The human body has an average density of 979 kg/m3 , what fraction of a person is submerged when floating gently in fresh water?

Answer:

See below

Explanation:

X component = 120 * cos 35° =  98.298 m/s

Y component = 120 * sin 35° = 68.829 m/s

Any object launched into space with only gravity acting on it is referred to as a projectile. Gravity is the main force affecting a projectile. The x and y components of the velocity vector are 98.298 m/s and 68.829 m/s.

When a particle is thrown obliquely close to the Earth's surface, it travels along a curving route while experiencing constant acceleration. Always pointing in the direction of the Earth's center is this curving path. Such a particle's motion is referred to as projectile motion, and its trajectory is known as the projectile's trajectory.

The components of the projectile are:

X component = 120 × cos 35° =  98.298 m/s

Y component = 120 × sin 35° = 68.829 m/s

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In a spectrophotometer, a prism or diffraction grating separates light into its constituent wavelengths.

To find the answer, we need to know more about the spectrometer.

Thus, we can conclude that, In a spectrophotometer, a prism or diffraction grating separates light into its constituent wavelengths.

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Answer:

D.  Sound

Explanation:

Waves: one of the ways that energy may be transferred. Waves can be described as oscillations.

Electromagnetic (EM) waves are transverse waves.

EM waves can be separated into seven groups in the spectrum.  From long wavelength to short wavelength:

Sound waves are longitudinal waves.

The direction of oscillations is different between longitudinal and transverse waves:

Answer:

Sound

Explanation:

EN waves are known as electromagnetic waves

They are divided into seven parts

We can only watch Visible light not others .

Sound is not transverse wave

Current in the inductor, I = 100A

Given,

Magnetic potential energy stored, U= 30 joule

Inductance, L = 6.0 H

Therefore, current in the inductor, [tex]I^{2}[/tex]= (2×30×10^3) ÷ 6

                                                           = 2×5×10^3

                                                           = 10×10^3

                                                   [tex]I^{2}[/tex]       = 10000

                                                   I        = √10000

                                                  I        = 100A

Concept:-

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shifting of the frequency will take place by 1.674 × 10¹² Hz.

Frequency is a unit of measurement for how frequently a recurrent event, like a wave, takes place over a specified period of time. A cycle is one repetition of the repeating pattern. Frequency only exists in moving waves that change their places throughout time. Frequency is one way to define how fast a wave moves.

Δλ/λ₀ = v/c

Relativistic doppler effect,

[tex]v' = v_{0} \frac{ \sqrt{ 1 - v/c}}{ \sqrt{ 1 + v/c}}[/tex]

[tex]\frac{v}{c}= \frac{7.16}{3000}[/tex]

[tex]v'= 6.91 * 10^{14} * \frac{\sqrt{1 -\frac{7.16}{3000} } }{\sqrt{1-\frac{7.16}{3000} } }[/tex]

[tex]v'=6.893 * 10^{14}[/tex]

[tex]|v'-v_{0}|= 1.647 * 10^{12}[/tex]

shifting of the frequency will take place by 1.674 × 10¹² Hz.

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The lower-mass star should have developed into a giant star.

Algol variables, also known as Algol-type binaries, are a subclass of eclipsing binary stars that resemble Persei, the class's prototype star (Beta Persei, Algol). An Algol binary is a system in which both stars are almost spherical, making it possible to precisely predict when the eclipses would begin and conclude. Usually, the primary is a main-sequence star that is located close to its Roche lobe. The secondary star might be either an evolved star occupying its Roche lobe, known as a semidetached binary, or it could be a main sequence star, known as a detached binary.

eclipsing variable stars-

One of the most well-known variable stars in the sky, Algol serves as the model for the Algol variables class of eclipsing variable stars. A B-class main sequence star, an orange subgiant, and a faint A-class star make up the triple star system known as Beta Persei Aa1, Aa2, and Ab.

The lower-mass star should have developed into a giant star first, followed by the higher-mass B main-sequence star.

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Answer:

W = m g h        work that must be done on car

P = W / t       power that must be input (in Watts)

P = m g h / t = 1500 kg * 9.8 m/s^2 * 360 m /  60 sec

P = 88,200 watts

P = 88,200 watts / 746 watts / hp = 118 hp

The horsepower of a 1,500 kg car that can go to the top of a 360 m high hill in exactly 1 min is 118.23 hp.

To find the power, the given values are,

Mass m = 1500 kg

Height h = 360 m

Time t = 1 minute = 60 seconds

g = 9.8 m/s

Power is the amount of work that is done per unit of time. It can be associated with the speed of a change of energy within a system, or the time it takes to perform a job.

There are different types of power,

Formula for Power is,

Power = mgh/t

Power = (1500 x 9.8 x 360)/60

Power = 8.8 x 10⁴ watts

Recall

746watts = 1hp

8 x 10⁴ watts = 8 x 10⁴ / 746

Power = 118.23 hp

Thus, Power was calculated as 118.23 hp.

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The hydrogen fusion process will begin after the protostar reaches a temperature of 10 million degrees kelvin, and it will then turn into a stable star.

The interstellar medium can sometimes be gathered into a large nebula, which is a cloud of gas and dust. A nebula can span a number of light years. These nebulae are where gas and dust can combine to produce stars. Until a star can combine hydrogen into helium, it cannot be considered a star. They are referred to as protostars before then. As gravity starts to gather the gases into a ball, a protostar is created. Accrution is the term for this procedure.

Gravitational energy starts to heat the gasses as gravity draws them into the ball's core, which causes the gasses to radiate radiation. Radiation initially just dissipates into space. However, much of the radiation is retained inside the protostar as it draws in stuff and becomes denser, which causes the protostar to heat up even more quickly.

The hydrogen fusion process will begin after the protostar reaches a temperature of 10 million degrees kelvin, and it will then turn into a star.

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The length of a box in which the minimum energy of an electron is 1. 1×[tex]10^{-18}[/tex] j will be 74 * [tex]10^{-10}[/tex] m

Energy levels (also called electron shells) are fixed distances from the nucleus of an atom where electrons may be found. As you go farther from the nucleus, electrons at higher energy levels have more energy

Energy levels (also called electron shells) are fixed distances from the nucleus of an atom where electrons may be found. Electrons are tiny, negatively charged particles in an atom that move around the positive nucleus at the center. Energy levels are a little like the steps of a staircase.

One electron volt is the energy that an electron gains when it travels through a potential difference of one volt (1 eV = 1.6 x 10-19 Joules). Electrons in a hydrogen atom must be in one of the allowed energy levels. If an electron is in the first energy level, it must have exactly -13.6 eV of energy.

Energy of an electron in nth shell can be calculated as

E (n) = [tex]\frac{n^{2} h^{2} }{8ml^{2} }[/tex]

energy will be minimum in 1st shell

putting n=1

E (n) = [tex](1)^{2}[/tex] *  [tex](6.63 * 10^{-34}) ^{2}[/tex] / 8 * 9.1 * [tex]10^{-31}[/tex] * [tex]l^{2}[/tex]

1.1 * [tex]10^{-18}[/tex] =  [tex](1)^{2}[/tex] *  [tex](6.63 * 10^{-34}) ^{2}[/tex] / 8 * 9.1 * [tex]10^{-31}[/tex] * [tex]l^{2}[/tex]

length(l)  = 74 * [tex]10^{-10}[/tex] m

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Yes , principle of optical reversibility hold for reflection as well as refraction

Reflection involves a change in direction of waves when they bounce off a barrier. Refraction of waves involves a change in the direction of waves as they pass from one medium to another. Refraction, or the bending of the path of the waves, is accompanied by a change in speed and wavelength of the waves.

The principle of reversibility of light states that light follows the same path if the direction of the travel of light is reversed.

This means that if a light ray travels from medium 1 to medium 2 and has angle of incidence and angle of refraction as i and r respectively, then if the light is incident from medium 2 at an angle r, then the angle of refraction in medium 1 will be i.

The principle of reversibility presumes that the attenuation of a light ray during its passage through an optical medium because of reflection, refraction, and absorption is not affected by a reversal of the direction of the ray.

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The pressure drop in pascal is 3.824*10^4 Pascals.

To find the answer, we need to know about the Poiseuille's formula.

                      [tex]Q=\frac{\pi Pr^4}{8\beta l}[/tex]

where, Q is the rate of flow, P is the pressure drop, r is the radius of the pipe, [tex]\beta[/tex] is the coefficient of viscosity (0.95Pas-s for Glycerin) and l being the length of the tube.

                [tex]Q=8*10^{-6}m^3/s\\diameter=30mm, thus,\\r=15mm\\l=100m\\\beta =0.95[/tex]

                [tex]P=\frac{8Q\beta l}{\pi r^4} =\frac{8*8*10^{-6}*0.95*100}{3.14*(15*10^{-3})^4} \\\\P=3.824*10^4Pascals.[/tex]

Thus, we can conclude that, the pressure drop in pascal is 3.824*10^4 Pascals.

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The kinetic energy is 1.8 × 10^ -1 J.

Rolling items each rotate and have linear (or translational) movement. consequently, they've both linear and rotational kinetic power. since the rotational kinetic strength of a rolling object depends at the inertia of the item.

The only kinetic energy involved here is rotational kinetic energy.

Kinetic Energy (Rotational) = 1/2Iω²

I = Moment of Inertia of a thin hoop =(Mass)(Radius)2

Mass = 3.0 kg

Radius = 10 cm = 0.10 m

ω = angular speed = 3.5 rad/s

Kinetic Energy (Rotational) = 1/2 * 3 * 12.25 J.

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The Kinetic energy is of thin hoop can be found out using the formulas of Rotational Kinetic Energy. The Kinetic Energy of the hoop is 18.375J.

Rolling items rotate and have linear or translational movement. consequently, they have both linear and rotational kinetic power. Since the rotational kinetic strength of a rolling object depends on the Inertia of the item.

The only kinetic energy involved here is Rotational Kinetic Energy.

Rotational Kinetic Energy = 1/2Iω²

where, I = Moment of Inertia of a thin hoop =(Mass)(Radius)²

              where, Mass of hoop, m = 3.0 kg

                           Radius of loop, R = 10 cm = 0.10 m

                           Angular speed, w= 3.5 rad/s

Since, Rotational Kinetic Energy = 1/2 × 3 × 12.25 J.

             Rotational Kinetic Energy = 18.375J

Hence, Rotational Kinetic Energy is 18.375J

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Answer:

The Object distance is 53.125cm. So the right option will be Option (c)

Explanation:

The converging lens has focal length positive, so it means:

            f=17cm

As the real image is formed so the distance of the image will be taken as positive. Let it is represented by q, So:

           q=25cm

Let the distance of object is p, it will obtained from the following formula:

If the heart is beating at 76. 0 beats per minute, the Frequency of heart's oscillations in hertz is 1.25 Hertz.

The Frequency is defined as the number of oscillations completed in 1s.

Our heart beats continuously giving rise to the frequency of the heart.

Measuring frequency would be possible if we measure the time in seconds.

75 beats per minute means that 75 beats occur in 60s.

Frequency = Number of beats / Total time taken

Frequency = 75 / 60

Frequency = 1.25 Hz

Hence, number of beats per second is 1.25 Beats.

Beats per second or Cycles per second is same as the frequency of oscillation called as Hertz (Hz)

Hence, frequency of the heart oscillation is 1.25 Hertz (Hz).

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Answer:

The age of the sample will decrease by 1/2 for each half-life that the sample undergoes:

1/2 * 1/2 * 1/2 = 1/8

The data indicates that the sample has undergone 3 half-lives of decay

3 * 5730 = 17190 yrs is the approximate age of the sample

The statement given about the critical path is true.

To find the answer, we have to know more about the critical path.

Thus, we can conclude that, the statement given about the critical path is true.

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The speed of an observer be if a red (4. 688 × 1014 hz) traffic light appeared green (5. 555 × 1014 hz) to the observer is 0.185v using doppler effect

Utilize the approximation of the Doppler shift formula, (delta f)/f = V/c, for V/c 1 to determine which V on the list is closest. It's a little trickier to calculate the precise Doppler shift formula for light. Use what you are aware of. It is often exclusively covered in relativity theory classes. The formula for the Doppler shift of sound heard by a moving observer is NOT the same.

5.551*107 m/s = (Delta f)/f = 0.185 V.

Doppler radar transmits energy in pulses and detects any signal that is returned. The "Doppler shift" seen with sound waves is comparable to the phase shift effect. Due to compression (a change in phase) of sound waves, the "Doppler shift" causes the sound pitch of an item traveling toward you to be higher.

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When conducting a hypothesis test there are two possible decisions  that you can make: reject the null hypothesis or fail to reject the null hypothesis.

A statistical hypothesis test is a method of statistical inference used to decide whether the data at hand sufficiently support a particular hypothesis. Hypothesis testing allows us to make probabilistic statements about population parameters.

When conducting a hypothesis test there are two possible decisions: reject the null hypothesis or fail to reject the null hypothesis. You should remember though, hypothesis testing uses data from a sample to make an inference about a population. When conducting a hypothesis test we do not know the population parameters. In most cases, we don't know if our inference is correct or incorrect.

When we reject the null hypothesis there are two possibilities. There could really be a difference in the population, in which case we made a correct decision. Or, it is possible that there is not a difference in the population (i.e.,  is true) but our sample was different from the hypothesized value due to random sampling variation. In that case we made an error. This is known as a Type I error.

When we fail to reject the null hypothesis there are also two possibilities. If the null hypothesis is really true, and there is not a difference in the population, then we made the correct decision. If there is a difference in the population, and we failed to reject it, then we made a Type II error.

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A atomic neutron particle that is attracting another atomic neutron is an example of the strong nuclear force acting in an atom (Option B).

The expression 'nuclear forces' makes reference to the attraction between different subatomic particles in a given nucleus of a particular atom, which represents the strongest force in the universe.

Subatomic particles include positively charged particles (i.e., protons), neutrally charged particles called neutrons, and electrically negative charged particles called electrons (e-).

In conclusion, a atomic neutron particle that is attracting another atomic neutron is an example of the strong nuclear force acting in an atom (Option B).

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Your car may hydroplane at speed as low as 56 Kilometer per hour

Hydroplaning occurs mostly during the raining period. When the tire of the car continue to loose grip and start skidding on the road surface.

It is true that water on the road can cause a vehicle to hydroplane. And your car may hydroplane at speeds as low as 35 mile per hour or approximately 56 kilometer per hour.

The three main factors of the car hydroplaning are;

Therefore, your car may hydroplane at speeds as low as 56 Kilometer per hour approximately.

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The frequency of the re-emitted light is identical to that of the absorbed light.

To find the answer, we need to know more about the frequency of light.

                              [tex]frequency=\frac{c}{wave length}[/tex] , c is the speed of light.

Thus, we can conclude that, the re-emitted light's frequency matches the absorbed light's frequency.

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The concentration of the acute leukemia cc95 combination value in micromolar (μm) units is  6 × 10-4 μM.

Acute lymphocytic leukemia (ALL) is also called acute lymphoblastic leukemia. “Acute” means that the leukemia can progress quickly, and if not treated, would probably be fatal within a few months. "Lymphocytic" means it develops from early (immature) forms of lymphocytes, a type of white blood cell.

A rapidly progressing cancer that starts in blood-forming tissue such as the bone marrow, and causes large numbers of white blood cells to be produced and enter the blood stream.

In acute leukemia, the abnormal blood cells are immature blood cells (blasts). They can't carry out their normal functions, and they multiply rapidly, so the disease worsens quickly. Acute leukemia requires aggressive, timely treatment.

This corresponds to 0.6 × 10^-9 M × (1 μM/1 × 10^-6 M) = 0.6 × 10^-3 μM = 6 × 10-4 μM.

Acute myeloid leukemia (AML) is caused by a DNA mutation in the stem cells in your bone marrow that produce red blood cells, platelets and infection-fighting white blood cells. The mutation causes the stem cells to produce many more white blood cells than are needed.

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A collection of a fixed number of elements (called components) arranged in n dimensions ( n >= 1) is called a(n) n- dimensional array

an array of dimensions gives Information about the material composition for each point in the heterogeneous part is stored in N.

Similar to a one-dimensional array, a two-dimensional array is represented graphically as a grid (or table) with rows and columns.

A big gathering of objects or people is referred to as a "array," especially one that is eye-catching, inspires admiration, or has been arranged in a particular way: The spread of food on the table was magnificent. They were seated in front of numerous microphones and cameras. Related words and phrases are part of the SMART Vocabulary. Things in groups and collections

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Answer: Nothing

Explanation:

The supplied energy is used for phase transition, not molecule kinetic energy.

Example: ice cannot be heated above 0Cº when it is being melted. Heat is consumed for phase change during its transition from solid to liquid. Only after all ice has melted, the temperature will rise until the next phase transition - vapor.

9 × 10²¹ electrons flow through a cross section of the wire in one hour.

= 1440 C

= 9 × 10²¹ electrons

Thus, we can conclude that the 9 × 10²¹ electrons flow through a cross section of the wire in one hour.

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Answer:

Kinetic energy doubles

Compare two separate regions of space. the electrical potential energy is the same in both regions. if the amount of charge in one region is larger, then potential in that region must be smaller.

The basic difference between electric potential and electric potential energy is that Electric potential at a point in an electric field is the amount of work done to bring the unit positive charge from infinity to that point, while electric potential energy is the energy that is needed to move a charge against the electric field.

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The shortest wavelength in the paschen series= [tex]8.2\times 10^{-7}[/tex] m.

Emission lines for hydrogen occur when electrons drop from some energy level to a lower energy level. To calculate the shortest wavelength in the paschen series we are using the formula,

[tex]\frac{1}{\lambda} =R_{H} (\frac{1}{n_{f}^{2} }-\frac{1}{n^{2} } )[/tex]

Here, we are given,

[tex]R_{H}[/tex]= Rydberg constant=[tex]1.09737 \times 10^{7} m^{-1}[/tex]

[tex]n_f[/tex]= The lower energy level quantum number.=3 (for the paschen series).

n= The quantum number of whichever state the transitions occur from = (for this case of the paschen series).

We have to find the wavelength associated with the photon emitted = [tex]\lambda[/tex] m.

Now we substitute the known values in the above equation, we can find that,

[tex]\frac{1}{\lambda} =1.09737 \times 10^{7} (\frac{1}{3^2 }-\frac{1}{\infty^{2} } )[/tex]

Or,[tex]\frac{1}{\lambda} =1.09737 \times 10^{7}\times \frac{1}{9 }[/tex]

Or,[tex]\frac{1}{\lambda} =1,219,300[/tex]

Or,[tex]\lambda= 8.2\times 10^{-7}[/tex] m

From the above calculation we can conclude that the shortest wavelength in the paschen series is [tex]8.2\times 10^{-7}[/tex] m

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