Using the graph as your guide, complete the following statement.
The discriminant of the function is

The volume of the rectangular prism aquarium = 17 1/16 ft.

Volume of a rectangular prism = (l)(w)(h), where:

The aquarium is a rectangular prism. Its dimensions are given as:

Length (l) = 3 1/4 ft

Width (w) = 3 ft

Height (h) = 1 3/4 ft

Substitute

Volume of the rectangular prism aquarium = (3 1/4)(3)(1 3/4)

Volume of the rectangular prism aquarium = (13/4)(3)(7/4)

Volume of the rectangular prism aquarium = (13 × 3 × 7)/(4 × 4)

Volume of the rectangular prism aquarium = (273)/(16)

Volume of the rectangular prism aquarium = 17 1/16 ft.

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Answer:

  (f•g)(x) = 4x² -7x -11

Step-by-step explanation:

The product of the two functions is the product of their respective definitions.

(f•g)(x) = f(x)•g(x) = (x+1)•(4x -11)

  = x(4x -11) +1(4x -11) . . . . . use the distributive property

  = 4x² -11x +4x -11 . . . . . . . and again

(f•g)(x) = 4x² -7x -11 . . . . . collect terms

Answer:

1) log7 (5*8)= log7(40)

2) log2(11) -log2(9)=log2(11/9)

3)2log9 2=log9(2^2)

In order to compare and contrast the steps of two different constructions using a compass, we simply take a note of the different steps followed in both the constructions.

How to compare and contrast the steps?

For both the constructions, observe the corresponding steps steps that have been performed in order.

Then, note down what similarity you find while constructing the two different constructions in the first step.

Once you know the the similarities, you can further trace down the differences in the procedure of the two constructions by observing the first step. This is how you can compare and contrast the first step of two different constructions using a compass.

This process can be followed for all the steps for comparing and contrasting two different constructions.

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The sum of normally distributed random variables is also a normally distributed random variable.

Given [tex]n[/tex] random variables with [tex]X_i\sim\mathrm{Normal}(\mu_i,\sigma_i^2)[/tex], their sum is

[tex]\displaystyle\sum_{i=1}^n X_i \sim \mathrm{Normal}\left(\sum_{i=1}^n \mu_i, \sum_{i=1}^n \sigma_i^2\right)[/tex]

i.e. normally distributed with mean and variance equal to the sums of the means and variances of the [tex]X_i[/tex].

In this case, each of [tex]X_1,X_2,X_3[/tex] are normally distributed with [tex]\mu=4[/tex] and [tex]\sigma^2[/tex] = ... I'm not sure what you meant for the variance, so I'll keep it symbolic. Then

[tex]V = X_1+X_2+X_3 \sim \mathrm{Normal}(12, 3\sigma^2)[/tex]

The linear equations are y - 25 = 0.89(x - 20) and y  = 0.89x + 7.2

The complete question is added as an attachment

The two points from the graph are (20, 25) and (38, 41)

The slope of the line is calculated using

m = (y2 - y1)/(x2 - x1)

Substitute the known values in the above equation

m = (41 - 25)/(38 - 20)

Evaluate

m =0.89

This is calculated as:

y - y1 = m(x - x1)

Substitute the known values in the above equation

y - 25 = 0.89 * (x - 20)

Evaluate

y - 25 = 0.89(x - 20)

We have:

y - 25 = 0.89(x - 20)

Expand

y - 25 = 0.89x - 17.8

Add 25 to both sides

y  = 0.89x + 7.2

Hence, the linear equations are y - 25 = 0.89(x - 20) and y  = 0.89x + 7.2

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Mike's speed driving to his office is 45 miles/hour, which is 10 miles less than his average speed driving back.

Speed is an average value of a scalar measurement of the distance covered over the time taken.

Speed is the equation,  r = d/Δt, where r = speed or rate, d = distance, and Δt is the change in time.

Thus, when the distance covered by a traveler is divided by the time consumed, one can determine the average speed for the travel.

Distance from Mike's home to his office = 40 miles

Distance to and from = 80 miles (40 miles x 2)

Hours covered from office = 1.6 hours

Average speed for the trip = 50 miles/hour (80/1.6)

Average speed to return home = 55 miles/hour

Average speed to office = 45 miles/hour (55 - 10)

Thus, Mike's speed of driving to his office is 45 miles/hour.

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What is Mike's speed driving to his office?

Answer:

A

Step-by-step explanation:

given the points

(0, 0 ) , (2, 4 ) , (4, 8 )

note that the y- coordinate is twice the value of the x- coordinate , so

y = 2x

Your answers seem to be on the right track. These online homework apps can be picky about the answer they accept, though.

Given [tex]f(x) = x^4 - 2x^2 + 3[/tex], we have derivative

[tex]f'(x) = 4x^3 - 4x = 4x (x^2 - 1) = 4x (x - 1) (x + 1)[/tex]

with critical points when [tex]f'(x) = 0[/tex]; this happens when [tex]x=0[/tex] or [tex]x=\pm1[/tex].

We also have second derivative

[tex]f''(x) = 12x^2 - 4 = 12 \left(x^2-\dfrac13\right) = 12 \left(x - \dfrac1{\sqrt3}\right) \left(x + \dfrac1{\sqrt3}\right)[/tex]

with (possible) inflection points when [tex]x=\pm\frac1{\sqrt3}=\pm\frac{\sqrt3}3[/tex].

Intercept

If "intercept" specifically means [tex]y[/tex]-intercept, what you have is correct. Setting [tex]x=0[/tex] gives [tex]f(0) = 3[/tex], so the intercept is the point (0, 3).

They could also be expecting the [tex]x[/tex]-intercepts, in which case we set [tex]f(x)=0[/tex] and solve for [tex]x[/tex]. However, we have

[tex]x^4 - 2x^2 + 3 = \left(x^2 - 1\right)^2 + 2[/tex]

and

[tex]x^2-1\ge-1 \implies (x^2-1)^2 \ge (-1)^2 = 1 \implies x^4-2x^2+3 \ge 2[/tex]

so there are no [tex]x[/tex]-intercepts to worry about.

Relative minima/maxima

Check the sign of the second derivative at each critical point.

[tex]f''(-1) = 8 > 0 \implies \text{rel. min.}[/tex]

[tex]f''(0) = -4 < 0 \implies \text{rel. max.}[/tex]

[tex]f''(1) = 8 > 0 \implies \text{rel. min.}[/tex]

So we have two relative minima at the points (-1, 2) and (1, 2), and a relative maximum at (0, 3).

Inflection points

Simply evaluate [tex]f[/tex] at each of the candidate inflection points found earlier.

[tex]f\left(-\dfrac{\sqrt3}3\right) = \dfrac{22}9[/tex]

[tex]f\left(\dfrac{\sqrt3}3\right) = \dfrac{22}9[/tex]

Answer:

93.39

Step-by-step explanation:

So the sum of exterior angles of the convex octagon is: 360 degrees

This means if we add all the equations that represent each angle, we can set it equal to 360 and solve for x

[tex](x+14) + (2x-3) + (3x+8) + (3x+16) + (2x-17) + (3x-4) + (3x-12) + (6x)[/tex]

Group like terms

[tex](x+2x+3x+3x+2x+3x+3x+6x) + (14-3+8+16-17-4-12)[/tex]

Add like terms

[tex]23x+2[/tex]

Now let's set the sum of exterior angles to 360

[tex]23x+2 = 360[/tex]

Subtract 2 from both sides

[tex]23x=358[/tex]

Divide both sides by 23

[tex]x\approx 15.565[/tex]

So by looking at all these, it appears that 6x is the highest value, given that x is positive. The way I estimated, is approximately 15.5, whenever I saw an equation like x+14, I estimated it's about 2x, since 14 is not exactly, but close to 15.5. I did this with each polynomial given. You could also manually check each one

Original equation

6x

Subsitute

6(15.565)

Simplify

[tex]93.39[/tex]

Answer:

d. (-6, 0)

Step-by-step explanation:

no explanation bc u need this quick

Answer:

All Real Numbers

Step-by-step explanation:

The domain is all the x values for a function. As this function is not restricted in any way, the domain is all real numbers. You can put any number in for x and plot it on the graph.

Answer: B

Step-by-step explanation:

The domain of a function is the set of x-values.

The value of c such that the function f is a probability density function is 2

The density function is given as:

f(x) = cxe^(−x^2) if x ≥ 0

f(x) = 0 if x < 0.

We start by integrating the function f(x)

∫f(x) = 1

This gives

∫ cxe^(−x^2) = 1

Next, we integrate the function using a graphing calculator.

From the graphing calculator, we have:

c/2 * (0 + 1) = 1

Evaluate the sum

c/2 * 1 = 1

Evaluate the product

c/2 = 1

Multiply both sides of the equation by 2

c = 2

Hence, the value of c such that the function f is a probability density function is 2

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The critical value for the given confidence level, c = 0.90 and n = 21 is [tex]t_c=1.725[/tex].

The critical value is calculated as follows:

It is given that,

confidence level c = 0.90

sample size n = 21

Then,

degree of freedom,

(d.f) = n - 1 = 21 - 1 = 20

So, from the t-distribution table,

at d.f = 20 and the confidence level 0.90, the critical value is 1.725.

I.e., [tex]t_c[/tex] = 1.725

For this, α = (1 - 0.90)/2 = 0.05

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In  triangle ABC, if m∠B = 90°, BH = AH, and the ratio of m∠A to m∠C is 1:2, then m∠BHA = 120° (C).

In the next given equilateral triangle ABC, y = 70°.

Finding m∠BHA:

In triangle ABC, it is given that,

∠B = 90°

And m∠A : m∠C = 1:2

Let us assume m∠A is x. Then, m∠C = 2x

According to the angle sum property of a triangle,

∠A + ∠B + ∠C = 180°

90° + x + 2x = 180°

90° + 3x = 180°

3x = 90°

x = 30°

⇒ In triangle ABC, ∠A = 30° and ∠C = 60°

Now, in triangle AHB, it is also given that,

BH = AH

⇒ ∠ABH = ∠A = 30°

Thus, according to the angle sum property of a triangle,

∠ABH + ∠A + ∠BHA = 180°

30° + 30° + ∠BHA = 180°

∠BHA = 180° - 60°

∠BHA = 120°

Finding y in the Second Triangle:

Since triangle ABC is equilateral,

∠A = ∠B = ∠C = 60°

∴ x + 2x + 3x = 60°

6x = 60°

x = 10°

In triangle ABD, using angle sum property of triangle,

x + ∠B +  ∠BDA = 180°

10° + 60° + ∠BDA = 180°

∠BDA = 180° - 70°

∠BDA = 110°

Now, since, ∠BDA and y are linearly adjacent  angles,

∠BDA + y = 180°

110° + y = 180°

y = 180° - 110°

y = 70°  

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The number of tiles used is 300 tiles.

According to the statement

We have given that:

The tiles are 20 cm by 30 cm. And the dark room floor is 6 meters by 3 meters.

And we have to find that the number of tiles used to prepare the dark room.

So, For this purpose we have to find the area of the room floor.

The area of the floor is 6 *3.

The area of the floor is 18 meter per square.

The area of the tile is 0.2*0.3

The area of the tile is 0.06 meter per square.

Now,

The number of tiles used is 18/0.06

The number of tiles used is 300.

So, The number of tiles used is 300 tiles.

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Answer: 7 1/16  and 1 9/16

Step-by-step explanation:  1 3/8 x 1.5 is 1 3/8 x 1 5/10  11/8 x 15/10 which is 165/80. We divide it by 5/5 to get 33/16. This as a mixed number is 2 1/16.  We add 5 to get 7 1/16.

5/8 divided by 0.4 is 5/8 divided by 2/5. We divide this by first finding the reciprocal of 2/5 which is 5/2. 5/8 x 5/2 = 25/16. This as a mixed number is 1 9/16.

We can write the integration domain as

[tex]D = \left\{(x,y) \mid -1 \le y \le 1 \text{ and } 2y-2 \le x \le -y+1\right\}[/tex]

so that the integral is

[tex]\displaystyle \iint_D -\sin(y+x) \, dA = \int_{-1}^1 \int_{2y-2}^{-y+1} -\sin(y+x) \, dx \, dy[/tex]

Compute the integral with respect to [tex]x[/tex].

[tex]\displaystyle \int_{2y-2}^{-y+1} -\sin(y+x) \, dx = \cos(y+x)\bigg|_{x=2y-2}^{x=-y+1} \\\\ ~~~~~~~~ = \cos(y+(2y-2)) - \cos(y+(-y+1)) \\\\ ~~~~~~~~ = \cos(3y-2) - \cos(1)[/tex]

Compute the remaining integral.

[tex]\displaystyle \int_{-1}^1 (\cos(3y-2) - \cos(1)) \, dy = \left(\frac13 \sin(3y-2) - \cos(1) y\right) \bigg|_{y=-1}^{y=1} \\\\ ~~~~~~~~ = \left(\frac13 \sin(3-2) - \cos(1)\right) - \left(\frac13 \sin(-3-2) + \cos(1)\right) \\\\ ~~~~~~~~ = \boxed{\frac13 \sin(1) - 2 \cos(1) + \frac13 \sin(5)}[/tex]

Considering the definition of probability, 12 of the 48 students surveyed were in favor of the new dress code.

Probability is the greater or lesser chance that a given event will occur.

In other words, the probability establishes a relationship between the number of favorable events and the total number of possible events.

Then, the probability of any event A is defined as the ratio between the number of favorable cases (number of cases in which event A may or may not occur) and the total number of possible cases. This is called Laplace's Law.

P(A)=number of favorable events÷ number of total events

In this case, you know:

Replacing in the definition of probability:

P(A)=225 students÷ 900 students

Solving:

P(A)= 0.25

Expressed as a percentage:

P(A)= 25%

In this case, you know:

Replacing in the definition of probability:

0.25=students in favor of the new dress code÷ 48 students

Solving:

students in favor of the new dress code= 0.25×48 students

students in favor of the new dress code= 12 students

Finally, 12 of the 48 students surveyed were in favor of the new dress code.

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Answer: 60

Step-by-step explanation:

Almost everything in this picture is irrelevant to finding the measure of x.

x = 180 - 90 - 30 = 60

Put the equation in standard linear form.

[tex]x'(t) + \dfrac{x(t)}{t + 5} = 5e^{5t}[/tex]

Find the integrating factor.

[tex]\mu = \exp\left(\displaystyle \int \frac{dt}{t+5}\right) = e^{\ln|t+5|} = t+5[/tex]

Multiply both sides by [tex]\mu[/tex].

[tex](t+5) x'(t) + x(t) = 5(t+5)e^{5t}[/tex]

Now the left side the derivative of a product,

[tex]\bigg((t+5) x(t)\bigg)' = 5(t+5)e^{5t}[/tex]

Integrate both sides.

[tex](t+5) x(t) = \displaystyle 5 \int (t+5) e^{5t} \, dt[/tex]

On the right side, integrate by parts.

[tex](t+5) x(t) = \dfrac15 (5t+24) e^{5t} + C[/tex]

Solve for [tex]x(t)[/tex].

[tex]\boxed{x(t) = \dfrac{5t+24}{5t+25} e^{5t} + \dfrac C{t+5}}[/tex]

Answer:

The original number is 72.

Step-by-step explanation:

Let the number by

[A][B]

The reverse number is

[B][A]

Original number:

A = B + 5

[A][B] - 2[B][A] = [A][B]/4

10A + B - 20B - 2A = (10A + B)/4

8A - 19B = (10A + B)/4

32A - 76B = 10A + B

22A - 77B = 0

22(B + 5) - 77B = 0

22B + 110 - 77B = 0

-55B = -110

B = 2

A = B + 5 = 2 + 5 = 7

The original number is 72.

The reverse is 27.

Let's check.

"the tens digit of a 2 digit number is 5 greater than the units digit"

7 is 5 greater than 2,so 72 looks good so far.

"if you subtract twice the reverse number the result is one fourth the original"

The reverse number is 27. Twice 27 is 2 × 27 = 54.

Subtract 54 from 72: 72 - 54 = 18

18 is 1/4 of 72. It works.

Answer: the original number is 72

Answer:

6a³b²

Step-by-step explanation:

3 × 2 = 6

a²× a¹ = a³

b × b = b²

Answer:

There are 5 ways to find if two triangles are congruent.

SSS- {Side Side Side Congruence.}

This law of congruence states that if we have two triangles, each with the same measures on each 3 sides it deems the triangles congruent.

SAS- {Side Angle Side Congruence.}

This law of congruence states that if we have two triangles, with 2 equal sides and one angle which is common among them; the triangles are congruent.

ASA- {Angle Side Angle Congruence.}

This law of congruence states that if we have two triangles, with 2 congruent angle measures and 1 congruent side; the triangles are indeed congruent.

AAS- {Angle Angle Side Congruence.}

You may be wondering how this law of congruence differs from the previous one. ASA refers to any two angles and the included side, whereas AAS refers to the two corresponding angles and the non-included side.

HL- {Hypotenuse Leg Congruence.}

This law of congruence states that if we have two triangles, with a common (congruent) leg and hypotenuse; the triangles are congruent.

I really hoped this helped, if it didn't leave a comment I am always open to feedback. If it did let me know, brainiest is always appreciated!

Hope you have a great rest of your day.

Answer:

Step-by-step explanation:

for completeness, here is the answer again:

1 Given is correct

2 Definition of right angle is correct

3 should be sum of interior angles in a triangle

4 is substitution

5 subtracting 90degree from left and right hand side

6 is definition of complementary angles

Considering the definition of combination, if no meal is repeated, 210 different meal arrangements are possible.

Combinations of m elements taken from n to n (m≥n) are called all the possible groupings that can be made with the m elements in such a way that not all the elements enter; the order does not matter and the elements are not repeated.

To calculate the number of combinations, the following formula is applied:

[tex]C=\frac{m!}{n!(m-n)!}[/tex]

The term "n!" is called the "factorial of n" and is the multiplication of all numbers from "n" to 1.

Joseph is planning dinners for the next 4 nights. There are 10 meals to choose from and no meal is repeated.

So, you know that:

Replacing in the definition of combination:

[tex]C=\frac{10!}{4!(10-4)!}[/tex]

Solving:

[tex]C=\frac{10!}{4!6!}[/tex]

[tex]C=\frac{3,628,800}{24x720}[/tex]

[tex]C=\frac{3,628,800}{17,280}[/tex]

C= 210

Finally, if no meal is repeated, 210 different meal arrangements are possible.

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Answer:

We lend 100% - 9.2% and this will equal 90.8%, then we will make this percentage of 42,600 which will give us 38,680 and we will add the 42,600 and this will give us a total of 81,460 copies.

The difference of squares is:

(x+i√3)(x-i√3)

So the correct option is the last one, D.

For a complex number:

[tex]Z = a + b*i[/tex]

We define the complex conjugate of Z as:

[tex]Z' = a - b*i[/tex]

Such that the product between the complex number and its complex conjugate gives:

[tex]Z*Z' = a^2 + b^2[/tex]

Now, of you look at option D, you can see we have the product of a number and its conjugate, then we can write the product and use the above rule to get:

[tex](x + i\sqrt{3} )*(x - i\sqrt{3} ) = x^2 + (\sqrt{3} )^2 = x^2 + 3[/tex]

Which is what we wanted to get, so that is the correct option.

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Answer:

2 × 4 - 2 / -3

8-2/-3

6/-3

-2