Suppose that 0.50 grams of barium-131 are administered orally to a patient. Approximately how many milligrams of the barium would still be radioactive two months later?

Answers

Answer 1

Two months later 13.8 milligrams of the barium-131 still be radioactive.

How is the decay rate of a radioactive substance expressed ?

It is expressed as:

[tex]A = A_{0} \times (\frac{1}{2})^{t/T}[/tex]

where,

A = Amount remaining

A₀ = Initial Amount

t = time

T = Half life

Here

A₀ = 0.50g

t  = 2 months = 60 days

T = 11.6 days  

Now put the values in above expression we get

[tex]A = A_{0} \times (\frac{1}{2})^{t/T}[/tex]

   [tex]= 0.50 \times (\frac{1}{2})^{60/11.6}[/tex]

   [tex]= 0.50 \times (\frac{1}{2})^{5.17}[/tex]

   = 0.50 × 0.0277

   = 0.0138 g

   = 13.8 mg          [1 mg = 1000 g]

Thus from the above conclusion we can say that Two months later 13.8 milligrams of the barium-131 still be radioactive.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Suppose that 0.50 grams of ban that 0.50 grams of barium-131 are administered orally to a patient. Approximately many milligrams of the barium would still be radioactive two months later? The half-life of barium-131 is 11.6 days.

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Related Questions

A pyranose with the hydroxyl group on the anomeric carbon pointing up in the haworth structure is designated?

Answers

A pyranose with the hydroxyl group on the anomeric carbon pointing up in the haworth structure is designated by alpha .

When aldohexoses undergo cyclization, anomers are formed. Anomers differ in the spatial position of the -OH group at [tex]C_{1}[/tex] . When the  -OH group is positioned along the direction of [tex]-CH_{2} OH[/tex] , alpha anomer exists but when the  -OH group is positioned opposite to the direction of the[tex]-CH_{2} OH[/tex] , then we have the beta anomer. Consider the alpha and beta anomers of galactopyranose and a pyranose with the hydroxyl group on the anomeric carbon pointing up in the haworth structure is given as ,

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How much heat is gained by cu when 51. 8 g of cu is warmed from 15. 5°c to 76. 4°c? the specific heat of cu is 0. 385 j/(g · °c). show the set up and answer with unit

Answers

The heat is gained by Cu when 51. 8 g of Cu is warmed from 15. 5°c to 76. 4°c If the specific heat of Cu is 0. 385 j/(g · °c) is 999.42 J.

What is specific heat?

Specific heat is defined as the heat which is required to raise the temperature by 1°C of the unit mass of a given substance by a given amount.

We are required to calculate the quantity of heat energy gained by Cu

As we know that,

Q = m × c ×∆T

where,

Q is the quantity of heat energy

m is mass of substance = 0.051kg

c is specific heat of substance = 385J/kg.°C

∆T is change in temperature = 50.9

By substituting all these value we will get,

Q = 0.051 × 385 × 50.9

Q = 999.42J

Thus, we calculated that the quantity of heat gained by 0.051kg of Cu is 999.42J.

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The energy levels of a quantum particle-in-a-box ______ as the quantum number increases.

Answers

Answer:

Explanation:

The energy of a particle in the box increases proportionally to n-squared. This means that the energy spacings increase at high values of n.

The energy levels of a quantum particle-in-a-box decreases as the quantum number increases.

What are Quantum Numbers?

Quantum numbers can be used to describe the trajectory and the movement of an electron in an atom.

The set of numbers used to describe the position and energy of an electron in an atom is called quantum numbers.

These are the four quantum numbers, i.e., principal quantum number (n), magnetic quantum number (m), azimuthal quantum number (l), and spin quantum number (s).

As the energy levels of a quantum particle-in-a-box decreases as the quantum number increases.

Therefore, The energy levels of a quantum particle-in-a-box decreases as the quantum number increases.

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Malic dehydrogenase is added to the aspartate aminotransferase (ast) reaction to catalyze the conversion of?

Answers

Malic dehydrogenase catalyzes the conversion of oxaloacetate to malate.

What is the mechanism of aspartate aminotransferase reaction?

The transaminase enzyme known as aspartate aminotransferase (AST) is responsible for converting aspartate and alpha-ketoglutarate into oxaloacetate and glutamate.

Malate Dehydrogenase catalyzes Oxaloacetate to Malate Oxidation in the Coupled Reaction of AST Measurement.

What is the reaction of aspartate aminotransferase

I understand the question you are looking for is this:

Malic dehydrogenase is added to the aspartate aminotransaminase (AST) reaction to catalyze the conversion of:

a. alpha-ketoglutarate to aspartate

b. alpha-ketoglutarate to malate

c. aspartate to oxaloacetate

d. oxaloacetate to malate

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What is the molarity of a NaOH solution if 32.47 mL is required to titrate 0.6013 g of potassium hydrogen phthalate (C8H5O4K)

Answers

Answer:

0.0907 M

Explanation:

Before you can calculate the molarity, you need to convert grams to moles (via molar mass) and convert mL to L.

(Step 1)

Molar Mass (C₈H₅O₄K):

8(12.011 g/mol) + 5(1.008 g/mol) + 4(15.998 g/mol) + 39.098 g/mol

Molar Mass (C₈H₅O₄K): 204.218 g/mol

0.6013 g C₈H₅O₄K             1 mole
------------------------------  x  ------------------  =  0.00294 moles C₈H₅O₄K
                                          204.218 g

(Step 2)

1,000 mL = 1 L

32.47 mL              1 L
---------------  x  -----------------  =  0.03247 L
                        1,000 mL

(Step 3)

Molarity (M) = moles / volume (L)

Molarity = 0.00294 moles / 0.03247 L

Molarity = 0.0907 M

Select true or false: if 2mg(s) o2(g) → 2mgo(s), δh° = –1203. 6 kj/mol, then formg(s) (1/2)o2(g) → mgo(s), the enthalpy change is δh = –601. 8 kj/mol

Answers

According to the given equation ,if 2Mg(s) O2(g) → 2MgO(s), δh° = –1203. 6

k j/m o l, then form g(s) (1/2)O2(g) → Mg O(s), the enthalpy change is δh = –601. 8 k j /m o l, hence the given statement is true.

What do you mean by enthalpy change?

An enthalpy change is roughly equivalent to the energy gained through the production of new chemical bonds in a reaction minus the energy required to break existing chemical bonds.

It describes how a system changes in terms of energy while pressure is constant.

The symbol ΔH stands for enthalpy change. At constant pressure, ΔH is equal to the sum of the system's internal energy and the pressure-volume work it performs on its surroundings.

It  is expressed in units of joules per mole.

If 2Mg(s) O2(g) → 2MgO(s), δh° = –1203. 6

k j/m o l, then form g(s) (1/2)O2(g) → Mg O(s), the enthalpy change is δh = –601. 8 k j /m o l, therefore the above given statement is true.

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What compound do you expect to be removed from the organic layer of the organic layer is extracted with 1 m naoh solution?

Answers

Hydrochloric acid  (HCl) and brine both  compound expect to be removed from the organic layer extracted with 1 m NaOH solution.

What is extraction?

Using a solvent, a component of interest is selectively removed from a mixture during extraction. The process has been utilized to form the phase separation with the solvent in one phase, and the solute to be present in another phase.

The extraction process can be differentiated based on the phase of the solute and solvent. For example, solid-liquid, liquid-liquid, solid-gas and others.

The extraction with the use of the NaOH forms the solute to lose an electron to the hydroxide of the NaOH and forms the layer of the negative acid. The use of Brine and HCl forms to bond with the organic layer and mediate the extraction process.

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What is the infusion of a radiopaque contrast medium, barium sulfate, into the rectum?

Answers

Infusion of radiopaque contrast medium, barium sulfate, into the rectum is technique used in barium enema.

What is barium enema?

Barium enema is technique used for the detection of abnormalities or changes in the large intestine colon via X- rays. The exam is indicated for investigation of

megacolonchronic constigation bleeding in stools Inflammatory bowel diseases.

Thus, from above we concluded that the silhouette of the colon. This type of diagnosis is used in the case of adnormal pain, rectal bleeding chronic diarrhea.

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Dentify the reagents used to carry out the chlorination of benzene. a. cl2/ccl4 b. cl2/fecl3 c. cl2/nacl d. both b and c e. a, b and c

Answers

The reagents which are used to carry out the chlorination of benzene are   cl2/fecl3 and cl2/nacl

Chlorination is the process of disinfecting drinking water by introducing chlorine to eradicate viruses, germs, and parasites. To get drinking water with safe levels of chlorine, various techniques can be utilized. Chlorination is the technique of disinfecting and eradicating bacteria from drinking water by adding chlorine to it.

To get drinking water with safe levels of chlorine, various techniques can be utilized. Chlorine can be found as solid calcium hypochlorite (Ca(OCl)2), sodium hypochlorite solution (NaOCl), or compressed elemental gas. Chlorine is added to water as part of the chlorination process, however the chlorinating substance need not be pure chlorine.

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An ideal reversible heat pump is taking heat from the outside air at -14.0°c and discharging it into the house at 20.0°c. what is the coefficient of performance of this heat pump?

Answers

the coefficient of performance of this heat pump is 8.61.

What is Heat pump ?

The air source heat pump converts heat from the ambient air into a low-temperature liquid refrigerant. The pump compresses the liquid to raise its temperature using power. To release the heat it had been holding, it then condenses back into a liquid. Your underfloor heating system or radiators get heat.

coefficient of performance -The usable heating or cooling delivered to work (energy) needed ratio, also known as the coefficient of performance, or COP, of a heat pump, refrigerator, or air conditioning system. Higher efficiency, less energy (power) usage, and thus reduced operational costs are all related to higher COPs.

temperature of cold reservoir = -14.0°C

Tc = [ 273+ (-14.0)]K = 259K

temperature of hot reservoir = 20°C

Th = [ 273+ (20)]K = 293K

therefor, formula for coefficient of performance

Cop = Th/Th-Tc

Cop = 293/34

Cop = 8.61

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Draw the structures of the two monomers that react together to form this polyurethane polymer

Answers

The monomers that react together to form polyurethane polymer are diisocyanate and diol.

What are polymers?Polymers are a class of natural or synthetic substancesIt is made up of small units called monomers arranged in a repeated pattern to form large molecules called macromoleculesCellulose and resins are examples of natural polymersPolyethylene and polychloroprene are examples of synthetic polymers.

Polyurethane polymer is made up of monomers diisocyanate and diol. It is mostly used in home furnishing in flexible form. The structures of monomers are as follows:

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In an sn2 reaction between bromomethane and hydroxide ion, the concentration of bromoethane is doubled and the concentration of hydroxide ion doubles the rate of reaction?

Answers

The rate of reaction in SN2 reaction becomes four times when the the concentration of bromoethane is doubled and the concentration of hydroxide ion doubles.

In SN2 reaction, the rate of reaction is depend on the concentration of both reactant.

For SN2 reaction,

r = k[bromoethane] [hydroxide ion]

r = k [CH3CH2Br] [OH]

When the concentration of bromoethane is doubled and the concentration of hydroxide ion doubles then,

r = k 2×[CH3CH2Br] × 2[OH]

r = 4k[CH3CH2Br] [OH]

Thus, we concluded that the rate of reaction in SN2 reaction becomes four times.

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You're going on a plane from Alaska to Florida and you're taking your bike. It's the middle of the winter. You fill up your tires before you leave to a pressure of 2.72
atm on a day that is -7.50°C. When you arrive in FL at 38°C, you check the pressure in your tires before you ride, what do you find the pressure to be?
Type your answer with the proper number of significant figures and proper units in the space below.

Answers

Answer:

2.3 atm

Explanation:

-7.50°C = 265.5 K

38°C = 315 K

(2.72)(265.5)=(pressure)(315)

pressure = 2.3 atm

A galvanic cell is set up with two cells containing a cadmium electrode in 0. 250 m cd(no3)2 solution and an iron electrode in 0. 050 m fe(no3)2 solution. what is the cell potential at 25 oc?

Answers

Cd2+(aq) + 2e- ---> Cd(s) , E° = -0.40 V Fe2+(aq) + 2e- ----> Fe(s) , E° = -0.44 V Since standard reduction potential.

Galvanic Cell: A chemical cell, also known as an electrochemical cell, is a device that transforms the chemical energy generated during a red-ox reaction into electrical energy. In honor of Luigi Galvanic and Alessandro Volta, who conducted the first experiments on the conversion of chemical energy into electrical energy, these are also known as galvanic or voltaic cells.

A spontaneous red-ox reaction occurs in an electrochemical cell in an indirect manner, and the reduction in free energy that occurs during the chemical reaction manifests as electrical energy. In an indirect red-ox reaction, the reduction and oxidation processes take place in two different containers known as half-cells.

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The cell potential is 0.01934 V at 25°C.

What is a galvanic cell?

A galvanic cell, also known as a voltaic cell, is an electrochemical cell that converts the chemical energy generated by spontaneous redox reactions into electrical energy.

The main components of a galvanic cell are

Anode – Oxidation occurs at the anode

Cathode – Reduction occurs at the cathode

Salt bridge – consists of electrolytes that are needed to complete the circuit in a galvanic cell.

Half-cells – It is important as reduction and oxidation reactions are separated into compartments.

External circuit – it helps in Conducting the flow of electrons between electrodes

At cathode,

[tex]Cd^{2+}(aq) + 2e^-\rightarrow Cd(s)[/tex]

At anode,

[tex]Fe(s)+2e^-\rightarrow Fe^{2+}(aq)[/tex]

Overall cell reaction

[tex]Fe(s)+Cd^{2+}(aq)\rightarrow Fe^{2+}(aq) + Cd(s)[/tex]

[tex]E^o_{cell} = E^o_{cathode} - E^o_{anode}[/tex]

          = -0.40 -(0.44) = 0.04 V

Nernst equation is given by

[tex]E_{cell} = E^o_{cell} - \frac{2.303RT}{nF} logQ[/tex]

At 25°C

[tex]E_{cell} = E^o_{cell} - \frac{0.0592V}{n} logQ[/tex]

Here, n = 2 and log Q = log [tex]\frac{0.250}{0.050}[/tex] = 0.699

[tex]E_{cell}[/tex]  = 0.01934 V

The cell potential is 0.01934 V at 25°C

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Explain how a redox reaction involves electrons in the same way that a neutralization reaction involves protons.

Answers

An oxidation-reduction (redox) reaction is a type of chemical reaction that involves a transfer of electrons between two species.In oxidation loss of electrons takes place and in reduction gain of electrons is takes place whereas nuetralization reaction is a reaction in which an acid and a base react to form water and a salt and involves the combination of [tex]H^{+}[/tex] (proton) and [tex]OH^{-}[/tex] to generate water.

The neutralization reaction is not a redox reaction is because in nuetralization reaction there is no transfer of electron takes place where as in redox reaction there is no exchange of electrons between atoms. Moat bond forming and breaking redox reaction requires the concomitant transfer of protons.

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What do the electron configurations for all the group 18 noble gases have in common?

Answers

Electron configurations for all the group 18 noble gases have eight electrons in their valence shell in common.

Noble gases are the gases that contain Eight electrons in their valence shells and are placed in Group 18 of the periodic table. The octet of Noble gases is complete. They are inert in nature since they have complete valence shells. They are not much abundant in nature due to their inert behaviour.

They are stable and realtively unreactive as compared to other members of the peiodic table.

Some other factors that remain common for noble gases:

High Ionisation energyNegligible ELectronegativityLow boiling pointsPsitive Elevtron gain enthalpyGases at Room temperature

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When a 0. 1 m aqueous solution of hydrocyanic acid, hcn, reaches equilibrium, the ph is measured to be 5. 20. using this information, calculate ka for hydrocyanic acid

Answers

When a 0. 1 m aqueous solution of hydrocyanic acid, HCN, reaches equilibrium, the ka for hydrocyanic acid is  3.969 x 10⁻¹⁰.

What is ka value?

It's the value of equilibrium constant for the dissociation of ions into a solution. The more the Ka value the more will be dissociation.

Ka = [H₃O⁺]² / [HCN] [H₃O⁺]

The pH is 5.20

-log [H₃O⁺] = 5.20

Putting antitlog both side.

The value will be 6.30 x 10⁻⁶

Ka = (6.30 x 10⁻⁶)²  / 0.1 - 6.30 x 10⁻⁶

0.1 - 6.30 x 10⁻⁶ = 0.1

Ka = 3.969 x 10⁻¹⁰

Thus, the Ka value for hydrocyanic acid is 3.969 x 10⁻¹⁰.

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What is the percent yield when 68. 5 kg of carbon monoxide is reacted with 8. 60 kg of hydrogen gas to produce methanol (ch3oh)? the actual yield of methanol was 3. 57 x 104 g

Answers

Hence the percent yield of methanol is 51.45%

Step 1: Convert Kg into g

68.5 Kg CO = 68500 g CO

8.60 Kg H₂ = 8600 g

Step 2: Find out the Limiting reactant;

The Balance Chemical Equation is as follows;

                CO + 2 H₂  →  CH₃OH

According to Equation,

         28 g (1 mol) CO reacts with = 4 g (2 mol) of H₂

So,

         68500 g CO will react with = X g of H₂

Solving for X,

          X = (68500 g × 4 g) ÷ 28 g

          X  = 9785 g of H₂

It shows that 9785 g H₂ is required to react with 68500 g of CO but we are provided with 8600 g of H₂ which is less than required. Therefore, H₂ is provided in less amount hence, it is a Limiting reagent and will control the yield of products.

Step 3: Calculate Theoretical Yield

According to the equation,

     4 g (2 mol) H₂ reacts to produce = 32 g (1 mol) Methanol

So,

            8600 g H₂ will produce = X g of CH₃OH

Solving for X,

          X  = (8600 g × 32 g) ÷ 4 g

          X = 68800 g of CH₃OH

Step 4: Calculate %age Yield

          %age Yield = Actual Yield ÷ Theoretical Yield × 100

Putting Values,

          %age Yield = 3.54 × 10⁴ g ÷ 68800 g × 100 = 51.45 %

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Identify oxidation. increase in oxidation number. loss of electrons. decrease in oxidation number. gain of electrons

Answers

Oxidation is "increase in oxidation number".

A growth in oxidation number results from the losing of negatively charged electrons, whereas a reduction in oxidation number results from the gain of electrons. The result is just a rise in the oxidation number of the oxidized element and ion.

The elements in molecules and compounds were rearranged to create the products when there is a chemical reaction at the molecular level, which is where chemical changes take place. One type of chemical change is called oxidation.

Therefore, Oxidation is increase in oxidation number.

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Identify atleast 2 limitations of the simulation. how do these limitations influence the simulation

Answers

It is crucial for the researcher to be aware of various restrictions when utilising simulations. This is due to the simulations' non-exact behaviour, the lack of crucial analysis-relevant features, and the lack of approximations of what actually occurs with what they are simulating.  When modeling the synthesis of Ammonia, for example, these limitations can cause inaccuracies that will compromise the entire analysis.

Which method is used for synthesis of ammonia?

The Haber-Bosch process

The dominant ammonia production process is the Haber-Bosch process invented in 1904 which requires high temperature (~500°C) and high pressure (150–300 bar), in addition to efficient catalysts3,4. Natural gas or coal is used as the energy source of the ammonia industry.

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Atoms and molecules are way too small to be seen even with a microscope so how can we count how many there are?

Answers

Atoms and molecules are way too small to be seen even with a microscope so it can be counted by mass.

According to the context, the term actually may or may not encompass ions that meet this requirement. A molecule would be a collection of more than two atoms held together through attractive forces described as chemical bonds.

Atoms are incredibly tiny, with a diameter of around 1 x [tex]10^{-10}[/tex] meters. They can't be seen with a light microscope due to their small size. The composition of atoms can be observed and studied using a variety of ways, even if a light microscope might not be able to see one atom.

Therefore, atoms and molecules are way too small to be seen even with a microscope so it can be counted by mass.

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[?] describes how small molecules can be selectively removed from a colloidal suspension while retaining large molecules.
A) Dialysis
B) The Tyndall effect​

Answers

Dialysis is correct……………

Answer:

using a centrifuge

Explanation:

Centrifugation will make the large molecules to settle at the bottom.

The Most suitable answer is tyndall effect

Tritium, or 3h, has a half-life of 12. 32 years. imagine a sample of tritium is prepared. (a) what fraction of the sample will remain 3. 80 yr after its preparation?

Answers

(a) 0.807 fraction of the sample will remain 3. 80 yr after its preparation of tritium.

What is half life?

Half life is the time taken for the radioactivity of a substance to fall to half its original value whereas mean life is average lifetime of all the nuclei of a particular unstable atomic species.

So if a radioactive element has a half life of one hour, this means that half of it will decay in one hour. After another hour, half of the remaining material will decay.

Example:

The radioactive isotope cobalt-60, which is used for radiotherapy, has, for example, a half-life of 5.26 years.

Tritium half life = 12.32 (T half)

Formula :

N/N₀ = (1/2) ^ t/T        (N/N₀ = Fraction ratio)t = 3.84 T = 12.32N/N₀ = (1/2) ^ 0.308N/N₀ = 0.807

(a) 0.807 fraction of the sample will remain 3. 80 yr after its preparation of tritium.

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Calcium oxide, cao, also known as quick lime, may react with carbon dioxide to form calcium carbonate, caco3. which acts as a lewis acid in the reaction?

Answers

When calcium oxide react with carbon dioxide to form calcium carbonate then  carbon dioxide would react as a Lewis acid in the reaction.

A chemical species known as a Lewis acid has an empty orbital that can accept a pair of electrons from a Lewis base to produce a Lewis adduct.

In the reaction, orbital of  carbon dioxide will be vacant orbital that's why it can be considered as Lewis acid.

Its reaction can be written as:

[tex]CaCO_{3}[/tex] → CaO +[tex]CO_{2}[/tex]

It is kind of decomposition reaction.

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In a kitchen, during preparation of food or tea, salt and sugar are
mixed. What methods for separation of this mixture would you
suggest to your mother?

Answers

Answer:

A mixture of salt and sugar can be separated by the process of filtration.

Which 5-carbon intermediate of the citric acid cycle is converted to a 4-carbon molecule with the release of carbon dioxide?

Answers

The alpha- ketoglutarate is the  5-carbon intermediate of the citric acid cycle which converted to a 4-carbon molecule with the release of carbon dioxide

The first decarboxylation reaction in Krebs cycle ( known as  citric acid cycle ) is catalyzed by isocitrate dehydrogenase in which one six carbon atoms compound isocitrate is decarboxylated to yield five carbon atom containing alpha ketoglutaric acid.

The alpha- ketoglutarate is the  5-carbon intermediate of the citric acid cycle which is salt of alpha ketoglutaric acid. The last reaction in the citric acid cycle produces a product that is a substrate for the first reaction of the citric acid cycle.

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The bluish color that makes the atmosphere of neptune so beautiful to the human eye is caused by the interaction of sunlight with what gas?

Answers

The bluish color that makes the atmosphere of neptune so beautiful to the human eye is caused by the interaction of sunlight with methane gas.

The compositions of Uranus but also Neptune are fairly similar at high altitudes. The existence of methane in both ice giants' upper atmospheres may be responsible for their blue hue. The majority of the red light that strikes the planets is absorbed by methane, giving the planets their blue appearance.

The blue marble occurrence of the faraway planet is actually a result of methane gas clouds. Methane is a gas that, despite making up a very small fraction of Neptune's atmosphere, absorbing red light's wavelengths while reflecting blue light outward.

Therefore, the bluish color that makes the atmosphere of neptune so beautiful to the human eye is caused by the interaction of sunlight with methane gas.

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For the reaction c 2h₂ ---> ch₄, how many moles of hydrogen are required to produce 10 mol of methane, ch₄

Answers

The number of moles of hydrogen required will be 20 moles.

Stoichiometric mole ratio

First, let us look at the balanced equation of the reaction:

[tex]C + 2H_2 --- > CH_4[/tex]

From the above equation, it is obvious that 1 mole of carbon requires 2 moles of hydrogen in order to produce a mole of methane.

In other words, the mole ratio of hydrogen to methane is 2:1. For every 1 mole of methane produced, 2 moles of hydrogen are consumed.

Now, what we want to produce is 10 moles of methane. The amount, in moles of hydrogen required, is calculated by:

                    10 moles x 2 = 20 moles.

Thus, 20 moles of hydrogen would be required to produce 10 moles of methane.

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When the solute concentration in solution 1 is lower than the solute concentration in solution 2, solution 2 is:_____.

Answers

When the solute concentration in solution 1 is lower than the solute concentration in solution 2, solution 2 is concentrated solution .

The dilute solution and concentrated solution is relative terms.

Now in any solution there are just solute and solvent.

If amount of solute is comparatively high as compare to amount of solvent  in solution then solution is called concentrated solution. Similarly , If amount of solute is comparatively low as compare to amount of solvent  in solution then solution is called dilute solution.

If the amount of solvent is more in a solution then the amount of solute would be less.Again if the amount of solvent is less in a solution then amount of solute is more.

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A cylindrical grain has a base radius of 5m. the surface area is 1099m^2. What is the height of the bin to the nearest metre?

Answers

The height of the bin is 29.9m.

The quantity of space enclosing a three-dimensional shape's exterior is its surface area.

The total surface area of the cylinder formula is simply the sum of the base surface area and the lateral surface area.

The radius of the cylinder, r = 5m

Surface area = 1099 m²

∴ A = 2πrh + 2πr²

  [tex]h = \frac{A- 2\pi r^2}{2\pi r}[/tex]

  [tex]h = \frac{1099- 2 (3.141) 5^2}{2 (3.141) 5}[/tex]

  [tex]h = \frac{1099- 157.05}{31.41}[/tex]

  [tex]h = \frac{941.95}{31.41}[/tex]

  [tex]h = 29.9 m[/tex]

Therefore, the height of the bin is 29.9m.

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