Answer:
If I'm not mistaken that is the answer
Pls answerrrrrrrrrrr
johns first three test scores out of 100 are 84,78,82. what did he score on his fourth test if the average for all four tests is 80 out of 100
Answer:
76
Step-by-step explanation:
In order for John's average to be 80, the sum of all of his test scores must be 4*80 = 320. We can add 84, 78, and 82 to get 244, and then we subtract 244 from 320 to obtain the answer 76.
Answer:
Step-by-step explanation:
80 * 4 = 320
84 + 78 + 82 + x = 244
244 + x = 320
x = 320 - 244
x = 76
Find the surface area of the composite figure.
4 cm
13 cm
3 cm
4 cm
SA
=
12 cm
[?] cm²
5 cm
3 cm
The surface area of the composite figure is: 300 cm².
What is the Surface Area of a Triangular Prism?Surface area of a triangular prism = (P)L + bh, where we have the following:
P = perimeter of the base
L = length of the triangular prism
h = height of the triangular base
b = base of the triangular base
What is the Surface Area of a Rectangular Prism?Surface area = 2(wl + hl + hw), where:
h = height of prism
w = width of prism
l = length of prism.
The surface area of the composite figure = surface area of triangular prism + surface area of rectangular prism - 2(the area where both figures are joined at).
Surface area of the triangular prism = (5 + 12 + 13)4 + (5)(12)
Surface area of the triangular prism = 180 cm²
Surface area of rectangular prism = 2(wl + hl + hw) = 2·(4·12+3·12+3·4) = 192 cm²
The area where both figures are joined at = (l)(w) = (3)(12) = 36 cm².
The surface area of the composite figure = 180 + 192 - 2(36)
The surface area of the composite figure = 180 + 192 - 72
The surface area of the composite figure = 300 cm².
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Ken can run m miles at a
pace of 6.30 minutes per
mile. He ran slower for 10
minutes to warm up.
Write an equation that
represents the total time,
t, Ken spent running.
Equation that represents the total time t (in minutes) Ken spent running is = 10 + m/6.30.
In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign = The word equation and its cognates in other languages may have subtly different meanings; for example, in French an équation is defined as containing one or more variables, while in English, any well-formed formula consisting of two expressions related with an equals sign is an equation
How to solve such time related questions?
The key concept for solving such questions is the relationship between speed, distance and time.
The relationship between them is Distance = Speed x Time
Total time t (in minutes) =Initial Time + distance/speed
Given :-
Distance = mSpeed = 6.30 miles per hourInitial Time = 10 minThus,
t = 10 + m/6.30.
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A rhombus with horizontal diagonal length 25 millimeters and vertical diagonal length 8 millimeters. what is the area of the rhombus? 25 mm2 33 mm2 50 mm2 100 mm2
The area of the rhombus is 100 mm². The correct answer is D.
What is a rhombus?A rhombus is one type of parallelogram and has 4 sides and 4 vertices.
Every side is equal in length and opposite angles are equal.
Given:
A rhombus with horizontal diagonal length 25 millimeters,
and vertical diagonal length 8 millimeters.
Let d₁ = 25 mm and, d₂ = 8 mm.
Let A be the area of rhombus.
To find the area of rhomus:
Using diagonals,
A = (1/2) × d₁× d₂.
Substituting the values of diagonals,
A = 1/2 x 25 x 8
A = 200/2
A = 100 mm².
Therefore, 100 mm² is the area of the rhombus.
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Write a series of instructions that will multiply eax by 18, using a combination of shift, mov, and add instructions
MOV EBX,EAX
SHL EAX,4
SHL EBX,1
ADD EAX,EBX these are the series of instructions that will multiply eax by 18, using a combination of shift, mov, and add instructions.
STEPS:
1. Copy EAX into another register, say EBX
2. We know that shift left by 'n' bits results in multiplication with 2^'n' , so perform shift left operation of EAX by 4 bits ( results in multiplication of EAX with 16) and perform shift left operation of EBX by 2 bits(results in multiplication of EBX with 2)
3. Now add EAX and EBX which is the required answer ( Since, i*16 + i*2 equals to i*18 )
INSTRUCTIONS:
mov ebx,eax ; make copy
shl eax,4 ; eax * 16
shl ebx,1 ; ebx * 2
add eax,ebx ; answer
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In 2010 and 2012, gallup asked the same 50 people how many hours had they worked at a job in the past 7 days. Is there a difference in the population mean amount of hours worked at a job between 2010 and 2012? would this be an example of independent or dependent samples?.
The given case of Gallup asking the same 50 people how many hours had they worked at a job in the past 7 days. is an example of dependent sample.
What is dependent sample?The measured values in relation in a dependent sample (also called a paired sample).
Some characteristics of dependent sample are-
It is a dependent sample, for instance, if a sample of patients who have knee reconstruction is selected, and each patient is questioned during the procedure. The reason for this is that the identical person was questioned twice.If, for instance, you wish to examine if a new category of baseball bat really does have an impact on notable features and the same individuals play once from the old bat and once with new bat, you also have a dependent sample. Since each player utilized both bats, there are two measured values for each player, all measured values are likewise accessible in pairs.A variation is preselected based on the format wherein you insert your data. A series is typically a respondent and, more broadly, a case. Metric values in a sequence are therefore originally regarded as dependent.To know more about dependent sample, here
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Select the correct answer. which exponential equation is equivalent to this logarithmic equation?
logarithmic equation log x = 4 is given by- [tex]10^{4}[/tex] = x
What is logarithmic equation?
A logarithmic equation is an equation that involves the logarithm of an expression containing a variable. To solve exponential equations, first see whether you can write both sides of the equation as powers of the same number.The given logarithmic equation is;
[tex]log x = 4[/tex]
Since, log with base 10 is written as [tex]log x[/tex] simply, therefore, we have:
[tex]log_{10} x[/tex] = 4
Using the definition of logarithm, we get;
[tex]x = 10^{4}[/tex]
Equivalently, [tex]10^{4} = x[/tex]
Thus, the exponential equation out of the specified options that is equivalent to this logarithmic equation log x = 4 is given by- [tex]10^{4}[/tex] = x
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The complete question is -
Which exponential equation is equivalent to this logarithmic equation?
log x = 4
Explain why the surface area of a right prism can be found using the formula
A = ph + 2B
where p = the perimeter of the base, h = height and B = the area of the base.
Answer:
ph : perimeter = 4 sides of the base; p*h = the area of the sides of that prism
B : 2 areas of the base = top and bottom
A right prism consists of a rectangle and two undersides S night prism =
S rectangle + 2S base
the length of the rectangle is the circumference of the base which is P so A = ph + 2B
NEED URGENT HELP: A random sample is taken of people who have bought tickets for a concert. In the sample, 21 out of 150 people say they will contribute $5.00 each towards a music scholarship for a local high school students. If 3,500 people bought concert tickets, predict how much will be raised for the scholarship.
Answer:
$2,450
Step-by-step explanation:
21:150 is the ratio of people who will donate $5.
21:150 / 3 = 7:50
7:50 x 2 = 14:100
14:100 = 21:50
14:100 x 35 = 490:3500
490 out of 3500 people will contribute $5.
490 x 5 = $2,450
what are the zeros of the function g(x)=x^2+3x-4
The zeroes of the function g(x) = x² +3x -4 as given in the task content is; x = -4 and x = 1.
What are the zeroes of the function given g(x) as represented in the task content?It follows from the task content that the function g(x) given in the task content is; g(x) = x² +3x -4.
On this note, it follows that the zeroes of the function can be determined by solving the quadratic function as follows;
x² +4x -x -4 = 0
(x+4) (x-1) = 0
Ultimately, it can be concluded that the values of x which represents the zeroes of the function are; x = -4 and x = 1.
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Howard buys 6 plants if same price from a flower shop for $640 including the shipping fee. If the shipping fee is $100, find the price of each plant.
If 2x + 5 ≤ 9, what is the greatest possible value of
2x - 5 ?
Answer:
-1
Step-by-step explanation:
Since we have the linear equation, 2x-5, and it's increasing since the slope is positive, that means we want the maximum x-value, to find the maximum y-value, or possible value.
This means, we want to find the maximum x-value of 2x+5 that is less than or equal to 9, and since we want the maximum x-value, we want the right side to also be the maximum, and since we have a less than or equal to symbol, we can have the equation equal to 9, which is the make value. So we get the following equation
[tex]2x+5=9\\[/tex]
Subtract 9 from both sides
[tex]2x=4[/tex]
Divide both sides by 2
[tex]x=2[/tex]
This is the maximum x-value we can get from the inequality, and now we plug this into the equation 2x-5
[tex]2(2)-5[/tex]
4-1
-1
So the maximum value is -1
A shape has an area of 37 mm², of which 60%
is green.
The shape is enlarged so that all its side lengths
increase by 45%.
Work out the area of the green part of the larger
shape.
If your answer is a decimal, give it to 1 d.p.
If the side are increased by 45% then the area of green part will be 26.6955 [tex]mm^{2}[/tex].
Given that area of a shape of 37 [tex]mm^{2}[/tex] in which 60% is green.
We are required to find the area of green region if the side is increased by 45%.
Area is basically part of a surface covered by a shape.
When the side is increased by 45% then the area will increase by 45%*45%=20.25%.
Increased area =37*20.25%=7.4925
New area=37+7.4925
=44.4925
We have been given that 60% is the area of green.
Area of green region=44.4925*60/100
=26.6955 [tex]mm^{2}[/tex]
Hence if the sides are increased by 45% then the area of green part will be 26.6955 [tex]mm^{2}[/tex].
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What is the volume of the pyramid
Answer:
Option A - 32 cm³
Step-by-step explanation:
Volume of a pyramid is given by the formula :
V = [tex]\frac{lwh}{3}[/tex]
Substituting values given gives us :
V = (4)(4)(6)/3
V = (16)(6)/3
V = 96/3
V = 32
Units will be cm³ as this is volume
Hope this helped and have a good day
Answer:
A. 32 cm³
Step-by-step explanation:
V = (1/3)(area of base)(height)
The base is a square of side 4 cm.
area of base = side × side
V = (1/3)(4 cm × 4 cm)(6 cm)
V = 32 cm³
PLS HELP IM STUCK PLS
The slope of the linear function described in this problem is:
m = -3.
What is a linear function?A linear function is modeled by:
y = mx + b
In which:
m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.In this problem, the line goes through points (5,3) and (8,-6). Considering that the slope is given by change in y divided by change in x, for this function, it is given by:
m = (-6 - 3)/(8 - 5) = -9/3 = -3
The slope of the linear function described in this problem is:
m = -3.
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Solve x in the equation 3x=2
❄ Hi there,
let us first figure out what we need to do to find x in this equation.
Since x is
multiplied by 3we will
divide by 3In other words we'll do just the opposite.
[tex]\sf{3x=2}\\\sf{x=\dfrac{2}{3}}[/tex]
That's it!
❄
A circle is shown. Points Q, U, A, D are on the circle. Lines connect the points to form a quadrilateral. Angle Q U A is 111 degrees. Arc Q U is 88 degrees.
What is the measure of Arc A U?
44°
50°
64°
92°
The measure of Arc AU of the given Circle Geometry is; 50°
How to find the measure of arc angle?The circle theorem we will apply to solve for the arc measure states that “Measure of angles subtended to any point on the circumference of the circle from the same arc is equal to half of the angle subtended at the center by the same arc.”
We can express the above theorem as;
Angle at the center = 2 × Angle at the circumference
From the attached image below and from the given statement in the question, we are given that; ∠QUA = 111°
Therefore, applying the circle theorem earlier quoted, we can say that; m∠QDA = 2 × ∠QUA
m∠QDA = 2 × 111° = 222°
Which gives;
∠QOA = = 360° - 222° = 138°
∠QOA = ∠QOU + ∠UOA (by angle addition property)
Thus;
∠QOA = 138° = 88° + ∠UOA
∠UOA = 138° - 88° = 50°
Thus, the measure of Arc AU is;
Arc AU = ∠UOA = 50°
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Answer: b
Step-by-step explanation:
I can’t seem to find this, I’m having trouble with this question! It would be nice if someone could help! Thanks
Answer:
-456 I think but I could be wrong though
A group of 5 students took 15 days to finish a project. After 9 days, 3 students left the group. How many days did it take the students to finish the project in this case?
Using proportions, it is found that it took 15 days for the students to finish the project.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.
In this problem, we have that:
100% of the project is done by 5 students in 15 days.After the 3 students left, 2 students will have a time of x days to do 100 - (9/15) = 40% of the project.The compound rule of three is given as follows:
1 project - 5 students - 15 days
0.4 project - 2 students - x days
Increasing the number of students, the number of days is reduced, hence the measures are inverse proportional and the rule of three is given by:
[tex]\frac{15}{x} = \frac{2}[5} \times \frac{1}{0.4}[/tex]
[tex]\frac{15}{x} = \frac{2}{2}[/tex]
15/x = 1
x = 15 days.
It took 15 days for the students to finish the project.
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-5/208 + 4/7 + -3/4. Please answer my question as soon as possible. Thanks!
Answer:
[tex] - 0.2026[/tex]
Step-by-step explanation:
I hope it is the right answer
I don’t understand why I got my answer wrong
The correct function that has been represented on the graph is,
f(x) = { 2 if -1 < x ≤ 2 as the values of f(x) for the other two parts, -6 ≤ x ≤ -1 and 2 ∠ x ≤ 6 are (2x+17)/5 and (16-7x)/2 respectively.
This can be broken into three parts :
-6 ≤ x ≤ -1-1 ∠ x ≤ 2 2 ∠ x ≤ 6In the first fragment two clearly visible points are (-1,3) and (-6,1). Thus the straight line can be easily drawn with equation [tex]\frac{y-3}{x+1} = \frac{3-1}{-1+6}[/tex]y-3/x+1 = 2/5
5y -15 = 2x +2
2x - 5y = -17
The second part is quite clear, the equation is y =2 (straight line parallel to x - axis)The third part two clearly visible points are (2,1) and (4,-6). Thus the straight line can be easily drawn with equation [tex]\frac{y-1}{x-2} = \frac{1+6}{2-4}[/tex]y-1/x-2 = -7/2
2y -2 = -7x + 14
2y + 7x = 16
Thus function becomes
2x - 5y = -17 for -6 ≤ x ≤ -1 y =2 for -1 ∠ x ≤ 2 2y + 7x = 16 for 2 ∠ x≤ 6Learn more about Straight lines here :
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Kelsey has a list of possible functions. pick one of the g(x) functions below and then describe to kelsey the key features of g(x), including the end behavior, y-intercept, and zeros. g(x) = (x 2)(x − 1)(x − 2) g(x) = (x 3)(x 2)(x − 3) g(x) = (x 2)(x − 2)(x − 3) g(x) = (x 5)(x 2)(x − 5) g(x) = (x 7)(x 1)(x − 1)
Answer: (x) = x^3 − x^2 − 4x + 4End behavior- Falls to the left rises to the righty intercept-(0, 4)Zeros- (1,-2,2)g(x) = x^3 + 2x^2 − 9x − 18
Step-by-step explanation:
If AB = 55, and BC = 49, find the length of the radius to the nearest tenth. Assume BC is tangent to Circle A.
Answer:
25.0
Step-by-step explanation:
Notice that points A, B, and C form a right triangle. This allows us to use the Pythagorean theorem, a^2 + b^2 = c^2, to find the missing side. AB is the hypotenuse, so substitute 55 for c, and BC is the leg, so substitute 49 into either a or b in the formula.
a^2 + b^2 = c^2
49^2 + b^2 = 55^2
b^2 = 3025 - 2401
b^2 = 624
b = sqrt (624)
b = 24.9799919936
Graph and label each cell phone plan as accurately as possible. You need a ruler or straight edge
See attachment for the graph of cell phone plan 1: y= 7.5x and cell phone plan 2: y= 5.5x + 10.1
What are linear equations?Linear equations are equations that have constant average rates of change, slope or gradient
How to graph and label each cell phone plan?The cell phone plans are given as:
Cell phone plan 1: y= 7.5x
Cell phone plan 2: y= 5.5x + 10.1
To plot the graph of both plans, we make use of the following domain for both cell phone plans
Domain: x >= 0
Next, we set x = 0, 1, 2, 3, 4 and 5 for both plans
So, we have:
Cell phone plan 1
y= 7.5x
When x = 0, y = 7.5 * 0 = 0
When x = 1, y = 7.5 * 1 = 7.5
When x = 2, y = 7.5 * 2 = 15
When x = 3, y = 7.5 * 3 = 22.5
When x = 4, y = 7.5 * 4 = 30
When x = 5, y = 7.5 * 5 = 37.5
Cell phone plan 2
y= 5.5x + 10.1
When x = 0, y = 5.5*0 + 10.1 = 10.1
When x = 1, y = 5.5 * 1 + 10.1 = 15.6
When x = 2, y = 5.5 * 2 + 10.1 = 21.1
When x = 3, y = 5.5 * 3 + 10.1 = 26.6
When x = 4, y = 5.5 * 4 + 10.1 = 32.1
When x = 5, y = 5.5 * 5 + 10.1= 37.6
Next, we plot both graphs on the domain x >= 0
See attachment for the graph of cell phone plan 1: y= 7.5x and cell phone plan 2: y= 5.5x + 10.1
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If r varies jointly as s and t, and r = 8 when s = 6 and t = 4, find s when t = 16 and r = 24.
The value of s for the given conditions is 9/2.
What is a quadratic equation ?Any equation that can be rewritten in standard form as where x represents an unknown, a, b, and c represent known numbers, and where a 0 is true is a quadratic equation. As there is no ax2 term when a = 0, the equation is linear rather than quadratic.
According to the given information:r = k*s*t
k = constant of proportionality
r = 8
s = 6
t = 5
Putting the value in the equation:
8 = k x (6) x (4)
8 = 24k
k = 8 /24
k = 1/3
Now,
t = 16
r = 24
Putting the value in the equation:
r = k*s*t
24 = 1/3( x (s) x (16))
((24) x (3) )/ 16 = s
((3) x (3))/2 = s
s = 9/2
The value of s for the given conditions is 9/2.
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The growth of algae can be modelled by the function f(t) = 2¹.
Find the value of t such that f(t) = 128.
Answer:
t = 7
Step-by-step explanation:
You can use your knowledge of powers of 2, or you can use logarithms to find the value of t.
Powers of 22^1 = 2
2^2 = 4
2^4 = 16
128 = 16×4×2 = (2^4)(2^2)(2^1) = 2^(4+2+1) = 2^7
Now, the equation is ...
f(t) = 2^t = 2^7
Equating exponents, we have ...
t = 7
LogarithmsTaking the log of both sides of the equation ...
2^t = 128
we have ...
t×log(2) = log(128)
t = log(128)/log(2) = 7 . . . . . divide by the coefficient of t
The value of t is 7.
__
Additional comment
The relevant rule of exponents is ...
(a^b)(a^c) = a^(b+c)
The relevant rule of logarithms is ...
log(a^b) = b×log(a)
An Escalator Moves At The Rate Of 2 Feet Per Second. At What Rate Does The Escalator Move In Miles Per Hour?
A)0.02 mph
B)0.34 mph
C)0.68 mph
D)1.36 mph
Answer:
1.36mph
Step-by-step explanation:
The escalator is moving at 2ft/s, lets convert this to miles/second.
2ft/s = 0.000378788miles/s.
Now that we have the miles/second lets multiply this value by 3600 to get the miles/h, because there are 3600 seconds in an hour.
2ft/s=1.3636368miles/h
Or approximately 1.36miles/h.
On a zip-line course, you are harnessed to a
cable that travels through the treetops. You
start at platform A and zip to each of the other
platforms. How far do you travel from Platform
B to Platform C?
Using the distance between two points, it is found that you travel approximately 41 meters.
What is the distance between two points?Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:
[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
In this problem, we have that:
The coordinates of B are (-25,-25).The coordinates of C are (-15,15).Hence the distance is:
D = sqrt[(-15 - (-25))² + (15 - (-25))²] = sqrt(10² + 40²) = 41 meters.
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Given u = ⟨3, 2⟩, v = ⟨1, 5⟩, and the angle between the vectors is 45°, what is u · v?
We need to use a technique called dot multiplication. In this technique, we multiply the magnitude of two given vectors by the value of the angle between them.
In the question, the value of the angle between two vectors [tex]cos(45^0)[/tex] and the coordinates of the two vectors are given. Let's multiply them by the dot product to get the result.
Formula: [tex]u.v=|u||v|cos(a)[/tex]
[tex]u=3i+2j[/tex]
[tex]v=i+5j[/tex]
[tex]cos(a)=\frac{1}{\sqrt{2}}[/tex]
To find the magnitude of a vector, we square the coordinates, add them up and take the square root of the result.
[tex]Magnitude=\sqrt{x^2+y^2+z^2+...}[/tex]Result: [tex]u.v=|\sqrt{(3^2)+(2^2)}||\sqrt{(1^2)+(5^2)}|.\frac{1}{\sqrt{2}}=(13\sqrt{2})\frac{\sqrt{2}}{2} =13[/tex]