A 100 N force pulls a box but it doesn’t move. How much work is done?
A. 0 J
B. 100 J
C. 50 J
D. Not enough info

The maximum rate at which energy can be added to the circuit element mathematically given as

[tex]MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}[/tex]

Generally, the equation for P is  mathematically given as

[tex]P=\ln s \frac{\Delta T}{\Delta t}[/tex]

Therefore

[tex]Rate\ of\ Change\ of\ Temp =\frac{p}{lnS}[/tex]

[tex]\frac{p}{lnS}=\frac{7.4 \times 10^{-3}}{23 \times 10^{-6} \times 705}[/tex]

[tex]\frac{p}{lnS}=0.456^{\circ \mathrm{c}} / \mathrm{sec}[/tex]

Max temp Change

[tex]MaxT=5.6^{\circ} \mathrm{C}[/tex]

[tex]\text { time }=3 \times 60[/tex]

t=180s

In conclusion, Max Energy Rate

[tex]MER =23 \times 10^{-6} \times \frac{301 \times 5.6}{180}[/tex]

[tex]MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}[/tex]

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(1) If the ship moves upward with a constant velocity, the period increases, false.

(2) If the length of the pendulum is doubled, the new period will be: square root of 2 times T₀. true.

(3) If the ship accelerates upward, the period increases, true.

(4) If the ship accelerates downward at 9.81 m/s² , the pendulum will no longer oscillate, false.

(5) If the mass of the pendulum is halved, the period decreases, false.

The period of a simple pendulum is given as;

T = 2π√(L/g)    ------- (1)

where;

When the ship moves upward with a constant velocity, the period will not change.

T ∝√L

when, L = 2L₀

T = T₀√2

Thus, if the length of the pendulum is doubled, the new period will be: square root of 2 times T₀.

t = √2h/g

T = √I/mgd

where;

when the mass is halved, the period increases.

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The period of the oscillations.T = 1.2042s

Opposition is the process of any quantity or measure fluctuating repeatedly about its equilibrium value throughout time. This process is referred to as oscillation. Oscillation, a periodic fluctuation of a substance, can also be described as alternating between two values or rotating around a central value.

Typically, the mathematical formula for the moment of inertia is

T = 2 π √(I / mgd)

Therefore, a moment of inertia

I = 9.00×10-3 + md^2 ;

I=9.00*10^{-3}+ 0.5 * 0.3^2

I=0.054

T=2[tex]\pi \sqrt{0.5*9.8*0.3}[/tex]

T=1.2042s

The period of the oscillations.T = 1.2042s

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Answer:

X component= 46 N

Y component= 80 N

Magnitude =( 46 ^2 + 80^2 )^0.5 = 92.3 N

The fraction of the magnitude of the kinetic energy lost is [tex]\frac{(change) KE }{KE} = 1 - \frac{m}{m + M }[/tex]. = 0.955.

using the law of conservation of momentum,

[tex]mv=(m+M)V[/tex]

[tex]V= m ( \frac{1}{M+m} ) v\\[/tex]

kinetic energy lost,

Δ[tex]KE=KE_{i} -KE_{f}[/tex]

(see image )

now, for the other part

the fraction of the kinetic energy lost,

ΔKE/ KE = [tex]1- m (\frac{1}{m+M} )[/tex]

ΔKE/ KE = [tex]1 - 18 ( \frac{1}{18 + 380 } )[/tex]

ΔKE/ KE = 0.955.

what is kinetic energy ?

The energy that an object has as a result of motion is known as kinetic energy. It is stated as the effort needed to transfer a bulk body from rest to the given velocity. The body holds onto the kinetic energy it gained during its acceleration until its speed changes.

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Answer:

Explanation:

yes

Answer:

A mechanical wave can only travel through a medium.

Answer:

an open fracture contains some sort of water which if it comes in contact with electrons could result to a shock

Answer:

an instrument measuring atmospheric pressure, used especially in forecasting the weather and determining altitude.

Explanation:

hope it helps ya

The minimum necessary height of the IV bag above the position of the needle is 0.37 m.

The minimum necessary height of the IV bag above the position of the needle is calculated as follows;

P = ρgh

where;

Substitute the given parameters and solve for minimum height

h = P/ρg

h = (4759.609) / (9.8 x 1308)

h = 0.37 m

Thus, the minimum necessary height of the IV bag above the position of the needle is 0.37 m.

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Answer:

because he's fast and speedy

Explanation:

Answer:

the earth receives the suns energy as radiation which is able to travel without the need of matter from point A to point B and this radiation is also in the form of heat.

Explanation:

Sun's energy fall on the earth in form of radiation and heats up the atmosphere and produces unequal heating due to its spherical nature and impacts climate of different areas.

The Sun is the only source of energy for the Earth's climate system. Fundamental to atmospheric composition is the warming of the atmosphere caused by solar radiation, which also causes global wind patterns and aids in the development of clouds, storms, and rainfall.

When the sun is at its maximum (peak in sunspots, prominences, and flares), it produces more ultraviolet (UV) radiation. More ozone is produced as a result of UV light, warming the stratosphere. The lower atmosphere and Earth's surface warm slightly as a result of the increased solar radiation.

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In thicker materials the particles can move more easily, therefore the resistance has to decrease.

Hence Option (b) is correct.

Resistivity, which is sometimes represented by the Greek letter rho, is quantitatively equal to a specimen's resistance R times its cross-sectional area A times its length.

ρ = R × A/ l

R = ρ × l/ A

It means the Resistance of the material is inversely proportional to the area of the material.

As the area of the material increases, the resistance decreases and vice versa.

Hence, In thicker particles, there is a greater area available and that's why resistance has to decrease so that particles can move more easily.

Hence, Option (b) is correct.

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Answer:

Warm weather may be found in the tropical zone since the sun's heat is concentrated in regions close to the equator. At 23.5 degrees north of the equator and 23.5 degrees south of the equator, this area is nearly in the middle of the world. It has a monthly average temperature of 18 degrees Celsius or higher.

Explanation:

Answer:

[tex]V = 900\; {\rm V}[/tex] for a resistor where [tex]I = 30\; {\rm A}[/tex] and [tex]R = 30\; {\rm \Omega}[/tex].

Explanation:

By Ohm's Law, if the electric resistance of a resistor is [tex]R[/tex] and the current going through that resistor is [tex]I[/tex], the voltage across that resistor would be [tex]V = I\, R[/tex].

Note that electric resistance is typically measured in Ohms, where [tex]1\; {\rm \Omega} = 1\; {\rm V \cdot A^{-1}}[/tex].

Given that [tex]I = 30\; {\rm A}[/tex] and [tex]R = 30\; {\rm \Omega}[/tex] for the resistor in this question, apply the formula [tex]V = I\, R[/tex] to find the voltage [tex]V[/tex] across this resistor:

[tex]\begin{aligned} V &= I\, R \\ &= 30\; {\rm A} \times 30\; {\rm \Omega} \\ &= 30\; {\rm A} \times 30\; {\rm V \cdot A^{-1}} \\ &= 900\; {\rm V} \end{aligned}[/tex].

Answer:

v

f=90km/h=25m/s

v_{_{i}}=0v

i=0

t=10\;\mathrm{s}t=10s

m=1000\;\mathrm{kg}m=1000kg

The acceleration of the car is 2.5 m/s². The net force acting on the car is 2500 Newtons (N). The correct answers are  2.5 m/s², 2500 Newtons (N).

Given:

Mass of the car (m) = 1000 kg

Acceleration (a) = 2.5 m/s²

a) The acceleration of the car is:

Acceleration (a) = Change in velocity / Time taken

Final velocity (v(f)) = 90 × 0.27778  = 25 m/s

Acceleration (a) = (Final velocity - Initial velocity) / Time taken

Acceleration (a) = (25 - 0 ) / 10

Acceleration (a) = 2.5 m/s²

Therefore, The acceleration of the car is 2.5 m/s².

b) Newton's second law of motion:

F = m × a

F = 1000 × 2.5

F = 2500 N

The net force acting on the car is 2500 Newtons (N).

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Answer:

Vo (vertical) = Vo sin 30 = 30 m/s / 2 = 15 m/s

Vo (horizontal) = Vo cos 30 = .866 30 m/s = 26 m/s

Answer:

See below

Explanation:

A) bearing y reaches the FLOOR in the same amount of time   .5 seconds  since there is no initial vertical velocity component

B.  in .5 seconds y will travel     5 m/s * .5 s = 2.5 meters horizontally

C.  d = 1/2 a t^2

         = 1/2 (9.81)(.5^2) = 1.23 m table height

(a) Bearing y takes 0.2 seconds to reach the table. (b) Bearing y travels 1 meter horizontally before hitting the floor. (c)  The height of the table top above the floor level is 1.225 meters.

a) Time is taken for bearing y to reach the table:

For a horizontal motion, the equation to calculate time is:

Time (t) = Distance (d) ÷ Velocity (v)

Time (t) = Width of the table / Velocity of y

t = 1  / 5

t = 0.2 sec

So, bearing y takes 0.2 seconds to reach the table.

b) Horizontal distance traveled by bearing y before hitting the floor:

Distance (d) = Velocity (v) × Time (t)

d = 5 × 0.2

d = 1 m

So, Bearing y travels 1 meter horizontally before hitting the floor.

c) The height of the table top above the floor level:

h = (1/2) × g × t²

h = (1/2) × 9.8 × (0.5)²

h = (1/2) × 9.8 × 0.25

h = 1.225 m

So, the height of the table top above the floor level is 1.225 meters.

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Answer:

B. 2.5 Ω

Explanation:

[tex]\frac{1}{5} +\frac{1}{5}=0.4[/tex]

Put a one on top of the 0.4

[tex]\frac{1}{0.4} =2.5[/tex]

Answer:

.12 N

Explanation:

Velocity goes from 2 m/s    to   0  m/s   so average velocity = 1 m/s

.250 m / 1 m/s  =  .25 second to stop

change in velocity / change in time = accel

  2 m/s / .25 sec =  8 m/s^2

F = ma

  = .015 kg *  8 m/s^2  = .12 N

Answer:

No because a pot plant system must interact with its surroundings (air, water, etc) and these are not closed systems.

Only if the pot plant were completely enclosed, say in a large glass jar would the system be closed.

Answer: 1.348 meters

Explanation: Although the sign is missing from the location of the 4.00 kg object, it is assumed to be positive. The net moment of all the objects about the center of mass must be zero. Let the center of mass be on the y axis at a point  c . Adding the four moments together, we get:

(2.00)(3.00−c)+(3.00)(2.50−c)+(2.50)(0−c)+(4.00)(0.500−c)=0

6.00−2.00c+7.50−3.00c+0−2.50c+2.00−4.00c=0

11.5c=15.50

c=  1.348 metres

The center of mass is on the y axis at  y  = 1.348 metres.

The final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

The time of motion of the girl is calculated as follows;

h = vt + ¹/₂gt²

where;

Substitute the given parameters and solve for time of motion;

50.8 = 0 + ¹/₂(9.8)t²

2(50.8) = 9.8t²

101.6 = 9.8t²

t² = 101.6/9.8

t² = 10.367

t = √10.367

t = 3.22 seconds

vf = vi + gt

where;

vi is the initial vertical velocity = 0

vf = 0 + 9.8(3.22)

vf = 31.56 m/s

Thus, the final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

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Answer:

Density of a substance is the ratio of mass of the substance to its volume.

Answer:

Density of a substance is the ratio of mass of the substance to its volume.

Answer:

water at 4°c that's abnormal stage of water

Answer:

Mass of block = 6kg

wright = 6 × g = 60 N using g = 10 m/s^2 .

compression= 0.20m

spring constant =( weight / compression) =( 60/0.20) = 300 N/m .

Work done in compressing 0.20 m =( 1/2 × 300 × 0.20 × 0.20)= 6 joule.

Additional compression = 0.10 m

total compression = 0.20+ 0.10= 0.30 m.

Total work done = ( 1/2 × 300 × 0.30× 0.30) = 13.5 joule.

Hence work done in compressing from 0.20 m to 0.30 m will be = ( 13.5 - 6) = 7.5 joule.

Note :- work done in compressing a spring having spring constant K N/m by x m is equal to 1/2× (K) × X^ 2 .