what is relative density of a substance​

The magnitude (in N) of the force she must exert on the wrench is 150.1 N.

The force exerted by the wrench is calculated using torque formula as follows;

torque, τ = F x r x sinθ

where;

F =  τ /(r sinθ)

F = (39) / (0.3 sin 60)

F = 150.1 N

Thus, the magnitude (in N) of the force she must exert on the wrench is 150.1 N.

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Answer:

24.2 m/s

Explanation:

Mass is irrelevant in this situation....

Displacement:  ( to find time)

 x = xo + vo t - 1/2 at^2

 30= 0   + 0  - 1/2 (9.8)t^2

              t = 2.47 seconds

Velocity:

vf = a t   = 9.8 (2.473)  = 24.2 m/s

Answer:Using the Nielsen form, determine the equation of motion for a mass m connected to a spring of constant k. Exercise 3.2 Using the

Explanation:

43.DB(decibels)

⇉ Unit conversion

4.3(bels)

4.951NP

4.3(decades)

14.28(octaves)

Interpretations

⇉ Power quantity level

Basic unit dimensions

⇉ ( logarithmic quantity ).

They provided the intensity in decibels for the problem, but they are unsure by what factor to increase it (I) to make the sound loud enough for the elderly person to hear.

Neglect f entirely.

The following equation must be used to convert decibels (dB) to I:

I=(10^(dB/10))*10^-12

Divide the elder person's dB by the younger person's dB after doing this for each dB.

1.8372093023.

Decibels are used to measure sound (dB). A motorcycle engine operating is roughly 95 dB louder than regular conversation, which is around 60 dB louder than a whisper. Your hearing may begin to be harmed if exposed to noise over 70 dB for an extended period of time. Your ears can suffer instant damage from loud noise above 120 dB.

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(a) The position where particle Q and P meet is 68.75 m.

(b) The velocity with which particle Q is shot is 15 m/s.

The time elapsed before the two particles meet is calculated as follows;

Distance Q - Distance P = Distance between them

Trise = (V - V₀)/g

Trise = (0 - 40) / -10

Trise = 4.0 s

Hmax = V₀t + 0.5gt²

Hmax = 40 x 4 - (0.5)(10)4²

Hmax = 80 m.

h = Hmax - (V² - V₀²)/2g

h = 80 - ((15)²- 0) / 20

h = 68.75 m.

Thus, the position where particle Q and P meet is 68.75 m

Tfall = (V - V₀)/g = (15-0) / 10

Tfall = 1.5 s

Fall time. = Rise time  for Q.

h = V₀t + 0.5gt²

h = 80 - 68.75

h = 11.25

V₀ x 1.5 - 5(1.5)² = 11.25

V₀ x 1.5 - 11.25 = 11.25

V₀ x 1.5 = 22.5

V₀ = 22.5 / 1.5

V₀ = 15 m/s

Thus, the velocity with which particle Q is shot is 15 m/s.

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(a) The speeds of the tips of both rotors; main rotor 178.3 m/s and  tail rotor 218.4 m/s.

(b) The speed of the main rotor is 0.52 speed of sound, and the speed of the tail rotor is 0.64 speed of sound.

v = ωr

where;

v(main rotor) = (444 rev/min x 2π rad x 1 min/60s) x (0.5 x 7.67 m)

v(main rotor) = 178.3 m/s

v(tail rotor) = (4,130 rev/min x 2π rad x 1 min/60s) x (0.5 x 1.01 m)

v(tail rotor) = 218.4 m/s

% speed (main motor) = 178.3/343 = 0.52 = 52 %

% speed (tail motor) = 218.4/343 = 0.64 = 64 %

Thus, the speed of the main rotor is 0.52 speed of sound, and the speed of the tail rotor is 0.64 speed of sound.

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Answer:

The visible light frequency is 400 THz to 700 THz, approximately. A THz is a Terahertz, which is a unit of frequency equal to one trillion Hertz.

The angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.046 rad/s.

The angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is calculated as follows;

a = v²/r

v² = ar

(ωr)² = ar

ω²r² = ar

ω²r = a

ω² = a/r

ω = √(a/r)

where;

ω = √(g/r)

ω =  √(9.8/4554.4)

ω = 0.046 rad/s

Thus, the angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.046 rad/s.

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Answer:

Electromagnetic waves

wind (b), also some others are:

- steam

- gas

- liquid fules

a. The magnitude of the tension, T₂ in the vertical rope on the left end is T₂ = 655.62 N

b. The magnitude of the tension in the rope in the right end is T₁ = 530.4 N

c. The magnitude of the tension in the horizontal rope on the left end, T₃ is T₃ = 406.3 N

Tension force refers to a pulling force that is exerted by a string or cable about an axis.

a. The magnitude of the tension, T₂ in the vertical rope on the left end is given as follows:

Taking moment about the vertical axis

T₂ = 30.23 * 9.81 + 700 - T₁ * Sin40°

Solving for T₁ by taking the left end as the pivot;

T₁ Sin 40° * 2.00 = 700 * 0.55 + (30.23 * 9.81) * 1.0

T₁ * 1.285 = 681.5563

T₁ = 530.4 N

Therefore;

T₂ = 30.23 * 9.81 + 700 - 530.4 * Sin 40°

T₂ = 655.62 N

b. From calculation, the magnitude of the tension in the rope in the right end is T₁.

T₁ = 530.4 N

c. The magnitude of the tension in the horizontal rope on the left end, T₃ is determined thus:

Taking moments about the left end in the horizontal direction;

T₃ = T₁ * cos 40°

T₃ =  530.4 N * cos 40°

T₃ = 406.3 N

In conclusion, the tension at the rope in the various ends is determined by taking moments about the left end.

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⇒ Acids taste sour, react with metals, react with carbonates, and turn blue litmus paper red. Bases taste bitter, feel slippery, do not react with carbonates and turn red litmus paper blue.

The study of acids and bases is crucial to chemistry. The Lewis acid/base motif, which broadens the concept of an acid and base beyond H+ and OH- ions, is one of the most relevant theories.

Acids are ionic compounds, which means they have a positive or negative charge. In water, these ionic compounds separate to create hydrogen ions, or H+.

The quantity of H+ ions in the solution determines how strong an acid is. Acid is stronger the more H+ there is. Bases are ionic substances that separate in water to produce the negatively charged hydroxide ion (OH-). The quantity of Hydroxide ions in a base determines its strength (OH-). The strength of the base increases with OH- ion concentration.

Hope this helps,

- Eddie.

The coefficient of kinetic friction on the horizontal surface, μ = 0.39.

The work done on the package by friction as it slides down the circular arc from A to B, W = -4.176.

Frictional force is the force which opposes the motion of an object over another.

Frictional force acts at the surface of contact of the objects.

The frictional force, F is related to the coefficient of kinetic friction on the horizontal surface, μ, and the normal reaction or weight, mg,  of the package as follows:

F = μmg

Work done against friction, W = F * d

W = μmgd

The Kinetic energy of the package is equal to the work done against friction.

Kinetic energy of the package = mv²/2

μmgd = mv²/2

μ = v²/2gd

μ = 4.8²/(2 * 9.81 * 3)

μ = 0.39

b. Work done on the package by friction as it slides down the circular arc from A to B is given as follows:

W = mv²/2 - mgh

W = v²/2 - gh

W = 4.8²/2 - 9.81 * 1.6

W = -4.176

In conclusion, the work done by friction is lost in the form of heat.

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The workout of Peter that involves jumping rope, doing push-ups, kicking a ball through a pattern of cones, doing sit-ups, and then repeats the cycle is an example of circuit training.

A workout is any activity that requires much physical or mental effort, or produces strain.

There are several approaches that can be employed to achieve workout procedures and they are as follows:

Circuit training is a combination of six or more exercises performed with short recovery periods between them for either a set number of repetitions or a prescribed amount of time.

On the other hand, interval training is similar to circuit training but differs in the sense that a period of rest is allowed in between the exercises.

Therefore, the workout of Peter that involves jumping rope, doing push-ups, kicking a ball through a pattern of cones, doing sit-ups, and then repeats the cycle is an example of circuit training.

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(a) The angular speed of the human centrifuge is 4.7 rad/s.

(b) The linear speed (in m/s)  a person in the centrifuge would have at this is 18.8 m/s.

a = ω²r

where;

ω = √(a/r)

ω = √(9g/r)

ω = √(9 x 9.8 / 4)

ω = 4.7 rad/s

v = ωr

where;

v = (4.7 rad/s) x 4 m

v = 18.8 m/s

Thus, the angular speed of the human centrifuge is 4.7 rad/s. The linear speed (in m/s)  a person in the centrifuge would have at this is 18.8 m/s.

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Answer:

The four inner planets have shorter orbits, slower spin, no rings, and they are made of rock and metal. The four outer planets have longer orbits and spins, a composition of gases and liquids, numerous moons, and rings. The outer planets are made of hydrogen and helium, so they are called gas giants.

(a) The speed of the center of mass of the spherical shell when it is at the bottom of the bowl is 3.1 m/s when the radius is 80 cm.

(b) The speed of the center of mass of the spherical shell when it is at the bottom of the bowl is 1.1 m/s when the radius is 10 cm.

The speed of the shell at the bottom of the bowl is calculated by applying the principle of conservation of energy.

K.E(rot) + K.E(trans) = P.E

where;

¹/₂mv² + ¹/₂Iω² = mgh

where;

¹/₂mv² + ¹/₂(²/₃Mr²)(v/r)² = mgh

¹/₂v² + ¹/₂(²/₃r²)(v²/r²) = gh

¹/₂v² + ¹/₂(²/₃)(v²) = gh

¹/₂v² + ¹/₃v² = gh

⁵/₆v² = gh

v² = 6gh/5

v = √(6gh/5)

Let the vertical height from the edge of bowl to the bottom , h = R = 80 cm

v = √(6 x 9.8 x 0.8 /5)

v = 3.1 m/s

v = √(6gh/5)

v = √(6 x 9.8 x 0.1 /5)

v = 1.1 m/s

Thus, the speed of the center of mass of the spherical shell when it is at the bottom of the bowl is 3.1 m/s when the radius is 80 cm.

The speed of the center of mass of the spherical shell when it is at the bottom of the bowl is 1.1 m/s when the radius is 10 cm.

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Q.1 Calculate the different accelerations from the graph

At initial point (let O) the velocity was 0 m/s to reach point A when the velocity was 5 m/s it took nearly 3 seconds as we all know that acceleration is nothing but the change in velocity per unit time

[tex]a \: = \frac{dv}{t} [/tex]

[tex]a = \frac{5 - 0}{3} = \frac{5}{3} \: m/ {s}^{2} [/tex]

Similarly from point A to point B the acceleration was

[tex]a = \frac{dv}{t} = \frac{7 - 5}{3} = \frac{2}{3} m/s²[/tex]

From Point B to C the velocity was constant so the acceleration at that point would be zero.

in the same way we can calculate acceleration for rest other points.

Q.2 Explain why a Merry-Go-Round and a Ferris Wheel have a constant acceleration when they are moving?

We all know that Velocity is nothing but the speed with direction. Merry Go Round and a Ferris Wheel has constant speed but dynamic direction due to which the magnitude of velocity at every point differs with different sign hence it have a constant acceleration.

Answer:

Dynamics is just a nice word used in physics denoting a branch of physics, related to the study of forces. Usually these forces are not in mechanical equilibrium, else the branch would be statics.

4. a poor insulator

If rest other things are kept constant or unchanged then a good conductor can be termed as a poor insulator.

Answer:

4 conductors and insulators are opposites of each other.

Explanation:

The work that the man does is the scalar product of the force applied by the man and the horizontal displacement of the bag.

In Physics, we define the work done as the product of the of force and distance. Hence, we generally define the work done as that which occurs when the force applied moves a distance in the direction of the force. This implies that the work done is not a vector but a  scalar quantity.

In relation to the man and the bag, the work done is the product of the force that the man applies and the displacement of the bag. As such, the reason for the tiredness of the man is that the internal energy that he possesses is transferred to moving the bag.

Thus, the work that the man does is the scalar product of the force applied by the man and the horizontal displacement of the bag.

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Answer:

The second universal law, the law of vibration, posits that everything (every atom, object, and living thing) is in constant motion, vibrating at a specific frequency.

Explanation:

Please mark brainly

The second universal law defines this.

The second universal law, also known as the Law of Vibration, The Law of Vibration states that everything in the universe is in a constant state of movement. We refer to these movements as vibration, and the speed or rate at which something vibrates is called its frequency. The only difference between one object and another is its vibration rate.

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Answer:

Approximately [tex]28^{\circ}[/tex].

Explanation:

The refractive index of the air [tex]n_{\text{air}}[/tex] is approximately [tex]1.00[/tex].

Let [tex]n_\text{glass}[/tex] denote the refractive index of the glass block, and let [tex]\theta _{\text{glass}}[/tex] denote the angle of refraction in the glass. Let [tex]\theta_\text{air}[/tex] denote the angle at which the light enters the glass block from the air.

By Snell's Law:

[tex]n_{\text{glass}} \, \sin(\theta_{\text{glass}}) = n_{\text{air}} \, \sin(\theta_{\text{air}})[/tex].

Rearrange the Snell's Law equation to obtain:

[tex]\begin{aligned} \sin(\theta_{\text{glass}}) &= \frac{n_{\text{air}} \, \sin(\theta_{\text{air}})}{n_{\text{glass}}} \\ &= \frac{(1.00)\, (\sin(45^{\circ}))}{1.50} \\ &\approx 0.471\end{aligned}[/tex].

Hence:

[tex]\begin{aligned} \theta_{\text{glass}} &= \arcsin (0.471) \approx 28^{\circ}\end{aligned}[/tex].

In other words, the angle of refraction in the glass would be approximately [tex]28^{\circ}[/tex].

The potential energy (P.E) of X at r is less than P.E at s.

The total energy (T.E) of Y is less than total energy (T.E) of X.

The PE of Y at v is greater than the PE of Z at c.

The speed of Y at i is .greater than that at v.

The kinetic energy (KE) of z at u is less than that at n.

The PE of Y at s is less than the PE of X at c.

The PE of X at c is less than the PE of Z at c.

The PE of X at c is less than the PE of Z at c.

The potential energy (P.E) of X at r is less than P.E at s due to greater displacement at s.

The total energy (T.E) of Y is less than total energy (T.E) of X because X has greater displacement from the planet.

The PE of Y at v is greater than the PE of Z at c due to greater displacement at v.

The speed of Y at i is .greater than that at v because i is closer to the planet than v.

The kinetic energy (KE) of z at u is less than that at n because n is closer to the planet and will have greater velocity.

The PE of Y at s is less than the PE of X at c, because position c has greater displacement.

The TE of Z is greater than the TE of X due to greater displacement of Z from the planet.

The PE of X at c is less than the PE of Z at c due to greater displacement of Z from c.

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a) The wheel of the car decelerates at an angular acceleration of - 0.577 radians per square second.

b) The wheel of the car requires a time of 51.149 seconds to stop.

c) The wheel of the car travels a distance of 683.225 meters before stopping.

a) In this case we have a rotating wheel that decelerates at constant rate. The angular acceleration, in radians per square second, of the tires is determined by the following formula:

α = [ω'² - ω²] / (2 · θ)      (1)

Where:

The initial and final angular velocities, in radians per second, are now determined:

ω' = v' / R      (2)

ω = v / R      (3)

Where:

If we know that R = 0.80 m, v = 23.611 m / s, v' = 15.556 m / s and θ ≈ 427.257 radians, then the angular acceleration of the tire is:

ω' = (15.556 m / s) / (0.80 m)

ω' = 19.445 rad / s

ω = (23.611 m / s) / (0.80 m)

ω = 29.513 rad / s

α = [(19.445 rad / s)² - (29.513 rad / s)²] / [2 · (427.257 rad)]

α = - 0.577 rad / s²

b) The time required to stop the car, in seconds, is determined by the following expression:

t = (ω' - ω) / α     (4)

t = (0 rad / s - 29.513 rad / s) / (- 0.577 rad / s²)

t = 51.149 s.

c) First, we find the change in angular displacement of the tire:

θ = [ω'² - ω²] / (2 · α)      (5)

θ = [(0 rad / s)² - (29.513 rad / s)²] / [2 · (- 0.577 rad / s²)]

θ = 754.781 rad

Lastly, the distance traveled by the vehicle is:

s = R · θ     (6)

s = (0.80 m) · (754.781 rad)

s = 683.825 m

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A piston-work cylinder device with a set of stops initially contains 0.6 kg of steam at 1.0 MPa and 400°C. The location of the stops corresponds to 40 percent of the initial volume. Now the steam is cooled. compression work is 44.32 KJ,

The amount of labor put into the piston to cause its reciprocating motion is known as the piston work. It is calculated by multiplying the piston's displacement by the net force.

An expanding gas cylinder's force output is transferred by pistons to the crankshaft, which then drives the flywheel's rotation. A reciprocating engine is a device like this.

Piston work is the effort made by the piston to make its reciprocating motion. The piston's displacement is calculated by multiplying it by the net force.

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Radar - measuring distances in our solar system

Parallax - measuring distances to nearby stars

Cepheids - measuring distances in our Galaxy and to nearby galaxies

Supernovae - measuring distances to other galaxies

Different techniques which can be used by the astronomers to determine the distances to the stars and galaxies include Radar, Parallax, Cepheids, and Supernova.

The distances to the nearby stars are precisely and accurately determined using the different techniques such as parallax. When a celestial body is seen from a different, widely separated viewing point, its position with respect to the more distant background stars or galaxies varies. This angular difference is known as parallax.

Radar is the measuring of the distances in the solar system.

Parallax is the measuring of distances to the nearby stars.

Cepheids is the measuring of distances in Galaxy and to nearby galaxies.

Supernovae is the measuring of distances to the other galaxies.

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When light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.

To find the answer, we have to know about the rules followed by drawing ray-diagram.

Thus, we can conclude that, when light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.

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Solids have very small intermolecular space and when heated, do not expand as per the container volume. Basically, their expansion is not good.

Liquids, on the other hand, have a definite volume and their expansion is ideal. Also, they fill the container only to the desired level, unlike gases.

In the left-hand rule, the field is represented by the forefinger and it is perpendicular to the motion.

A force perpendicular to the field's direction and the direction of the current flow is experienced by a current-carrying conductor when it is exposed to an external magnetic field. According to Fleming's Left Hand Rule, if the thumb, forefinger, and middle finger are arranged in a straight line on the left hand, the thumb will point in the direction of the force experienced by the conductor, and the forefinger will point in the direction of the magnetic field, and the middle finger will point in the direction of the electric current. This rule is employed to determine the magnetic force's direction within an electric motor.

Fleming’s Left-Hand Rule are essential rules applicable in magnetism and electromagnetism. They were created by John Ambrose Fleming in the late 19th century as an easy method of determining the direction of motion in an electric motor.

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