The velocity of the block when t == 2 s is 60.7 ft./sec.
Equations of Motion.
Here the friction is [tex]F_f = \mu_k N[/tex] = 0.2 N
[tex]+ \uparrow \sum F_y = ma_y; \quad N – 10 = \frac { 10 } { 32.2 }(0) \quad N = 10 lb \\ \begin{aligned} \underrightarrow{ + } \sum F_x = ma_x; \quad 8t^2 – 0.2(10 &) = \frac { 10 } { 32.2 }a \\ & a = 3.22(8t^2 – 2) ft/s^2 \end{aligned}[/tex]
Kinematics.
The velocity of the block as a function of t can be determined by
integrating dv = adt using the initial condition v = 4 ft./s at t = 0.
[tex]\int_{ 4 ft/s }^{ v } dv = \int_0^t 3.22(8t^2 – 2)dt \\ \begin{aligned} v – &4 = 3.22 (\frac 8 3 t^3 – 2t) \\ & v = \{8.5867t^3 – 6.44t + 4 \} ft/s \end{aligned}[/tex]
The displacement as a function of t can be determined by integrating
ds = vdt using
the initial condition s = 0 at t = 0
[tex]\int_0^s ds = \int_0^t (8.5867t^3 – 6.44t + 4)dt \\ s = \{2.1467t^4 – 3.22t^2 + 4t \} ft[/tex]
at t = 2 sec
s = 30 ft.
Thus, at s = 30 ft.,
[tex]\begin{aligned} v &= 8.5867(2.0089^3) – 6.44(2.0089) + 4 \\ &= 60.67 ft/s \\ &= 60.7 ft/s \end{aligned}[/tex]
Kinematics is a subfield of physics, developed in classical mechanics, that describes the motion of points, bodies (objects), and systems of bodies (groups of objects) without considering the forces that cause them to move.
Kinematics, as a field of study, is often referred to as the "geometry of motion" and is occasionally seen as a branch of mathematics. A kinematics problem begins by describing the geometry of the system and declaring the initial conditions of any known values of position, velocity and/or acceleration of points within the system.
Then, using arguments from geometry, the position, velocity and acceleration of any unknown parts of the system can be determined. The study of how forces act on bodies falls within kinetics, not kinematics. For further details, see analytical dynamics.
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Jennifer works for an automaker and tests the safety performance of cars. she watches a 2,000-kilogram car crash into a wall with a force of 30,000 newtons. what’s the acceleration of the car at impact? use f = ma. the car accelerates at a rate of meters/second2 at impact.
The acceleration of the car at impact is 15m/s².
What is Newton's Second Law of Motion?Newton's second law provides a precise explanation of the modifications that a force can make to a body's motion. According to this, a body's momentum changes at a rate that is equal to the force acting on it over time in both magnitude and direction. A body's momentum is equal to the sum of its mass and velocity. Similar to velocity, momentum has both a magnitude and a direction, making it a vector quantity.
acceleration - rate of change of velocity with time, both in terms of speed and direction. A point or object going straight forward is accelerated when it accelerates or decelerates.
There are three types of accelerated motions :
uniform acceleration, non-uniform accelerationaverage acceleration.express all the units in their most basic form.
kg, newton = kg*m/s², acceleration =m/s²
[tex]\frac{ 30000 kg*m/s^{2} }{ 2000 kg} = 15m/s^{2}[/tex]
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A positive charge of 94. 0 nc is 22. 0 cm from a negative charge of 53. 0 nc. the force on one of the charges due to the other is approximately________.
A positive charge of 94. 0 NC is 22. 0 cm from a negative charge of 53. 0 NC. The force on one of the charges due to the other is approximately 92.6× 10⁹ N
Force between the two charges depends upon the charges, distance between the charges and the medium between the two charges. It is given by:
F = kq₁q₂ / r²
where q₁ is the charge of the first charge
q₂ is the charge of the second charge
r is the distance between the charges
k is the permitivitty of medium
F is the force between the two charges
Given , q₁ = 94NC
q₂ = 53NC
r = 22cm = 0.22m
On subsituting,
F = 9 × 10⁹ × 94 × 53 / (0.22)²
⇒ F = 92.6 × 10⁹ N
Since, the force between the two charges is equal on both the charges hence, force on one of the charges due to the other is approximately 92.6× 10⁹ N.
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The electric field at a distance of 10 cm from an isolated point particle with a charge of 2 x 10–9 c is:________
The electric field at a distance of 10 cm from an isolated point particle with a charge of 2 x 10–9 c is 1.8×10³N/C.
When the charge is present in any form, an electric field is linked with each point in space. The value of E, also known as electric field strength, electric field intensity, or simply the electric field, expresses the magnitude and direction of the electric field.
The electric field is formally defined as a vector field associated with each location in space, the force per unit charge exerted on a positive test charge at rest at that point. The electric charge or time-varying magnetic fields generate the electric field. The magnitude of the electric field produced by a point charge Q is given by this equation.
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Due to its motion in the magnetic field of the bar magnet, the charge will experience a force in which direction?
Due to its motion in the magnetic field of the bar magnet, the charge will experience a force perpendicular to both the velocity of the charge and the magnetic field
Magnetic Field is the region around a magnetic material or a moving electric charge within which the force of magnetism acts. A pictorial representation of the magnetic field which describes how a magnetic force is distributed within and around a magnetic material.
If you point your pointer finger in the direction the positive charge is moving, and then your middle finger in the direction of the magnetic field, your thumb points in the direction of the magnetic force pushing on the moving charge is called right hand rule .
The magnitude of the force is proportional to q, v, B, and the sine of the angle between v and B.
Hence , the magnetic force on a free moving charge is perpendicular to both the velocity of the charge and the magnetic field with direction given by the right hand rule.
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What is the magnitude of the magnetic field at the point the center of a long, straight solenoid; the solenoid carries current 0.300 A and has 4.00 * 103 windings per meter
The magnitude of the magnetic field at the point at the center of a long, straight solenoid if the solenoid carries a current of 0.300 A and has 4.00 ×10³ windings per meter would be 1.512 ×10⁻³ N/Amps m
What is a magnetic field?A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted. The SI unit of the magnetic field is tesla.
The magnetic field at the point at the center of a long, straight solenoid can be calculated by using the formula
B = μnI
where B is the magnetic field
μ is the Permeability constant having a value of 1.26 × 10⁻⁶ T/m
n is the number of winding per meter
I represent the current
By substituting the respective value in the formula
B=( 1.26 × 10⁻⁶ )× (4.00 ×10³)×0.300
B =1.512 ×10⁻³ N/Amps m
Thus, the magnitude of the magnetic field at the point at the center of a long, straight solenoid would be 1.512 ×10⁻³ N/Amps m.
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In what part of the electromagnetic spectrum does the sun radiate maximum energy? How does this compare to earth?
The visible region of the electromagnetic spectrum is where the Sun radiates maximum energy. Since Earth is substantially cooler, the majority of the radiation it emits is longwave radiation.
The complete spread of electromagnetic radiation by wavelength or frequency. Despite the fact that all electromagnetic waves have a wide range of frequencies, wavelengths, and photon energies, they all move at the speed of light in a vacuum known as the electromagnetic spectrum.
The sun emits electromagnetic waves over a wide spectrum, from radio waves with a wavelength of 10 meters to X-rays with a wavelength of 2 nanometers. Visible light, with a wavelength of around 500 nanometers, is the most powerful of them to reach the earth's surface. The visible spectrum is where the Sun's energy is most intensely emitted. The maximum amount of radiation that the Earth emits occurs at 10 mm, in the infrared heat spectrum. Since the Earth's surface temperature is far lower than that of the sun and its radiation has longer wavelengths than solar radiation, the majority of this energy is then reradiated into space. The atmosphere is easily able to absorb the longer wavelengths that the Earth radiates.
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What does it mean when work is positive? Velocity is greater than kinetic energy. Kinetic energy is greater than velocity. The environment did work on an object. An object did work on the environment.
Work is said to be positive when Kinetic energy is greater than velocity (option B). Details about work can be found below.
What is work?Work is a measure of energy expended in moving an object; most commonly, force times distance. This means that no work is done if the object does not move.
However, work can either positive or negative depending on the direction of the object and the force applied.
When force and displacement are in the same direction, the work performed on an object is said to be positive work.
This further means that the kinetic energy, which is the energy due to motion, will be greater than the velocity of the object in order to overcome the object.
Therefore, work is said to be positive when kinetic energy is greater than velocity.
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Answer: (B) Kinetic energy is greater than velocity
Explanation:
The world’s longest organ pipe, in the boardwalk hall auditorium in atlantic city, is 64 feet long. what is the fundamental frequency of this openopen pipe?
The fundamental frequency of this open-open pipe is 8.82 Hz
The quantity of waves that pass a set location in a predetermined period of time is known as frequency. Frequency is the number of full cycles per second in the alternating current direction for an oscillating or fluctuating current. The hertz, also known as Hz, is the accepted unit of frequency.
The temporal rate of change observed in oscillatory and periodic phenomena, such as mechanical vibrations, audio signals (sound), radio waves, and light, is specified by the frequency, an essential parameter in science and engineering.
Assume vs = 344 m/s
f1 = vs/2L
= 344 m/s/ 2∙64 ft/(3.281 ft/m)
= 8.82 Hz
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A cardiac pacemaker can be affected by a static magnetic field as small as 1. 7 mt. how close can a pacemaker wearer come to a long, straight wire carrying 28 a?
A cardiac pacemaker can be affected by a static magnetic field as small as 1. 7 mt. pacemaker wearer comes to a long, straight wire carrying 28 amperes.
A pacemaker is a device that regulates an unsteady heartbeat. A pacemaker is inserted into one or more cardiac chambers using flexible, insulated wires called leads. The electrical pulses needed to change the heart rate are delivered by these lines. Some of the most recent pacemakers don't need leads.
The risk of problems is often quite low while having a pacemaker put. The primary worry is that the pacemaker will no longer be able to regulate the heartbeat due to a malfunction or a wire that has moved out of place. The average patient lived 101.9 months (or 8.5 years) after having a pacemaker implanted; at 5, 10, 15, and 20 years later, 65.6%, 44.8%, 30.8%, and 21.4% of patients were still living, respectively.
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The closest distance peacemaker come to is r=3mm.
How to find closest distance?Given data:-
B=1.7mt.
I=28A.
by using the equation B=(μ₀I)/2πr
r=μ₀I/2πB
r=[tex]\frac{4\pi *10^{-7} Tm/A *28A}{2\pi (0.0017T)}[/tex]
r=32*[tex]10^{-4}[/tex]m
r=3.2mm.
thus from the above conclusion we can say that when magnetic field is 1.7mt and current =28A then pacemaker can come close r=3.2mm.
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The speed of a car is increased uniformly from 11 meters per second to 19 meters per second. the average speed of the car during this interval is________.
Answer:
ΔV=Vi + Vf
2
ΔV= 11m/s + 19m/s
2
ΔV= 15m/s
Explanation:
Assuming a mass of 0.04-g, what is the power exerted by the electrical forces on a fragment of fiber if the fragment has a velocity of 200 mm/s, 10 ms after ejection?
8.0× 10⁻⁵ Watts is the power exerted
What is Power, Energy and Work done?Physics' three essential notions are work, energy, and power. When a force (push or pull) given to an item results in the displacement of the object, that force is said to have performed work. Energy is how we describe the ability to perform the task. Power is the amount of work completed in a given amount of time.
mass of the body = 0.04 g = 4.0 × 10^-5 kg
velocity of the body = 200mm/s = 0.2 m/s
Kinetic energy of the body = 1/2 × 4.0 × 10^-5 × 0.2^2
Kinetic energy of the body = 8.0× 10^-7
Thus, work done = 8.0× 10^-7 J
Power = work done/ time
Power exerted = 8.0× 10^-7/0.01
Power exerted = 8.0× 10^-5 Watts
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A car drives around a curve with a radius of 42 m at a velocity of 24 m/s. what is the centripetal acceleration of the car? m/s2
Answer:
13.7 m/s^2
Explanation:
Radius, r= 42m
Velocity, v= 24m/s
Ac= V^2/r
Ac=(24)^2/42
Ac= 13.7m/s2
The centripetal acceleration is 13.7 m/s².
Calculation:Centripetal acceleration is given by,
Ac = v²/r
where,
Ac = centripetal acceleration
v = velocity
r = radius
Given,
v = 24 m/s
r = 42 m
To find,
Ac =?
Put the value in the formula,
Ac = v²/r
= (24)²/42
= 576/42
= 13.7 m/s²
Hence, the centripetal acceleration is 13.7 m/s².
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How does position depend on time on a free falling motion, for short distance, near the surface of the earth?
Answer:
if an object is in free fall for a longer time its position will increase at an exponential rate because the object is accelerating
If the fifth order minimum in the diffraction pattern of a thin slit is at 40° from the central maximum, what is the highest order minimum in the pattern?
The highest order minimum in the diffraction pattern [tex]7^{0}[/tex].
Diffraction patternThe same way that an imaging mode electron beam is focused on the material to create an image, a parallel electron beam is used to create diffraction patterns. The beam transmitted is focused on the screen's diffraction pattern by the intermediate lens and its chosen area aperture, which determines the beam's width.
Crystallography studies of materials can benefit from the diffraction mode. Using this mode, one can establish the space group and orientation of crystals. the anoparticle's diffraction pattern, which is depicted on the left. The little spots and rings in polycrystalline samples indicate that it is crystalline.
A disc's closely spaced tracks work as a diffraction grating to create the well-known rainbow pattern that is seen while staring at a disc, which is one of the most spectacular instances of diffraction.
If the fifth order minimum in the diffraction pattern of a thin slit is at 40° from the central maximum, what is the highest order minimum in the pattern?
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FInal physics question please help asap
The cannonball will be 311.8 m far in meter when it travels horizontally
What is a Projectile ?A projectile is any object like stone, ball or javelin that take a parabolic path when thrown into the air.
The following parameters are given from the question
Ф = 30°u = 60 m/sg = 10 m/s²R = ?Resolve the initial velocity into horizontal and vertical components. That is,
Horizontal component = ucosФVertical component = usinФTo calculate the range that is, the horizontal distance, will can first calculate the total time take by the ball to reach the ground.
Total time T = 2usinФ / g
Substitute all the parameters
T = (2 x 60sin30) / 10
T = (2 x 30) / 10
T = 60 / 10
T = 6 s
The horizontal distance R = ucosФ x T
R = 60 x cos 30 x 6
R = 311.77 m
Therefore, the cannonball will travel 311.8 m approximately horizontally.
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F 2000. kg of ice cover your driveway, how many kilojoules of heat would be required to melt it? the heat of fusion of water is 334 j/g .
Answer:
668 000 kJ
Explanation:
2000 kg = 2000 000 gm
2000000 gm * 334 J/g = 668 000 000 J = 668 000 kJ
A "sound" is different than a "sound wave"
because
A. sound is how an animal (including humans) perceives a sound
wave
B. a sound wave can exist without creating a sound
C. sounds only exist within brains
D. all of the above
Answer:
sound is how an animal or human perceives a sound wave
A crowbar of 2m is used to lift an object of 800N if the efforts arm is 160cm clalculate the efforts applied
The applied effort represents the time devoted to the analysis of theory, attendance at theory classes, and the authentic performance of all practical skills.
How to calculate efforts applied?The applied effort represents the time devoted to the analysis of theory, attendance at theory classes, and the authentic performance of all practical skills.
The effort, application, endeavor, and exertion imply activities directed or force expended toward a definite end. Effort exists as an expenditure of energy to perform some objective: He created an effort to control himself. The application exists continuous struggle plus careful attention: constant application to duties.
Length of crow bar = 2m
length of load arm = 0.1M
length effort arm = length of crow bar -length of load arm
=2−0.1=1.9m
so, velocity ratio = length of effort arm/length of load arm = 1.9/0.1 = 19
use formula, velocity ratio = load/effort
19 = 100kgf/effort
effort = 100/19= 5.26 kgf
hence,5.26 effort is required.
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Type the correct answer in the box. use numerals instead of words. anne has a sample of a substance. its volume is 20 cm3, and its mass is 100 grams. what is the sample’s density? the sample’s density is g/cm3.
The density of sample is 5 g/cm3
Given:
volume of sample = 20 cm3
mass of sample = 100 grams
To Find:
density of sample
Solution: Density is the measure of how much “stuff” is in a given amount of space. For example, a block of the heavier element lead (Pb) will be denser than the softer, lighter element gold (Au). A block of Styrofoam is less dense than a brick. It is defined as mass per unit volume
density = mass/volume
d = 100/20
d = 5 g/cm3
So, density of sample is 5 g/cm3
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What potential difference is required in an electron microscope to give an electron wavelength of 4. 5 nm?
Potential difference required in an electron microscope to give an electron wavelength of 4. 5 nm will be 0.063 V.
The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other is called potential difference.
The wavelength of an electron is calculated for a given energy (accelerating voltage) by using the de Broglie relation between the momentum p and the wavelength λ of an electron
lambda = 4.5 nm = 4.5 * [tex]10^{-9}[/tex] m
h = [tex]6.626 * 10^{-34}[/tex] J s
e = 1.6 * [tex]10^{-19}[/tex] C
m = 9.1 * [tex]10^{-31}[/tex] kg
Energy = eV
lambda = h / [tex]\sqrt{2mE}[/tex] = h / [tex]\sqrt{2m(eV)}[/tex]
[tex](lambda)^{2}[/tex] = [tex]h^{2}[/tex] / (2m (eV))
V = [tex]h^{2}[/tex] / (2 m e [tex](lambda)^{2}[/tex] )
V = [tex](6.626 * 10^{-34} )^{2}[/tex] / 2 * 9.1 * [tex]10^{-31}[/tex] * 1.6 * [tex]10^{-19}[/tex] * [tex](4.9 * 10^{-9}) ^{2}[/tex]
V = 0.063 V
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A tennis ball is hit into the air with a racket. when is the ball’s kinetic energy the greatest? ignore air resistance.
When the player strikes the ball, kinetic energy is at its greatest.
Kinetic energy = 1/2*m*[tex]v^{2}[/tex]
where m denotes mass and v denotes velocity.
Therefore, kinetic energy is inversely correlated with square of velocity.
When a player strikes the ball, velocity is at its highest.
Thus, when the player strikes the ball, kinetic energy is at its highest.
What is kinetic energy?It is the energy that a body has because it is moving.
Which 5 forms of kinetic energy are there?Kinetic energy comes in five different forms:
radiantthermalsoundelectricalmechanical.Kinetic energy is measured in Joules.
Importance of kinetic energy:
The capacity to perform work is kinetic energy's most significant quality. Force acting on an object while it is moving is referred to as work. Energy and work are interchangeable because of their tight relationship.To learn more about kinetic energy visit:
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What is free-fall acceleration toward the sun at the distance of the earth's orbit?
Answer:
The free fall acceleration toward the sun at the distance of the earth's orbit is 9.8m/s^2
What are the three paths taken by incoming solar radiation, and what percentage of incoming solar radiation does each path generally deal with?
The three paths taken by incoming solar radiation are:
Earth's surfaceAtmospheric gasesReflected backAbout 29 percent of the solar radiation that arrives at the top of the atmosphere is reflected back to space by clouds, atmospheric particles, or bright ground surfaces like sea ice and snow. This radiation plays no role in Earth’s climate system.
About 23 percent of incoming solar energy is absorbed in the atmosphere by water vapour, dust, and ozone, and
48 percent passes through the atmosphere and is absorbed by the surface. Thus, about 71 percent of the total incoming solar energy is absorbed by the Earth system.
Solar radiation, often called the solar resource or just sunlight, is a general term for the electromagnetic radiation emitted by the sun. Solar radiation can be captured and turned into useful forms of energy, such as heat and electricity, using a variety of technologies. However, the technical feasibility and economical operation of these technologies at a specific location depends on the available solar resource.
Every location on Earth receives sunlight at least part of the year. The amount of solar radiation that reaches any one spot on the Earth's surface varies according to:
Geographic locationTime of daySeasonLocal landscapeLocal weatherDIFFUSE AND DIRECT SOLAR RADIATION
As sunlight passes through the atmosphere, some of it is absorbed, scattered, and reflected by:
Air moleculesWater vapourCloudsDustPollutantsForest firesVolcanoesThis is called diffuse solar radiation. The solar radiation that reaches the Earth's surface without being diffused is called direct beam solar radiation. The sum of the diffuse and direct solar radiation is called global solar radiation. Atmospheric conditions can reduce direct beam radiation by 10% on clear, dry days and by 100% during thick, cloudy days.
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When a small force is applied to a gyro, the result will instead occur 90 degrees ahead of that point, in the direction of rotation. this principle is known as:_____.
When a small force is applied to a gyro, the result will instead occur 90 degrees ahead of that point, in the direction of rotation. this principle is known as: Precession
What is precession?Precession is a shift in the direction of a rotating body's rotational axis. It can be described as a modification of the first Euler angle in the proper reference frame, while the rotation itself is defined by the third Euler angle. In other terms, a body is said to be precessing about a second axis if its own axis of rotation is spinning about that second axis. Nutation is a motion in which the second Euler angle varies. Precession can be either torque-free or torque-induced in physics.
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The ramp has an efficiency of 80%. If you perform 600 J of work, how much useful work does the ramp do
The ramp does 480J of useful work with an efficiency of 80% .
What is efficiency of work done ?Efficiency is the ratio of the useful energy released by a system to the input energy .Mathematically, efficiency of energy = out put energy/ input energy What is the useful work done by the ramp having efficiency 80% and an input work done 600J?The efficiency =output work done/ input work done 80% =output work done/ 600Joutput work done =( 80×600)/100=480J
Thus, we can conclude that the useful work done by the ramp is 480J.
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Why is it necessary to level the rotating platform? How would the motion of the revolving mass be affected if the base were not level? Explain
It necessary to level the rotating platform to maintain uniform circular motion.
The outcomes will be negatively impacted if the platform is not level since the heavy end will sway toward the side that is low.
To maintain a balance of the speed it is necessary to level the rotating platform.
What is uniform circular motion?When a particle follows a circular path while maintaining a constant speed, its motion is described as being uniformly circular.
Why is circular motion uniform?A body moving in a circular motion while maintaining a consistent speed is known as uniform circular motion. The velocity changes, but the speed doesn't. A particle's speed is constant if it is moving in a circular motion.Why is uniform circular motion important?Uniform circular motion is a crucial example of direction change while keeping constant speed. In that instance, the object's direction must change continuously in order to keep it moving in a circle while the object's speed remains constant, therefore "uniform."To learn more about uniform circular motion visit:
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Waves start as a disturbance (an input of energy) in a medium (water, air, the earth etc). The energy of the disturbance is moved from the starting point to other places in the medium by what means?
A
It depends on whether the wave is longitudinal or transverse. Transverse waves move energy differently than longitudinal waves.
B
The means of energy movement in a wave depends on the magnitude (force) of the original wave. Strong waves propagate by a different method than weak ones.
C
Molecules in the original disturbance disturb (move) adjacent molecules which disturb more adjacent molecules and so the wave travels.
D
It depends on the wavelength of the wave, short wavelength waves travel faster and move energy differently than long wavelength waves.
C. Molecules in the original disturbance disturb (move) adjacent molecules which disturb more adjacent molecules and so the wave travels.
What is wave?A wave can be defined as a propagating dynamic disturbance of one or more quantities.
A wave can be propagated in longitudinal or transverse method.
When waves start as a disturbance (an input of energy) in a medium (water, air, the earth etc).
The energy of the disturbance is moved from the starting point to other places in the medium by molecules in the original disturbance disturb (move) adjacent molecules which disturb more adjacent molecules and so the wave travels.
Thus, the correct option is C.
"Molecules in the original disturbance disturb (move) adjacent molecules which disturb more adjacent molecules and so the wave travels".
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Assuming the diode is ideal but with a forward voltage drop of. 65 volts, what is the current in ma if v1=0v, and r1=490ω?
The current in the ideal diode with forward biased voltage drop of 65V is 132.6 mA.
To find the answer, we have to know more about the ideal diode.
What is an ideal diode?A type of electronic component known as an ideal diode has two terminals, only permits the flow of current in one direction, and has less zero resistance in one direction and infinite resistance in another. A semiconductor diode is the kind of diode that is used the most commonly. It is a PN junction-containing crystalline semiconductor component that is wired to two electrical terminals.How to find the current in ideal diode?Here we have given with the values,[tex]V_2=65V\\V_1=0V\\R_1=490Ohm.[/tex]
We have the expression for current in mA of the ideal diode with forward biased voltage drop as,[tex]I=\frac{V_2-V_1}{R_1} =\frac{65}{490} =132.6mA[/tex]
Thus, we can conclude that, the current in mA of the ideal diode with forward biased voltage drop of 65 V is 132.6.
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The voltage between two parallel plates separated by a distance of 3. 0 cm is 120 v. The electric field between the plates is?
The electric field between plates is 4000V/m.
An electric field (sometimes E-field) is the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them. It also refers to the physical field for a system of charged particles.
The value of the electric field has dimensions of force per unit charge. In the metre-kilogram-second and SI systems, the appropriate units are newtons per coulomb, equivalent to volts per metre.
The voltage between points A and B is
V=E.d
E =V/d (uniform E- field only)
where d is the distance from A to B, or the distance between the plates.
Given:
distance d = 3 cm
voltage V = 120 V
Electric field E = V/d
E = 120 V / 3cm
E = 40 V / 1 cm [ 1 cm = 1/100 m ]
E = 4000 V/m.
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A large plate carries a uniform charge density σ = 8. 85 × 10-9 c/m2. a pattern showing equipotential surfaces with a 5 v potential difference would appear as:_________
The potential difference comes out to be
[tex]10 \times 10 {}^{ - 3} m[/tex]
Given:
σ = 8. 85 × 10-9 c/m2
we know,
[tex]E = \frac{σ}{2ε0}[/tex]
[tex]E = \frac{8.85 \times 10 {}^{ - 9} }{2ε0}[/tex]
[tex]E = \frac{v}{d} [/tex]
given the potential difference between two equipotential surface=5v
E=∆v
∆d=∆v/E
[tex] = \frac{5 \times 8.85 \times 10 { }^{ - 12} \times 2 }{8.85 \times 10 {}^{ - 9} } [/tex]
[tex]Δ = 10 \times 10 {}^{ - 3} m[/tex]
Thus the potential difference is
[tex]10 \times 10 {}^{ - 3} m[/tex]
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