Physics question regarding kinetic friction. Please include explanation with answer. Thanks!

The resistance of the conductor is 0.07940 Ohms.

The wire's resistance is inversely related to its cross-sectional area; as the area drops, so does the resistance.

and it is formulated as:  

[tex]R=p\frac{l}{s}[/tex]

where,

p - resistivity of the conductor (0.0214-ohm mm²/m)

R - resistance

l- length of conductor (50 feet) (15.24 m)

s - the area of the wire

Thus the resistance can be calculated as

R = 0.07940 Ohms.

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The tangential speed of the tip of the bat is 2.2 m/sec.

Any item travelling in a circular direction has a tangential velocity, which is its linear speed. In one full round of a turntable, a point at the outside edge travels further than a point close to the center.

The formula for tangential velocity is given by-

[tex]V_{r}[/tex] = rω

r = radius of the circular path (m)

ω = angular speed

According to the question;

The angular speed of bat is  2. 0 rad/s.

The length of the bat is equal to radius of circular path = 1.1 m.

Angular speed = angular displacement/time

ω = Ф/t

2 = Ф/t

(∵ Ф = s/r); s is the actual distance travelled.

2 = s/(r×t)

s/t = r×2

    = 1.1×2

s/t = 2.2

v = 2.2 (∵ s/t = v)

Therefore, the tangential speed of the tip of the bat is v = 2.2 m/sec.

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The resulting velocity of marble B after the collision is 2.4 m/s.

The object with the faster velocity, and thus larger momentum, will impart more energy to the slower object during the collision than vice versa. Following the collision, the object with the lower beginning velocity will travel away from the other object with a higher speed and momentum.
Marble A's mass, marble B's mass, marble B's initial velocity, marble A's final velocity, marble B's final velocity, and marbles A and B's combined mass and initial velocity

Applying the mass-conservation principle
Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(0.08 kg)(0.5 m/s) + (0.05 kg)(0 m/s) = (0.08 kg)(-0.1 m/s) + (0.05 kg) v

0.04 kg m/s = -0.08 kg m/s + (0.05 kg) v

0.12 kg m/s = (0.05 kg) v

v = 2.4 m/s

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The temperature of boiling liquid will be 78°C.

To find the correct answer, we need to know about the upper and lower fixed points of the thermometer.

                           [tex]T=\frac{x-x_0}{x_{100}-x_0} *100[/tex]

where,

[tex]x=[/tex] length of liquid at T temperature = 19.5cm.

[tex]x_0=[/tex] length of liquid thread at ice point = 0°C

[tex]x_{100}=[/tex] length of liquid thread at steam point = 25 cm.

                            [tex]T=\frac{19.5-0}{25-0}*100\\ T=0.78*100=78^0C[/tex]

Thus, we can conclude that, the temperature of boiling liquid will be 78°C.

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It now radiates at a rate of 160 W.

The ratio of the energy emitted from a material's surface to the energy emitted from a blackbody, a perfect emitter with the same temperature, wavelength, and viewing conditions. It is a dimensionless number between 0 (for the ideal reflector) and 1. (for a perfect emitter).

Emissivity, which measures a material's capacity to emit infrared energy from its surface, is a crucial component of the ability to accurately measure temperature using either an infrared temperature sensor or a thermal imaging camera.

In addition to the material, a surface's emissivity also depends on the type of surface. In contrast to a roughened and oxidized metal surface, which will have a high emissivity, a clean and polished metal surface will have a low emissivity.

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The value and unit of rate constant k are 1.61[tex]M^{-1} S^{-1}[/tex]

The rate law of a reaction correlates the concentration of reactants with the rate of the reaction. The rate of a reaction is always proportional to the concentration of reactants. Hence, a proportionality constant (called as the rate constant) is always present in the rate law.

Rate = k [tex][A][B]^{2}[/tex]

Rate = k [tex][0.15][0.12]^{2}[/tex]

3.4×[tex]10^{-3}[/tex] = k 0.0021

k = 1.61[tex]M^{-1} S^{-1}[/tex]

Therefore, the value and unit of rate constant k are 1.61[tex]M^{-1} S^{-1}[/tex]

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The magnetic flux through a certain coil is given by phim = (1/50pi) cos( 100pi t) where the units are si. the coil has 100 turns. The magnitude of the induced EMF (in volts) when t = 1/200 s is 1 / 50 π

Magnetic flux is defined as the number of magnetic field lines passing through a given closed surface. It provides the measurement of the total magnetic field that passes through a given surface area.

An EMF is induced in the coil when a bar magnet is pushed in and out of it. EMF of opposite signs are produced by motion in opposite directions, and the EMF are also reversed by reversing poles.

EMF =   d Ф / d t

Given phi = Ф =  (1/50pi) cos100pi t  

hence ,

EMF = d ((1/50pi) cos 100pi t ) / d t

       = 1/50π * cos 100 pi

       substituting value of pi

       = 1 / 50 π * cos (100 * 180)

       = 1/ 50 π * cos ( 1800 )

EMF = 1 / 50 π

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The speed of the wave is 0.68 m/s.

Wave speed is the distance the wave travels in a given amount of time, such as the number of meters it travels per second.

V = Fλ

where;

This is the distance between two sequential troughs = 1.1 m

The frequency is number of complete oscillation per second.

f = n/t

where;

f = (9)/(14.5)

f = 0.62 Hz

V = 0.62 x 1.1

V = 0.68 m/s

Thus, the speed of the wave is 0.68 m/s.

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Answer:

Proportional

Explanation:

The conditions that must be met to produce SHM are;

-The restoring force must be proportional to the displacement and act opposite to the direction of motion with no drag forces or friction.

- The frequency of oscillation does not depend on the amplitude.

The torque developed by an industrial motor whose output is 175 kw at an angular speed of 4300 rev/min will be 389 Nm.

Given

Let Torque = т

P = т * ω

т = P/ ω

т = 17500 / 450 = 388.88 Nm (approx. 389 Nm)

Hence , the torque developed by an industrial motor whose output is 175 kw at an angular speed of 4300 rev/min will be 389 Nm.

In physics and mechanics, torque is the rotational equivalent of linear force. It is also referred to as the moment, moment of force, rotational force or turning effect, depending on the field of study. It represents the capability of a force to produce change in the rotational motion of the body.

We can define power as the rate of doing work, it is the work done in unit time. The SI unit of power is Watt (W) which is joules per second (J/s). Sometimes the power of motor vehicles and other machines is given in terms of Horsepower (hp), which is approximately equal to 745.7 watts.

Angular speed is the speed of the object in rotational motion.

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The rate of heat transfer from the entire plate is 710.8 kW

The properties of mercury at the film temperature of (75+25)/2= 50°C

k = 8.83632 W/m °C

v = 1.056 × [tex]10^-^7[/tex] m²/s

Pr = 0.0223

The local Nusselt number relation for liquid metals is given by

 [tex]N_u =\frac{h_sx}{k} = 0.565 9Re_x Pr)^\frac{1}{2}[/tex]

The average heat transfer coefficient for the entire surface can be determined from

[tex]h = \frac{1}{L} \int\limits^1_0 {h_x} \, dx[/tex]

Substituting the local Nusselt number relation into the above equation and performing the integration we obtain

[tex]N_u = 1.13 (Re_s Pr)^\frac{1}{2}[/tex]

The Reynolds number is

[tex]Re_L = \frac{VL}{v} = \frac{(0.01)(3m)}{1.056 * 10^-^7 m^2/s} = 0.028 * 10^7[/tex]

Using the relation for the Nusselt number, the average heat transfer coefficient and the heat transfer rate are determined to be

                       Q = 710.8 kW

Therefore, the rate of heat transfer from the entire plate is 710.8 kW

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Answer:

so the answer is 45

Explanation:

you 15x3=45

5x3=15

this is a  another way to do it add 15+15+15=45

15+15=30

then you add 15

then you get 45

The element Guideline of the security policy framework offers suggestions rather than mandatory actions.

To find the answer, we have to know more about the security policy framework.

Thus, we can conclude that, the element Guideline of the security policy framework offers suggestions rather than mandatory actions.

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Answer:

1. Vector, base

2. Vector, derived

3. Vector, ?

4. Scalar, derived

5. scalar, base

The capacitive reactance is reduced by a factor of 2.

We know the capacitive reactance is given as,

[tex]Xc = \frac{1}{2\pi fC}[/tex]

where,

[tex]Xc[/tex] = capacitive reactance

f = frequency

C = capacitance

It is given that frequency is doubled, i.e.,

f' = 2f

To find,

[tex]Xc'[/tex] =?

[tex]Xc' = \frac{1}{2\pi f'C}[/tex]

      [tex]= \frac{1}{2\pi 2f C}[/tex]

      [tex]= \frac{1}{2} (\frac{1}{2\pi fC} )[/tex]

[tex]Xc'[/tex]  [tex]= \frac{1}{2} Xc[/tex]

Therefore, the capacitive reactance is reduced by a factor of 2.

I understand the question you are looking for is this:

A capacitor is connected across an AC source. Suppose the frequency of the source is doubled. What happens to the capacitive reactant of the inductor?

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When a beam of light  that is, at first, in air and oriented perpendicular to the surface of a body of water be deflected as a result of transition into water--------It does not deflect , the light direction will not change.

What happens to light when it passes through air?

All materials have what is known as an index of refraction, which is linked to how fast light can travel through the material. As light passes through air and into another clear material (such as glass), it changes speed, and light is both reflected and refracted by the glass.

How does light travel through air and water?

When light travels from air into water, it slows down, causing it to change direction slightly. This change of direction is called refraction. When light enters a more dense substance (higher refractive index), it 'bends' more towards the normal line.

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Hg vacuum at 20 inches is the saturation pressure that corresponds to 32 degrees Fahrenheit of R-123.

To find the answer, we need to know more about the saturation pressure.

Thus, we can conclude that, Hg vacuum at 20 inches is the saturation pressure that corresponds to 32 degrees Fahrenheit of R-123.

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The total mass of the earth's atmosphere is 5×[tex]10^{8}[/tex] kg.

To calculate the total mass of the earth's atmosphere we use the expression

[tex]P=\frac{F}{A}[/tex]

or, [tex]F=P\times A[/tex]

or,[tex]M\times g=P\times A[/tex]

or,[tex]M=\frac{P\times 4\times \pi\times r^{2} }{g}[/tex]

Here, P= Atmospheric pressure at the surface = [tex]10^{5}[/tex] N/m2

F= Force at the earth surface.

A= Area of the earth.

r= Radius of the earth=6.4 × [tex]10^{6}[/tex] m

g= Acceleration due to gravity. = 9.8 m/s2 ≈ 10 m/s2

Let, M be the total mass of the earth's atmosphere.

Now, [tex]M=\frac{10^{5}\times4\times\pi\times(6.4\times10^{6} )^{2} }{10}[/tex]

M= 5×[tex]10^{8}[/tex] kg.

Thus from the above calculation we can show that, the total mass of the earth's atmosphere is 5×[tex]10^{8}[/tex] kg.

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The car’s momentum after 4.21s is 24617.4 kgm/s

Newton's second law state that, the rate of change of momentum, is directly proportional to the applied force.

Given that a 1200 kg car passes traffic light at a velocity of 10.2 m/s to the north and accelerates at a rate of 2.45 m/s^2. To calculate the car’s momentum after 4.21 s, Let us first list all the parameters involved.

From Newton's second law,

F = (mv - mu) / t

ma = (mv - mu) / t

Substitute all the parameters into the formula above.

1200 × 2.45 = ( mv - 1200 × 10.2 ) / 4.21

2940 = ( mv - 12240 ) / 4.21

Cross multiply

12377.4 = mv - 12240

Make mv the subject of the formula

mv = 12377.4 + 12240

mv = 24617.4 kgm/s

Therefore, the car’s momentum after 4.21s is 24617.4 kgm/s

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B. The sound wave will not be generated, so there will be no echoes received

An ultrasound is the process of sending high-frequency sound waves to make an image of an  internal structures of an object.

If the machine is broken and it is not sending out the sound wave, then it simply means that the sound wave will not be generated, so there will be no echoes received.

Thus, for an ultrasound tech that is trying to identify an object, but the machine is broken and is not sending out the sound wave.

The statement that best describes this situation is "The sound wave will not be generated, so there will be no echoes received".

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Answer:

B

Explanation:

Boyle's Law

As weight was added to the top of a syringe, the volume of the air trapped in the syringe decreased. The weight and the surface area of the plunger were used to calculate pressure. As more weight was added, the pressure increased. The volume decreased in response.

As the pressure on a gas increases, the volume of the gas decreases because the gas particles are forced closer together. Conversely, as the pressure on a gas decreases, the gas volume increases because the gas particles can now move farther apart

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Answer:yes

Explanation:

Sample Justification: As weight was added to the top of a syringe, the volume of the air trapped in the syringe decreased. The weight and the surface area of the plunger were used to calculate pressure. As more weight was added, the pressure increased. The volume decreased in response.

then

yes and yes

The  bowling ball reaches the bottom first.

In the game of bowling, a bowling ball is a tough, spherical ball used to knock down bowling pins. The customary holes in ten-pin bowling and American nine-pin bowling balls are for the thumb and two other fingers. Five-pin bowling, candlepin bowling, duckpin bowling, and European nine-pin bowling all use balls with no holes that can fit comfortably in the palm of the hand. Ball motion and how it affects scoring are influenced by a complicated interplay of many different factors. The delivery of the bowler, the construction of the bowling ball, and the state of the lane can all be considered as contributing variables.

In a similar rolling race (no slipping), the two objects are a bowling ball and a circular hoop of unknown masses and radii. which reaches the bottom first?

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Answer:

C, it doesnt accelerate

Explanation:

F=ma

F = 100 east + 100 west

F = 100 east + (-100 east)

F = 0

0 = ma

in order to isolate acceleration, we would be dividing 0 by mass, which would equal 0

The force stood needed to stretch the spring by the initial 15cm exists  1420 N.

The motion between two positions back and forth, or swinging back and forth like a pendulum exists comprehended as oscillation.

A condition where competing forces or activities exist in balance exists named equilibrium.

Tensional force exists as the force exerted by a stretched item.

It could be a rope, string, elastic band, or wire that exists being extended.

The object's tensional force exists used to the object stretching it.

The stretched object exists subject to tensile force.

Force stood needed to stretch the spring by the initial 15cm exists 1420 N.

Let, m = 15, P = 0.25, x = 0.15

F = -K x for spring

where, F is the force

K be the constant

ω [tex]= (K/m)^{1/2[/tex]

where, ω be the angular frequency

m b the mass of the block

[tex]$\omega^2 = K / m[/tex]

[tex]K = m \omega^2[/tex] [tex]= m (2 \pi f)^2[/tex]  [tex]= m 4 \pi ^2 / P^2[/tex]

K = 4[tex]\pi ^2[/tex] m / [tex]P^2[/tex]

[tex]F = K x = x * 4 \pi ^2 m / P^2[/tex]

[tex]F = 0.15 * 4 * \pi ^2 * 15 / 0.25^2[/tex]

F = 1420 N

The force stood needed to stretch the spring by the initial 15cm exists  1420 N.

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Ten seconds after starting from rest, a car is moving at 60 m/s. what is the cars acceleration? 6 m/s^2

Average acceleration= (final velocity-initial velocity)/time

The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. It is a vector quantity to accelerate (in that they have magnitude and direction). The direction of the net force acting on an object determines the direction of its acceleration. According to Newton's Second Law, an object's acceleration is the result of two factors working together: the object's mass, which varies depending on the materials it is made of, and the net balance of all external forces acting on it. The magnitude of an object's acceleration is inversely proportional to the object's mass.

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The intensity of electric field E midway between these two charges is 2.52*10^7N/C.

To find the answer, we have to know more about the electric field.

                      [tex]E=\frac{kQ}{r^2}[/tex]

where, k is the constant equal to 8.99*10^9.

                [tex]E_1=\frac{8.99*10^9*20*10^{-6}}{10*10^{-2}} =1.79*10^7N/C[/tex]

                 [tex]E_2=\frac{8.99*10^9*8*10^{-6}}{(10*10^{-2})^2} =7.19*10^6N/C[/tex]

                [tex]E=1.79*10^7+7.19*10^6=2.52*10^7N/C[/tex]

Thus, we can conclude that, the intensity of electric field e midway between these two charges is 2.52*10^7N/C.

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Electric Current:

Electric current is the flow of charge through a given circuit per unit time. Electric current is one of the components needed to calculate the electric power that a device needs to operate and do work. Electric current is measured in amperes (A), which is equal to:

            1A = 1 C/ s

Recall that the coulomb (C) is the unit for charge while the second (s) is the unit for time

Given: I = 3.5

A is the current

Δt =30 s is the time interval

                     A =ΔQ/ΔT

Net charge = 100C

Electricity is produced when an electric current runs through a circuit.

How does electric current work?

A current of electricity is a steady flow of electrons. When electrons move from one place to another, round a circuit, they carry electrical energy from place to place like marching ants carrying leaves. Instead of carrying leaves, electrons carry a tiny amount of electric charge.

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The separation between the two slits, d is related to the wavelength, and angle using the formula below. Hence, the value of d is 1.22 x 10⁻⁶ m.

For ease of calculations we take 29.8° = 30°

Using the relation :

[tex]\frac{m * λ }{sin\theta}[/tex]

where :

d = distance between the slits

θ = 30°

λ = wavelength of light = 617 nm = 6.17 x 10⁻⁷ m

m = 1

Substituting the values into the equation :

d = 1 x 6.17 x 10⁻⁷ / 0.5 = 0.00000122 = 1.22 x 10⁻⁶ m

Therefore, the seperation between the two slits is 1.22 x 10⁻⁶ m.

The double-slit experiment is a demonstration that light and matter can display characteristics of both classically defined waves and particles; moreover, it displays the fundamentally probabilistic nature of quantum mechanical phenomena.

This type of experiment was first performed, using light, by Thomas Young in 1802, as a demonstration of the wave behavior of light. At that time it was thought that light consisted of either waves or particles.

With the beginning of modern physics, about a hundred years later, it was realized that light could in fact show behavior characteristic of both waves and particles. Young's experiment with light was part of classical physics long before the development of quantum mechanics and the concept of wave–particle duality.

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When the current in the micro-robot’s circuit increases and the resistance of the circuit remains constant, the voltage of the circuit: increases

With manual control, microrobots have demonstrated tremendous potential for carrying out microscale activities as drug delivery, cell manipulation, micro construction, and biosensing. Magnetotactic bacteria were used to illustrate the use of targeted delivery in the presence of DC magnetic field gradients. Microrobots for magnetic field-based delivery of target objects like cells and chemicals have also been investigated by other research teams. Micro-electro-mechanical systems have been used to create microgrippers for microrobots, a technique that can be used to increase the capability of microrobots in addition to targeted distribution. The kinematic models of produced microrobots have been researched in order to obtain motion control. Microrobots that are both biological and non-biological have been guided using autonomous motion planning. These devices utilize visual systems for feedback control.

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Number of rulings per centimeter for the grating 4.5 x 10^3 grooves/cm

Given:

wavelength of light = 635.00 nm

angle of first order = 38.0∘

To Find:

Length of slits marked on grafting

Solution: Grafting and budding are horticultural techniques used to join parts from two or more plants so that they appear to grow as a single plant

We use the grating equation dsinθ = mλ

d = mλ/sinθ

d = 1 x 635x10^-7 m/sin 38.0∘

d = 2189.6 x 10^-7 m

Thus the grating gauge is

1/d = 0.00045 x 10^7 = 4.5 x 10^3 grooves/cm

So, number of rulings per centimeter for the grating 4.5 x 10^3 grooves/cm

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