PLEASE HELP IN STUCK

Angelique takes 8 hours to drive from a to b.

How quickly something or someone is moving is indicated by their speed. If you know how far something travels and how long it takes, you can calculate their average speed. Speed equals distance  x times time, according to the speed formula. Knowing the units for distance and time will help you determine what the units are for speed.

let us assume distance from a to b be x units.

let us assume speed of vehicle be y units/hour.

For Satia, speed=y units time=4 hours we know the formula of distance is:

     distance=speed × time distance=(y× 4) units               -------------------(1)

        Angelique :speed=y / 2 units time=?

We know the formula of distance is:

Distance=speed × time distance=(y/2)× time            -------------------(2)

We can see that distance in both cases is equal,

So compare case (1) ad (2) ,

We get  (y× 4)=(y/2)× time

On rearranging ,

Time= (4×2) hours=8 hours

hence,

Angelique takes 8 hours to cover the distance from a to b.

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Answer:

1441.503 square inches

Step-by-step explanation:

155×60cm=9300square centimeter

9300 divide 6.452 to change to square inches.

Ans=1441.503

Answer:

64.58 sq.in

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

The growth factor is the same as the base of the exponential factor.

The value of the function [tex]$f(x)=(1/3)(6)^x[/tex] growth factor exists 6.

function [tex]$f(x)=(1/3)(6)^x[/tex]?

Given: [tex]$f(x)=(1/3)(6)^x[/tex]

For any equation [tex]$ f(x)=ab^x[/tex]

Let, 'a' exists the initial value

b exists the growth or decay factor.

When the value of b exists greater than 1 then its growth factor

when the value of b exists between 0 and 1 then it exists a decay factor

Let x exists the number of years

Given function, [tex]$ f(x)=(1/3)(6)^x[/tex]

The value of b exists 6.

So the growth factor exists 6.

Therefore, the correct answer is option c. 6.

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Answer: I believe it is 4m

Step-by-step explanation:

m+m+m+m would be equivalent to 4m which is 4 times m

Step-by-step explanation:

It's like you're adding 1+1+1+1 which equals 4 so that's what I think

Answer:

Step-by-step explanation:

3 units

Answer:

3 units.

Step-by-step explanation:

Opposite sides of a parallelogram are equal in length,

So side OD = side WS.

We see from the diagram that OD is 3 units long so

WS = 3 also.

The summary of the given data is are as follows :-

Minimum: 11

Lower quartile:11

Median:24

Upper quartile:34

Maximum:45

Interquartile range:23

Given :- 9, 11, 11, 16, 16, 24, 28, 30, 34, 42, 45

Minimum = The smallest number of data

Thus Minimum = 11

Maximum = The largest number of data

Thus Maximum = 45

Median = The middle number of the data if data consists of odd number of elements

Thus Median = 45

Lower quartile = The median of the lower half of data

Thus Lower quartile = 11

Upper quartile = The median of the upper half of data

Thus Upper Quartile = 34

Interquartile range = The difference of upper and lower quartiles,

Thus Interquartile range = 34 -11 = 23

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Answer:

A = 0; B = -9/2

Step-by-step explanation:

To have no solutions, you need parallel lines with equal slopes and different y-intercepts.

3x + 4y = A      Eq. 1

Bx - 6y = 15     Eq. 2

In Eq. 1, notice that the coefficient of x is 3/4 of the coefficient of y.

We must have the same ratio for the coefficients in Eq. 2.

B/(-6) = 3/4

4B = -6(3)

4B = -18

B = -9/2

Now we have

3x + 4y = A      Eq. 1

-9/2 x - 6y = 15     Eq. 2

How do we change the left side of the second equation into the left side of the first equation? -6/4 = -3/2 and also -9/2 ÷ 3 = -3/2

To change the left side of the second equation into the left side of the first equation, divide the left side by -3/2.

If we divide 15 by -3/2 we get -10.

The equation -9/2 x - 6y = -10 is the same as Eq. 1, so that would create a system of equations with only one equation and an infinite number of answers.

To have no equations, the y-intercepts must be different, so A can be any number other that -10.

Answer: A = 0; B = -9/2

The 125 feet long line and the angles 65°10', and 60°10' obtained from the surveying equipment gives the length of the bridge as approximately 1234.2 feet.

Given;

Location of the tree = The other side of the river from the surveyor

Length of the line measured along the river, L = 125 feet

Angle to the tree from the start of the line = 65°10'

1° = 60'

10' = ((1/60)×10)° = (1/6)°

65°10' = (65 + 10/60)° = (65 + 1/6)°

Angle measured at the end of the line, E = 60°10'

Similarly;

E = 60°10' = (60 + 1/6)°

The interior angle, S, of the triangle formed by the tree and the line, at the start of the line is therefore;

Angle S = 180° - (65 + 1/6)° = (114+5/6)° (linear pair angles)

S = (114+5/6)°

From the angle sum property of a triangle, angle formed at the tree, T, is therefore;

T = 180° - ((114+5/6)° + (60 + 1/6)°) = 5°

According to the rule of sines, we have;

l/(sin T) = b/(sin E)

Where;

b = The length of the bridge

Which gives;

124/(sin 5°) = b/(sin (60 + 1/6)°)

b = (sin (60 + 1/6)°) × (124/(sin 5°)) ≈ 1234.2

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Answer:

1/311875200.

There is exactly 1 way to have all 5 of these cards.  For the first card, there are 52 total cards to be had; for the second, 51; for the third, 50; for the fourth, 49; and for the fifth, 48:

(1/52)(1/51)(1/50)(1/49)(1/48) = 1/311875200.

Step-by-step explanation:

Answer:

Saturday

Step-by-step explanation:

2 days before (starting from Monday) is Saturday

Answer:

Step-by-step explanation:

The relevant relations here are ...

The given arc CD is part of the semicircular arc CDA. The remaining arc, DA, is the supplement of CD:

  arc DA = 180° -CD = 180° -125° = 55°

Central angle AOD has the same measure, 55°. That is one of the acute angles in right triangle AOB, so the other one is the complement of 55°.

 ∠ABO = 90° -∠AOB = 90° -55°

  ∠ABO = 35°

In right triangle ABC, angle ABC is given as 55°. The other acute angle, ACB, will be the complement of this.

  ∠ACB = 90° -∠ABC = 90° -55°

  ∠ACB = 35°

In the figure, angles ABO and ACB have measures of 35°.

Answer:

x=0, x= -9

Step-by-step explanation:

First we simplify the equation into the form

ax^{2}+bx+c=0

By adding 4x+3 on both sides, we form the equation

x^{2}+9x=0

Now, we factor out the common factor: x.

x(x+9)=0

The only values that allow x(x+9) to be equal to 0 are:

x=0  or

x+9=0

The solutions are x=0 or x= -9

[tex]CD=14.37cm.[/tex]

Find CD:

Let,

[tex]r_{1}[/tex] be a radius of Circle A

[tex]r_{2}[/tex] be a radius of Circle B

Given:

[tex]r=4cm.[/tex]

Circumference: [tex]2\pi r[/tex]

[tex]2\pi r_{1} =20[/tex]

[tex]r_{1} =\frac{10}{\pi }[/tex]

[tex]CD=D_{1} +D_{2}[/tex]

[tex]=2r_{1} +2rx_{2}[/tex]

[tex]=2*(\frac{10}{\pi } )+2*4[/tex]

[tex]CD=14.37cm.[/tex]

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Answer:

Y-intercept = 22

Step-by-step explanation:

The equation of a line in slope-intercept format is given by the equation y=mx+c

where m is the slope and c the y-intercept.

(The y-intercept is the value of y when x = 0)

Slope given as -4

And we know it passes through the point(4,6) ie at x=4, y =6

Substitute in above equation to get value of c, the y-intercept

6 = -4(4) + c

6 = -16 + c

c = 22

And this is the y-intercept

The equation of the line is y = -4x + 22

See attached figure for graph

Answer: 4.0 * 10^0 kg = 4.0 kg essentially

Step-by-step explanation:

No need to convert these to numbers...

Weight of 1 bee: 1 * 10^-4 = (0.0001 kg)

Number of bees: 4 * 10^4 = (40000 bees)

(1 * 10^-4) * (4 * 10^4) =

(1 * 4) * (10^-4 * 10^4) =

(10^0 because when multiply exponential numbers, you add the exponents)

4 * 10^0 =

4 * 1 = 4 kg

Answer:

2280 minutes.

Step-by-step explanation:

Time spent each week in lessons = (Lessons per week)(Time per lesson)

= (6)(38)

= 228 minutes/week

Time spent in a 10-week period:

10 weeks * 228 minutes/week

= 2280 minutes

Use conversion factors to determine the time in the desired units (i.e. Hours, seconds, etc.).

Hope this helps!

Answer:

a) Class A has the larger interquartile range.

b) Class A has the highest test score.

c) Class B has higher median test score.

d) Class B has smaller range of test score.

Step-by-step explanation:

a) Inter quartile range (IQR) =  upper quartile - lower quartile

  Class A:  IQR = 79 - 65 = 14

  Class B: IQR = 77 - 70 = 7

Class A has larger interquartile range.

b)  Class A has the highest test score.

c) Median of class A = 70

 Median of class B   = 74

Class B has higher median test score.

d) Range is the difference between the highest and lowest score.

Range = highest score - lowest score

 Range of Class A = 85 - 62 = 23

 Range of class B  =  79 - 68 = 11

Class B has smaller range of test score.

Answer:

22.05

Step-by-step explanation:

First, convert 63% into a decimal.

To do this, divide it by 100.

[tex] \frac{63}{100} = 0.63[/tex]

Multiply 0.63 by 35.

[tex]35 \times (0.63) = 22.05[/tex]

Answer:

Step-by-step explanation:

.63(35)= 22.05

Multiply .63(35)

Answer:

-2

Step-by-step explanation:

<________|____|___-2___|___0___|____|____|____4________>

                                    E                                                    D

The Point E is located at -2.

Given that Point D is located at 4. Point E is 6 less than Point D.

We need to find the location of the point E.

Based on the information provided, Point D is located at 4. Now, we know that Point E is 6 less than Point D.

When we say, "less than," it means we need to subtract the given value from Point D to find the location of Point E.

If Point D is located at 4, and Point E is 6 less than Point D, then the location of Point E can be calculated as follows:

E = D - 6

Since D is 4, we can substitute that value into the equation:

E = 4 - 6

E = -2

So, Point E is located at -2.

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The perimeter of the rhombus FGHJ is 20 units

The coordinates are given as:

F = (-2, -2)

G = (-2, 3)

H = (2, 6)

From the question, we understand that vertex J is directly below vertex H.

This means that vertices H and J have the same x coordinate.

So, we have

J = (2, y)

The distance between F and G is 5 units,

So, we have

J = (2, y - 5)

Where

y = 6 i.e. the y coordinate of H

This gives

J = (2, 6 - 5)

Evaluate

J = (2, 1)

See attachment for the graph of the rhombus

In (a), we have:

The distance between F and G is 5 units,

This means that

FG = 5

The side lengths of a rhombus are equal.

So, the perimeter is

P = 4 * FG

This gives

P =4 * 5

Evaluate

P = 20

Hence, the perimeter of the rhombus is 20 units

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[tex]\Large\texttt{Answer}[/tex]

[tex]equation=[/tex][tex]\bold{y=5x-33}[/tex]

[tex]\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}[/tex]

[tex]\Large\texttt{Process}[/tex]

⇨ Use the formula below

[tex]\bf{y-\hfill\stackrel{y \:co-ordinate}{y1}=\hfill\stackrel{slope}{m}(x-\hfill\stackrel{x\:co-ordinate}{x1)}}[/tex]

⇨ Substitute the parameters:

[tex]\bold{y-(-8)=5(x-5)}[/tex]

[tex]\bold{y+8=5x-25}[/tex]

[tex]\bold{y=5x-33}[/tex]

Hope that helped

is there a picture included in this problem? if so please comment it so i can answer this problem.

A graph for the data (time and distance) shown in the given table is plotted in the image attached below.

A graph can be defined as a type of chart that's commonly used to graphically represent data on both the horizontal and vertical lines of a cartesian coordinate, which are the x-axis and y-axis.

A linear function can be defined as a type of function whose equation is graphically represented by a straight line on the cartesian coordinate.

This ultimately implies that, the data of a linear graph are directly proportional and as such as the value on the x-axis increases or decreases, the values on the y-axis also increases or decreases.

In this exercise, you're required to plot a graph for the data (time and distance) that are recorded for an object that is starting from rest.

By critically observing the graph (see attachment) which models the data in the given table, we can infer and logically deduce that the linear function is given by:

y = 67.814x

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well, let's notice the denominators, hmmm so we can use as the LCD say the expression of "rpq", so, let's multiply both sides by the LCD of "rpq" to do away with the denominators.

[tex]\cfrac{2}{r}+\cfrac{1}{p}=\cfrac{1}{q}\implies \stackrel{\textit{multiplying both sides by } ~~ \stackrel{LCD}{rpq}}{rpq\left( \cfrac{2}{r}+\cfrac{1}{p} \right)=rpq\left( \cfrac{1}{q} \right)}\implies 2pq+1rq=1rp \\\\\\ 2pq+rq=rp\implies rq=rp-2pq\implies rq=\stackrel{\textit{common factoring}}{p(r-2q)}\implies \cfrac{rq}{r-2q}=p[/tex]

Answer:

f(x) = 5x - 5

Step-by-step explanation:

f(x) = 5x - 5 is a linear equation as it has no power.

Answer:

Step-by-step explanation:

Remember the midpoint formula:

[tex](\frac{x2+x1}{2},\frac{y2+y1}{2} )\\[/tex]

Substitute in your values

 [tex](\frac{7.6+21.8}{2},\frac{1.7+9.3}{2} )\\[/tex]

Solve

[tex](\frac{29.4}{2},\frac{11}{2} )\\(14.7,5.5)\\[/tex]

Answer: (14.7,5.5)

Step-by-step explanation: I got it right on the test...

Answer:

[tex]y=\frac{-x}{78} -\frac{220}{78}[/tex]

Step-by-step explanation:

Remember to create a line perpendicular to one another the slope has to be the reverse reciprocal of the first line.

Given the current slope is [tex]\frac{-78}{1}[/tex] the new slope would be [tex]\frac{1}{78}[/tex].

To find the line that passes through a point with a given slope we must use point slope form, remember the default equation of point slope form:

[tex]y-y1=m(x-x1)[/tex]

Where y1 is the y value of the point, m is the slope, and x1 is the x value of the point.

Lets substitute in our values

[tex]y-(-3)=\frac{-1}{78} (x-14)[/tex]

Simplify the equation

[tex]y+3=-\frac{1}{78}\left(x-14\right)\\y+3=\frac{-x}{78}+\frac{14}{78}\\y=\frac{-x}{78}-\frac{220}{78}\\[/tex]

Use hit and trial method

Answer is (-1,4)

Verification

Put x and. y

Option A

The equation be 20.10 = X × 3 × 5/100 then, the value of X = 134.

To estimate the value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to estimate the result.

The formula for Simple Interest exists PTR/100,

where, P = Principal

T = Time period in years

R = Rate of interest per annum.

Simple interest = PTR / 100

20.10 = X × 3 × 5/100

simplifying the above equation, we get

20.10 = 15X / 100

15X = 20.10 × 100 = 2010

X = 2010/15 = 134

X = 134.

Therefore, the value of X exists at 134.

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