What is the following simplified product? Assume x 20.
(√6x² +4√8x³)(√9x-x√5x^5)
O 3x√√6x+x²√30x+24x²2x+8x³10x
O 3x√6x+x√30x+24x²√2+8x5/10
O 3x√√6x-x+√30x+24x² √2-8x² 10
O3x6x-x30x+24x²2x-8x510x

Using the Geometric mean theorem and the Pythagorean theorem:

x = 3√3, and y = 6.

The Geometric mean theorem or the right triangle altitude theorem states that the geometric mean of the the two segments equals he length of the altitude of a right triangle.

The geometric mean theorem is expressed by the equation, h = √(ab), where:

Given the following:

h = x

a = 9

b = 3

x = √(9 × 3)

x = 3√3

Find y using the Pythagorean theorem

Based on the Pythagorean theorem, we would have the following:

y = √(x² + 3²)

y = √((3√3)² + 3²)

y = √(27 + 9)

y = √(36)

y = 6

Thus, in the simplest radical form, the value of x = 3√3, and y = 6.

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The range of the means is 0.5

Mean of S1

= 5 + 6+ 6+ 2

= 19/4

= 4.75

Mean of S2

= 4 + 8 + 4 + 3

= 19/4

= 4.75

Mean of s3

= 4 + 2 + 6+ 5

= 17/4

= 4.25

Range of sample means = 4.75 - 4.25

= 0.5

c. the true statements here is that

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Answer:

Wayne used 2/5 more flour than sugar

Step-by-step explanation:

If you add 2/5 to 2/5 you get 4/5

Answer:

Sum of 374 and 25 = 374+25 = 399

now subtract 9 from the sum, i.e. 399 = 399 - 9 = 390 is your answer

Answer:

Step-by-step explanation:

374+25

=399

Now, subtracting the sum from 9

9-399

=   -390

Y receives $30000 less than if the profit were divided in proportion to how much they invested.  

In a proportional tax system, everyone is compelled to pay the same amount of taxes as a percentage of their income.

Profit will Divide into 4 equal parts.

The total Profit for the month is  = $120,000

The party will receive a sum of = $30,000

This shows that Y also receive the same amount

Y = $30,000 (Profit received)

Now

If the Profits were divided in proportion to the investments made .

The proportion on investment made by Y.

The total investment made = $12000+$6000+$25000+$7000

                                            = $50000

Out of this the Amount invested by Y = $25000

The Proportional Profit of Y.

=  (25000/ 50000) x 120000                      

= $60,000

So Y receives 60000 - 30000

                       = 30000

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Answer:

y= 4

Step-by-step explanation:

(y-4) (y+7)=0

(4-4) (4+7)=0

(0) (11)=0

11*0=0

Answer:

C

Step-by-step explanation:

for AB to be parallel to CD then the slopes of both segments must be equal

using the slope formula to find the slopes , then

A (x₁, y₁ ) and B (x₂, y₂ )

[tex]m_{AB}[/tex] = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

C (x₃, y₃ ) and D (x₄, y₄ )

[tex]m_{CD}[/tex] = [tex]\frac{y_{4}-y_{3} }{x_{4}-x_{3} }[/tex]

then

[tex]m_{CD}[/tex] = [tex]m_{AB}[/tex]

[tex]\frac{y_{4}-y_{3} }{x_{4}-x_{3} }[/tex] = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex] → C

The probability that the number of heads is equal to the number showing on the die is [tex]\frac{21}{128}[/tex] .

According to the question

we roll one fair six-sided die, and flip six coins

i.e

The Total Outcomes is the product of the sample spaces for the dice and the coins.  

sample spaces for the dice = 6

sample spaces for the coins = 2⁶

S = 6.2⁶

S = 384

Now, The  probability is

Therefore, the Favorable Outcomes

Consider the number of ways to get each total of heads from 1 to 6.

= 2⁶-1 (as TTT is excluded )

= 63

The probability that the number of heads is equal to the number showing on the die

As

Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event.

Probability(Event) = Favorable Outcomes/Total Outcomes

By substituting the values in the formula

Probability(Event) = [tex]\frac{63}{384}[/tex]

Probability(Event) = [tex]\frac{21}{128}[/tex]

Hence, the probability that the number of heads is equal to the number showing on the die is [tex]\frac{21}{128}[/tex]

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Answer:

=> -2.22

Step-by-step explanation:

=> 2.35 + ( -4.57)

=> 2.35 - 4.57

=> - 2.22

Answer:

28 DVDs

Step-by-step explanation:

Given information from the question, we can deduce:

2 weeks = 4 DVDs

1 week =

[tex] \frac{4}{2} \\ = 2[/tex]

2 DVDs on average.

Which means,

14 weeks = 2 × 14 = 28 DVDs

Therefore, Katy will buy 28 DVDs in 14 weeks.

Based on the type I error, if a hypothesis test leads to the probability of a type I error decreasing, then the a. probability of incorrectly accepting the null hypothesis decreases.

A type I error refers to when we are are engaged in a hypothesis test and end up rejecting the Null hypothesis even though it is true.

If we are in hypothesis tests and the probability of a type 1 error decreases, then it means that the probability of us correctly rejecting the null hypothesis when it is false increases.

It also means that the probability of us correctly accepting the null hypothesis when it is true increases as well.

This can further be said as the probability of us accepting the null hypothsis when it is false, decreases. There are therefore less chances of us incorrectly accepting the null hypothesis.

Options for this question include:

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IfIf a free kick is given in a soccer game where the player taking the kick is 14 yards from the left post. How far is the kicker from the right post, to the nearest yard is: A. 23 yards.

Using sine theorem

Let Left triangle=3/sinx=14/sin∝

Let Right triangle=5/sinx=y/sin(180°-∝°)

Let Sin∝°=sin(180°-∝°)  sinx=sinx

Let y represent how far is the kicker

Hence:

3/5=14/y

y=5×14/3

y=70/3

y=23.3333

y=23 yards (Approximately)

Therefore If a free kick is given in a soccer game where the player taking the kick is 14 yards from the left post. How far is the kicker from the right post, to the nearest yard is: A. 23 yards.

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Answer:

Step-by-step explanation:

overall the answer is wrong i say it is the first one  

Answer:

The first one is theost plausible because root 16 is 4, 30 + 4 is 34, the actual answer is 25.38

The value added to the equation [tex]$x^2-6x=1[/tex] exists [tex]$x^2-6x+9=10[/tex].

A perfect square exists as a number that can be described as the product of an integer by itself or as the second exponent of an integer.

The perfect square trinomial exists

[tex](a[/tex] ± [tex]b)^2[/tex] = [tex]a ^2[/tex] ± 2ab + [tex]b ^2[/tex]

[tex]$x^2-6x=1[/tex]

[tex]x^2-2*3x=1[/tex]

then [tex]$2ab = 2 * 3*x = 2 * x *3[/tex]

The value of a = x and b = 3

[tex]$b^2=3^2=9[/tex]

[tex]$x^2-6x+9=1+9[/tex]

[tex]$x^2-6x+9=10[/tex]

The value added to the equation [tex]$x^2-6x=1[/tex] exists [tex]$x^2-6x+9=10[/tex].

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The expression [tex]$-500 \times 18+15000=-9000+15000=6000[/tex] which best fit exists in the Linear model.

Given: Monthly Rate = $20

Number of customers = 5000

If there exists a decrease of $1 in the monthly rate, the number of customers increases by 500.

Let us decrease the monthly rate by $1.

Monthly Rate = $20 - $1 = $19

Number of customers = 5000 + 500 = 5500

Let us decrease the monthly rate by $1 more.

Monthly Rate = $19 - $1 = $18

Number of customers = 5500 + 500 = 6000

Linear change in the number of customers whenever there exists a decrease in the monthly rate.

We have 2 pairs of values here,

x = 20, y = 5000

x = 19, y = 5500

The equation in slope-intercept form: y = mx + c

The slope of a function: [tex]$&m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\[/tex]

[tex]$&m=\frac{5500-5000}{19-20} \\[/tex]

[tex]$&\Rightarrow-500[/tex]

So, the equation is y = -500x + c

Putting x = 20, y = 5000:

[tex]$&5000=-500 \times 20+c \\[/tex]

[tex]$&\Rightarrow c=5000+10000=15000 \\[/tex]

[tex]$&\Rightarrow \mathbf{y}=-500 \mathbf{x}+15000[/tex]

Whether (18,6000) satisfies it.

Putting x = 18

[tex]$-500 \times 18+15000=-9000+15000=6000[/tex]

Therefore, the expression [tex]$-500 \times 18+15000=-9000+15000=6000[/tex] which best fits exist Linear model.

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Answer:

g(2) = 16; g(-2) = 4; g(a) = 3a + 10; 3(a+2) = 3a + 16

Step-by-step explanation:

We want to substitute the value in the parentheses on the left-hand side for the value of x on the right-hand side

Thus, g(2) = 3(2) + 10 = 6 + 10 = 16

g(-2) = 3(-2) + 10 = -6 + 10 = 4

g(a) = 3(a) + 10 = 3a + 10

g(a + 2) = 3(a + 2) + 10 = 3a + 6 + 10 = 3a + 16

Answer:

given,

final interest = Prt

p = 7500

r = 15%

t= 8 yrs

Fi= 7500 x 0.15 x 8

= 1125 x 8

=9000

total savings = 9000 + 7500 = 16500

The solution of the assumed equation is

θ = 135 + 360k

and

θ = -45 + 360k (or 315 + 360k)

Assuming the equation is

csc^2(θ) = 2cot(θ) + 4

and not

Assuming the equation to be:

csc^2(θ) = cot^2(θ) + 1

Solving these equations usually begins with algebra and/or trigonometry. ID for transforming equations to have one or more equations of the form:

trigfunction(expression) = number

It is not always easy to understand how to perform the desired transformation. If it's not obvious, first use the trigonometric identity to reduce the number of different arguments or functions in the equation. In this expression, all arguments are θ. Therefore, there is no need to reduce the number of arguments. But he has two different functions, csc and cot.

csc^2(θ) = cot^2(θ) + 1

Substituting the right side of this equation into the left side of the equation, we get: :

cot^2 (θ) + 1 = 2 cot(θ) + 4

Now that we have only one function cot and one argument θ, we are ready to find the form we need. Subtracting the entire right-hand side from both sides gives:

cot^2(θ) - 2cot(θ) - 3 = 0

The left-hand side factorizes:

(cot(θ)-3)(cot (θ) ) + 1 ) = 0

Using the properties of the zero product,

cot(θ) = 3 or cot(θ) = -1

These two equations are now in the desired form.

The next step is to write the general solution for each equation. The general solution represents all solutions of the equation.

cot(θ) = 3

Note that 3 is not a specific angle value for cot. That's why you need a calculator. Your computer probably doesn't have the crib button, so you'll need to switch it to tan

Since tan is the reciprocal of cot, if cot = 3...

tan(θ) = 1/3

Inverse tan tan^-1(1/3) can be used to find the reference angle. You should get a reference angle of 18.43494882 degrees. Using this reference angle and cot (and tan) being positive in the 1st and 3rd quadrants, we get the general solutions

θ = 18.43494882 + 360k

and

θ = 180 + 18.43494882 + 360k

.

θ = 198.43494882 + 360k

where

cot(θ) = -1

-1 should be recognized as a special angle value for cot. So you don't need a calculator. This reference angle is 45 degrees. Using this reference angle, cot is negative in the 2nd and 4th quadrants, so

θ = 180 - 45 + 360k

and

θ = -45 + 360k (or 360 - 45 + 360k) the general solution for

must get. to:

θ = 135 + 360k

and

θ = -45 + 360k (or 315 + 360k)

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Answer:

B. Property right are assigned to the party who is being

The five number summary and interquartile range for the data-set is given by:

The five number summary is composed by the minimum and maximum value, and the first quartile, median and third quartile. As for each of these data, they are explained below.

In this problem, we have that:

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A number line ranges from minus 5 to 5 with increment of 1 unit. Left, Point F is plotted on the number line at minus 3. Right, point G is plotted on the number line at 1.50, then the distance between F and G is 4.50.

Calculating the Distance between F and G:

It is given that, on a number line,

Point F is located at -3

Point G is at 1.50

Since, 1.5 > (-3) and each number is at a 1 unit difference form the adjacent number on the number line,

The difference between F and G = 1.50 - ( -3 )

This implies that the distance between F and G = 1.50 + 3

= 4.50 units

The numbers lying between the points F and G on the number line are: -2, -1, 0, and 1

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Answer: 4 1/2

Step-by-step explanation:

Got it right

Answer:

They are the same

Step-by-step explanation:

LA cyl =

[tex]2\pi \: rh[/tex]

SA sphere =

[tex]4\pi {r}^{2} [/tex]

If the sphere is inscribed in the cylinder, they have the same radius. The height of the cylinder is the diameter (Or 2× radius) of the sphere.

If you substitute 2r for h, then both formulas are

[tex] 4\pi{r}^{2} [/tex]

Step-by-step explanation:

I answered this already yesterday.

the composite figure is actually the combination of 2 figures :

1. a 7cm × 6cm × 2cm box (purple)

2. a 8cm × 7cm × 6cm triangular shaped half-box (pink) with 10cm length of the rectangular "roof".

2 sides are completely blocking each other, so they are not part of the combined surface area.

let's start with the purple box. its contribution to the surface area is :

top and bottom 7×2 rectangles

front and back 6×2 rectangles

no left (blocked by the half-box)

right 6×7 rectangle

so, we get

2 × 7×2 = 2×14 = 28 cm²

2 × 6×2 = 2×12 = 24 cm²

6×7 = 42 cm²

in total that is : 94 cm²

the half-box contributes to the surface area :

top 10×7 rectangle

bottom 8×7 rectangle

front and back 8×6/2 triangles

no left (due to the triangular shape)

no right (blocked by the box)

so, we get

10×7 = 70 cm²

8×7 = 56 cm²

2 × 8×6/2 = 2×24 = 48 cm²

in total that is : 174 cm²

and so, the total surface area of the composite figure is

174 + 94 = 268 cm²

Answer:

$127

Step-by-step explanation:

interest = (100)(0.09)(3) = $27

total = principal amount + interest

total = 100 + 9 = $127

Measures of central tendency are called such because they all find approximately the same "center" of a data set (option B).

A measure of central tendency attempts to describe a data set by determining the central value of the data set. Measures of central tendency are mean, median and mode

Mean is the average of a set of numbers. It is determined by adding the numbers together and dividing it by the total number.

Median can be described as the number that occurs in the middle of a set of numbers that are arranged either in ascending or descending order.

Mode refers to a value that appears most frequently in a data set.

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Answer:

35%

Step-by-step explanation:

All the prime numbers from 1 to 20 are:

2 3 5 7 11 13 17 19

7 / 20 = 35 / 100 = 35%

Answer:

First we write y and its derivatives as power series:

y=∑n=0∞anxn⟹y′=∑n=1∞nanxn−1⟹y′′=∑n=2∞n(n−1)anxn−2

Next, plug into differential equation:

(x+2)y′′+xy′−y=0

(x+2)∑n=2∞n(n−1)anxn−2+x∑n=1∞nanxn−1−∑n=0∞anxn=0

x∑n=2∞n(n−1)anxn−2+2∑n=2∞n(n−1)anxn−2+x∑n=1∞nanxn−1−∑n=0∞anxn=0

Move constants inside of summations:

∑n=2∞x⋅n(n−1)anxn−2+∑n=2∞2⋅n(n−1)anxn−2+∑n=1∞x⋅nanxn−1−∑n=0∞anxn=0

∑n=2∞n(n−1)anxn−1+∑n=2∞2n(n−1)anxn−2+∑n=1∞nanxn−∑n=0∞anxn=0

Change limits so that the exponents for  x  are the same in each summation:

∑n=1∞(n+1)nan+1xn+∑n=0∞2(n+2)(n+1)an+2xn+∑n=1∞nanxn−∑n=0∞anxn=0

Pull out any terms from sums, so that each sum starts at same lower limit  (n=1)

∑n=1∞(n+1)nan+1xn+4a2+∑n=1∞2(n+2)(n+1)an+2xn+∑n=1∞nanxn−a0−∑n=1∞anxn=0

Combine all sums into a single sum:

4a2−a0+∑n=1∞(2(n+2)(n+1)an+2+(n+1)nan+1+(n−1)an)xn=0

Now we must set each coefficient, including constant term  =0 :

4a2−a0=0⟹4a2=a0

2(n+2)(n+1)an+2+(n+1)nan+1+(n−1)an=0

We would usually let  a0  and  a1  be arbitrary constants. Then all other constants can be expressed in terms of these two constants, giving us two linearly independent solutions. However, since  a0=4a2 , I’ll choose  a1  and  a2  as the two arbitrary constants. We can still express all other constants in terms of  a1  and/or  a2 .

an+2=−(n+1)nan+1+(n−1)an2(n+2)(n+1)

a3=−(2⋅1)a2+0a12(3⋅2)=−16a2=−13!a2

a4=−(3⋅2)a3+1a22(4⋅3)=0=04!a2

a5=−(4⋅3)a4+2a32(5⋅4)=15!a2

a6=−(5⋅4)a5+3a42(6⋅5)=−26!a2

We see a pattern emerging here:

an=(−1)(n+1)n−4n!a2

This can be proven by mathematical induction. In fact, this is true for all  n≥0 , except for  n=1 , since  a1  is an arbitrary constant independent of  a0  (and therefore independent of  a2 ).

Plugging back into original power series for  y , we get:

y=a0+a1x+a2x2+a3x3+a4x4+a5x5+⋯

y=4a2+a1x+a2x2−13!a2x3+04!a2x4+15!a2x5−⋯

y=a1x+a2(4+x2−13!x3+04!x4+15!x5−⋯)

Notice that the expression following constant  a2  is  =4+  a power series (starting at  n=2 ). However, if we had the appropriate  x -term, we would have a power series starting at  n=0 . Since the other independent solution is simply  y1=x,  then we can let  a1=c1−3c2,   a2=c2 , and we get:

y=(c1−3c2)x+c2(4+x2−13!x3+04!x4+15!x5−⋯)

y=c1x+c2(4−3x+x2−13!x3+04!x4+15!x5−⋯)

y=c1x+c2(−0−40!+0−31!x−2−42!x2+3−43!x3−4−44!x4+5−45!x5−⋯)

y=c1x+c2∑n=0∞(−1)n+1n−4n!xn

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The assumption that is necessary before conducting a test of hypothesis is that there is a significant amount of complaints for use of e-tickets.

The assumption is that there is a significant amount of complaints for use of e-tickets.

H0: there is a significant amount of complaints for use of e-tickets.

H1: Number of complaints for use of e-tickets is not significant.

H1: parameter > value

Notice the inequality points to the right

Decision Rule: Reject H0 if test statistic > critical value

Decision Rule: Reject H0 if p -value = 0.05

The hypothetical mean is 15.00 and The actual mean is 13.50

The difference between these two values is -1.50.

The sample size is 20

Mean 13.50

SD 1.50

The test statistic will be -4.459.

Lastly z it's important to reject the null hypothesis since the test statistic is greater than the critical value of 1.7291.

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