QUESTION 1 Consider the following diagram that shows liquid water evaporating to form water vapour. Evaporation 1.1. Use chemical formulae to represent the process in the diagram above and indicate the phases of the substance undergoing this process (2) 1.2. Give three separation methods that can be used to reverse a physical change. (3)​

Mass percentages of the the elements in the compound is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of the compound are provided.

The Empirical formula is the simplest whole number ratio of atoms present in given compound.

Molecular Formula = Empirical Formula × n

n =  [tex]\frac{\text{Molar Mass}}{\text{Empirical Formula weight}}[/tex]

Thus from the above conclusion we can say that Mass percentages of the the elements in the compound is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of the compound are provided.

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Taking into account the definition of molarity, the molarity of the solution is 8 M.

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]Molarity=\frac{number of moles}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].

In this case, you know:

Replacing in the definition of molarity:

[tex]Molarity=\frac{2 moles}{0.250 L}[/tex]

Solving:

Molarity= 8 [tex]\frac{moles}{liter}[/tex]= 8 M

Finally, the molarity of the solution is 8 M.

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The volume of the gas sample will be 1.79 L.

A liquid, solid, or gas's volume represents the amount of three-dimensional space it occupies. Although there are many additional units that can be used to indicate volume, the most used ones are liters, cubic meters, gallons, milliliters, teaspoons, as well as ounces.

Given data :

Mass of [tex]O_{2}[/tex] = 1.20 g

Mass of [tex]N_{2}[/tex] = 1.43 g

Number of moles can be calculated by suing the formula:

Number of moles of [tex]O_{2}[/tex] = Mass / molar mass = 1.20 / 32 = 0.03 mol

Number of moles of [tex]N_{2}[/tex] =  Mass / molar mass  = 1.43 / 28 = 0.05 mol

So, the total count of moles can be calculated by :

Total moles = moles of [tex]O_{2}[/tex]  +  moles of [tex]N_{2}[/tex]

Total moles = 0.03  + 0.05 = 0.08 mol

The volume of the gas at STP can be calculated as:

Volume = 0.08 mol × 22.4 mol/L

Volume = 1.79 L

Therefore, the volume of the gas sample will be 1.79 L.

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The same amount of energy released when they recombine

Yes, the energy required to separate water into O2 and H2 is at least equal to the energy released when these gases come together to form water.

The process of separating water into hydrogen and oxygen is known as electrolysis. This reaction occurs in a device known as an electrolyzer.

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The volume sulfuric acid will be 89.3mL.

Volume will be determined by the molarity relation. The quantity of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a component per liter of a solution would be known as molarity. The molar concentration of any solution would be another name for molarity.

The volume can be calculated by using molarity formula:

[tex]M_{1} V_{1} = M_{2} V_{2}[/tex]

Given data:

[tex]M_{1}[/tex] = 3.50 m

[tex]M_{2}[/tex] =  1.25 m

[tex]V_{1}[/tex]= 250.0 ml

Put the value of given data in above formula:

[tex]M_{1} V_{1} = M_{2} V_{2}[/tex]

( 3.50 m) ( 250 mL) = ( 1.25 m) [tex]V_{2}[/tex]

[tex]V_{2}[/tex] = 89.3mL

Therefore, the volume sulfuric acid will be 89.3mL.

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Milk is an example of solid emulsion. Hence, option D is correct.

An emulsion is defined as a colloid consisting of two or more non-homogenous type of liquids in which one of the liquid contains the dispersion of the different form of liquids.

Emulsion consist of a dispersion of two liquids that are immiscible with each other.

One of the liquids act as the dispersion medium and the other will act as the dispersed phase.

Emulsions are colloids in which both the dispersed phase and dispersion medium are liquids.

Types of Emulsion:

    2. Water in oil (W/O)

Milk is an example of solid emulsion. Hence, option D is correct.

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The descriptive term that is applied to the type of diene represented by 1,5-octadiene is isolated diene. The correct option is C.

Diene is a compound that contains two or more double bonds, usually  carbon bonds, which are separated by a single bond. They are covalent compounds. Alkene units are surely present in these compounds, whose quantity is two.

1,5-octadiene is a polymer of diene, which are generally elastomers, and they made of vulcanized rubber. They are isolated diene.

Thus, the correct option is C) Isolated diene.

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The question is incomplete. The complete question is given below:

A) Conjugated diene.

B) Cumulated diene.

C) Isolated diene.

D) Alkynyl diene.

E) None of the above.

Answer:

D. carbohydrate, blue-purple

Explanation:

Carbohydrates are one of many types of macronutrients found in certain foods and drink. For example, sugars, starches, and fibers are carbohydrates.

When starch is present, using an iodine solution will turn it blue-black or purple. If starch is NOT present, it will stay orange or yellow. The reason starch reacts with iodine is due to the amylose present in starch. Iodine is not soluble in water, so it's dissolved along with potassium iodide that forms a triiodide molecule. That then enters the helical structure of amylose and changes its color.

The amount of charge required to reduce Zn²⁺ to Zn is 1585.26 coulomb.

The process that has been equipped with the use of electric current to break the chemical compound and deposited at the constituent electrodes is termed as electrolysis.

The reaction of reduction of Zn can be given as:

Zn²⁺ + 2e⁻ → Zn (s)

Molar mass of Zn = 65.39 g

The equivalent of Zn²⁺ has been:

Equivalent = atomic mass/equivalent weight

Equivalent Zn²⁺ = 65.39/32.69

Equivalent Zn²⁺ = 2 mol

1 equivalent = 1 F charge used

2 mol equivalent = 2 F charge used

Charge in coulomb can be given as:

1 Faraday = 96500 coulomb

2 F = 96500 * 2 coulomb

2 F = 1,93,000 coulomb

The moles of Zn to be deposited is:

Moles = weight /molar weight

Moles = 0.5371 g/ 65.39 g/mol

Moles = 0.00821 mol

Therefore, the charge used for the deposition of 0.00821 mol is:

Charge = 0.00821 * 1,93,000 coulomb

Charge = 1585.26 coulomb

1585.26 coulomb charge was used to reduce the Zn²⁺ to Zn.

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The percentage of excess air used during combustion process of ethane will be 37 %.

Burning, also known as combustion, would be a high-temperature highly exothermic chemical process that occurs when an oxidant, typically atmospheric oxygen, interacts with a fuel to generate oxidized, frequently gaseous products in a mixture known as smoke.

Calculation of percentage of air .

[tex]C_{2} H_{6} + (1-x)+a(O_{2} +3.76N_{2} )=bCO_{2} + cH_{2} O + axO_{2} + 3.76dN_{2} .[/tex]

Mair=Mair/Rin

[tex]( MN)O_{2}[/tex] + [tex](MN)N_{2}[/tex]÷ [tex](MN)O_{2}[/tex] + [tex](MN)N_{2}[/tex] +[tex](MN)C_{2} H_{6} .[/tex]

33 . 3.25(1-x) + 28 × 13.16(1-x) ÷ 33 × 3.25(1-x) + 28 × 13.16(1-x). + 30.1

= 176/176+8

X= 0.37

0.37 × 100

X= 37%

Therefore, the percentage of excess air used during combustion process of ethane will be 37 %.

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The highest energy transition state in the solvolysis of [tex](CH_{3} )_{3} CI[/tex] in [tex]CH_{3} OH[/tex] is given as ,

The mechanism of solvolysis of tert-butyl iodide follow nucleophilic substitution reaction . The nucleophilc substitution reaction are two types one unimolecular and second bimolecular  nucleophilc substitution .

The mechanism of solvolysis of tert-butyl iodide follows unimolecular nucleophilic substitution reaction in which carbocation is the intermediate which as a transition state of it. The carbocation formed by  solvolysis of tert-butyl iodide is 3° carbocation or tertiary carbocation which is most stable. The methanol as neutral nucleophile and oxygen of methanol  attack at carbocation intermediate.

Therefore , the highest energy transition state in the solvolysis of [tex](CH_{3} )_{3} CI[/tex] in [tex]CH_{3} OH[/tex] is given .

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Answer:

sorry i don't know this question of answer

The equation described by the kb value is 5.21 x [tex]10^-^3[/tex].

The potential of Hydrogen is what pH is formally known as. The negative logarithm of the concentration of H+ ions is known as pH. Thus, the definition of pH as the amount of hydrogen is provided. The hydrogen ion concentration in a solution is described by the pH scale, which also serves as a gauge for the solution's acidity or basicity.

Assuming  PO₄³⁻ (the phosphate anion).

PO₄³- + H₂O ==> HPO₄²⁻ + OH⁻

Kb = [HPO₄²⁻][OH⁻] / [PO₄³⁻]

We can find the [OH⁻] from the pH of 12.70.

pH + pOH = 14

14.0 - 12.7 = 1.3 = pOH

[OH] = 1x[tex]10^-^1^.^3[/tex]

[OH-] = 5.0x[tex]10^-^2[/tex] M

[HPO₄²⁻] = 5.0x[tex]10^-^2[/tex] M

Kb = (5.0x[tex]10^-^2[/tex])2 / 0.48

     = 2.5x[tex]10^-^3[/tex] / 0.48

Kb = 5.21 x [tex]10^-^3[/tex]

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An aqueous solution of hso−3 is created at 25∘c. is the solution basic in nature.

An aqueous solution is a solution wherein the solvent is water. Its miles are primarily shown in chemical equations by appending them to the relevant chemical formula.

An aqueous solution is a water that carries one or more dissolved materials. The dissolved substances in an aqueous answer can be solids, gases, or different beverages.

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At 25°C, an aqueous solution of hso3 is formed. This is the solution basic in nature.

Aqueous solutions are those in which the solvent is water. Its miles are often represented in chemical equations by attaching them to the appropriate chemical formula.

An aqueous solution is a mixture of water and one or more dissolved components. Solids, gases, or various beverages can be dissolved in an aqueous solution.

Aqueous solutions contain liquid water as the solvent. Solute (dissolved) ions and molecules are surrounded by water molecules and absorbed into the water's network of bonds. After then, the dissolved species diffused throughout the water.

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Answer:

Section 2 will decrease.

Explanation:

A catalyst is a substance that increases the rate of the chemical reaction without taking part in the overall reaction. Catalysts speed up a reaction by lowering the activation energy needed for a reaction to take place. The activation energy is the minimum energy necessary for a reaction to take place. As such, when a catalyst is added, the activation energy (or the potential energy) needed to start the reaction decreases. This shows itself in the graph by decreasing the "hump" in Section 2.

It should be noted that Sections 1 and 3 will remain the same. This is because the energy of the reactants and products does not change regardless of a catalyst being present.

The volume is the product of the molar concentration and the moles of the substance. The volume of hydrochloric acid that can be added to the buffer is 0.066 L.

A buffer is a constant solution with a proton or hydrogen ion concentration with an acid, base, or salt dissolved in them.

The chemical reaction between hydrochloric acid and sodium acetate is given as,

HCl + CH₃Coo-Na → CH₃CooH + NaCl

From above the initials moles of acetic acid are given as,

Moles = molarity × volume

= 0.139 M × 0.0346 L

=  0.0048 moles

The initials moles of sodium acetate are given as,

M = 0.182 M × 0.0365 L

= 0.0066 moles

As it is known that the ratio of the buffer capacity is 10 for sodium acetate and acetic acid so,

Moles sodium acetate ÷ Moles Acetic acid = 10

(0.0066 moles + X) ÷ (0.0048 moles - X)  = 10

Here, X is the moles of HCl and is calculated as,

0.0066 moles + X = 0.048 moles - 10X

11 X = 0.048 ÷ 0.0066

11 X = 7.27

X = 0.66 moles  

The volume of 0.100 HCl with 0.66 moles is:

Volume = moles × molarity

= 0.100 × 0.66

= 0.066 L

Therefore, 0.066 L of 0.100 M HCl is required to reach the buffer capacity.

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Answer:

A

Explanation:

Isotopes are atoms of the same element with the same number of protons and electrons but different numbers of neutrons.

Isotopes can also be defined as atoms of the same element with the same atomic number but different mass numbers e.g isotopes of chlorine, oxygen and so on.Oxygen for instance has three isotopes with the same atomic number,8 and different mass numbers,16,17 and 18.

Explanation:

metallic conduction:the movement of electrons through a metal, with no changes in the metal and no movement of the metal atoms.

I hope this help uuhh............

The 7160 cal energy is required to melt 10. 0 g of ice at 0. 0°C, warm it to 100. 0°C and completely vaporize the sample.

Calculation,

Given data,

Mass of the ice = 10 g

Temperature of ice =  0. 0°C

Heat required at this stage = mas of the ice ×latent heat of fusion of ice

Heat required at this stage = 10 g×80 = 800 cal  

Heat required for this = mass of the ice×rise in temperature×specific heat of water

Heat required for this  = 10 g×100× 1 = 1000 cal

Heat required for this = Mass of water× latent heat

Heat required for this  = 10g ×536 =5360 cal

Total energy or heat required = sum of all heat = 800 +1000+ 5360  = 7160 cal

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Answer:

6molO2 3/2O22Fe=4,5024molFe .

Explanation:

You have to start with the balanced chemical equation. Iron is just Fe. Oxygen in nature is found as an O2 molecule.

2Fe(s)+3/2O2(g) Fe2O3(s)

If you check the balance. There are two Fe on both sides of the equation and three O on both sides, so it’s balanced.

Now use the stoichiometric ratios (the coefficients of the balanced chemical equation) to convert 6 mol of oxygen to iron.

6molO2 3/2O22Fe=4.5024molFe .

These coefficients can be used as conversion factors when it comes to substance moles.

Some of you may insist that a balanced chemical reaction must have whole numbers. This is not really necessary. The reaction I wrote above is a named type of reaction, called Fe2O3 formation. In this type of reaction, there must be a mole of product so that it requires that sometimes there are fractional numbers for the coefficients in the reagents.

But, just for the argument, let’s rebalance the equation for integer coefficients only.

4Fe(s)+3O2(g) 2Fe2O3(s)

We are now using the coefficients as conversion factors, as we have done before.

Density of ZnS given that the zn-s distance and bond angle are 0. 234 nm and 109. 5o, respectively if the atomic weights of zinc and sulfur are 65. 41 g/mol and 32. 06 g/mol. is 4.1109 g/cm³

For density In the crystal structure, we determine the angle's value for one set of ZnS bonds. θ θ + ∅ + 90° = 180° θ = 90° - ∅ θ = 90° - (109.5° / 2) After determining that = 35.25°, we derive the value of x from the geometry: distance angle d = 0.234 x = dsin = 0.234 sin35.25°) = 0.135 nm = 0.135 107 cm; following this, we get the length of the unit cell: a = 4x a = 4(0.135) a = 0.54 nm = 0.54 107 cm; and The formula for n' is (number of corner atoms in unit ell contribution of each corner atom in unit cell) + (number of face center atoms in unit cell contribution of each face center atom in unit cell). n' = 8 × 1/8) + (6 × 1/2) = 1 + 3 = 4

Density = P = [4( 65.41 + 32.06)] / [ ( 0.54 × 10⁻⁷ )³ × (6.023 × 10²³)] = 389.88 / 94.84 = 4.1109 g/cm³

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N3- and Mg2 ions have the same ground-state electron configuration.

Understanding molecule bonding, characteristics, and structures begin with understanding ground state electron configurations. The ground state electron configuration provides insight into a wide range of atomic properties, including the electrons in an atom, distinct orbitals, and hybridization.

The ground state of an atom's electrons is the lowest energy state that is feasible for that atom since, throughout the cosmos, a system's natural state is to use the least amount of energy.

Aufbau-Principle: If you have a lot of luggage, you'll probably choose the room that is closest to the ground floor in a hotel without an elevator. The Aufbau principle demonstrates the identical behavior of electrons in the ground state. According to the Aufbau principle, electrons first occupy lower energy orbitals before moving on to higher energy orbitals.

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The molar mass of the other gas is 450.56 g.

Relation between rate of diffusion and molar mass of two gases is given by:

r₁/r₂ = (√m₂)/(√m₁)

Given,

r₁ = 3.2r₂                          

(r₁ is the diffusion rate of CO₂ and r₂ is the diffusion rate of the other gas)

We know

m₁ = molar mass of CO₂ = 44 g

To find,

m₂ = molar mass of the other gas =?

Put the values in the above equation,

r₁/r₂ = (√m₂)/(√m₁)

3.2r₂/r₂ = (√m₂)/(√44)

3.2 = (√m₂)/(√44)

Squaring both the sides,

10.24 = m₂/44

m₂ = 10.24 (44)

m₂ = 450.56 g

Hence, the molar mass of the other gas is 450.56 g.

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Answer:

0.71 moles KI

Explanation:

At STP, there should be 1.0 moles at 22.4 L. However, there are only 8.0 L of I₂. Therefore, we must set up a proportion to find the correct moles of I₂.

[tex]\frac{1 mole}{22.4 L} =\frac{? moles}{8.0 L}[/tex]                                <----- Proportion

[tex]8.0 = 22.4(? moles)[/tex]                         <----- Cross multiply

[tex]0.36 = ? moles[/tex]                                 <----- Divide both sides by 22.4

To find the moles of KI, you can use the mole-to-mole ratio from the balanced equation coefficients. The final answer should have 2 sig figs.

2 KI(aq) + Cl₂(g) ---> 2KCl(aq) + 1 I₂(g)
^                                                   ^

0.36 moles I₂          2 moles KI
----------------------  x  --------------------  =  0.71 moles KI
                                   1 mole I₂

Answer: 0.71 moles KI

Explanation:

The relative velocity is described as the velocity of an object with respect to another viewer. It is the time rate of shift of relative position of one object with respect to another object.

a) Velocity of car A (Va) = 20m/s

Velocity of car B (Vb) = -6m/s

To find the Relative Velocity, we should apply the formula as,

Relative Velocity of car A and car B = Vab

Vab = Va - Vb

Vab = 20 - (-6)

Vab = 20+6

Vab = 26m/s

b). if Velocity of car A = Velocity of car B

Va = Vb

In this case,

Relative Velocity = Vab

Vab = Va - Vb

(since Va = Vb)

Vab = 0m/s

Hence, the Relative Velocity in a). is 26m/s and in b). is 0m/s.

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Considering the definition of pH, the hydronium ion concentration [H₃O⁺] of the solution is  1×10⁻³ M.

pH is the Hydrogen Potential. It is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

Mathematically, pH is calculated as the negative base 10 logarithm of the activity of hydrogen ions:

pH= - log [H⁺]= -log [H₃O⁺]

The numerical scale that measures the pH of substances includes the numbers from 0 to 14. The pH value 7 corresponds to neutral substances. Acidic substances are those with a pH lower than 7, while basic substances have a pH higher than 7.

In this case, being pH= 3, you can replace this value in the definition of pH:

3= -log [H₃O⁺]

Solving:

[H₃O⁺]= 10⁻³ M

[H₃O⁺]= 1×10⁻³ M

Finally, the hydronium ion concentration [H₃O⁺] of the solution is  1×10⁻³ M.

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The mechanism for the interconversion of α-d-glucose and β-d-glucose in dilute HCl include the proton transfer in first step and nucleophilic attack in second step.

In the first step oxygen donates its lone pair of electron to hydrogen of HCl. There is removal of water molecule from the substance α-d-glucose.

The organic reaction where one nucleophile replaces another is called nucleophilic substitution reaction. These reaction takes place in aromatic compounds, acyl compounds and aliphatic compounds. SN¹ reactions are nucleophilic substitution reaction.

Thus from the above conclusion we can say that The mechanism for the interconversion of α-d-glucose and β-d-glucose in dilute HCl include the proton transfer in first step and nucleophilic attack in second step.

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The mass of AgCl precipitated is 0.215g.

Precipitate is to form an insoluble compound either by reacting two salts or by changing the temperature to affect the solubility of the compound.

To calculate mass of AgCl precipitate -

The first step is to make a balanced chemical equation.

2AgNO3 + CaCl2 ---> 2AgCl + Ca(NO3)2

Molecular Weights:

CaCl2 = 110.98 g/mol

AgNO3 =170.01g/mol

AgCl= 143.45 g/mol

Volume:

CaCl2: 30.0mL=0.03L

AgNO3: 15.0mL=0.015 L

mole  CaCl2 = 30/1000 x 0.2 =0.006

mole  AgNO3 =15/1000 x 0.1 = 0.0015

CaCl2 is in excess so 0.0015 mole AgCl  will form

0.0015 x 143.5 = 0.215g

The 0.215 mass in grams of AgCl will precipitate.

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Answer:

sublimation because it's has changed from solid to gaseous

1. I think r0b a bank would be such a rush. Imagine r0b a bank, driving a souped up getaway vehicle, and then successfully escaping with loads of cash...., that would be such an adrenaline rush.

2. Nationwide animal release. Just ninja into pounds and shelters and set them all free. It'd get to the point that they'd have to get armed guards. Soon wild packs of pugs and Chihuahuas roam freely claiming their territory against man.

3. Putting glitter bombs in mailboxes. Not sending but personally taping it in there so it goes off when opened.