The concentration of hydroxide ion of a solution with a pH of 8. 25 is 1.77×[tex]10^{6}[/tex] M
Calculation,
The pH of a solution tells us about concentration of the [tex]H^{+[/tex] ion ( proton ) in solution. However, if we know the value of pH , we can calculate pOH with the help of pH and from pOH we can find concentration of hydroxide ions in the solution.
pH + pOH = 14
8. 25 + pOH = 14
pOH = 14 - 8. 25 = 5.75
Since, pH = -㏒[ [tex]H^{+[/tex] ]
Similarly, pOH = -㏒[[tex]OH^{-[/tex] ]
If pOH = 5.75 , that means that -㏒[[tex]OH^{-[/tex] ] = 5.75 ,which means that,
[[tex]OH^{-[/tex] ] = [tex]10^{-5.75}[/tex] = 1.77×[tex]10^{6}[/tex].
So, we know that the concentration of the [tex]OH^{-[/tex] ions in the solution with pH of 8.25 is 1.77×[tex]10^{6}[/tex] Molar
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N2 + 3H2 → 2NH3 △H = -92 kJ / mol
Which of the following statements is correct?
(A) The energy taken in to break bonds is greater than the energy released in making bonds.
(B) The temperature increases.
(C) The reaction is endothermic.
(D) The potential energy of the product is greater than that of the reactant.
(E) Heat is absorbed into the reaction.
Explanation:
(e)the heat is absorbed into the reaction .
How many moles of Ag form from 5.0 mol Zn?
Answer:
8.0 moles Ag
Explanation:
To find the moles of silver (Ag), you need to multiply the moles of Zn and AgNO₃ by the mole-to-mole ratio. This ratio is made of the coefficients from the balanced chemical equation. It is important to arrange the ratio in a way that allows for the cancellation of units.
2 AgNO₃ + 1 Zn -----> 2 Ag + Zn(NO₃)₂
^ ^ ^
5.0 moles Zn 2 moles Ag
----------------------- x ---------------------- = 10. moles Ag
1 mole Zn
8.0 moles AgNO₃ 2 moles Ag
---------------------------- x ---------------------------- = 8.0 moles Ag
2 moles AgNO₃
We needed to convert both reactants into the product because we wre not given a limiting reagent. The limiting reagent is the reactant that is completely reacted first. The limiting reagent in this reaction is AgNO₃ because it produces the smallest amount of product. As such, the actual amount of moles Ag is 8.0 moles.
For every one nadh molecule oxidized at complex i, how many total hydrogen ions are pumped across all of the complexes from the mitochondrial matrix to the inner membrane space?.
10
For every one NADH molecule oxidized at complex i , 10 total hydrogen ions are pumped across all of the complexes from the mitochondrial matrix to the inner membrane space.
How many complexes are involved in mitochondrial electron transport?4 proteins
The oxidative phosphorylation process, also known as the electron transport chain, is a collection of four protein complexes that combine redox events to produce an electrochemical gradient that results in the production of ATP. Both photosynthesis and cellular respiration take place in mitochondria.What distinguishes Complex 1 from Complex 2 in particular?Complex I pulls four protons from the matrix into the intermembrane gap and absorbs high energy electrons from NADH. Succinate dehydrogenase is in Complex II. In the Krebs cycle, Complex II transforms succinate to fumarate and produces FADH2. Directly obtaining FADH2, Complex II provides two electrons to electron transport system..To learn more about mitochondrial matrix visit:
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What are the two most common unwanted side reactions which can occur when monosaccharides are treated with base?
Epimerization and Enediol rearrangement are the two most common unwanted side reactions which can occur when monosaccharides are treated with base.
Epimerization is a process in stereochemistry in which there is a change in the configuration of only one chiral centre. As a result, a diastereomer is formed. The classical example of this in medicine is tetracycline. In acidic conditions around pH 4, tetracycline readily undergoes epimerization at position 4, and an inactive 4-epitetracycline is produced, which on dehydration forms 4-epianhydrotetracycyline, a highly toxic product. This toxic compound can also be formed from acid catalysed (at lower pH) dehydration of tetracycline via anhydrotetracycline.
Enediol rearrangement is a transformation which occurs at basic medium and allows the conversion of epimers, defined as isomeric forms that differ in the position of the hydroxyl group at C-2. In this way it is possible to transform through the enediol intermediate glucose to mannose and vice versa.
Another important isomerization process through the enediol rearrangement is the interconversion of glucose and fructose. Thus, the enolization proceeds by migration of proton at position 2, to carbon at 1.
Monosaccharides contain both alcohol and carbonyl functional groups. This allows monosaccharides to undergo many of the reactions typical for these functional groups. In particular, alcohols can be converted to esters, converted to ethers, converted to acetals, or oxidized. Carbonyls can be reacted with nucleophiles, be reduced to form alcohols, or be oxidized to form carboxylic acids.
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What mass of ch4 is consumed when 587. 9 kj of energy is evolved from the combustion of a mixture of ch4(g) and o2(g)? show the set up and answer with unit. ch4 molar mass = 16. 05 g/mol
Mass of CH₄ is 10.591 g.
The molar mass is a crucial characteristic of the material that is independent of sample size. The coherent unit of molar mass in the International System of Units (SI) is kg/mol. However, molar masses are usually generally given in g/mol due to historical considerations.
A chemical compound's molar mass is calculated by dividing its mass by the number of moles of the substance that make up the sample.
Δg = 587.9 KJ
CH₄ Molar mass = 16.05 g/mol
mol CH₄ = Δg / ΔH°
= 587.9 / 890.3 KJ/ mol
= 0.6603 mol CH₄
Mass CH₄ = 0.6603 × 16.05 g/mol
= 10.591 g
Therefore, the mass of CH₄ is 10.591 g.
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Predict the mass (in grams) of precipitate that will form if a solution containing 2.34 g of cesium hydroxide is added to a solution containing a large excess of tiso4?
The mass of precipitate formed if a solution containing 2.34 g of cesium hydroxide is added to a solution containing a large excess of tiso4 is 0.6387 g
Mass of CsOH = 2.34 g
Number of moles of CsOH = 149.9 g / mol
Molar mass of CsOH = Mass of CsOH / Number of moles of CsOH
= 2.34 / 149.9
Molar mass of CsOH is 0.0156 mol
Chemical reaction2 CsOH + TiSO4 → Ti(OH)2 + CsSO4
In this reaction 2 moles of CsOH gives 1 mole of Ti(OH)2
0.0156 mol of CsOH will produce, 0.0156 / 2 = 0.0078 mol
0.0156 mol of CsOH will produce 0.0078 mol of Ti(OH)2
Mass of Ti(OH)2 = Molar mass of Ti(OH)2 / Number of moles of Ti(OH)2
= 0.0078 * 81.88
= 0.6387 g
Mass of Ti(OH)2 formed is 0.6387 g
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The mass of precipitate formed is 0.90441 g
cesium hydroxide is added to a solution containing a large excess of TiSo4
The chemical reaction is
2CsOH + TiSo4 → Ti(OH)2 + CsSo4
The above reaction the Ti(OH)2 is a precipitate formed
Molar mass = mass of a substance / mass of one mole
Mass of CsOH = 2.34 / 149.912
Mass of CsOH = 0.0156 mol
The above reaction 2 mol of cesium hydroxide yield 1 mol of titanium hydroxide
Then, 0.0156 mol of CsOH yield 0.0156 / 2 = 0.0078 mol of Ti(OH)2
The mass of Ti(OH)2 is 115.95
0.0078 mol of Ti(OH)2 = 115.95 X 0.0078
= 0.90441
Hence, The mass of Ti(OH)2 = 0.9044 gLearn more about the mass of precipitate on
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What laboratory conditions (temperature and pressure) were assumed when calculating ksp based on measured electrochemical potential?
The temperature of the lab is assumed at 25°C while calculating Ksp. Pressure of the lab is assumed at 1 atm normal atmospheric conditions while calculating Ksp.
If we increase the temperature of the solvent, the average kinetic energies of the molecules start increases. Hence, the solvent is more able to dislodge more molecules from the surface of the solute. Thus, by increasing the temperature the solubilities of substances also increases. Temperature is directly proportional to the solubility.
As we goes on increasing the pressure of a gas, the collision between the molecules start increasing and thus the solubility goes up, as we decrease the pressure, the number of collision decreases thus solubility goes down.
Thus, with further increase in the temperature and pressure the Ksp value changes. Thus, temperature of the lab is assumed at 25°C while calculating Ksp. Pressure of the lab is must be 1 atm normal atmospheric conditions while calculating Ksp.
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Find δs∘ for the reaction between nitrogen gas and hydrogen gas to form ammonia:12n2(g) 32h2(g)→nh3(g)
Nitrogen (N2) and hydrogen (H2) gases react to form ammonia, which requires -99.4 J/K of standard entropy (ΔS°).
What is standard entropy?
The difference between the total standard entropies of the reaction mixture and the summation of the standard entropies of the outputs is the standard entropy change. Each entropy in the balanced equation needs to be compounded by its coefficient, as shown by the letter "n."
Calculation:
Balancing the given reaction following-
1/2 N₂(g) + 3/2 H₂ (g)→ NH₃ (g)
ΔS° = [1 mol x S° (NH₃)g] - [1/2 mol x S° (N₂)g] - [3/2 mol x S°(H₂)g]
Here S° = standard entropy of the system
Insert into the aforementioned equation all the typical entropy values found in the literature:
ΔS° = [1 mol x 192.45 J/mol.K] - [1/2 mol x 191.61 J/mol.K] - [3/2 mol x 130.684 J/mol.K]
⇒ΔS° = - 99.4 J/K
Therefore, the standard entropy, ΔS° is -99.4 J/K.
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The smallest particle of an element that retains all of the properties of that element is called a(n) ______.
Answer:
Atom
Explanation:
That describes an ATOM
What happens to the kinetic energy of the particles in a sample of gas as
the temperature of the sample increases?
Answer:
See below
Explanation:
Temperature is basically a measure of the average kinetic energy of the particles in the sample ....so as temp goes up, kinetic energy increases
A pure element unbound or in a diatomic state, such as cl2, always has an oxidation number of ________. a. 1 b. 2 c. magnitude equal to its valence number d. 0
A pure element unbound or in a diatomic state, such as cl2, always has an oxidation number of 0 (zero).
Why does pure element or a diatomic molecule has zero oxidation state?In a neutral substance with atoms of only one element, the oxidation number of an atom is zero. As a result, the oxidation number of the atoms in O2, O3, P4, S8, and aluminum metal is 0. The oxidation numbers for an element in its normal state will be zero. O2 and Cl2 are diatomic gas molecules that occur naturally, thus when they are in that state, they have an oxidation state of zero. Metals like zinc will also have an oxidation number of zero if they are in their natural solid state.
O2 and Cl2 are neutral diatomic, hence they will always have a zero oxidation state. It is impossible for one oxygen atom to have a negative 2 charge while the other has a positive 2. The oxidation states should be 0 if the elements are solids, liquids, or any type of diatomic molecule.
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option (d) 0 is the right option.
A pure element unbound or in a diatomic state, such as cl2, always has an oxidation number of 0.
An unbound or diatomic pure element, like cl2, always has an oxidation number of 0 (zero).
Why does a diatomic molecule or pure element have zero oxidation state?The oxidation number of an atom is 0 in a neutral substance that contains solely atoms of one element. Because of this, the oxidation number of the atoms in aluminum metal, O2, O3, P4, and S8 is 0. An element will have zero oxidation numbers in its natural state. Since O2 and Cl2 are diatomic gas molecules that are found in nature, they have an oxidation state of zero while they are in that state. If a metal is in its natural solid state, it will also have an oxidation number of zero.O2 and Cl2 will always have a zero oxidation state because they are neutral diatomic. One oxygen atom cannot have a negative charge of two while the other has a positive charge of two. If the elements are solids, liquids, or any sort of diatomic molecule, the oxidation states should be 0.To learn more diatomic state visit:
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18 the first step in the mechanism is the acid catalyzed generation of an enol and then electrophilic addition of bromine. which cation is formed and why?
the first step in the mechanism is the acid-catalyzed generation of an enol and then electrophilic addition of bromine and cation is formed because of the destabilization effect of the electronegativity of oxygen
The ability of an atom or functional group to draw electrons to itself is known as an electronegativity in chemistry. An atom's electronegativity is influenced by both its atomic number and how far away from its charged nuclei its valence electrons are located.
The ability of an atom to draw shared electrons in a covalent connection is referred to as electronegativity. The stronger an element attracts the shared electrons, the higher its degree of electronegativity.
The propensity of an atom to attract other atoms when it is combined is known as an element's electronegativity. Additionally, a pair of bound electrons are shared. In contrast, an element's electropositivity refers to an atom's propensity to contribute electrons while also withdrawing from covalent connections.
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LOTS OF POINT PLS HELP!!!! What is the balanced, net ionic equation for the reaction shown below? HCI (aq) + NaOH (ag)-> NaCI (aq) +H2P(l)
The net ionic equation is written as H^+(aq) + OH^-(aq) -------> H2O(l)
What is the net ionic equation?The term net ionic equation refers to the equation that shows the ions that underwent a change in the reaction. We have to note that the reaction species here must be ionic species which are able to dissociate into ions in solutions.
Now the first step is to put down the molecular equation. The molecular equation shows the reaction of the compounds as follows;
HCI (aq) + NaOH (ag)-> NaCI (aq) +H2O(l)
Next, we put own the complete ionic reaction equation as follows;
H^+(aq) + Cl^-(aq) + Na^+(aq) + OH^-(aq) -------> Na^+(aq) + + Cl^-(aq) + H2O(l)
Next we have the net ionic equation;
H^+(aq) + OH^-(aq) -------> H2O(l)
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If the dehydration reaction of an alcohol is successful. What changes would be seen in the ir spectrum for the product compared to the starting material?
If the dehydration reaction of an alcohol is successful. The changes would be seen in the IR spectrum for the product compared to the starting material are as,
The O-H and C-O band is disappear from stating materialThe addition of a C-C double bond band in the product.In dehydration reaction of alcohol ( O-H and C-O bond ) contain , the water molecule ( [tex]H_{2}O[/tex] ) is release from the reactant and C-C double bond is form which is known as alkene in the product .
The reactant and product have different structure. To determine the structure of the compound IR spectroscopy is used. In IR spectrum the peak corresponds to 3400-3600 cm is missing in the product of dehydration reaction of an alcohol. It means O-H band is disappear from stating material.
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In a solution, when the concentrations of a weak acid and its conjugate base are equal, ________.
In a solution, when the concentrations of a weak acid and its conjugate base are equal: 1. the -log of the concentration of H+ and the -log of the Ka are equal.
What are Strong acid strong bases ?Any acid that entirely ionises in solutions is considered a strong acid. When positioned, it emits the most hydrogen ions or protons.
It is a substance with the capacity to take a proton out of an extremely weak acid. In water, they can also entirely separate into its ions. Examples include sodium hydroxide and potassium hydroxide (KOH) (NaOH)What are weak acid and weak bases ?Acids that don't entirely dissociate in solution are referred to as weak acids. In other words, any acid that is not a strong acid qualifies as a weak acid. The amount of dissociation determines how strong an acid is; the more dissociation, the stronger the acid.
Weak bases are basic compounds that, when dissolved in solutions, do not entirely separate into their constituent ions.Learn more about Acids and bases here:
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chlorine + sulfur dioxide + water = hydrochloric acid + sulfuric acid
The given example is a chemical reaction.
The contents (separated as reactants and products) :
[tex]\begin{tabular}{c | l}Reactants & Products \\\cline{1-2}Chlorine & Sulfuric Acid \\Water & Hydrochloric Acid \\Sulfur Dioxide & \\\end{tabular}[/tex]
The written reaction is :
[tex]\boxed {Cl + SO_{2} + H_{2}O \implies HCl + H_{2}SO{4}}[/tex]
I hope it helped you solve the problem.
Good luck on your studies!
Write a balanced overall reaction from these unbalanced half-reactions. sn⟶sn2 ag ⟶ag
The balanced overall reaction from these unbalanced half-reactions is given in following steps ,
Step 1 : [tex]Sn[/tex] → [tex]Sn^{+2}+ 2e^{-}[/tex]
Step 2 : [tex]Ag^{+}[/tex] + [tex]e^{-}[/tex] → [tex]Ag[/tex]
[tex]2Ag^{+} + 2e^{-}[/tex] → [tex]2Ag[/tex]
Overall reaction : [tex]Sn[/tex] + [tex]2Ag^{+}[/tex] → [tex]Sn^{+2}[/tex] + [tex]2Ag[/tex]
The equation in which number of atoms of elements in reactant side is equal to the number of atoms of elements in product side is called balanced chemical equation .
This step is oxidation half-reaction in which loss of electron is takes place .
Second steps is reduction reaction in which fain of electrons is takes place. We multiple second half-reaction by two to make equal number of electrons in both steps to cancel out the electrons from the equation.
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2. Calculate the number of moles represented by the following masses.
a. 2.00 × 102 g of silver
b. 37.1 g of silicon dioxide, SiO2
40 POINTS!!!!!!!!!!!!
a. There are 1.85 moles in 2.00 × 10² g of silver (Ag).
b. There are 0.618 moles in 37.1 g of silicon dioxide (SiO₂)
What is the molar mass?The molar mass is the mass in grams of 1 mole of particles, that is, the mass in grams of 6.02 × 10²³ particles. The units are g/mol.
We want to calculate the number of moles represented by different masses of different substances. In each case, the conversion factor between mass and moles is the molar mass.
a. 2.00 × 10² g of silver (Ag)The molar mass of silver is 107.87 g/mol.
2.00 × 10² g × (1 mol/107.87 g) = 1.85 mol
b. 37.1 g of silicon dioxide (SiO₂)The molar mass of silicon dioxide is 60.08 g/mol.
37.1 g × (1 mol/60.08 g) = 0.618 mol
a. There are 1.85 moles in 2.00 × 10² g of silver (Ag).
b. There are 0.618 moles in 37.1 g of silicon dioxide (SiO₂)
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How wide in m is a single slit that produces its first minimum for 624-nm light at an angle of 18. 0°?
A single slit with a width of 2019 * 109 m creates its initial minimal for 624 nm light at an angle of 18°.
How does diffraction work?
Waves spreading outward around obstructions are known as diffraction. Diffraction happens with sound, electromagnetic radiation like light, X-rays, and gamma rays, as well as with incredibly minuscule moving particles like atoms, neutrons, and electrons that exhibit wavelike qualities. Diffraction prevents the creation of sharp shadows as one of its effects. In order to spread out and illuminate regions at which a shadow is anticipated, light must be bent around corners, which is known as diffraction.
Calculation:
Provided for a single slit, m=1
λ = 624 *10⁻⁹
sinθ = sin 18⁰
Therefore,
asinθ=mλ
a = [tex]\frac{1 * 624 *10^{-9} }{sin 18}[/tex]
⇒a = 2019 *10⁻⁹ m
Therefore the width of a single slit is 2019 *10⁻⁹ m.
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3. A lab technician is preparing urea broth. It should be sterilized by filtration, he autoclaves it instead, just like he does for any other media. The high temperature of the autoclave causes the urea to break down. What color is the sterile urea broth when it comes out of the autoclave? but rstroedave tocave.
Urea get decomposed during autoclaving, because it is volatile. It is filter sterilized and added aseptically to your autoclave media.
Can urea be autoclaved?
Urea get decomposed during autoclaving, because it is volatile. It is filter sterilized and added aseptically to your autoclave media.What is autoclave sterilization?
In medical and laboratory settings, an autoclave is used to sterilise waste and lab supplies. Heat is used in the autoclave sterilisation process to eliminate bacteria and spores. Pressurized steam provides the heat.What is filter sterilization?
By using filtering, it is possible to exclude organisms based on their size. There are many different kinds of filtration methods, but membrane filtration is utilised to sterilise a system. Contaminants that are larger than the pore size are captured by membrane filtration on the membrane's surface.Learn more about autoclave media.
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Which process in the nitrogen cycle converts nitrogen into its most polluting form?
The process in the nitrogen cycle converts nitrogen into its most polluting form will be "nitrification".
The biological process of nitrification turns ammonia into nitrite and nitrite into nitrate. The technique of denitrification, which turns nitrate into nitrogen gas, is such treatment option if requirements demand that the resultant nitrate be eliminated.
A surplus of nitrogen compounds could result in pollutants like ammonia and ozone that can affect plant growth, visibility, and human capacity to breathe. Excess nitrogen from the atmosphere that returns to earth could be damaging to the health of forests, soils, including streams.
Therefore, the process in the nitrogen cycle converts nitrogen into its most polluting form will be "nitrification".
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The density of aluminum is 2.7 g/cm³. What is the density of aluminum in decagrams/m³?
Answer:
Density = 0.27 decagrams/cm³
Explanation:
From conversion tables, we know that;
1 g/cm³ = 0.1 decagrams/cm³
We are given;
Density of aluminium = 2.7 g/cm³
Thus;
Density = 2.7 * 0.1
Density = 0.27 decagrams/cm³
Answer:
270000 decagrams/m³
Explanation:
1.
Density=mass/Volume
=2.7g/1cm3
=(2.7/1000)/(1/1000000)
=2.7x1000
Density=2700kg/ m3
= 270000 decagrams/m³
2.
1000g=1kg
1g=1/1000kg
1cm3= ? m3
100cm=1m
1cm=1/100 m
1cm3=1/1000000 m3
What volume (ml) of fluorine gas is required to react with 1. 28 g of calcium bromide to form calcium fluoride and bromine gas at stp?
144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.
What is Ideal Gas Law ?The ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.
PV = nRT
where,
P = Presure
V = Volume in liters
n = number of moles of gas
R = Ideal gas constant
T = temperature in Kelvin
Here,
P = 1 atm [At STP]
R = 0.0821 atm.L/mol.K
T = 273 K [At STP]
Now first find the number of moles
F₂ + CaBr₂ → CaF₂ + Br₂
Here 1 mole of F₂ reacts with 1 mole of CaBr₂.
So, 199.89 g CaBr₂ reacts with = 1 mole of F₂
1.28 g of CaBr₂ will react with = n mole of F₂
[tex]n = \frac{1.28\g \times 1\ \text{mole}}{199.89\ g}[/tex]
n = 0.0064 mole
Now put the value in above equation we get
PV = nRT
1 atm × V = 0.0064 × 0.0821 atm.L/mol.K × 273 K
V = 0.1434 L
V ≈ 144 mL
Thus from the above conclusion we can say that 144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.
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Na -k pumps couple atp hydrolysis with the transport of na and k. in which direction do they move those ions?
Na -k pumps couple atp hydrolysis with the transport of Na and k.
Both ions are used for active transport.
d. K+ and Na+ both diffuse into the cell along their concentration gradients and drive the transport of glucose.
Na/K pump is a pump located on the plasma membrane which uses ATP to move 3 Na ions out the cell and brings in 2 K ions into the cell. It is an example of primary active transport. As a consequence, concentration of Na is higher outside the cell, while K concentration is higher inside the cell.
Glucose is transported in the cell against its gradient, together with Na ions (symport) which move down their concentration gradient.
This is an example of secondary active transport because it uses the energy from the primary active transport to move other substances such as glucose against their own gradients.
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A mixture of reactants and products for the reaction shown below is at
equilibrium in a 2.0 L container. What would most likely happen to the
equilibrium if the volume of the container were increased to 4.0 L?
N₂(g) + 3H₂(g)—2NH₂(g)
A. More NH3 would be produced.
B. Less N₂, H₂, and NH3 would be produced.
C. More N₂, H₂, and NH3 would be produced.
D. More N₂ and H₂ would be produced.
If the volume of the container were increased to 4.0 L, more N₂ and H₂ would be produced (Option D)
What is chemical equilibrium?
This is simply defined as a state in a chemical system where there is no observable change in the properties of the system with time.
Principle of chemical equilibriumA French scientist postulated a principle which helps us to understand a chemical system in equilibrium.
The principle states as follow:
If a an external constraint such as change in temperature, pressure or concentration is imposed on a system in equilibrium, the equilibrium will shift so as to neutralize the effect.
How to determine what will happen if the volume of the container is increased from 2 L to 4 LFrom the principle given above, we can see that volume does not affect equilirium position.
However, from Boyle's law, we understood that pressure and volume are in invest relationship.
Thus, increasing volume simply means decreasing pressure.
A decrease in pressure will favors the side where there is an increase in volume.
Let us consider the equation from the question:
N₂(g) + 3H₂(g) <=> 2NH₃(g)
Volume of reactants = 1 + 3 = 4 LVolume of products = 2 LThus, we can conclude that increasing the volume (i.e decreasing the pressure) of the reaction will favors the backward reaction, hence, more N₂ and H₂ would be produced.
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How many amps are required to produce 75. 8 g of iron metal from a solution of aqueous iron(iii)chloride in 6. 75 hours?
The amount of current required to produce 75. 8 g of iron metal from a solution of aqueous iron (iii)chloride in 6. 75 hours is 168.4A.
The amount of Current required to deposit a metal can be find out by using The Law of Equivalence. It states that the number of gram equivalents of each reactant and product is equal in a given reaction.
It can be found using the formula,
m = Z I t
where, m = mass of metal deposited = 75.8g
Z = Equivalent mass / 96500 = 18.6 / 96500 = 0.0001
I is the current passed
t is the time taken = 75hour = 75 × 60 = 4500s
On subsituting in above formula,
75.8 = E I t / F
⇒ 75.8 = 0.0001 × I × 4500
⇒ I = 168.4 Ampere (A)
Hence, amount of current required to deposit a metal is 168.4A.
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A solution is 0. 0480 m lif. What is the molarity of the solution if the density is 1. 10 g/ml?.
The molarity of the solution is 0.528 mol/l.
What is molarity?
The molarity of any solution is the number of moles per liter of the solution.
Given,
The molality of the solution is 0.0480 m Lif
The density of the solution is 1.10 g/ml
Step 1: 0.0480 moles of LiF were present in 1 kg solvent.
Mass of 0.0480 moles of LiF = 0.0480 mol × 26 g/mol = 1.248 g
Mass of the solution (m)= 1 kg (solvent) + 1.248 g(solute)
m = 1000 g + 1.248 g = 1001.248 g
Step 2: Find the volume of the solution
Step 3: Calculating the molarity
Thus, the molarity of the solution is 0.528 mol/l.
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Describe the principle. Involved in Gas chromatography.
20. 10 in the molecular orbital model of benzene, the six p atomic orbitals combine to form how many molecular orbitals?
The six p atomic orbitals combine to form 6 molecular orbitals. The correct option is A.
What is molecular orbital?Molecular orbitals are the functions that tell the position of an electron in the orbital and the wave like property of the electron. This function is used to find the chemical and physical property of the element.
The six p atomic electrons will combine to constitute 6 molecular pi electrons. Because in benzene there are 6 pi orbitals. As benzene is planar, hexagonal and have sp2 hybridization. The remaining cyclic orbitals overlap to create 6 pi molecular orbitals.
Thus, the correct option is A. 6.
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The question is incomplete. Your complete question is given below:
A. 6
B. 5
C. 4
D. 3
E. 2
A sample of gas occupies 75.5 mL at -14.2°C. What volume does the sample occupy at 146.7 °C?