Parallel lines maintain the exact slope but different y-intercepts. Perpendicular lines have to oppose, reciprocal slopes like 1/2 and -2 or 8/7 and -7/8.
What was the relationship between the lines with equations 4x − 8y = 9 and 8x − 7y = 9?Given: 4x - 8y = 9 ............(1)
8x - 7y = 9 ............(2)
To be the same line, the equations have to be multiples of each other.
Multiplying (1) by 2, we get
2(4x - 8y = 9) = 8x - 16y = 18
From (1) solve the value of y, we get
4x - 8y = 9 ............(1)
-8y = -4x + 9
The value of y = (1/2)x - 9/8
From (2),
8x - 7y = 9
solve the value of y, we get
-7y = -8x + 9
The value of y = (8/7)x - 9/7
To be the exact line, the equations would be exact. Parallel lines maintain the exact slope but different y-intercepts. Perpendicular lines have to oppose, reciprocal slopes like 1/2 and -2 or 8/7 and -7/8.
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If 3(x-3) = 5(2x + 1), then
x=-2
Step-by-step explanation:
Solution Given:
3(x-3) = 5(2x + 1)
Opening bracket we get
3x-9=10x+5
keeping common value in same side
-9-5=10x-3x
-14=7x
x=-14/7
x= -2
Answer:
-2 =x
Step-by-step explanation:
3(x-3) = 5(2x + 1)
To solve for x
Distribute
3x -9 = 10x +5
Subtract 3x from each side
3x-9-3x = 10x -3x+5
-9 = 7x+5
Subtract 5 from each side
-9-5 = 7x+5-5
-14 = 7x
Divide by 7
-14/7 = 7x/7
-2 =x
Please answer quickly! It would be great if you could include the question # and the answer in the answer section, and then explain it below. Thank you in advance!
Answer:
[tex]\textsf{19.} \quad S_{20}=1490[/tex]
33. None of these are correct.
Step-by-step explanation:
Question 19General form of an arithmetic sequence:
[tex]a_n=a+(n-1)d[/tex]
where:
[tex]a_n[/tex] is the nth terma is the first termd is the common difference between termsGiven values:
[tex]a_n[/tex] = 27n = 20d = -5Substitute the given values into the formula and solve for a:
[tex]\implies 27=a+(20-1)(-5)[/tex]
[tex]\implies 27=a+(19)(-5)[/tex]
[tex]\implies 27=a-95[/tex]
[tex]\implies a=27+95[/tex]
[tex]\implies a=122[/tex]
Sum of the first n terms of an arithmetic series:
[tex]S_n=\dfrac12n[2a+(n-1)d][/tex]
where:
a is the first term.d is the common difference.Given values:
a = 122n = 20d = -5Substitute the given values into the formula and solve:
[tex]\implies S_{20}=\dfrac{1}{2}(20)[2(122)+(20-1)(-5)][/tex]
[tex]\implies S_{20}=10[244-95][/tex]
[tex]\implies S_{20}=10[149][/tex]
[tex]\implies S_{20}=1490[/tex]
Question 33Sum of the first n terms of a geometric series:
[tex]S_n=\dfrac{a(1-r^n)}{1-r}[/tex]
where:
a is the first termr is the common ratioGiven values:
a₁ = 1458r = ¹/₃Substitute the given values into the formula and solve:
[tex]\implies S_6=\dfrac{1458\left(1-\frac{1}{3}^6\right)}{1-\frac{1}{3}}[/tex]
[tex]\implies S_6=\dfrac{1456}{\frac{2}{3}}[/tex]
[tex]\implies S_6=\dfrac{1456 \cdot 3}{2}[/tex]
[tex]\implies S_6=2184[/tex]
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PLS HELP LOTs OF POINTS!!!!What is the difference of….
[tex]\frac{-2x^{2} +25 }{(x-2) (x-5)} ,x\neq 2,x\neq 5[/tex] is the difference.
What is an expression?
⇒ An expression is a combination of numbers, variables, and functions (such as addition, subtraction, multiplication or division, etc.)
Calculation :
⇒ [tex]\frac{3x^{2} }{(x^{2} -7x+10)}- \frac{5x} {x-2}[/tex]
⇒ [tex]\frac{3x^{2} }{(x-2)(x-5)}- \frac{5x} {x-2}[/tex]
⇒1/(x-2) [(3x²-5x{x-5})/(x-5)]
⇒1/(x-2) [(3x²-5x²+25x)/(x-5)]
⇒1/(x-2) [ (-2x²+25x)/(x-5)]
⇒[tex]\frac{-2x^{2} +25x }{(x-2)(x-5)}[/tex]
at x=2 and x=5 the denominator becomes zero If the denominator of a fraction is zero, the expression is not a legal fraction because its overall value is undefined.
⇒ [tex]\frac{-2x^{2} +25 }{(x-2) (x-5)} ,x\neq 2,x\neq 5[/tex] is the difference
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5. During the season, the Rangers played 25 games. They won 14 of the games.
What fraction and percent of the games did they lose? Show your work in the
space below. Remember to check your solution.
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Your Turn:
Simplify the following expressions by combining like term
1) 4x + 7 + 2x
2) -4x+3y-3x+8+2y
Answer:
[tex]\Large\boxed{1)~6x+7}[/tex]
[tex]\Large\boxed{2)~-7x+5y+8}[/tex]
Step-by-step explanation:
Question 1: 4x + 7 + 2xGiven expression
4x + 7 + 2x
Move like terms together
= 4x + 2x + 7
= (4x + 2x) + 7
Combine like terms
[tex]\Large\boxed{=6x+7}[/tex]
Question 2: -4x+3y-3x+8+2yGiven expression
-4x + 3y - 3x + 8 + 2y
Move like terms together
= -4x - 3x + 3y + 2y + 8
= (-4x - 3x) + (3y + 2y) + 8
Combine like terms
[tex]\Large\boxed{=-7x+5y+8}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
Find the measure of the indicated angle to the nearest degree.
Answer:
24.315°
Step-by-step explanation:
First use the pythagorean theorem to get the missing side since this is a right triangle.
a^2 + b^2 = c^2 →
b^2 = c^2 – a^2 →
b = (c^2 – a^2)^½
b = (17^2 – 7^2)^½
b = (289 – 49)^½
b = √240.
Then use the law of cosines to find the angle in between.
b^2 = a^2 + c^2 - 2ac * cos(B) →
b^2 - a^2 - c^2 = -2ac * cos(B) →
a^2 + c^2 – b^2 / 2ac = cos(B) →
cos^-1(a^2 + c ^2 – b^2 / 2ac) = C →
B = cos^-1(a^2 + c ^2 – b^2 / 2ac)
B = cos^-1(49 + 289 – √240 / 238)
B ≈ 75.685°.
A = 180 – B
A = 180 – 75.685
A = 24.315°
The volume of a cone is 1,782 cubic centimeters. a cylinder has the same radius and height as the cone. what is the volume of the cylinder?
The volume of the cylinder that has same height and radius with the given cone is 5,346 cm³
What are the 3-D figure?Pyramids and prisms are examples of three-dimensional shapes, as are shapes with curved surfaces. The three-dimensional prism shape has two bases that are parallel and congruent. Any polygon is acceptable for the bases, which are two of the faces. Rectangles make up the remaining faces.
What is the Volume of a Cylinder?Given that the cylinder and the cone have the same radius and height, the volume of a cylinder equals 3 times the volume of a cone.
According to the given figure:
Given, a cone that has a volume of 1,782 cubic cm, has the same radius and height with a cylinder,
therefore,
Volume of the cylinder = 3 x (1,782)
Volume of the cylinder = 5,346 cubic centimeters
Hence, the volume of the cylinder is 5,346 cubic centimeter.
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3. The MPG (Miles per Gallon) for a mid-size car is normally distributed with a mean of 32 and a standard deviation of .8. What is the probability that the MPG for a selected mid-size car would be: Less than 33.2
Answer:
93.32 %
Step-by-step explanation:
33.2 is 1.2 away from 32 this is 1.2 / .8 = 1.5 standard deviations ABOVE the mean z -score = + 1.5
from z-score table this corresponds to .9332 this is 93.32 %
The probability that a randomly selected passenger car gets more than 33.2 mpg is 0.14.
What is P- value?The p-value, used in null-hypothesis significance testing, represents the likelihood that the test findings will be at least as extreme as the result actually observed, assuming that the null hypothesis is true.
Let the random variable X represent the miles-per-gallon rating of passenger cars. Compute the probability that a randomly selected passenger car gets more than 33.2 mpg as follows:
The probability will be calculated as below;-
[tex]P(x > 33.2) = p(\dfrac{x-\mu}{\sigma} > \dfrac{33.2 - 32}{0.8})[/tex]
P( x > 33.2) = 1 - P ( z < 1 )
P( x > 33.2) = 1 - 0.86
P( x > 33.2) = 0.14
Thus, the probability that a randomly selected passenger car gets more than 33.2 mpg is 0.14.
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Re-write the quadratic function below in Standard Form y=-5(x+1)²+7
Answer:
y = - 5x² - 10x + 2
Step-by-step explanation:
y = - 5(x + 1)² + 7 ← expand (x + 1)² using FOIL
= - 5(x² + 2x + 1) + 7 ← distribute parenthesis by - 5
= - 5x² - 10x - 5 + 7 ← collect like terms
= -5x² - 10x + 2 ← in standard form
Answer: y = -5x² - 10x + 2
Step-by-step explanation:
Given quadratic function
y = -5 (x + 1)² + 7
Given requirement
Quadratic Standard Form: y = ax² + bx + c
Simplify the exponents
y = -5 (x + 1) (x + 1) + 7
y = -5 (x² + x + x + 1) + 7
y = -5 (x² + 2x + 1) + 7
Expand the parenthesis by distributive property
y = (-5) · x² + (-5) · 2x + (-5) · 1 + 7
y = -5x² + (-10x) + (-5) + 7
y = -5x² - 10x - 5 + 7
Combine like terms
[tex]\Large\boxed{y=-5x^2-10x+2}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
Leo is 23 years old and works for a company that matches his 401(k) contribution up to 4.6%. the interest rate for his 401(k) is 5.32%. if he puts away 8% of his $65,000 salary every year, how much would he have saved in 10 years? round your answer to the nearest cent. a. $7110,127.51 b. $104,564.67 c. $65,582.40 d. $62,269.66
The amount saved in 10 years is = $1,04,461.13
The correct option is B.
Future:An annuity is a series of payments that are distributed evenly over time.
One way to express the future value of an annuity of payment P for n years is,
Total salary is $65000
The interest rate is 5.32%
Trent save 8% of his salary every year.
Company puts 4.6% of salary every year.
[tex]\text { Future Value }=\mathrm{P} \times \frac{\left(1+\frac{i}{n}\right)^{n t}}{\frac{i}{n}}[/tex]
Given:
Total salary is $65000
The interest rate is 5.32%
Trent save 8% of his salary every year.
Company puts 4.6%of salary every year.
The 8% of salary is calculated as:
[tex]\text { Amount } &=\frac{8}{100} \times 65000\\[/tex]
[tex]&=\$ 5200[/tex]
The following information is available on the company's put:
[tex]\text { Amount } &=\frac{4.6}{100} \times 65000\\[/tex]
[tex]&=\$ 2990[/tex]
Total amount as follows:
[tex]\begin{aligned}\text { Amount } &=5200+2990 \\&=\$ 8190\end{aligned}[/tex]
The future value can be obtained as follows
[tex]\begin{aligned}\mathrm{FV} &=8190 \times \frac{(1+0.053)^{10}-1}{0.053} \\&=8190 \times 12.75 \\&=1,04,461.13\ \\\end{aligned}[/tex]
Hence, the amount saved in 10 years is = $1,04,461.13
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Two linear equations are shown.
A coordinate grid with 2 lines. The first line is labeled y equals StartFraction one-third EndFraction x plus 2 and passes through (negative 6, 0) and (0, 2). The second line is labeled y equals StartFraction 4 over 3 EndFraction minus 5.
What is the solution to the system of equations?
Answer:
x = 7; y = 4 1/3
Step-by-step explanation:
The solution is the point of intersection of the lines.
Read the point of intersection.
You can also solve the system using algebra.
y = 1/3 x + 2
y = 4/3 x - 5
1/3 x + 2 = 4/3 x - 5
x + 6 = 4x - 15
-3x = -21
x = 7
y = 1/3 x + 2
y = 1/3 × 7 + 2
y = 2 1/3 + 2
y = 4 1/3
Answer: x = 7; y = 4 1/3
(Essay Worth 10 points)
(08.01 HC)
Use the function f(x) to answer the questions:
f(x) = 5x²+2x-3
Part A: What are the x-intercepts of the graph of f(x)? Show your work. (2 points)
Part B: Is the vertex of the graph of f(x) going to be a maximum or a minimum? What are the coordinates of the vertex? Justify your answers and show your work. (3 points)
Part C: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph. (5 points)
The vertex of the function is a minimum and the coordinate of the vertex of the function is (0.2, -2.4)
Part A: What are the x-intercepts of the graph of f(x)The function is given as:
f(x) = 5x^2 + 2x - 3
Expand the function
f(x) = 5x^2 + 5x - 3x - 3
Factorize the function
f(x) = (5x - 3)(x + 1)
Set the function to 0
(5x - 3)(x + 1) = 0
Solve for x
x = 3/5 and x =-1
Hence, the x-intercept is 3/5 and -1
Is the vertex of the graph of f(x) going to be a maximum or a minimum?The vertex of the function is a minimum.
This is so because the leading coefficient of the function is positive
What are the coordinates of the vertex?Here, we have:
f(x) = 5x^2 + 2x - 3
Differentiate and set to 0
10x + 2 = 0
Solve for x
x = -0.2
Substitute x = -0.2 in f(x) = 5x^2 + 2x - 3
f(0.2) = 5(0.2)^2 + 2(0.2) - 3
Evaluate
f(0.2) = -2.4
Hence, the vertex of the function is (0.2, -2.4)
What are the steps you would use to graph f(x)?To do this, we simply plot the x-intercept and the vertex.
And then connect the points
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Please explain to me how to do this
#43
1+2+3+..+200We may observe. 200+1=201,199+2=201,198+3=201So
200/2=100 pairs of 201
Sum
100(201)=20100#44
1+2+3+..+400400/2=200 pairs of 401
Sum
200+40180200#45
1+2+3+..+800800/2=400 pairs of 801
Sum
400(801)320400#46
1+2+3+..+20002000/2=1000 pairs of 2001
Sum
2001(1000)2001000Answer:
43. 20,100
44. 80,200
45. 320,400
46. 2,001,000
Step-by-step explanation:
Gauss's method
General formula for the sum of the first n integers:
[tex]1+2+3+ \dots +n=\dfrac{1}{2}n(n+1)[/tex]
Question 43
Given sum:
1 + 2 + 3 + ... + 200Therefore, n = 200.
Substitute the value of n into the formula:
[tex]\implies \dfrac{1}{2}(200)(200+1)=100 \cdot 201=20100[/tex]
Question 44
Given sum:
1 + 2 + 3 + ... + 400Therefore, n = 400.
Substitute the value of n into the formula:
[tex]\implies \dfrac{1}{2}(400)(400+1)=200 \cdot 401=80200[/tex]
Question 45
Given sum:
1 + 2 + 3 + ... + 800Therefore, n = 800.
Substitute the value of n into the formula:
[tex]\implies \dfrac{1}{2}(800)(800+1)=400 \cdot 801 =320400[/tex]
Question 46
Given sum:
1 + 2 + 3 + ... + 2000Therefore, n = 2000.
Substitute the value of n into the formula:
[tex]\implies \dfrac{1}{2}(2000)(2000+1)=1000 \cdot 2001=2001000[/tex]
Two marbles are to be pulled from a bag that contains 2 yellow marbles, 4 green marbles, and 6 orange marbles. After the first marble is drawn, it is not replaced. What is the probability that two red marbles are chosen from the vase?
Using it's concept, the probability that two red marbles are chosen from the vase is of 0%.
What is a probability?A probability is given by the number of desired outcomes divided by the number of total outcomes.
In this problem, we have that there are no red marbles, hence the number of desired outcomes is of 0, and there is a 0% probability that two red marbles are chosen from the vase.
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Fiona wrote the linear equation y = 2/5x -5. When Henry wrote his equation, they discovered that his equation had all the same solutions as Fiona’s. Which equation could be Henry’s?
Given the equation written by Fiona and Henry, If both linear equations have the same solutions, Henry's equation is x - 5/2y = 25/2.
Hence, option D is the correct answer.
This question is incomplete, the missing answer choices are;
A. x- 5/4y =25/4
B. x-5/2y=25/4
C. x-5/4y =25/4
D. x- 5/2y=25/2
Which equation could be Henry’s?Given the linear equation written by Fiona; y = 2/5x - 5.
From the answer choices provided, they are in the form of x - (m)y = b.
We will transform Fiona's equation into that form.
y = 2/5x - 5
Divide each term by the coefficient of x.
y(5/2) = (5/2)2/5x - (5/2)5
5/2y = x - 25/2
25/2 = x - 5/2y
x - 5/2y = 25/2
Given the equation written by Fiona and Henry, If both linear equations have the same solutions, Henry's equation is x - 5/2y = 25/2.
Hence, option D is the correct answer.
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Find the sum of the geometric series 9000-900 +...+ 0.009
Based on the calculations, the sum of this geometric series is equal to 9,990.
The standard form of a geometric series.Mathematically, the standard form of a geometric series can be represented by the following expression:
[tex]\sum^{n-1}_{k=0}a_1(r)^k[/tex]
Where:
a₁ is the first term of a geometric series.r is the common ratio.How to calculate the sum of a geometric series?Also, the sum of a geometric series is given by this mathematical expression:
[tex]S=\frac{a_1(1-r^n)}{1-r}[/tex]
Given the following data:
First term, a = 9000.Common ratio, r = 900/9000 = 0.1Substituting the given parameters into the formula, we have;
[tex]S=\frac{9000(1-0.1^3)}{1-0.1}\\\\S=\frac{9000(1-0.001)}{1-0.1}[/tex]
S = 9000(0.999)/0.9
S = 8,991/0.9
S = 9,990.
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what is the formula to calculate area of square
Answer:
Step-by-step explanation:
A square is made up of 4 sides that are equal in length. They can all be called "x" or "s" or whatever variable you want. The formula for the area of a square (and also the area of a rectangle) is Area = side × side.
If you called your sides "x", then the formula is A = x × x or A = x². Another way to note the area of either a square or a rectangle is to call the "bottom" the base and one of the sides the height and then the area formula looks like this:
A = b × h
or
A = length × width
They are all the same thing.
Which equation represents a population of 370 animals that decreases at an annual rate of 11% ?
The equation represents a population of 370 animals that decreases at an annual rate of 11% is [tex]p=370(0.89)^{t}[/tex].
What is an exponential function?It is defined as the function that rapidly decreases and the value of the exponential function is always positive. It denotes with exponent y = a^x
where a is a constant and a>1.
Given that,
A population of 370 animals that decreases at an annual rate of 11%
a = 370, r = 11%
p = [tex]a(1-r)^{t}[/tex]
= [tex]370(1-0.11)^{t}[/tex]
p = [tex]370(0.89)^{t}[/tex]
Hence, The equation represents a population of 370 animals that decreases at an annual rate of 11% is [tex]p=370(0.89)^{t}[/tex].
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PLEASE HELP FAST!
A cylinder and a cone have the same volume. The cylinder has radius x
and height y. The cone has radius 1/2x. Find the height of the cone in terms of y.
The height of the cone in terms of y is h = 12x⁴y
How to find the volume of a cone and cylinder?The cylinder and the cone have the same volume.
Volume of a cylinder = πr²h
where
r = radiush = heightTherefore,
Volume of a cylinder = πx²y
volume of a cone = 1 / 3 πr²h
where
r = radius of the coneh = height of the coneTherefore,
πx²y = 1 / 3 × π × (1 / 2x)² × h
πx²y = πh / 12x²
πx²y × 12x² / π = h
h = 12x⁴y
Therefore, the height of the cone in terms of y is h = 12x⁴y
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Find the total surface area of the cone in the figure. (Use π = 3.14.)
radius - 5cm, height - 12cm
I need help on how to solve for Z
Answer:
[tex]z=\frac{t^{2}(m-3) }{4}[/tex] or [tex]z=\frac{1}{4}t^{2} (m-3)[/tex]
Step-by-step explanation:
[tex]t=\sqrt{\frac{4z}{m-3} }[/tex]
[tex]t^{2} =\frac{4z}{m-3}[/tex]
[tex]4z=t^{2} (m-3)[/tex]
[tex]z=\frac{t^{2}(m-3) }{4}[/tex]
Hope this helps
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each quadratic function with its respective graph. Graph Functions Graph of quadratic functions on a coordinate plane. Upward parabola vertex is at (2, 1) in quadrant 1. Left slope at (1, 2), (0, 5) enters quadrant 3. Right slope is at (3, 2), (4, 5) in quadrant 1. arrow Both Graph shows downward parabola plotted on a coordinate plane. The parabola has vertex at (minus 1, 4). The parabola has left slope at (minus 3, 0) and right slope at (1, 0). arrowBoth Graph shows upward parabola plotted on a coordinate plane. The parabola has vertex at (3, minus 4). The parabola has left slope at (1, 0) and right slope at (5, 0). arrowBoth
The correctly matched quadratic functions are given as follows:
Part A) The function of the First graph is f(x) = (x-3) (x + 1) Part B) The function of the Second graph is f(x) = -2 (x - 1) ( x + 3) Part C) The function of the Third graph is f(x) = 0.5(x - 6) (x + 2) What is a Quadratic Function?Quadratics are polynomial equations of the second degree, which means that they contain at least one squared term.
Quadratic equations are another name for it. The quadratic equation has the following general form: ax2 + bx + c = 0.
How do we correctly match the graphs?Recall that:
f(x) - a (x -c) (x - d)
where
a is the leading coefficientc and d are the roots or zeros of the function.Part A) First graph
We are given to know
The solutions or zeros of the first graph are
x=-1 and x=3
The parabola open up, so the leading coefficient a is positive, the function therefore, is equal to
f(x) = (x-3) (x + 1); Find the value of the coefficient a.The vertex is equal to the point (1, -4)
Substitute and solve for a
-4 = a(1-3)(1+1)
-4 = a(-2)(2)
a = 1
Hence, the function is equal to f(x) = (x-3) (x + 1)
Part B) Second Graph
We are also given to know that
The solutions or zeros of the first graph are
x=-3 and x=1
The parabola open down, so the leading coefficient a is negative
The function is equal to f(x) = a (x-1)(x+3)
Find the value of the coefficient a
The vertex is equal to the point (-1,8)
to solve for a, we must substitute:
8 = a(-1-1) (-1+3)
8 = a(-2)(2)
a = -2
Hence, the function is equal to: f(x) = -2 (x - 1) ( x + 3)
Part C)
We are given to know that the solutions or zeros of the first graph are
x=-2 and x=6
The parabola open up, so the leading coefficient a is positive
The function is equal to f(x) = a(x-6) (x+2).
Find the value of the coefficient a
The vertex is equal to the point (2,-8)
We substitute and solve for a:
-8 = a(2-6) (2+2)
-8 = a(-4)(4)
a = 0.5
Hence, the function is equal to f(x) = 0.5(x - 6) (x + 2)
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If the graph of f(x)=x2, how will the graph be affected if it is changed to f(x)=3x2?
There will be a vertical stretch with a factor of 3.
16. The average age of a group of 8 people is 22. After the oldest person leaves the room the average age decreases to 20. How old was the person who left the room? (A) 15 (B) 16 (C) 24 (D) 36
The age of the oldest person that leaves the room is 36 years
How to calculate the average of a data?The average of a data is defined as the ratio of the sum of the data to the sample size. Mathematically;
Average = sum/sample size
If the average age of a group of 8 people is 22. then;
22 = Xn/8
Xn = 22 * 8
Xn = 176
If after the oldest person leaves the room the average age decreases to 20, hence;
20 = H/7
H = 140
Xn = H + x
176 = 140 + x
x = 176 - 140
x = 36
Hence the age of the oldest person that leaves the room is 36 years
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Find the surface area of the pyramid with a regular pentagon as its base. Round to the nearest tenth if necessary. (13 is the length of the edge not the slant)
The surface area of this pyramid with a regular pentagon as its base is equal to 851.09 square units.
How to calculate the surface area?In Mathematics, a complete circle has a magnitude of 360° and when it is divided by the 10 triangles, the angle formed at the center of the pentagon would always be equal to 36°.
Also, the length of the apothem of a pentagon can be calculated by using this formula:
a = s/2tan(36)
Where:
a represents the length of the apothem of a pentagon.s represents the length of the sides of a pentagon.Substituting the given parameters into the formula, we have;
a = 10/2tan(36)
a = 10/1.45
a = 6.90 units.
Next, we would determine the slant height of this pyramid by applying Pythagorean theorem:
c² = a² + b²
c² = 6.9² + 13²
c² = 47.61 + 169
c² = 216.1
c = √216.1
c = 14.72 units.
For the surface area, we have:
Mathematically, the surface area of a pyramid with a regular pentagon as its base can be calculated by using this formula:
SA = 1.72l² × (5/2 × l × h)
SA = 1.72(14.72)² × (5/2 × 14.72 × 13)
SA = 372.69 + 478.4
SA = 851.09 square units.
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Daniela recorded the low temperatures during the school day last week and this week. Her results are shown in the table below.
Low Temperatures during the School Day This Week and Last Week
Low Temperatures
This Week (Degrees Fahrenheit)
42
38
45
46
39
Low Temperatures
Last Week (Degrees Fahrenheit)
56
58
52
62
62
Daniela used the steps below to find a relationship between the difference in the mean temperatures and the mean absolute deviations of the data sets.
This Week Last Week
Step 1
Find the mean.
StartFraction 42 + 38 + 45 + 46 + 39 over 5 EndFraction = 42
Find the mean.
StartFraction 56 + 58 + 52 + 62 + 62 over 5 EndFraction = 58
Step 2
Find the mean absolute deviation.
StartFraction StartAbsoluteValue 42 minus 42 EndAbsoluteValue + StartAbsoluteValue 38 minus 42 EndAbsoluteValue + StartFraction StartAbsoluteValue 45 minus 42 EndAbsoluteValue + StartFraction StartAbsoluteValue 46 minus 42 EndAbsoluteValue + StartFraction StartAbsoluteValue 39 minus 42 EndAbsoluteValue over 5 EndFraction = 2.8
Find the mean absolute deviation.
StartFraction StartAbsoluteValue 56 minus 58 EndAbsoluteValue + StartAbsoluteValue 58 minus 58 EndAbsoluteValue + StartFraction StartAbsoluteValue 52 minus 58 EndAbsoluteValue + StartFraction StartAbsoluteValue 62 minus 58 EndAbsoluteValue + StartFraction StartAbsoluteValue 62 minus 58 EndAbsoluteValue over 5 EndFraction = 3.2
Step 3 Find the ratio of the differences of the means compared to the mean absolute deviation.
StartFraction 42 over 2.8 EndFraction = 15 Find the ratio of the differences of the means compared to the mean absolute deviation.
StartFraction 58 over 3.2 EndFraction = 18.125
Step 4 The difference in the means is about StartFraction 15 + 18 over 2 EndFraction = 16.5 times the mean absolute deviations.
In which step did Daniela make the first error?
Based on the information given about the temperature, Daniela made her error on step 3 because it says: "Find the ratio of the differences of the means compared to the mean absolute deviation.
How to illustrate the error?From the information given, it van be seen that Daniela recorded the low temperatures during the school day last week and this week and her results are shown in the table.
Here, she didn't find the difference between the today and last week means. She just put the mean as a whole.
Therefore, Daniela made her error on step 3 because it says: "Find the ratio of the differences of the means compared to the mean absolute deviation. This was the error.
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algebra 2: help please
a scuba diver enters the water 1m away from her boat. She dives down and then resurfaces 12m away from her boat. Her diving path id in the shape of a quadratic function, where x is the distance away from the boat and y is the distance away from the surface of the water, and negative values of y are below the water. She reaches a maximum depth of 30.25m below the surface of the water.
Her diving partner wants to estimate the diver’s depths at different points away from the boat. What is the diver’s depth when she is 4m away from the boat?
Answer:
24 m depth
Step-by-step explanation:
The quadratic function modeling depth will have zeros at x=1 and x=12, the distances in meters from the boat where the diver is at the surface.
Quadratic functionThe factored form of a quadratic function can be written as ...
y = a(x -p)(x -q)
where p and q are zeros of the function. The value 'a' is a vertical scale factor.
Here, we are given y=0 at the surface, at points where x=1 and x=12. This means the function can be written as ...
y = a(x -1)(x -12)
Scale factorTo find the value of 'a', we can use the maximum depth value. That depth will be halfway between the function zeros, at x = (1+12)/2 = 6.5
-30.25 = a(6.5 -1)(6.5 -12)
30.25 = 5.5²·a = 30.25a ⇒ a=1
Model of depthThen the function modeling the diver's depth in meters is ...
y = (x -1)(x -12)
And the depth at x=4 will be ...
y = (4 -1)(4 -12) = 3(-8) = -24 . . . . meters
The diver's depth is 24 meters when she is 4 m away from the boat.
Pythagorean Theorem
In a right triangle, the square of the _____ equals the sun of the squares of the ______.
Answer: In a right triangle, the square of the Hypotenuse equals the sun of the squares of the other two sides.
Step-by-step explanation: a^2+b^2=c^2
Answer: the Pythagoras theorem states that in a right angled triangle, the square of THE HYPOTENUSE is equal to the sum of the squares of the OTHER TWO SIDES.
Step-by-step explanation: :)
PLS HELP ITS MATH PLS
Answer:
Step-by-step explanation:
y=-1/2x+6
Geometry: fill in the blanks, ASAP!!!
5. Alternate interior angles: ∠1 ≅ ∠5; ∠5 ≅ ∠7 and ∠4 ≅ ∠6
6. Alternate exterior angles: ∠3 ≅ ∠9 and ∠2 ≅ ∠8
7. Corresponding angles: ∠2 ≅ ∠6; ∠3 ≅ ∠7; ∠5 ≅ ∠9; ∠4 ≅ ∠8 and ∠1 ≅ ∠3
8. Vertical angles: ∠2 ≅ ∠4; ∠3 ≅ ∠5; ∠7 ≅ ∠9; and ∠6 ≅ ∠8 .
9. ∠1 and ∠7.
What are the Special Pairs of Angles Formed by a Transversal and Parallel Lines?If two lines that are cut across by a transversal are parallel, the following special angles are formed:
Corresponding angles which are congruent: they share the same corner and lie along a transversal.Alternate interior angles which are congruent: they lie opposite each other along the transversal inside each parallel lines.Alternate exterior angles which are congruent: they lie opposite each other along the transversal outside each parallel lines.Vertical Angles which are congruent: they are directly opposite each other and share the same vertex but they are non-adjacent.Given the image given, we can identify the following special angles:
5. Alternate interior angles: ∠1 ≅ ∠5; ∠5 ≅ ∠7 and ∠4 ≅ ∠6
6. Alternate exterior angles: ∠3 ≅ ∠9 and ∠2 ≅ ∠8
7. Corresponding angles: ∠2 ≅ ∠6; ∠3 ≅ ∠7; ∠5 ≅ ∠9; ∠4 ≅ ∠8 and ∠1 ≅ ∠3
8. Vertical angles: ∠2 ≅ ∠4; ∠3 ≅ ∠5; ∠7 ≅ ∠9; and ∠6 ≅ ∠8 .
9. ∠1 ≅ ∠3 and ∠3 ≅ ∠7. So the two angles would be ∠1 ≅ ∠7.
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