Answer:
[tex]21 \sqrt{2} [/tex]
Step-by-step explanation:
See attached image.
The figure below is a scale drawing of an office courtyard using the scale 1 centimeter = 4 feet.
Which figure is a scale drawing of the same courtyard using the scale 1 centimeter = 3 feet?
Using proportions, it is found that option A gives a figure that is a scale drawing of the same courtyard using the scale 1 centimeter = 3 feet.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.
Researching this problem on the internet, the figure with a scale of 1 cm = 4 feet has the dimensions of:
51 cm, 75 cm, 30 cm and 72cm.
For a scale of 1 centimeter = 3 feet, these measures will be multiplied by 4/3, hence the figure is given in option A, as:
51 x 4/3 = 68 cm.75 x 4/3 = 100 cm.30 x 4/3 = 40 cm.72 x 4/3 = 96 cm.More can be learned about proportions at https://brainly.com/question/24372153
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a) Find the perimeter of a rectangle whose length is 10 10²/3 cm and breadth is 6 cm.
please need fast I will make brilliant
Answer:
40
Step-by-step explanation:
P=2(l+w)
2·(10+10)
=40
In parallelogram DEFG, DH equals X +3, HF equals 3Y, GH equals 2X -5 and HE equals 5Y plus to find the values of X and Y
The values of X and Y are 30 and 11 respectively
How to determine the values of X and Y?The figure that represents the complete question is added as an attachment
The given parameters are:
DH = X +3
HF = 3Y
GH = 2X -5
HE = 5Y
From the attached parallelogram, we have:
DH = HF
GH = HE
Substitute the known values in the above equation
X + 3 = 3Y
2X - 5 = 5Y
Make X the subject in X + 3 = 3Y
X = 3Y - 3
Substitute X = 3Y - 3 in 2X - 5 = 5Y
2(3Y - 3) - 5 = 5Y
Expand
6Y - 6 - 5 = 5Y
Evaluate the like terms
Y = 11
Substitute Y = 11 in X = 3Y - 3
X = 3*11 - 3
Evaluate
X = 30
Hence, the values of X and Y are 30 and 11 respectively
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Find the slope and reduce.
P=(-8, 3) Q=(-6, 2)
Slope
Answer:
[tex]-\frac{1}{2}[/tex]
Step-by-step explanation:
Slope/Gradient = [tex]\frac{y1-y2}{x1-x2}[/tex]
P = (-8 , 3) (x1, y1)
Q = (-6 , 2) (x2, y2)
Slope = [tex]\frac{3-2}{-8-(-6)}[/tex] =[tex]\frac{1}{-8+6}[/tex] = [tex]\frac{1}{-2}[/tex] = [tex]-\frac{1}{2}[/tex]
Answer:
-1/2
Step-by-step explanation:
The formula for the slope is (change in y)/(change in x) or Rise/Run.
The change in y for the two points is: 3 --> 2 which is -1
The change in x for the two points is: -8 --> -6 which is +2
If we input these numbers in the slope equation, we end up with -1/2.
Since we cannot simplify -1/2 further, that is our final answer.
he polynomial of degree 5, P ( x ) has leading coefficient 1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of multiplicity 1 at x = − 1 Find a possible formula for P ( x ) .
f]
The possible formula for the polynomial in discuss whose roots are described as; having roots of multiplicity 2 at x = 3 and x = 0 , and a root of multiplicity 1 at x = − 1 is; P(x) = x^5 -5x⁴-6x³+18x².
What is the polynomial in discuss whose roots and leading coefficient are as discussed?The polynomial which is as described in the task content whose roots are as given can be written in its factorised form as follows;
P(x) = (x-3) (x-3) (x) (x) (x+1)
The expanded form is therefore;
P(x) = x^5 - 5x⁴- 6x³+ 18x².
Therefore, the polynomial having roots of multiplicity 2 at x = 3 and x = 0 , and a root of multiplicity 1 at x = − 1 is P(x) = x^5 - 5x⁴- 6x³+ 18x².
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Which are valid pairs of opposite angle measures for a quadrilateral inscribed
in a circle? Select all that apply.
A. 72°, 108°
B. 66°, 114°
C. 80°, 90°
D. 64°, 106°
Answer:
A., B.
Step-by-step explanation:
Opposite angles of a quadrilateral inscribed in a circle are supplementary, so their sum must equal 180°.
A. 72° + 108° = 180° Answer: yes
B. 66° + 114° = 180° Answer: yes
C. 80° + 90° = 170° Answer: no
D. 64° + 106° = 170° Answer: no
Answer: A., B.
a. Based on the picture, what properties can you be sure this figure has? Think about angles, lines, and points.
b. Does ray l bisect ∠ABC? Explain your thinking.
c. What would you need to do to prove that ray l bisects ∠ABC?
The angle measures ABD = 45, DBC = 45 and ABC = 90 imply that ray l bisect ∠ABC?
The properties of the figureFrom the figure, we have the following highlights:
The lines AB and BC are perpendicular lines i.e. the angle at B =90Ray I bisects the angle ABC (because 45 + 45 = 90)Angles ABD and DBC are adjacent anglesThis means that the points ABC can be joined to form a right triangle
Does ray l bisect ∠ABC?Yes, it does.
This is so because it divides the angle ABC into equal segments.
i.e.
ABC = 90
DBC = 45
So, we have
ABD = 90 - 45
ABD = 45
The angle measures ABD = 45, DBC = 45 and ABC = 90 imply that ray l bisect ∠ABC?
What would you need to do to prove that ray l bisects ∠ABC?You would need the measures of ABC and ABD
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A recipe calls for 3/4 cups of water, 2/3 cups of flour, and 1/6 cups of sugar. What is the ratio of water: flour: sugar? Express your answer reduced to the lowest terms
Answer:
9:8:2
Step-by-step explanation:
3/4 : 2/3 : 1/6 Multiply by 12.
9 : 8 : 2
Decreasing the number of years of a loan decreases the amount of interest repaid over the term of the loan. Suppose a dental hygienist has the option of a 30-year loan or a 25-year loan of $345,000 at an annual interest rate of 3.75%.
(a)
a) Calculate the monthly payment (in dollars) for each loan. (Round your answers to the nearest cent.)
30-year loan
25-year loan
b) Calculate the savings in interest (in dollars) by using the 25-year loan. (Round your answer to the nearest cent.)
Answer:
a) 30 yr: $1597.75; 25 yr: $1773.75
b) $43065.00
Step-by-step explanation:
The monthly payment for each loan can be found using the amortization formula, or a spreadsheet or calculator. The shorter 25-year loan has fewer and larger payments, but the net result is less interest paid.
a)The attached calculator shows the monthly payments to be ...
30 year loan: $1597.75 monthly
25 year loan: $1773.75 monthly
b)The number of payments is the product of 12 payments per year and the number of years. The total repaid is the monthly payment times the number of payments.
The difference in amounts repaid is the difference in interest charged.
360×1597.75 -300×1773.75 = $43065 . . . . savings using 25-year loan
__
Additional comment
The monthly payment on a loan of principal P at annual rate r for t years is ...
A = P(r/12)/(1 -(1 +r/12)^(-12t))
Some calculators and all spreadsheets have built-in functions for calculating this amount.
Does the following series converge or diverge?
Σ
n=1
4
8√n +7³√n
O The series diverges.
O The series converges.
Answer:
converges
Step-by-step explanation:
the individual fraction terms go against 0 with larger and larger n.
and therefore the sum converges.
the numerator of the fractions stays constant (4) but the denominator (bottom) of the fraction increases more and more with investing n (it does not matter that it uses roots, compared to the constant 4 they too grow immensely large with large n).
the limit of a/infinity is defined as 0.
Which set of ordered pairs represents a function?
{(-6,-4), (1, -7), (-4, 3), (-4, 8)}
{(-8, -3), (-8, 9), (9, 6), (1, -4)}
{(4,1), (-6, 6), (5,-2), (-4,1)}
{(-3, 6), (-1,0), (-8, 1), (-8, -3)}
Answer:
{(4,1), (-6, 6), (5,-2), (-4,1)} set of ordered pairs represents a function.
Step-by-step explanation:
Because every element or component of domain has unique image in co-domain.
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y=3x-2
y=-2x+8 solve this equation
Answer:
x = 2
Step-by-step explanation:
3x - 2 = - 2x + 8
→ Add 2x on both sides
5x - 2 = 8
→ Add 2 on both sides
5x = 10
→ Divide both sides by
x = 2
Answer:
x = 2, y = 4 (2,4)
Step-by-step explanation:
Put both the equation in ax + by = c
-3x + y = -2
2x + y = 8
Find x:
Multiply 8 times 1, -2 by 1, 2 times 1, and -3 by 1
8 - (-) 2/2 - (-) 3 = x
10/5
x = 2
Plug x back into equation:
-3(2)+y = -2
y = 4
IM IN A HURRY PLEASE HELP ME QUESTION IS DOWN BELOW WORTH 15 POINTS each
Answer:
22.34021442
Step-by-step explanation:
22.34021442
3. In AABC, a = 35, c = 25, and m can be drawn given these measurements?
Only one triangle possible with angle 38.2° at C.
According to the given statement
we have to seek out that the measurement of m with the help of the a and c.
Then for this purpose, we all know that the
The ambiguous case occurs when one uses the law of sines to see missing measures of a triangle when given two sides and an angle opposite one in every of those angles (SSA).
According to the this law
The equation become
35/sin(60) = 25/sinC
sinC = 0.6185895741
C = 38.2, 141.8
Since 141.8+60 = 201.8 > 180
It will not form a triangle.
So, only 1 triangle possible with angle 38.2° at C
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Disclaimer: This question was incomplete. Please find the full content below.
Question:
Law of Sines and the Ambiguous Case.
In ∆ ABC, a =35, c = 25, and m < A = 60*
How many distinct triangles can be drawn given these measurements?
Find the range of y=7x-34/x-5
Answer:
Option A
Here you go.
Hope this help!!
Good luck!!
Horizontal asymptote
y=7x/x=7The range is
(-oo,oo)-{7}Or
R-{7}Option A
Consider the spiral curves given parametrically by: (see picture and answer question)
a. The arc length is given by the integral
[tex]L(r) = \displaystyle \int_3^\infty \sqrt{x'(t)^2 + y'(t)^2} \, dt \\\\ ~~~~~~~~ = \int_3^\infty \sqrt{\left(\frac{t\cos(t) - r\sin(t)}{t^{r+1}}\right)^2 + \left(-\frac{t\sin(t) + r\cos(t)}{t^{r+1}}\right)^2} \, dt \\\\ ~~~~~~~~ = \int_3^\infty \sqrt{\frac{(t^2+r^2)\cos^2(t) + (t^2+r^2)\sin^2(t)}{\left(t^{r+1}\right)^2}} \, dt \\\\ ~~~~~~~~ = \boxed{\int_3^\infty \frac{\sqrt{t^2+r^2}}{t^{r+1}} \, dt}[/tex]
b. The integrand roughly behaves like
[tex]\dfrac t{t^{r+1}} = \dfrac1{t^r}[/tex]
so the arc length integral will converge for [tex]\boxed{r>1}[/tex].
c. When [tex]r=3[/tex], the integral becomes
[tex]L(3) = \displaystyle \int_3^\infty \frac{\sqrt{t^2+9}}{t^4} \, dt[/tex]
Pull out a factor of [tex]t^2[/tex] from under the square root, bearing in mind that [tex]\sqrt{x^2} = |x|[/tex] for all real [tex]x[/tex].
[tex]L(3) = \displaystyle \int_3^\infty \frac{\sqrt{t^2} \sqrt{1+\frac9{t^2}}}{t^4} \, dt \\\\ ~~~~~~~~ = \int_3^\infty \frac{|t| \sqrt{1+\frac9{t^2}}}{t^4} \, dt \\\\ ~~~~~~~~ = \int_3^\infty \frac{t \sqrt{1+\frac9{t^2}}}{t^4} \, dt \\\\ ~~~~~~~~ = \int_3^\infty \frac{\sqrt{1+\frac9{t^2}}}{t^3} \, dt[/tex]
since for [tex]3\le t<\infty[/tex], we have [tex]|t|=t[/tex].
Now substitute
[tex]s=1+\dfrac9{t^2} \text{ and } ds = -\dfrac{18}{t^3} \, dt[/tex]
Then the integral evaluates to
[tex]L(3) = \displaystyle -\frac1{18} \int_2^1 \sqrt{s} \, ds \\\\ ~~~~~~~~ = \frac1{18} \int_1^2 s^{1/2} \, ds \\\\ ~~~~~~~~ = \frac1{27} s^{3/2} \bigg|_1^2 \\\\ ~~~~~~~~ = \frac{2^{3/2} - 1^{3/2}}{27} = \boxed{\frac{2\sqrt2-1}{27}}[/tex]
a) The improper integral in simplified form is equal to [tex]L = \int\limits^{\infty}_{3} {\frac{\sqrt{t^{2}+r^{2}}}{t^{r + 1}} } \, dt[/tex].
b) r > 1 for a spiral with finite length.
c) The length of the spiral when r = 3 is (1 - 2√2) / 9 units.
How to characterize and analyze a group of parametric functions
a) The arc length formula for 2-dimension parametric functions is defined below:
L = ∫ √[(dx / dt)² + (dy / dt)²] dt, for [α, β] (1)
If we know that [tex]\dot x (t) = \frac{t \cdot \cos t - r \cdot \sin t}{t^{r+1}}[/tex], [tex]\dot y(t) = \frac{t\cdot \sin t + r\cdot \cos t}{t^{r + 1}}[/tex], α = 0 and β → + ∞ then their arc length formula is:
[tex]L = \int\limits^{\infty}_{3} {\sqrt{\left(\frac{t\cdot \cos t - r\cdot \sin t}{t^{r + 1}}\right)^{2}+\left(\frac{t\cdot \sin t + r\cdot \cos t}{t^{r+1}}\right)^{2}} } \, dt[/tex]
By algebraic handling and trigonometric formulae (cos ² t + sin² t = 1):
[tex]L = \int\limits^{\infty}_{3} {\frac{\sqrt{t^{2}+r^{2}}}{t^{r + 1}} } \, dt[/tex] (2)
The improper integral in simplified form is equal to [tex]L = \int\limits^{\infty}_{3} {\frac{\sqrt{t^{2}+r^{2}}}{t^{r + 1}} } \, dt[/tex].
b) By ratio comparison criterion, we notice that √(t² + r²) is similar to √t² = t and [tex]\frac{\sqrt{t^{2}+r^{2}}}{t^{r + 1}}[/tex] is similar to [tex]\frac{t}{t^{r +1}} = \frac{1}{t^{r}}[/tex].
The integral found in part a) has a finite length if and only the governing grade of the denominator is greater that the governing grade of the numerator. and according to the ratio comparson criterion, the absolute value of the ratio is greater than 0 and less than 1. Therefore, r > 1 for a spiral with finite length.
c) Now we proceed to integrate the function:
L = ∫ [√(t² + 9) / t⁴] dt, for [3, + ∞].
L = ∫ [t · √(1 + 9 / t²) / t⁴] dt, for [3, + ∞].
By using the algebraic substitutions: u = 1 + 9 / t², du = - (18 / t³) dt → - (1 / 18) du.
L = ∫ √u du, for [3, + ∞].
L = - (1 / 9) · √(u³), for [3, + ∞].
L = - (1 / 9) · [√(1 + 9 / t²)³], for [3, + ∞].
L = - (1 / 9) · [√(2³) - √(1³)]
L = - (1 / 9) · (2√2 - 1)
L = (1 - 2√2) / 9
The length of the spiral when r = 3 is (1 - 2√2) / 9 units.
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Point A and B are respectively 20m north and 48m east of point c.find the distance AB
Answer:
[tex]\boxed {AB = 52 m}[/tex]
Step-by-step explanation:
This forms a right triangle.
Therefore, by using the Pythagorean Theorem, we can find AB.
AB = √AC² + BC²
AB = √(20)² + (48)²AB = √400 + 2304AB = √2704AB = 52mI hope it helped you solve the problem.
Good luck on your studies!
Answer: Distance AB = 52 m
Step-by-step explanation:
Given information
Point A = 20 m north of point C
Point B = 48 m east of point C
Please refer to the attachment below for a graphical understanding
Concept
According to the graph drawn, Point A, Point B, and Point C form a right angle, and the distance between Point A and B would form a right triangle.
Therefore, we can use the Pythagorean theorem to find the distance between points A and B.
Given formula
a² + b² = c²
a = distance between point A and point Cb = distance between point B and point Cc = distance between point A and point BSubstitute values into the formula
a² + b² = c²
(20)² + (48)² = c²
Simplify exponents
400 + 2304 = c²
Simplify by addition
2704 = c²
c = √2704
c = 52 or c = -52 (reject, since no distance can be negative)
Therefore, the distance AB is [tex]\Large\boxed{52~m}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
6. Find the mean, median, and mode of the set of
numbers: 6, 7, 11, 5, 8, 7, 4, 13, 11, 2.
Answer:
Mean 7.4
Median 7
Mode 7, 11
Step-by-step explanation:
Let me know if this is correct!
Answer: 7.4, 7, 7 and 11
Step-by-step explanation:
The mean is the sum of all the numbers divided by the number of numbers. In this case, there are 10 numbers.
[tex]Mean=\frac{6+7+11+5+8+7+4+13+11+2}{10}=\frac{74}{10}=7.4[/tex]
The median is the number (or the average of the two numbers) in the middle of the set when it is ordered in ascending order. Let's first order it from least to greatest.
[tex]2,4,5,6,7,7,8,11,11,13[/tex]
The two middle numbers are 7 and 7. The median is the mean of these two numbers.
[tex]Median=\frac{7+7}{2}=\frac{14}{2}=7[/tex]
The mode is the number that is most repeated number in the set. The numbers 7 and 11 are repeated twice. Hence, the modes are 7 and 11.
Someone please help with this question asap!
Answer:
Side b is the longest because the longer side always lie opposite the bigger angle. Angle B is the biggest angle, and since side b is opposite angle B, side b is the longest.
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
The side opposite to the largest angle is the longest side of a triangle.
[tex] \qquad \large \sf {Conclusion} : [/tex]
hence, we can conclude that the longest side is b
( since it's opposite angle is the largest, i.e 91° )
Service Department Charges and Activity Bases
Middler Corporation, a manufacturer of electronics and communications systems, uses a service department charge system to charge profit centers with Computing and Communications Services (CCS) service department costs. The following table identifies an abbreviated list of service categories and activity bases used by the CCS department. The table also includes some assumed cost and activity base quantity information for each service for October.
CCS Service
Category
Activity Base
Budgeted Cost Budgeted Activity
Base Quantity
Help desk Number of calls $160,000 3,200
Network center Number of devices monitored 735,000 9,800
Electronic mail Number of user accounts 100,000 10,000
Smartphone support Number of smartphones issued 124,600 8,900
One of the profit centers for Middler Corporation is the Communication Systems (COMM) sector. Assume the following information for the COMM sector:
• The sector has 5,200 employees, of whom 25% are office employees.
• All the office employees have been issued a smartphone, and 96% of them have a computer on the network.
• One hundred percent of the employees with a computer also have an e-mail account.
• The average number of help desk calls for October was 1.5 calls per individual with a computer.
• There are 600 additional printers, servers, and peripherals on the network beyond the personal computers.
a. Determine the service charge rate for the four CCS service categories for October.
CCS Service Category Service Charge Rate
Help desk $fill in the blank 1
Per call
Network center $fill in the blank 3
Per device monitored
Electronic mail $fill in the blank 5
Per user or e-mail account
Smartphone support $fill in the blank 7
Per smartphone issued
b. Determine the charges to the COMM sector for the four CCS service categories for October.
October charges to the COMM sector
Help desk charge $fill in the blank 9
Network center charge $fill in the blank 10
Electronic mail charge $fill in the blank 11
Smartphone support charge $fill in the blank 12
Feedback Area
Feedback
a
The answers to the question are:
50751014a. How to determine the service charge rate for the month of OctoberThis is the number of calls for the help desk
160000/3200 = 50per call
network center
735000/9800
= 75 per device that was monitored
Electronic mail
100000/10000 =
10 for the mail account
For smart phone support
124600/8900
= 14 per phone extension
b. Charges to the COMM sectorfor helpdesk
5200 * 0.25 * 0.96 *1.5 calls * $50
= 93600
For network center
(5200 * 0.25 * 0.96) + 600] x 75
= 138600
For Electronic mail
5200 * 0.25 * 0.96 * 10 per email account
= 12480
Smart support charge
5200 * 0.25 * 14 = 18200
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Earlier in this course, you explored Euclidean geometry, which is the study of flat space. This approach follows the teachings of Euclid, in which he describes the relationships between points, lines, and planes without any numerical measurement. You saw evidence of Euclidean geometry inside several proofs and geometric constructions.
In contrast, the focus of this unit is understanding geometry using positions of points in a Cartesian coordinate system. The study of the relationship between algebra and geometry was pioneered by the French mathematician and philosopher René Descartes. In fact, the Cartesian coordinate system is named after him. The study of geometry that uses coordinates in this manner is called analytical geometry.
It’s clear that this course teaches a combination of analytical and Euclidean geometry. Based on your experiences so far, which approach to geometry do you prefer? Why? Which approach is easier to extend beyond two dimensions? What are some situations in which one approach to geometry would prove more beneficial than the other? Describe the situation and why you think analytical or Euclidean geometry is more applicable.
The Elements can be defined as a mathematical treatise which comprises 13 books that are attributed to the ancient Greek mathematician who lived in Alexandria, Ptolemaic Egypt c. 300 BC and called Euclid.
Basically, the Elements is a collection of the following geometric knowledge and observations:
DefinitionsPostulatesPropositionsMathematical proofs of the propositions.Based on my experiences so far, an approach to geometry which I prefer is Euclidean geometry because it's much easier than analytical geometry. Also, an approach that is easier to extend beyond two-dimensions is Euclidean geometry because it can be extended to three-dimension.
A situation in which one approach to geometry would prove to be more beneficial than the other is when dealing with flat surfaces. In Euclidean geometry, a correspondence can be established between geometric curves and algebraic equations.
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Define the linear programming problems. State the key terms in L.P.P.
Answer:
Step-by-step explanation:
Linear Programming Problems (LPP): Linear programming or linear optimization is a process which takes into consideration certain linear relationships to obtain the best possible solution to a mathematical model. It is also denoted as LPP. It includes problems dealing with maximizing profits, minimizing costs, minimal usage of resources, etc. These problems can be solved through the simplex method or graphical method.
Linear Programming For Class 12
Linear Programming
Linear Programming Worksheet
The Linear programming applications are present in broad disciplines such as commerce, industry, etc. In this section, we will discuss, how to do the mathematical formulation of the LPP.
Mathematical Formulation of Problem
Let x and y be the number of cabinets of types 1 and 2 respectively that he must manufacture. They are non-negative and known as non-negative constraints.
The company can invest a total of 540 hours of the labour force and is required to create up to 50 cabinets. Hence,
15x + 9y <= 540
x + y <= 50
The above two equations are known as linear constraints.
Let Z be the profit he earns from manufacturing x and y pieces of the cabinets of types 1 and 2. Thus,
Z = 5000x + 3000y
Our objective here is to maximize Z. Hence Z is known as the objective function. To find the answer to this question, we use graphs, which is known as the graphical method of solving LPP. We will cover this in the subsequent sections.
Graphical Method
The solution for problems based on linear programming is determined with the help of the feasible region, in case of graphical method. The feasible region is basically the common region determined by all constraints including non-negative constraints, say, x,y≥0, of an LPP. Each point in this feasible region represents the feasible solution of the constraints and therefore, is called the solution/feasible region for the problem. The region apart from (outside) the feasible region is called as the infeasible region.
The optimal value (maximum and minimum) obtained of an objective function in the feasible region at any point is called an optimal solution. To learn the graphical method to solve linear programming completely reach us.
Linear Programming Applications
Let us take a real-life problem to understand linear programming. A home décor company received an order to manufacture cabinets. The first consignment requires up to 50 cabinets. There are two types of cabinets. The first type requires 15 hours of the labour force (per piece) to be constructed and gives a profit of Rs 5000 per piece to the company. Whereas, the second type requires 9 hours of the labour force and makes a profit of Rs 3000 per piece. However, the company has only 540 hours of workforce available for the manufacture of the cabinets. With this information given, you are required to find a deal which gives the maximum profit to the décor company.
Linear Programming problem LPP
Given the situation, let us take up different scenarios to analyse how the profit can be maximized.
He decides to construct all the cabinets of the first type. In this case, he can create 540/15 = 36 cabinets. This would give him a profit of Rs 5000 × 36 = Rs 180,000.
He decides to construct all the cabinets of the second type. In this case, he can create 540/9 = 60 cabinets. But the first consignment requires only up to 50 cabinets. Hence, he can make profit of Rs 3000 × 50 = Rs 150,000.
He decides to make 15 cabinets of type 1 and 35 of type 2. In this case, his profit is (5000 × 15 + 3000 × 35) Rs 180,000.
Similarly, there can be many strategies which he can devise to maximize his profit by allocating the different amount of labour force to the two types of cabinets. We do a mathematical formulation of the discussed LPP to find out the strategy which would lead to maximum profit.
PLEASE HELP ME QUICK
In the diagram, points D and E are marked by drawing arcs of equal size centered at B such that the arcs intersect BA and BC
Then, intersecting arcs of equal size are drawn centered at points D and E. Point P is located at the intersection of these arcs.
Based on this construction, m∠ABP is ANSWER ° and m∠ABC is ANSWER°
Answer:
m∠ABP is 32°,m∠ABC is 64°.Step-by-step explanation:
According to the construction we have:
BD = BEPD = PEBP - is common side of triangles BPD and BPEIt gives us:
ΔPBD ≅ ΔPBEThen, corresponding angles of congruent triangles are congruent:
∠DBP ≅ ∠EBPSo,
∠ABP ≅ ∠CBP ⇒ m∠ABP = 32°Then,
m∠ABC = m∠ABP + m∠CBP = 32° + 32° = 64°What value of b will cause the system to have an infinite number of solutions y=6x+b
-3x+1/2y=-3
A-(-6)
B(-3)
C(3)
D(6)
Answer: -6
Step-by-step explanation:
[tex]-3x+\frac{1}{2}y=-3\\\\\frac{1}{2}y=3x-3\\\\y=6x-6[/tex]
For there to be infinite solutions, b = -6.
Find the area of the trapezoid 19 12.6 29.2 14.5
Answer:
303.66 in²
Option 4 is the correct answer
Suppose Z follows the standard normal distribution. Use the calculator provided, or this table, to determine the value of so that the following is true.
P(-0.78≤Z≤c)=0.7657
For a standard normal distribution, the value of the z-score represented as c in P(-0.78≤Z≤c)=0.7657 is 0.0166
How to find the p-value from 2 z-scores?We want to find the p-value between 2 z-scores expressed as;
P(-0.78 < z < c) = 0.7657
To solve this, we will solve it as;
0/7657= 1 - [P(z < -0.78) + P(z > c)]
From normal distribution table, we have that;
P(z < -0.78) = 0.217695
Thus;
0.7657 = 1 - (0.217695 + c)
c = 1 - 0.7657 - 0.217695
c = 0.0166
Thus, For a standard normal distribution, the value of the z-score represented as c in P(-0.78≤Z≤c)=0.7657 is 0.0166
Read more about p-value from z-score at; brainly.com/question/4621112
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!!!!!!!!! Helppppppp plsssss
Answer:
(6 / 4) * (7 + 9)
Step-by-step explanation:
sry that took me so long lol
Select all the correct graphs.
Choose the graphs that indicate equations with no solution.
The graph first, and the graph fifth have no solution because there are no intersection options (A) and (E) are correct.
What is a function?It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
It is given that:
The graph of equations is shown in the graph.
As we know, if two equations of a function intersect on the coordinate plane that means they have a solution.
If there will be no intersection then the equations have no solution.
Thus, the graph first, and the graph fifth have no solution because there are no intersection options (A) and (E) are correct.
Learn more about the function here:
brainly.com/question/5245372
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If you are taking a 3 credit college class and fail, and you have a 3.3 GPA. How mush will it affect it?
Answer:
it depend on your total credit load u register, if it's d only credit load it affect your gpa alot
it took a 3D priner 10528 minutes to print 87 percent of a 3D print job. At this rate of speed how much time will take for the print to
reach 100 percent completion?
The time it would take for the print to reach 100 percent completion is 12,101 minutes 9 seconds.
What is time it would take to reach 100%?The mathematical operations that would be used to determine the required value are division and multiplication. Division is the process of grouping a number into equal parts using another number. The sign used to denote division is ÷. Multiplication is the process of determining the product of two or more numbers. The sign used to denote multiplication is ÷.
Other mathematical operations that are used to solve problems include addition and subtraction.
Time it would take to reach 100% completion = (minutes it takes to print 87% of the words x 100%) / 87%
Time it would take to reach 100% completion = (10,528 x 1) / 0.87 =
10.528 / 0.87
= 12,101. 15
= 12,101+ (0.15 x 60)
= 12,101 minutes 9 seconds
To learn more about division, please check: https://brainly.com/question/13281206
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