What pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c?
a) 4. 1 atm
b) 5. 0 atm
c) 6. 4 atm
d) 1. 1 atm

At r = 0.766 R the magnetic field intensity will be half of its value at the center of the current carrying loop.

We have a circular loop of radius ' r ' carrying current ' i '.

We have to find at what distance along the axis of the loop is the magnetic field one-half its value at the center of the loop.

The formula to calculate the magnetic field intensity due to a current carrying ( i ) circular loop of radius ' R ' at a distance ' x ' on its axis is given by -

[tex]B(x) = \frac{\mu_{o} iR^{2} }{2(x^{2} +R^{2})^{\frac{3}{2} } }[/tex]

Now, for magnetic field intensity at the center of the loop can calculated by putting x = 0 in the above equation. On solving, we get -

[tex]B(0) = \frac{\mu_{o} i}{2R}[/tex]

Let us assume that the distance at which the magnetic field intensity is one-half its value at the center of the loop be ' r '. Then -

[tex]\frac{\mu_{o} iR^{2} }{2(r^{2} +R^{2})^{\frac{3}{2} } } = \frac{1}{2} \frac{\mu_{o}i }{2R}[/tex]

[tex]2R^{3} = (r^{2} +R^{2} )^{\frac{3}{2} }[/tex]

[tex]4R^{6} = (r^{2} +R^{2} )^{3}[/tex]

[tex]r^{2} =0.587R^{2}[/tex]

r = 0.766R

Hence, at r = 0.766 R - the magnetic field intensity will be half of its value at the center of the current carrying loop.

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A subcritical state will result by flattening a critical mass of fissionable material into the shape of a hamburger.

To find the answer, we need to know about the critical mass.

Thus, we can conclude that, a subcritical state will result by flattening a critical mass of fissionable material into the shape of a hamburger.

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When conducting a hypothesis test for a given sample size, if α is increased from 0.05 to 0.10, then the probability of incorrectly rejecting the null hypothesis increases ,the probability of incorrectly failing to reject the null hypothesis decrease, the probability of Type II error decreases.

A. the probability of incorrectly rejecting the null hypothesis increases

B. the probability of incorrectly failing to reject the null hypothesis decreases

C. the probability of Type II error decreases

Higher values of α make it easier to reject the null hypothesis, so choosing higher values for α can reduce the probability of a Type II error. The consequence here is that if the null hypothesis is true, increasing α makes it more likely that we commit a Type I error.

A type 1 error is also known as a false positive and occurs when a researcher incorrectly rejects a true null hypothesis. This means that your report that your findings are significant when in fact they have occurred by chance.

hence , all the options are correct

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When one member of a binary star system is a black hole, and astronomers detect flickering x-rays coming from the system, these x-rays usually coming from a disk of material around the black hole (material that has been pulled from the companion star and is falling toward the black hole).

A binary black hole (BBH) is a system consisting of two black holes in close orbit around each other. Like black holes themselves, binary black holes are often divided into stellar binary black holes, formed either as remnants of high-mass binary star systems or by dynamic processes and mutual capture; and binary supermassive black holes, believed to be a result of galactic mergers.

For many years, proving the existence of binary black holes was made difficult because of the nature of black holes themselves and the limited means of detection available.

However, in the event that a pair of black holes were to merge, an immense amount of energy should be given off as gravitational waves, with distinctive waveforms that can be calculated using general relativity.

Therefore, during the late 20th and early 21st century, binary black holes became of great interest scientifically as a potential source of such waves and a means by which gravitational waves could be proven to exist. Binary black hole mergers would be one of the strongest known sources of gravitational waves in the universe, and thus offer a good chance of directly detecting such waves.

As the orbiting black holes give off these waves, the orbit decays, and the orbital period decreases. This stage is called binary black hole inspiral. The black holes will merge once they are close enough. Once merged, the single hole settles down to a stable form, via a stage called ringdown, where any distortion in the shape is dissipated as more gravitational waves. In the final fraction of a second the black holes can reach extremely high velocity, and the gravitational wave amplitude reaches its peak.

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The military time corresponding to 3:00p.m is 1500, and it is pronounced as fifteen hundred hours.

To find the answer, we have to know more about the Military time.

Thus, we can conclude that the option B is right.

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A current of 0. 82A flows through a light bulb. The charge passed through the light bulb during 94 s is 77.08C

The amount of charge flown for a given period of time determines the current passed through a bulb or electrical body.

The relation between the charge, current and time is given as:

Q = I × t

where, Q is the charge flown through bulb

I is the current passed through bulb

t is the time for which charge passes through bulb

Given,

I = 0.82A

t = 94s

Q = ?

Substituting the values in the above formula:

Q = I × t

Q = 0.82 × 94

Q = 77.08C

Hence, The charge passed through the light bulb during 94 s is 77.08C

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A Capacitor is a device consisting of two conductors that can be charged with equal and opposite charges, separated by a thin insulator.

According to principle of a capacitor, capacitor is a system of conductors or dielectric.

If there is a single conductor, it cannot holds very much current then its potential reaches to its maximum values and it cannot hold more charge.

If we place another conductor near it, its potential becomes low and it is able to store more charge.

We know from the definition of the capacitor, A capacitor is a two-terminal electrical device that possesses the ability to store energy in the form of an electric charge. It consists of two electrical conductors that are separated by a distance.  

Capacitors store energy by holding apart pairs of opposite charges. The simplest design for a capacitor is a parallel plate capacitor.

Therefore, this device is called a capacitor.

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Possible beat frequencies with tuning forks of frequencies 255, 258, and 260 Hz are 2, 3 and 5 Hz respectively.

The beat frequency refers to the rate at which the volume is heard to be oscillating from high to low volume. For example, if two complete cycles of high and low volumes are heard every second, the beat frequency is 2 Hz. The beat frequency is always equal to the difference in frequency of the two notes that interfere to produce the beats. So if two sound waves with frequencies of 256 Hz and 254 Hz are played simultaneously, a beat frequency of 2 Hz will be detected. A common physics demonstration involves producing beats using two tuning forks with very similar frequencies. If a tine on one of two identical tuning forks is wrapped with a rubber band, then that tuning forks frequency will be lowered. If both tuning forks are vibrated together, then they produce sounds with slightly different frequencies. These sounds will interfere to produce detectable beats. The human ear is capable of detecting beats with frequencies of 7 Hz and below.

A piano tuner frequently utilizes the phenomenon of beats to tune a piano string. She will pluck the string and tap a tuning fork at the same time. If the two sound sources - the piano string and the tuning fork - produce detectable beats then their frequencies are not identical. She will then adjust the tension of the piano string and repeat the process until the beats can no longer be heard. As the piano string becomes more in tune with the tuning fork, the beat frequency will be reduced and approach 0 Hz. When beats are no longer heard, the piano string is tuned to the tuning fork; that is, they play the same frequency. The process allows a piano tuner to match the strings' frequency to the frequency of a standardized set of tuning forks.

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Observing star clusters will give astronomers needed data for stellar evolution because all the stars in the have the same Age

A star changes over time through a process called stellar evolution. A star can have a life that is substantially longer than the age of the universe, ranging from a few million years for the most massive to billions of years for the least massive.

Stellar evolution is a term used to describe how stars change through time. Most stars don't seem to change much on a human time scale, but if we looked for billions of years, we would witness how stars are born, how they grow older, and then how they die. Stellar evolution is significant because it produces the majority of the components.

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17.90 KJ of energy must be added to 69. 0 grams of water to change the temperature from 33°C to 95°C

Specific heat, the quantity of heat required to raise the temperature of one gram of a substance by one Celsius degree. The units of specific heat are usually calories or joules per gram per Celsius degree.

Heat added = H = mc(ΔT )

where,

H = heat

m = mass of water = 69 g

c = specific heat of water = 4.184 J/g/°C

ΔT = change in temperature

H = 69 * 4.184 * ( 95 - 33 )

H   = 17899.152 J

     = 17.90 KJ

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Chyme is a semi-liquid paste that results from the mixing of partially digested food with gastric juice in the stomach.

When food enters the stomach, the gastric gland releases gastric juice, which the stomach's muscular wall thoroughly stirs into the meal. Chyme is the term for partially digested food that contains gastric juice.

Only a small amount of chyme is released into the small intestine at a time. The movement of chyme from the stomach into the small intestine is regulated by the pyloric sphincter.

In contrast, chyle is a milky body fluid made up of lymph and free fatty acids that have been emulsified (FFAs). While roughage refers to the inorganic fibre included in food, it is generated in the small intestine after the breakdown of fatty foods and taken up by lymph channels specifically known as lacteals.

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Speed of a car = 36 km/h

Time taken = 15 minutes

Converting the time into hour:-

= 15/60 hours

= 1/4 hours

As we know that,

= (36 × 1/4) kilometres

= 9 kilometres

Hence the distance covered is 9 kilometres.

This is a uniform rectilinear motion exercise.

To start solving this exercise, we obtain the following data:

                                     Minutes to hour converter

                                                  60 min = 1 hour

                                       [tex]\boldsymbol{\sf15\not{min}*\dfrac{1 \ hr}{60 \not{min}}=0.25 \ hr }}[/tex]

To calculate distance, speed is multiplied by time.

We apply the following formula: d = v * t

We substitute our data into the formula:

                                     [tex]\boldsymbol{\sf{d=v*t}}[/tex]

                                     [tex]\boldsymbol{\sf{d=36 \dfrac{km}{\not{h}}*0.25 \not{h} }}[/tex]

                                     [tex]\boldsymbol{\sf{d=9 \ km}}[/tex]

The distance traveled by a car moving with a speed of 36 km/h in 15 m is 9 km.

The flux through the paper when the paper is turned 25° with respect to field will be 22.67 [tex]Nm^{2} /C[/tex].

We have a piece of paper is held with one face perpendicular to a uniform electric field the flux through it is 25 [tex]Nm^{2} /C[/tex].

Now we have to calculate the flux through the paper if it is turned 25° with respect to the field.

Electric flux (E) through a surface is defined as the dot product of Electric field vector and Normal vector to the surface. The formula to calculate the electric flux is -

Φ = [tex]\vec{E}.\vec{A}[/tex] = E x A x cosθ

In the question it is given that when one face perpendicular to a uniform electric field the flux through it is 25 [tex]Nm^{2} /C[/tex]. In this case θ = [tex]0^{o}[/tex].

Therefore -

E x A x cos [tex]0^{o}[/tex] = 25

EA = 25 [tex]Nm^{2} /C[/tex]

When the paper is turned [tex]25^{o}[/tex] with respect to field, then the flux through it can be calculated as follows -

Φ = 25 x cos ([tex]25^{o}[/tex]) = 22.67 [tex]Nm^{2} /C[/tex].

Hence, the flux through the paper will be 22.67 [tex]Nm^{2} /C[/tex].

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The magnitude of the magnetic field at the location of the charge due to the current-carrying wire is given as B = μI/2πr.

A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials.

A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field.

The magnitude of the magnetic field at the location of the charge due to the current-carrying wire is calculated as follows;

B = μI/2πr

where;

Thus, the magnitude of the magnetic field at the location of the charge due to the current-carrying wire is given as B = μI/2πr.

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The rms voltage output of the generator is 1.94 × 10⁻ ⁵ V.

RMS is an acronym for root mean squared. An RMS value is more than just the "amount of AC power that causes the same heating impact as an analogous DC power" or something along those lines.

No. of loop = 795

Diameter of the coil = 10.5 cm

Radius of the coil = 5.25 cm

Magnetic Field, B = 0.45 T

Time, t = 70.0 rev/s

              [tex]V_{rms} =\frac{NwAB}{\sqrt{2} }[/tex]

Where,

              N = No. of loop

              A = Area of the coil

              B = Magnetic Field

              [tex]V_{rms}[/tex] = Voltage rms

Area of the coil = πr²

                        = 86.57 cm²

w = 2π/t

   =( 2 × 3.141)/70.0

   = 0.089

[tex]V_{rms} =\frac{795*0.089*86.57* 0.45}{\sqrt{2} }\\\\V_{rms} =\frac{2756.36}{\sqrt{2} }\\\\\\V_{rms} =\frac{2756.36}{1.414 }\\\\V_{rms} = 1.94 * 10^-^5 V[/tex]

Therefore, the rms voltage output of the generator is 1.94 × 10⁻ ⁵ V.

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According to the Elements of Style, the telescope was set up on the tripod by the astronomy club.

To find the answer, we need to know about the revision.

Thus, we can conclude that, according to the Elements of Style, the telescope was set up on the tripod by the astronomy club.

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The empirical formula of the antimony chloride is [tex]SbCl_{3}[/tex].

Chemical formulas for compounds that simply specify the proportions of the elements they contain rather than the exact number or arrangement of atoms are known as empirical formulas. The element in the compound with the lowest whole number ratio would be this one.

Data obtained from the question

Antimony (Sb) = 0.338 g

Chlorine (Cl) = 0.295 g

Divide by their molar mass.

Sb = 0.338 / 122 = 0.0028

Cl = 0.295 / 35.5 = 0.0083

Divide by the smallest.

Sb = 0.0028 / 0.0028 = 1

Cl = 0.0083 / 0.0028 = 3

Thus, the empirical formula of the compound is SbCl₃.

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Answer:

Book. Bottle. table are some examples of objects in equilibrium found in classroom

When discharging equivalent of 0% starting voltage will the capacitor reach after 5RC.

V(t) = V0e-t/RC = V0b initially.

The numerous kinds of capacitors and their applications.

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The value of the equivalent resistance for the three resistors connected in series will be the sum of the three values.

To find the answer, we have to know more about the equivalent resistance.

                [tex]R_E=R_1+R_2+..........+R_n[/tex]

               [tex]R_E=R_1+R_2+R_3[/tex]

Thus, we can conclude that, the value of the equivalent resistance for the three resistors connected in series will be the sum of the three values.

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In comparison to a vacuum, the speed of light in glass is 1.52 times slower.

To find the answer, we need to know more about the refractive index.

This implies that the speed of light is 1.52 times slower in glass than in a vacuum.

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The hydroxide ion concentration in a solution is 3.31*10^-8M.

To find the answer, we have to know more concentration of solution.

                     [tex]pH=-log[H_3O^+][/tex]

                   [tex][H_3O^+]=-10^{pH}=10^{-6.25}=5.6*10^{-7}M[/tex]

                        [tex]K_w=[H_3O^+][OH^-]\\Where,\\K_w=10^{-14}[/tex]

                         [tex][OH^-]=\frac{K_w}{[H_3O^+]} =\frac{10^{-14}}{10^{-6.52}}\\\\[/tex]

                           [tex][OH^-]=3.31*10^{-8}M[/tex]

Thus, we can conclude that, the hydroxide ion concentration in a solution is 3.31*10^-8M.

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An Olympic high diver has gravitational potential energy because of her height. As she dives, kinetic energy becomes of her energy just before she hits the water.

Gravitational potential energy is the energy possessed or acquired by an object due to a change in its position when it is present in a gravitational field. In simple terms, it can be said that gravitational potential energy is an energy that is related to gravitational force or to gravity.

Kinetic energy is the energy of motion, observable as the movement of an object, particle, or set of particles.

When the high diver is standing stable and not moving , that diver has a gravitational potential energy because of the height . The moment she dives , before hitting the water , from being stationary she gained some momentum and come in motion , due to motion her gravitational potential energy will change to kinetic energy before hitting the ground.

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Answer:

if a car is increasing it's acceleration uniformly in a unit time, the graph will be moving away from it's origin. that's how you get this kind of graph.

A drift velocity in physics is the average speed that charged particles—like electrons—achieve within a material as a result of an electric field. An electron will typically move randomly across a conductor at the Fermi velocity, producing an average velocity of zero. Applying an electric field causes a little net flow in one direction to be added to this random motion; this is the drift.

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Drift velocity

it is a average speed of the particle reached in a random motion

The angle between the transmission axes of the polarizers if it is desired that one-tenth of the incident intensity be transmitted, ∝ = 63.435°

We'll assume that [tex]I_{0}[/tex] represents the incident light's intensity. Two polarizers are provided to us, but the first polarizer's angle is not disclosed. The incident light in situations like this needs to be unpolarized. This is due to the fact that, regardless of angle, the transmitted intensity via the polarizer is reduced by half for unpolarized light:

[tex]I_{1} =\frac{1}{2} I_{0}[/tex]

Then,

[tex]I_{2} =\frac{1}{10} I_{0}[/tex]

By using Malu's law,

[tex]I_{2} =I_{1} cos^{2} \alpha[/tex]

That is,

[tex]cos^{2} \alpha = \frac{I_{2} }{I_{1} }[/tex]

In terms of [tex]I_{0}[/tex], we get

[tex]cos^{2} \alpha =\frac{0.1I_{0} }{0.5I_{0} }[/tex]

[tex]cos^{2} \alpha = 0.2[/tex]

Now the angle is,

[tex]cos\alpha =\sqrt{0.2}[/tex]

cos ∝ = 0.44721

[tex]\alpha =cos^{-1} (0.44721)[/tex]

Then, ∝ = 63.435°

This angle is measured with respect to the first polarizer angle.

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The distance should be increased by 0.4 mm.

Lens formula is used here.

For a spherical mirror, the focal length, image distance, and object distance are all related by the lens equation, often known as the lens formula.

It is given by,

[tex]\frac{1}{f} = \frac{1}{v} -\frac{1}{u}[/tex]

where,

f = focal length

u = distance of the object

v = distance of the image formed

Given,

f = 40 mm

u = 4 m = 4000 mm

v =?

Using the lens formula,

[tex]\frac{1}{f} = \frac{1}{v} -\frac{1}{u}[/tex]

[tex]\frac{1}{40} = \frac{1}{v} -\frac{1}{4000}\\[/tex]

[tex]\frac{1}{v} = \frac{1}{40} + \frac{1}{4000}[/tex]

v = 39.6 mm

Change in distance = 40 - 39.6

                                 = 0.4 mm

Hence, the distance should be increased by 0.4 mm.

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0.4 mm

The distance should be increased by 0.4 mm.

We use lens formula here,

[tex]\frac{1}{f}[/tex] = [tex]\frac{1}{v}[/tex] - [tex]\frac{1}{u}[/tex]

where,

f =  focal length

u = distance of the object

v = distance of the image formed

Given that,

f = 40 mm

u = 4 m = 4000 mm

v = ?

Using the lens formula, we get:

[tex]\frac{1}{f}[/tex] = [tex]\frac{1}{v}[/tex] - [tex]\frac{1}{u}[/tex]

[tex]\frac{1}{40}[/tex] = [tex]\frac{1}{v}[/tex] - [tex]\frac{1}{4000}[/tex]

[tex]\frac{1}{v}[/tex] = [tex]\frac{1}{40}[/tex] + [tex]\frac{1}{4000}[/tex]

v = 39.6 mm

Change in the distance = 40 - 39.6

                                        = 0.4 mm

Therefore, the distance has to be increased by 0.4 mm

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Hi, your answer is below.

Time dilation is usually defined as the slowing of the passage of time experienced by objects in motion relative to an observer; measurable only a relativistic speeds.  Because time moves at various rates for the two of them depending on their relative velocities and/or proximity to things of considerable mass, if two persons (or objects) are moving relative to one another, they will age at separate rates. They will age differently from one another over time since their two timepieces will really tick at separate speeds. If they cross paths again later, they will both have aged differently, which may be determined by using their own timepieces, presuming they each had one. Einstein's Special and General Relativity equations, which have undergone extensive testing over the past 115 years and have never been shown to falter, regulate this "time dilation." The general relativity theory of Einstein, which states that a huge body's gravity warps space-time around it, causes time to move more quickly or more slowly depending on how far away the mass is from the observer, is what causes this so-called "time-dilation" phenomenon.

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The rms current in the transmission lines is I = 487.18 A.

The root-imply-rectangular (rms) voltage of a sinusoidal supply of electromotive force  is used to represent the source. it is the rectangular root of the time average of the voltage squared.

Alternating-present day circuits. the root-imply-square (rms) voltage of a sinusoidal source of electromotive force is used to symbolize the supply. it's far the square root of the time average of the voltage squared.

Electric power is  by using present day or the waft of electric fee and voltage or the capacity of rate to deliver electricity. A given cost of power can be produced by using any combination of contemporary and voltage values

power = 38 M watt

rms voltage = 78 K v

power = IV

I = power/V

I = (38 * 1000000)/78*1000

I = 487.18 A.

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The overall dimming of starlight passing through dust clouds is Extinction .

To find the answer, we need to know more about the Extinction.

Thus, we can conclude that, the overall dimming of starlight passing through dust clouds is Extinction .

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