The amount of heat transferred from an object depends on
Group of answer choices

A. The initial temperature of the object

B. All of the above

C. The specific heat of the object

D. The mass of the object

Answer:

Silver

Explanation:

What mass of copper was discharge at the cathode in a cell

Answer:

is a solution whose pH is above 7or is a basic solution

Answer:

D

Explanation:

Grinding to a powder increases the surface area of the charcoal .

The reaction of charcoal (carbon) and oxygen is sped up by grinding the charcoal into a fine powder. This is an example of increasing surface area to increase reaction rate. Option D is the answer.

Grinding charcoal into a fine powder enhances its reactivity by increasing surface area. This finer texture promotes more frequent collisions between charcoal particles and oxygen molecules, facilitating faster chemical reactions.

The heightened contact points enable efficient utilization of reactants, optimizing resource consumption. Shorter diffusion paths within smaller particles expedite reactant diffusion, aiding quicker reaction rates.

Additionally, the augmented surface area promotes efficient heat transfer, crucial in reactions involving temperature changes.

Grinding charcoal amplifies the reaction rate by maximizing interaction opportunities, accelerating the conversion of charcoal and oxygen into products.

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First base abstract a proton from acidic hydrogen gives carbanion.

What is a carbon atom?

Here First base abstract, a proton from acidic hydrogen gives carbanion

Which undergoes enolate form, then it reacts with CH3I, gives4-methyl-3-hexanone as below:

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Taking into account the definition of Avogadro's number and molar mass, 4.806 grams of water are present in 1.61×10²³ molecules.

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

Taking into account the definition of Avogadro's Number, you can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of water, then 1.61×10²³ molecules are contained in how many moles of water?

amount of moles of water= (1.61×10²³ molecules× 1 mole)÷ 6.023×10²³ molecules

amount of moles of water= 0.267 moles

Now, taking into account the definition of molar mass, and knowing that the molar mass of water is 18 g/mole, you can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 18 grams, 0.267 moles of the compound contains how much mass?

[tex]mass= \frac{0.267 molesx 18 grams}{1 mole}[/tex]

mass= 4.806 grams

Finally, 4.806 grams of water are present in 1.61×10²³ molecules.

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Answer:

Strong Acid

Explanation:

Hope this helps! :)

Answer:

The balanced equation is 5Fe2++MnO-4+8H+→5Fe3++Mn2++4H2O .

Explanation:

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Answer:

5Fe2++MnO-4+8H+→5Fe3++Mn2++4H2O .

Explanation:

Answer:

61 atm

Explanation:

You can calculate osmotic pressure using the following equation:

π = i MRT

In this equation,

-----> π = osmotic pressure (atm)

-----> i = van't Hoff's factor

-----> M = molarity (M)

-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)

-----> T = temperature (K)

The van't Hoff's factor is the amount of ions the substance dissociates into. Since sugar does not dissociate, this value is 1. After converting Celsius to Kelvin, you can plug the values into the equation and simplify.

i = 1                                 R = 0.08206 atm*L/mol*K

M = 2.5 M                      T = 25 °C + 273.15 = 298.15 K

π = i MRT

π = (1)(2.5 M)(0.08206 atm*L/mol*K)(298.15 K)

π = 61 atm

The gases have no definite shape, low density, and are highly compressible while the liquids only have a definite volume but no definite shape.

Any substance which has mass and occupies space is called matter. Commonly, there are three states of matter that are:

There are other two states of matter that are Plasma and man-made Bose-Einstein condensates. They are not so common.

Plasma is commonly found in the universe. Stars are the superheated balls of the plasma.

Thus, gases have no definite shape, low density, and are highly compressible. On the other hand, the liquids only have a definite volume but no definite shape.

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The condition that will increase the entropy in a reaction is heating up the reaction (option B).

Entropy in chemistry is the measure or degree of the disorder or randomness present in a chemical system.

In a chemical reaction, reacting substances called reactants collide with one another to form products.

However, the degree at which the reactants collide with one another is referred to as the entropy of the reaction.

Therefore, the condition that will increase the entropy in a reaction is heating up the reaction i.e. increase in temperature.

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The answer will be - 1.67 x [tex]10^{-6[/tex]

The problem can be solved by using the rule of BODMAS.

21-4/1002-730+83920/839

First, the operation is divided into 3 parts

For the first part:

    21 - 4 = 17

For the second part:

1002-730+83920

According to BODMAS, addition operations come before subtractions.

So, the operation becomes (1002)-(730+83920)

  = (1002) - (84650)  

     = -83648

The entire operation becomes 17/-83648/839

      17/-83648 x 1/839 = -17/70180672

                                  = - 1.67 x [tex]10^{-6[/tex]

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Answer:

hope this helps

Explanation:

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The equilibrium constant for this reaction at 350°C is D. 282.

A dynamic chemical system approaches chemical equilibrium constant when enough time has passed and its composition no longer exhibits any discernible propensity to change further. The equilibrium constant of a chemical reaction is the value of its reaction quotient in this condition. The equilibrium constant is independent of the initial analytical concentrations of the reactant and product species in the mixture for a specific set of reaction conditions. Understanding equilibrium constants is crucial for comprehending many chemical systems as well as biological processes like the transport of oxygen by hemoglobin in the blood and the maintenance of acid-base homeostasis in the human body. There are many different kinds of equilibrium constants, including stability constants, formation constants, binding constants, association constants, and dissociation constants.

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A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.

Br2(g) + I2(g) ↔ 2IBr(g)

When the mixture has come to equilibrium, the concentration of iodine monobromide is

1.190 M. What is the equilibrium constant for this reaction at 350°C? Show step-by step explanation.

A) 3.55 × 10^3

B) 1.24

C) 1.47

D) 282

E) 325

The equilibrium constant for this reaction at 350°C is determined as 5.85.

concentration of bromine, C(Br) = 0.6 mol/1 = 0.6

concentration of iodine, C(I) = 1.6 mol/1 = 1.6

An ICE table is a tabular system of keeping track of changing concentrations in an equilibrium reaction.

ICE is an abbreviation that stands for initial, change, equilibrium.

Create ICE table for the reactants and products formed;

      Br2(g)   +     I2(g)    ↔     2IBr(g)

I     0.6              1.6                 0

C    -1.19            -1.19               1.19

E    0.6 - 1.19      1.6  - 1.19       1.19

E = -0.59           0.41                1.19

The equilibrium constant is calculated as follows;

KC = [IBr]²/[Br][I]

KC = (1.19²) / (0.59 x 0.41)

KC = 5.85

Thus, the equilibrium constant for this reaction at 350°C is determined as 5.85.

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The boiling point of the solution will be 100.97 ° C.

[tex]T_f[/tex], pure water = 0.00 ° Celsius.

[tex]T_b[/tex] , pure water = 100° Celcius

[tex]K_b[/tex] = 0.512 C kg/mol

[tex]K_f[/tex] = -1.86 C kg/mol.

Given,

[tex]K_b = \frac{0.512 C kg}{mol}[/tex]

[tex]m = \frac{115g \frac{mol }{342.300g} }{0.35 kg}[/tex]

m = 0.95

i = 2 ( assuming no ion pairing)

Now, recall,

Δ[tex]T_b[/tex] =[tex]iK_bm[/tex]

Hence,

Δ[tex]T_b[/tex] = [tex]iK_bm[/tex]

      = 2 × 0.512 × 0.95

      = 0.97 °C

Therefore, the boiling point of the solution will be 100.97 °C.

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Answer: Iron

Explanation: IRON : Iron is an element with symbol Fe and atomic number 26 2) it is the fourth most common element in earth's crust 3) It is a heavy silvery grey metal belongs to the first transition series. 4) High ductility and malleability 5) It is a good conductor.

The identity of the substance is Iron.

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Answer:

The answer is The unsorted sand and rock is the least porous.

Answer:

large pebbles and boulders

Answer:

neutral

Explanation:

dss

The equilibrium constant of the reaction is 282. Option D

The term equilibrium constant refers to the number that often depict how much the process is able to turn the reactants in to products. In other words, if the reactants are readily turned into products, then it follows that the equilibrium constant will be large and positive.

Concentration of bromine = 0.600 mol /1.000-L = 0.600 M

Concentration of iodine = 1.600 mol/1.000-L =  1.600M

In this case, we must set up the ICE table as shown;

              Br2(g) + I2(g) ↔ 2IBr(g)

I          0.6            1.6           0

C      -x                -x             +2x

E    0.6 - x         1.6 - x       1.190

If 2x = 1.190

x = 1.190/2

x = 0.595

The concentrations at equilibrium are;

[Br2] = 0.6 -  0.595 = 0.005

[I2] =   1.6 - 0.595 = 1.005

Hence;

Kc = [IBr]^2/[Br2] [I2]

Kc = ( 1.190)^2/(0.005) (1.005)

Kc = 282

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Sn^2+ + Br2 ---> Sn^4+ + 2Br^- is referred to as a non-spontaneous redox reaction.

This type of reaction doesn't favor the formation of the product and must be endothermic.

In the reaction above under the given conditions, ΔG is positive and it is intended to form Sn(s) and Br(l) through the reduction of tin cation to make bromine liquid and tin solid. This therefore points to the direction of the reaction being non-spontaneous one.

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Answer:

a) 1

Explanation:

Unfortunately, we are not given the limiting reagent. The limiting reagent is the reactant which is completely used up first. We can identify it by converting both reactants into the product. The reactant which produces the smallest amount of product is the limiting reagent.

You can convert the moles of CO₂/H₂ to moles CH₃OH using the mole-to-mole ratio. This ratio is made up the balanced equation coefficients of the relevant substances.

1 CO₂ + 3 H₂ -----> 1 CH₃OH + H₂O

2 moles CO₂           1 moles CH₃OH
---------------------  x  ----------------------------  =  2 moles CH₃OH
                                    1 mole CO₂

3 moles H₂           1 moles CH₃OH
-------------------  x  ---------------------------  =  1 mole CH₃OH
                                  3 moles H₂

Because H₂ produces the smallest amount of CH₃OH, it is the limiting reagent. This means that all the H₂ is used up before CO₂ runs out. Therefore, the actual amount of CH₃OH produced is 1 mole.

When 2 mol of carbon dioxide and 3 mol of hydrogen, then one mole of methanol will be produced. Therefore, option (a) is correct.

A limiting reagent is a substance or reactant that is completely consumed in the completion of a chemical reaction and is also known as limiting reactant.

When reactants are not present in stoichiometric quantities, the limiting reactant decides the maximum amount of product that can be formed in a chemical reaction from the reactants.

Given the balanced chemical equation of formation of methanol:

CO₂ + 3 H₂  →  CH₃OH  +  H₂O

From the above reaction, we can say that 1 mole of carbon dioxide reacts with three moles of hydrogen gas to form one mole of methanol.

Then, 2mol of carbon dioxide will react with 6 moles of hydrogen gas.

But we have only 3 mol of hydrogen gas therefore, hydrogen gas acts as a limiting reagent that will be consumed first.

Therefore, three moles of hydrogen gas will produce one mole of methanol maximum.

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The correct alternative is (b). NaOH will be present in the test tube, after performing electrolysis.

Aqueous electrolysis of salt solutions finds the salt ions in competition with electrolysis of water at the respective electrodes. That is, water can undergo reduction at the cathode as can the cation of the salt; while at the anode water can undergo oxidation as can the anion of the salt. The reactions are as follows:

Cathode:

H₂O(l) + 2e⁻ ⇄ 2OH⁻(aq) + H₂(g)

Anode:  

2H₂O(l) ⇄ O₂(g) + 4H⁺(aq) + 4e⁻

The distinction can be determined by comparing the 'Standard Reduction Potentials' of the half-reactions.

For NaCl(s) => Na⁺(aq) + Cl⁻(aq) :

At the Cathode:

Na⁺ + e⁻ => Na⁰(s); εo = -2.71v

2H₂O(l) + 2e⁻ ⇄ 2OH⁻(aq) + H₂(g); εo = -0.83v (Dominant Rxn at cathode – more positive value)

At the Anode:

Cl⁻(aq) => Cl₂(g) + 2e⁻; εo = 1.36v

2H₂O(l) => O₂(g) + 4H⁺ + 4e⁻; εo = 1.23v (Dominant Rxn at anode – more positive value)

Since the more dominant reaction at the cathode(reduction) produces hydroxide ions, the solution would become alkaline with Na⁺ ions already present.

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A catalyst is a substance added to the reaction that lowers the activation energy by providing an alternate pathway for the reactions to go to completion.

A catalyst is a substance that accelerates a chemical response, or lowers the temperature or strain needed to begin one, with out itself being ate up at some stage in the response. Catalysis is the procedure of adding a catalyst to facilitate a response.

Catalysts may be categorized as homogeneous, heterogeneous, or enzymatic. Homogeneous catalysts exist inside the identical phase as the reactants, whereas heterogeneous catalysts exist in a exclusive section than the reactants.

Catalysts are basically categorised into 4 kinds.Homogeneous, Heterogeneous, Heterogenized homogeneous catalyst and Biocatalysts. Homogeneous catalyst: In homogeneous catalysis, reaction mixture and catalyst both are gift inside the equal segment.

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The equation for the autoionization of water is-

NH3 + H2O → NH4+ + OH− (H2O acts as an acid)

HCl + H2O → H3O+ + Cl− (H2O acts as a base)

Autoionization of water, the autoionization constant Kw, and the relationship between [H⁺] and [OH⁻] in aqueous solutions.

Water can undergo autoionization to form and ions.

The expression for the autoionization constant is

[tex]The expression for the autoionization constant isK_\text{w}=[\text{H}_3\text{O}^+][\text{OH}^-]\quad\quad\text{(Eq. 1)}K w​ =[H 3​ O + ][OH − ][/tex]

In this way the autoionization of water,

NH3 + H2O → NH4+ + OH− (H2O acts as an acid)

HCl + H2O → H3O+ + Cl− (H2O acts as a base) is given.

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Answer:

Explanation:

When wind passes through. the dust, the dust then also moves throughout the air, when you move and breath in a room, you create slight wind (like a fan moving to creating wind) and this slight wind moves the dust particles.

The edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.

The cubic unit cell is the smallest repeating unit when all angles are 90 degrees and all lengths are equal.

The volume of the molybdenum is calculated from mass and density of the molybdenum as shown below;

V = (zm/ρN)

where;

V = (2 x 95.96) / (10.28 x 6.02 x 10²³)

V = 3.10 x 10⁻²³ cm³

a³ = V

a = (V)^¹/₃

a = ( 3.10 x 10⁻²³)^¹/₃

a = 3.142 x 10⁻⁸ cm

a = 3.142 x 10⁻¹⁰ m

a = 314.2 x 10⁻¹² m

a = 314.2 pm

Thus, the edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.

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Hydrochloric Acid would best be described as an Arrhenius and BrØnsted-Lowrey acid.

Hydrochloric Acid HCl(g) is the proton donor and therefore a Brønsted-Lowry acid.

According to Arrhenius theory, hydrochloric acid is an acid which gives hydrogen ions in water but according to Bronsted-Lowry theory, hydrochloric acid is an acid because it donates a proton to the water molecule.

Hydrochloric acid (HCl) cannot be classified as a Lewis acid since it cannot accept an electron pair.

Thus, hydrochloric Acid would best be described as an Arrhenius and BrØnsted-Lowrey acid.

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Answer:

C.) [tex]K_a = \frac{[H^+][H_2PO_4^-]}{[H_3PO_4]}[/tex]

Explanation:

The general structure for a Ka expression is:

[tex]K_a = \frac{[H^+][A^-]}{[HA]}[/tex]

In this expression,

-----> Ka = equilibrium constant

-----> [A⁻] = base

-----> [HA] = acid

The products are in the numerator and the reactants are in the denominator. In this case, H₃PO₄ serves as an acid and H₂PO₄⁻ serves as a base.

As such, the equilibrium expression is:

[tex]K_a = \frac{[H^+][H_2PO_4^-]}{[H_3PO_4]}[/tex]

According to chemical equilibrium, the Ka for the given chemical equation is Ka=[H⁺][H₂PO₄⁻]/[H₃PO₄].

Chemical equilibrium is defined as the condition which arises during the course of a reversible chemical reaction with no net change in amount of reactants and products.A reversible chemical reaction is the one wherein the products as soon as they are formed react together to produce back the reactants.

At equilibrium, the two opposing reactions which take place take place at equal rates and there is no net change in amount of the substances which are involved in the chemical reaction.At equilibrium, the reaction is considered to be complete . Conditions which are required for equilibrium are given by quantitative formulation.

Factors which affect chemical equilibrium are change in concentration , change in pressure and temperature and presence of catalyst.

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