boys to girls in the schools are:
1 : 2
1 : 5
2 : 1
This means that:
School X: Boys = 1/3 and Girls = 2/3School Y: Boys = 1/6 and Girls = 5/6School Z: Boys = 2/3 and Girls = 1/3So, we have:
Boys = 1/3X + 1/6Y + 2/3Z
Girls = 2/3X + 5/6Y + 1/3Z
Substitute the above equations in Girls = Boys + 50
2/3X + 5/6Y + 1/3Z = 1/3X + 1/6Y + 2/3Z + 50
Evaluate the like terms
1/3X + 2/3Y - 1/3Z = 50
Multiply through by 3
X + 2Y - Z = 150
So, we have:
X = 12 + Y
X = Z - 18
X + 2Y - Z = 150
Substitute X = 12 + Y in X = Z - 18 and X + 2Y - Z = 150
12 + Y = Z - 18 ⇒ Y - Z = 30
12 + Y + 2Y - Z = 150 ⇒ 3Y - Z = 138
Subtract Y - Z = 30 from the equation 3Y - Z = 138 to eliminate Z
2Y = 108
Divide by 2
Y = 54
Substitute Y = 54 in X = 12 + Y
X = 12 + 54
X = 66
Substitute X = 66 in X = Z - 18
66 = Z - 18
Solve for Z
Z = 66 + 18
Z = 84
So, the total number of participants from the 3 schools is
Total = X + Y + Z
This gives
Total = 66 + 54 + 84
Evaluate the sum
Total = 204
Hence, there were 204 participants from the three schools
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Help please! What is the correct answer and how do I solve for R?
Given the angles inscribed in the circle, find m ∠ DBC.
Answer:
m∠DBC = 51°
Step-by-step explanation:
Circle Theorem vocabulary
Chord: A straight line joining two points on the circle.Inscribed angle: The angle formed when two chords meet at one point on a circle.Intercepted arc: The arc that is between the endpoints of the chords that form the inscribed angle.Inscribed Angle Theorem
The measure of an inscribed angle is half the measure of the intercepted arc.
Therefore:
[tex]\sf \implies \angle DBC=\dfrac{1}{2}\:\overset{\frown}{BC}[/tex]
[tex]\sf \implies \angle DBC=\dfrac{1}{2}\:(102^{\circ})[/tex]
[tex]\sf \implies \angle DBC=51^{\circ}[/tex]
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[tex]\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}[/tex]
To determine ∠DBC, we will apply the theorem relating the inscribed angle to the intercepted arc:
[tex]\longrightarrow \sf{Intercepted \: arc= (inscribe \: angle)}[/tex]
[tex]\longrightarrow \sf{Intercept \: arc= 102^\circ}[/tex]
[tex]\longrightarrow \sf{Inscribed \: angle= \angle DBC }[/tex]
[tex]\longrightarrow \sf{102=2( \angle DBC)}[/tex]
[tex]\longrightarrow \sf{\angle DBC= \dfrac{102}{2} }[/tex]
▪ [tex]\longrightarrow \sf{\angle DBC = 51^\circ}[/tex]
[tex]\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}[/tex]
[tex]\boxed{\bf{\large m \: \angle DBC= 51^\circ}}[/tex]
Need this quick ! Correct answers appreciated
(Selected answer is not known to be correct it just won’t let me un select an answer)
According to USA Today, the average cost of a private university is $50,000 with a population standard deviation of $2,500. 100 universities are randomly selected and the average income of those 100 universities was $49,450. Using the 5 step hypothesis testing process, can you support the claim that the average cost of private universities are decreasing? Use a .01 significance level. (Use the z or t value of -2.2) What is your conclusion based on p-value?
Using the z-distribution, it is found that since the p-value is less than 0.05, there is evidence to support the claim that the average cost of private universities are decreasing.
What are the hypothesis tested?At the null hypothesis, it is tested if the average cost is still of $50,000, that is:
[tex]H_0: \mu = 50000[/tex]
At the alternative hypothesis, it is tested if the average cost is decreasing, that is:
[tex]H_1: \mu < 50000[/tex]
What is the test statistic?The test statistic is:
[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which:
[tex]\overline{x}[/tex] is the sample mean.[tex]\mu[/tex] is the value tested at the null hypothesis.[tex]\sigma[/tex] is the standard deviation of the population.n is the sample size.The parameters for this problem are:
[tex]\overline{x} = 49450, \mu = 50000, \sigma = 2500, n = 100[/tex]
Hence:
[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{49450 - 50000}{\frac{2500}{\sqrt{100}}}[/tex]
z = -2.2.
What is the p-value and the conclusion?Using a z-distribution calculator, for a left-tailed test, as we are testing if the mean is less than a value, with z = -2.2, the p-value is of 0.0139.
Since the p-value is less than 0.05, there is evidence to support the claim that the average cost of private universities are decreasing.
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ASAP NOW
below is the question
The mean of the data set A is 4.58 while the mean of data set B is 5.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
The mean of a set of numbers is the average of that group of number. It is the ratio of the sum of the data to the total number of data.
Mean of data set A = [(3 * 1) + (4 * 3) + (5 * 2) + (6 * 2) + (7 * 3) + (8 * 1)] / (1 + 3 + 2 + 2 + 3 + 1) = 4.58
Mean of data set B = [(4 * 2) + (5 * 2) + (6 * 2)] / ( 2 + 2 + 2) = 5
The mean of the data set A is 4.58 while the mean of data set B is 5.
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Area=
Help me please asap.
Thanks so much :)
The area of the given parallelogram is 8 square units
Area of a parallelogramA parallelogram is a 2 dimensional figure with 4 sides and angles. From the given diagram, the opposite sides are equal and the sum of the adjacent angles are supplementary
The formula for calculating the area of a parallelogram is expressed as:
A = base * height
From the given diagram
Base = (4, 0) = 4 units
Height. = (2, 0) = 2 units
Substitute the given values into the formula to have:
A = 4 units * 2 units
A = 8 square units
Hence the area of the given parallelogram is 8 square units
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A study of college freshmen found that students who watched tv for more than one hour each night gained 15 pounds in the first semester, compared to those who watched less than one hour. they concluded that there is an association between watching tv and weight gain in college freshmen. which study design did they most likely use?
Answer:
C. They most likely used an observational study asking students to keep track of their TV habits and weight.
A. This is an experiment because a treatment was applied to a group.
Step-by-step explanation:
According to our question:
1. The study concluded that there is a relation between watching TV and the weight gain in college freshmen.
Now, this is possible when a group of college students were asked to participate to watch TV for more than 1 hour for a specific amount of time and have a record of their weights.
So, the study is an observational study where the habits and weights of college students were observed.
Hence, option C is correct.
2. The students were divided onto two groups where one group used the computer program and the other did not to check the improvement in the reading levels.
This means that the students were given a procedure to follow during the study in order to see the results..
So, the study is an experiment where a treatment is applied to the group of students.
Hence, option A is correct.
Answer: C
For the people who want only one answer and not 2 for the question if you can only submit one answer :)
Explain the similarities and differences between the two relationships in this situation.
Find the surface area of the prism.
Answer:
204
Step-by-step explanation:
6*10=60
6*6=36
6*8=48
2((10*6)/2)=60
60+60+36+48=204
Find the number of ways of delivering five letters to five houses so that no house gets
a correct letter.
Using the Fundamental Counting Theorem, it is found that there are 1024 ways of delivering the letters.
What is the Fundamental Counting Theorem?It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:
[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]
In this problem, each house has a correct letter, however the letter cannot be used for the house, hence the parameters are given as follows:
n1 = n2 = n3 = n4 = n5 = 5 - 1 = 4.
Thus the number of ways is:
N = 4 x 4 x 4 x 4 x 4 = 4^5 = 1024.
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8 out of 10 people saw the show
Answer: 80% of the 10 people saw the show.
Step-by-step explanation:
8/10 = 0.8, which is 80%.
I hope this helped!
divide the polynomials:
x^2-3x+9/x-2
The value of dividing x^2-3x+9 by x-2 is x + 3
Ways of dividing polynomialsThere are several ways to divide polynomial functions; some of these ways include
By factorizationBy long divisionBy synthetic divisionBy using technology such as graphHow to divide the polynomials?The expression for the polynomial division is given as:
x^2-3x+9/x-2
To divide polynomial functions, we make use of the division by factorization method
Start by expanding the numerator of the polynomial division
x^2-3x+9/x-2 = x^2 + 3x - 6x + 9/x-2
Factorize the equation
x^2-3x+9/x-2 = x(x + 3) - 2(x + 3)/x - 2
Factor out x + 3 from the numerator
x^2-3x+9/x-2 = (x- 2)(x + 3)/x - 2
Cancel out the common factors
x^2-3x+9/x-2 = x + 3
Hence, the value of dividing x^2-3x+9 by x-2 is x + 3
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I need help asap please help me
Answer:
8
Step-by-step explanation:
I belive what they mean is how many dots thier are i am not complety sure though but just by counting them up i came up with 8.
hope this helped
A retailer allowed 4% discount on his goods to make 20% profit and sold a refrigerator for Rs 10,848 with 13% VAT. By how much is the discount to be increased so that he can gain only 15%?
The discount to be increased so that he can gain only 15% is 8%.
What is a discount? Discounts are given when a reduction in the price is permitted to promote more purchases or timely payments. Discounts are divided into Trade reduction: The discount granted when substantial purchases are made is referred to as a trade discount.Discounts are given when a reduction in the price is permitted to promote more purchases or timely payments. Discounts are divided into Trade reduction: The discount granted when substantial purchases are made is referred to as a trade discount.Since sales discounts lower the cost of a product, they are not considered costs. These monetary discounts provided to consumers do, however, have an impact on a company's financial statements. Thus they must be reported as a decrease in revenue under the accounts receivable line item.How much is the discount to be increased so that he can gain only 15%:
The cost price of the goods - y.
The selling price of the goods - x.
The selling price is
1.2y (100% + 20% = 120%).
The refrigerator was sold at 13% VAT at Rs. 10848:
=> 1.2y + 13%(1.2y) = 10848
=> 1.2y + 0.156y = 10848
=> 1.356y = 10848
=> y = 8000
Thus, the cp is Rs 8000.
The selling price is:
=> 0.96x = 1.2y
=> 0.96x = 1.2(8000)
=> x = 10000
The selling price is Rs. 10000
For a profit of 15%, that is 1.15(8000) = 9200, the discount is:
(1 - discount)10000 = 9200
1 - discount = 0.92
Discount = 1 - 0.92 = 0.08 or 8%
How much is the discount to be increased so that he can gain only 15%: Discount=8%
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April was asked to determine whether f(x)=x^3 -1 is even, odd, or neither. Here is her work:
April's work in checking for the function, [tex]f(x) = x^3 - 1[/tex], to be even, odd, or neither, is incorrect. She did a mistake in step 2, where she took [tex]f(-x) = - f(x)[/tex], which was not true, since [tex]f(-x) = -x^3 - 1[/tex], whereas [tex]- f(x) = -x^3 + 1[/tex].
A function f(x) is said to be odd or even when it completes the condition:
f(-x) = -f(x), for f(x) to be an odd function, andf(-x) = f(x), for f(x) to be an even function.In the question, we are given that April was asked to determine whether [tex]f(x) = x^3 - 1[/tex], is even, odd, or neither, and are shown her work.
We are asked whether April's work is correct, and if not, what is the first step where April made a mistake.
To check for a function is even or odd, we first calculate f(-x).
April's first step was also finding f(-x), which she found accurately as [tex]f(-x) = -x^3 - 1[/tex].
Next, we need to check whether f(-x) is equal to f(x), -f(x), or neither, to check if the function is even, odd, or neither, respectively.
April, also choose the right step of checking, but did a mistake in checking, since f(-x) ≠ f(x), and also, f(-x) ≠ - f(x), since, [tex]- f(x) = -(x^3 - 1)[/tex] = [tex]-x^3 + 1[/tex], which is not equal to f(-x).
Thus, April's work in checking for the function, [tex]f(x) = x^3 - 1[/tex], to be even, odd, or neither, is incorrect. She did a mistake in step 2, where she took f(-x) = - f(x), which was not true, since [tex]f(-x) = -x^3 - 1[/tex], whereas [tex]- f(x) = -x^3 + 1[/tex].
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An amusement park sells adults' and
children's passes. An adult's pass is $25,
and a child's pass is $15. A group spent
$440 on 20 passes. How many children's
passes did the group purchase?
A
Answer:
6 children passes
Step-by-step explanation:
a = adult and c = children
25a + 15c = 440 and a + c = 20
c = 20 - a
25a + 15(20-a) = 440
25a + 300 - 15a = 440
25a - 15a = 440 - 300
10a = 140
a = 140/10
a = 14 and this is 14 adult tickets
Now we plug the a value into the equation to find the c value
14 + c = 20
c = 20 - 14
c = 6
Verify answer:
25(14) = 15(6) = 440
350 + 90 = 440
440 = 440
Evaluate the surface integral. s y ds s is the surface z = 2 3 x3/2 y3/2 , 0 ≤ x ≤ 4, 0 ≤ y ≤ 1
The surface integral of the given surface [tex]z=\frac{2}{3}(x^\frac{3}{2}+y^\frac{3}{2})[/tex] in the intervals 0 ≤ x ≤ 4, 0 ≤ y ≤ 1 is 7.36615.
How to evaluate the surface integral?To evaluate the surface integral, the formula applied is
[tex]S=\int\limits^b_a\int\limits^d_c {f(x,y)} \ dy\ dx[/tex]
⇒ S = [tex]\int\limits^b_a \int\limits^d_c {\sqrt{1+(\frac{dz}{dx})^2+(\frac{dz}{dy})^2 } } \, dy \, dx[/tex]
Where the differentiation is partial differentiation and f(x, y) = z.
Calculation:The given function is
f(x, y) = [tex]z=\frac{2}{3}(x^\frac{3}{2}+y^\frac{3}{2})[/tex]
Then, applying the partial differentiation w.r.t x and y respectively,
dz/dx = [tex]\frac{2}{3}(\frac{3}{2})x^{1/2}[/tex] = [tex]x^{1/2}[/tex]
dz/dy = [tex]\frac{2}{3}(\frac{3}{2})y^{1/2}[/tex] = [tex]y^{1/2}[/tex]
Then,
we have surface integral formula as
S = [tex]\int\limits^b_a \int\limits^d_c {\sqrt{1+(\frac{dz}{dx})^2+(\frac{dz}{dy})^2 } } \, dy \, dx[/tex]
On substituting,
⇒ S = [tex]\int\limits^4_0 {\int\limits^1_0 {\sqrt{1+(x^{1/2})^2+(y^{1/2})^2} \, dy } \, dx[/tex]
⇒ S = [tex]\int\limits^4_0 {\int\limits^1_0 {\sqrt{1+x+y} \, dy } \, dx[/tex]
On integrating w.r.t y
⇒ S = [tex]\int\limits^4_0 {\frac{2}{3}(1+x+y)^{3/2}} \,|_0^1 dx[/tex]
Applying limits,
⇒ S = [tex]\int\limits^4_0 {\frac{2}{3}[(1+x+1)^{3/2}-(1+x+0)^{3/2} } \, dx[/tex]
⇒ S = [tex]\frac{2}{3} \int\limits^4_0 {[(x+2)^{3/2}-(x+1)^{3/2}}] \, dx[/tex]
Again applying the integration w.r.t x
⇒ S = [tex]\frac{2}{3}[\frac{2}{5}(x+2)^{5/2}-\frac{2}{5}(x+1)^{5/2}]|_0^4[/tex]
Applying the limits and simplifying,
⇒ S = [tex]\frac{4}{15}[(4+2)^{5/2}-(4+1)^{5/2}-(0+2)^{5/2}+(0+1)^{5/2}][/tex]
⇒ S = [tex]\frac{4}{15}[1+36\sqrt{6}-25\sqrt{5}-4\sqrt{2}][/tex]
∴ S = 7.36615
Therefore, the surface integral of the given function is 7.36615.
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The area of a painting is 4081 c m squared.
If the width of the painting is 53 cm, what is its length, in centimeters?
Type your numerical answer below (without units). If necessary, round to the nearest integer.
The length of the rectangle is 77cm.
According to the statement
we have given that the area of a painting is 4081 c m squared. and width of the painting is 53 cm.
And we have to find the Length of the painting.
So, For this purpose
Area of rectangle is the region occupied by a rectangle within its sides. It depends on its sides.
So, the formula to find the area of rectangle is
Area = Length*Breadth
4081 = L*53
L = 4081/53
L = 77 cm.
So, The length of the rectangle is 77cm.
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3x+5<6x+8
4x+3 is <7x+5
The solution to the inequalities 3x + 5 < 6x + 8 and 4x + 3 < 7x + 5 is x > -1 and x > -2/3 respectively
InequalityInequality signs are;
Greater than >Less than <Equal to =Less than equal to ≤Greater than equal to ≥3x + 5 < 6x + 8
collect like terms3x - 6x < 8 - 5
-3x < 3
divide both sides by -3x > 3/-3
The inequality sign is flipped from < to greater than because of the division with negative value.
x > -1
2. 4x + 3 < 7x + 5
collect like terms4x - 7x < 5 - 3
-3x < 2
divide both sides by -3The inequality sign is flipped from < to greater than because of the division with negative value.
x > -2/3
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