Answer:
9
Step-by-step explanation:
We can tackle the individual parts and combine
1/5 of the sum of 9 and 6 means 1/5 * (9 + 6)
The quotient of 18 divided by the sum of 2 and 4 is 18 / (2 + 4)
Combing everything gives us (1/5 * (9 +6)) * (18 / (2 + 4)
(1/5 * 15) * 18/6
3 * 3 = 9
20 pts !!! Please give a detailed answer thanks :)
How do you construct the inscribed and circumscribed circles of a triangle?
Answer:
inscribed: centered at the intersection of angle bisectors, radius = distance to one sidecircumscribed: centered at the intersection of perpendicular bisectors, radius = distance to one vertexStep-by-step explanation:
The steps to constructing either circle start with finding the relevant center and radius. The required construction techniques are ...
bisect an angleperpendicular to a line through an external pointperpendicular bisectorInscribed circleSummaryThe incenter (center of the inscribed circle) is located at the coincidence of the angle bisectors. The radius is the perpendicular distance to any side, so will lie on the line through the incenter and perpendicular to one side.
Angle bisectorsReference the first attachment. We have elected to bisect the largest two angles of triangle ABC. In each case, we used these steps:
Centered at a vertex (B for example), draw an arc through the two sides of that angle (arc HI for example).Centered at the points of intersection with the sides, draw two intersecting arcs with the same radius (arcs HQ and IQ).Draw the angle bisector through this point of intersection and the original vertex (green line BQ).After this process is repeated for another angle, the point of intersection of the two angle bisectors is the incenter (R).
RadiusFinding the radius requires finding the perpendicular distance to one side of the triangle. That is done by constructing a perpendicular to the side through the incenter.
Centered at the incenter (R), draw an arc that intersects one side in two places (arc UV).Centered at the points of intersection with the side, draw two intersecting arcs with the same radius (arcs UZ and VZ. Z is the unlabeled point at upper right).Draw perpendicular RZ intersecting the midpoint of UV at X.IncircleThe inscribed circle is centered at R and has radius RX.
__
Circumscribed CircleSummaryThe circumcenter (center of the circumscribed circle) is located at the coincidence of the bisectors of the sides of the triangle. The radius is the distance from the circumcenter to any vertex.
Perpendicular bisectorReference the second attachment. We have elected to bisect the longest and shortest of the triangle's sides. The purpose of this choice is to make the perpendicular bisectors intersect at a large angle, so the point is as accurately located as possible.
Choose one side of the triangle and set the radius to more than half its length.Using that radius, draw intersecting arcs using each end of the side as a center (side AB and arcs FG, for example).Draw the perpendicular bisector through the points where the arcs intersect (line FG).Repeat this process for another side (BC to create bisector JK). The intersection of the two bisectors (L) is the circumcenter.
CircumcircleThe circumscribed circle is centered at L and has radius LA.
__
Additional comments
In general, arcs that are required to intersect each other will be drawn with the same radius. An arc that is required to intersect two lines, or one line in two places, may have any convenient radius.
As with any geometric construction, the tools required are a marking tool, a compass, and a straightedge. Usually, the preferred marking tool is a sharp pencil.
If the triangle is obtuse, the circumcenter will be outside the triangle (adjacent to the long side). If the triangle is a right triangle, the circumcenter is the midpoint of the hypotenuse.
Determine whether the given correlation coefficient is statistically significant at the specified level of significance and sample size. r=−0. 599, α=0. 01, n=11
Yes, the correlation coefficient is statistically significance
The precise metric used in a correlation analysis to quantify the strength of the linear relationship between two variables is the correlation coefficient. In a correlation report, the r stands for the coefficient.
Given,
Sample size, n = 11
Where ρ is the population correlation.
Then the number of degrees of freedom is, df = n-2 = 11-2 = 9
The corresponding critical correlation value re for a significance level of a 0.01, for a two-tailed test is た= 0.254
Here,
The null hypothesis, = ρ - 0 is rejected
Suppose lr> re 0.254
Because on the sample correlation provided, we know that lrl = 0.599>=0.254.
Here, it is clear that the null hypothesis is rejected.
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Find the missing probability.
The value of the missing probability is:
P(A) = 1/5
So the correct option is D.
How to find the missing probability?First, we know that:
P(A∩B) = probability that events A and B are true = 3/100
And we also know that:
P(B|A) = probability that event B is true given that event A is true = 3/20
Here we have the rule:
P(A∩B) = P(B|A)*P(A)
Replacing the first two:
3/100 = (3/20)*P(A)
Solving for P(A), we get:
(3/100)*(20/3) = 1/5 = P(A).
So we conclude that the correct option for the missing probability is the one in option D.
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Using the graph of the function g(x) = log3 (x – 4), what are the x-intercept and asymptote of g(x)?
The x-intercept is when y=0, but since [tex]\log_{3}(x-4) \neq 0 \text{ } \forall x[/tex], there is no x-intercept.
The asymptote is when the argument equals 0, which is at x=4.
. Factorise the following expression fully
(a+1)²-4b²
The factoring the equation (a + 1)² - 4b² we get (a+1+2b)(a+1-2b).
What is the factoring function of (a + 1)² - 4 b²?Given: (a + 1)² - 4b²
Apply Perfect Square Formula, and we get
(a + b)² = a² + 2 a b + b²
(a + 1)² = a² + 2a1+1²
= a² + 2a1 + 1² - 4 b²
simplifying the equation, we get
a² + 2a1 + 1² = a² + 2a + 1
= a² + 2a + 1 - 4b²
Factor, a² + 2a + 1 = (a + 1)²
= (a + 1)² - 4 b²
Simplify 4 b² = (2 b)²
= (a + 1)² - (2b)²
Apply the Difference of Two Squares Formula, and we get
x² - y² = (x + y)(x - y)
(a + 1)² - (2b)² = ((a + 1) + 2b)((a + 1) - 2 b)
simplifying the equation, we get
= ((a + 1) + 2b)(a + 1) - 2 b)
= (a + 1 + 2b)(a + 1 - 2b)
Therefore, the correct answer is (a+1+2b)(a+1-2b).
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Instructions: Find the surface area of each figure. Round your answers to the nearest tenth, if necessary.
The surface area of the shape is 117.8 km²
Surface area of a coneFrom the question, we are to determine the surface area of the figure
The given figure is a cone.
Total surface area of a cone = Area of circular part + Curved surface area
Total surface area of a cone = πr² + πrl = πr(r + l)
Where r is the radius
and l is the slant height
From the given information,
r = 3 km
l = 9.5 km
The total surface area of the cone = π×3(3+9.5)
The total surface area of the cone = 3π(12.5)
The total surface area of the cone = 117.8 km²
Hence, the surface area of the shape is 117.8 km²
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When the points in a scatter plot cluster closely around the regression line, the correlation can be said to be?
The points in a scatter plot cluster closely around the regression line, the correlation can be said to be the proportion of variance in Y that is determined or explained by X.
It is critical to understand that a correlation coefficient of zero indicates that there is no linear courting, but there can also nonetheless be a strong relationship among the 2 variables.
If one point of a scatter diagram is farther from the regression line than a few other factor, then the scatter diagram has as a minimum one outlier. If two or extra points are the identical farthest distance from the regression line not a commonplace prevalence), then every of those points is an outlier.
When the y variable has a tendency to increase because the x variable increases, we say there may be a high-quality correlation between the variables. when the y variable has a tendency to lower as the x variable increases, we are saying there's a bad correlation between the variables.
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two trains are moving towards each other on the same railroad track. From this track there's an offshot peice of railroad- the length of whice is shorter than the length of the train but longer than the length of one train car. How can the trains pass eash other?
If the length of whice is shorter than the length of the train but longer than the length of one train car then the train can pass one car at a time.
Given that two trains are moving towards each other on the same railroad track. From this track there's an offshot peice of railroad- the length of whice is shorter than the length of the train but longer than the length of one train car.
We are required to find how the trains pass each other.
Two cases are there:
For each car in the shorter train
Train A leaves one of its cars on the offshot.Both trains move until train B car move the car from the offshoot the portion of track away from train A.Train B moves to allow the cycle to repeat.We assume that cars can be decoupled at any point in the train,so that any required order of cars can be preserved.We further assume that train can move any one of the A's car in addition to all of them.
The total number of cars lengths that must pass the off shoot is the product of the number of cars in both the trains.So,it does not seems to matter which train makes use of the offshoot.
Hence if the length of whice is shorter than the length of the train but longer than the length of one train car then the train can pass one car at a time.
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If z = 1+ i√3, what is z^5?
Answer:
.....................................
simplify -3/2 * 9/6
A. -4
B. -1
C. 4
D. 1
Answer:
-2.25
Step-by-step explanation:
John is 12 meters away from a cliff and looks up to the top of the cliff at an angle of 45. His eyes are 2 meters above the ground. How tall is the cliff?
Answer:
14m
Step-by-step explanation:
Please refer to the attached figure
B is the position where John is standing, His eyes are at point A, 2 meters from the ground
D is the base of the cliff and E is the top of the cliff
∠EAC is the angle at which John looks up to the cliff and is given as 45°
BD is the distance from the cliff given as 12m
So AC is also 12m
∠ACE is 90°
Therefore ∠AEC is 180-(45+90) = 45° since AEC forms a triangle and sum of angles in a triangle = 180°
In the ΔAEC, by the law of sines
12/sin(45) = EC/sin(45) . This means EC = 12 since the denominators cancel out
Since point C is 2 meters above ground(the base of the cliff) add 2 and we get the height of the cliff as 12+2 = 14m
Volume=
Help asap!! Pleaseee thanks so much
The volume of the right prism is 1280 cm³
Volume of a right prism
The volume of a right prism is calculated using the formula
Volume = length × width × height
Where
height = 20cm
width = 8cm
length = 8cm
Substitute into the formula
Volume = 20 × 8 × 8
Volume = 1280 cm³
Thus, the volume of the right prism is 1280 cm³
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Find the total surface area. A. 78 B. 98 C. 69 D. 92
The total surface area of the figure is 92 m².
How to find the surface area of a figure?The surface area of a figure is the sum of the whole sides of the figure.
Therefore,
surface area = 4 × 4 + 4 × 4 + 6 × 4 + 2 × 4 + 1 / 2 (2 + 6)3.5 + 1 / 2 (2 + 6)3.5
Hence,
surface area = 16 + 16 + 24 + 8 + 14 + 14
Therefore,
surface area = 32 + 24 + 8 + 28
surface area = 56 + 8 + 28
surface area = 92 m²
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Ethan bought 3 pints of raspberries for $5 per pint and x pints of blueberries for $3 per pint. The average
15 + 3x
3+x
15+ 3x dollars per pint. If the equation y =
=
is graphed in the
3+x
cost of all the berries he bought was
xy-plane, what quantity will be represented by the y-intercept of the graph?
O The total cost, in dollars, of all the raspberries Ethan bought
O The average cost, in dollars per pint, of all the raspberries Ethan bought
O The total cost, in dollars, of all the blueberries Ethan bought
O The average cost, in dollars per pint, of all the blueberries Ethan bought
The y-intercept represents the average cost, in dollars per pint, of all the raspberries Ethan bought. Therefore, option B is the correct answer.
Given that, Ethan bought 3 pints of raspberries for $5 per pint and x pints of blueberries for $3 per pint.
The average is (15 + 3x)/(3+x) per pint.
We need to find what quantity will be represented by the y-intercept of the graph.
How to find the y-intercept of the graph?Since the y-intercept always has a corresponding x-value of 0, replace x with 0 in the equation and solve for y. On a graph, the y-intercept can be found by finding the value of y when x=0. This is the point at which the graph crosses through the y-axis.
Now, the graph of y=(15 + 3x)/(3+x)is given below.
To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.
x-intercept(s): (−5,0)
y-intercept(s): (0,5)
So, the y-intercept represents the average cost, in dollars per pint, of all the raspberries Ethan bought.
Therefore, option B is the correct answer.
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possible roots math related olds helppp
In accordance with the Ferrari's method, all the roots of the quartic polynomial are complex numbers.
What kind of roots does a quartic polynomial have?
By fundamental theorem of algebra quartic polynomials have four roots. Based on characteristics of the quadratic formula, use for the solution of quadratic polynomials, there are three possible sets of roots:
All roots are real numbers.Two roots are real numbers and two roots are complex numbers.All roots are complex numbers.There are several methods to solve quartic polynomials. In this case, we decide to use the Ferrari's method to determine all roots of the polynomial:
[tex]x_{1} = \frac{1 + i \sqrt{3}}{2}[/tex], [tex]x_{2} = \frac{1 - i\,\sqrt{3}}{2}[/tex], [tex]x_{3} = - \frac{5}{3} + i\,0.471[/tex], [tex]x_{4} = -\frac{5}{3} - i\,0.471[/tex]
All the roots of the quartic polynomial are complex numbers.
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The speed, s, of the current in a certain whirlpool is modeled by x = StartFraction 300 Over d EndFraction, where d is the distance from the center of the whirlpool. Which statement is true?
The real statement is that the closer you get to the center of the vortex, the closer the current speed approaches infinity. option C is correct.
Given the speed s of the flow in a given vortex is modeled by x=300/d, where d is the distance to the center of the vortex.
speed is defined as the rate of change of an object's position in any direction. Speed is measured as the ratio of distance traveled to time traveled.
As d approaches 0, you are approaching the center of the vortex.
[tex]\begin{aligned}S&=\lim_{d\rightarrow 0}\frac{300}{d}\\ &=\frac{300}{0}\\ &=\infty\end[/tex]
Thus, if the flow in a given vortex is modeled by x = 300/d, as one approaches the center of the vortex, the speed of the flow tends to infinity.
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Answer: C- As you move closer to the center of the whirlpool, the speed of the current approaches infinity.
Express 16% percent as a fraction in the simplest form
Your friends and you notice a classmate who always has brand new clothes, shoes, and electronics. What would you need to know in order to tell if this classmate’s family is actually wealthy?
To know if the classmate’s family is actually wealthy, one will need to know their assets and their debt.
What is an asset?In financial accounting, an asset means a resource that is owned or controlled by a business or an economic entity. An asset is anything that can be used to produce positive economic value.
Assets represent the value of ownership that can be converted into cash and the examples of personal financial assets include cash and bank accounts, real estate, personal property like furniture and vehicles, and investments such as stocks, mutual funds, and retirement plans.
In this case, through the assets, one will be able to know that they're wealthy. The debt is an obligation that requires one party, the debtor, to pay money or other agreed-upon value to another party, the creditor. This is the money that they owe.
The asset should more than the debt.
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Graph paper recommended***
Quadrilateral MATH includes the points M(2,-4) and A(5,-2).
Part A: Find coordinates for T and H such that quadrilateral MATH is a rectangle.
Part B: Prove that the resulting quadrilateral is a rectangle.
18
a) The coordinates for T and H such that quadrillateral MATH is a rectangle are T(x, y) = (2, - 2) and H(x, y) = (5, - 4).
b) The quadrilateral MATH is a rectangle.
How to create and analyze quadrillateral on a Cartesian plane
Quadrilaterals are figures with four sides and whose internal angles sums a total of 360 degrees. A quadrilateral is a rectangle when each pair of opposite sides are parallel and have the same length to each others, each of the four angles are right angles and each pair of perpendicular sides.
a) Vectorially speaking, we can construct a rectangle by using the following definitions:
M(x, y) = (a, b), A(x, y) = (c, d), T(x, y) = (a, d), H(x, y) = (c, b)
If we know that a = 2, b = - 4, c = 5, d = - 2, then the points T and H are described below:
T(x, y) = (2, - 2), H(x, y) = (5, - 4)
The coordinates for T and H such that quadrillateral MATH is a rectangle are T(x, y) = (2, - 2) and H(x, y) = (5, - 4).
b) To prove that quadrilateral MATH, we need to prove that:
MT = HA
(2, - 2) - (2, - 4) = (5, - 2) - (5, - 4)
(0, 2) = (0, 2)
TA = MH
(5, - 2) - (2, - 2) = (5, - 4) - (2, - 4)
(3, 0) = (3, 0)
MT • TA = 0
(0, 2) • (3, 0) = 0 · 3 + 2 · 0 = 0
MH • HA = 0
(3, 0) • (0, 2) = 3 · 0 + 0 · 2 = 0
Therefore, the quadrilateral MATH is a rectangle.
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‼️‼️‼️‼️HELP‼️‼️‼️‼️‼️‼️‼️
Michael took a drive down to the beach and drove at a pace of 45mph on the way there. The trip took him 3 hours. He drives the exact same route on the way back, but takes it slow so he can enjoy the sunset. If Henry's return trip took him 4 hours, how fast was he driving on his return?
Michael took the return trip at a velocity 33.75 miles per hour.
How fast did Michael drive in his return trip?
Let suppose that Michael drove in straight line road and at constant velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
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Quick algebra 1 question for 10 points!
Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!
Answer:
○ 1 hour 41 minutes or more
Step-by-step explanation:
We can make two equations that represent the total amount each plumber charges.
If [tex]x[/tex] represents the number of hours they work, then:
•Total charged by Plumber A = [tex]35 + 15x[/tex]
• Total charged by Plumber B = [tex]40+12x[/tex]
Now, if Plumber A is more expensive than Plumber B, then:
Total charged by Plumber A > Total charged by Plumber B
∴ [tex]35 + 15x[/tex] > [tex]40+12x[/tex]
Now all we have to do is solve for [tex]x[/tex]:
[tex]35 + 15x[/tex] > [tex]40+12x[/tex]
⇒ [tex]35 + 15x -12x > 40[/tex]
⇒ [tex]35 + 3x > 40[/tex]
⇒ [tex]3x > 5[/tex]
⇒ [tex]x > \bf \frac{5}{3} \space\ \mathrm{h}[/tex]
[tex]\frac{5}{3} \space\ \mathrm h[/tex] is equivalent to [tex]\frac{5}{3} \times 60 \space\ \mathrm {min}[/tex] = 100 minutes, which is the same as 1h 40min.
This means if Plumber A works more than 1h 40min, they become more expensive than Plumber B.
More than 1h 40min is equivalent to '1 hour 41 minutes or more', therefore the first option is correct.
Question 7(Multiple Choice)
(05.02 MC)
Which expression is equivalent to 3 log2 x - 4 log2 y + 2 log2 z?
Answer:
C.) [tex]log_2(\frac{x^3z^2}{y^4})[/tex]
Step-by-step explanation:
To find the answer, you need to simplify the expression. To do so, you must combine the logs. You can combine the logs because they all have the same subscript (2).
[tex]3 log_2x - 4log_2y + 2log_2z[/tex] <----- Given expression
[tex]log_2x^3-log_2y^4+log_2z^2[/tex] <----- Raise coefficients to variables
[tex]log_2x^3+log_2z^2-log_2y^4[/tex] <----- Rearrange
[tex]log_2(x^3z^2)-log_2y^4[/tex] <----- Multiply added logs
[tex]log_2(\frac{x^3z^2}{y^4})[/tex] <------ Divide subtracted log
Express the multiplication of a logarithm number of an expression as the logarithm of the power of the expression.
㏒₂ x³ - ㏒₂ y⁴ + ㏒₂ z²Take the product of the arguments
[tex]\red{\boxed{\boldsymbol{\sf{\blue{Answer \ \ \longmapsto \ \ Log_{2} \frac{x^{3}z^{2} }{y^{4} } } }}}}[/tex]
Therefore, the correct option is alternative "C".
Rhombus A B C D is shown. All sides are congruent. Lines are drawn from point A to point C and from point D to point B and intersect at point E at the center.
The area of rhombus ABCD is 120 square units.
AE = 12 and BD = x – 2. What is the value of x and the length of segment BD?
x =
BD = units
Answer:
x = 22
BD = 20 units
Step-by-step explanation:
The formula for the area of a rhombus can be used with the given values to write an equation that can be solved for x and for BD.
Area of a rhombusThe formula is ..
A = 1/2(d1)(d2) . . . . where d1 and d2 are the lengths of the diagonals.
Using the given values, we have ...
120 = 1/2(12)(x-2)
SolutionDividing by 6, we find ...
20 = x -2 = BD
22 = x . . . . . . . . add 2
The value of x is 22.
The length of BD is 20.
Answer:
x=12
BD=10
Step-by-step explanation:
Tanya is 12 years older than Leah. Three years ago, Tanya was five times as old as Leah.
What is the age of Tanya and Leah now?
Answer:
tanya 22
leah12
Step-by-step explanation:
i hope it
help ...
Box a has a volume of 32 cubic meters. box b is similar to box a. to create box b, box a's dimensions were tripled. what is the volume of box b?
The volume of box B is (A) 864 cubic meters.
What is volume?The amount of three-dimensional space enclosed by a closed surface is expressed as a scalar quantity. For example, the space occupied or contained by a substance or 3D object.Volume is frequently mathematically quantified using the SI-derived unit, the cubic meter.To find the volume of box B:
We have been assigned a volume of 32 cubic meters. The cubic root of 32 yields the box's dimensions, which are 3.1748 x 3.1748 x 3.1748 meters. Meters when the dimensions are tripled: 9.5244 x 9.5244 x 9.5244= 864 cubic meters.
Therefore, the volume of box B is (A) 864 cubic meters.
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The complete question is given below:
Box A has a volume of 32 cubic meters. Box B is similar to box A. To create box B, box A's dimensions were tripled. What is the volume of box B?
a. 864 m3.
b. 288 m3.
c. 96 m3.
d. 32 m3
What is the exact value of cos(c d), given sine c = startfraction 24 over 25 endfraction for c in quadrant ii and cosine d = negative three-fourths for d in quadrant iii?
The exact value of cos(c+d) is (D) [tex]cos(c+d) = \frac{21+24\sqrt{7} }{100}[/tex].
What are trigonometric functions?Trigonometric functions are real functions in mathematics that connect an angle of a right-angled triangle to ratios of two side lengths. They are widely utilized in all geosciences, including navigation, solid mechanics, celestial mechanics, geodesy, and many more.To find the exact value of cos(c+d):
In the second quadrant:
c = 180° -arcsin(24/25) ≈ 106.26°In the third quadrant:
d = 360° -arccos(-3/4) ≈ 221.41°Then cos(c+d) = cos(327.67°) ≈ 0.84498
This is a positive irrational number, greater than 21/100, so the only reasonable choice is the last one:
[tex]\frac{21+24\sqrt{7} }{100}[/tex] ≈ [tex]0.84498[/tex]
To prove: Perhaps you want to work this out using the trignometric identities.
cos(c) = -√(1 -sin(c)²) = -7/25
sin(d) = -√(1 -cos(d)²) = -(√7)/4
Then the desired cosine is: cos(c+d) = cos(c)cos(d) -sin(c)sin(d)
cos(c+d) = (-7/25)(-3/4) -(24/25)(-√7/4)
Therefore, the exact value of cos(c+d) is (D) [tex]cos(c+d) = \frac{21+24\sqrt{7} }{100}[/tex].
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The complete question is given below:
What is the exact value of cos(c+d), given sine c = start fraction 24 over 25 end fraction for c in quadrant ii and cosine d = negative three-fourths for d in quadrant iii?
(A) Negative StartFraction 47 Over 100 EndFraction
(B) Negative 1 and StartFraction 3 Over 100 EndFraction
(C) StartFraction 21 minus 24 StartRoot 7 EndRoot Over 100 EndFraction
(D) StartFraction 21 + 24 StartRoot 7 EndRoot Over 100 EndFraction
The law of Cosines Is......
Answer: [tex]\Large\boxed{C.~21}[/tex]
Step-by-step explanation:
The goal of the question
Find the value of 2abcosC
Given information
a = 4
b = 3
c = 2
Given formula (Law of Cosine)
[tex]c^2=a^2+b^2-2abcosC[/tex]
Substitute values into the formula (Leave 2abcosC as it is)
[tex](2)^2=(4)^2+(3)^2-2abcosC[/tex]
Simplify the exponents
[tex]4=16+9-2abcosC[/tex]
Simplify by addition
[tex]4=25-2abcosC[/tex]
Add 2abcosC on both sides
[tex]4+2abcosC=25-2abcosC+2abcosC[/tex]
[tex]4+2abcosC=25[/tex]
Subtract 4 on both sides
[tex]4 + 2abcosC-4=25-4[/tex]
[tex]\Large\boxed{2abcosC=21}[/tex]
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Answer:
C
Step-by-step explanation:
a² + b² - 2abcosC = c² ( subtract a² + b² from both sides )
- 2abcosC = c² - a² - b² ( multiply through by - 1 )
2abcosC = a² + b² - c²
a, b, c are the sides opposite vertices A, B, C
here a = 4 , b = 3 , c = 2 , then
a² + b² - c²
= 4² + 3² - 2²
= 16 + 9 - 4
= 25 - 4
= 21
Which expression is equivalent to RootIndex 4 StartRoot StartFraction 24 x Superscript 6 Baseline y Over 128 x Superscript 4 Baseline y Superscript 5 Baseline EndFraction EndRoot? Assume x not-equals 0 and y
The expression [tex]\sqrt[4]{\frac{24x^6y}{128x^4y^5} }[/tex] is equivalent to the expression [tex]\frac{\sqrt[4]{3x^2}}{2y}[/tex]
What is an equation?An equation is an expression that shows the relationship between two numbers and variables.
An independent variable is a variable that does not depend on any other variable for its value whereas a dependent variable is a variable that depend on any other variable for its value.
Given the expression:
[tex]\sqrt[4]{\frac{24x^6y}{128x^4y^5} }\\ \\Simplifying:\\\\=\frac{\sqrt[4]{3x^2}}{2y}[/tex]
The expression [tex]\sqrt[4]{\frac{24x^6y}{128x^4y^5} }[/tex] is equivalent to the expression [tex]\frac{\sqrt[4]{3x^2}}{2y}[/tex]
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Answer:
The answer is D
Step-by-step explanation:
Find the distance between the points (-3, -2) and (-1, -2).
2
Answer:
the answer to your question is 2
Step-by-step explanation:
using distance formula
√(-1-(-3))^2+(-2-(-2))^2
Answer:
2
Step-by-step explanation:
since the y- coordinates are equal, both - 2
then the distance between the points is the absolute value of the difference of the x- coordinates, that is
d = | - 1 - (- 3) | = | - 1 + 3 | = | 2 | = 2
or
d = | - 3 - (- 1) | = | - 3 + 1 | = | - 2 | = 2
nts out of
10
Flag question
Instructions: Find the surface area of each figure. Round your answers to the nearest tenth, if necessary.
Surface Area:
Check
9 km.
7 km.
km²
6 km.
8 km.
11 km.
PLEASE HELP MEEEE
EXPLAIN
The Surface area of the triangular prism is: 318 km³.
What is a Triangular Prism?A triangular prism is a solid that has two triangular bases and three rectangular faces.
What is the Surface Area of a Triangular Prism?The surface area of a triangular prism is the sum of the areas of its two triangular bases and three rectangular faces.
The formula for the surface area of a triangular prism = (S1 +S2 + S3)L + bh, where:
Perimeter of the base = S1 + S2 + S3
Length of the prism = L
2 × Base Area = bh
Given the following:
s1 + s2 + s3 = 7 + 9 + 8 = 24 km
L = 11 km
bh = (9)(6) = 54 km²
Plug in the values
Surface area of the triangular prism = (24)11 + 54
Surface area of the triangular prism = 264 + 54
Surface area of the triangular prism = 318 km³
Thus, the Surface area of the given triangular prism in the diagram above is: 318 km³.
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