The average THC content of marijuana sold on the street is 10.5%. Suppose the THC content is normally distributed with standard deviation of 2%. Let X be the THC content for a randomly selected bag of marijuana that is sold on the street. Round all answers to 4 decimal places where possible,

a. What is the distribution of X? X ~ N(
,
)

b. Find the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 8.9.


c. Find the 76th percentile for this distribution.
%

Answer:

x=18

Step-by-step explanation:

[tex]\frac{4}{12} =\frac{6}{x} \\[/tex]

[tex]\frac{4}{12}[/tex] ÷ [tex]\frac{2}{2}[/tex] = [tex]\frac{2}{6}[/tex] = [tex]\frac{6}{x}[/tex]

[tex]\frac{2}{6} = \frac{6}{x}[/tex]  

2×3 =6

6×3=18

x=18

Answer:

D

Step-by-step explanation:

Widrawal is - 30

Deposit is +30

-30+30 = 0

The answer is 492 feet.

If we picture the scenario as a right triangle, using trigonometric ratios, this problem can be solved.

cos 60° = x / 984

1/2 = x/984

x = 984/2

x = 492 feet

The percentage that each transaction contributed to the total transactions in the same account (Cash Account and Service Revenue) is computed as follows:

1. Service Revenue $900   = 8%

2. Owner's Equity, Barbara Hanson $2,200 = 19.8%

3. Accounts Receivable $750 = 6.8%

5. Note Payable $6,000 = 54.1%

6. Unearned Revenue $1,250 = 11.3%

Total cash receipts = $11,100

1. Cash $900 = 70.6%

4. Accounts Receivable $375 = 29.4%

Total $1,275

The percentage that each transaction contributed to the total transactions in the same account can be computed by taking the dollar value of the transaction over the total value of transactions in the same account and then multiplying by 100.

Percentage values show the degrees of relationship among variables.

The formula for computing percentage in this scenario is transaction value/total transactions value × 100%.

1. Cash $900 Service Revenue $900

2. Cash $2,200 Owner's Equity, Barbara Hanson $2,200

3. Cash $750 Accounts Receivable $750

4. Accounts Receivable $375 Service Revenue $375

5. Cash $6,000 Note Payable $6,000

6. Cash $1,250 Unearned Revenue $1,250

The following transactions occurred during July:

1. Received $900 cash for services provided to a customer during July.

2. Received $2,200 cash investment from Barbara Hanson, the owner of the business.

3. Received $750 from a customer in partial payment of his account receivable, which arose from sales in June.

4. Provided services to a customer on credit, $375.

5. Borrowed $6,000 from the bank by signing a promissory note.

6. Received $1,250 cash from a customer for services to be rendered next year.

Use the transactions to compute the percentage of each transaction relative to the total transactions in the same account.

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Answer: The given integral is impossible to solve.

Step-by-step explanation: I tried solving it right now with integration by parts and trigonometric substitution, and I was unable to solve it.

So I looked at two math solvers and tried inputting the question, and it either says "There is nothing more you can do with this problem," or "We are unable to solve this problem."

First, let's substitute [tex]x=\frac w4[/tex] and [tex]dx=\frac{dw}4[/tex] to get rid of the fraction.

[tex]\displaystyle \int \csc^6\left(\dfrac w4\right) \cot^4\left(\dfrac w4\right) \, dw = 4 \int \csc^6(x) \cot^4(x) \, dx[/tex]

Recall that

[tex]\cot^2(x) + 1 = \csc^2(x)[/tex]

[tex]\dfrac{d}{dx} \cot(x) = -\csc^2(x)[/tex]

We can the rewrite the integrand as

[tex]\displaystyle 4 \int \csc^6(x) \cot^4(x) \, dx = 4 \int \left(\cot^2(x) + 1\right)^2 \cot^4(x) \csc^2(x) \, dx[/tex]

then substitute [tex]y=\cot(x)[/tex] and [tex]dy=-\csc^2(x)\,dx[/tex] to get

[tex]\displaystyle -4 \int (y^2 + 1)^2 y^4 \, dy[/tex]

Expand the integrand.

[tex]\displaystyle -4 \int (y^4 + 2y^2 + 1) y^4 \, dy = -4 \int (y^8 + 2y^6 + y^4) \, dy[/tex]

Now integrate with the power rule.

[tex]\displaystyle -4 \left(\frac{y^9}9 + \frac{2y^7}7 + \frac{y^5}5\right) + C[/tex]

[tex]\displaystyle -\frac{4y^9}9 - \frac{8y^7}7 - \frac{4y^5}5 + C[/tex]

Put everything back in terms of [tex]x[/tex], then [tex]w[/tex].

[tex]\displaystyle -\frac{4\cot^9(x)}9 - \frac{8\cot^7(x)}7 - \frac{4\cot^5(x)}5 + C[/tex]

[tex]\displaystyle \boxed{-\frac49 \cot^9\left(\dfrac w4\right) - \frac87 \cot^7\left(\dfrac w4\right) - \frac45 \cot^5\left(\dfrac w4\right) + C}[/tex]

Answer:

transitive property

Step-by-step explanation:

This is the answer by definition.

The substitution property is demonstrated in the case of m∠AZF=m∠AZL+m∠LZF and m∠AZL+m∠LZF=m∠SZW+m∠LZF, so, m∠AZF=m∠SZW+m∠LZF.

In order to find the value of the unknown, the substitution property is a concept in algebra that is used to substitute the value of a given variable or quantity into an expression.

According to the substitution property of equality, "If two variables x and y are equal, then x can be substituted for y in any equation or expression, and y can be substituted for x in any equation or expression."

According to the question, m∠AZF=m∠AZL+m∠LZF and m∠AZL+m∠LZF=m∠SZW+m∠LZF, so by the substitution property, on substituting the value of  m∠AZL+m∠LZF in the first expression, we get, m∠AZF=m∠SZW+m∠LZF.

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Answer:

A. 2-liter bottle;$1.40

Step-by-step explanation:

We have to find out which option has the higher cost per liter. To do this we must find out how much each option would be if it was a liter.

1st set up each equation
2-liter = $2.80 we can divide by 2 on both sides of the equal sign and we get 1 liter = $1.40.
6(1/2) liter bottles = $3.90 this becomes 3 liters = $3.90 then we divide by 3 on both sides of the equal sign and we get $1.30

2nd we compare
$1.40(2 liter bottle) > $1.30 (6 1/2 liter bottles)

The interest due on financing option is $307.50

What is interest on financing?

Interest on financing is the extra amount paid by the couple when their total payments are compared to the cash price of $6,230.

The total payments would be the 25% down payment plus the sum of the twelve monthly payments of $415 each

Down payment=cash price*25%

Down payment=$6230*25%

Down payment=$1,557.50

Total monthly payments=amount of each monthly payment*number of monthly payments

monthly payment=$415

number of monthly payments=12

Total monthly payments=$415*12

Total monthly payments=$4,980

Total payment under financing=Down payment +Total monthly payments

Total payment under financing=$1,557.50+$4,980

Total payment under financing=$6,537.50

Interest=$6,537.50-$6,230

Interest on financing=$307.50

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The information given regarding the computation of the profit or loss shows that there's a loss of RS 500,000.

From the information given, it was stated that the real estate agent bought two triangular Kittas' having a common side as shown in the figure from two people for Rs 2000,000 altogether.

It was further depicted that he sold the land in the shape of a quadrilateral at Rs 1,500,000. In their case, the sale is less than the cost and therefore, there's a loss.

The loss will be:

= 2,000,000 - 1,500,000

= 500,000

Therefore, the information given regarding the computation of the profit or loss shows that there's a loss of RS 500,000.

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Answer:

2x + 8

Step-by-step explanation:

(4x + 5) - (2x - 3)

4x + 5 - 2x + 3

2x + 8

Answer: 2x+8

Step-by-step explanation:

4x+5-2x+3

=2x+8

Answer:

(x+8) (x+1)

Step-by-step explanation:

To find the common denominator, we need to find the least common multiple of the terms in the denominator

(x+8) from the first term

(1) from the second term

(x+1) from the third term

The least common denominator is

(x+8) (1)(x+1)

Simplifiying

(x+8) (x+1)

Answer:

2/3rds of liad's run

Step-by-step explanation:

3 min 45s = 3 3/4 min = 15/4 min; 10/(15/4) = 8/3 laps

2min 30s = 2 1/2 min = 5/2 min; 10/(5/2) = 4 laps

(8/3)/4 = 2/3

If the three vertices of the rhombus are W(2,5),x(6,3),Y(2,1) then the area of the rhombus is 16 square units.

Given the three vertices of the rhombus are W(2,5),x(6,3),Y(2,1).

We are required to find the area of the rhombus when the fourth point Z is plotted.

We have to plot the points of the rhombus in the graph. We know that all the sides of the rhombus should be equal to each other. So by adjusting the blocks in the graph we will be able to plot Z as (-2,3).

In this way the diagonals are ZX and WY.

ZX=[tex]\sqrt{(3-3)^{2} +(6+2)^{2} }[/tex]

=[tex]\sqrt{64}[/tex]

=8 units

WY=[tex]\sqrt{(1-5)^{2} +(2-2)^{2} }[/tex]

=[tex]\sqrt{16}[/tex]

=4 units

Area of rhombus=1/2 *([tex]d_{1} *d_{2}[/tex])

=1/2* (8*4)

=8*2

=16 Square units.

Hence if the three vertices of the rhombus are W(2,5),x(6,3),Y(2,1) then the area of the rhombus is 16 square units.

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Answer:

Hi, to find the surface area of a cone is πrl

if your radius and length is given.

hope this helps (•‿•)

Using it's concept, the probability that the first coin is a nickel and the second coin is a quarter is: 2/39.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

Hence:

Then the probability for both coins is:

p = 4/13 x 1/6 = 4/78 = 2/39

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X=1.33

Y=4.9875;approx. 5.0

Answer:

(2/120=X/80)=Y/300

2×80=120×X

X=160/120

X=1.33

X/80=Y/300

But X=1.33

By substituting

X=1.33, We have that

1.33/80=Y/300

80×Y=1.33×300

80Y=399

Y=399/80

Y=399/80

Y=5.0 approx.

Filling in the frequency table according to the colors observed and expected on the M & M Peanut candies is as follows:

Color                              Brown    Yellow     Red      Green     Orange    Total

Observed Frequency     67           22           51           24           24         188

Expected Frequency     56           38           38           38            18         188    

Observed Frequency   36%         12%       27%         13%          13%

Expected Frequency    30%        20%      20%        20%          10%

A frequency table is a display of the number of occurrences of a particular value or characteristic.

A frequency table makes it easy to display and interpret a distribution of data.

The absolute frequencies shows the absolute values of the observed and expected frequencies, while the relative frequencies shows the percentage values of the observed and expected frequencies.

Color                              Brown    Yellow     Red      Green     Orange    Total

Observed Frequency     67           22           51           24           24         188

Expected Frequency     30%        20%       20%        20%         10%      100%

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Fill in the following table on the frequency of the colors, indicating the absolute and relative frequencies of the distributions.

Answer:

1/5 of it

Step-by-step explanation:

5/5 represents all of her homework

5/5-4/5= 1/5

4/5 represents the homework she did before dinner

1/5 represents the homework left to do

The area is:

A = (θ/2)*R^2

The circumference is:

C = θ*R

And the area of the circle when the angle is π/4 is: 39.25 cm^2

For a circle of radius R, the area is:

A = pi*R^2

where pi = 3.14

And the circumference is:

C = 2*pi*R

Now, remember that a circle has an angle of 2pi radians, then if we only define an arc in the circle, defined by an angle θ, the area of said arc will be:

A = (θ/2pi)*pi*R^2 = (θ/2)*R^2

And the circumference is:

C = (θ/2pi)*2pi*R = θ*R

Now, we want to find the area when the circle has a radius R = 10cm and θ = pi/4

Replacing that in the area equation, we get:

A = (pi/4/2)*(10cm)^2 = (3.14/8)*(10cm)^2 = 39.25 cm^2

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Answer:

36

Step-by-step explanation:

[tex]\sqrt{24a}=12\sqrt{6} \\ \\ 24a=864 \\ \\ a=36[/tex]

The total distance Ramiro travelled is 380 miles.

Equations are mathematical statements containing two algebraic expressions on both sides of an 'equal to (=)' sign. It shows the relationship of equality between the expression written on the left side with the expression written on the right side. In every equation in math, we have, L.H.S = R.H.S (left hand side = right hand side).

There are different parts of an equation which include coefficients, variables, operators, constants, terms, expressions, and an equal to sign. When we write an equation, it is mandatory to have an "=" sign, and terms on both sides. Both sides should be equal to each other. An equation doesn't need to have multiple terms on either of the sides, having variables, and operators. An equation can be formed without these as well, for example, 5 + 10 = 15. This is an arithmetic equation with no variables. As opposed to this, an equation with variables is an algebraic equation.

let x be the first day hours

let y be the second day hours.

now,

x = y + 2

40x = 60y + 20

Putting x= y+2

40(y + 2) = 60y + 20

40y + 80 = 60y + 20

60 = 20y

y = 3 hours

For, first day

x = y + 2

x = 3 + 2

x = 5 hours

Thus,

Total distance = 40(5) + 60(3)

=200 + 180

=380 miles

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Answer: $3.2a

Step-by-step explanation: We need to decrease $8a by 60 percent because $8a is the price after a 60% increase. 8 x 6/10 is 48/10 which as a mixed number is 4 8/10 or 4.8. Now, we subtract 4.8 from 8 which yields our answer of 3.2.

The monthly payment is $796.40.

The total amount she would deposit is $286,705.51

The total interest earned is $513,294.49

The payments made by Jessica are known as deferred annuities. Deferred annuities are when a series of payments are made in exchange for an amount of money in the future.

The formula that can be used to determine the amount of monthly deposit is: future value / annuity factor

Annuity factor = {[(1+r)^n] - 1} / r

Where:

r = interest rate = 6%/12 = 0.5%

n = number of years = 30 x 12 = 360

Annuity factor = ](1.005^360) - 1] / 0.005 = 1004.515

Monthly payments = 800,000 / 1004.515 = $796.40

Total amount she would deposit = monthly payment x number of years x number of months in a year

$796.40 x 30 x 12 = 286,705.51

Total interest earned = value of the retirement account - total amount deposited

800,000 - 286,705.51 = 513,294.49

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Could you try reposting the question clearly

Answer:

$824.56

Step-by-step explanation:

Use the compound interest formula which is A = P(1+r/n)^nt

1st using the given information we are going to find out values:
P is our initial amount of $500
r is the annual rate of interest (expressed as a decimal) 8% becomes 0.08.
n is how many times interest is compounded per year, in this case since its not stated we are going to assume its annually, so n is 1
t is how long the money is deposited (in years) so t is 6.5
A is our final amount

2nd plug in our values into the equation

Plugging all these values we get A = 500 (1 +0.08/1)^(0.08)(6.5)

A = $824.56

Answer:

85 C

Step-by-step explanation:

Temperature range means the difference between the maximum and minimum in temperature for an area. 40C-(-45C)=85 C

The solutions to the exponential growth problem are:

A. [tex]P(t) = 260e^0.3662t[/tex]

B.[tex]P(3) = 260e^0.3662(3) = 779[/tex]

C.3.367 hours

The  exponential growth problem obeys the equation:

P(t) = P0ekt

P0=population

time t

We can find the value of k At t=3 hours as,

780 = 260e^k(3)

k = (1/3) ln(780/260) hours-1 ≅ 0.3662 hours-1

A. [tex]P(t) = 260e^0.3662t[/tex]

B. [tex]P(3) = 260e^0.3662(3) = 779[/tex]

C.  1870 = 260e^0.3662t

To Solve for t, w2e make t the subject of the formula

t = ln(1870/260) / 0.3662 hours = 3.367 hours

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Answer:

98 degrees

Step-by-step explanation:

In a quadrilateral, we have 4 angles whose sum is 360 degrees which can be derived using the Exterior Angle Sum Theorem which essentially states that any convex polynomial will have a sum of 360 degrees for it's exterior angles.

Since we know that two of the angles are equal, we can just represent angle A and D as "x", and since they're congruent, and there is two of them, the sum can be represented as "2x"

So using all the known values we can set up the following equation:

[tex]2x+64+100=360[/tex]

Simplify on the left side

[tex]2x+164=360[/tex]

Subtract 164 from both sides

[tex]2x=196[/tex]

Divide both sides by 2

[tex]x=98[/tex]

Since we know that "x" represents both angle A and B, then the angle A is 98 degrees.