0.56 V is the standard potential, e∘cell∘, for this galvanic cell.
The standard reduction potential can be calculated by subtracting the standard reduction potential for the reaction occurring at the cathode from the standard reduction potential for the reaction occurring at the anode. The minus sign is necessary because oxidation is the polar opposite of reduction. The total cell potential can be calculated using the formula E0cell=E0red+E0oxid. Step two is to find a solution. Before the two reactions may be integrated, the number of electrons gained in the reduction must match the number of electrons lost in the oxidation
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#4204.
The standard potential for the given galvanic cell is 0.477 V
What is electrode potential?The electrode potential is the electromotive force of a galvanic cell built using a standard reference electrode and another electrode whose potential is to be found.
There are two types of electrode potential
Oxidation potential - The potential associated with oxidation reaction is known as oxidation potential
Reduction potential - The potential associated with reduction reaction is known as reduction potential
At the anode, oxidation occurs
[tex]Sn(s)\rightarrow Sn^{2+}(aq)+2e^-[/tex]
At the cathode, reduction occurs
[tex]Cu^{2+}(aq)+2e^-\rightarrow Cu(s)[/tex]
[tex]E^o_{cell} =E^o_{cathode} -E^o_{anode}[/tex]
= 0.337 - (-0.140)
= 0.477 V
Thus, The standard potential for the given galvanic cell is 0.477 V
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Disclaimer: The question was given incomplete on the portal. Here is the complete question
Question: What is the standard potential, E∘cell, for this galvanic cell? Use the given standard reduction potentials in your calculation as appropriate.
[tex]Sn^{2+}(aq)+2e^-\rightarrow Sn(s)[/tex], E°red=−0.140 V
[tex]Cu^{2+}(aq)+2e^-\rightarrow Cu(s)[/tex], E°red=+0.337 V
1.0 mole of a gas is enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm. Half of the gas is removed, leaving 0.50 mole in the cylinder and the system is warmed to 900 K. The cylinder changes volume to maintain constant pressure. What is the volume in the final system?
The volume in the final system that was initially enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm is 36.9L.
How to calculate volume?The volume of a given amount of gas can be calculated by using the combined gas law formula as follows;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressureP2 = final pressureT1 = initial temperatureT2 = final temperatureV1 = initial volumeV2 = final volumeAccording to this question, 1.0 mole of a gas is enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm.
However, half of the gas is removed, leaving 0.50 mole in the cylinder and the system is warmed to 900 K. The volume in the final system can be calculated as follows:
2 × 12.3/300 = 2 × V2/900
0.082 = 2V2/900
73.8 = 2V2
V2 = 73.8 ÷ 2
V2 = 36.9L
Therefore, the volume in the final system that was initially enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm is 36.9L.
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Answer:
Explanation:
it's 18.45, my sister just got the guestion right! hope it helps :)
A salt solution contains ammonium cation (ka = 5.7 × 10^–10) and nitrite anion (kb = 1.4 × 10^–11) in equal proportions. The ph of the solution will be?
The ph of the solution will be acidic. It is because of the higher ka value of ammonia as compared to kb of nitrate
As we know, A salt solution contains ammonium cation (ka = 5.7 × 10^–10) and nitrite anion (kb = 1.4 × 10^–11) in equal proportions but the ka and kb are different.
As we see that the value of ka is higher than the kb that's why the ph level will be acidic.
Acidic solutions are sour in taste as compared to alkaline solutions.
We know that the ph scale basically ranges from 0 to 14. The ph solutions less than 7 are acidic and greater than 7 are basic.
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A mixture of reactants and products for the reaction shown below is at
equilibrium in a 2.0 L container. What would most likely happen to the
equilibrium if the volume of the container were increased to 4.0 L?
N₂(g) + 3H₂(g)—2NH₂(g)
A. More NH3 would be produced.
B. Less N₂, H₂, and NH3 would be produced.
C. More N₂, H₂, and NH3 would be produced.
D. More N₂ and H₂ would be produced.
If the volume of the container were increased to 4.0 L, more N₂ and H₂ would be produced (Option D)
What is chemical equilibrium?
This is simply defined as a state in a chemical system where there is no observable change in the properties of the system with time.
Principle of chemical equilibriumA French scientist postulated a principle which helps us to understand a chemical system in equilibrium.
The principle states as follow:
If a an external constraint such as change in temperature, pressure or concentration is imposed on a system in equilibrium, the equilibrium will shift so as to neutralize the effect.
How to determine what will happen if the volume of the container is increased from 2 L to 4 LFrom the principle given above, we can see that volume does not affect equilirium position.
However, from Boyle's law, we understood that pressure and volume are in invest relationship.
Thus, increasing volume simply means decreasing pressure.
A decrease in pressure will favors the side where there is an increase in volume.
Let us consider the equation from the question:
N₂(g) + 3H₂(g) <=> 2NH₃(g)
Volume of reactants = 1 + 3 = 4 LVolume of products = 2 LThus, we can conclude that increasing the volume (i.e decreasing the pressure) of the reaction will favors the backward reaction, hence, more N₂ and H₂ would be produced.
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The density of aluminum is 2.7 g/cm³. What is the density of aluminum in decagrams/m³?
Answer:
Density = 0.27 decagrams/cm³
Explanation:
From conversion tables, we know that;
1 g/cm³ = 0.1 decagrams/cm³
We are given;
Density of aluminium = 2.7 g/cm³
Thus;
Density = 2.7 * 0.1
Density = 0.27 decagrams/cm³
Answer:
270000 decagrams/m³
Explanation:
1.
Density=mass/Volume
=2.7g/1cm3
=(2.7/1000)/(1/1000000)
=2.7x1000
Density=2700kg/ m3
= 270000 decagrams/m³
2.
1000g=1kg
1g=1/1000kg
1cm3= ? m3
100cm=1m
1cm=1/100 m
1cm3=1/1000000 m3
Be sure to answer all parts. what are the concentrations of hso4−, so42−, and h in a 0. 31 m khso4 solution? (hint: h2so4 is a strong acid; ka for hso4− = 1. 3 × 10−2. ) [hso4−] = m [so42−] = m [h ] = m
At equilibrium the concentrations of:
[HSO₄⁻] = 0.10 M;
[SO₄²⁻] = 0.037 M;
[H⁺] = 0.037 M;
There is initially very little H+ and no SO₄²⁻ in the solution. A salt is KHSO₄⁻. All KHSO₄⁻ will split apart into K⁺ and HSO₄⁻ ions. [HSO₄⁻] will initially be present at a concentration of 0.14 M.
HSO₄⁻ will not gain H⁺ to produce H₂SO₄ since H₂SO₄ is a strong acid. HSO₄⁻ may act as an acid and lose H⁺ to form SO₄²⁻. Let the final H⁺ concentration be x M. Construct a RICE table for the dissociation of HSO₄²⁻.
R [tex]HSO_4^-[/tex] ⇄ [tex]H^+ + SO_4^2^-[/tex]
I [tex]0.14[/tex]
C [tex]- x[/tex] [tex]+x[/tex] [tex]+x[/tex]
E [tex]0.14-x[/tex] [tex]x[/tex] [tex]x[/tex]
[tex]K_a = 1.3[/tex] × [tex]10^-^2[/tex] for [tex]HSO^-_4[/tex] . As a result,
[tex]\frac{[H^+]. [SO_4^2^-]}{HSO_4^-} = K_a[/tex]
[tex]K_a[/tex] is large. It is no longer valid to approximate that [tex][HSO^-_4][/tex] at equilibrium is the same as its initial value.
[tex]\frac{x^2}{0.14-y} = 1.3 * 10^-^2[/tex]
[tex]x^2+1.3*10^-^2x - 0.14[/tex] × [tex]1.3[/tex] × [tex]10^-^2= 0[/tex]
Solving the quadratic equation for [tex]x , x \geq 0[/tex] since [tex]x[/tex] represents a concentration;
[tex]x=0.0366538[/tex]
Then, round the results to 2 significant figure;
[tex][SO_4^2^-] = x = 0.037 mol. L ^-^1[/tex][tex][H^+] = x = 0.037 mol. L ^-^1[/tex][tex][HSO_4^-] = 0.14 - x = 0.10 mol. L ^-^1[/tex]Learn more about concentration here:
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2. Calculate the number of moles represented by the following masses.
a. 2.00 × 102 g of silver
b. 37.1 g of silicon dioxide, SiO2
40 POINTS!!!!!!!!!!!!
a. There are 1.85 moles in 2.00 × 10² g of silver (Ag).
b. There are 0.618 moles in 37.1 g of silicon dioxide (SiO₂)
What is the molar mass?The molar mass is the mass in grams of 1 mole of particles, that is, the mass in grams of 6.02 × 10²³ particles. The units are g/mol.
We want to calculate the number of moles represented by different masses of different substances. In each case, the conversion factor between mass and moles is the molar mass.
a. 2.00 × 10² g of silver (Ag)The molar mass of silver is 107.87 g/mol.
2.00 × 10² g × (1 mol/107.87 g) = 1.85 mol
b. 37.1 g of silicon dioxide (SiO₂)The molar mass of silicon dioxide is 60.08 g/mol.
37.1 g × (1 mol/60.08 g) = 0.618 mol
a. There are 1.85 moles in 2.00 × 10² g of silver (Ag).
b. There are 0.618 moles in 37.1 g of silicon dioxide (SiO₂)
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A ballasted flocculation process has two hydrocyclones in operation (two trains) with an influent flow of 6,000 gpm and a microsand slurry recirculation rate of 300 gpm. Six volumes of samples from the train produced the following volumes of settled microsand: 20 mL, 15 mL, 15 mL, 30 mL, 20 mL, and 20 mL. The six volumes of samples collected in the cone averaged 2,000 mL. Calculate Cm, the microsand concentration in the tanks, in grams of microsand per liter (g/L).
The Cm of the Microsand concentration in the tanks when expressed in grams of Microsand per liter (g/L) is known to be 3.8 g/L.
What is Microsand?This is known to be a kind of aggregate, that is said to be exempted from clay and shale and it is one that can rightly fine to pass via a No. 100 (that is 150 µm) sieve.
Note that from the question:
The Average of six samples = 30mg/L.
Then one need to Multiply:
30 by 300gpm x 1 Train x 1700 ( this is the use of the bulk density conversion factor).
Then one need to also Divide by (4000 gpm x 2000 mL) = 1.8 g/L.
Lastly you then multiply by 2,
1.8 g/L x 2 = 3.8 g/L.
Therefore, looking at the solution above, the Cm of the Microsand concentration in the tanks is seen to be 3.8 g/L.
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How many amps are required to produce 75. 8 g of iron metal from a solution of aqueous iron(iii)chloride in 6. 75 hours?
The amount of current required to produce 75. 8 g of iron metal from a solution of aqueous iron (iii)chloride in 6. 75 hours is 168.4A.
The amount of Current required to deposit a metal can be find out by using The Law of Equivalence. It states that the number of gram equivalents of each reactant and product is equal in a given reaction.
It can be found using the formula,
m = Z I t
where, m = mass of metal deposited = 75.8g
Z = Equivalent mass / 96500 = 18.6 / 96500 = 0.0001
I is the current passed
t is the time taken = 75hour = 75 × 60 = 4500s
On subsituting in above formula,
75.8 = E I t / F
⇒ 75.8 = 0.0001 × I × 4500
⇒ I = 168.4 Ampere (A)
Hence, amount of current required to deposit a metal is 168.4A.
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Describe the principle. Involved in Gas chromatography.
A solution is 0. 0480 m lif. What is the molarity of the solution if the density is 1. 10 g/ml?.
The molarity of the solution is 0.528 mol/l.
What is molarity?
The molarity of any solution is the number of moles per liter of the solution.
Given,
The molality of the solution is 0.0480 m Lif
The density of the solution is 1.10 g/ml
Step 1: 0.0480 moles of LiF were present in 1 kg solvent.
Mass of 0.0480 moles of LiF = 0.0480 mol × 26 g/mol = 1.248 g
Mass of the solution (m)= 1 kg (solvent) + 1.248 g(solute)
m = 1000 g + 1.248 g = 1001.248 g
Step 2: Find the volume of the solution
Step 3: Calculating the molarity
Thus, the molarity of the solution is 0.528 mol/l.
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3. A lab technician is preparing urea broth. It should be sterilized by filtration, he autoclaves it instead, just like he does for any other media. The high temperature of the autoclave causes the urea to break down. What color is the sterile urea broth when it comes out of the autoclave? but rstroedave tocave.
Urea get decomposed during autoclaving, because it is volatile. It is filter sterilized and added aseptically to your autoclave media.
Can urea be autoclaved?
Urea get decomposed during autoclaving, because it is volatile. It is filter sterilized and added aseptically to your autoclave media.What is autoclave sterilization?
In medical and laboratory settings, an autoclave is used to sterilise waste and lab supplies. Heat is used in the autoclave sterilisation process to eliminate bacteria and spores. Pressurized steam provides the heat.What is filter sterilization?
By using filtering, it is possible to exclude organisms based on their size. There are many different kinds of filtration methods, but membrane filtration is utilised to sterilise a system. Contaminants that are larger than the pore size are captured by membrane filtration on the membrane's surface.Learn more about autoclave media.
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What volume (ml) of fluorine gas is required to react with 1. 28 g of calcium bromide to form calcium fluoride and bromine gas at stp?
144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.
What is Ideal Gas Law ?The ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.
PV = nRT
where,
P = Presure
V = Volume in liters
n = number of moles of gas
R = Ideal gas constant
T = temperature in Kelvin
Here,
P = 1 atm [At STP]
R = 0.0821 atm.L/mol.K
T = 273 K [At STP]
Now first find the number of moles
F₂ + CaBr₂ → CaF₂ + Br₂
Here 1 mole of F₂ reacts with 1 mole of CaBr₂.
So, 199.89 g CaBr₂ reacts with = 1 mole of F₂
1.28 g of CaBr₂ will react with = n mole of F₂
[tex]n = \frac{1.28\g \times 1\ \text{mole}}{199.89\ g}[/tex]
n = 0.0064 mole
Now put the value in above equation we get
PV = nRT
1 atm × V = 0.0064 × 0.0821 atm.L/mol.K × 273 K
V = 0.1434 L
V ≈ 144 mL
Thus from the above conclusion we can say that 144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.
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If the dehydration reaction of an alcohol is successful. What changes would be seen in the ir spectrum for the product compared to the starting material?
If the dehydration reaction of an alcohol is successful. The changes would be seen in the IR spectrum for the product compared to the starting material are as,
The O-H and C-O band is disappear from stating materialThe addition of a C-C double bond band in the product.In dehydration reaction of alcohol ( O-H and C-O bond ) contain , the water molecule ( [tex]H_{2}O[/tex] ) is release from the reactant and C-C double bond is form which is known as alkene in the product .
The reactant and product have different structure. To determine the structure of the compound IR spectroscopy is used. In IR spectrum the peak corresponds to 3400-3600 cm is missing in the product of dehydration reaction of an alcohol. It means O-H band is disappear from stating material.
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Find δs∘ for the reaction between nitrogen gas and hydrogen gas to form ammonia:12n2(g) 32h2(g)→nh3(g)
Nitrogen (N2) and hydrogen (H2) gases react to form ammonia, which requires -99.4 J/K of standard entropy (ΔS°).
What is standard entropy?
The difference between the total standard entropies of the reaction mixture and the summation of the standard entropies of the outputs is the standard entropy change. Each entropy in the balanced equation needs to be compounded by its coefficient, as shown by the letter "n."
Calculation:
Balancing the given reaction following-
1/2 N₂(g) + 3/2 H₂ (g)→ NH₃ (g)
ΔS° = [1 mol x S° (NH₃)g] - [1/2 mol x S° (N₂)g] - [3/2 mol x S°(H₂)g]
Here S° = standard entropy of the system
Insert into the aforementioned equation all the typical entropy values found in the literature:
ΔS° = [1 mol x 192.45 J/mol.K] - [1/2 mol x 191.61 J/mol.K] - [3/2 mol x 130.684 J/mol.K]
⇒ΔS° = - 99.4 J/K
Therefore, the standard entropy, ΔS° is -99.4 J/K.
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What is the carbon nucleophile which attacks molecular bromine in the acid-catalyzed α-bromination of a ketone?
The enol carbon or ∝-carbon nucleophile attacks at molecular bromine in the acid-catalyzed α-bromination of a ketone
Treatment of ketones with bromine in the presence of acid will results in formation of a new C-Br bond at the alpha position. The purpose of the acid is to catalysed formation of the enol from ketone , which is active nucleophile in the reaction. This reaction is called haloform reaction which is used to identify the methyl substituted ketone in the presence of aldehyde.
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Another real-world example of a change is rust. rust is iron(iii) oxide (fe2o3), which results when iron is exposed to oxygen and water. what are some indicators of rusting? check all that apply.
Rusting of Iron is the formation of rust which is characterized by formation of layer of red colour. Formula of Rust is Ferric Oxide (Fe₂O₃) where iron exhibits oxidation state of +3.
Following are the indicators of rusting:
Colour change to redSolid formationFlaky substances crumbling into powderEven if the Reddish brown rust is not visible on the iron surface, then also Ferroxyl Indicator turns blue in presence of Iron ions.
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Na -k pumps couple atp hydrolysis with the transport of na and k. in which direction do they move those ions?
Na -k pumps couple atp hydrolysis with the transport of Na and k.
Both ions are used for active transport.
d. K+ and Na+ both diffuse into the cell along their concentration gradients and drive the transport of glucose.
Na/K pump is a pump located on the plasma membrane which uses ATP to move 3 Na ions out the cell and brings in 2 K ions into the cell. It is an example of primary active transport. As a consequence, concentration of Na is higher outside the cell, while K concentration is higher inside the cell.
Glucose is transported in the cell against its gradient, together with Na ions (symport) which move down their concentration gradient.
This is an example of secondary active transport because it uses the energy from the primary active transport to move other substances such as glucose against their own gradients.
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How wide in m is a single slit that produces its first minimum for 624-nm light at an angle of 18. 0°?
A single slit with a width of 2019 * 109 m creates its initial minimal for 624 nm light at an angle of 18°.
How does diffraction work?
Waves spreading outward around obstructions are known as diffraction. Diffraction happens with sound, electromagnetic radiation like light, X-rays, and gamma rays, as well as with incredibly minuscule moving particles like atoms, neutrons, and electrons that exhibit wavelike qualities. Diffraction prevents the creation of sharp shadows as one of its effects. In order to spread out and illuminate regions at which a shadow is anticipated, light must be bent around corners, which is known as diffraction.
Calculation:
Provided for a single slit, m=1
λ = 624 *10⁻⁹
sinθ = sin 18⁰
Therefore,
asinθ=mλ
a = [tex]\frac{1 * 624 *10^{-9} }{sin 18}[/tex]
⇒a = 2019 *10⁻⁹ m
Therefore the width of a single slit is 2019 *10⁻⁹ m.
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Which process in the nitrogen cycle converts nitrogen into its most polluting form?
The process in the nitrogen cycle converts nitrogen into its most polluting form will be "nitrification".
The biological process of nitrification turns ammonia into nitrite and nitrite into nitrate. The technique of denitrification, which turns nitrate into nitrogen gas, is such treatment option if requirements demand that the resultant nitrate be eliminated.
A surplus of nitrogen compounds could result in pollutants like ammonia and ozone that can affect plant growth, visibility, and human capacity to breathe. Excess nitrogen from the atmosphere that returns to earth could be damaging to the health of forests, soils, including streams.
Therefore, the process in the nitrogen cycle converts nitrogen into its most polluting form will be "nitrification".
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Fluids used for an intravenous transfusion must be ________ with bodily fluids. group of answer choices isosmotic hyperosmotic hyposmotic neosmotic magnosmotic
Fluids used for an intravenous fluid transfusion must be isosmotic with bodily fluids.
Intravenous fluids, sometimes abbreviated as "IV fluids," are liquids that are administered to replace water, sugar, and salt that you may need if you're ill or having surgery and are unable to eat or drink regularly. Through a drip, Intravenous fluids are administered directly into a vein.
In order to treat or prevent dehydration, Intravenous fluids are carefully prepared liquids that are injected into a vein. They are applied to patients of all ages who are ill, hurt, becoming dehydrated from physical activity or the heat, or who are having surgery. Rehydrating intravenously is a straightforward, risk-free treatment that is frequently used.
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Draw the major product formed in the reaction involving an acid anhydride dissolved in alcohol.
A symmetrical acid anhydride will undergo a reaction with an alcohol to give an ester and a carboxylic acid. An asymmetrical acid anhydride will undergo a reaction with an alcohol to give two esters and two carboxylic acids.
Alcohols and anhydrides react to produce esters as the main product and a carboxylate as a byproduct. To neutralise any generated acid, the process is often conducted with a base, such as NaOH or pyridine.Learn more about Acid anhydride and alcohol reaction here:
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What is the maximum vertical distance between the line y = x 2 and the parabola y = x2 for −1 ≤ x ≤ 2?
x2=x+2 at x=−1 and x=2 so we have no need to worry about the end-points
f(x)=x+2−x^2
df/dx=1–2x
and that is zero (indicating a maximum) at x=1/2
So the maximum distance is f(1/2)=2.5–0.25=2.25
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The smallest particle of an element that retains all of the properties of that element is called a(n) ______.
Answer:
Atom
Explanation:
That describes an ATOM
What are the two most common unwanted side reactions which can occur when monosaccharides are treated with base?
Epimerization and Enediol rearrangement are the two most common unwanted side reactions which can occur when monosaccharides are treated with base.
Epimerization is a process in stereochemistry in which there is a change in the configuration of only one chiral centre. As a result, a diastereomer is formed. The classical example of this in medicine is tetracycline. In acidic conditions around pH 4, tetracycline readily undergoes epimerization at position 4, and an inactive 4-epitetracycline is produced, which on dehydration forms 4-epianhydrotetracycyline, a highly toxic product. This toxic compound can also be formed from acid catalysed (at lower pH) dehydration of tetracycline via anhydrotetracycline.
Enediol rearrangement is a transformation which occurs at basic medium and allows the conversion of epimers, defined as isomeric forms that differ in the position of the hydroxyl group at C-2. In this way it is possible to transform through the enediol intermediate glucose to mannose and vice versa.
Another important isomerization process through the enediol rearrangement is the interconversion of glucose and fructose. Thus, the enolization proceeds by migration of proton at position 2, to carbon at 1.
Monosaccharides contain both alcohol and carbonyl functional groups. This allows monosaccharides to undergo many of the reactions typical for these functional groups. In particular, alcohols can be converted to esters, converted to ethers, converted to acetals, or oxidized. Carbonyls can be reacted with nucleophiles, be reduced to form alcohols, or be oxidized to form carboxylic acids.
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A sample of gas occupies 75.5 mL at -14.2°C. What volume does the sample occupy at 146.7 °C?
For every one nadh molecule oxidized at complex i, how many total hydrogen ions are pumped across all of the complexes from the mitochondrial matrix to the inner membrane space?.
10
For every one NADH molecule oxidized at complex i , 10 total hydrogen ions are pumped across all of the complexes from the mitochondrial matrix to the inner membrane space.
How many complexes are involved in mitochondrial electron transport?4 proteins
The oxidative phosphorylation process, also known as the electron transport chain, is a collection of four protein complexes that combine redox events to produce an electrochemical gradient that results in the production of ATP. Both photosynthesis and cellular respiration take place in mitochondria.What distinguishes Complex 1 from Complex 2 in particular?Complex I pulls four protons from the matrix into the intermembrane gap and absorbs high energy electrons from NADH. Succinate dehydrogenase is in Complex II. In the Krebs cycle, Complex II transforms succinate to fumarate and produces FADH2. Directly obtaining FADH2, Complex II provides two electrons to electron transport system..To learn more about mitochondrial matrix visit:
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In a solution, when the concentrations of a weak acid and its conjugate base are equal, ________.
In a solution, when the concentrations of a weak acid and its conjugate base are equal: 1. the -log of the concentration of H+ and the -log of the Ka are equal.
What are Strong acid strong bases ?Any acid that entirely ionises in solutions is considered a strong acid. When positioned, it emits the most hydrogen ions or protons.
It is a substance with the capacity to take a proton out of an extremely weak acid. In water, they can also entirely separate into its ions. Examples include sodium hydroxide and potassium hydroxide (KOH) (NaOH)What are weak acid and weak bases ?Acids that don't entirely dissociate in solution are referred to as weak acids. In other words, any acid that is not a strong acid qualifies as a weak acid. The amount of dissociation determines how strong an acid is; the more dissociation, the stronger the acid.
Weak bases are basic compounds that, when dissolved in solutions, do not entirely separate into their constituent ions.Learn more about Acids and bases here:
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N2 + 3H2 → 2NH3 △H = -92 kJ / mol
Which of the following statements is correct?
(A) The energy taken in to break bonds is greater than the energy released in making bonds.
(B) The temperature increases.
(C) The reaction is endothermic.
(D) The potential energy of the product is greater than that of the reactant.
(E) Heat is absorbed into the reaction.
Explanation:
(e)the heat is absorbed into the reaction .
find total atoms present in 0.1 mol of H2so4 show your calculations or u will be reported
Answer:
1 mole of H2SO4 contains 2 x 6.023 x 10²³ So, 0.1 mole of H2SO4 contains =2 x 6.023 x 10²³ x 0.1
= 1.2 x 10²³atoms of hydrogen
hello there !!
In the Question it's asked that total atoms present in 0.1 mol of H2So4.
so , in the question number of moles is given as 0.1 mole
=> n = 0.1 mole
and total atoms present are = ???
So , in H2So4 molecule there are two hydrogen atoms
=> H2So4 → 2 hydrogen atoms
one mole of H2So4 consist of ;
=> 2 × 6.022 × 10²³
1 mol = 6.022 × 10 ²³ atoms
Therefore, 0.1 mole of H2So4
=> 0.1 × 2 × 6.022 × 10²³ Atoms
=> 0.1 × 2 × 6.022 × 10²³ Atoms=> 12.004 × 10²² Atoms
What mass of ch4 is consumed when 587. 9 kj of energy is evolved from the combustion of a mixture of ch4(g) and o2(g)? show the set up and answer with unit. ch4 molar mass = 16. 05 g/mol
Mass of CH₄ is 10.591 g.
The molar mass is a crucial characteristic of the material that is independent of sample size. The coherent unit of molar mass in the International System of Units (SI) is kg/mol. However, molar masses are usually generally given in g/mol due to historical considerations.
A chemical compound's molar mass is calculated by dividing its mass by the number of moles of the substance that make up the sample.
Δg = 587.9 KJ
CH₄ Molar mass = 16.05 g/mol
mol CH₄ = Δg / ΔH°
= 587.9 / 890.3 KJ/ mol
= 0.6603 mol CH₄
Mass CH₄ = 0.6603 × 16.05 g/mol
= 10.591 g
Therefore, the mass of CH₄ is 10.591 g.
Learn more about molar mass here:
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