Answer:
Using the usual notations and formulas,
Using the usual notations and formulas,mean, mu = 3550
Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870
Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000
Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculate
Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839
Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839Probability of weight below 3000 lbs
Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839Probability of weight below 3000 lbs=P(X < 3000) = P(z < Z) = P(z < - 0.6321839) =
Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839Probability of weight below 3000 lbs=P(X < 3000) = P(z < Z) = P(z < - 0.6321839) =0.2636334
Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839Probability of weight below 3000 lbs=P(X < 3000) = P(z < Z) = P(z < - 0.6321839) =0.2636334Answer:
Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839Probability of weight below 3000 lbs=P(X < 3000) = P(z < Z) = P(z < - 0.6321839) =0.2636334Answer:Probability that a car randomly selected is less than 3000
Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839Probability of weight below 3000 lbs=P(X < 3000) = P(z < Z) = P(z < - 0.6321839) =0.2636334Answer:Probability that a car randomly selected is less than 3000=P(X < 3000) = 0.2636 (to 4 decimals)
Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839Probability of weight below 3000 lbs=P(X < 3000) = P(z < Z) = P(z < - 0.6321839) =0.2636334Answer:Probability that a car randomly selected is less than 3000=P(X < 3000) = 0.2636 (to 4 decimals)Probability that a car randomly selected is greater than 3000
Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839Probability of weight below 3000 lbs=P(X < 3000) = P(z < Z) = P(z < - 0.6321839) =0.2636334Answer:Probability that a car randomly selected is less than 3000=P(X < 3000) = 0.2636 (to 4 decimals)Probability that a car randomly selected is greater than 3000=1 - P(X < 3000) = 1 - 0.2636 (to 4 decimals) =0.7364 (to 4 decimals)
Help me, 50 pts, I'll give brainliest, *take your time answering if you need *
1. how many groups of 5/7 are in 1
2. 8 divided by 5/7
3. The tape diagram shows that Ehecatl's hair, which is now 12cm long is 60% as long as it was before his haircut.
Complete the table to show different percentages of Ehecatl's hair length before the haircut. (table is the file)
There are 1.40 groups of 5/7 in 1.
8 divided by 5/7 is 11 1/5.
Here is the completed table:
Length (cm) Percentage
12 60% of Ehecatl's old hair
4 20% of Ehecatl's old hair
20 100% of Ehecatl's old hair
How do we carry out division?Division is the process of grouping a number into equal parts using another number. The sign used to denote division is ÷. Division is one of the basic mathematical operations.
In order to determine how many groups of 5/7 are in 1, divide 1 by 5/7
1 ÷ 5/7
1 x 7/5 = 7/5 = 1.40
8 ÷ 5/7
8 x 7/5
= 56 / 5
= 11 1/5
What are the lengths of Ehecatl's hair ?
The first step is to determine the length of her hair before she cut it
Length of the hair before it was cut = new length / 60%
12 / 0.6 = 20
60% x 20 = 12cm
20% x 20 = 4cm
100% x 20 = 20cm
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f(x)
Which type of function describes f(x)?
•
Rational
Polynomial
O Logarithmic
• Exponential
Answer:
Exponential function
[tex]y=1.25(2)^x[/tex]
Step-by-step explanation:
Definitions
Asymptote: a line that the curve gets infinitely close to, but never touches.
Hole: a point on the graph where the function is not defined.
Polynomial Function[tex]f(x)=a_nx^n+a_{n-1}x^{n-1}+...+a_2x^2+a_1x+a_0[/tex]
An equation containing variables with non-negative integer powers and coefficients, that involves only the operations of addition, subtraction and multiplication.
A continuous function with no holes or asymptotes.
Rational Function[tex]f(x)=\dfrac{h(x)}{g(x)}[/tex]
An equation containing at least one fraction whose numerator and denominator are polynomials.
A rational function has holes and/or asymptotes.
A rational function has holes where any input value causes both the numerator and denominator of the function to be equal to zero.A rational function has vertical asymptotes where the denominator approaches zero.If the degree of the numerator is smaller than the degree of the denominator, there will be a horizontal asymptote at y = 0.If the degree of the numerator is the same as the degree of the denominator, there will be a horizontal asymptote at y = ratio of leading coefficients.If the degree of the numerator is exactly one more than the degree of the denominator, slant asymptotes will occur. Logarithmic Function[tex]f(x) =\log_ax[/tex]
A continuous function with a vertical asymptote.
A logarithmic function has a gradual growth or decay.
Exponential Function[tex]f(x)=ab^x[/tex]
The variable is the exponent.
A continuous function with a horizontal asymptote.
An exponential function has a fast growth or decay.
Answer: exponential
Step-by-step explanation:
Use the ratio test to determine whether the series is convergent or divergent. 2 4/2^2 8/3^2 16/4^2 ......
I assume the given series is
[tex]\displaystyle 2 + \frac4{2^2} + \frac8{3^2} + \frac{16}{4^2} + \cdots = \frac{2^1}{1^2} + \frac{2^2}{2^2} + \frac{2^3}{3^2} + \frac{2^4}{4^2} + \cdots = \sum_{n=1}^\infty \frac{2^n}{n^2}[/tex]
By the ratio test, the series diverges, since
[tex]\displaystyle \lim_{n\to\infty} \left|\frac{2^{n+1}}{(n+1)^2} \cdot \frac{n^2}{2^n}\right| = 2 \lim_{n\to\infty} \frac{n^2}{(n+1)^2} = 2 > 1[/tex]
Graph f(x) = 2x - 3 on a coordinate plane.
Can you explain what you are going to do in order to graph this equation?
What do you expect the graph to look like?
Answer:
Create a table.
Plug values into the equation to complete the table.
Use the table to plot points on the graph.
Draw lines through the points on your graph.
The graph should look linear because there is an x that doesn't have a power greater than or less than 1.
A square of sides 6cm has been removed from regular pentagon of sides 12cm. Calculate the perimeter of the shape
The perimeter of the shape is 52 cm
How to determine the perimeter of the shape?The shape is given as:
Regular pentagon
The length of the sides are
Length = 12 cm
So, the perimeter of the regular pentagon is
P = 5* Length
This gives
P = 5 * 12cm
Evaluate
P = 60 cm
When the square of sides 6cm is removed from the regular pentagon, the perimeter becomes
P = 60cm - 6cm
Evaluate the difference
P =52 cm
Hence, the perimeter of the shape is 52 cm
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3. If the geometric mean of a and 25 is 20,
find the value of a.
Answer:
Value of a is 16.
Step-by-step explanation:
Solution Given:
we know that
Geometric mean=[tex]\sqrt{a*b}[/tex]
By using this formula
20=[tex]\sqrt{a*25}[/tex]
20=5[tex]\sqrt{a}[/tex]
dividing both side by 5, we get
20/5=5/5* [tex]\sqrt{a}[/tex]
4=[tex]\sqrt{a}[/tex]
squaring both side
4²=a
:. a=16
What is the slope of the line represented by the equation y = x-3?
O-3
های د
Answer:
1
Step-by-step explanation:
The slope of a function is equal to the coefficient of x when the equation is in standard form (y=mx+c)
In this case the equation is already in standard form and thusly we can see that the coefficient of x is 1 (the constant has no effect on the slope)
HELPPPP!!!!! Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each given function with the description of its graph.
Answer:
y = 2(1/2)^x --> Second choice
y = (1/4)^x --> First choice
y = 3^x --> Third choice
Step-by-step explanation:
Take a look at the images uploaded for the reasons why.
y = 2(1/2)ˣ is y intercept (0,2) second choice, y = (1/4)ˣ is y intercept (0,1) first choice, y = 3ˣ is y intercept (0,1), fourth choice.
Let's break down each of the given exponential functions and understand their y-intercepts:
y = 2(1/2)ˣ :
When x = 0, the value of (1/2)ˣ is 1, since any number raised to the power of 0 is 1. Therefore, y = 2 * 1 = 2 when x = 0. This gives us the y-intercept (0, 2).
y = (1/4)ˣ :
Similarly, when x = 0, the value of (1/4)ˣ is 1, since any number raised to the power of 0 is 1. Therefore, y = 1 when x = 0. This gives us the y-intercept (0, 1).
y = 3ˣ :
Again, when x = 0, the value of 3ˣ is 1. Therefore, y = 1 when x = 0. This gives us the y-intercept (0, 1).
The y-intercept is the point where the graph of the function intersects the y-axis, which occurs when x is zero. In all three cases, when x = 0, the exponent becomes zero, resulting in the base being raised to the power of zero, which is always equal to 1. The graph is given below.
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The following table represents a relation. X Y -3 0 0-2 5 -3 11-2 Does the table represent y as a function of c? Why or why not? No, because a number in the input is the same as a number in the output. Yes, because there are no x-values with more than one y-value. Yes, because every x-value has at least one y-value. No, because there are two inputs that have the same output.
The table represent y as a function of c, Yes because every x-value has at least one y-value.
According to the question,
X -3 0 5 11
Y 0 2 -3 -2
In order to find the table represent y as a function of c, When x = -3; y=0; x= 0 ;y=2; x= 0 y=2; x= 5 y=-3; x= 11 y=-2.
No, because a number in the input is the same as a number in the output.⇒ Above option is wrong, because a number in the input is not same as a number in the output.
Yes, because there are no x-values with more than one y-value.⇒ Above option is wrong, because there are many x-values with more than one y-value.
Yes, because every x-value has at least one y-value.⇒ Above option is correct, because every x-value has at least one y-value.
No, because there are two inputs that have the same output.⇒ Above option is wrong, because there are not two inputs that have the same output
Hence, the table represent y as a function of c, Yes, because every x-value has at least one y-value. Above option is correct, because every x-value has at least one y-value.
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Rearrange the formula to highlight the height
Answer:
[tex]h = \frac{2A}{b+c}[/tex]
Step-by-step explanation:
Original Equation:
[tex]A = \frac{1}{2} (b+c)h[/tex]
Divide both sides by height
[tex]\frac{A}{h} = \frac{1}{2}(b+c)[/tex]
Raise both sides to the exponent -1 :
[tex](\frac{A}{h})^{-1} = (\frac{1}{2}(b+c))^{-1}[/tex]
Rewrite using the definition of a negative exponent: [tex](\frac{a}{b})^{-x} = (\frac{b}{a})^{x}[/tex]
[tex]\frac{h}{A} = \frac{1}{\frac{1}{2}(b+c)}\\[/tex]
Multiply 1/2 by (b+c)
[tex]\frac{h}{A} = \frac{1}{\frac{b+c}{2}}\\[/tex]
Keep, change, flip
[tex]\frac{h}{A} = \frac{1}{1} * \frac{2}{b+c} = \frac{2}{b+c}[/tex]
Multiply both sides by A
[tex]h = \frac{2A}{b+c}[/tex]
Also I forgot to mention but the exponent (-1) can be ignored after you flip it, since: [tex](\frac{a}{b})^x = \frac{a^x}{b^x}[/tex], but since in our case the exponent is 1, and [tex]a^1 = a[/tex], so there's really no need to write out the distribution part, since we just get the same fraction, after flipping it.
Find the value of Theta in these diagrams (a and b)
a. θ = 36. 9°
b. θ = 114. 2°
How to determine the value of theta
a. We use the cosine identity
cos θ = adjacent/hypotenuse
Adjacent = 4cm
Hypotenuse = 5cm
cos θ = 4/ 5
cos θ = 0. 8
Now, we have the inverse of the cosine value
θ = cos^-1 (0. 8)
θ = 36. 9°
b. We use the tangent identity
tan a = opposite / adjacent
tan a = 3. 8/1. 7
tan a = 2. 23
a = tan^-1 ( 2. 23)
a = 65. 8
We have;
a + θ = 180 °; angles on a straight line
θ = 180 - 65. 9
θ = 114. 2°
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s in
Squaring both sides of the equation
√√x+1=√x+6-1 and simplifying, the equation
becomes 3 = √√x+6.
The solution of the equation is
The value of x in given linear equation is x = 3.
According to the statement
we have given that the equation and we have to find the solution of that equation.
So, For this purpose,
The given equation is :
[tex]\sqrt{ x+1} = \sqrt{ x+6} -1[/tex]
From this equation it is clear that the it is a linear equation.
So, for find the value of x
To solve this equation squaring on both sides then equation become
x+1 = x+6 +1 -2√x+6.
Then
-2√x+6 = -6
then
[tex]\sqrt{x + 6} = 3[/tex]
Now remove the square by S.B.S.
Then the equation become
x +6 = 9
x = 3.
In this equation the value of x is 3.
So, The value of x in given linear equation is x = 3.
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Tim, paco, maria, and jenny are standing in line for lunch. jenny is standing between paco and maria, and paco’s position in line is an odd number. tim is not standing on either end of the line, and he is in front of jenny. which friend is standing third in line?
Answer:
the order is Paco, Tim, Jenny, Maria
Step-by-step explanation:
Answer:
b.
Paco, Tim, Jenny, Maria
Step-by-step explanation:
Draw at least six different sized rectangles that have an area of 64 square units then find the perimeter of each rectangle.
Six different sized rectangles that have an area of 64 square units:
1) 64 units x 1 unit
2) 32 units x 2 units
3) 16 units x 4 units
4) 40 units x 1.4 units
5) 20 units x 3.2 unit
6) 10 units x 6.4 units
For given question,
Let l be the length of the rectangle and w be the width of the rectangle.
We know that, the area of a rectangle is equal to
A = l × w
Here, A = 64 square units
So, we get an equation
l × w = 64 ...............................(1)
let's assume different values of l to get the different values of w.
Case 1) For l = 64 units
substitute in the equation 1
⇒ 64 × w = 64
⇒ w = 64/64
⇒ w = 1 units
The dimensions of the rectangle are 64 units x 1 unit
See the draw in the attached figure 1
Case 2) For l = 32 units
substitute in the equation 1
⇒ 32 × w = 64
⇒ w = 64/32
⇒ w = 2 units
The dimensions of the rectangle are 32 units x 2 unit
See the draw in the attached figure 2
Case 3) For l = 16 units
substitute in the equation 1
⇒ 16 × w = 64
⇒ w = 64/16
⇒ w = 4 units
The dimensions of the rectangle are 16 units x 4 unit
See the draw in the attached figure 3
Case 4) For l = 40 units
substitute in the equation 1
⇒ 40 × w = 64
⇒ w = 64/40
⇒ w = 1.4 units
The dimensions of the rectangle are 40 units x 1.4 unit
See the draw in the attached figure 4
Case 5) For l = 20 units
substitute in the equation 1
⇒ 20 × w = 64
⇒ w = 64/20
⇒ w = 3.2 units
The dimensions of the rectangle are 20 units x 3.2 unit
See the draw in the attached figure 5
Case 6) For l = 10 units
substitute in the equation 1
⇒ 10 × w = 64
⇒ w = 64/10
⇒ w = 6.4 units
The dimensions of the rectangle are 10 units x 6.4 unit
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which fraction is greater 3/6 or 6/10
Answer:
6/10
Step-by-step explanation:
3/6 = 0.5
6/10 = 0.6
0.6>0.5
Then
6/10 is greater than 3/6
The area of a circle is 9pi cm². Find its radius.
Please do this question with full solution:)
Answer:
3 cm
Step-by-step explanation:
The formula for the area of a circle is:
[tex]A = \pi r^2[/tex]
Where "r" represents the radius of the circle. We can substitute the given value for Area into the equation to solve for the radius.
Solve for Radius[tex]A=\pi r^2\\9\pi = \pi r^2[/tex]
Divide both sides by π
[tex]9=r^2[/tex]
Take the square root of both sides
[tex]\sqrt9=\sqrt {r^2}\\r=3[/tex]
The radius of the circle is 3 cm.
A kite has vertices at (2, 4), (5, 4), (5, 1), and (0, –1).
What is the approximate perimeter of the kite? Round to the nearest tenth.
11.3 units
13.6 units
16.8 units
20.0 units
Answer:
16.8
Step-by-step explanation:
here is that kite on a graph. you can see there are 2 sides of length 5, and 2 sides of length 3, so closest perimeter is 16.8
Please answer correctly
Answer:
Option (1)
Step-by-step explanation:
We need a recursive formula.
Eliminate option 3.The common ratio is 2.
Eliminate options 2 and 4.So, the answer is option 1.
An ellipse has a center at the origin, a vertex along the major axis at (10, 0), and a focus at (8, 0).
Which equation represents this ellipse?
Answer:
In standard form x^2/64 + y^2/100 = 1
Step-by-step explanation:
The major axis is the y axis because 10 has a larger value than 8.
8x8 = 64
10 x10 = 100
What is the slope of the line that passes through the points (1, 1) and (4, 4)?
Write your answer in simplest form.
Answer:
The answer is 1
Step-by-step explanation:
Formula for finding the slope: [tex]\frac{y2-y1}{x2-x1}[/tex]
Take y2 and y1 from (4,4) (1,1)
Take x2 and x1 from (4,4) (1,1)
[tex]\frac{y2-y1}{x2-x1} = \frac{4-1}{4-1} = \frac{3}{3} = 1[/tex]
This is how the answer is 1
Hope it helps :)
Pick the correct answer
Help me please thanks so much
Answer:
E
Step-by-step explanation:
line I slopes downwards from left to right and has a negative slope.
line K is a horizontal line and has a slope of zero
line J slopes upwards from left to right and has a positive slope
slopes from least to greatest are therefore I, K, J
Okay so this is super tricky, there is a riddle on my math quiz. Yk for extra credit and its 25% of my grade, according to Mr. Wells.
If you have 1 cow that is worth $2,500 and 2 cats worth $100. But one dog is worth $7000, what would the outcome be if there was only 1 of each animal? Hint: It could be division or multiplication.
A. 2 cats and one dog
B. 1 cow and 1 dog
C. $600 for each animal
D. If you think its none of these listed, you may write your own!
Note: this makes no sense whatsoever, so please help. Mr. Wells is a good teacher, but this question is hard
If there was just one of each animal, the outcome would be that of 1 cow and 1 dog.
Option(B) is correct.
The average cost, or how much it generally costs to produce a unit, can be discovered using the cost function.
If you own two cats worth $100 each and a cow worth $2,500. One dog, though, is worth $7000.
Cost of 1 cow = $2500
Cost of 2 cats = $100
Thus, cost of 1 cat = $100/2 = $50
Cost of 1 dog = $7000
If there was only 1 of each animal, total cost = $(2500+50+7000) = $9550.
This outcome resembles the situation of having 1 cow and 1 dog.
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PLEASE HELP!!!!!!!!!!!!!!!!!!
Answer:
[tex]\sin\left(x+\frac{\pi}{7} \right)[/tex]
Step-by-step explanation:
[tex]\sin\left(x+\frac{\pi}{7} \right)=\sin \frac{\pi}{7}\cos x +\cos \frac{\pi}{7} \sin x[/tex]
5.
A section of a tessellated plane is shown. Which type of symmetry does the tessellated plane have?
The tessellated plane has translational symmetry option (A) translational symmetry is correct.
What is geometric transformation?It is defined as the change in coordinates and the shape of the geometrical body. It is also referred to as a two-dimensional transformation. In the geometric transformation, changes in the geometry can be possible by rotation, translation, reflection, and glide translation.
A geometric figure is given:
As we know, from geometric transformation, geometric transformation, changes in the geometry can be possible by rotation, translation, reflection, etc.
Without any further changes, the tessellated plane is moved a few units to the right. If the translated plane is again moved left by the same amount of units, we will once more obtain the original plane. Translational symmetry is present as a result.
Thus, the tessellated plane has translational symmetry option (A) translational symmetry is correct.
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im pulling my hair out with this problem my calculator simplified it to [tex]\frac{1+/-\sqrt{14}}{10}[/tex]
What am i doing wrong?? :')
[tex]~~~~~~~~~~~~\textit{quadratic formula} \\\\ 0=\stackrel{\stackrel{a}{\downarrow }}{3}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{-5} \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ x= \cfrac{ - (2) \pm \sqrt { (2)^2 -4(3)(-5)}}{2(3)} \implies x = \cfrac{ -2 \pm \sqrt { 4 +60}}{ 6 } \\\\\\ x= \cfrac{ -2 \pm \sqrt { 64 }}{ 6 }\implies x=\cfrac{ -2 \pm 8}{ 6 }\implies x= \begin{cases} ~~ 1\\ -\frac{5}{3} \end{cases}[/tex]
Answer:
-5/3 and -1
Step-by-step explanation:
I am not sure what you mistake is, but here is my solution. I hope that it helps. I am sorry that you are frustrated. We have all been there.
As people exited a movie theater, they were informally surveyed about whether they enjoyed the movie or not.
What are the values of a and b in the relative frequency table for the survey results? Round answers to the nearest percent.
Write (9 + 6i) − (1 + 3i) as a complex number in standard form.
A.
10 + 9i
B.
8 − 3i
C.
8 + 3i
D.
7 − 12i
The sum of the complex number in standard form is 8 + 3i
Complex numbersComplex numbers are square roots of negative numbers. The square root of -1 for example is equal to "i" as shown;
√-1 = i
The complex number is written as x + iy. Given the expression
(9 + 6i) − (1 + 3i)
Expand to have:
9 + 6i − 1 - 3i
Collect the like terms
9-1 + 6i - 3i
Group into real and imaginary parts
(9-1) + (6i-3i)
8 + 3i
Hence the sum of the complex number in standard form is 8 + 3i
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The histogram shows the distribution of minting year for a sample of
100
100100 nickels at a bank.
a histogram. the x-axis is labeled minting year and numbered from 1900 to 2020. the y-axis is labeled nickels and numbered from 0 to 25. there are 12 buckets of equal width. the mids and counts for the buckets are mid: 1905, count: 1. mid: 1915, count: 0. mid: 1925, count: 0. mid: 1935, count: 0. mid: 1945, count: 1. mid: 1955, count: 1. mid: 1965, count: 11. mid: 1975, count: 17. mid: 1985, count: 15. mid: 1995, count: 20. mid: 2005, count: 24. mid: 2015, count: 10.
0
0
5
5
10
10
15
15
20
20
25
25
1900
19001900
1910
19101910
1920
19201920
1930
19301930
1940
19401940
1950
19501950
1960
19601960
1970
19701970
1980
19801980
1990
19901990
2000
20002000
2010
20102010
2020
20202020nickelsminting year
describe the distribution of minting year.
shape: the distribution of minting year is
.
center: the median is somewhere between
years.
spread: the range is approximately
years.
outliers: there are
potential outliers.
All the parts of the questions about the given histogram have been answered below.
What is a histogram?A histogram is a graph that depicts the frequency of numerical data using rectangles. The vertical axis of a rectangle represents the distribution frequency of a variable (the amount, or how often that variable appears).(A) The distribution of minting year:
According to the histogram, the distribution of minting years is 1900-1910 and 1940-2020.
(B) The median:
Add the two middle numbers together and divide them by two to get the median.
10 + 15 / 2 = 12.5
So, the median is somewhere between 10-15.
(C) The range:
The range is computed by subtracting the lowest and highest values.
25 - 0 = 25
So, the range is 25.
(D) The potential outliers:
According to the histogram, the potential outliers are 1910-1940.
Therefore, all the parts of the questions have been answered.
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Answer:
Step-by-step explanation:
I got it right on khan
please help im sorry it is late but please i dont understand
Answer:
416 people
Step-by-step explanation:
The way you get the answer is by adding up the number of people from the sample, which gives you 175 people. After finding that you take the number of people who like pretzels (26) and divide it by 175, giving you 0.16 or 16%.
This means 16% of people will like pretzels, so you apply this to the actual number of people coming, 2600, and find 16% of 2600 (0.16 x 2600) which is 416 people. I hope this makes sense :)
In mr. wilson's geometry class, 12 of the students received a's and 20 received b's. in his statistics class, 11 of the students got a's and 15 got b's. in which class did mr. wilson's students earn a higher ratio of a's to b's? a. statistics b. neither, the ratios are equivalent c. geometry d. not enough information
In (A) statistics class Wilson's students earn a higher ratio of a's to b's.
What are ratios?A ratio in mathematics describes how many times one number contains another. For example, if a dish of the fruit contains eight oranges and six lemons, the orange-to-lemon ratio is eight to six. Similarly, the lemon to orange ratio is 6:8, while the orange to total fruit ratio is 8:14.To find the higher ratio:
Given -
Geometry class = a:b = 12:20 = 3:5Statistics class = a:b = 11:15As we can observe that 3:5 < 11:15.
Therefore, in (A) statistics class Wilson's students earn a higher ratio of a's to b's.
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