The vertices of an isosceles triangle are A(3, 6), B(7, 2), and C4, 3).
What is the equation of the triangle's line of symmetry?

The probability of drawing a red card from a standard deck of cards is 1/2.

Given that there is a standard deck of cards.

We are required to find the probability of drawing a rd card from a standard deck of cards.

Probability is the calculation of chance of happening an event among all the events possible. It lies between 0 and 1. It cannot be negative.

Probability=Number of items/Total items.

Total number of cards=52

Number of red cards =26

Number of black cards=26

Probability of drawing a red card =Number of red cards/ Total cards.

=26/52

=1/2

Hence the probability of drawing a red card from a standard deck of cards is 1/2.

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2 x 10² kcal are in the serving report your answer to 2 significant figures.

According to the question

A serving of fish contains 50 g of protein and 4. 0 g of fat.

i.e. content of protein = 50 g

Content of fat = 4 g

kcal are in the serving report your answer to 2 significant figures:

As the serving of fish contains 50g of protein that is 4.0kcal/g

Calories in 50 g protein = (Content of protein) × (caloric value in protein)

50g × (4.0kcal/g) = 200kcal

That means the kcal of the serving is 200kcal

In 2 significant figures: 2 x 10² kcal

Hence,

2 x 10² kcal are in the serving report your answer to 2 significant figures.

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Answer:

Step-by-step explanation:

[tex]We\ summarize\ (1) \ and\ (2),\ \ (2) \ and\ (3):\\\displaystyle\\\left \{ {{2x\geq -6\ |:2} \atop {-2x\geq -6\ |:(-2)}} \right. \ \ \ \ \ \left \{ {{x\geq -3} \atop {x\leq 3}} \right. \ \ \ \ \ \Rightarrow\ \ \ \ x\in[-3;3].\\[/tex]

[tex]2)\ We\ subtract\ equation\ (2) \ from \ equation (1),[/tex]

The rectangular pyramid rises 7 feet in height.

Pyramids are three-dimensional objects with triangle-shaped faces and an all-encompassing polygonal base. It is referred to as a rectangular pyramid if the base of the structure is rectangular. Although all pyramids have a rectangular foundation, they all have triangular edges.

How is the height of the rectangular pyramid determined?

First, we understand that a rectangular pyramid's volume is determined by:

                         [tex]V=B * H / 3[/tex]

The height H is determined by the base B.

When we know the volume is 56 [tex]ft^{3}[/tex] and the base is 24 [tex]ft^{2}[/tex], we can then swap out those two numbers in the volume calculation to get:

                          [tex]56 f t^{3}=24 f t^{2} * H / 3[/tex]

When we solve it for H, we get:

                          [tex]H=3 *\left(56 f t^{\circ} / 24 f t^{2}\right)=7 f t[/tex]

The rectangular pyramid rises 7 feet in height.

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Proved that the cofunction identity sec([tex]\frac{\pi }{2}[/tex]) - u = csc(u)

We have to prove that the cofunction identity using the addition and subtraction formulas.

sec([tex]\frac{\pi }{2}[/tex]) - u = csc(u)

We can prove this by using the identities given below:

[tex]sec(u)=\frac{1}{cos(u)}[/tex]

[tex]\frac{1}{sin(u)} =csc(u)[/tex]

cos(a-b) = cos a cos b + sin a sin b

Now the explanation,

[tex]sec(\frac{\pi }{2} -u) = csc(u)[/tex]

By using trignometric identities,

[tex]cos(u)=\frac{1}{sec(u)}[/tex]   ∴[tex]sec(u)=\frac{1}{cos(u)}[/tex]

So,

[tex]\frac{1}{cos(\frac{\pi }{2}-u) } =csc(u)[/tex]

By substituting the given identities we get,

  [tex]\frac{1}{cos(\frac{\pi }{2})cos(u)+sin(\frac{\pi }{2} )sin(u) }[/tex]

= [tex]\frac{1}{0.cos(u)+(1).sin(u)}[/tex]

=[tex]\frac{1}{sin(u)}[/tex]

= csc(u)

csc(u) = csc(u)

Here we proved that the cofunction identity sec([tex]\frac{\pi }{2}[/tex]-u) = csc(u)

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There are 105 numbers in the  the first 1000 positive integers contain only 0s and 1s when written in base 3

The number base is given as:

Base 3

To determine the count of numbers, we make use of the following Python program

count = 0

for n in range(1,1001):

   digits = []

   while n:

       digits.append(int(n % 3))

       n //= 3

   myStr = ''.join(map(str,digits[::-1]))

   if(myStr.count('0')+myStr.count('1') == len(myStr)):

       count+=1

print(count)

The above program counts the numbers in the  the first 1000 positive integers contain only 0s and 1s when written in base 3

The output of the program is 105

Hence, there are 105 numbers in the  the first 1000 positive integers contain only 0s and 1s when written in base 3

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Answer:

Step-by-step Explanation:

The correct option is C.

The algebraic expression for "seven more than the product of three and some number = 3x + 7 = 0

An algebraic expression is one that is composed of variables, integer constants, and algebraic operations. An algebraic expression is, for instance, 3x² 2xy + c.

we can search for the product of 3 and "some number",

Let the number be x.

So, the product of x is 3 times = 3x

And now

7 more then the Product .

we add the 7 to the product .

3x + 7 = 0

So the equation will be 3x + 7 = 0

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I understand that question you are looking for is:

Which of these is the algebraic expression for "seven more than the product of three and some number?"

A. 7 + 3 + x

B. 3 + 10 ÷ x

C. 3x + 7

D. 3 + 7x

from 2007 to 2012 is only 5 years, so we can see this as a compound interest with a rate of 1.2% per annum for 5 years, so

[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$113505\\ r=rate\to 1.2\%\to \frac{1.2}{100}\dotfill &0.012\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{per year, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=113505\left(1+\frac{0.012}{1}\right)^{1\cdot 5}\implies A=113505(1.012)^5\implies A\approx 120481[/tex]

Answer:

[tex]12.50 \space\ h = 2500.75[/tex]

Step-by-step explanation:

We know from the question that the student earned $12.50 per hour.

Using this information, we can say that if the student worked for h hours, they would make a total of 12.50 × h dollars.

We also know that the total money they earned is $2500.75.

∴ Therefore, we can set up the following equation:

[tex]\boxed {12.50 \times h = 2500.75}[/tex]

From here, if we want to, we can find the number of hours worked by simply making h the subject of the equation and evaluating:

h = [tex]\frac{2500.75}{12.50}[/tex]

  = 200.6 hours

Answer: 12.50h = 2500.75

Step-by-step explanation:

We know from the question that the student earned $12.50 per hour.

Using this information, we can say that if the student worked for h hours, they would make a total of 12.50 × h dollars.

We also know that the total money they earned is $2500.75.

Answer:

627

267

276

762

726

and the no. itself, 672

This is voluntary response bias. The result overestimates true support for firing the coach.

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If the vertices of parallelogram ABCD is A(-6,-4),B(0,-4),C(3,4),D(-3,4) ,then the area of parallelogram ABCD will be 48 square units.

Given that the vertices of parallelogram ABCD is A(-6,-4),B(0,-4)

,C(3,4),D(-3,4).

We are required to find the area of parallelogram ABCD.

Let the point of intersection of height of parallelogram from point A is point E.

When we see the graph on which the parallelogram then we will be able to know that point E has coordinates of (-3,-4).

Area of parallelogram=Base*Height

=AB*DE

DE=[tex]\sqrt{(-4-4)^{2} +(-3+3)^{2} }[/tex]

=[tex]\sqrt{64}[/tex]

=8 units

AB=[tex]\sqrt{(-4+4)^{2} +(0+6)^{2} }[/tex]

=[tex]\sqrt{36}[/tex]

=6 units

Area=6*8

=48 square units.

Hence if the vertices of parallelogram ABCD is A(-6,-4),B(0,-4),C(3,4),D(-3,4) ,then the area of parallelogram ABCD will be 48 square units.

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Answer:

17, 5

Step-by-step explanation:

Let the width be x

width = x

length = x + 12

length x width = x(x + 12)

length x width = x² + 12x

x² + 12x = 85

x² + 12x - 85 = 0

Now it is just a quadratic:

The 2 numbers we need are 17 and -5

(x + 17)(x - 5) = 0

x = -17 or x = 5.

Since width and length cannot be negative, x must equal 5.

Width = 5

length = 17

The answer is 17, 5.

We are given two things :

We can represent the length and width as x + 12 and x respectively.

Now, the formula for the area of a rectangle is :

Area = Length x width

Now, let's substitute the values for length and width in the formula along with the area.

We now have a quadratic equation, which can either be solved by splitting the middle term, or by using the quadratic formula. For convenience purposes, we'll go with the first one.

Answer:[tex]x^3-x^2-17x+20[/tex]

Step-by-step explanation:

For the given functions, the domains are:

1) All real numbers.

2) D: x≥ -3

3) D: set of all real numbers such that x ≠ 0

4) D: 7 ≥ x ≥-7

5)  All real numbers.

For any function, we assume that the domain is the set of all real numbers, and then we remove all the values of x that generate problems (like a denominator equal to zero or something like that).

1) f(x) = x^2 - 4

This is just a quadratic equation, the domain is the set of all real numbers.

2) f(x) = √(x + 3)

Remember that the argument of a square root must be equal to or larger than zero, so here the domain is defined by:

x + 3 ≥ 0

x≥ -3

The domain is:

D: x ≥ -3

3) f(x) = 1/x

We can assume that the domain is the set of all real numbers, but, we can see that when x = 0 the denominator becomes zero, then we need to remove that value from the domain.

Thus, we conclude that the domain is:

D: set of all real numbers such that x ≠ 0

4) f(x) = √(49 - x^2)

Here we must have:

49 - x^2 ≥ 0

49 ≥ x^2

√49  ≥ x ≥-√49

7 ≥ x ≥-7

The domain of this function is:

D:  7 ≥ x ≥-7

5) f(x) = √(x^2 + 1)

Notice that x^2 is always a positive number, then the argument of the above square root is always positive, then the domain of that function is the set of all real numbers.

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Step-by-step explanation:

25 as binary number is

11001

1×2⁴ + 1×2³ + 0×2² + 0×2¹ + 1×2⁰ = 16 + 8 + 1 = 25

25×2 = 50 = 11001 × 2 = 110010

multiplying a binary number by 2 is the save effect as multiplying a normal decimal number by 10 : all digits move one position to the left, and a 0 is put into the empty right position.

and so, we see

110P = 110010

P = 010

FYI : you normally don't mix binary and decimal numbers. if one of the numbers is binary, then all the others have to be binary too.

so, the problem should have looked like

110P/10 = 11001

110P = 11001×10 = 110010

P = 010

Answer:

01

Step-by-step explanation:

From decimal to binary;

25/2==> 1 (remainder)

12/2===>0

6/2==>0

3/2===>1

1

=11001

Checking the answer;

11001

=1*2^4+1*2^3+0*2*2+0*1+1*2^0

=1*16+1*8+0+0+1*1

=16+8+0+0+2

=25

Answer:

50 ^^

Step-by-step explanation:

So first an easy way to solve this problem is by removing the zeros then you'll have 35 and
7x1=7

7x2=14

7x3=21

7x4=28

7x5=35

So 7x5 dont forget to add your zeros to 35 and 5 and boom your answer is 50

need more explaining tell me ^^

The step which contains the first error in calculation is: B. Step 2 - the sine ratio was applied incorrectly.

The law of sines is also referred to as sine law or sine rule and it can be defined as an equation that relates the side lengths of a triangle to the sines of its angles.

Mathematically, the law of sines is given by this equation:

[tex]\frac{sinA}{a} =\frac{sinB}{b}[/tex]

For any right-angled triangle, the ratio of the length of its opposite sides to the length of its hypotenuse is generally referred to as sine ratio. Thus, sine ratio is given by this formula:

cos(θ) = Opp/Hyp

Where:

In this context, we can infer and logically deduce that the step which contains the first error in calculation is step 2:

sin(W) = y/XZ; XZsin(W) = y.

In conclusion, the correct step should have been written as follows:

sin(W) = XZ/y; ysin(W) = XZ.

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Answer:

step 2 is incorrect

Step-by-step explanation:

B. Step 2 - the sine ratio was applied incorrectly

The correct graph is in the attached image.

Answer:

  B.  A linear graph of solid line intercepts X-axis at the point (2, 0) and Y-axis at the point (0, -4)

Step-by-step explanation:

The boundary line of an inequality is graphed as though the expression were an equality. The nature of the line used will depend on the nature of the inequality.

When the inequality includes the "or equal to" case (≤ or ≥), the boundary line is part of the solution set. It is drawn as a solid line.

When the inequality excludes the "or equal to" case (< or >), the boundary line is not part of the solution set. It is drawn as a dotted or dashed line.

The given inequality

  y ≤ 2x -4

includes the "or equal to" case, so the boundary line is solid.

The equation of the boundary line is written in slope-intercept form:

  y = mx +b . . . . . . . line with slope m and y-intercept b

  y = 2x -4 . . . . . . . boundary line with slope 2 and y-intercept -4.

This tells you that the boundary line intercepts the y-axis at the point (0, -4).

The probability that the service time will be more than three minutes is 0.3012.

Given that the average wait time at the Rivertown bank's neighborhood branch is 2.5 minutes and has an exponential distribution,

The time it takes to succeed in a continuous sequence of independent trials is described by the exponential distribution, which is a continuous probability distribution.

At the River Town Bank's neighborhood branch, the random variable X service time has an exponential distribution with a mean value of 2.5 minutes. Therefore,

[tex]f(x)=\left\{\begin{array}{ll}\theta e^{-\theta x},& \theta \geq 0,0\leq x\leq \infty\\0&\text{otherwise}\end{array}[/tex]

E(x)=1/θ

θ=1/2.5

θ=0.4

The probability that the service time will be longer than three minutes:

[tex]\begin{aligned}P(X > 3)&=1-P(X\leq 3)\\ &=1-(1-e^{-0.4\times 3}\\ &=e^{-1.2}\\ &=0.3012\end[/tex]

Since the service duration has an exponential distribution and a mean of 2.5 minutes, the needed chance that it will exceed 3 minutes is 0.3012.

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The expression for the volume of the pyramid in terms of the radius of the cone is  [tex]V=\pi r^{3}[/tex].

The expression for the volume of the pyramid in terms of the radius of the cone:

B= base area of the cone.

[tex]V=\pi r^{2}[/tex]

The volume of the Pyramid,

[tex]V=\frac{1}{3} *B*height[/tex]

[tex]$\Rightarrow V=\frac{1}{3} \times \pi r^{2} \times 3 \gamma$[/tex]

[tex]V=\pi r^{3}[/tex]

The expression for the volume of the pyramid in terms of the radius of the cone is [tex]V=\pi r^{3}[/tex]

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Answer:

7/10

Step-by-step explanation:

take 3, 2, 1 from the equation and your left with 7 numbers. Add those together you get 10. 7/10 is the probability that you will draw a number greater than 3

We can observe

Its a geometric progression having first term 9(3)=27 and common ratio as 1/3

So

The firmula is

Option C

Answer:

[tex]a_n=27\left(\dfrac{1}{3}\right)^{n-1}[/tex]

Step-by-step explanation:

From inspection of the graph, the given points are:

If we draw a line through the given points, the line is a curve rather than a straight line. If the line was a straight line, the graph would be modeled as an arithmetic sequence. Therefore, as the line is a curve, the given points are modeling a geometric sequence.

General form of a geometric sequence:

 [tex]a_n=ar^{n-1}[/tex]

where:

Rewrite the given points as terms of the sequence:

To find the common ratio r, divide consecutive terms:

[tex]\implies r=\dfrac{a_3}{a_2}=\dfrac{3}{9}=\dfrac{1}{3}[/tex]

Calculate the first term (a) by substituting the found value of r and the given values of one of the terms into the formula:

[tex]\implies a_2=9[/tex]

[tex]\implies a\left(\dfrac{1}{3}\right)^{2-1}=9[/tex]

[tex]\implies \dfrac{1}{3}a=9[/tex]

[tex]\implies a=27[/tex]

Substitute the found values of r and a into the general formula to create the sequence modeled by the graph:

[tex]a_n=27\left(\dfrac{1}{3}\right)^{n-1}[/tex]

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Answer:

1 hour

Step-by-step explanation:

Answer:

330

Step-by-step explanation:

the change in hirght = 120 - 90 = 30

so 90 + (30 x 8)

= 90+240

= 330//

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {z}^{2} - 14z + 48 }{ {z}^{2} + 6x - 27} ÷ \cfrac{z -8}{z-3} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {z}^{2} - 8z - 6z+ 48 }{ {z}^{2} + 9z- 3z- 27} ÷ \cfrac{z -8}{z-3} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {z(}^{} z- 8) - 6(z - 8) }{ {z}^{} (z+ 9)- 3(z + 9)} ÷ \cfrac{z -8}{z-3} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {(}^{} z- 8) (z - 6) }{ {}^{} (z+ 9)(z - 3)} ÷ \cfrac{z -8}{z-3} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ (z - 6) }{ {}^{} (z+ 9)}[/tex]

Break into two parts and simplify

[tex]\\ \rm\dashrightarrow \dfrac{z^2-14z+48}{z^2+6z-27}[/tex]

[tex]\\ \rm\dashrightarrow \dfrac{z^2-8z-6z+48}{z^2+9z-3z-27}[/tex]

[tex]\\ \rm\dashrightarrow \dfrac{(z-8)(z-6)}{(z+9)(z-3)}[/tex]

Now divide by the denominator

[tex]\\ \rm\dashrightarrow \dfrac{(z-8)(z-6)(z-3)}{(z+9)(z-3)(z-8)}[/tex]

[tex]\\ \rm\dashrightarrow \dfrac{z-6}{z+9}[/tex]