What is the gravitational acceleration on the board of the Deepsea Challenger when it is in the Mariana Trench, 11 km below the surface of the Pacific Ocean?
a. It is slightly less than 9.81 m/s2.
b. It is very large due to the high pressure.
c. It is zero.
d. It is significantly less than 9.81 m/s2.

Answers

Answer 1

The gravitational acceleration on the board of the Deepsea Challenger when it is in the Mariana Trench, 11 km below the surface of the Pacific Ocean is very large due to the high pressure. That is option B

What is gravitational acceleration?

The gravitational acceleration is the acceleration of an object that is under free fall. The acceleration due to gravity is 9.81 m/s2. above the sea level.

One of the factors that affect gravitational acceleration is depth. This is because as the depth increases so will pressure increase.

Increase in pressure leads to increase in gravitational acceleration.

Therefore, the gravitational acceleration on the board of the Deepsea Challenger when it is in the Mariana Trench, 11 km below the surface of the Pacific Ocean is very large due to the high pressure.

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Related Questions

A worker uses a pulley system to raise a 225
N carton 16.5 m. A force of 129 N is exerted
and the rope is pulled 33.0 m. What is the IMA
of the system?

Answers

Answer:

1.74

Explanation:

"How do you calculate the mechanical advantage of a block and tackle pulley?

To calculate the mechanical advantage, we can either divide the weight of the object being lifted by the force required to lift it or we can divide the amount of rope we have to pull by the distance the object moves."

If we use the rope method the mech advantage is  33.0/16.5 = 2

  now if we use the forces   MA = 225/129 =1.74 <==== this is not equal to '2' as we first found due to energy being lost to friction/deformation of rope etc.              SO I would say the true mechanical advantage = 1.74  

Efficiency =  1.74/2 = 87%

On space missions with international teams, every country involved wants the flight
director to be chosen from their country because their national space organization
receives a significant amount of funding if they lead the mission.

True

False

Answers

False, their national space organization receives a significant amount of funding if they lead the mission.

The team typically sends about 30,000 remote control commands from the ground to the space station to manage the platform. Highly interactive, hands-on, tactile, and highly rewarding.

A mission control center (MCC, sometimes called a flight control center or operations center) is a facility that typically manages spaceflight from the launch point to landing or the end of the mission. This is part of the ground segment of spacecraft operations.

The station serves as a microgravity and space laboratory where scientific research in fields such as astrobiology, astronomy, meteorology, and physics is conducted.

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What does the Q stand for in the enthalpy of fusion equation?

Answers

The Q in the enthalpy of fusion equation stands for heat energy absorbed or released.

What is enthalpy?

In thermodynamics, enthalpy is a measure of the heat content of a chemical or physical system.

The enthalpy of fusion is the amount of heat energy required to convert a unit mass of a solid at its melting point into a liquid without an increase in temperature.

Its units are usually Joules per gram (J/g) or calories per gram (cal/g).

The enthalpy of fusion equation is given as follows:

Q = m·ΔHf

Where;

Q = heat energym = massΔHf = heat of fusion

Therefore, the Q in the enthalpy of fusion equation stands for heat energy absorbed or released.

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A child rolls a ball on a level floor 5.2 m to another child.
If the ball makes 15.0 revolutions, what is its diameter?
Express your answer to two significant figures and include the appropriate units.

Answers

Diameter of the ball = 11.03cm

The ball rolled by the child must cover a distance in a linear motion which will be then equal to the circumference of the ball after one complete revolution.

Linear distance = 5.2m

d = diameter of the ball =?

Total revolutions = 15

S = 2πr

S = πd

For 15 revolutions

S = 15πd

The Diameter of a ball is double the radius of the ball thus we use D instead of 2r in the formula

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A thin-walled hollow sphere has a radius 4cm from the center
of the sphere, the eletric field points radially inward and
has a magnitude of 1.5 × 10^4 NC". How much charge is on the surface

Answers

The  electric charge on surface is 2.66×10-⁹NC

What is an electric charge?

The electric charge is the property  of subatomic particle that causes it to experience a force when placed in an electric and magnetic field.

We have given ,

Electric field= 1.5×10⁴N/C

 Radius = 4cm = 0.04m

E = k× q/ r²

 1.5×10⁴×16×10-⁴/9×10⁹=q

 q= 2.66×10-⁹C

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The speed of a box traveling on a horizontal friction surface changes from vi = 13 m/s to vf = 11.5 m/s in a distance of d = 8.5 m. If the box has a mass of 1 kg, what is the average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s?

Answers

The average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.

Acceleration of the box

The acceleration of the box is calculated as follows;

vf² = vi² + 2as

a = (vf² - vi²)/2s

a = (11.5² - 13²) / (2 x 8.5)

a = -2.16 m/s²

Time of motion of the box

The time taken for the box to travel is calculated as follows;

a = (vf - vi)/t

t = (vf - vi) / a

t = (11.5 - 13) / (-2.16)

t = 0.69 s

Average power supplied by the friction

P = Fv

P = (ma)(vf - vi)

P = (1 x -2.16) x (11.5 - 13)

P = 3.24 W

Thus, the average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.

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A thin-walled hollow sphere has a radius 4cm from the center
of the sphere, the eletric field points radially inward and
has a magnitude of 1.5 × 10^4NC^-1 How much charge is on the surface

Answers

A thin-walled hollow sphere has a radius of 4 cm from the center

of the sphere, the electric field points radially inward and

has a magnitude of 1.5 × 10⁴ N/C then the charge on the surface would be 2.6690×10⁻⁹ C

What is an electric charge?

Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. You can have a positive or negative electric charge.

The electric field inside a spherical shell is given by the formula

E = q/4πεr²

where q is the charge on the surface

r is the radius of the sphere

ε is the electrical permeability

By substituting the respective values in the given formula

1.5 × 10⁴ = q/4π(8.85✕ 10⁻⁻¹²)(.04²)

q = 2.6690×10⁻⁹ C

Thus, the charge on the surface would be2.6690×10⁻⁹ C

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A body of mass 80kg moving with a velocity of 6m/s hits a stationary body
of mass of 40kg. If the two bodies stick after the impact, calculate their
common velocity.

Answers

Answer:

4 m/s

Explanation:

Conservation of momentum ,  mv

Before collision  80 kg * 6 m/s  = 480  kg-m/s  

   after the collision,

         the momentum is the same but the mass is 80+40 kg =120 kg

 mv = 480

120 * v = 480

v = 4 m/s

A -4.00 nC point charge is at the origin, and a second -6.00 nC point charge is on the x-axis at x = 0.800 m. Find the net electric force that the two charges would exert on an electron placed at point on the x -axis at x = 0.200 m'

Answers

The net electric force that the two charges would exert on an electron placed at point on the x -axis is 1.68 x 10⁻¹⁶ N.

Force on electron due to charge 1

The force exerted on the electron due to the charge q1 placed at the origin is calculated as follows;

F = kq₀q₁/r²

where;

k is coulomb's constantq0 is charge at the originq1 is the charge at 0.2 m (electron)r is the distance between the charges

F(01) = (9 x 10⁹ x 4 x 10⁻⁹ x 1.6 x 10⁻¹⁹)/(0.2²)

F(01) = 1.44 x 10⁻¹⁶ N

Force on electron due to charge 2

The force exerted on the electron due to the charge q1 placed at the origin is calculated as follows;

F = kq1q2/r²

where;

k is coulomb's constantq2 is charge at the 0.8 mq1 is the charge at 0.2 m (electron)r is the distance between the charges = 0.8 m - 0.2 m = 0.6 m

F(12) = (9 x 10⁹ x 6 x 10⁻⁹ x 1.6 x 10⁻¹⁹)/(0.6²)

F(12) = 2.4 x 10⁻¹⁷ N

Net force on the electron

F(net) = 2.4 x 10⁻¹⁷ N +  1.44 x 10⁻¹⁶ N

F(net) = 1.68 x 10⁻¹⁶ N

Thus, the net electric force that the two charges would exert on an electron placed at point on the x -axis is 1.68 x 10⁻¹⁶ N.

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Quark gluon plasma (qgp) is what kind of state of matter I.e. it’s equation of state is what?

Answers

a 10 kg block reaches a point with a velocity of 15 m per second and slides down a rough track my the coefficient of the kinetic energy between the two surface ab and the block iis0.52

Lifting a 81-kg barbell and weights from rest up to a speed of 1.0 m/s in 0.50 s, resisted by the combined weight of the barbell and weights, requires what applied force in N to two significant digits?

Answers

Answer:

960 N

Explanation:

answer should have two signif digits  

a = change in velocity divided by change in time

   1 m/s / .5 s =   2 m/s^2

F = ma      a = g + 2 m/s^2 = 9.81 + 2 =  11.81 m/s^2

  81 kg * 11.81 m/s^2   = 956.61   N = ~ 960 N  (two sig digits)

(Please let me know if this is incorrect....I am not SURE )

2. What energy source produces most of the electrical energy in the United States?
natural gas
O oil
O coal

Answers

Answer:

Nat gas

Explanation:

Approx:

Natural gas 38%       coal 21%       oil  19%

Write a properly formatted hypothesis statement to answer this question: How does the amount of salt added to ice affect the rate at which the ice will melt?



Specify how you plan to change the independent variable by using terms such as increase or decrease. Also, specify how the dependent variable will change in response by using terms such as increase, decrease, or stays the same.



Criteria pts
Correct placement of IV 5
Correct placement of DV 5
If, then format 5
IV indicates either "increases" or "decreases" 5
DV indicates either "increases", "decreases", or "stays the same" 5

Answers

The hypothesis will be:

H₀ = The amount of salt added to ice will not affect the rate at which the ice will melt.

H₁ =  The amount of salt added to ice will affect the rate at which the ice will melt.

The independent variable which is can be changed by increasing the rate of salt added to the equation.

The dependent variable which is ice will change or melt in response as it will decrease if the rate of the salt added increases.

What is the effect of salt on the melting temperature of ice?

Salt does not really lower the temperature of an ice cubes, it is known to just lowers their freezing point, that is lowers their melting point.

Note that if salt is around, ice cubes are known to be colder to be solid, and they tend to melt at a temperature that is said to be lower than the freezing point of pure water.

If  the ionic compound salt is known to be added, it tends to lowers the freezing point of the water, which implies that the ice on the ground is not able to freeze that layer of water at all.

Therefore, The hypothesis will be:

H₀ = The amount of salt added to ice will not affect the rate at which the ice will melt.

H₁ =  The amount of salt added to ice will affect the rate at which the ice will melt.

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16) Find the orbital speed of an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radius of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2) A) 19.5 km/s B) 27.5 km/s *C) 11.2 km/s D) 20.5 km/. orbital speed?

Answers

The orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s. The correct answer is option C

What does Orbital speed depend on ?

The speed of an object travelling around a circle depends on two quantities namely;

Its angular velocity wIts distance from the center of the circle.

Given that  an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radius of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2)

The given parameters are:

The mass of Saturn = 5.68 x 10^26 kgThe orbital radius = 3.00 x 105 kmG = 6.67 × 10-11 N·m2/kg2

Let us first calculate the gravitational field strength on the Saturn.

g = GM/r²

Substitute all the necessary parameters and convert km to m

g = (6.67 × [tex]10^{-11}[/tex] × 5.68 × [tex]10^{26}[/tex]) ÷ (300000 × 1000)²

g = 3.79 × [tex]10^{16}[/tex] ÷ 9 × [tex]10^{16}[/tex]

g = 0.421 m/s²

The  orbital speed will be

V² = gr

V² = 0.4211 × 300000 × 1000

V² = 126333333.3

V = √126333333.3

V = 11239.8 m/s

Convert it to Km/s by dividing the answer by 1000

V = 11239.8/1000

V = 11.2 Km/s

Therefore, the orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s

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Glucose solution is administered to a patient in a hospital. The density of the solution is 1.308 kg/l. If the blood pressure in the vein is 35.7 mmHg, then what is the minimum necessary height of the IV bag above the position of the needle?

Answers

The minimum necessary height of the IV bag above the position of the needle is 0.37 m.

Minimum necessary height

The minimum necessary height of the IV bag above the position of the needle is calculated as follows;

P = ρgh

where;

ρ is density = 1.308 kg/L = 1308 kg/m³g is acceleration due to gravity = 9.8 m/s²p is pressure = 35.7 mmHg = 4759.609 Pah is height, (m) = ?

h = P/ρg

h = (4759.609) / (9.8 x 1308)

h = 0.37 m

Thus, the minimum necessary height of the IV bag above the position of the needle is 0.37 m.

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A ball is released from the top of a tower of height h meters. it takes T seconds to reach the ground . what is the position of the ball in T/3 seconds ?​

Answers

Answer:the

8/9 h

Explanation:

Height  =   1/2 a T^2     now change to T/3

 now height = 1/2 a (T/3)^2   = 1/9  1/2 a T^2     <===== it is 1/9 of the way down   or   8/9 h

 

A solid cylinder of uniform density of 0.85 g/cm3 floats in a glass of water tinted light blue by food coloring.
Its circular surfaces are horizontal. What effect will the following changes, each made to the initial system, have on X, the height of the upper surface above the water? The liquids added do not mix with the water, and the cylinder never hits the bottom.

1. The cylinder is replaced with one that has the same density and diameter, but with half the height.
2. Some of the water is removed from the glass.
3. A liquid with a density of 1.06 g/cm3 is poured into the glass.
4. The cylinder is replaced with one that has the same height and diameter, but with density of 0.83 g/cm3.
5. A liquid with a density of 0.76 g/cm3 is poured into the glass.
6. The cylinder is replaced with one that has the same density and height, but 1.5× the diameter.
Options are: Increase, Decrease, No change

Answers

Each side has to have at least 44 horses

F61160 N. This is further explained below.

What is the force?

Generally, We are only interested in the component that operates horizontally since the vertical components all cancel each other out. The pressure difference works on the hemisphere to generate a normal force all over the surface, but we are only concerned with that force's horizontal component. This may be determined by supposing the hemispheres to be two flat circular plates of the same radius as the hemispheres that have been forced together.

Therefore, force is equal to pressure multiplied by area, which is

F= (970 -15 )( * (0.45 m)2)

F=60754 N for each side.

Therefore, each side has to have at least 44 horses

44* 1390 = 61160 N

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If a person walks first 70 m in the direction 37° north of east, and then walks 82 m in the
direction 20° south of east, and finally walks 28 m in the direction 30° west of north.(2pt)

a) How far and at what angle is the Aster's final position from her initial position?

b) In what direction would she has to head to return to her initial position

Answers

The Aster's final position from her initial position is determined as 45.3 m.

The direction that she has to head to return to her initial position is 30° west of north.

Distance of the person from her initial position

The distance traveled by the person can be determined by making a sketch of the person's journey.

From the initial distance traveled and the second distance distance the angle between the two position is calculated as;

θ = 37⁰ + 20⁰ = 57⁰

Distance opposite to the angle

The distance opposite to the angle is resultant displacement and it is calculated as follows;

r² = (70²) + (82²)  - (2 x 70 x 82) x cos(57)

r² = 5,371.54

r = √5,371.54

r = 73.3 m

Haven walked 28 m in the same direction to her initial position, the remaining distance is calculated as follows;

d = 73. 3 m  - 28 m

d = 45.3 m

Thus, the Aster's final position from her initial position is determined as 45.3 m.

The direction that she has to head to return to her initial position is 30° west of north.

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Answer:

See below

Explanation:

I will break the legs into vertical and horizontal components then add them

Horizontal = 70 cos 37  + 82 cos 340  + 28 cos 120 =  118.96 m

Vertical  =   70 sin 37     + 82 sin 340   + 28 sin 120 =  38.33 m

Resultant distance from origin is found via pythag theorem

   d^2 = 118.96^2  + 38.33^2        d = 124.98 m

   direction FROM origin is   arctan ( 38.33/118.96) = 17.86°

       to get BACK to the origin , will have to walk 180 degrees from this = 197.86°

Calculate the frequency if the number of revolutions is 300 and the paired poles are 50.



15 kHz

150 kHz

1500 kHz

150 Hz

Answers

Answer: A

Explanation: We know that f=p*n

f=50*300=15000 Hz = 15kHz.

Have a great day! <3

If the number of revolutions is 300 and the paired poles are 50 , then the frequency would be 15 kHz, therefore the correct answer is option A.

What is the frequency ?

It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.

The frequency of a pendulum is the reciprocal of the time period can be given by the following relation,

F = 1 / T

As given in the problem, we have to calculate frequency if the number of revolutions is 300 and the paired poles are 50.

F = 300 × 50

  = 1500 kHz

Thus, If the number of revolutions is 300 and the paired poles are 50, then the frequency would be 15 kHz, therefore the correct answer is option A.

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the apparent weight of a student in alift is 564N . if the mass of the student is 60.3kg, what is the acceleration of the lift ? use negative is the acceleration vector is pointing downwards

Answers

Answer:

-.457 m/s^2

Explanation:

Actual weight =   60 .3 (9.81) = 591.54 N

Accel of lift changes this to    60.3 ( 9.81 - L)     where L - accel of lift

                                           60.3 ( 9.81 - L ) = 564

                                               solve for L = .457 m/s^2  DOWNWARD

                                                        so L = - .457 m/s^2

Give two examples of situations or application where electronic circuits are used

Answers

a battery running to a transistor to regulate voltage to then power an LED lightbulb.


Warm-Up
Type your response in the box.
When the Moon comes directly between the Sun and Earth, a solar eclipse occurs. The eclipse may be a total eclipse,
where the Sun is completely blocked by the Moon, or an annular eclipse, where you can see a ring of sunlight
surrounding the Moon. What do you think makes a total eclipse occur instead of an annular eclipse?

Answers

The moon surrounding it makes be believe it is it

Answer: Both total and annular eclipses depend on the distances between Earth, the Moon, and the Sun. A total solar eclipse occurs when the Moon is closer to Earth, thus taking up a larger portion of the sky. The Moon is then able to cover the entire Sun.

Explanation: Edmentum answer

The Sun subtends an angle of about 0.5∘ to us on Earth, 150 million km away.
Estimate the radius of the Sun.
Express your answer to two significant figures and include the appropriate units.

Answers

The radius of the Sun is approximately 654497.9 kilometers.

A subtended angle in geometry is an angle created by a common point (in this case, the Earth) that crosses two points of a nearby circular arc (the Sun in this case). Below is a visual illustration of the subtended angle.

The law of cosine can be used to calculate the sun's radius, which is 654497.950 kilometers in kilometers.

The Sun's radius is nearly 109 times bigger than the Earth's. The Earth's radius is 6378 kilometers. Or to put it another way, both dimensions are 1: 109 ratios.

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PLEASE read this carefully.
A solid, homogeneous sphere with a mass of m0, a radius of r0 and a density of ρ0 is placed in a container of water. Initially the sphere floats and the water level is marked on the side of the container. What happens to the water level, when the original sphere is replaced with a new sphere which has different physical parameters? Notation: r means the water level rises in the container, f means falls, s means stays the same. Combination answers like 'r or f or s' are possible answers in some of the cases.
The new sphere has a radius of r < r0 and a mass of m > m0.
The new sphere has a mass of m > m0 and a density of ρ < ρ0.
The new sphere has a density of ρ < ρ0 and a radius of r > r0.

Answers

For each of the given scenarios and based on the  volume, mass, and density of the spheres, the water level is given as follows:

Scenario 1: The water level will rise; r

Scenario 2: The water level may rise or fall; r or f

Scenario 3: The water level will fall; f

What is the relationship between volume, density, and mass of the objects?

The density, volume and mass of an object are related by the formula below:

Density = mass/volume

The rise in the level of fluid when an object is placed in that fluid depends on the weight, volume and density of that object.

This is given by Archimedes' principle which states that the upthrust acting on a body immersed fully or partially in a fluid, is equal to the weight of the fluid displaced.

Based on the above, the water level in each of the scenarios is described thus:

Scenario 1: The new sphere has a radius of r < r0 and a mass of m > m0.

The new has a smaller volume and a greater mass and density. The water level will rise.

Scenario 2: The new sphere has a mass of m > m0 and a density of ρ < ρ0.

The new sphere has a greater volume and will float. Therefore, the water level may rise or fall.

Scenario 3: The new sphere has a density of ρ < ρ0 and a radius of r > r0.

The new sphere has a greater volume but less mass. Therefore, the water level will fall.

In conclusion, the rise or fall of the water level in the container depends on the volume, mass, and density of the spheres.

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The technology in the picture produces which energy conversion?
O A. Light energy to electrical energy
• B. Thermal energy to kinetic energy
C. Chemical energy to kinetic energy
D. Kinetic energy to electrical energy

Answers

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

Option D

[tex]\textsf{ \underline{\underline{Explanation} }:}[/tex]

The given picture shows a dam, and as we know dam ises water current to produce electricity. as the water current has high kinetic energy, so when it hits and rotates the turbine, the generator produces electricity.

Hence, the correct option will be :

❖ D. Kinetic energy to electrical energy

The density of molybdenum is 10.28 g/cm^3 and it crystallizes in the face centered cubic unit cell. Calculate the edge length of the unit cell. (The atomic mass of Mo is 95.96 g/mole)

Answers

The edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.

Volume of molybdenum

V = (zm/ρN)

where;

z is 2 for cubic unit cellm is mass of the molybdenumρ is density of the molybdenum

V = (2 x 95.96) / (10.28 x 6.02 x 10²³)

V = 3.10 x 10⁻²³ cm³

Edge length of the unit cell

a³ = V

a = (V)^¹/₃

a = ( 3.10 x 10⁻²³)^¹/₃

a = 3.142 x 10⁻⁸ cm

a = 3.142 x 10⁻¹⁰ m

a = 314.2 x 10⁻¹² m

a = 314.2 pm

Thus, the edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.

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A 22-g bullet traveling 265 m/s penetrates a 1.9 kg block of wood and emerges going 125 m/s .
If the block is stationary on a frictionless surface when hit, how fast does it move after the bullet emerges?
Express your answer to two significant figures and include the appropriate units.

Answers

The body moves at a velocity of 1.62m/s after the bullet emerges.

Given:

Mass of bullet, [tex]m_1[/tex] = 22g

                               = 0.022 kg

Mass of the block, [tex]m_2[/tex] = 1.9 kg

Velocity of bullet , [tex]v_1[/tex] = 265 m/s

[tex]v_2 = 0[/tex]

According to the law of collision which states that the momentum of the body before the collision is equal to the momentum of the body after the collision.

After penetration;

[tex]v^{'}_1 =125 m/s[/tex]

[tex]v^{'}_2=?[/tex]

The formula for calculating the collision of a body is expressed as:

p = mv

m is the mass of the body

v is the velocity of the body

Momentum before = Momentum after

Substitute the given parameters into the formula as shown:

   [tex]m_1v_1+ m_2v_2 = m_1v^{'}_1+ m_2v^{'}_2\\0.022* 265 + 0 = 0.022*125+1.9*v^{'}_2\\5.83 = 1.9 v^{'}_2\\v^{'}_2 = 1.62 m/s[/tex]

Therefore, It moves with a velocity of 1.62 m/s.

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A weight lifter lifts a mass of 250 kg with a force of 5000N to a height of 5m. a. What is the workdone by the weight lifter? b. What is the workdone by the gravity? c. What is the net workdone on the object?
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Answers

Answers are:

a. The work done by the weight lifter W = 25000 Joule

b. The work done by the gravity W = 12250 Joule

c. The net work done on the object W = 12750 Joule

What is Work ?

Work is the product of force and distance in the direction of the force applied. That is, W = F x h

The S.I unit is Joule.

Given that a weight lifter lifts a mass of 250 kg with a force of 5000N to a height of 5m.

The given parameters are;

Mass  m = 250 kgForce F = 5000 NHeight h = 5 m

a. The work done by the weight lifter will be

W = F x h

W = 5000 x 5

W = 25000 Joule

b. The work done by the gravity will be

W = mg x h

W = 250 x 9.8 x 5

W = 12250 Joule

c. The net work done on the object will be

W = 25000 - 12250

W = 12750 Joule

Since the work done by the gravity is in opposite direction to the work done by the weight lifter, the net work done on the object will be the difference between the two.

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4. A hemispherical surface (half of a spherical surface) of radius R is located in a uniform electric field of magnitude E that is parallel to the axis of the hemisphere. What is the magnitude of the electric flux through the hemisphere surface? how to draw the question?

Answers

It is to be noted that the magnitude of the electric flux through the hemisphere surface  is πR²E. (Option D)

What is an Electric Flux?

The characteristic of an electric field known as electric flux may be thought of as the quantity of electric lines of force (or electric field lines) that cross a certain region.

According to this theory, electric field lines begin with positive electric charges and end with negative charges.

What is the calculation for the above?

Recall  that the A hemispherical surface (half of a spherical surface) of radius R.

In order to derive the Magnitude of the electric flux we use the following formula:

Ф = ∈ x Area of the Curve Surface

⇒ Ф = ∈ x πR²

⇒ Ф = πR²∈

Thus, option D is the correct answer.

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Full Question:

A hemispherical surface (half of a spherical surface) of radius R is located in a uniform electric field of magnitude E that is parallel to the axis of the hemisphere. What is the magnitude of the electric flux through the hemisphere surface?

A) 2πR²∈

B) 0

C) 4 πR²∈/3

D) πR²∈

It's your first day on the job without your mentor as a member of mission control.
Your shift begins and your counterpart, who happens to be in their 10th year in this
position, speaks to you for about 45 minutes as they end their shift and you begin
yours. What were they talking to you about?

getting you up to date with recent mission developments

sanitation protocol that all employees must memorize

connecting you with each of the astronauts in space at the time

how to change settings for each system that's in use

Answers

Explanation:

getting me up to date with recent mission development

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